Using the laws of rational function, we can find that this function is represented by the following equation: \(f(x)= \frac{(x-1)}{(x+2)} -2\)
Describe rational function?The ratio of two polynomial functions is known as a rational function, which is a sort of mathematical function.
It is a function that can be written as f(x) = p(x)/q(x), where q(x) is not the zero polynomial and both p(x) and q(x) are polynomials.
The information from the horizontal and vertical asymptotes can be used to calculate the values of a and q.
Since the horizontal asymptote lies at y = 1, the degree of the denominator polynomial, which is 1, must match the degree of the numerator polynomial. Which also equals 1. Q and an are hence equal to 1.
Entering these values gives us:
f(x) = (x - 1) / (x + 2) - 2
As a result, the equation that describes the displayed graph is:
f(x) = (x - 1) / (x + 2) - 2.
\(f(x)= \frac{(x-1)}{(x+2)} -2\)
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To find the number in a square, add the numbers in the two circles
connected to it.
Fill in the missing numbers.
The missing values in the quantitative reasoning given are : -2, 13 and 9
Given the rule :
square = circle + circleWe can deduce that :
circle = square - circleFor the left circle :
circle = -6 - (-4) = -6 + 4 = -2
For the right circle :
circle = 11 - (-2) = 11 + 2 = 13
For the left square :
square = 13 + (-4)
square = 13 -4 = 9
Therefore, the missing values are : -2, 13 and 9
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Enter the decimal represented by the shaded square.
The shaded square represents
Answer: the shaded squares are equal to 0.3
Which of the following is an obtuse angle in this figure?
a protractor, with segment DEF along the bottom, EH point to the 55 degree on the left, EJ to 90 degrees, EK to the 30 degrees on the right
angle DEK
angle DEJ
angle DEH
angle FEK
Halp how to factor 4x-2
Answer:
2(2−1)
Step-by-step explanation:
4−2
Grouping
Common factor
4−2
2(2−1)
Solution
2(2−1)
To factor, you do the opposite of what you would in distributive property. You have to find the greatest common factor, or GCF, of 4 and -2.
4 2
------ -------
1 | 4 1 | 2
2 | 2
So the GCF is 2. Now we factor the expression.
4x-2
2(2x-1)
---
hope it helps
What is the distance between the points (2, 1) and (14, 6) on a coordinate
plane?
Answer:
the answer is 13 units
Step-by-step explanation:
What property is used to show that 6(x + 7) = 6x + 42?
Commutative property
Identity property
Distributive property
Associative property
Answer: Distributive because 6 has to be multiplied by x and 7
1/6 (12 -6x) = 5 (x+4) plz help.
Answer:
\( \frac{1}{6} (12 - 6x) = 5(x + 4) \\ \frac{12}{6} - \frac{6x}{6} = 5x + 5 \times 4 \\ 2 - x = 5x + 20 \\ x \: terms \: togather \\ 5x + x = 2 - 20 \\ 6x = - 18 \\ x = \frac{ - 18}{6} \\ x= - 3 \\ thank \: you\)
expand and simplify (x+5)(x-1)
The expanded and simplified form of the expression (x + 5)(x - 1) is x² - x + 5x - 5.
What is the expanded form of the expression?Given the expression in the question;
(x + 5)(x - 1)
To expand and simplify the expression (x+5)(x-1),
we use the distributive property:
(x + 5)(x - 1)
x(x - 1) + 5(x - 1)
Now we can simplify each term by using the distributive property again:
x(x - 1) = x² - x
5(x - 1) = 5x - 5
Putting these terms back together, we have:
(x+5)(x-1) = x² - x + 5x - 5
Combining like terms, we get:
(x+5)(x-1) = x² + 4x - 5
Therefore, (x+5)(x-1) simplifies to the quadratic expression x² + 4x - 5.
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PLEASE HELP ASAP!!!!
Step-by-step explanation:
F(x) =x^2
G(x) =x-3
G(f(x))
= (x^2) -3
F(f(x))
= (x-3)^2
(x-3)(x-3)
x^2 -6x+9
For the second one
1/(x-3)
x-3 ≠ 0
x ≠ 3
So the domain restriction = 3
Answer:
i agrey with other guy
Step-by-step explanation:
Maxine wants a necklace 49 beads long.
She needs __ blue beads and __ black beads.
A pizzeria sold $3,432 worth of pizzas this week. Each pizza costs $12. How many pizzas were sold?
Answer:
286
Step-by-step explanation:
its 286 that's the answer
Please help!! I’ll do what ever! find m<1, m<2, m<3, m<4, and m<5,
Answer:
1.)111
2.)69
3.)60
4.)60
5.)51
(02.02 MC)
If trapezoid ABCD was reflected over the y-axis, reflected over the x-axis, and rotated 180°, where would point A′′′ lie?
Trapezoid formed by ordered pairs A at negative 4, 1, B at negative 3, 2, C at negative 1, 2, D at 0, 1.
(1, −1)
(−4, 1)
(1, 1)
(−4, −1)
The location of point A''' after the three transformations would be (-4, 1).
To determine the location of point A''', we need to apply the three transformations (reflection over the y-axis, reflection over the x-axis, and rotation of 180°) to point A.
When a point is reflected over the y-axis, the x-coordinate is negated while the y-coordinate remains the same.
So, the reflection of point A (-4, 1) over the y-axis would be (4, 1).
When a point is reflected over the x-axis, the y-coordinate is negated while the x-coordinate remains the same. So, the reflection of point (4, 1) over the x-axis would be (4, -1).
When a point is rotated 180°, the x-coordinate and y-coordinate are both negated. So, the rotation of point (4, -1) by 180° would be (-4, 1).
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1 point
A box contains 6 black pens, 4 blue pens, and 7 red pens. Without looking, Clarissa randomly picks a black pen out of the box. If she chooses another pen out of the
box without replacing the first one, what is the probability that she will pick a black pen both times? Write your answer as a percent.
The probability that she will select a black pen both times if she takes a pen from the box without replacing the first one is 41.176%.
Given that
Six black, four blue, and seven red pens are included in a box. Clarissa takes a black pen at random from the box without even looking.
We have to find what is the probability that she will select a black pen both times if she takes a pen from the box without replacing the first one.
Based on the given conditions, formulate:
7/(7+6+4)
7/(13+4)
7/17
0.41176
41.176%
Therefore, the probability that she will select a black pen both times if she takes a pen from the box without replacing the first one is 41.176%.
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I don’t understand what I’m supposed to do
The area of the composite shape can be found to be 112 sq in.
How to find the area ?This is a composite shape and the most likely question to be answered is to find the area of the composite shape.
To find the area of the composite shape consisting of a triangle and a rectangle, we need to find the area of each shape and then add them together.
The area of a triangle is given by the formula:
A = (1/2)bh
A = (1/2)(4)(6) = 12 sq in
The area of a rectangle is given by the formula:
A = lw
A = (10)(10) = 100 sq in
To find the area of the composite shape, we add the areas of the triangle and the rectangle:
A = 12 + 100 = 112 sq in
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Kai and Finley were studying together for their exams the
following day. They had planned to spend the entire two days
after the exams hiking to a log cabin on the Winslow trail. The trail
was closed on Mondays, Wednesdays, and weekends.
On which day of the week was their exam scheduled?
Their exam must have been scheduled on Wednesday, allowing them to start hiking on Thursday after the exams.
How to determine which day of the week was their exam scheduledTo determine the day of the week on which Kai and Finley's exam was scheduled, we need to consider the information provided about the trail being closed on Mondays, Wednesdays, and weekends.
If they had planned to hike to the log cabin for two days after the exams, and the trail is closed on weekends, it means they cannot start hiking on Saturday or Sunday.
Since they cannot start hiking on Saturday or Sunday, the two possible options for the exam day would be Monday or Wednesday, as they have not specified whether the hike starts immediately after the exams or the day after.
However, we can conclude that their exam was not scheduled on Monday, as the trail is closed on Mondays, and they had planned to hike immediately after the exams.
Therefore, their exam must have been scheduled on Wednesday, allowing them to start hiking on Thursday after the exams.
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Instructions: Identify the key features of the following graph. If the Domain is all real numbers, type in 'All Real" into the Domain box
Key features for the graph given in the problem will be-:Vertex (-1, -5), Axis of symmetry=> (x = -1), y-intercept (0,-3), Minimum=> (y=-5), Domain=> (All Real), Range=>( y >= -5)
How to determine the key features?Refering to the graph given in the problem(refer image attached).The key features of the graph can be given as:
Vertex: The graph's vertex is at (-1, -5), which indicates that the graph extends upwards (because y = -5 is the minimal value).A vertical line at x = -1 serves as the graph's axis of symmetry. The graph is split into two symmetrical sections by this line.Y-intercept: The graph's y-intercept is at (0, -3), which indicates that here is where the graph and y-axis connect.The graph has a minimum point at y = -5, which is also the vertex of the graph and the lowest point on it.The graph's domain is set as "All Real" or "(-, )", which signifies that it spans all real values on the x-axis horizontally.Range: The graph's range is defined as y -5, which indicates that it climbs vertically from -5 and above on the y-axis.The graph has an upward-opening form, an axis of symmetry at x = -1, a y-intercept at (0, -3), a minimum point at y = -5 (which is also the vertex), and it spans all real numbers on the x-axis (domain) while being larger than or equal to -5 on the y-axis (range).
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Marking as Brainliest
Answer:
(8, -2)
Step-by-step explanation:
please answer this question below
Find the general solution of
dy/dx + 2y =6
Answer:
ye^(2x) - 3e^(2x) = C or (y - 3)e^(2x) = C
Step-by-step explanation:
dy/dx + 2y = 6
This is a first order linear ODE.
p(x) = 2
Integrating factor: I(x) = e^(∫ 2 dx) = e^(2x)
e^(2x)(dy/dx + 2y) = 6e^(2x)
e^(2x) dy + 2ye^(2x) dx = 6e^(2x) dx
Integrate both sides of the equation.
ye^(2x) = 3e^(2x) + C
Thus, the general solution is ye^(2x) - 3e^(2x) = C or (y - 3)e^(2x) = C.
What is the present value of R13 000 p.a. invested at the beginning of each year for 8years at 10%p.a. compound interest? (NB Use the compound interest tables provided or work to three decimal places only.)
Given statement solution is :- The present value of R13,000 per year invested for 8 years at 10% compound interest is approximately R69,776.60.
To calculate the present value of an investment with compound interest, we can use the formula for the present value of an annuity:
PV = A *\((1 - (1 + r)^(-n)) / r\)
Where:
PV = Present value
A = Annual payment or cash flow
r = Interest rate per period
n = Number of periods
In this case, the annual payment (A) is R13,000, the interest rate (r) is 10% per year, and the investment is made for 8 years (n).
Using the formula and substituting the given values, we can calculate the present value:
PV = \(13000 * (1 - (1 + 0.10)^(-8)) / 0.10\)
Calculating this expression:
PV = \(13000 * (1 - 1.10^(-8)) / 0.10\)
= 13000 * (1 - 0.46318) / 0.10
= 13000 * 0.53682 / 0.10
= 6977.66 / 0.10
= 69776.6
Therefore, the present value of R13,000 per year invested for 8 years at 10% compound interest is approximately R69,776.60.
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What is the area of the square that measures 3.1 m on each side
The area of the square with a side length of 3.1 meters is 9.61 square meters.
To find the area of a square, we need to multiply the length of one side by itself. In this case, the square has a side length of 3.1 m.
Area of a square = side length × side length
Substituting the given side length into the formula:
Area = 3.1 m × 3.1 m
To perform the calculation:
Area = 9.61 m²
It's worth noting that when calculating the area, we are working with squared units. In this case, the side length is in meters, so the area is expressed in square meters (m²). The area represents the amount of space enclosed within the square.
Remember, to find the area of any square, you simply need to multiply the length of one side by itself.
The area of the square with a side length of 3.1 meters is 9.61 square meters.
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image
Identify a pair of parallel lines in the given figure.
Question 2 options:
A)
p and s
B)
r and q
C)
r and p
D)
r and s
The parallel lines are r and s.
What are Parallel lines?Parallel lines are those lines that are equidistance from each other and never intersect each other.
Given that;
There are 4 lines ae shown in figure.
Now,
Since, There are 4 lines ae shown in figure.
We know that,
Parallel lines are those lines that are equidistance from each other and never intersect each other.
And, Here p and s are intersect at a point.
Lines q and r are intersect at a point.
Lines p and r are intersect at a point.
And, Lines r and s are not intersect at any point and equidistance from each other.
Thus, The lines r and s are parallel lines.
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At the beginning of 2019, Milos owned 30 model cars. If he purchases and builds 2 models each month, which of the following tables represents the numbers of model cars he has m months after January 1, 2019
What are the tables? I would need to get more info
Let D={12,15,17), E = {12,14,15,16) and F = {11,13,14,15,17).
List the elements in the set D UE.
DUE= (Use commas to separate answers.)
The elements that will be coming in the set D∪E will be {12, 14, 15, 16, 17}.
A set may be defined as a collection of letters or numbers that are written in order to depict a certain value or entity. A set is always represented by a capital letter symbol and is always written in curly brackets { }. Union of two sets may be defined as a new set which has the collection of all the elements of the two individual sets. Union of two sets is represented by the symbol '∪'. Union of two Indvidual sets, set A and set b is written as A∪B.
Now, according to the question set D is = {12, 15, 17} and set E is = {12, 14, 15, 16}.
The union of the two sets contains all the elements of the sets D and E.
Thus, D∪E will be given by {12, 14, 15, 16, 17}.
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PLEASE HELP WITH THIS?!!!!
Answer:
A parabola
Explanation:
52. Find a vector v whose magnitude is 3 and whose component in the i direction is equal to the component in the j direction.
The vector whose magnitude is 3 and whose components I. the I and j direction are equal is; <3√2/2i, 3√2/2j>.
Which vector is as described in the task content above?It follows that the magnitude of a vector in terms of its components in the i and j direction is;
M = √(x² + y²).
On this note, since the i and j components are equal; x = y and hence, we have;
3 = √(x² + x²).
3² = 2x²
x² = 9/2
x = 3/√2
x = 3√2/2
On this note, the required vector which is as described is; <3√2/2i, 3√2/2j>.
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Which of the following statements is true concerning f(x) = x2 - 22 - 24
Please help !
Write two different fractions where the LCD (lowest common denominator) is 20
Answer:
1/4 and 1/5
Step-by-step explanation:
The first thing is to define what is the least common denominator (LCD) that would be the smallest number that can be a common denominator for a set of fractions. Also known as the least common denominator, it is the lowest number you can use in the denominator to create a set of equivalent fractions that have the same denominator.
If we want it to be 20, we must decompose the number:
5 * 4
In other words, the fractions could be:
or also:
1/4 and 1/5
Answer:
1/5 and 1/4 hope this helped<3
Step-by-step explanation:
Use properties of operations to generate an expression that is equivalent to –5(x–8)+32
An expression that is equivalent to –5(x–8)+32 is -5x + 72.
What is an expression ?
To generate an equivalent expression for –5(x–8)+32, we can simplify the expression using the distributive property of multiplication over addition/subtraction.
Starting with -5(x-8), we can distribute the -5 across the parentheses by multiplying it by each term inside the parentheses. This gives us:
-5(x-8) = -5x + (-5)(-8)
Simplifying further, we get:
-5(x-8) = -5x + 40
Now we can substitute this expression back into the original equation:
-5(x-8) + 32 = (-5x + 40) + 32
Simplifying further, we get:
-5(x-8) + 32 = -5x + 72
Therefore, an expression that is equivalent to –5(x–8)+32 is -5x + 72.
In mathematics, an expression is a combination of numbers, symbols, and/or variables that are grouped together to represent a mathematical relationship or operation. An expression can contain one or more terms, which are separated by mathematical operators such as addition, subtraction, multiplication, division, and exponentiation.
Expressions can be used to represent a wide variety of mathematical concepts, such as equations, inequalities, functions, and formulas. They can be evaluated or simplified to obtain a numerical or algebraic result, or they can be manipulated and transformed using mathematical rules and properties.
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