The [H3O+] of a solution with pH = 9.7 is

Step 1

Molarity is defined as:

molarity (M or mol/L) = moles of solute/volume of the solution (L)

-------------

Step 2

Information provided:

Moles of solute (LiCl) = 4.5 moles

Volume of solution = 3.7 L

-------------

Step 3

Procedure:

Molarity = 4.5 moles/3.7 L = 1.216 mol/L

Answer: Molarity = 1.216 mol/L

The answer is d. 2

Put the value in 'n' and determine the molar mass. It will match with what is given in question,i.e., 46.00 g/mol.

Answer:

h

Explanation:

The mass of hydrogen needed to produce 51.0 grams of ammonia is  ≈ 9.07 grams.

To determine the mass of hydrogen required to produce 51.0 grams of ammonia (NH3) using the Haber process, we need to calculate the stoichiometric ratio between hydrogen and ammonia.

From the balanced chemical equation:

3 H₂(g) + N₂(g) → 2 NH₃(g)

We can see that for every 3 moles of hydrogen (H₂), we obtain 2 moles of ammonia (NH₃).

First, we need to convert the given mass of ammonia (51.0 grams) to moles. The molar mass of NH₃ is 17.03 g/mol.

Number of moles of NH₃ = Mass / Molar mass

                     = 51.0 g / 17.03 g/mol

                     ≈ 2.995 moles

Next, using the stoichiometric ratio, we can calculate the moles of hydrogen required.

Moles of H₂ = (Moles of NH₃ × Coefficient of H₂) / Coefficient of NH₃

           = (2.995 moles × 3) / 2

           ≈ 4.493 moles

Finally, we can convert the moles of hydrogen to mass using the molar mass of hydrogen (2.02 g/mol).

Mass of H₂ = Moles × Molar mass

          = 4.493 moles × 2.02 g/mol

          ≈ 9.07 grams

Therefore, approximately 9.07 grams of hydrogen is needed to produce 51.0 grams of ammonia in the Haber process.

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At equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

1: Write the balanced chemical equation:

\(C_O\)(g) + \(Cl_2\)(g) ⟶ \(C_OCl_2\)(g)

2: Set up an ICE table to track the changes in moles of the substances involved in the reaction.

Initial:

\(C_O\)(g) = 0.3500 mol

\(Cl_2\)(g) = 0.05500 mol

\(C_OCl_2\)(g) = 0 mol

Change:

\(C_O\)(g) = -x

\(Cl_2\)(g) = -x

\(C_OCl_2\)(g) = +x

Equilibrium:

\(C_O\)(g) = 0.3500 - x mol

\(Cl_2\)(g) = 0.05500 - x mol

\(C_OCl_2\)(g) = x mol

3: Write the expression for the equilibrium constant (Kc) using the concentrations of the species involved:

Kc = [\(C_OCl_2\)(g)] / [\(C_O\)(g)] * [\(Cl_2\)(g)]

4: Substitute the given equilibrium constant (Kc) value into the expression:

1.2 x \(10^3\) = x / (0.3500 - x) * (0.05500 - x)

5: Solve the equation for x. Rearrange the equation to obtain a quadratic equation:

1.2 x \(10^3\) * (0.3500 - x) * (0.05500 - x) = x

6: Simplify and solve the quadratic equation. This can be done by multiplying out the terms, rearranging the equation to standard quadratic form, and then using the quadratic formula.

7: After solving the quadratic equation, you will find two possible values for x. However, since the number of moles cannot be negative, we discard the negative solution.

8: The positive value of x represents the number of moles of \(Cl_2\)(g) at equilibrium. Substitute the value of x into the expression for \(Cl_2\)(g):

\(Cl_2\)(g) = 0.05500 - x

9: Calculate the value of \(Cl_2\)(g) at equilibrium:

\(Cl_2\)(g) = 0.05500 - x

\(Cl_2\)(g) = 0.05500 - (positive value of x)

10: Calculate the final value of \(Cl_2\) (g) at equilibrium to get the answer.

Therefore, at equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

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The concentration (molarity) of the final NaCl solution is 175 M.

To find the concentration (molarity) of the final NaCl solution, we can use the equation:

M1V1 = M2V2

Where M1 is the initial concentration, V1 is the initial volume, M2 is the final concentration, and V2 is the final volume.

In this case, we have an initial NaCl solution with a concentration of 2.5 M and a volume of 350 mL (0.350 L). We are diluting this solution to a total volume of 5.0 mL (0.005 L).

Plugging these values into the equation, we have:

(2.5 M) * (0.350 L) = M2 * (0.005 L)

Simplifying the equation:

0.875 = 0.005 * M2

Dividing both sides by 0.005:

M2 = 0.875 / 0.005

M2 = 175M

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The linear densities and the tension in the equation v = F T can be used to determine the wave's speed. According to the calculation v = F T, v = F T, the linear density would require a 20-fold increase in tension.

The vertical density of both the rope a wave travels through determines its speed. The speed rises as the linear density decreases. The relationship states that the denominator of linear density and speed are inversely related. Hence, a doubling or tripling of speed results from a razing of the linear density.

The pitch of a rope is also influenced by its tension. With their tuning keys, guitar string are adjusted (tightened and loosened). A string can be easily raised to the height.

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The moles of BaOH necessary are 3.75 moles.

The mole is an amount unit similar to familiar units like pair, dozen, gross, etc. It provides a specific measure of the number of atoms or molecules in a bulk sample of matter.

A mole is defined as the amount of substance containing the same number of atoms, molecules, ions, etc. as the number of atoms in a sample of pure 12C weighing exactly 12 g.

Given,

Concentration = 5M

Volume = 750 ml

Moles = Concentration × volume

= 5 × 0.75

= 3.75 moles

Therefore, the moles of BaOH necessary are 3.75 moles.

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Answer:

Ratio = 2 : 3 (Approx.)

Explanation:

Given:

Compound A = 1.278 g

Compound B = 1.904

Find:

Ratio

Computation:

Ratio = Compound A / Compound B

Ratio = 1.278 / 1.904

Ratio = 2 : 3 (Approx.)

Answer:

Answer- K2CO3

Explanation:

hope it helps :)

we would need 2625.13 grams (or 2.62513 kilograms) of NaCl.

To calculate the mass of NaCl required to produce a 26.4 mol/L solution with a 1.7 L volume, we need to use the formula that relates the mass of solute, moles of solute, and molarity:Molarity (M) = moles of solute / liters of solution Rearranging this formula, we get:moles of solute = Molarity (M) x liters of solutionWe can use this formula to find the moles of NaCl needed:moles of NaCl = 26.4 mol/L x 1.7 L = 44.88 molNow, we can use the molar mass of NaCl to convert from moles to grams. The molar mass of NaCl is 58.44 g/mol:mass of NaCl = moles of NaCl x molar mass of NaClmass of NaCl = 44.88 mol x 58.44 g/mol = 2625.13 gTo produce a 26.4 mol/L solution with a 1.7 L volume.

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The experimental results would change if a different gas, such as CO₂, were used instead of air.

This comprises of gases that form the atmosphere and they include:

Due to the presence of other gases in air, there would be a change in experimental results.

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Answer:

right now we are using energy by online learning on our laptops , air conditioning, and transportation

Explanation:

Answer:

A a chemical change

Explanation:

because a chemical change is when you mix tow substance together and they creat a new substance

2NH3(g) = N2(g) + 3H2(g)

Before decomposed :

P NH3 = 2.7 atm

After decomposed :

P N2 = 0.54 atm

P H2 = P N2 / 3 = 0.54 / 3 = 0.18 atm

P NH3 = 2.7 - 2(0.18) = 2.34 atm

Pressure equilibrium constant :

Kp = (P N2)(P H2)³ / (P NH3)²

Kp = (0.54)(0.18)³ / (2.34)²

Kp = 5.75 × 10^(-4)

Answer:

reduce water loss  

absorb sunlight

take in carbon dioxide

produce oxygen

Explanation:

i think

Answer:

A, D, and E

Reduces water loss, take in carbon dioxide, and produce oxygen.

Explanation:

Explanation:

decrease T = eq shifts left, because youre taking energy from the system and this is an endothermic reaction, it needs energy to make products = co2 concentration decreases

add CO = eq shifts right, because you're adding reactants in the equilibrium = i2o5 concentration decreases

increase i2o5 = same = can't affect T

decrease co2 = eq shifts right, because by

decreasing co2 you'll have less of this product than you normally have in the equilibrium, then eq will shift toward making more product = both reactants, CO and I2O5 decrease their concentration because they're being used to shift equilibrium right

Nitrogen G is a colorless, tasteless gas that is the most plentiful element in Earth's atmosphere and is a constituent of all living matter of nitrogen.

Nitrogen is an essential gaseous element with an atomic number of 7 and an atomic weight of 14.0067. Nitrogen gas has two particles of Nitrogen therefore, the molecular formula of this gas is N2. It is a non-metallic element that settled Group 15

nitrogen. [ nī′trə-jən ] N. A nonmetallic element that constructs up about 78 percent of the atmosphere by capacity, Nitrogen is a nonmetal and the lightest member of group 15 of the periodic table

So we can conclude that Nitrogen is the chemical element with the symbol N and atomic number 7.

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Answer:

Calcium

Explanation:

Zinc cannot displace Ca because calcium is above it in the reactivity series

Answer: 0.133 mol/l

Explanation: molality = concentration = 0.400 mol/3.0 l

Answer:

X2Y4–6Z8O20 (OH, F)4

Explanation:

The chemical formula for micas is X2Y4–6Z8O20 (OH, F)4, where X is K, Na, or Ca or less commonly Ba, Rb, or Cs; Y is Al, Mg, or Fe or less commonly Mn, Cr, Ti, Li, etc.; Z is chiefly Si or Al, but also may include Fe3+ or Ti1. Structurally, micas can be classed as dioctahedral (Y = 4) and trioctahedral (Y = 6)1.

The chemical formula for micas varies, but they typically have the general formula:

(K,Na,Ba,Rb,Ca)(Al,Mg,Fe)2(Si3Al)O10(OH,F)2

Where:

So in summary, micas have a layered aluminosilicate structure with interlayer cations that can vary, but they are generally characterized by an approximate 3:1 ratio of silicon to aluminum within the silica tetrahedral sheets. The chemical formula given is the generalized structural formula for micas, but the actual compositions can vary based on the specific mica.

Answer:

Benzene is an organic chemical compound with the molecular formula C₆H₆. The benzene molecule is composed of six carbon atoms joined in a planar ring with one hydrogen atom attached to each. Because it contains only carbon and hydrogen atoms, benzene is classed as a hydrocarbon.

If number of bonds is three (3) then bond angle is 120° and structure is trigonal and if number of bonds is four( 4) then bond angle will be 109° 28' and structure is tetrahedral.

The angle between two bonds in a complex molecule or between two orbitals that include bonding electron pairs encircling the core atom is the bond angle. It is calculated and represented in degrees using a spectroscopic method.

When a single electron pair there at central atom begins to resist the bound pair of electrons, the bond angle decreases and the bonds are slightly shifted inward. When there is a increase in back bonding, the bond angle increases.

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Answer:

13 mol NO

Explanation:

Step 1: Write the balanced equation

4 NH₃(g) + 5 O₂(g) ⇒ 4 NO(g) + 6 H₂O(g)

Step 2: Establish the appropriate molar ratio

According to the balanced equation, the molar ratio of O₂ to NO is 5:4.

Step 3: Calculate the number of moles of O₂ needed to produce 16 moles of NO

We will use the previously established molar ratio.

16 mol O₂ × 4 mol NO/5 mol O₂ = 13 mol NO

Molar mass of LiBr

\(\\ \sf\hookrightarrow No\:of\;moles=\dfrac{Given\:mass}{Molar\:mass}\)

\(\\ \sf\hookrightarrow No\:of\:moles=\dfrac{66.1}{87}\)

\(\\ \sf\hookrightarrow No\:of\:moles=0.75mol\)

Answer: d

Explanation:because it makes sence i think

1. Height of the shooter: approximately 183.20 ft.

2. Height of the shooter: approximately 880.24 ft.

3. Height of the shooter: approximately 229.33 ft.

1. Given: Angle of trajectory: 15°

Distance to the building: 700 ft

Height of the victim: 6.0 ft

Using trigonometry, we can write the equation:

tan(angle) = opposite/adjacent

tan(15°) = 6.0 ft/h

h = 700 ft * tan(15°) / 1

h ≈ 183.20 ft

Therefore, the height of the shooter is approximately 183.20 ft.

2. Using the trigonometric equation, we have:

tan(angle) = opposite/adjacent

tan(35°) = 4.8 ft/h

Rearranging the equation, we get:

h = 1000 ft * tan(35°) / 1

h ≈ 880.24 ft

Therefore, the height of the shooter is approximately 880.24 ft.

3.h = 500 ft * tan(25°) / 1

h ≈ 229.33 ft

Therefore, the height of the shooter is approximately 229.33ft.

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