Substitution method please

Answer:

Put the thing at the 6 going forward. The inequality would be w>6

Step-by-step explanation:

Answer:

m< JKL = 63°

m< MKL = 27°

Step-by-step explanation:

(12x+3) + (6x-3) =90°

18x = 90

x= 90/18

x=5

m< JKL (12x+3) = 12(5)+3=60+3=63

m< MKL (6x-3)=6(5)-3=30-3=27

I hope I helped you^_^

The value of the total area of the shaded region are,

⇒ 42 units²

We have to given that;

Sides of rectangle are,

AB = 9

BC = 6

Hence, The area of rectangle is,

⇒ 9 x 6

⇒ 54 units²

And, Area of triangle is,

A = 1/2 × 4 × 6

A = 12 units²

Thus, The value of the total area of the shaded region are,

⇒ 54 - 12

⇒ 42 units²

So, The value of the total area of the shaded region are,

⇒ 42 units²

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She multiplied by -5 on one side whereas she should have divided by -5 on both sides, and she failed to turn the > sign to a symbol. She should divide both sides by -5. Option B

This is further explained below.

Since, we have to solve for x

-5x-3.5>6.5

Add both sides by 3.5

-5x-3.5+3.5>6.5+3.5

-5x>10

Divide both sides by -5

We are aware that anytime both sides are divided by a negative sign, the inequality of the result is appreciated.

\(\frac{-5 x}{-5} < \frac{-50}{-5}\)

x<10

She multiplied by -5 on one side whereas she should have divided by -5 on both sides, and she failed to turn the > sign to a symbol. She should divide both sides by -5.

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CQ

Parul attempted to solve an inequality but made one or more errors. Her work and the graph she drew are shown below. What errors did Parul make? Check all that apply. She added 3.5 to both sides when she should have subtracted. She should have divided both sides by as her first step. She divided one side by -5 while multiplying the other side by -5. She did not change the > symbol to a < symbol. She used a closed circle instead of an open circle on the number line.

Answer:

An odd number

Step-by-step explanation:

suppose n is 2.

If we add 1 into it, the answer will be 3, making it odd. same goes for any other even number if 1 is added in it

Answer:

To solve the equation y = -5/2x - 7, we can first multiply both sides of the equation by 2x + 7, which is the denominator of the fraction on the right-hand side. This gives us the equation 2xy + 7y = -5, which we can rearrange to isolate the variable y on one side of the equation. Dividing both sides of the equation by 2x + 7, we get y = -5 / (2x + 7). This is the solution to the original equation.

Step-by-step explanation:

Simplify each term.

y= −5 x2 −7

Answer:

-2.1f-18

Step-by-step explanation:

-2.4f+0.3f=-2.1f.

-16-3=-19

distance = speed x time

distance  time

45 ft          3.0 s

87 ft          5.8 s

166.5 ft    11.1 s

210 ft        14.0 s

P(X = 0) = 0.335 Probability = 0.335.The given formula for probability distribution is:P(X) = (n! / x! (n - x)!) * πx * (1 - π)n - xwhere, P = Probability X = Random variable, n = Total number of trialsπ = Probability of success. Let us consider the given probabilities:(a) For n - 5 and π = 0.16, what is P(X:0)?When n = 5 and x = 0, then n - x = 5.

Therefore,

P(X = 0) = (5! / 0! (5 - 0)!) * (0.16)0 * (1 - 0.16)5 - 0= (1 / 1) * 1 * 0.3277= 0.3277Round off the answer to four decimal places as needed.P(X = 0) = 0.3277.(b) For n 9 and x-0.50, what is P(X 8)?When n = 9 and x = 8, then n - x = 1. Therefore,P(X = 8) = (9! / 8! (9 - 8)!) * (0.50)8 * (1 - 0.50)9 - 8= (9 / 1) * 0.00390625 * 0.5= 0.0176.

Round off the answer to four decimal places as needed.P(X = 8) = 0.0176(c) For n 9 and -0.40, what is P(X-7)?When n = 9 and x = 7, then n - x = 2. Therefore,P(X = 7) = (9! / 7! (9 - 7)!) * (0.40)7 * (1 - 0.40)9 - 7= (36 / 1) * 0.0809856 * 0.027= 0.0807.

Round off the answer to four decimal places as needed.P(X = 7) = 0.0807(d) For n-6 and x-0.81, what is P(x-5)?When n = 6 and x = 5, then n - x = 1. Therefore,P(X = 5) = (6! / 5! (6 - 5)!) * (0.81)5 * (1 - 0.81)6 - 5= (6 / 1) * 0.3252718081 * 0.19= 0.3727Round off the answer to four decimal places as needed.P(X = 5) = 0.3727.

To determine the given probabilities, the probability distribution formula has been used. The formula used is:P(X) = (n! / x! (n - x)!) * πx * (1 - π)n - xWhere,P is the probability,X is the random variable,n is the total number of trials, andπ is the probability of success. The first probability is to calculate the probability for n - 5 and π = 0.16, what is P(X:0)?The value of x is zero, and n - x is 5. The formula is applied to get the probability, and it is rounded off to four decimal places as needed. The second probability is to calculate the probability for n 9 and x-0.50, what is P(X 8)?The value of x is 8, and n - x is 1. The formula is applied to get the probability, and it is rounded off to four decimal places as needed. The third probability is to calculate the probability for n 9 and -0.40, what is P(X-7)?The value of x is 7, and n - x is 2. The formula is applied to get the probability, and it is rounded off to four decimal places as needed. The fourth probability is to calculate the probability for n -6 and x-0.81, what is P(x-5)?The value of x is 5, and n - x is 1. The formula is applied to get the probability, and it is rounded off to four decimal places as needed.

Therefore, the probabilities for different values of n, x, and π have been calculated by using the probability distribution formula.

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Answer:

Step-by-step explanation:

According to question we have:

See attached picture

Find the area:

As per the median, the set of data that fulfilling Marjane's requirement is 24, 25, 25, 25, 26, 26 (option c).

In statistics, data is a collection of numbers or values that represent a particular phenomenon. One way to measure central tendency, or the typical or representative value of the data, is through the median and the mode.

The median is the middle value when the data is arranged in numerical order, and the mode is the value that appears most frequently.

The third set of data is 24, 25, 25, 25, 26, 26.

The median is the middle value, which is also (25+25)/2 = 25.

The mode is the value that appears most frequently, which is 25.

Therefore, the mode and median are the same, fulfilling Marjane's requirement.

Therefore, the correct option is (c).

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Answer:

52%

Step-by-step explanation:

Divide the number 26 by the whole 50

26/50=0.52

Then multiply the result by 100. Why?-----> % is out of 100

0.52*100= 52

And add the % sign

= 52%

Given:

Find-:

How many times greater the radius of Saturn is than the radius of Earth

Explanation:-

Let "x" times greater than the radius of Saturn is than the radius of Earth

So,

So Saturn's radius is 9.407 times greater than the radius of the earth.

Bracing a newly planted tree with a stake creates a triangular support system that satisfies the SAS or SSS Inequality, ensuring the tree remains perpendicular to the ground and stable.

The SAS (Side-Angle-Side) or SSS (Side-Side-Side) Inequality is a geometric principle used to determine whether a triangle can be formed with given side lengths or angle measures. While it is typically used in triangle geometry, we can apply the concept of the SAS or SSS Inequality to explain why bracing a newly planted tree with a stake is effective in keeping it perpendicular to the ground.

When a tree is planted, it may not have a strong root system established yet, making it vulnerable to being tilted or uprooted by external forces such as wind or uneven soil conditions. By bracing the tree with a stake tied to the trunk, a triangular support system is created.

Now, let's consider the triangle formed by the tree trunk, the stake, and the ground. The length of the stake acts as one of the sides of the triangle, while the distance between the base of the tree trunk and the stake forms the other side. The height of the tree from the base to the top represents the third side of the triangle.

To ensure the tree remains perpendicular to the ground, the length of the stake and the distance between the base of the trunk and the stake must be carefully chosen. The length of the stake needs to be long enough to provide sufficient support and prevent the tree from leaning or tilting. Similarly, the distance between the base of the trunk and the stake should be adjusted to provide stability.

Applying the SAS or SSS Inequality, we can state that for the tree to remain perpendicular to the ground:

1. The length of the stake (side) must be greater than the distance between the base of the trunk and the stake (side) to provide adequate support.

2. The height of the tree (side) should not exceed the sum of the length of the stake (side) and the distance between the base of the trunk and the stake (side).

By satisfying these conditions, the triangular support system created by the stake and the tree trunk ensures that the tree remains stable and upright, minimizing the risk of leaning or falling over.

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The Propositions from the given data are All Statements except Statement A.

(a) What time is dinner? This is not a proposition because it is a question and does not have a definite truth value.

(b) It is not the case that π is not a rational number. This is a proposition and its truth value is True because pi is not a rational number.

(c) x / 2 is a rational number. This is not a proposition because it is a statement about a variable, and the truth value depends on the value of x.

(d) 2x + 3y is a real number. This is not a proposition because it is a statement about variables, and the truth value depends on the values of x and y.

(e) Either π is rational and 17 is a prime, or 7 < 13 and 81 is a perfect square. This is a proposition and its truth value is False, because neither pi is rational nor 17 is prime.

(f) Either 2 is rational and π is irrational, or 2π is rational. This is a proposition and its truth value is False, 2 is rational and π is irrational.

(g) Either 5π is rational and 4.9 is rational, or there are exactly four primes less than 10. This is a proposition and its truth value is False because 5π is not rational and 4.9 is not rational and also there are four primes less than 10.

(h) −3.7 is rational, and either 3π < 10 or 3π > 15. This is a proposition and its truth value is False because −3.7 is not rational.

(i) It is not the case that 39 is prime, or that 64 is a power of 2. This is a proposition and its truth value is True because 39 is not a prime and 64 is a power of 2.

(j) There are more than three false statements in this book, and this statement is one of them. This is a proposition and its truth value is False because it is self-referential and also it's not true that there are more than three false statements in this book.

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Answer:

C

Step-by-step explanation:

I might be wrong but the best option I see would be C

The exact forecasted number of customers to be served on each of the next five business days, rounded to one decimal place, are as follows:

Tuesday: 389.1

Wednesday: 368.7

Thursday: 326.5

Friday: 510.9

To forecast the number of customers served on each of the next five business days using Winters' method, we need to follow these steps:

Calculate the seasonal factor for each day by multiplying the seasonal index by the level.

Monday: 1.10 × 20 = 22

Tuesday: 0.95 × 20 = 19

Wednesday: 0.90 × 20 = 18

Thursday: 0.80 × 20 = 16

Friday: 1.25 × 20 = 25

Update the level and trend using the following formulas:

New Level = α × (Actual Value / Seasonal Factor) + (1 - α) × (Previous Level + Previous Trend)

New Trend = β × (New Level - Previous Level) + (1 - β) * Previous Trend

For Tuesday:

New Level = 0.2 × (30 / 22) + 0.8 × (20 + 1) = 20.3636

New Trend = 0.1 × (20.3636 - 20) + 0.9 × 1 = 0.0364

Forecast the number of customers served on each subsequent day using the formula:

Forecast = (New Level + Forecasted Trend) × Seasonal Factor

Tuesday Forecast = (20.3636 + 0.0364) × 19 = 389.0909

Wednesday Forecast = (20.3636 + 0.0364) × 18 = 368.7273

Thursday Forecast = (20.3636 + 0.0364) × 16 = 326.5455

Friday Forecast = (20.3636 + 0.0364) × 25 = 510.9091

Therefore, the forecasted number of customers to be served on each of the next five business days, rounded to one decimal place, are as follows:

Tuesday: 389.1

Wednesday: 368.7

Thursday: 326.5

Friday: 510.9

The question should be: A local bank is using Winters' method with α = 0.2, β= 0.1, and γ = 0.5 to forecast the number of customers served each day. The bank is open Monday through Friday. At the end of the previous week, the following seasonal indexes have been estimated: Monday, 1.10; Tuesday, 0.95; Wednesday, 0.90; Thursday, 0.80; Friday, 1.25. Also, the current estimates of level and trend are 20 and 1. After observing that 30 customers are served by the bank on this Monday, forecast the number of customers who will be served on each of the next five business days. Round your answers to one decimal place, if necessary.

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Answer:

The tip is $7.43

The total answer $56.93

Step-by-step explanation:

Hope this helps!

Answer:

c 56.93

Step-by-step explanation:

49.5 × 1.15= 56.93

Since there are uncountably many distinct pairs of real numbers, we get an uncountable family of dense subsets of R.

Let S and T be non-empty subsets of a topological space (X,τ) with S⊆T.

Here is the solution:(i) If p is a limit point of the set S, then every open set that contains p contains a point q of S, distinct from p. If U is an open set containing p, then U also contains q ∈ S ⊆ T, so p is a limit point of T.(ii) We know that Sˉ, the closure of S is the set of all limit points of S. Hence, Sˉ consists of points p of X that satisfy the condition that every open set U containing p intersects S in a point q distinct from p. If p ∈ Sˉ, then every open set U containing p intersects S in a point q.

In particular, every open set V containing p also intersects T in a point q ∈ S ⊆ T. Therefore, p ∈ Tˉ.(iii) If S is dense in X, then Sˉ = X. From part (ii) of the question, we know that Sˉ ⊆ Tˉ. Therefore, Tˉ = (Sˉ)ˉ = X.

In other words, T is dense in X.(iv) To show that R has an uncountable number of distinct dense subsets, we make the following observation: for any distinct a,b ∈ R, the sets a + Z and b + Z are dense in R.

Indeed, let U be an open set in R. Let r be any real number. Then U contains an open interval (r - ε, r + ε) for some ε > 0. Let n be any integer. Then the set (a + nε/2, b + nε/2) intersects U.

Therefore, (a + Z) ∪ (b + Z) is dense in R.

Since there are uncountably many distinct pairs of real numbers, we get an uncountable family of dense subsets of R.

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Using proportions, it is found that it will take 75 loads to move all the gravel.

A proportion is a fraction of a total amount, and the measures are related using a rule of three.

In one load, they mode 80 pounds. How many loads are needed to move 3 tons = 3 x 2000 = 6000 pounds? The rule of three is given as follows:

1 load - 80 pounds

x loads - 6000 pounds

Applying cross multiplication:

80x = 6000

x = 6000/80

x = 75.

It will take 75 loads to move all the gravel.

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Answer: it should be 3/4

Step-by-step explanation:

There is not sufficient evidence at the 0.02 level to refute the hospital director's claim that 44 percentage of lab reports contain errors.

To determine if there is sufficient evidence to refute the hospital director's claim that 44% of lab reports contain errors, we can use a hypothesis test with a significance level of 0.02.

Our null hypothesis (H0) is that the true proportion of errors in lab reports is 0.44, while our alternative hypothesis (Ha) is that the true proportion is different from 0.44.

We can use the formula for a test statistic, which is:

z = (p‌ - p) / √(p*(1-p)/n)

where p‌ is the sample proportion, p is the hypothesized proportion under the null hypothesis, and n is the sample size.

Plugging in the given values, we get:

p‌ = 92/230 = 0.4

p = 0.44

n = 230

Calculating the test statistic, we get:

z = (0.4 - 0.44) / √(0.44*(1-0.44)/230) = -1.93

Looking up the critical value for a two-tailed test at a significance level of 0.02, we get 2.33. Since our test statistic (-1.93) is less than the critical value (-2.33), we fail to reject the null hypothesis.

Therefore, there is not sufficient evidence at the 0.02 level to refute the hospital director's claim that 44% of lab reports contain errors. However, it is important to note that this conclusion is based on a single sample and may not necessarily hold true for all lab reports in the hospital. Further testing with larger samples may be necessary to confirm or refute this claim with greater certainty.

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The acceleration components of point D are, ax = 3.6 m/s², ay = 6.4 m/s², az = -1.14 m/s²

At the instant shown, the shaft and plate rotates with an angular velocity of 19 rad/s and angular acceleration of 9 rad/s2. The given diagram is shown below. Angular velocity (w) = 19 rad/sAngular acceleration (α) = 9 rad/s²Plate dimension AB = 0.6 m, BC = 0.2 m, CD = 0.4 m, DA = 0.3 m, AE = 0.3 m and EF = 0.4 m.

Determine the wocl and Dsea of Enter the ", y, and Z components of the velocity separated by commas vec m/sThe velocity components for point D can be calculated using the following formula.Vd = R x wWhere R is the position vector of D relative to the origin.

According to the given diagram, the position vector of point D relative to the origin is, R = 0.2i + 0.4j + 0.3kThe velocity of point D can be calculated as follows.Vd = R x w = 0.2i + 0.4j + 0.3k x 19The cross product of R and w can be calculated as follows.i j k 0.2 0.4 0.3 0 19 0 = [(0.4 × 0) - (0.3 × 19)] i - [(0.2 × 0) - (0.3 × 0)] j + [(0.2 × 19) - (0.4 × 0)] kVd = -5.7i + 6.8kThus, the velocity components of point D are, Vx = -5.7 m/s, Vy = 0 m/s, Vz = 6.8 m/s

Determine the acceleration of point D located on the corner of the plate at this instant. Enter the, y, and Z components of the velocity separated by commas vec m/sThe acceleration components of point D can be calculated using the following formula.aD = R x α + w x (w x R)Where R is the position vector of D relative to the origin.

According to the given diagram, the position vector of point D relative to the origin is, R = 0.2i + 0.4j + 0.3kThe acceleration of point D can be calculated as follows.aD = R x α + w x (w x R) = (0.2i + 0.4j + 0.3k) x 9 + 19 x (19 x (0.2i + 0.4j + 0.3k)) = (0.4k - 0.3j) x 9 + 19 x (0.4 x (0.4j - 0.3k))aD = 3.6i + 6.4j - 1.14k.

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Answer:

this is how you solve it

Step-by-step explanation:

so how many times can 15 fit in 1 hour

4 times right?

15 x 4 = 60

theres 3 hours

60 x 3 = 120!

120 is ur answer

hope this helps

have a great day

stay safe

We must solve for x using the addition principle, the equation is as follows

In conclusion, the answer is x = -9

The concept of "equally likely outcomes" refers to the idea that every possible outcome in a given sample space has an equal chance of occurring. In other words, if we were to conduct the experiment multiple times, each possible outcome would have an equal probability of being observed.

In the case of rolling a fair die, the sample space consists of the numbers 1 through 6, and each of these outcomes has an equal probability of occurring. This is because the die is assumed to be fair, meaning that each side has an equal chance of landing face-up.

However, in the case of a loaded die, the sample space does not have equally likely outcomes. This is because the probabilities of each outcome are not equal. A loaded die is one that has been manipulated in some way so that certain outcomes are more likely than others. For example, if the loaded die has been weighted to favor the number 6, then the probability of rolling a 6 would be higher than the probability of rolling any of the other numbers.

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The 85% confidence interval that the true mean number of words a third grader can read per minute is between 30.131 and 30.869.

To create a confidence interval for the mean number of words a third grader can read per minute, an educational psychologist wishes to know the mean number of words a third grader can read per minute. She intends to produce an estimate at an 85% level of confidence.

For a sample of 146 third graders, the mean words per minute read was 30.5. Assume a population standard deviation of 3.1.

To create a confidence interval, the following formula can be used:

µ±z_α/2*σ/√n

Here, we are given the following details:

Sample size: n = 146

Mean: µ = 30.5

Population standard deviation: σ = 3.1

Level of confidence: α = 1 - 0.85 = 0.15

We need to determine the critical value of z_α/2.

α/2 ⇒ 0.15/2 ⇒ 0.075

Using a standard normal distribution table, we find that the value of z_0.075 is 1.44.

Confidence Interval: µ ± z_α/2*σ/√n

⇒ 30.5 ± 1.44 × (3.1/√146)

⇒ 30.5 ± 0.369

Thus, the confidence interval for the mean number of words a third grader can read per minute is (30.131, 30.869).

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