The graph ta free rotht shows how many pounds of apples and one wine. Fir examples if you devote al of your time ta poing apples and none of your time 10 inckino chemos. you can prow. 72 pounds of apples. If you devote al of your nime bo picking chetres, you can plos 12 pounds. Ar the same fime, if your neighbor deyotes afl of her time fo phiching apples, she can pick 32 pounds of appies. If she devohes all of her time to picking cherrief, she can pick 32 pocmate Suppose mitialy that you (Y) are consumhng 24 pounts of appiot and 11 pounds of cherries and that your neighbor (N) is consurning 28 pounds of apples and 4 pounds of cherries. as indisated in the graph. Then, suppese you and your neighbor specialize by each only picking the good for which. you have a comparative adyantage and trade. in particular, suppose you trade your neightor haif of your production for haif of what your nedghbor produces. In the cable below, first fis in production when specializing: Enter numene responses using integers.)

The pair of equations whose lines are perpendicular is (d) y = 1/6x + 3; y = -6x - 3

from the question, we have the following parameters that can be used in our computation:

The pair of equations

By definition;

The slopes of perpendicular lines are opposite reciporcals

So, we have

(a) -1/3 and -3 false

(b) -3 and -6 false

(c) 3 and 3 false

(d) 1/6 and -6 true

Hence, the equations are (d) y = 1/6x + 3; y = -6x - 3

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Using the bisection concept, it is found that the measure of angle PQR is of 130º.

A bisection divides an angle into two equal angles. In this problem, the angles are given as follows:

Hence the value of x is given as follows:

3x + 5 = 2x + 25

x = 20º.

Hence the measure of angle PQR is given as follows:

m<PQR = 3x + 5 + 2x + 25 = 5x + 30 = 5 x 20º + 30º = 130º.

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Given the topological spaces X = {D, O, R, K} with the topology Tx and Y = {M, A, T, H} with the topology Jy, we are asked to determine whether the set E = {0, K} is open in X and open in Y.

To determine whether the set E = {0, K} is open in the topological spaces X and Y, we need to check if E belongs to the respective topologies, Tx and Ty.

In X, the topology Tx is given by: Tx = {Ø, {0}, {D, O}, {O, R}, {D, O, R}, X}. We can see that E = {0, K} is not explicitly listed in Tx. Therefore, E is not open in X since it does not belong to the topology.

In Y, the topology Ty is given by: Jy = {0, {M}, {M, A}, {M, A, T}, Y}. Again, E = {0, K} is not explicitly listed in Ty. Hence, E is not open in Y as it does not belong to the topology.

In both cases, the set E = {0, K} is not open in the respective topological spaces X and Y because it is not a member of the defined topologies.

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Answer:

See below

Step-by-step explanation:

I'll provide an example to help you. Let's say we were solving \(x^2+5x-7=0\) and we wanted to factor the quadratic on the left side. We can't do that because the factors of -7 don't add up to 5. So we'd have to use the quadratic formula. The quadratic formula is essentially the last resort that will solve all quadratic equations, so it could be seen as a preferred method. But, unless you can factor the quadratic, it's much easier to solve.

Now let's do another one. \(x^2+5x+6=0\) for example can be written as \((x+2)(x+3)=0\) and we can easily get \(x=-2\) and \(x=-3\) as solutions since plugging them into the factors would produce 0 (from the Zero Product Property). If we used the quadratic formula, it would take more time to plug in the variables and solve when we can just simply factor.

Hopefully, this explanation helps you to think of your discussion post!

Answer:

Step-by-step explanation:

You need to set up a proportion.

10 pounds of potatoes/15 pounds of mashed potatoes

Before going on notice that the potatoes are on the top part of the fraction and the mashed potatoes are on the bottom. The right hand side of the proportion must be the same.

10 pounds potatoes/15 pounds mashed = x pounds / 50 pounds mashed.

The raw potatoes are on the top, The mashed is on the bottom. It's always like that.

The second step is to cross multiply.

10 / 15 = x / 50          Cross miultiply

10*50 = 15 * x            Combine the left

500 = 15x                  Divide by 15

500/15 = x

x = 33.33

Answer:

33.33

Step-by-step explanation:

The maximum value of the objective function is 4 at the vertex (4, 0), and the minimum value is -8 at the vertex (0, -4). The optimal solutions for the given LP problem are Maximum: p = 4 at x = 4 and y = 0 and Minimum: p = -8 at x = 0 and y = -4.

Maximize and minimize p = x + 2y

subject to:

x + y ≥ 4

x + y ≤ 10

x - y ≤ 4

x - y ≥ -4

First, let's graph the feasible region defined by the given constraints:

Plotting the lines:

x + y = 4 (solid line)

x + y = 10 (solid line)

x - y = 4 (solid line)

x - y = -4 (solid line)

The feasible region is the area that satisfies all the constraints and is bounded by the lines on the graph.

Upon examining the feasible region, we can observe that it is a bounded region.

To find the optimal solution, we need to evaluate the objective function p = x + 2y at the vertices (corner points) of the feasible region.

Now, let's find the vertices of the feasible region by solving the intersection points of the lines:

1. Intersection of x + y = 4 and x + y = 10:

Subtracting the equations, we get 0 = 6, which is not possible. No intersection point exists for these lines.

2. Intersection of x + y = 4 and x - y = 4:

Adding the equations, we get 2x = 8, x = 4. Substituting x = 4 into x + y = 4, we get 4 + y = 4, y = 0. The first vertex is (4, 0).

3. Intersection of x - y = 4 and x - y = -4:

Adding the equations, we get 2x = 0, x = 0. Substituting x = 0 into x - y = 4, we get -y = 4, y = -4. The second vertex is (0, -4).

Now, we evaluate the objective function at each vertex:

p(4, 0) = 4 + 2(0) = 4

p(0, -4) = 0 + 2(-4) = -8

The maximum value of the objective function is 4 at the vertex (4, 0), and the minimum value is -8 at the vertex (0, -4).

Therefore, the optimal solutions for the given LP problem are Maximum: p = 4 at x = 4 and y = 0 and Minimum: p = -8 at x = 0 and y = -4.

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The total number of samples will be 1109 .

Given ,

Margin of error 0.02

Here,

According to the formula,

\(Z_{\alpha /2} \sqrt{pq/n}\)

Here,

p = proportions of scientist that are left handed

p = 0.09

n = number of sample to be taken

Substitute the values,

\(Z_{0.01} \sqrt{0.09 * 0.91/n} = 0.02\\ 2.33 \sqrt{0.09 * 0.91/n} = 0.02\\\\\\\)

n ≈1109

Thus the number of samples to be taken will be approximately 1109 .

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Answer:

the club should start the process of extending the center in 2024 or 9 years after 2015

Step-by-step explanation:

Since it takes 2 years to build the extension, the club should start the process of extending the center 2 years before it reaches its carrying capacity of 400.

Initially, In the year 2015, it has 50 members.

The number of members increase by 30 per year.

This follows a linear equation

y = mx + b,

where y = number of members and x = number of years

initially, x = 0 and y = 50. so,

50 = b

since each year the number of members increases by 30, the slope m is 30,e.g.

for in the 2nd year,(after 1 year has passed)

y = 30(1) + 50

y = 80 members,

now, we have to find the number of years when the stadium reaches maximum capacity and then subtract that by 2 years to find the year when the club should start the extension process,

capacity = 400,

then

400 = 30x + 50

400 - 50 = 30x

350 = 30x

350/30 = x

x = 11.67 years,

This is when the stadium reaches maximum capacity,

We subtract this by 2, to get,

x = 9.67 years,

so, we should start to build the extension 9.67 years after 2015, but to get a whole number, we round down to get,

x = 9 years

or, the club should start the process of extending the center in 2024

Step-by-step explanation:

they say the club started with 50 members, so

m0= 50

and they expect they'll increase by 30 members per year

you can write this as a lineal function,

with the y-intercept being m0=50

because that's the value for your dependent variable when your independent variable year=0

and your slope is the increase of 30 members per year

so the lineal function is

members = 30year + 50

when will the club reach 400 members?

400 = 30y + 50

11,7=y

they'll reach 400 members when the club reaches its 11,7 years

now since the extension process takes 2 years , they'll need to start 2 years before

11,7 - 2 = 9,7

they'll need to start when the club reaches 9,7 years since its foundation

hope it was helpful!

The correct description for the distribution of the sample proportion of adults in the sample who don't have health insurance is X - B(120, 0.15).

B(120, 0.15) represents a binomial distribution with parameters n = 120 (the sample size) and p = 0.15 (the population proportion of adults without health insurance).

The binomial distribution is appropriate in this case because we have a fixed sample size and each individual in the sample can either have health insurance (success) or not have health insurance (failure). The sample proportion of adults without health insurance can be calculated by dividing the number of adults without health insurance by the total sample size.

Therefore, the correct description is X - B(120, 0.15).

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Answer:

B. Arm circles

Hope you have a great day :)

Answer:

C

Step-by-step explanation:

3x - 9y = 9 → (1)

- 2x +2y = 8 ( subtract 2y from both sides )

- 2x = - 2y + 8 ( divide through by - 2 )

x = y - 4

substitute x = y - 4 into (1)

3(y - 4) - 9y = 9

3y - 12 - 9y = 9

- 6y - 12 = 9 ( add 12 to both sides )

- 6y = 21 ( divide both sides by - 6 )

y = \(\frac{21}{-6}\) = - \(\frac{7}{2}\)

Answer:

y = 6

Step-by-step explanation:

hope it's helpful :)

The Taylor polynomials P1, P2, P3, and P4 centered at a0 for f(x) are given as:P1(x) = 1P2(x) = 1 - x²/2!P3(x) = 1 - x²/2! + x⁴/4!P4(x) = 1 - x²/2! + x⁴/4! - x⁶/6!

We will apply the Taylor's theorem formula, which is supplied as follows, to determine the Taylor polynomials P1, P2, P3, and P4 centred at a0 for f(x) in the given question:f'(a)(x-a)/1 = f(x) = f(a) + f'(a)! + f''(a)(x-a)²/2! + ... + fⁿ(a)(x-a)ⁿ/n!We have f(0) = 1f'(0) = 0f''(0) = -1f'''(0) = 0f4(0) = 1 for f(x) = cos(x) at x = 0.We can get the following polynomial expressions by using these values in the Taylor's theorem formula:P1(x) = 1P2(x) = 1 - x²/2!P3(x) = 1 - x²/2! + x⁴/4!P4(x) = 1 - x²/2! + x⁴/4! - x⁶/6!Consequently, the Taylor polynomials P1, P2, P3, and P4 for f(x) are provided as follows:P1(x) = 1P2(x) = 1 - x²/2!P3(x) = 1 - x²/2! + x⁴/4!P4(x) = 1 - x²/2! + x⁴/4! - x⁶/6!

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Answer:

Option 2

Step-by-step explanation:

Go through until you find a true statement:

- The number of observations is 10

Count the number of data points. You should end up with 15, so this option is not correct.

-The median of the data set is 10

To find the median, you know that there are a total of 15 data points, so the median would be the mean of the 7th and 8th (because those are the middle numbers). If you look at the data points, the 7th and 8th points are at 10. The mean of 10 and 10 is just 10,  so that means the median of the set is 10.

This is the correct answer.

If you want, you can also go through the other options and see that none of them work.

Answer:

The person above is correct it would be option two!

Step-by-step explanation:

The explanation makes alot of sence. I took the test to make sure it was correct i gotten a 100~!!! ty!

Answer:

The third answer is correct.

Step-by-step explanation:

You are going to translate the smaller quadrilateral (4 sided figure) to the larger quadrilateral.  Then you need the scale factor from the smaller figure to the larger.  

Side EF times the scale factor will give you side AB.  Let's call the scale factor s then our equation would be:

EF x s = AB  To find s divide both sides by EF

\(\frac{EF(s)}{EF}\) = \(\frac{AB}{EF}\)

s = \(\frac{AB}{EF}\)  This is our scale factor.

Helping in the name of Jesus.

Answer:

Multiply 2/3 and your number. If you have a whole number, convert it to a fraction by putting it over a denominator of 1. When multiplying fractions, calculate numerator times numerator, then denominator times denominator. For example, to find two-thirds of 18, multiply 2/3 x 18/1 to get 36/3.

It's important to note that changing the order of integration may not always be possible or straightforward, and it depends on the nature of the function and the region of integration. It's essential to carefully analyze the problem and determine the most suitable order of integration for a given situation.

To change the order of integration, we need to swap the order in which we integrate with respect to x and y. This involves rewriting the integral with respect to one variable and then integrating with respect to the other.

For example, if we have the integral:∫∫ f(x, y) dx dy

To change the order of integration, we can write it as:∫∫ f(x, y) dy dx

Now, we integrate with respect to y first, treating x as a constant. After integrating with respect to y, we then integrate with respect to x, treating y as a constant.

This change in the order of integration can be useful in certain situations, especially when the original order of integration leads to complex or difficult calculations. By changing the order, we may simplify the integral and make it easier to solve.

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Answer:−3+3=−4

2+3−=15

4−3−=19

2 3

Step 1: Pair the equations to eliminate y because the y terms are already additive inverses

1

−3+3=−4

2+3−=15

2

2+3−=15

4−3−=19

2 3 4

3 =11

5

6 −2=34

Step 2: Write the two new equations

as a system

Step 3: Substitute the value for x and z

into one of the original equations

3 =11

3 5 +2=11

4

5−3+3 −2 =−4

15+2=11

5

6 −2=34

5−3−6=−4

−3−1=−4

9x

2=−4

=−2

= 45

x = 5

−3=−3

=1

The solution (5, 1, -2)

Step-by-step explanation:

The rule of inference being used here is Modus Tollens. Modus Tollens is a valid deductive argument form that states if a conditional statement "If P, then Q" is true and the consequent Q is false, then the antecedent P must also be false.

In the given scenario, the conditional statement is "If the guard dog doesn't know a person, then it barks."

The observation that the dog didn't bark (Q is false) leads to the conclusion that the dog must have known the person (the antecedent P is false).

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a) 16p

b) 1ab

hope i helped

Answer:

6

Step-by-step explanation:

Answer:

6 Inches

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

The sum of the interior angles of a quadrilateral = 360°

The interior angle at 150° = 360° - 150° = 210°

sum the angles and equate to 360

25 + 30 + 210 + x = 360 , that is

265 + x = 360 ( subtract 265 from both sides )

x = 95 → C

Answer:

You increase each term inside the parentheses by −1 in order to subtract each term, since subtraction is the additive inverse.

Step-by-step explanation:

The length of the fence in yards, using all 144 feet of material, is 12 yards. Jason will have a fence with a length of 21 yards if he uses all 144 feet of material to build the fence around his rectangular garden.

Let's denote the length of the fence as L in feet. The width of the fence is given as 9 feet. The perimeter of a rectangle is given by the formula P = 2L + 2W, where P is the perimeter, L is the length, and W is the width.

In this case, we have P = 144 feet and W = 9 feet. We want to find the value of L that satisfies the equation 2L + 2W = P.

Substituting the given values, we have:

2L + 2(9) = 144

2L + 18 = 144

2L = 144 - 18

2L = 126

L = 126/2

L = 63

So the length of the fence is 63 feet.

To convert this length from feet to yards, we know that 1 yard is equal to 3 feet. Therefore, to obtain the length in yards, we divide the length in feet by 3:

63 feet / 3 = 21 yards

Therefore, the length of the fence, using all 144 feet of material, is 21 yards.

Jason will have a fence with a length of 21 yards if he uses all 144 feet of material to build the fence around his rectangular garden.

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¬ Vx(Fx → Gx) v 3xFx ⊢ Fx → Gx [1-5, Modus Ponens]

i. ∃x(Fx & Gx) ⊢ ∃xFx & ∃xGx (5 marks)

Proof:

1. ∃x(Fx & Gx) [Premise]

2. Fx & Gx [∃-Elimination, 1]

3. ∃xFx [∃-Introduction, 2]

4. ∃xGx [∃-Introduction, 2]

5. ∃xFx & ∃xGx [Conjunction Introduction, 3 and 4]

6. ∃x(Fx & Gx) ⊢ ∃xFx & ∃xGx [1-5, Modus Ponens]

ii. ¬ 3x(Px v Qx) ⊢ Vx ¬ Px (5 marks)

Proof:

1. ¬ 3x(Px v Qx) [Premise]

2. ¬ Px v ¬ Qx [DeMorgan’s Law, 1]

3. Vx ¬ Px [∀-Introduction, 2]

4. ¬ 3x(Px v Qx) ⊢ Vx ¬ Px [1-3, Modus Ponens]

iii. ¬ Vx(Fx → Gx) v 3xFx (10 marks; Hint: To derive this theorem use RA.)

Proof:

1. ¬ Vx(Fx → Gx) v 3xFx [Premise]

2. (¬ Vx(Fx → Gx) v 3xFx) → (¬ Vx(Fx → Gx) v Fx) [Implication Introduction]

3. ¬ Vx(Fx → Gx) v Fx [Resolution, 1, 2]

4. (¬ Vx(Fx → Gx) v Fx) → (Fx → Gx) [Implication Introduction]

5. Fx → Gx [Resolution, 3, 4]

6. ¬ Vx(Fx → Gx) v 3xFx ⊢ Fx → Gx [1-5, Modus Ponens]

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Respuesta:

x = 5.656854249

Explicación paso a paso:

[NOTA: Solo quería disculparme de antemano por cualquier mala gramática, ya que estoy usando un traductor para esto.]

x/Sen30°= 8/Sen45° [Multiplica ambos lados por Sen30°]

x = (8/Sen45°) * Sen30° [Resuelve usando una calculadora]

x = 5.656854249

Answer:

40% and 0.4

Step-by-step explanation:

The fraction 8/20 can be simplified into 4/10 by dividing both 8 and 20 by 2.

4/10 is the same as 40/100, which can be also be written as 40% or 0.4.

Answer:

Decimal = 0.4

Percent = 40%

Step-by-step explanation:

Step 1:

8/20 = 40/100       Convert

Step 2:

40/100 = 0.40        Convert

Step 3:

0.40 = 40%    Convert

Answer:

Decimal = 0.4

Percent = 40%

Hope This Helps :)

Answer:

πr(r+h2+r2)

Step-by-step explanation:

Answer:

A=πr(r+h2+r2

Step-by-step explanation: