The bricks that hold up the walls and ceiling in the classroom

Answers

Answer 1

The bricks that hold up the walls and the ceiling in the classroom were compared to the cell organelles. The cell organelle acts like bricks and holds the walls called cytoskeleton.

The cell organelles are considered the subcellular structure that may perform a specific function in the cell. Some cell organelles are plastids, mitochondria, lysosomes, and cytoskeleton. The cytoskeleton is a structure that provides shape and structure to the body. It gives mechanical support to the body and helps in movement and locomotion.

Hence, cell organelles and the cytoskeleton is compared to the bricks that hold up the wall and ceiling in the classroom.

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Related Questions

If the distance between slits on a diffraction grating is 0. 50 mm and one of the angles of diffraction is 0. 25°, how large is the path difference? nm How many orders of bright lines does this equal for red light with a wavelength of 650 nm? wavelengths.

Answers

The distance the wave traveled between the two-point is the path difference. The path difference will be 2200 nm and 3 orders of bright lines do this equal red light with a wavelength of 650 nm.

What is diffraction grating?

A diffraction grating is a type of optical instrument obtained with a continuous pattern. The pattern of the diffracted light by a grating depends on the structure and number of elements present.

The equation of diffraction grating is given as

\(\rm n\lambda=dsin\phi\\\\\rm n\lambda=0.50\times10^{-3}\times sin(0.25) \\\\ n\rm \lambda=2.18\times10^{-6} \;m \\\\\rm n\lambda=2200\;nm\)

Hence the path difference will be 2200 nm.

\(\rm n\lambda=2200\;nm \\\\\rm n\times650=2200 \\\\\rm n=3.38\)

n= 3

Hence 3 orders of bright lines do this equal red light with a wavelength of 650 nm.

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In which image below is the angle of refraction the greatest?

In which image below is the angle of refraction the greatest?

Answers

Answer:

Explanation:

Angle of refraction is the angle made by refracted ray with the normal at the point of incidence . In this figure , refracted ray has been shown by line having arrow-head . Normal has been shown by broken line .

We observe that in figure D , angle made by refracted ray with normal is greatest . So figure D is the answer.

The  image where the angle of refraction is the greatest is the image D

What is the angle of refraction?

The angle of refraction is the angle that the refracted ray made with the x-axis.

The higher the angle between the refracted ray and the x-axis, the higher the angle of refraction and vice versa.

From the given diagram, we can see that the  image where the angle of refraction is the greatest is the image D

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A guitar string is set into vibration with a frequency of 512 Hz. How many oscillations does it undergo each minute?A) 512B) 30,700C) 1610D) 8.53E) 26.8

Answers

The guitar string undergoes 30,720 oscillations each minute, which is not among the given options. However, it is closest to option B) 30,700.

We're given that the frequency of the guitar string's vibration is 512 Hz, which means it undergoes 512 oscillations per second. We need to find out how many oscillations it undergoes each minute.
Step 1: Convert the frequency from oscillations per second (Hz) to oscillations per minute.
To do this, we'll multiply the frequency (in Hz) by the number of seconds in a minute.

Step 2: Calculate the number of oscillations per minute.
Frequency (Hz) = 512 oscillations/second
Number of seconds in a minute = 60 seconds
Oscillations per minute = (Frequency in Hz) * (Number of seconds in a minute)
Oscillations per minute = (512 oscillations/second) * (60 seconds)

Step 3: Calculate the result.
Oscillations per minute = 30720 oscillations
It is important to note that the actual answer is 30,720, but if you must choose from the given options, B) 30,700 is the closest approximation.

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what forms of energy best describes the energy stored in food

Answers

Answer:

probably potentially energy

Explanation:

hopefully this helps

Find the center of mass of the region bounded by y=9-x^2 y=5/2x , and the z-axis. Center of Mass = __?
Note: You can earn partial credit on this problem.

Answers

The centre of mass of the region is bounded by y=9-x^2 y=5/2x, and the z-axis is (3.5, 33/8). Formulae used to find the centre of mass are as follows:x bar = (1/M)*∫∫∫x*dV, where M is the total mass of the system y bar = (1/M)*∫∫∫y*dVwhere M is the total mass of the system z bar = (1/M)*∫∫∫z*dV, where M is the total mass of the systemThe region bounded by y=9-x^2 and y=5/2x, and the z-axis is shown in the attached figure.

The two curves intersect at (-3, 15/2) and (3, 15/2). Thus, the total mass of the region is given by M = ∫∫ρ*dA, where ρ = density. We can assume ρ = 1 since no density is given.M = ∫[5/2x, 9-x^2]∫[0, x^2+5/2x]dAy bar = (1/M)*∫∫∫y*dVTherefore,y bar = (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]y*dA= (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]ydA...[1].

The limits of integration in the above equation are from 5/2x to 9-x^2 for x and from 0 to x^2+5/2x for y.To evaluate the above integral, we need to swap the order of integration. Therefore,y bar = (1/M)*∫[0, 3]∫[5/2, (9-y)^0.5]y*dxdy...[2].

The limits of integration in the above equation are from 0 to 3 for y and from 5/2 to (9-y)^0.5 for x.Substituting the values and evaluating the integral, we get y bar = (1/M)*[(9-5/2)^2/2 - (9-(15/2))^2/2]= (1/M)*(25/2)...[3].

Also, the x coordinate of the center of mass is given by,x bar = (1/M)*∫∫∫x*dVTherefore,x bar = (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]x*dA= (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]xdA...[4].

The limits of integration in the above equation are from 5/2x to 9-x^2 for x and from 0 to x^2+5/2x for y.To evaluate the above integral, we need to swap the order of integration. Therefore, x bar = (1/M)*∫[0, 3]∫[5/2, (9-y)^0.5]xy*dxdy...[5].

The limits of integration in the above equation are from 0 to 3 for y and from 5/2 to (9-y)^0.5 for x.

Substituting the values and evaluating the integral, we get x bar = (1/M)*[63/8]= (1/M)*(63/8)...[6]Thus, the centre of mass of the region is bounded by y=9-x^2 y=5/2x, and the z-axis is (3.5, 33/8).

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A 50Kg block is pulled up in an inclined plane at angle of 53° to the horizontal, if the surface is frictionless, what is the efficiency of the inclined?

Answers

Efficiency is defined as the ratio of useful work output to total work input. In this case, the useful work output is the work done in lifting the block, and the total work input is the work done by the pulling force.

The work done in lifting the block is given by the formula: work = force x distance x cos(theta), where theta is the angle between the force and the displacement.

In this case, the force is the weight of the block, which is given by: F = m x g = 50 kg x 9.8 m/s^2 = 490 N.

The distance lifted by the block is given by: d = h / sin(theta), where h is the height the block is lifted.

Let's assume that the block is lifted to a height of 1 meter. Then, we have: d = 1 / sin(53) = 1.28 meters.

So, the work done in lifting the block is: work = 490 N x 1.28 m x cos(53) = 295 J.

The work done by the pulling force is given by: work = force x distance, where the distance is the length of the inclined plane. Let's assume that the length of the inclined plane is 2 meters. Then, we have: work = 490 N x 2 m = 980 J.

Therefore, the efficiency of the inclined plane is: efficiency = useful work output / total work input = 295 J / 980 J = 0.301 or 30.1%.

When balancing a chemical equation, can a coefficient within a chemical equation be adjusted to
balance the chemical equation?

Answers

The answer is down ther

Even though chemical compounds are broken up and new compounds are formed during a chemical reaction, atoms in the reactants do not disappear, nor do new atoms appear to form the products. In chemical reactions, atoms are never created or destroyed. The same atoms that were present in the reactants are present in the products—they are merely reorganized into different arrangements. In a complete chemical equation, the two sides of the equation must be present on the reactant and the product sides of the equation.

Coefficients and Subscripts

There are two types of numbers that appear in chemical equations. There are subscripts, which are part of the chemical formulas of the reactants and products; and there are coefficients that are placed in front of the formulas to indicate how many molecules of that substance is used or produced.

The subscripts are part of the formulas and once the formulas for the reactants and products are determined, the subscripts may not be changed. The coefficients indicate the number of each substance involved in the reaction and may be changed in order to balance the equation. The equation above indicates that one mole of solid copper is reacting with two moles of aqueous silver nitrate to produce one mole of aqueous copper (II) nitrate and two atoms of solid silver.

Hope this help you.

If the volume of a rock is 8 cm3 and its' mass is 16 g. what is its density?

Answers

The answer is 2 g/ cm3

density = mass/volume

density=16/8

Density=2g/cm^2

A ray diagram is shown what does the letter x represent?

Answers

Answer: angle of incidence

Answer:

A) angle of incidence

Explanation:

A 500 kg roller coaster car crests a 20m high hill at a speed of 10 m/s. It then rolls down the other side, all the way to ground level, and climbs a second hill. What is the speed of the car when it is 10 m up the second hill

Answers

The speed of the roller coaster car when it is 10 m up the second hill is approximately 12.17 m/s.

To determine the speed of the roller coaster car when it is 10 m up the second hill, we can use the principle of conservation of mechanical energy.

The total mechanical energy of the car remains constant throughout the motion, neglecting any energy losses due to friction or air resistance.

The total mechanical energy (E) of the car can be expressed as the sum of its kinetic energy (KE) and potential energy (PE):

E = KE + PE

Initially, when the car crests the first hill at a height of 20 m, all of its energy is in the form of potential energy since its velocity is zero at the crest. Therefore, at the crest of the first hill:

E1 = PE1

When the car rolls down to the ground level, all of its potential energy is converted into kinetic energy since its height is zero. Therefore, at the bottom of the first hill:

E2 = KE2

Finally, when the car climbs the second hill to a height of 10 m, its mechanical energy will be the sum of kinetic and potential energy. Therefore, at a height of 10 m on the second hill:

E3 = KE3 + PE3

According to the principle of conservation of mechanical energy, the total mechanical energy at each point remains the same:

E1 = E2 = E3

Now let's calculate the speeds of the car at the different points:

At the crest of the first hill (20 m high), the potential energy is given by:

PE1 = m * g * h1

where:

m = mass of the car (500 kg)

g = acceleration due to gravity (approximately 9.8 m/s^2)

h1 = height of the crest (20 m)

PE1 = 500 kg * 9.8 m/s^2 * 20 m

PE1 = 98,000 J

At the bottom of the first hill (ground level), the kinetic energy is given by:

KE2 = (1/2) * m * v2^2

where:

v2 = speed of the car at the bottom of the first hill (10 m/s)

KE2 = (1/2) * 500 kg * (10 m/s)^2

KE2 = 25,000 J

At a height of 10 m on the second hill, the potential energy is given by:

PE3 = m * g * h3

where:

h3 = height of the second hill (10 m)

PE3 = 500 kg * 9.8 m/s^2 * 10 m

PE3 = 49,000 J

Since the total mechanical energy is conserved:

E1 = E2 = E3

PE1 = KE2 = KE3 + PE3

Solving for KE3:

KE3 = PE1 - PE3 + KE2

KE3 = 98,000 J - 49,000 J + 25,000 J

KE3 = 74,000 J

Now, we can find the speed of the car at a height of 10 m on the second hill using the kinetic energy formula:

KE3 = (1/2) * m * v3^2

Solving for v3:

v3^2 = (2 * KE3) / m

v3^2 = (2 * 74,000 J) / 500 kg

v3^2 = 148 J / kg

v3 = sqrt(148 J / kg)

v3 ≈ 12.17 m/s

Therefore, the speed of the roller coaster car when it is 10 m up the second hill is approximately 12.17 m/s.

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if load is 10 kn, cross sectionl area is 2 square mm, contact area = 5 square mm. what will be bearing stress?

Answers

The bearing stress in this scenario is 2 kN/mm². To calculate the bearing stress, we need to use the formula:
Bearing Stress = Load / Contact Area


Substituting the given values:
Bearing Stress = 10 kn / 5 square mm
Bearing Stress = 2 N/mm^2

It is important to note that bearing stress is a measure of the force per unit area exerted on the contact surface between two components. In this case, the load is distributed over an area of 5 square mm, resulting in a bearing stress of 2 N/mm^2. It is important to ensure that the bearing stress is within the allowable limits to prevent failure or damage to the components.


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a busis moving with the initial velocity 10m/s . after 4 seconds, the velocity becomes 30m/s . find the acceleration produce by bus,......please I need help​

Answers

Answer:

5 m/s²

Explanation:

Use the acceleration formula: \(a=\frac{v_f-v_i}{t}\)

a = acceleration (m/s²)vf = final velocity (m/s)vi = initial velocity (m/s)t = time (s)

Based on the information given to us by the prompt, we know:

vi = 10 m/svf = 30 m/st = 4 s

Substitute these values for the variables to calculate the acceleration:

\(a=\frac{30-10}{4}\\\\a=\frac{20}{4}\\\\a=5\)

Therefore, the acceleration of the bus is 5 m/s².

Length, time, mass, and temperature are four of the five values that need to be measured with consistent units. what is the fifth value?

Answers

Length, time, mass, and temperature are four of the five values that need to be measured with consistent units the last one is eletric current.

What is electrical current?

Electric current is the orderly movement between electric charges present in a metallic conductor. This organization of movement happens when an electric field is created inside this conductor, causing its free electrons to develop an orderly movement.

Electric current is a scalar quantity. Its unit of measurement, according to the International System of Units, is the ampere (A). This unit measures the magnitude of the electric charge that crosses the cross section of a conductor every second.

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What is the amount of energy transferred by a force acting through a distance called?

Answers

The amount of energy that is transferred by a force acting through a distance is known as work.

If we apply a force on an object, this force transforms into kinetic motion and distance is moved by the object. When there is displacement due to this force, work is said to be done.

Work is actually the transfer of mechanical energy from one substance to another. As work is the result of the transfer of energy, it has the same unit as energy, i.e., joule.

When work is done, the kinetic energy of the object is changed, or it has altered potential energy. Potential energy may change into kinetic energy due to the application of force. If position or shape is changed due to force, then we have altered potential energy.

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you are superman (or superwoman). with what super-human feat could you increase the length of a tidal day?

Answers

The correct option is A, accelerate the rotation of the moon across the sun.

The Sun is a star that is at the center of the solar system. It is classified as a G-type main-sequence star, which means that it is a relatively average star in terms of size, temperature, and luminosity. The Sun is about 4.6 billion years old and is expected to remain stable for another 5 billion years or so before it begins to run out of fuel and eventually dies.

The Sun is a massive object, with a diameter of about 1.39 million kilometers, which is about 109 times the size of Earth. It is made up mostly of hydrogen and helium, which undergo nuclear fusion in its core, producing enormous amounts of energy that radiate out into space as light and heat. This energy drives the weather and climate on Earth, and also powers all life on our planet.

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Complete Question:

you are a superman (or superwomen). With what terrific-human feat may want to you growth the length of a tidal day?

a. accelerate the rotation of the moon across the sun

b. increase the mass of the moon

c. speed up the rotation of the earth around its axis

d. slow the rotation of the moon across the earth

e. decrease the mass of the earth

A
heat engine is measured to have 30% efficiency. Is the theoretical
efficiency going to be greater or less than that? Why?

Answers

The theoretical efficiency is greater than that of the actual efficiency of the engine. This is because heat engine always produces some waste heat.

The Second Law of Thermodynamics states that a heat engine cannot be 100% efficient. In practice, a heat engine is only 100% efficient when it is operating at about 30-50% efficiency.

If we were to multiply this by 100, we would get the efficiency as a percent: 49%. This is the theoretical maximum efficiency. If we were to actually build an engine, it would be less efficient than the theoretical engine. The theoretical engine that can achieve this theoretical maximum efficiency is called the Carnot Engine.

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95 cm = ________________ m
Will give brainlists
Unit 1 Test Physical Science need this to help my grade

Answers

Answer:

0.95 metre

Explanation:

divide the value in centimeters by 100 because 1 meter equals 100 centimeters.

So, 95 centimeters = 95/100

= 0.95 meter.

the wave speed on a string is 150 m/s when the tension is 66.0 n . part a what tension will give a speed of 185 m/s ?

Answers

To solve for the tension needed to give a speed of 185 m/s, we can use the following formula:
wave speed = square root of (tension/linear mass density)We are given that the wave speed is 150 m/s when the tension is 66.0 N. We can use this to solve for the linear mass density 150 m/s = square root of (66.0 N/linear mass density)Squaring both sides, we get 22500 m^2/s^2 = 66.0 N/linear mass density

Solving for the linear mass density, we get linear mass density = 66.0 N/22500 m^2/s^2
linear mass density = 0.002933 kg/m Now we can use this linear mass density to solve for the tension needed to give a speed of 185 m/s: 185 m/s = square root of (tension/0.002933 kg/m) Squaring both sides, we get 34225 m^2/s^2 = tension/0.002933 kg/m Solving for the tension, we get tension = 34225 m^2/s^2 x 0.002933 kg/m
tension = 100.3 N Therefore, a tension of 100.3 N is needed to give a speed of 185 m/s. To find the tension that will give a speed of 185 m/s, we'll use the wave speed formula for a string, which is:v = √(T/μ) Where v is the wave speed, T is the tension, and μ is the linear mass density of the string. First, we need to find μ using the given information.
For the initial condition v1 = 150 m/s T1 = 66.0 N 150 = √(66.0/μ) 150² = 66.0/μ
μ = 66.0/(150²) Now, we need to find the new tension (T2) that will give a speed of 185 m/s:
v2 = 185 m/s 185 = √(T2/μ) To find T2, we can plug in the value of μ we found earlier:
185 = √(T2/(66.0/(150²))) 185² = T2/(66.0/(150²)) T2 = 185² * (66.0/(150²)) Now, calculate the value of T2
T2 ≈ 101.64 N So, the tension that will give a wave speed of 185 m/s is approximately 101.64 N.

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1. The electric field strength between two parallel plates separated by 6.00 cm is 7.50 × 104 V/m . (a) What is the potential difference between the plates? (b) The plate with the lowest potential is taken to be zero volts. What is the potential 1.00 cm from that plate and 6.00 cm from the other?

Answers

Answer:

a)4500V

b)750V

Explanation:

Given:

Distance between the plate=

6.00 cm

We need to convert to m

Then the Distance between the plate=

0.06m

electric field strength between two parallel plates =

7.50 × 104 V/m .

Then E= 7.50 × 104 V/m .

(a) What is the potential difference between the plates?

potential difference between the plates can be calculated using the formula below

Δ Vab=ED

Where E is the given electric field strength

D= The Distance between the plate

ΔVab=7.50 × 10⁴V/m ×

0.06m

= 4500V

(b) The plate with the lowest potential is taken to be zero volts. What is the potential 1.00 cm from that plate and 6.00 cm from the other?

the potential 1cm from the zero volt plate

Then the 1cm must be converted to m

= 0.01m

Let us say plate A as the plate at 0 volts:

The potential increases linearly going from plate A (0 V) to plate B (4500V).

Therefore,if the potential difference between A and B, separated by 6 cm, is 4500 V, then the potential difference between A and a point located at 1 cm from A is can be calculated also

If the plate with Lowest potential is taken to be zero then

=ΔVab=Vab-Vb=Va-0=Va=ED

Va=7.50 × 10⁴V/m × 0.01=750V

The picture shows a bicyclist increasing speed while riding down a hill during a bicycle race.

Which statements accurately describe the potential and kinetic energy of this bicyclist?

The picture shows a bicyclist increasing speed while riding down a hill during a bicycle race.Which statements

Answers

The statement "Kinetic energy increases. Potential energy decreases" accurately describes the potential and kinetic energy of the bicyclist.

What is Kinetic Energy?

The kinetic energy of an object is directly proportional to its mass and the square of its velocity. This means that an object with a larger mass or higher velocity will have a greater kinetic energy than an object with a smaller mass or lower velocity.

As the bicyclist moves downhill, their speed increases, and therefore their kinetic energy increases. At the same time, the height of the bicyclist above the ground (and therefore their potential energy) decreases as they move downhill. This is because potential energy is energy that is stored in an object due to its position or configuration in a force field, and in this case, the force field is gravity. As the bicyclist moves downhill, they are losing potential energy and converting it to kinetic energy, which is the energy of motion.

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Write down the method for the verification of Newton's second law of motion

Answers

We can verify the Newton's second law of motion mathematically by using the momentum impulse relation.

The rate of change of a body's momentum is directly proportional to the applied force and occurs in the direction in which the force operates, according to Newton's Second Law of Motion. where F is the applied force, M is the body's mass, and A is the resulting acceleration.

One way to state Newton's second law of motion is as follows:

Force is inversely correlated with change in momentum and time.

Now, F is directly proportional to mv-mu t or m(v-u) t [where (v-u) represents the acceleration, or change in velocity].

As a result, we discover that F is inversely proportional to m.

By using a constant k, this relationship F is directly proportional to ma can be transformed into an equation.

Thus, F=kma (where k is constant)

The preceding equation is now F=ma or Force= Mass*Acceleration because the value of k in SI units is 1.

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what would happen if a permanent magnet is placed on top of a straight wire

Answers

When a permanent magnet is placed on top of a straight wire, a magnetic field is produced in the region surrounding the wire due to the motion of charges in the wire. The magnetic field produced by the wire interacts with the magnetic field of the permanent magnet and causes a force to be exerted on the wire.

The direction of the force is perpendicular to both the magnetic field and the current in the wire. If the wire is not fixed in place, it will experience a force and move in a direction that is perpendicular to both the magnetic field and the current in the wire. This phenomenon is known as the Lorentz force, which is the force that is exerted on a charged particle when it moves in an electromagnetic field.

The direction of the force is given by the right-hand rule, which states that if the thumb of the right hand points in the direction of the current, and the fingers point in the direction of the magnetic field, then the palm of the hand will point in the direction of the force. The magnitude of the force is proportional to the current in the wire and the strength of the magnetic field.

Therefore, the stronger the magnetic field or the current, the greater the force that is exerted on the wire. The Lorentz force is the basis for the operation of many devices such as motors, generators, and transformers.

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21. What hazards do you see in the scene below? Which zones are open? What would you do to avoid the hazards?

21. What hazards do you see in the scene below? Which zones are open? What would you do to avoid the

Answers

The answers include the following:

The hazards which one can see in the scene below is the possibility of another vehicle stopping in front or colliding with the other.The open zone is on the left lane.The things which can be dome to prevent is not to over speed.

What are Hazards?

This is referred to as any source of potential damage, harm or adverse health effects on something or someone.

In the diagram given, we can see a car coming from behind and one in front which wants to enter the lane which makes them potential hazards as collision may occur which is why overspeeding shouldn't be encouraged to reduce the effect of anything happens.

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A radio announcer's voice is transmitted via radio waves a distance of 998.25 km. How much time, in microseconds, will it take to transmit the wave over this distance?

Answers

A radio wave travels at the speed of light, which is equal to approximately 300,000 km/s.

So, to travel a distance of 998.25 km, the time needed is:

\(\begin{gathered} distance=speed\cdot time\\ \\ 998.25=300000\cdot time\\ \\ time=\frac{998.25}{300000}\\ \\ time=0.0033275\text{ seconds}\\ \\ time=3327.5\text{ microseconds} \end{gathered}\)

Therefore the time required is approximately 3327.5 microseconds.

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An ion is neutral and has no charge.


True
False

Answers

Answer: False

Explanation: need points

How much heat is released by 38 gram sample of water to freeze

Answers

The heat released = 38 x specific latent heat of ice
approx = 38 x 334 = 12692 Joules

If a football player hits the ball with a force of 50 N, determine the reaction force. Science Newton’s third law of motion suggests that forces occur in equal and opposite pairs, explain why they do not cancel out each othe​

Answers

The reaction force in this case is also 50 N, and it acts in the opposite direction to the action force. They do not cancel each other out because they act on different objects.

According to Newton's third law of motion, for every action, there is an equal and opposite reaction. This means that when the football player hits the ball with a force of 50 N, the ball exerts an equal and opposite force of 50 N on the player. This force is called the reaction force.

The action force is applied by the football player on the ball, while the reaction force is applied by the ball on the football player.

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Observing that the bulb does not glow in circuit X , Raj changed the circuit as shown in figure Y.
a. What did he observed in circuit Y?

b. Why did the bulb not glow in figure X?

c. What will happen if the number of the cells will increase in circuit Y?

Observing that the bulb does not glow in circuit X , Raj changed the circuit as shown in figure Y.a.

Answers

Answer:

a. He notices that when he kept the compass near the electrical wire with current flowing through it, the compass did not point north; instead, the compass needle pointed in the direction of the current's magnetic field.

b. The bulb did not glow because the current was not sufficient to make it glow.

c. Deflection in the compass will increase further.

Explanation:
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A boy pulls a bag of baseball bats across a ball field toward the parking lot. The bag of bats has a mass of 6. 80 kg, and the boy exerts a horizontal force of 24. 0 n on the bag. As a result, the bag accelerates from rest to a speed of 1. 12 m>s in a distance of 5. 25 m. What is the coefficient of kinetic friction between the bag and the ground?

Answers

The coefficient of kinetic friction between the bag and the ground is found to be 0.0251. It represents the ratio of the frictional force to the normal force acting between them.

In this question, a boy pulls a bag of baseball bats across a ball field toward the parking lot. The bag of bats has a mass of 6.80 kg, and the boy exerts a horizontal force of 24.0 N on the bag. As a result, the bag accelerates from rest to a speed of 1.12 m/s at a distance of 5.25 m. We have to find the coefficient of kinetic friction between the bag and the ground.The formula used to find the coefficient of kinetic friction is given as,μk= (a/g) + μs (1 - a/g), Where, μk = coefficient of kinetic friction, a = acceleration of the body, g = acceleration due to gravity (9.8 m/s2), μs = coefficient of static frictionGiven, Mass of the bag (m) = 6.80 kg, Force applied (F) = 24.0 N, Initial velocity (u) = 0 m/s, Final velocity (v) = 1.12 m/s, Distance covered (s) = 5.25 m, Acceleration (a) = (v2 - u2) / 2s. Substituting the given values, a = (1.12² - 0²) / (2 * 5.25)m/s²a = 0.247m/s². Now, we will use the formula of the coefficient of kinetic friction. μk= (a/g) + μs (1 - a/g)Let's assume the value of μs to be zero.μk= (a/g) + 0 (1 - a/g) = μk= (a/g) + 0 (1 - a/g) = μk = (a/g) = μk = (0.247m/s²) / (9.8m/s²) = μk= 0.0251. Therefore, the coefficient of kinetic friction between the bag and the ground is 0.0251. In order to move the bag, the boy had to overcome friction. From the given values, we calculated the acceleration of the bag, which was found to be 0.247 m/s². Using this acceleration, we can find the coefficient of kinetic friction, which came out to be 0.0251. This value represents the ratio of the frictional force to the normal force acting between the bag and the ground.

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While passing a slower car on the highway, you accelerate uniformly from 17.5 m/s to 29.5 m/s in a time of 11.1 s. how far do you travel during this time?

Answers

When I accelerate uniformly from 17.5 m/s to 29.5 m/s in a time of 11.1 s, I travel 260.85 m

The formula for Uniformly varied rectilinear motion (UVRM) and procedure we will use to solve this exercise is:

x = [(vi + vf) /2] * t

Where:

x = distancevf = final velocityvi = initial velocityt = time

Information about the problem:

vi= 17.5 m/svf = 29.5 m/s t = 11.1 sx= ?

Applying the distance formula, we have:

x = [(vi + vf) /2] * t

x = [(17.5 m/s + 29.5 m/s ) /2] * 11.1 s

x = [(47 m/s ) /2] * 11.1 s

x = (23.5 m/s) * 11.1 s

x = 260.85 m

What is acceleration?

It is a physical quantity that indicates the variation of velocity as a function of time, it is expressed in units of distance per time squared e.g.: m/sec2 ; km/h2

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While passing a slower car on the highway, you accelerate uniformly from 17.5 m/s to 29.5 m/s in a time
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