The diagrams suggest that compounds must be

Answer:

Iron has four naturally-occurring stable isotopes, 54Fe, 56Fe, 57Fe and 58Fe. The relative abundances of the Fe isotopes in nature are approximately 54Fe (5.8%), 56Fe (91.7%), 57Fe (2.2%) and 58Fe (0.3%).

The considerations which are applicable in a suitable recrystallization solvent are: should have a boiling point that is ~ 30-50 °C, Should be unreactive, Offers minimal solubility and solubility-temperature relationship. Option A, C, D and E will be correct.

This statement is true. Because the solvent should have a boiling point that is around 30-50 °C higher than the melting point of the compound to be recrystallized in order to achieve efficient dissolution and crystal formation.

This statement is false. Because a good recrystallization solvent should dissolve the compound of interest well at high temperatures but not at all or only slightly at lower temperatures. Ideally, the impurities should dissolve well at all temperatures, so that they can be separated from the compound of interest during the filtration step.

This statement is true. Because the solvent should not react with the compound of interest, which would affect the purity of the final product.

This statement is true. Because the solvent should have minimal solubility for the compound to be purified at room temperature and lower temperatures, but should dissolve the compound well at higher temperatures in order to achieve efficient recrystallization.

This statement is true. Because the solubility-temperature relationship for the solvent and the compound should have a low slope in order to achieve efficient recrystallization.

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--The given question is incorrect, the correct question is

"Which of the following considerations are applicable when choosing a suitable recrystallization solvent? (TRUE / FALSE) A) Should have a boiling point that is ~ 30-50 °C above room temperature. B) Does not dissolve impurities at all temperatures or completely dissolves impurities at all temperatures. C) Should be unreactive toward the compound of interest. D) Offers minimal solubility of the compound to be purified at room and lower temperatures. E) Its solubility-temperature relationship to the compound should give a curve with a low slope."--

Answer:

GHG emissions are often measured in carbon dioxide (CO2) equivalent. To convert emissions of a gas into CO2 equivalent, its emissions are multiplied by the gas's Global Warming Potential (GWP).

If each BAL molecule binds one arsenic (As) atom, 1.4 x 10^ 22 atoms can be removed by 1.3 g of BAL.  BAL can also be used to remove poisonous heavy metals like mercury (Hg) and lead (Pb). If each BAL binds one Hg atom, the mass percent of Hg in a BAL-Hg complex is 61.95 %.

The term mass percent of a solution is defined as the ratio of the mass of solute that is present in a solution, relative to the mass of the solution, as a whole.

A. Molar mass of BAL ( C3H8OS2) is 124.2 g/mol

Mass = 2.9 g

Number of moles of BAL = mass / Molar mass

= ( 2.9g / 124.2 g/mol)

= 0.02335 mol

Number of BAL molecules = moles of BAL x Avogadro number

= 0.02335 mol x 6.022 x 10^ 23

= 1.4 x 10^ 22

Then,each BAL binds with 1 As atom. Number o As atoms that can be removed by binding

= 1.4 x 10^ 22

B. BAL molecular formula is C3H8OS2 , so when 1 H si removed and Hg is bonded we get the new formula as C3H7OS2Hg

Molar mass of complex = ( 3 x C atomic mass) + ( 7 x H atomic mass) + O atomic mass + ( 2 x S atomic mass ) + Hg atomic mass

= ( 3 x 12 amu) + ( 7 x 1 amu) + 16 amu + ( 2 x 32 amu) + ( 200.6 amu)

= 323.8 amu

Mass percent of Hg in complex

= 100 x Hg atomic mass / complex molar mass

= ( 100 x 200.6 amu) / ( 323.8 amu)

= 61.95 %

Thus, the mass percent of Hg in a BAL-Hg complex is 61.95 %.

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Answer:

Calculate the number of moles of NaOH:

molar mass of NaOH = 23.0 g/mol (Na) + 16.0 g/mol (O) + 1.0 g/mol (H) = 40.0 g/mol

moles of NaOH = mass / molar mass = 28.1 g / 40.0 g/mol = 0.7025 mol

Use stoichiometry to determine the number of moles of Na2SO4 produced:

From the balanced chemical equation, we see that 2 moles of NaOH react to form 1 mole of Na2SO4, so:

moles of Na2SO4 = 0.7025 mol NaOH × (1 mol Na2SO4 / 2 mol NaOH) = 0.35125 mol Na2SO4

Therefore, 28.1 g of sodium hydroxide will produce 0.35125 mol of sodium sulfate.

Explanation:

Answer:

1.An atom is the defining structure of an element, which cannot be broken by any chemical means. A typical atom consists of a nucleus of positively-charged protons and electrically neutral neutrons with negatively-charged electrons orbiting this nucleus.

2.a chemical process is a method or means of somehow changing one or more chemicals or chemical compounds.

3. a process that involves rearrangement of the molecular or ionic structure of a substance, as opposed to a change in physical form or a nuclear reaction.

Answer:

Option A. LR = N2O4, 45.7g N2 formed

Explanation:

The balanced equation for the reaction is given below:

N2O4(l) + 2N2H4(l) → 3N2(g) + 4H2O(g)

Next, we shall determine the masses of N2O4 and N2H4 that reacted and mass of N2 produced from the balanced equation. This is illustrated below:

Molar mass of N2O4 = 92.02 g/mol

Mass of N2O4 from the balanced equation = 1 x 92.02 = 92.02 g

Molar mass of N2H4 = 32.05 g/mol

Mass of N2H4 from the balanced equation = 2 x 32.05 = 64.1g

Molar mass of N2 = 2x14.01 = 28.02g/mol

Mass of N2 from the balanced equation = 3 x 28.02 = 84.06g

Summary:

From the balanced equation above,

92.02g of N2O4 reacted with 64.1g of N2H4 to produce 84.06g of N2.

Next, we shall determine the limiting reactant. This can be obtained as follow:

From the balanced equation above,

92.02g of N2O4 reacted with 64.1g of N2H4.

Therefore, 50g of N2O4 will react with = (50 x 64.1)/92.02 = 34.83g of N2H4.

From the calculations made above, we can see that only 34.83g out 45g of N2H4 is required to react completely with 50g of N2O4.

Therefore, N2O4 is the limiting reactant and N2H4 is the excess reactant.

Finally, we shall determine the mass of N2 produced from the reaction.

In this case the limiting reactant will be used as it will produce the maximum yield of N2 since all of it is used up in the reaction.

The limiting reactant is N2O4 and the mass N2 produced can be obtained as illustrated below:

From the balanced equation above,

92.02g of N2O4 reacted to produce 84.06g of N2.

Therefore 50g of N2O4 will react to produce = (50 x 84.06)/92.02 = 45.7g of N2.

Therefore, 45.7g of N2 were produced from the reaction.

At the end of the day,

The limiting reactant is N2O4 and 45.7g of N2 were produced from the reaction.

Answer:

C)The same bond in a different molecule has a different energy. For example, O-H in water versus ethanol has different energies.

Explanation:

This is true going by the the statement about the bond energies and the bonding being different among the various elements. In the example given which is between ethanol and water, the bonds which exist among the elements is stronger in water than in ethanol. That is why, ethanol is easily combustible than water.

Answer:

The same bond in a different molecule has a different energy. For example, O-H in water versus ethanol has different energies.

Explanation:

Answer:

Photosynthesis, Respiration, Combustion, Anaerobic Respiration

Explanation:

Im not 100% sure if this is what you are looking for but it should be correct. Hope this helps! :)

Answer:

51 L

Explanation:

Step 1: Given data

Step 2: Calculate the final volume of nitrogen

The volume of a gas is inversely proportional to the pressure. If we consider nitrogen as an ideal gas at a constant temperature, we can find the final volume using Boyle's law.

P₁ × V₁ = P₂ × V₂

V₂ = P₁ × V₁ / P₂

V₂ = 90 kPa × 22.5 L / 40 kPa

V₂ = 51 L

100 mL of 2.0 M HNO3 is needed to neutralize 40.0 mL of 5.0 M NaOH.

To determine the volume of 2.0 M HNO3 needed to neutralize 40.0 mL of 5.0 M NaOH, we can use the concept of stoichiometry and the balanced chemical equation for the neutralization reaction between HNO3 and NaOH.

The balanced chemical equation for the reaction is:

HNO3 + NaOH → NaNO3 + H2O

From the balanced equation, we can see that the stoichiometric ratio between HNO3 and NaOH is 1:1. This means that 1 mole of HNO3 reacts with 1 mole of NaOH.

First, let's calculate the number of moles of NaOH in 40.0 mL of 5.0 M NaOH:

moles of NaOH = volume (in L) × concentration (in M)

moles of NaOH = 0.040 L × 5.0 M = 0.2 moles

Since the stoichiometry is 1:1, we know that 0.2 moles of HNO3 are required to neutralize 0.2 moles of NaOH.

Now, let's calculate the volume of 2.0 M HNO3 needed to provide 0.2 moles of HNO3:

volume of HNO3 = moles of HNO3 / concentration (in M)

volume of HNO3 = 0.2 moles / 2.0 M = 0.1 L or 100 mL

Therefore, 100 mL of 2.0 M HNO3 is needed to neutralize 40.0 mL of 5.0M NaOH.

It's important to note that during the neutralization reaction, the reaction goes to completion. However, in practice, it is recommended to add the acid slowly and carefully while continuously monitoring the pH to ensure complete neutralization and avoid over-titrating.

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The activity that we would have after 15 minutes would be  0.625 pCi.

The half-life, when referring to radioactive decay, is the amount of time needed for half of the radioactive isotopes in a sample to decay. Because they are unstable, radioactive isotopes spontaneously decay into other isotopes or elements. Each radioactive isotope has a distinctive attribute called a half-life that doesn't change over time.

We know that;

N/No = (1/2)^t/t1/2

N =No(1/2)^t/t1/2

N = 5(1/2)^15/5

N = 0.625 pCi

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Mangrove forests are areas in estuaries that are occupied by salt and water. Mesohaline  estuarine zone is conducive to the growth of mangrove forests.

The intertidal areas of tropical and subtropical coastlines are home to an assortment of salt-tolerant plants and shrubs known as mangroves.

Between the river's delta section and the remaining land, there is a mangrove area where the sea meets the river.

They flourish luxuriantly where freshwater and saltwater meet and where mu collected deposits make up the sediment.

In this location, salt marshes extend well inland, while estuary habitats cover substantial amounts along tidal rivers. Mangrove forests, often known as mangals, are vast networks that line the Gulf of Mexico and Florida's southern coast.

Thus, option B is correct.

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Answer:

C

Explanation: I think

Answer:

K2CO3 is the salt

Explanation:

K2CO3 is the salt

since, H2O is a liquid

so, it's lefting K2CO3 a salt.

The correct answer is 1.5 m/s

Explanation:

To find the average speed of the movement of a body, for example, the movement of the marble. The first step is to know the total distance traveled and the time of the movement. These two details can be found in the graph presented, in this, the maximum distance (vertical axis) is 15 meters and at this distance, the time is 10 seconds. Now, with this information we can use the formula Average speed = Total distance ÷ Total time.

\(Average speed = \frac{15 meters}{10 seconds}\)

\(Average speed= 1.5 m/s\)

According to this, the correct answer is 1.5 m/s. Also, meters per second or m/s is the correct unit because the distance is provided in meters (m) and the time is provided in seconds (s).

Answer:

1.5ms took the quiz got it wrong but heres the correct answer

Explanation:

Answer:

The trait of the other cactus stopped it from being able to reproduce and survive.

Answer:

A

Explanation:

I had the exact same question on my test and I got it right

Answer:

Number of atoms = 5.1345 x 10²³

Explanation:

Given:

Mass of sodium = 19.6

Find:

Number of atoms

Computation:

We know that atomic mass of sodium is 22.98

So,

Number of atoms = [Mass of sodium/atomic mass of sodium]Avogadro's number

Number of atoms = [19.6 / 22.98]6.02 x 10²³

Number of atoms = 5.1345 x 10²³

can i have Brainliest i need 1 more

Answer:

30 yard per second

Explanation:

300/10 = 30

Answer:

Concentration C = 0.0189 mol/L

Explanation:

From the given information:

Let consider the formula used in calculating the concentration according to Beer's law:

\(\mathtt{A =\varepsilon \times L \times C}\) --- (1)

here;

A = absorbance

ε = coefficient of molar absorptivity

L = path length

C = concentration (mol/L)

Also, from Beer law plot:

y = mx+b

where,

y represent absorbance A

b represents intercept

m represents the coefficient of molar absorptivity ε

and x represents the concentration(C).

replacing the substituted entities

A = ε × C + b ---- (2)

Making the concentration the subject of the above formula:

\(C = \dfrac{A-b}{\varepsilon}\)----(3)

From y = 11.589x - 0.0002

A = 11.589 *C - 0.0002

Given that:

A = 0.219

∴

0.219 = 11.589 *C - 0.0002

0.219 + 0.0002 =  11.589 *C

C = 0.2192/11.589

C = 0.0189 mol/L

The percent composition of CuBr₂ is approximately 28.46% of Cu and 71.54% of Br.

To determine the percent composition of CuBr₂ (copper(II) bromide), we need to calculate the mass of each element in the compound and then divide it by the molar mass of the entire compound.

The molar mass of CuBr₂ can be calculated by adding up the atomic masses of copper (Cu) and bromine (Br) in the compound. The atomic masses of Cu and Br are approximately 63.55 g/mol and 79.90 g/mol, respectively.

Molar mass of CuBr₂ = (63.55 g/mol) + 2(79.90 g/mol) = 223.35 g/mol

Now, let's calculate the percent composition of each element in CuBr₂:

Percent composition of copper (Cu):

Mass of Cu = (63.55 g/mol) / 223.35 g/mol × 100% ≈ 28.46%

Percent composition of bromine (Br):

Mass of Br = 2(79.90 g/mol) / 223.35 g/mol × 100% ≈ 71.54%

Therefore, the percent composition of CuBr₂ is approximately:

- Copper (Cu): 28.46%

- Bromine (Br): 71.54%

These values represent the relative mass percentages of copper and bromine in the compound CuBr₂.

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The element with the least tendency to form an ion is C) Kr.

The ionization tendency of an element is determined by its electron configuration and the energy required to remove an electron from its valence shell. The element with the least tendency to form an ion is the one that requires the highest energy to remove an electron and form a positive ion.

In the case of Kr (Krypton), it has a full electron configuration in its valence shell, making it difficult to remove an electron and form an ion. On the other hand, elements like Ca (Calcium), K (Potassium), and Se (Selenium) have relatively low ionization energies and can easily form positive ions.

Key points:

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Precision relates to the consistency and reproducibility of measurements, while accuracy reflects how close measurements are to the true value.

Precision and accuracy are two important concepts in the context of errors in measurements. While they both pertain to the quality of data, they refer to different aspects.

Precision refers to the degree of consistency or reproducibility in a series of measurements. It reflects the scatter or spread of data points around the average value. If the measurements have low scatter and are tightly clustered, they are considered precise. On the other hand, if the measurements have a high scatter and are widely dispersed, they are considered imprecise.

Accuracy, on the other hand, refers to the closeness of measurements to the true or target value. It represents how well the measured values align with the actual value. Accuracy is achieved when measurements have a small systematic or constant error, which is the difference between the average measured value and the true value.

Errors in measurements can be classified into two types: random errors and systematic errors.

Random errors are associated with the inherent limitations of measurement instruments or fluctuations in the measurement process. They lead to imprecise data and affect the precision of measurements. Random errors can be reduced by repeating measurements and calculating the average to minimize the effect of individual errors.

Systematic errors, on the other hand, are caused by consistent biases or inaccuracies in the measurement process. They affect the accuracy of measurements and lead to a deviation from the true value. Systematic errors can arise from factors such as instrumental calibration issues, environmental conditions, or experimental techniques. These errors need to be identified and minimized to improve the accuracy of measurements.

In summary, precision refers to the degree of consistency or reproducibility of measurements, while accuracy refers to the closeness of measurements to the true value. Random errors affect precision, while systematic errors affect accuracy. To ensure high-quality measurements, both precision and accuracy need to be considered and appropriate techniques should be employed to minimize errors.

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Answer:

Reactions are given below.

Explanation:

Chemical equation:

CuCl₂ + NaOH     →    Cu(OH)₂ + NaCl

Balanced Chemical equation:

CuCl₂(aq) + 2NaOH(aq)     →    Cu(OH)₂(s) + 2NaCl(aq)

Ionic equation:

Cu²⁺(aq) + 2Cl⁻(aq) + 2Na⁺(aq) + 2OH⁻(aq) →  Cu(OH)₂(s) + 2Na⁺(aq) + 2Cl⁻ (aq)

Net ionic equation:

H⁺(aq) + OH⁻(aq) → H₂O(l)  

The Cl⁻(aq) and Na⁺ (aq) are spectator ions that's why these are not written in net ionic equation. The Cu(OH)₂ can not be splitted into ions because it is present in solid form.

Spectator ions:

These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.  

Answer:

The world's overall tree leader is Russia, with 642 billion trees, reports The Washington Post, which analyzed the data presented by researchers. Next is Canada with 318 billion trees and Brazil with 302 billion. The United States comes in fourth with 228 billion trees.

The cardboard sleeves reduce the heatness from the coffee cup. So then the cosumer does not get a burn.

Answer:

0.0123 moles

Explanation:

Concentration = Moles / Volume of solution

or you can rearrange the formula to get

Moles = concentration (moles/liter)  x  volume of solution (liter)

First convert your volume to L instead of mL.  35mL = 0.035L

moles  =  0.350 moles/liter   x    0.035 liter  (liters cancel out)

moles = 0.0123

For each color of paper, the part of white light that is reflected depends on the color of the paper. When white light strikes an object, some of the light is absorbed by the object, some of it is transmitted through the object, and some of it is reflected.

The color of the object that we see is the color of the light that is reflected by the object.

For example, when white light strikes blue paper, the blue color of the paper absorbs all the other colors of the spectrum except blue, which is reflected back to our eyes. This is why we see the paper as blue. Similarly, when white light strikes red paper, the red color of the paper absorbs all the other colors except red, which is reflected back to our eyes. This is why we see the paper as red.

In summary, the color of an object is determined by the color of the light that is reflected by the object, and the color of the light that is reflected depends on the color of the object and the colors of the spectrum that are absorbed or transmitted by the object.

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