Suppose that you have 185 mL
of a buffer that is 0.420 M
in both formic acid (HCOOH)
and its conjugate base (HCOO−).
Calculate the maximum volume of 0.430M
HCl
that can be added to the buffer before its buffering capacity is lost

Answer:I would say

its mass

Explanation:

Answer:

I believe the answer is density.

Explanation:

By comparing the density of the unknown substance to a list of densities of known substances, you can identify it.

Answer:

The Hawaiian Islands are a very small section of a huge chain of volcanic islands that crosses the northern half of the Pacific Ocean, called the Hawaiian-Emperor Volcanic Island Chain, which is over 6,000 kilometres long. The chain is linear, with a large bend in the middle: the southern half is called the Hawaiian Ridge and the northern half is called the Imperial Seamount.

Explanation:

Answer:

FeO

Explanation:

Iron(II) oxide or ferrous oxide is the inorganic compound with the formula FeO. Its mineral form is known as wüstite. One of several iron oxides, it is a black-colored powder that is sometimes confused with rust, the latter of which consists of hydrated iron(III) oxide (ferric oxide).

Density = mass/Volume    or    D = m/V  

Given:  V = 22.3 gal

           D = 0.8206 g/mL

1)  Rearrange the equation to solve for m

2)  Find conversion factor(s) and convert V from gal to mL (by dimensional analysis) so the units cancel

3)  Solve for m in g

4)  Find conversion factor(s) and convert m from g → lbs

1)  D = m/V  rearranges to  m = D ∗ V

2)  1 gal = 3.785 L  and  1 L = 1000 mL;     22.3 gal  ∗  3.785  L/1 gal  ∗  1000 mL/1 L   =  84 406 mL

3)  m =  0.8206 g/mL  ∗  84 406 mL    =  69 260 g

4)  1 lb = 453.6 g;   69 260  g  ∗  1 lb/453.6 g   =  153 lbs

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If a snail crawls 55 inches per day ,the snail will crawl approximately \(3.2 * 10^3 centimeters.\)

To convert inches to centimeters, we need to use the conversion factor: 1 inch = 2.54 centimeters.

First, let's calculate the distance the snail crawls in inches in 23 days. We can multiply the daily distance by the number of days:

Distance in inches = 55 inches/day × 23 days = 1265 inches.

Now, to convert the distance from inches to centimeters, we multiply the distance in inches by the conversion factor:

Distance in centimeters = 1265 inches × 2.54 cm/inch = 3215.1 cm.

Rounding to the appropriate number of significant figures, the snail will crawl approximately 3215 cm or \(3.2 * 10^3 centimeters.\) in 23 days.

Therefore, the answer is  Option 3:\(3.2 * 10^3 centimeters.\)

This means that in 23 days, the snail will crawl approximately\(3.2 * 10^3 centimeters.\)

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Answer:

The Sun Ray's hit earths surface at Earths Equator

Answer:

3Cu(NO3)2 + 2Al —> 2Al(NO3)3 + 3Cu

Explanation:

From the question given above,

Copper (II) nitrate reacts with aluminum to form aluminum nitrate and copper. This can be obtained represent as follow:

Cu(NO3)2 + Al —> Al(NO3)3 + Cu

Thus, we can balance the above equation as follow:

Cu(NO3)2 + Al —> Al(NO3)3 + Cu

There are 2 atoms of N on the left side and 3 atoms on the right side. It can be balance by putting 3 in front of Cu(NO3)2 and 2 in front of Al(NO3)3 as shown below:

3Cu(NO3)2 + Al —> 2Al(NO3)3 + Cu

There are 3 atoms of Cu on the left side and 1 atom on the right side. It can be balance by putting 3 in front Cu as shown below:

3Cu(NO3)2 + Al —> 2Al(NO3)3 + 3Cu

There are 2 atoms of Al on the right side and 1 atom on the left side. It can be balance by putting 2 in front of Al as shown below:

3Cu(NO3)2 + 2Al —> 2Al(NO3)3 + 3Cu

Thus, the equation is balanced.

The oxidation number of chlorine in KClO3 is +5 (option A).

The oxidation number of an element is the hypothetical charge of an atom within a molecule.

The oxidation number of an element like chlorine in a compound like Pottasium chlorate can be calculated as follows:

The oxidation number of the elements in KClO3 is as follows:

1 + x - 2(3) = 0

x - 5 = 0

x = +5

Therefore, the oxidation number of chlorine in KClO3 is +5.

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It is expected at 1.05 atm the solubility increases if compared to the solubility at 0.222 atm.

In general, an increase in pressure leads to an increase in solubility. In the same way, a decrease in pressure will decrease solubility.

Considering the pressure increased, the most likely result is for the solubility to proportinally increase.

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Answer:

Explanation:

Radical chlorination of butane in the presence of light gives rise to the formation of two isomeric monochlorides B (1-chlorobutane) and C  (2-chlorobutane). Both upon reaction with a bulky base (potassium tert-butoxide) give rise to D(but-1-ene) and E(but-2-ene) respectively, this is because the bulky base abstracts the less hindered proton. Compound B and C were later treated with aqueous C2H5OH which results in the hydrolysis of alkyl halides to produce Compound F(butan-1-ol) and compound G (butan-2-ol) respectively.

The diagrammatic expression of the whole reaction is shown in the attached image below.

Chemical reactions occur when chemical bonds between atoms are formed or broken. The substances that go into a chemical reaction are called the reactants, and the substances produced at the end of the reaction are known as the products.

The end of a chemical reaction is the product.

What is a chemical reaction?

A chemical reaction contains a reactant that reacts to form products. The reactant can be more than two, and the product can be two or more.

Food spoiling is a chemical reaction because it has an unpleasant odor, taste, and color change. Fruits undergo a chemical shift as they ripen. For instance, both the texture and color may change.

When we balance a chemical process, the number of moles or atoms on the left must match the amount on the right. Thus, the atoms participating in such a chemical process are discovered to have mass.

Chemical elements are uncontaminated by impurities or other elements and are pure substances made up of just one type of atom. They are found in the crust of the earth. Carbon, hydrogen, and oxygen are some examples.

Therefore, the end is the product.

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The concept ideal gas equation is used here to determine the volume of the carbondioxide. Combustion reactions are generally highly exothermic reactions. The volume of CO₂ is

A combustion is a chemical reaction in which a fuel undergoes oxidation as a result of the reaction with an oxidizing agent which causes the release of energy in the form of heat.

15.0 °C = 288 K

The ideal gas equation is:

PV = nRT

V = nRT / P

V = 354 × 0.0821 × 288 / 0.995 = 8412.3 L

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The correct dose for a 175 lb patient would be approximately 0.48602 grams.

To convert 6.13 mg/kg to grams, we need to consider the weight of the patient and perform a unit conversion. Here's the step-by-step process:

1. Convert the weight of the patient from pounds to kilograms.

  175 lb * (1 kg / 2.205 lb) = 79.37 kg (rounded to two decimal places)

2. Calculate the correct dose in grams by multiplying the patient's weight by the given dosage.

  79.37 kg * 6.13 mg/kg = 486.02 mg

3. Convert the dose from milligrams (mg) to grams (g) by dividing by 1000.

  486.02 mg / 1000 = 0.48602 g (rounded to five decimal places)

Therefore, the correct dose for a 175 lb patient would be approximately 0.48602 grams.

It's important to note that this calculation assumes the dosage is based on body weight and that the given dosage is appropriate for the patient's condition. Always consult a healthcare professional or follow the instructions of a medical prescription for accurate dosing information.

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Answer:

Question (a):

Answer: 2:8:7

Explanation: Chlorine, Cl is in period 3 hence two energy levels [ 2:8:_]. Chlorine is in group IV (halogen) hence it has 7 outermost energy level electrons. Hence deducing 2:8:7

Question (b)

» (i): Carbon and silicon [ C and Si ]

A group is a column in a periodic table

» (ii): Silicon and Chlorine [ Si and Cl ]

A period is a row in a periodic table

» (iii): Hydrogen and Chlorine [ H and Cl ]

It forms hydrogen chloride gas. When this gas is passed on warm water or steam, hydrochloric acid is formed.

» (iv): Chlorine [ Cl ]

An element has electron number equivalent to group number. Group I elements have one electron, Group ii elements have two electrons and so on.

Helium is in group Viii but in period 1, so it has eight electrons.

But chlorine has seven outermost electrons but since it is in period 3, its electrons are 8 + 7 = 15 electrons.

» (v): Chlorine [ Cl ]

Chlorine only lacks one electron to become full and stable. So it is assigned by Cl- (-1)

This representation suggests that the element is phosphorus (P) with a mass number of 30, which is incorrect. The correct mass number for phosphorus is approximately 30.97. The incorrect representation for a neutral atom is 36Li

To determine the correct representation for a neutral atom, we need to consider the atomic number (Z) and mass number (A) of the element. The atomic number represents the number of protons in the nucleus, while the mass number represents the sum of protons and neutrons.

Let's analyze the given representations:

36Li:

This representation suggests that the element is lithium (Li) with a mass number of 36, which is incorrect. The correct mass number for lithium is approximately 6.94.

613C:

This representation suggests that the element is carbon (C) with a mass number of 13, which is correct. Carbon has different isotopes, and 13C represents one of its stable isotopes.

3063Cu:

This representation suggests that the element is copper (Cu) with a mass number of 63, which is correct. Copper has different isotopes, and 63Cu represents one of its stable isotopes.

1530P:

This representation suggests that the element is phosphorus (P) with a mass number of 30, which is incorrect. The correct mass number for phosphorus is approximately 30.97.

Therefore, the incorrect representation for a neutral atom is 36Li, as it does not match the known properties of lithium.

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The correct option is (d) To express very large or very small number.

What is the Scientific Notation?

Scientific notation is a way to present numbers that are too large or too small to be easily written in decimal form. The three components of  scientific notation are coefficient, base and exponent. The proper format to write a scientific notation is a x 10^b, where a is a number or decimal number and b is the power of 10 to make scientific notation equivalent to original number. When a number between 1 and 10 is multiplied by a power of 10 then the number is expressed in scientific notation. For example,  10000000 can be written as 10⁷, which is the scientific notation and the exponent is positive here. Similarly, for the negative exponent 0.000001 can be can be represented as 10-⁷.                             Hence, the scientific notation is used to express very large or very small numbers.

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Answer:

The percentage of the R-enantiomer is 26.18% while the percentage of the S-enantiomer is 73.82%

Explanation:

If the specific rotation of R enantiomer = -28.4, then the specific rotation of S = +28.4

Now, let us have x = % R, thus

% S = 100-x =y

Hence;

{- 28.4x + 28.4( 100 -x)}/100= 14.1

Thus;

-28.4x + 2840 -28.4x = 1410

-56.8x + 2840 = 1410

-56.8x = 1410-2840

-56.8x = -1430

x = 1430/56.8

x = 26.18%

y = 100-26.18% = 73.82%

Answer:

The value of the rate constant at 381 K is:

k2 = k1 * (k2/k1) = 0.178 M/s * 4.50 = 0.801 M/s (rounded to three significant figures)

Commercial agriculture often leads to water-quality problems as a result of run-offs and agrochemical discharge.

Most commercial agriculture requires the use of agrochemicals and fertilizers.

Agrochemicals such as insecticides and herbicides are poisonous to aquatic biodiversity when run-offs are discharged from farmlands to water bodies.

Fertilizer run-offs into water bodies also cause nutrient enrichment, leading to eutrophication.

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Ketoacidosis is a potentially life-threatening condition that happens when the body begins breaking down fat at very fast rate. The fat is converted by the liver and causes the blood to become acidic and needs to be treated immediately.

Diabetes-related ketoacidosis (DKA) is a potentially fatal condition that affects diabetics. It happens when the body begins breaking down fat at an abnormally fast rate. The fat is converted by the liver into a fuel called ketones, which causes the blood to become acidic.

Diabetic ketoacidosis symptoms frequently appear suddenly, sometimes within 24 hours. High blood sugar levels and high ketone levels in urine are some of the first signs for DKA.

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Answer: i think its empirical

Explanation:

The water with the salt boiled at a higher temperature than the water without the salt.

When we add any solute or other compound in any pure solvent then the boiling point of the solution will increases.

And elevation in boiling point will be expressed by the following equation:

ΔTb = (Kb)(m)(i), where

So the pot with salt will have higher boiling point then the simple water.

Hence, pot with salt has a higher boiling point.

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Answer:

percentage yield = 67%

Explanation:

Mass of Cu(NO₃)₂  = 15.25 g

Mass of NaOH   = 12.75 g

Percentage yield = ?

Solution:

Cu(NO₃)₂ + 2NaOH   →  Cu(OH)₂ + 2NaNO₃

Moles of Cu(NO₃)₂:

Number of moles = mass/ molar mass

Number of moles = 15.25 g /187.56 g/mol

Number of moles = 0.08 mol

Moles of NaOH :

Number of moles = mass/ molar mass

Number of moles = 12.75 g / 40 g/mol

Number of moles = 0.32 mol

Now we will compare the moles of Cu(OH)₂ with NaOH and Cu(NO₃)₂.      NaOH             :      Cu(OH)₂

                               2                   :          1

                               0.32              :           1/2×0.32 = 0.16 mol

                            Cu(NO₃)₂         :           Cu(OH)₂

                                  1                  :               1

                             0.08                :              0.08

The number of moles produced by  Cu(NO₃)₂  are less so it will limiting reactant.

Mass of Cu(OH)₂:

Mass = number of moles × molar mass

Mass = 0.08 mol × 97.6 g/mol

Mass = 7.808 g

Theoretical yield = 7.808 g

Percent yield:

percentage yield = Actual yield/ theoretical yield ×  100

percentage yield = 5.23 g/  7.808 g ×  100

percentage yield = 0.67 ×  100

percentage yield = 67%

1.3 grams of copper (II) hydroxide can be prepared from 2.4 grams of copper (II) nitrate (Cu(NO₃)₂) and excess sodium hydroxide.

Let's consider the following balanced double displacement reaction.

Cu(NO₃)₂ + 2 NaOH ⇒ Cu(OH)₂ + 2 NaNO₃

2.4 g of Cu(NO₃)₂ (molar mass 187.56 g/mol) react. The reacting moles of Cu(NO₃)₂ are:

\(2.4 g \times \frac{1mol}{187.56g} = 0.013 mol\)

The molar ratio of Cu(NO₃)₂ to Cu(OH)₂ is 1:1. The moles of Cu(OH)₂ produced from 0.013 moles of Cu(OH)₂ are:

\(0.013molCu(NO_3)_2 \times \frac{1molCu(OH)_2}{1molCu(NO_3)_2} = 0.013 molCu(OH)_2\)

The molar mass of Cu(OH)₂ is 97.56 g/mol. The mass corresponding to 0.013 moles of Cu(OH)₂ is:

\(0.013 mol \times \frac{97.56g}{mol} = 1.3 g\)

1.3 grams of copper (II) hydroxide can be prepared from 2.4 grams of copper (II) nitrate (Cu(NO₃)₂) and excess sodium hydroxide.

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Answer:

Its D and E

Explanation:

i took the test and the other guy who answered gave u half of the answer

hope this helps

pls mark brainliest

The information which can be inferred about the Sun according to the graph include:

This is defined as a pictorial representation of data in an organized manner.

From the graph, we can infer that the Sun has an intermediate temperature and is less brighter than most stars.

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The partial pressure of hydrogen in the collected gas sample is 733.0 mm Hg (calculated by subtracting the partial pressure of water, 17.0 mm Hg, from the total atmospheric pressure, 750.0 mm Hg).

When a gas is collected over water, the presence of water vapor affects the total pressure observed. In this case, the total atmospheric pressure is given as 750.0 mm Hg, and the partial pressure of water vapor at 19.5°C is 17.0 mm Hg.

To determine the partial pressure of hydrogen, we need to subtract the partial pressure of water vapor from the total atmospheric pressure. Partial pressure refers to the pressure exerted by an individual gas component in a mixture. In this scenario, the collected gas is primarily hydrogen, with water vapor being the other component.

By subtracting the partial pressure of water vapor (17.0 mm Hg) from the total atmospheric pressure (750.0 mm Hg), we can find the partial pressure of hydrogen:

Partial pressure of hydrogen = Total atmospheric pressure - Partial pressure of water vapor

Partial pressure of hydrogen = 750.0 mm Hg - 17.0 mm Hg

Partial pressure of hydrogen = 733.0 mm Hg

Therefore, the partial pressure of hydrogen in the collected gas sample is 733.0 mm Hg.

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Answer:

16.0 mol H.

Explanation:

Hello!

In this case, since the Avogadro's number help us to compute the moles of methanol in the given molecules:

\(n_{CH_3OH}=2.41x10^{24}molecCH_3OH*\frac{1molCH_3OH}{6.022x10^{23}molecCH_3OH}=4.00molCH_3OH\)

Thus, since 1 mole of methanol contains 4 moles of hydrogen atoms, we obtain:

\(n_H=4.00molCH_3OH*\frac{4molH}{1molCH_3OH}\\\\n_H=16.0molH\)

Best regards!

Answer:

It changes from a liquid to a gas. I hope this helps you! :D

Answer:

\([PH_3]=0.30M\) but see detailed explanation, please.

Explanation:

Hello there!

In this case, unfortunately, we are not given the rate constant but we can set up a reaction according to the information available on the internet:

\(4PH_3\rightarrow P_4+6H_2\)

Whose rate constant is 0.0375/s. In such a way, it is possible infer that this is first-order reaction whose integrated rate law is:

\([PH_3]=[PH_3]_0exp(-kt)\)

Thus, given the initial concentration, rate constant and elapsed time, the final concentration of PH3 would be:

\([PH_3]=(0.95M)exp(-30.50s*0.0375/s)\\\\\)

\([PH_3]=0.30M\)

However, it is important to keep in mind this result may vary according to your actual question.

Regards!