The given unit step response of a feedback control system \(y(t) = \left(0.8 - e^{-t}(0.8 \cos(t) - 3 \sin(t))\right)u(t)\) is used to answer five questions related to the system's characteristics.
The unit step response provides insights into the behavior of a feedback control system. Let's address the questions using the given unit step response:
Q1. The "first overshoot" refers to the maximum overshoot that occurs in the response. To determine this, we need to analyze the response curve and identify the peak value beyond the steady-state value.
In the given unit step response, the first overshoot can be observed as the maximum positive peak that exceeds the steady-state value of 0.8.
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What is 0.351 as a fraction
Answer:
351/1000
Step-by-step explanation:
Answer:
351/1000
Step-by-step explanation:
Step 1:
0.351 ÷ 1000
Answer:
351/1000
Hope This Helps :)
set up a double integral for calculating the flux of the vector field through the open-ended circular cylinder of radius and height with its base on the xy-plane and centered about the positive z-axis, oriented away from the z-axis. if necessary, enter as theta.
The double integral for calculating the flux of a vector field F through an open-ended circular cylinder of radius r and height h, with its base on the xy-plane and centered about the positive z-axis, oriented away from the z-axis, is given by the expression ∫∫(F · n) r dr dθ, where n is the outward unit normal to the cylindrical surface S and the integration is over the cylindrical surface S.
Let F be the vector field and let S be the open-ended circular cylinder of radius r and height h, with its base on the xy-plane and centered about the positive z-axis. We want to calculate the flux of F through S, oriented away from the z-axis.
To set up the double integral for calculating the flux, we use the divergence theorem:
flux = ∫∫(F · n) dS = ∭(div F) dV
where n is the outward unit normal to the surface S, dS is the surface area element, dV is the volume element, and div F is the divergence of F.
Since S is a cylindrical surface, we can use cylindrical coordinates (r, θ, z) to parameterize the surface and the volume enclosed by S. Specifically, we have:
r ≤ r
0 ≤ θ ≤ 2π
0 ≤ z ≤ h
Then, the double integral for calculating the flux is:
flux = ∫∫(F · n) dS = ∬(F · n) r dr dθ
where n = (cos θ, sin θ, 0) is the outward unit normal to the cylindrical surface S.
Note that we do not need to integrate over the z-variable, since the cylindrical surface is orthogonal to the z-axis, and the divergence of F may not depend on z.
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what the answr
Please explain
The missing angle in the triangle is as follows:
m∠ABC = 54 degrees
How to find angles in a triangle?When lines segment intersect, angle relationships are formed such as vertically opposite angles, adjacent angles etc.
Therefore, let's find m∠ABC.
Hence,
9x - 9 + 3x + 9 = 180 (sum of angles on a straight line)
12x = 180
divide both sides of the equation by 12
x = 180 / 12
x = 15
Therefore,
m∠ABC = 3x + 9(Vertically opposite angles)
m∠ABC = 3(15) + 9
m∠ABC = 45 + 9
m∠ABC = 54 degrees
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The logarithm form of 5^3 =125 is equal to
a. log5 125 = 3 b. log5 125 = 5
c. log3 125 = 5 d. log5 3 = 3
The correct logarithm form is: a. log5 125 = 3
Question is about finding the logarithm form of 5³ = 125 using the given options.
The correct logarithm form is:
a. log5 125 = 3
Here's the step-by-step explanation:
1. The exponential form is given as 5³= 125.
2. To convert it to logarithm form, you have to express it as log(base) (argument) = exponent.
3. In this case, the base is 5, the argument is 125, and the exponent is 3.
4. Therefore, the logarithm form is log5 125 = 3.
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a machine is used to fill 1-liter bottles of a type of soft drink. we can assume that the output of the machine approximately follows a normal distribution with a mean of 1.0 liter and a standard deviation of .01 liter. the firm uses means of samples of 25 observations to monitor the output, answer the following questions: determine the upper limit of the control chart such that it will include roughly 97 percent of the sample means when the process is in control. (3 decimal points are required)
The upper limit of the control chart such that it will include roughly 97 percent of the sample means when the process is in control is 1.008.
For a process with a normal distribution, the mean of the sample means is equal to the population mean and the standard deviation of the sample means is equal to the population standard deviation divided by the square root of the sample size. In this case, the mean of the output is 1.0 liter and the standard deviation is 0.01 liter, so the standard deviation of the sample means is 0.01 / √25 = 0.002.
To construct a control chart for the sample means, we need to determine the upper and lower control limits such that the process is in control when the sample means fall within these limits. Assuming the process is in control, we want to find the upper limit such that roughly 97% of the sample means fall below this limit.
Using the standard normal distribution, the Z-score corresponding to the 97th percentile is approximately 1.88.
Therefore, the upper control limit is 1.0 + 1.88(0.002) = 1.008. Any sample mean above this limit should be investigated for potential process issues.
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while performing a test of details during an audit an auditor determined that the sample results supported the conclusion that the recorded account balance was materially misstated. it was in fact not materially misstated. this situation illustrates
When an auditor has performed a test of details during an audit and established that the sample results prove that the recorded account balance was materially misstated while in reality, it was not materially misstated, it illustrates sampling risk.
What is sampling risk?
Sampling risk refers to the likelihood of selecting sample data that are not indicative of the actual data population. It's a danger that arises because the auditor only audits a small portion of the population, which may or may not be representative of the whole population.
To summarize, the scenario presented in the problem statement is an instance of sampling risk.
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find ∫ c x 3 y 4 d x where c is the arc of the curve x = y 2 from (0,0) to (4,2)
The curve is given by \(x = y^2,\)so we can express the integral as:
\(∫c x^3 y^4 dx = ∫c (y^2)^3 y^4 dx = ∫c y^10 dx\)
To find the limits of integration, we need to determine the values of y for the endpoints of the curve. At the starting point (0, 0), we have y = 0, and at the endpoint (4, 2), we have y = 2^(1/2). Therefore, the integral becomes:
\(∫c x^3 y^4 dx = ∫0^(2^(1/2)) y^10 dx = [1/11 y^11]_0^(2^(1/2)) =\)\(2^(11/2) / 11\)
Therefore, the value of the integral is \(2^(11/2) / 11\)
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What is the remainder when 31,671 ÷ 68?
Answer:
465.75
Step-by-step explanation:
If you do the math and divide 31,671 by 68, your answer should be:
465.75
Hope this helps :)
Answer:
51
Step-by-step explanation:
Write 2/8 in simplified form
Answer:
1/4
Step-by-step explanation:
because you basically divided by two on
Answer:
1/4 is the answer mark me brainliest
Julian is working two summer jobs, making $13 per hour lifeguarding and making $8 per hour washing cars. In a given week, he can work a maximum of 15 total hours and must earn at least $160. If xx represents the number of hours lifeguarding and yy represents the number of hours washing cars, write and solve a system of inequalities graphically and determine one possible solution.
Answer:
if he can work 15 hours and must make at least 160 dollars, he'll need to work 8 hours lifeguarding and 7 hours washing cars
Step-by-step explanation:
13 x 8 = 104
8 x 7 =56
when added we get 160, and the hours are exactly 15
x + y ≤ 15
13x + 8y = 160
Do anyone know how to do this I need help now
Answer:
Box 1: 38
Box 2: 72
Box 3: 110
Step-by-step explanation:
Add both numbers in each row up
The last box is 110 because it is the total number of students asked.
What are the solutions to the quadratic equation (2b+3)^2=12
Answer:
b=− 3/4 =−1.333
b= 2/3=1.500
explanation
middle term, which is -1 .
-72 + 1 = -71
-36 + 2 = -34
-24 + 3 = -21
-18 + 4 = -14
-12 + 6 = -6
-9 + 8 = -1 That's it
Two real solutions:
b =(1+√289)/12=(1+17)/12= 1.500
or:
b =(1-√289)/12=(1-17)/12= -1.333
Distance (ft.)
Daniela
Kayla
me (sec.)
Kayla and Daniela started walking at constant speeds.
After 3 seconds:
-Kayla walked 6 feet.
• Daniela walked 12 feet.
Label each graph with the name it represents.
Then write an equation for Kayla's walk. Use d for
distance and t for time.
Daniella's graph is the first from the left and Kayla's is the other. Kayla's walk can be represented as ; d = 2t
Given that after 3 seconds:
distance walked by Kayla = 6 feets distance walked by Daniela = 12 feetsThis shows that the speed at which Daniela walked is faster than that of Kayla. Hence, the line with the steepest slope represents Daniela's movement.
Hence, Daniela's graph is the first from the left while Kayla's is the other.
2.)
Kayla's walk can be expressed mathematically as :
d = distance; t = timed = 6 feets ; t = 3 seconds
Walking speed = distance/ time
Walking speed = 6/3 = 2 ft/sec
Hence, Kayla's walk ;
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Determine which of the following lines the point (2,-2) lies on.
Answer:
IV QUADRANT
Step-by-step explanation:
Help anyone can help me do this question 3,I will mark brainlest.
Answer:
see explanation
Step-by-step explanation:
Calculate the slopes between pairs of the 3 points using the slope formula
m = \(\frac{y_{2}-y_{1} }{x_{2}-x_{1} }\)
with (x₁, y₁ ) = (- 9, 3) and (x₂, y₂ ) = (- 3, 9)
m = \(\frac{9-3}{-3-(-9)}\) = \(\frac{6}{-3+9}\) = \(\frac{6}{6}\) = 1
Repeat with (x₁, y₁ ) = (5, 1) and (x₂, y₂ ) = (- 3, 9)
m = \(\frac{9-1}{-3-5}\) = \(\frac{8}{-8}\) = - 1
If lines are perpendicular then the product of their slopes = - 1 , then
1 × - 1 = -1
Thus there is a right angle between the 2 lines
Then triangle is right- angled
Out of the last 50 guest,only 1 of them brought a coupon for free admission to the carnival. If there are 1500 guests expected this weekend, how many can we except will receive free admission
We can expect 30 guests to receive free admission out of the 1500 guests expected this weekend.
To determine how many guests can be expected to receive free admission, we need to use the given information about the ratio of guests with coupons to guests without coupons. We can do this by setting up a proportion and solving for the unknown variable.
Let x be the number of guests we can expect to receive free admission.
1/50 = x/1500
Cross-multiplying gives us:
50x = 1500
Dividing both sides by 50 gives us:
x = 30
Therefore, we can expect 30 guests to receive free admission out of the 1500 guests expected this weekend.
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All of the following could be measurements on a scale drawing that has a scale of 1:4 except
PLEASE HELP ME ILL GIVE 20 points
Answer: 3 centimeters equals 12 meters
Hope this helps!
Answer:
Three centimeters represent 12 meters.
Step-by-step explanation:
Paulina has completed 24 of the 42 math problems she was assigned for homework. She plans to finish her homework by completing 9 math problems each hour h. Write an equation to find the number of hours it will take Paulina to complete her math homework assignment.
Answer:
9h=42-24 so it is 2 hours
Step-by-step explanation:
9h for 9 problems per hour. Also 42-24 because she had that much left to do.
Plssss help I will mark brainlist plsss
Answer:
D
Step-by-step explanation:
What you need to apply there is basically 3D Pythagoras which goes like r=
\( \sqrt{23 { }^{2} + 10 { }^{2} + 15 {}^{2} } \)
then punching on the calculator, the answer will be 29. 22 in
Answer:
D 29.2 I am pretty sure that is the right one so if it not sorry
A square has the same area as a rectangle whose
longer side is 2 times the length of its shorter
side. If the perimeter of the rectangle is 24, what
is the perimeter of the square?
A) 8 √2
B)16 √2
C)32 √2
D)32
Answer:
C) 32 * 2**1/2
Step-by-step explanation:
For rectangle P = L + W = 24 but L = 2W so
2W + W = 24
3W = 24
W = 8 and L = 2W = 16
A = L * W = 16 * 8 = 128
SO for the square with the same area
A = L * L = 128
L**2 = 128
L = 8 * 2**1/2
P = 4L = 32 * 2**1/2
PLEASE HELP HARD FOR ME BUT EASY FOR OTHERS
secA-tanA=(cosA/2-sinA/2)/(cosA/2+sinA/2)
Answer:
Step-by-step explanation:
SecA - TanA
= 1/CosA - SinA/CosA
= 1 - SinA/CosA
We know that Sin2A = 2SinACosA and Cos2A = Cos²A - Sin²A
Thus SinA = Sin2(A/2) = 2Sin(A/2)CosA/2
CosA = Cos2(A/2) = Cos²A/2 - Sin²A/2
Now substituting the values back,
=> 1 - 2Sin(A/2)Cos(A/2) / Cos²(A/2) - Sin²(A/2)
// we know that Sin²θ + Cos²θ = 1
=> Sin²(A/2) + Cos²A/2 - 2Sin(A/2)Cos(A/2) / Cos²(A/2) - Sin²(A/2)
//We know that numerator is of form a² + b² - 2ab which is (a - b)².
//Similarly denominator is of form a² - b² which is (a - b)(a + b)
=> [Sin(A/2) - Cos(A/2)]² / [Cos(A/2) + Sin(A/2)][Cos(A/2) - Sin(A/2)]
=> [ - {Cos(A/2) - Sin(A/2)}]² / [Cos(A/2) + Sin(A/2)][Cos(A/2) - Sin(A/2)]
=> [Cos(A/2) - Sin(A/2)]² / [Cos(A/2) + Sin(A/2)][Cos(A/2) - Sin(A/2)]
=> [Cos(A/2) - Sin(A/2)] / [Cos(A/2) + Sin(A/2)]
= R.H.S
Hence proved.
use the laplace transform to solve the given initial-value problem. use the table of laplace transforms in appendix iii as needed. y''+16y = cos(4t), y(0) = 3, y'(0) = 2
y(t)=
Using the Laplace transforms the solution is y(t) = (15÷16)cos(4t) + (5÷16)tsin(4t) - (1÷32)sin(4t), where y(0) = 3 and y'(0) = 2.
To solve the given initial-value problem using Laplace transforms, we first take the Laplace transform of both sides of the differential equation:
L{y''(t)} + 16L{y(t)} = L{cos(4t)}
Using the property L{f'(t)} = sL{f(s)} - f(0), where f(0) is the initial value of f(t), and the fact that y(0) = 3 and y'(0) = 2, we have:
s² Y(s) - s y(0) - y'(0) + 16 Y(s) = L{cos(4t)}
Substituting y(0) = 3 and y'(0) = 2, and using the Laplace transform of cos(4t) from the table in Appendix III (L{cos(4t)} = s ÷ (s² + 16)), we obtain:
s² Y(s) - 3s - 2 + 16 Y(s) = s ÷ (s² + 16)
Simplifying and solving for Y(s), we get:
Y(s) = (s + 4)÷(s² + 16)²
Now we need to find the inverse Laplace transform of Y(s) to obtain the solution y(t). We can use partial fraction decomposition and the Laplace transform table to obtain:
Y(s) = (s + 4)÷(s² + 16)² = A÷(s² + 16) + B÷(s² + 16)²
Multiplying both sides by (s² + 16)² and equating the numerators, we get:
s + 4 = A(s² + 16) + B
Setting s = 0, we get:
4 = 16A + B
Setting s = 4i, we get:
4i + 4 = -16B÷(16i)²
B = i÷8
Substituting B into the equation 4 = 16A + B, we get:
A = 15÷16
Therefore, we have:
Y(s) = 15÷(16(s² + 16)) + i÷(8(s² + 16)²)
Using the Laplace transform table, we can find the inverse Laplace transform of each term. The solution is:
y(t) = (15÷16)cos(4t) + (5÷16)tsin(4t) - (1÷32)sin(4t)
Therefore, the solution to the given initial-value problem is y(t) = (15÷16)cos(4t) + (5÷16)tsin(4t) - (1÷32)sin(4t), where y(0) = 3 and y'(0) = 2.
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24.7% of the products in the local shop are specialty soaps. 76% of those soaps are made with fresh herbs. if there are 350 bars of specialty soap in the shop, approximately how many of them are not made with fresh herbs? round your answer up to nearest whole number
we know that 76% of the specialty soaps are made with fresh herbs, and we also know that there are a total of 350 specialty soap bars, so how many are made with fresh herbs? well, just 76% of those 350
\(\begin{array}{|c|ll} \cline{1-1} \textit{\textit{\LARGE a}\% of \textit{\LARGE b}}\\ \cline{1-1} \\ \left( \cfrac{\textit{\LARGE a}}{100} \right)\cdot \textit{\LARGE b} \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{76\% of 350}}{\left( \cfrac{76}{100} \right)350}\implies 266\)
consider a linear transformation t from r2 to r2 for which
T([1]) = (5 ) and T ([0]) = [3]
([0]) (-5) ([1]) [1]
find the matrix of A of T
A=[_ _]
[_ _]
The matrix A of T is:
A = [[5, 3], [-5, 1]]
We know that a linear transformation is completely determined by its action on the basis vectors. In this case, we are given the images of the standard basis vectors [1, 0] and [0, 1].
The matrix A of the linear transformation T is given by:
A = [T([1, 0]), T([0, 1])]
So we just need to compute T([1, 0]) and T([0, 1]).
Using the linearity of T, we have:
T([1, 0]) = T(1*[1, 0] + 0*[0, 1]) = 1T([1, 0]) + 0T([0, 1])
= [5, -5]
and
T([0, 1]) = T(0*[1, 0] + 1*[0, 1]) = 0T([1, 0]) + 1T([0, 1])
= [3, 1]
Therefore, the matrix A of T is:
A = [[5, 3], [-5, 1]]
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Can someone help me do these problems?
The solutions using laws of exponents are:
a) \((4x)^{\frac{3}{2} }\)= \(8 \sqrt[]{x^{3} }\)
b) \(x^{\frac{-2}{3}}\)\(= \sqrt[3]{x^{2} }\)
d) \(\frac{\sqrt[3]{x} }{\sqrt{x} }\)\(=\) \(\sqrt[3]{x^{2} }\)
e) \(\frac{\sqrt{x} * x^{2} }{{x^{\frac{5}{2} } } }\)= 1
How to use laws of exponents?Some of the laws of exponents are:
- When multiplying by like bases, keep the same bases and add exponents.
- When raising a base to a power of another, keep the same base and multiply by the exponent.
- If dividing by equal bases, keep the same base and subtract the denominator exponent from the numerator exponent.
The expression we want to solve is given as:
a) \((4x)^{\frac{3}{2} }\)
Using laws of exponents, the bracket is simplified to get:
\(4^{\frac{3}{2}} * x^{\frac{3}{2}}\)
= \(8 \sqrt[]{x^{3} }\)
b) The expression we want to solve is given as:
\(x^{\frac{-2}{3}}\)
This simplifies to get:
\(\sqrt[3]{x^{2} }\)
d) The expression we want to solve is given as:
\(\frac{\sqrt[3]{x} }{\sqrt{x} }\)
This simplifies to get:
\(x^{\frac{-2}{3}}\) = \(\sqrt[3]{x^{2} }\)
e) The expression we want to solve is given as:
\(\frac{\sqrt{x} * x^{2} }{{x^{\frac{5}{2} } } }\)
This simplifies to get:
\(\frac{{x^{\frac{5}{2} } } }{{x^{\frac{5}{2} } } }\)
= 1
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(Look at image) Need help for question 5. Need this by tomorrow ASAP!
(Repost cuz it’s gonna be impossible for anyone to answer at the rate of questions asked)
Answer:
little falls has more
Step-by-step explanation:
show your work: little falls total rainfall is 1 6/8 and riverside is 1 5/8
use that to explain :) your welcome
Answer:
Riverside had the greatest rainfall total
Step-by-step explanation:
The total amount of rain in a city will be the sum of products of rain amount and days that got that amount. The city with the largest sum got the most rain. The difference in rainfall can be found by subtracting the lesser amount from the greater.
__
RiversideTotal rainfall in Riverside was ...
(1/8)×1 +(2/8)×3 +(3/8)×3 +(4/8)×1 +(5/8)×1
= (1 +6 +9 +4 +5)/8 = 25/8 = 3 1/8 . . . . inches
__
Little FallsTotal rainfall in Little Falls was ...
(1/8)×1 +(3/8)×1 +(4/8)×1 +(6/8)×2
= (1 +3 +4 +12)/8 = 20/8 = 2 1/2 . . . . inches
__
Riverside had more rainfall, because 3 1/8 is more than 2 1/2.
__
Without calculationYou can "cancel" dots that are in the same place on each plot. Doing so leaves Riverside with 3 dots at 2/8, 2 dots at 3/8, and 1 dot at 5/8. The remaining dots on the Little Falls plot are the 2 dots at 6/8.
The 3 dots at 2/8 add up to 6/8, as do the 2 dots at 3/8 on the Riverside plot. These two 6/8 values cancel the two 6/8 dots on the Little Falls plot. That leaves one uncancelled dot at 5/8 on the Riverside plot, indicating more rain fell at Riverside.
Sam Houston middle school has a height of 24 feet and a length of 96 feet. On a scale drawling of the building the length is 40 inches. what is the hieght of the drawing in inches?
Answer:
288 inches
Step-by-step explanation:
Just do 24 x 12 you will get the answer since 1ft=12 inches!
Hope this helps please mark me brainliest it means a lot to me.
Find the measure of SRT
please help!
Answer:
∠ SRT = 55°
Step-by-step explanation:
angles on the circle ( inscribed angles ) from the same chord are equal.
∠ SRT and ∠ SVT are inscribed angles from the same chord ST , then
∠ SRT = ∠ SVT = 55°
A college student is considering two television streaming services instead of cable. The table shows the monthly cost, y, for purchasing x extra channels for each service. Service 1 Service 2 $20 service fee plus $8 for each extra channel $45 service fee plus $3 for each extra channel If the college student plans to purchase 8 extra channels, which statement is true?
The charges by both streaming services are illustrations of linear functions
Service 1 charges more for 8 extra channels, than service 2
Let x represents the number of extra channels, and y represents the cost.
For service 1, we have:
$20 service fee plus $8 for each extra channel
So, the linear equation that represents this service is:
\(y = 20 + 8x\)
For service 2, we have:
$45 service fee plus $3 for each extra channel
So, the linear equation that represents this service is:
\(y = 45 + 3x\)
For extra 8 channels, the total charges of service 1 is:
\(y = 20+ 8 \times 8\)
\(y = 84\)
For extra 8 channels, the total charges of service 2 is:
\(y = 45 + 3 \times 8\)
\(y = 69\)
By comparison, 84 > 69
Hence, service 1 charges more for 8 extra channels, than service 2
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