Suppose a large star explodes in a supernova, leaving a core that is 10 times the mass of the Sun. What would happen to the core of the star

Answers

Answer 1

If a large star explodes in a supernova and leaves a core that's 10 times the mass of the Sun, the core of the star would collapse.

What is a star?

A star can be defined as a giant astronomical object that contains a luminous sphere of plasma, and it is bounded together by its own gravitational force.

Based on astronomical information, if a large star explodes in a supernova and leaves a core that's 10 times the mass of the Sun, the core of the star would collapse due to its own gravity which creates a violent explosion known as a supernova.

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Related Questions

distinguish between speed and velocity ​

Answers

Speed has no direction.

Velocity has one.

classify each polynimal based on the number of terms it contains

Answers

Polynomials can be classified based on the number of terms is contains which may be monomial, binomial, or trinomial.

What are polynomials?

Polynomials are algebraic expressions that contains a constant that is multiplied by one or more variables.

Monomials is a type of polynomial that has only one term. From the question, the monomial is 10xyz^3.

Binomial is a type of polynomial that has only two terms. From the question, the binomial are 8x^2+0.25 and -x^2y^2+2y.

Trinomial is a type of polynomial that has only three temrs. From the question, the trinomial are -2x^2-x+3.5 and x^3y^4+2x^2y-3z.

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The complete question:

Classify each polynomials based on the number of terms it contains.

-2x^2-x+3.5

10xyz^3

-x^2y^2+2y

8x^2+0.25

x^3y^4+2x^2y-3z

what must the charge (sign and magnitude) of a particle of mass 1.45 g be for it to remain stationary when placed in a downward-directed electric field of magnitude 700 n/c ?

Answers

The charge (sign and magnitude) of a particle of mass 1.45 g must be for it to remain stationary when placed in a downward-directed electric field of magnitude 700 n/c is -1.029x10⁻⁴ C.

The magnitude of the charge must be equal to the magnitude of the electric field (700 n/c).

Therefore, we can write:-mg = qE

where, m = 1.45g = 1.45 x 10⁻³ kg

E = 700 N/cm = 1.45 x 10⁻³ kg x 9.81 m/s²

= 0.01419 N (Weight of the particle)

q = -1.029 x 10⁻⁴ C

To remain stationary when placed in a downward-directed electric field of magnitude 700 n/c, the charge (sign and magnitude) of a particle of mass 1.45 g must be negative.

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You may have already used the Blackbody Spectrum simulation to see how the temperature of a substance affects how light is emitted. Many of the light sources you’re familiar with are incandescent light sources. They glow because they have a nonzero temperature. The hotter the source, the more radiant energy it gives off. Now, let’s explore a few different incandescent energy sources and investigate their lighting efficiency. In this simulation, the curve represents the radiation intensity and energy emitted with respect to the wavelength at a given temperature.
To begin, launch the Blackbody Spectrum simulation.

You may have already used the Blackbody Spectrum simulation to see how the temperature of a substance

Answers

The Blackbody Spectrum simulation allows us to explore how the temperature of incandescent light sources affects their emitted light.

First, discuss the relationship between temperature, radiant energy, and lighting efficiency.
Incandescent light sources emit light due to their nonzero temperature. As the temperature of the source increases, the amount of radiant energy it gives off also increases. The Blackbody Spectrum simulation helps us visualize how the temperature of a substance affects the way light is emitted.
In the simulation, a curve represents the radiation intensity and energy emitted with respect to the wavelength at a given temperature. As the temperature rises, the curve's peak shifts towards shorter wavelengths, and the area under the curve increases. This shift indicates that the emitted light becomes more energetic and intense.
However, not all of this emitted energy is in the visible spectrum; a significant portion can be in the form of infrared radiation (heat). Incandescent light sources are not very energy-efficient, as a large portion of their energy output is wasted as heat rather than visible light. The lighting efficiency of an incandescent source is determined by the percentage of radiant energy that falls within the visible spectrum.
To summarize, the Blackbody Spectrum simulation allows us to explore how the temperature of incandescent light sources affects their emitted light. As the temperature increases, the emitted radiant energy also increases. However, a considerable amount of energy is lost as heat, making incandescent sources less energy-efficient compared to other lighting technologies.

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A laser emits a narrow beam of light. The radius of the beam is 1.5 mm, and the power is 1.9 mW. What is the intensity of the laser beam?

Answers

Answer: 268.80 W/m^2

Explanation:

Intensity = Power/Area

first convert radius to meters

1.5mm= 1.5x10^-3m

area= pi (1.5x10^-3)^2

= 7.069m^2

convert power to W

1.9mW= 1.9x10^-3W

plug into intensity formula

(1.9x10^-3)/(7.069) = 268.80 W/m^2

a) Calculate the oscillating frequency of an LC circuit with a capacitor of 2 Farads and an inductor of 2 Henry.
b) Calculate the frequency in units of Hz in part (a).
c) What will you do to double the oscillating frequency in part (a)?

Answers

The oscillating frequency of the LC circuit with a capacitor of 2 Farads and an inductor of 2 Henrys is approximately 0.03979 Hertz or 39.79 millihertz.

the oscillating frequency of an LC circuit can be calculated using the formula:

f = 1 / (2π√(LC))

where f is the frequency in hertz (Hz), L is the inductance in henries (H), and C is the capacitance in farads (F).

Given that the capacitor has a capacitance of 2 Farads (F) and the inductor has an inductance of 2 Henrys (H), we can substitute these values into the formula:

f = 1 / (2π√(2 H * 2 F))

Simplifying further:

f = 1 / (2π√(4 H*F))

f = 1 / (2π * 2 H*F)

f = 1 / (4π H*F)

Using the approximation of π as 3.14159:

f ≈ 1 / (4 * 3.14159 * 2 H * 2 F)

f ≈ 1 / (25.13272 H*F)

f ≈ 0.03979 H*F

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A car travels from point A to point B in 3.991 hours and returns back to point A in 4.109 hours. Points A and B are 134.2 miles apart along a straight highway. What was the car's average speed and average velocity over this time period?

Answers

Answer:

gjsgjdcjpdcojdcoj gud gud gud gud gud gud gud gud gud gud gud gud gud gud get home h hum h hum hth hai h h g c b c b v g c h x corolla

The average speed of the car over this time period is 38.6 miles per hour. The average velocity of the car over this time period is 0 miles per hour.

The average speed of an object is the total distance traveled divided by the total time taken to travel that distance. In this case, the car travels a total distance of 134.2 miles in a total time of 3.991 + 4.109 = 8.1 hours. This means that the car's average speed is 134.2 miles / 8.1 hours = 38.6 miles per hour.

The average velocity of an object is the total displacement of the object divided by the total time taken to make that displacement. In this case, the car returns to its starting point, so its displacement is 0 miles. This means that the car's average velocity is 0 miles / 8.1 hours = 0 miles per hour.

Average speed and average velocity are not the same thing. Average speed only takes into account the distance traveled, while average velocity takes into account the displacement of the object. In this case, the car's displacement is 0, so its average velocity is 0.

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When a 2.75-kg fan, having blades 18.5 cm long, is turned off, its angular speed decreases uniformly from 10.0 rad/s to 6.30 rad/s in 5.00 s. (a) What is the magnitude of the angular acceleration of the fan? (b) Through what angle (in degrees) does it turn while it is slowing down during the 5.00 s? (c) If its angular acceleration does not change, how long after it is turned off does it take the fan to stop.

Answers

The magnitude of the angular acceleration of the fan is approximately 0.74 rad/s². The fan turns approximately 1800 degrees while slowing down during the 5.00 s. Meanwhile, if the angular acceleration does not change, it would take the fan approximately 0 seconds to stop after being turned off.

(a) To find the magnitude of the angular acceleration of the fan, we can use the formula for angular acceleration:

\(angular acceleration (a) =\frac{d (change in angular speed)}{time}\)

Initial angular speed (ω1) = 10.0 rad/s

Final angular speed (ω2) = 6.30 rad/s

Time (t) = 5.00 s

Using the formula:

\(a = \frac{w2 - w1}{t} \\a =\frac{6.30 rad/s - 10.0 rad/s}{5.00 s}\)

Calculating the expression, we find:

α = -0.74 rad/s^2

The magnitude of the angular acceleration of the fan is approximately 0.74 rad/s^2.

(b) To determine the angle through which the fan turns while slowing down, we can use the formula for angular displacement:

\(angular displacement (θ) =\frac{initial angular speed + final angular speed}{2 x time} \\\)

θ = (ω1 + ω2) / 2 x t

θ = (10.0 rad/s + 6.30 rad/s) / 2 x 5.00 s

Calculating the expression, we find:

θ = 31.5 rad

To convert the angle from radians to degrees:

θ_degrees = θ x (180° / π rad)

θ_degrees = 31.5 rad x (180° / π rad)

Calculating the expression, we find:

θ_degrees ≈ 1800°

Therefore, the fan turns approximately 1800 degrees while slowing down during the 5.00 s.

(c) If the angular acceleration does not change, we can use the formula for time to stop:

time to stop = (final angular speed) / (angular acceleration)

Final angular speed (ω2) = 0 rad/s (when the fan stops)

Using the formula:

time to stop = ω2 / α

time to stop = 0 rad/s / -0.74 rad/s^2

Calculating the expression, we find:

time to stop ≈ 0 s

Therefore, if the angular acceleration does not change, it would take the fan approximately 0 seconds to stop after being turned off. 0.74 rad/s² is the magnitude of the angular acceleration of the fan. While slowing down during the 5.00 s, the fan turns approximately 1800 degrees.

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. A boy wishes to make a catapult out of a rubber band of width 9mm and thickness 1.55mm. Determine the length of the band that he must use so that when he stretches it by 0.25 of its natural length and releases it the velocity of pebble of mass 0.006kg will be 30m/s. Take young modulus of the rubber to be 4×10^7 N/m^2 ​

Answers

The length of the rubber band that the boy must use is 0.024 m or 24 mm.

What will be the length of the rubber required?

To determine the length of the rubber band, we can use the formula for the potential energy stored in a stretched spring, which is also applicable to a stretched rubber band:

U = 1/2 kx²

where U is the potential energy stored in the rubber band, k is the spring constant (or in this case, the rubber band constant), and x is the displacement of the rubber band from its natural length.

Since the rubber band is stretched by 0.25 of its natural length, the displacement x is 0.25 times the natural length of the rubber band.

We can solve for the rubber band constant k by using the formula for the velocity of a projectile launched by a spring (or in this case, a rubber band):

v = √(2mk/M)

where v is the velocity of the projectile, m is the mass of the rubber band, M is the mass of the projectile, and k is the spring constant. We can rearrange this equation to solve for k:

k = (v² M) / (2 m)

We can now combine the two equations to solve for the length of the rubber band, L:

U = 1/2 k x²

U = 1/2 ((v² M) / (2 m)) (0.25 L)²

U = (v² M L²) / (32 m)

The potential energy stored in the rubber band must be equal to the kinetic energy of the projectile when it is launched:

U = 1/2 M v²

(v² M L²) / (32 m) = 1/2 M v²

L = ((16 m v²) / (k M))

L = ((16 m v²) / ((v² M) / (2 m) M))

L = √(32 m^2 / M)

L = (0.032 M)

Substituting the given values, we get:

L = √(0.032 * 0.006)

L = 0.024 m

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which of the following correctly describes the hierarchy of genetic material within a cell

Answers

Answer: D- Each chromosome in a cell is made up of two chromatids, which are each made up of molecules of DNA

Explanation:

A macromolecule is a large molecule that is made of many smaller units. Chromosomes are macromolecules that contain all of the genetic information in a cell. Chromosomes are each made of two smaller units called chromatids. Chromatids are each made up of molecules of DNA. Therefore, the correct description of the hierarchy of genetic material in a cell is that each chromosome in a cell is made up of two chromatids, which are each made up of molecules of DNA. The structures become more and more microscopic as one moves down the hierarchy.

I NEED ANSWERS ASAP!!!! Which of the following would accelerate faster with the same amount of force?


150 pound person on a skateboard


200 pound person on a skateboard


They all accelerate equally


300 pound person on a skateboard

Answers

150 pound person on a skateboard

The 150-pound person on a skateboard would accelerate faster with the same amount of force. Therefore, option (A) is correct.

What is acceleration?

Acceleration of a body is demonstrated as the change of velocity with respect to time. The acceleration is a vector parameter as it carries both magnitude and direction. Acceleration is defined as the 2nd derivative of position w.r.t. time and the 1st derivative of velocity w.r.t. time.

According to Newton's 2nd law, the force is equal to the multiplication of the mass and acceleration of an object.

F = ma

and, a ∝ 1/m

From the above equation, we can say that acceleration (a) is inversely proportional to the mass (m) of the body.

In the given option the person with a mass of 150 pounds will accelerate faster with the same amount of force and the person with a mass of 300 pounds will accelerate the least.

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if it rotates through 8.00 revolutions in the first 2.50 s , how many more revolutions will it rotate through in the next 5.00 s ?

Answers

The object will rotate through 16.00 revolutions in the next 5.00s if it rotates through 8.00 revolutions in the first 2.50s.

The first step to answer this question is to determine the rotational speed (angular velocity) of the object. To do this, we use the formula:

Angular velocity = number of revolutions / time

So, the angular velocity of the object is given by:

Angular velocity = 8.00 revolutions / 2.50 s

Angular velocity = 3.20 revolutions per second

Now, we can use this angular velocity to determine the number of revolutions the object will rotate through in the next 5.00 s. To do this, we use the formula:Number of revolutions = angular velocity x time

So, the number of revolutions the object will rotate through in the next 5.00 s is given by:

Number of revolutions = 3.20 revolutions per second x 5.00 s

Number of revolutions = 16.00 revolutions

Therefore, the object will rotate through 16.00 revolutions in the next 5.00 s.

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On a distance-time graph, time is shown on the y-axis.
A) True
B) False

Answers

Answer:

false : In distance time graph,time is shown on the x -axis

On the line before each effect, write the letter of the cause that correctly complete each sentence. Some causes might be more than once.

On the line before each effect, write the letter of the cause that correctly complete each sentence.

Answers

The light energy absorbed by a surface depends on D. the tilt of the surface.

A beam of light becomes more spread out as E. the beam of light is spread out more.

Some energy is absorbed by Earth's surface when C. the beam of light reaches Earth.

Energy is less concentrated near

G. Earth's poles.

Less energy reaches the poles because

E. the beam of light is spread out more.

Earth is warmest at the equator because

F. energy is concentrated there.

Earth is coldest at the poles because

H. tilt is the greatest there.

Surface temperature depends on the amount of energy absorbed by the surface.

Less energy is received in regions where

E. the beam of light is spread out more.

Earth is warm at the equator and cold at

G. Earth's poles.

What is the motion of the Earth about

The Earth moves in a variety of ways through space. Its main motions are:

Rotation: The Earth rotates on its axis, an imaginary line passing through the North and South Poles. This motion causes day and night to occur, and it takes approximately 24 hours for the Earth to complete one rotation.

Revolution: The Earth revolves around the sun in an elliptical orbit, completing one revolution in approximately 365.25 days. This motion is responsible for the changing of the seasons and the length of the year.

Precession: The Earth's axis wobbles as it rotates, like a spinning top.

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A simple harmonic oscillator has an amplitude of 3. 50 cm and a maximum speed of 26. 0 cm/s. What is its speed when the displacement is 1. 75 cm?.

Answers

Answer:

1.) A simple harmonic oscillator has an amplitude of 3.50 cm and a maximum speed of 26.0 cm/s. What is its speed when the displacement is 1.75 cm? 2.) Both pendulum A and B are 3.0 m long. The period of A is T. Pendulum A is twice as heavy as pendulum B. What is the period of B? 3.) The time for one cycle of a periodic process is called the _ ? 4.) In simple harmonic motion, the acceleration is proportional to? 5.) The position of a mass that is oscillating on a spring is given by x= (18.3 cm) cos [(2.35 s-1)t]. What is the frequency of this motion?

Explanation:

You will measure and record the time it takes the cart to travel certain distances, and then complete some calculations. In the space below, write a scientific question that you will answer by doing this experiment.

Answers

Answer:

Take the measurement of the distance (d) with a meter rule (in meters) and also measure the time (t) of the travel in seconds with a stopwatch.

question: What is the speed of the cart?

Explanation:

The speed of an object in motion is the distance covered by the object with respect to time, that is, the ratio of distance covered to the time taken to reach that distance.

Speed = distance / time

           = d (in meters m) / t (in seconds s) = m/s

suppose you place 3.31mL of a substance into a graduated cylinder. The graduated cylinder has a mass of 12.55 g when empty and a mass of 15.5 7 g after adding the substance. what is the density of the substance (in g/ml)

Answers

The density of the substance is 0.913 grams per milliliter (g/mL).

Density is a measure of how much mass is contained in a certain volume of a substance. It is defined as the mass of a substance divided by its volume. In this problem, we need to calculate the density of a substance given its volume and the mass of the substance and the container it is placed in.

To calculate the density of the substance, we need to first determine the mass of the substance alone. We can do this by subtracting the mass of the empty graduated cylinder from the mass of the cylinder with the substance in it.

The mass of the substance can be calculated as follows:

Mass of substance = Mass of cylinder with substance - Mass of empty cylinder

Mass of substance = 15.57 g - 12.55 g

Mass of substance = 3.02 g

Now that we know the mass of the substance, we can calculate its density using the formula:

Density = Mass / Volume

We were given the volume of the substance as 3.31 mL, so we can plug this into the formula:

Density = 3.02 g / 3.31 mL

Simplifying this expression gives us the density of the substance:

Density = 0.913 g/mL

Therefore, the density of the substance is 0.913 grams per milliliter (g/mL). This means that for every milliliter of the substance, there is 0.913 grams of mass. Density is a fundamental property of a substance that can help us identify or classify it.

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What field of vision is more sensitive to light and motion and orients individuals to the environment?

Answers

The peripheral field of vision is more sensitive to light and motion and orients individuals to the environment.

Field of vision refers to the total area that an individual can see without moving the eyes. It comprises the central and peripheral fields of vision. The central field of vision is the area directly in front of an individual, whereas the peripheral field of vision is the area beyond the central field of vision. The peripheral field of vision detects movement and light and orients individuals to their environment. As a result, the peripheral field of vision is more sensitive to light and motion and orients individuals to the environment.

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does anybody know?? Please help

does anybody know?? Please help

Answers

Step 1;
Resolve or break the motion into horizontal and vertical components along the x- and y- axes.

Step 2;
Treat the motion as two independent one-dimensional motions, one horizontal and the other vertical

Step 3;
Solve for the unknowns in two separate motions—one horizontal and one vertical

Step 4; Recombine the two motions to find the total displacements and velocity v.

A student walked 100 meters north, then 100 meters west. How many more meters did the student walk compared to their total displacement from their starting point?.

Answers

Answer: The total distance walked is about 59 meters more than the student’s displacement.

Explanation:

The student walked 58.57 meters more than compared to its total displacement from its starting point.

What are Distance and Displacement?

Distance is a measurement of how far apart two things or points are, either numerically or occasionally qualitatively. The distance can refer to a physical length in physics or an estimate based on other factors in common usage.

The term "displacement" refers to a shift in an object's position. It is a vector quantity with a magnitude and direction. The symbol for it is an arrow pointing from the initial location to the ending place. For instance, if an object shifts from location A to position B, its position changes. Displacement is the term used to describe this shift in an object's position.

According to the question :

A student walked 100 meters north and then walks 100 meters west then its displacement will be, according to the Pythagoras theorem

h² = p²+b²

h² = 100² + 100²

h² = 20,000

h = 141.42 meters

This means the total displacement is 141.42 meters, but the student has traveled 200 meters.

200 - 141.42 = 58.57 meters

Hence, the student walks 58.57 meters more than the total displacement.

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5. Determine What factors affect the strength

of the gravitational force between objects?

Provide an example. SC.8.E.5.4

Answers

The two key factors that affect the strength of the gravitational force between objects are their mass and the distance between them.

The factors that affect the strength of the gravitational force between objects are:
1. Mass of the objects: The strength of the gravitational force increases with the increase in mass of the objects involved.
2. Distance between the objects: The strength of the gravitational force decreases with the increase in distance between the objects.
In summary, the strength of the gravitational force between objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between them. This relationship is described by Newton's law of universal gravitation.

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If the period of the oscillator doubles, what happens to the wavelength and wave speed?.

Answers

If the period of the oscillator doubles, what happens to the wavelength and wave speed, then the wavelength doubles but the wave speed is unchanged.

A periodic wave's wavelength is its spatial period or the length over which its shape repeats. a measurement of the separation between two similar points (adjacent crests) in two successive cycles of a waveform signal travelling through space or along a wire. As a result, the wave has travelled one wavelength in one period of time. With this knowledge and the speed formula (speed = distance/time), it is possible to conclude that a wave's speed is also its wavelength/period.

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A turbine fan in jet engine has a moment of inertia of 2.5 kg'm12 about its axis of rotation. As the turbine starts up, it angular velocity is given by w,2 = (40 rad/s 3)t*2. (a) Find the fan's angular momentum as a function of time, and find its value at t- 3.0s. (b) Find the net torque on the fan as a function of time, and find its value at t= 3.0s.

Answers

a. Therefore, the angular momentum of the fan at t = 3.0 s is 900 kg \(m^2/s.\)

b. Therefore, the net torque on the fan at t = 3.0 s is 600 kg \(m^2/s^2.\)

(a) The angular momentum (L) of the fan is given by:

L = Iω

I = moment of inertia and ω is the angular velocity.

Substituting the given values, we get:

L = \((2.5 kg m^2)(40 rad/s^3t^2) = 100t^2 kg m^2/s\)

The angular momentum at t = 3.0 s, we simply substitute t = 3.0 s into the equation:

L = \(100(3.0 s)^2 kg m^2/s = 900 kg m^2/s\)

(b) The net torque (τ) on the fan is given by:

τ = Iα

α is the angular acceleration.

Taking the derivative of the angular velocity with respect to time, we get:

α = dω/dt = 80 rad/s^3t

Substituting the given values, we get:

τ = \((2.5 kg m^2)(80 rad/s^3t) = 200t kg m^2/s^2\)

To find the net torque at t = 3.0 s, we simply substitute t = 3.0 s into the equation:

τ = \(200(3.0 s) kg m^2/s^2 = 600 kg m^2/s^2\)

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you place a 100 g piece of iron and a 100g piece of lead inside a well insulated container. the initial temp of the lead is 30 degrees celsius, but you do not know the initial temperature of the iron. You seal the insulated container and wait until the lead and iron reach a common final temperature of 177 degrees Celcius. What was the initial temperature of the iron?

Answers

The initial temperature of the iron was approximately 94.3 degrees Celsius.

To solve this problem, we can use the principle of conservation of energy, which states that the total energy of a closed system is constant.

We can assume that the insulated container and its contents form a closed system, and that the heat lost by the lead is gained by the iron until they reach a common final temperature.

We can use the following equation to relate the heat gained or lost by a substance to its mass, specific heat, and change in temperature:

Q = mcΔT

where

Q is the heat gained or lost,

m is the mass,

c is the specific heat, and

ΔT is the change in temperature.

Since the insulated container is well insulated, we can assume that no heat is lost to the surroundings, so the total heat gained by the iron must equal the total heat lost by the lead:

\(m_{iron} * c_{iron} * (T_{final} - T_{initial}) = m_{lead} * c_{lead} * (T_{initial} - T_{lead})\)

where

\(m_{iron}\) and  \(c_{iron}\)  are the mass and specific heat of iron,

\(T_{final\) is the common final temperature of the iron and lead,

\(T_{initial\) is the initial temperature of the iron,

\(m_{lead\)  and  \(c_{lead\)  are the mass and specific heat of lead, and

\(T_{lead\) is the initial temperature of the lead.

We can substitute the given values into the equation and solve for \(T_{initial\):

\(100 g * c_{iron} * (177°C - T_{initial}) = 100 g * c_{lead} * (T_{initial} - 30C)\)

Dividing both sides by 100 g and rearranging:

c_iron * (177°C - T_initial) = c_lead * (T_initial - 30°C)

c_iron * 177°C - c_iron * T_initial = c_lead * T_initial - c_lead * 30°C

(c_iron + c_lead) * T_initial = c_iron * 177°C + c_lead * 30°C

T_initial = (c_iron * 177°C + c_lead * 30°C) / (c_iron + c_lead)

Substituting the specific heat values for iron and lead (0.45 J/g°C and 0.13 J/g°C, respectively):

T_initial = (0.45 J/g°C * 177°C + 0.13 J/g°C * 30°C) / (0.45 J/g°C + 0.13 J/g°C)

T_initial = 94.3°C

Therefore, the initial temperature of the iron was approximately 94.3 degrees Celsius

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I was watching quantum leap and I was wondering if we can actually travel through different people's body without knowing it's actually me.

Answers

Answer:

No you could not do that because if you tried even if you where to go super fast they would feel a breif second of pain before being completely riped from there body

Please for the love of humanity please answer this question and my other question...​

Please for the love of humanity please answer this question and my other question...

Answers

Answer:

It's "C"

Explanation:

Friction slows things down.

"Friction always slows a moving object down. The amount of friction depends on the materials from which the two surfaces are made. The rougher the surface, the more friction is produced. Friction also produces heat. "

-Google

Sherlock Holmes examines a clue by holding his magnifying glass (with a focal length of 24.5 cm) 10.5 cm away from an object.
a.) Find the image distance. Answer in units of cm
b.) Find the magnification.
c.) Describe the image he observes (real/virtual, upright/inverted, larger/smaller)

Answers

a) The image distance is -31.18 cm (real and inverted).

b) The magnification is -1.28.

c) Sherlock Holmes observes a real and inverted image that is smaller in size.

a) To find the image distance, we can use the lens equation:

  1/f = 1/di + 1/do

  where f is the focal length, di is the image distance, and do is the object distance. Given that the focal length (f) is 24.5 cm and the object distance (do) is 10.5 cm, we can substitute these values into the equation:

  1/24.5 = 1/di + 1/10.5

  Solving for di, we find:

  di ≈ -31.18 cm

  The negative sign indicates that the image is formed on the opposite side of the lens, which corresponds to a real image.

b) The magnification (M) is given by the ratio of the image distance to the object distance:

  M = di/do

  Substituting the values, we have:

  M ≈ -31.18 cm / 10.5 cm ≈ -1.28

  The negative magnification indicates that the image is inverted.

c) Based on the negative magnification and the fact that the image is formed on the opposite side of the lens (real image), we can conclude that Sherlock Holmes observes a real and inverted image. Since the magnification is greater than 1, the image is smaller in size compared to the object.

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Suppose that a (small) charged conductor is connected to ground. We all know that the charged conductor will become uncharged because charges move. Explain why any charges move. [2]

Answers

When a small charged conductor is connected to the ground, charges move to make the potential on the conductor zero. These charges flow from the conductor to the ground, canceling the electric field on the conductor.

When a small charged conductor is connected to the ground, the charges start to move to make the potential on the conductor zero. It is due to the potential difference between the conductor and the ground that charges flow between the conductor and the ground. In this process, electrons flow from the ground to the charged conductor, neutralizing it. As a result, the charge on the conductor disappears.When a conductor is charged, it has a potential difference between it and the ground. The potential difference is due to the charges residing on the conductor. If the conductor is connected to the ground, the potential difference between the conductor and the ground is removed, and the charges flow to the ground until the potential on the conductor becomes zero. This is because the charges move until the potential on the conductor is zero because the potential difference between the conductor and the ground is the driving force for the movement of the charges. As a result, the charged conductor becomes uncharged.

When a charged conductor is connected to the ground, charges move from the conductor to the ground, canceling the electric field on the conductor. It is due to the potential difference between the conductor and the ground that charges flow between the conductor and the ground. As a result, the conductor becomes uncharged.

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What is the average speed of the tiger between the times t = 0s and t
= 12 s?
Choose 1 answer:
m
(A
6
S
m
B
-0.33
s
m
S
0.33
S

Answers

Answer:

A.6s

Explanation:

Average time=

\(average time \: t = \frac{t1 + t2}{2 } \\ \frac{0 + 12}{2} \\ \frac{ 12}{2} \\ t = 6s\)

Cane Company manufactures two products called Alpha and Beta that sell for $240 and $162, respectively. Each product uses only one type of raw material that costs $5 per pound. The company has the capacity to annually produce 131,000 units of each product. Its average cost per unit for each product at this level of activity are given below:

Alpha Beta
Direct materials $ 35 $ 15
Direct labor 48 23
Variable manufacturing overhead 27 25
Traceable fixed manufacturing overhead 35 38
Variable selling expenses 32 28
Common fixed expenses 35 30
Total cost per unit $ 212 $ 159
The company considers its traceable fixed manufacturing overhead to be avoidable, whereas its common fixed expenses are unavoidable and have been allocated to products based on sales dollars.

8. Assume that Cane normally produces and sells 80,000 Betas and 100,000 Alphas per year. If Cane discontinues the Beta product line, its sales representatives could increase sales of Alpha by 13,000 units. What is the financial advantage (disadvantage) of discontinuing the Beta product line?

9. Assume that Cane expects to produce and sell 100,000 Alphas during the current year. A supplier has offered to manufacture and deliver 100,000 Alphas to Cane for a price of $160 per unit. What is the financial advantage (disadvantage) of buying 100,000 units from the supplier instead of making those units?

10. Assume that Cane expects to produce and sell 75,000 Alphas during the current year. A supplier has offered to manufacture and deliver 75,000 Alphas to Cane for a price of $160 per unit. What is the financial advantage (disadvantage) of buying 75,000 units from the supplier instead of making those units?

Answers

The financial advantage of discontinuing the Beta product line would be a disadvantage of $9,840,000. The financial advantage of buying 100,000 units from the supplier instead of making them would be an advantage of $4,700,000.The financial advantage of buying 75,000 units from the supplier instead of making them would be an advantage of $3,525,000.

To calculate the financial advantage or disadvantage of discontinuing the Beta product line, we need to compare the costs and revenues associated with the current situation and the proposed scenario.

Currently, the company produces and sells 80,000 Betas and 100,000 Alphas. If the Beta product line is discontinued, the sales representatives can increase Alpha sales by 13,000 units.

In the current situation:

Revenue from Beta sales = 80,000 units × $162 = $12,960,000

Revenue from Alpha sales = 100,000 units × $240 = $24,000,000

Total revenue = $12,960,000 + $24,000,000 = $36,960,000

In the proposed scenario:

Increased Alpha sales = 113,000 units × $240 = $27,120,000

Therefore, the financial advantage or disadvantage can be calculated as:

Financial Advantage = Revenue in proposed scenario - Revenue in current situation

Financial Advantage = $27,120,000 - $36,960,000 = -$9,840,000

The financial advantage of discontinuing the Beta product line would be a disadvantage of $9,840,000.

To determine the financial advantage or disadvantage of buying 100,000 units from the supplier instead of making them, we need to compare the costs of production with the purchase cost from the supplier.

Cost of producing 100,000 Alphas:

Direct materials cost = 100,000 units × $35 = $3,500,000

Direct labor cost = 100,000 units × $48 = $4,800,000

Variable manufacturing overhead = 100,000 units × $27 = $2,700,000

Traceable fixed manufacturing overhead = 100,000 units × $35 = $3,500,000

Variable selling expenses = 100,000 units × $32 = $3,200,000

Common fixed expenses = 100,000 units × $30 = $3,000,000

Total cost of producing 100,000 units = $3,500,000 + $4,800,000 + $2,700,000 + $3,500,000 + $3,200,000 + $3,000,000 = $20,700,000

Cost of buying 100,000 units from the supplier = 100,000 units × $160 = $16,000,000

Therefore, the financial advantage or disadvantage can be calculated as:

Financial Advantage = Cost of producing - Cost of buying

Financial Advantage = $20,700,000 - $16,000,000 = $4,700,000

The financial advantage of buying 100,000 units from the supplier instead of making them would be an advantage of $4,700,000.

Similarly, to determine the financial advantage or disadvantage of buying 75,000 units from the supplier instead of making them, we follow the same calculations as in question 9, but with the quantities adjusted accordingly.

Cost of producing 75,000 Alphas:

Direct materials cost = 75,000 units × $35 = $2,625,000

Direct labor cost = 75,000 units × $48 = $3,600,000

Variable manufacturing overhead = 75,000 units × $27 = $2,025,000

Traceable fixed manufacturing overhead = 75,000 units × $35 = $2,625,000

Variable selling expenses = 75,000 units × $32 = $2,400,000

Common fixed expenses = 75,000 units × $30 = $2,250,000

Total cost of producing 75,000 units = $2,625,000 + $3,600,000 + $2,025,000 + $2,625,000 + $2,400,000 + $2,250,000 = $15,525,000

Cost of buying 75,000 units from the supplier = 75,000 units × $160 = $12,000,000

Therefore, the financial advantage or disadvantage can be calculated as:

Financial Advantage = Cost of producing - Cost of buying

Financial Advantage = $15,525,000 - $12,000,000 = $3,525,000

The financial advantage of buying 75,000 units from the supplier instead of making them would be an advantage of $3,525,000.

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