Ssuming that the relationship between spring compression and height is quadratic, how far will the ball go at the highest setting, which compresses the spring 3 cm ?

The strong nuclear force overcomes the repulsive electric force of protons in the atomic nucleus because it is a much stronger force. It is able to act over very short distances and is mediated by particles that are much heavier than electrons and photons.

The repulsive electric force of protons in the atomic nucleus does not cause the protons to fly apart because of the strong nuclear force. The strong nuclear force is an attractive force between nucleons that overcomes the repulsion between protons due to the electromagnetic force. This force is responsible for holding the nucleus of an atom together.

We will explain the physics behind why the strong nuclear force overcomes the repulsive electric force. The protons in the nucleus are positively charged and would normally repel each other due to the electrostatic force. The reason why they do not is because they are held together by a stronger force, the strong nuclear force. This force acts between nucleons, which are particles found in the nucleus of an atom. The strong nuclear force is a short-range force that acts over distances of less than a femtometer. It is much stronger than the electrostatic force, which is why it is able to hold the nucleus together. The reason for this is that the strong nuclear force is mediated by particles called mesons, which are much heavier than electrons and photons. The strong force is able to overcome the repulsion between protons because it is much stronger than the electromagnetic force, which is what causes the repulsion in the first place.

The strong nuclear force overcomes the repulsive electric force of protons in the atomic nucleus because it is a much stronger force. It is able to act over very short distances and is mediated by particles that are much heavier than electrons and photons. This force is responsible for holding the nucleus of an atom together and is what allows for the existence of matter as we know it.

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The power of the appropriate corrective lens should be approximately -49.75 diopters (D) to see objects clearly at a distance of 26.0 cm.

To calculate the power of the appropriate corrective lens, we can use the lens formula:

1/f = 1/v - 1/u

Where:

f is the focal length of the lens,

v is the image distance (distance of the clear image formed by the lens), and

u is the object distance (distance of the object being viewed).

In this case, we want to see objects clearly at a distance of 26.0 cm, so v = -26.0 cm (since the image is formed on the same side as the object). The near point of the person's eye is given as 54.2 cm, so u = -54.2 cm.

Plugging these values into the lens formula:

1/f = 1/(-26.0 cm) - 1/(-54.2 cm)

Simplifying:

1/f = -0.0385 cm⁻¹ - (-0.0184 cm⁻¹)

1/f = -0.0385 cm⁻¹ + 0.0184 cm⁻¹

1/f = -0.0201 cm⁻¹

To find the power (P) of the lens in diopters, we can use the formula:

P = 1/f

Substituting the value of 1/f we obtained:

P = 1/(-0.0201 cm⁻¹)

P ≈ -49.75 D

The negative sign indicates that the lens required is a concave lens (diverging lens).

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Answer:

Simple machines are useful because they reduce effort or extend the ability of people to perform tasks beyond their normal capabilities. Simple machines that are widely used include the wheel and axle, pulley, inclined plane, screw, wedge and lever.

Answer:

Simple machines are useful because they reduce effort or extend the ability of people to perform tasks beyond their normal capabilities. Simple machines that are widely used include the wheel and axle, pulley, inclined plane, screw, wedge and lever.

Explanation:

funny answer cuz peeps be lazy

Answer:

I THINK ITS B but I'm not suresorry

Answer:

The amplitude is a measure of its change in a single period (such as time or spatial period)

what is amplitude?

A periodic variable's amplitude is a measure of its change across a single period, such as time or space. Amplitude is defined in a variety of ways, but they're all based on the size of the disparities between the variable's extreme values. The amplitude of a periodic function is sometimes referred to as the phase in older writings texts.

So free point OK ty see ya!

Answer:

silk-ties fabric

rubber-rubber bands

cellulose-jeans

starch-food and paper

dna-genetic

Explanation:

If the speed of the magnet is doubled, the induced voltage will be four times as great.

According to Faraday's Law of Electromagnetic Induction, the magnitude of the induced voltage in a coil is directly proportional to the rate of change of magnetic flux through the coil. When the speed of the magnet is doubled, the rate of change of magnetic flux through the coil also doubles, resulting in a doubling of the induced voltage.

However, since the induced voltage is directly proportional to the rate of change of magnetic flux, a doubling of the speed of the magnet results in a fourfold increase in the rate of change of magnetic flux, which leads to a fourfold increase in the induced voltage. Therefore, if the speed of the magnet is doubled, the induced voltage will be four times as great. This effect is important in many applications, such as electrical generators, where the speed of the rotor is used to control the output voltage of the generator.

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Answer:

See below

Explanation:

You didn't show the e-magnet construction diagram....but:

If the e-magnet is built properly and has current flowing through the coils, it will affect the compass.....also note that a compass is a magnet, so if the e-magnet is ferrous (iron-containng)  material it will affect the compass ....current flowing or not !

In order to find the magnitude of the electric field at the origin, you need to use the equation E = q/4πεr², where q is the charge, ε is the permittivity of space, and r is the distance from the origin.

To calculate the electric field, you must first determine the charge of the particle, then determine the distance to the origin, and finally, use the equation to calculate the magnitude of the electric field.

Once you have the magnitude of the electric field at the origin, you can then use it to explore the behavior of other electric fields in the area.

To calculate the magnitude, you must first determine the values of k, q, and r, then plug them into the equation and solve. The resulting answer will be the magnitude of the electric field at the origin.

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The distance the 2.0-cm-diameter piston must be pushed down to raise 9 cm diameter is 607.5 cm.

The distance the piston must be pushed down is calculated as follows;

A₁d₁ = A₂d₂

πr₁²d₁ = πr₂²d₂

r₁²d₁ = r₂²d₂

(1)²(d₁) = (4.5)²30

d₁ = 607.5 cm

Thus, the distance the 2.0-cm-diameter piston must be pushed down to raise 9 cm diameter is 607.5 cm.

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Answer:

Synthesis(Two substances that react to form one product): A + C -> AC

Decomposition(A compound that breaks down into two+ more substances): AB -> A + B

Single Replacement(replaced by another substance): A + BC -> AC + B

Double Replacement(Two substances replaced): AB + CD -> AD + CB

Combustion(A reaction between oxygen and another substance such as water) : CH + O2 -> CO2 + H2O

So that would mean that

\(H_{2}O + SO_{3} - > H_{2}SO_{4}= Synthesis 2H_{2}O_{2} - > 2H_{2}O + O_{2} = DecompositionPb(No_{3})_{2} + 2KI - > 2KNO_{3} + PbIx_{2} = Replacement C_{3}H_{8} + 50_{2} - > 3C0_{2} + 4H_{2}O - Combustion\)

Explanation:

The lawn mower is moving with a velocity of 17.53 m/s

Energy is the ability to do work while Work is defined as the product of force and distance moved in the direction of the force. Both work and energy are measured in Joule (J)

Work = Force (F) × distance (d) = FdCosθ

With the above formula, we can obtain the energy used in pushing the lawn mower as illustrated below

From the question given above, the following data were obtained:

•Force (F) = 75 N

•Distance (d) = 25 m

•Angle (θ) = 35°

•Energy (E) =?

E = FdCosθ

E = 75 × 25 × Cos 35

E = 1535.91 J

Velocity is the rate of change of displacement with time.

Velocity and energy are related according to the following equation:

E = ½ × mass (m) × square velocity (v²)

E = ½mv²

With the above formula, we can obtain the velocity of the lawn mower as follow

•Mass (m) = 10 Kg

•Energy (E) = 1535.91 J

•Velocity (v) =?

E = ½mv²

1535.91 = ½ × 10 × v²

1535.91 = 5 × v²

Divide both side by 5

v² = 1535.91 / 5

Take the square root of both side

v = √(1535.91 / 5)

v = 17.53 m/s

Thus, the lawn mower is moving with a velocity of 17.53 m/s

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Answer:

gamma waves

Explanation:

gamma rays" from lightning discharges at 10 to 20 MeV, and known to be produced by the bremsstrahlung mechanism. Another example is gamma-ray bursts, now known to be produced from processes too powerful to involve simple collections of atoms undergoing radioactive decay.

Answer:

B. 24.2 m/s

Explanation:

Given;

mass of the roller coaster, m = 450 kg

height of the roller coaster, h = 30 m

The maximum potential energy of the roller coaster  due to its height is given by;

\(P.E_{max} = mgh\\\\PE_{max} = 450 *9.8*30\\\\PE_{max} = 132,300 \ J\)

\(P.E_{max} = K.E_{max} \ (law \ of \ conservation\ of \ energy)\)

\(K.E_{max} = \frac{1}{2}mv_{max}^2\\\\ v_{max}^2 = \frac{2K.E_{max}}{m}\\\\ v_{max}^2 = \frac{2*132300}{450}\\\\ v_{max}^2 =588\\\\v_{max} = \sqrt{588}\\\\ v_{max} = 24.2 \ m/s\)

Therefore, the maximum speed of the roller coaster is 24.2 m/s.

Answer:

1. 24.2 m/s

2. 20.4 m

3. 22.5 m/s

4. 109,375 J

5. It is easy to calculate new scenarios.

Explanation:

5/5 on the Maximum Energy Quick Check

Answer:the magnitude of the hikers resultant displacement

Explanation:

Gamma: 4

Infrared: 1

X-Ray: 3

Visible Light: 2

Infrared has the longest wavelength between the four options, meaning that it has the lowest frequency. Since the longer the frequency, the lower the frequency. While the shorter the wavelength, the higher the frequency.

The portions of the electromagnetic spectrum are called from greatest to lowest energy: gamma rays, X-rays, ultraviolet radiation, visible light, infrared radiation, and radio waves. Microwaves (such as those used in microwave ovens) are a subset of the electromagnetic spectrum's radio wave segment.

Next would be visible light since it has the second longest wavelength out of the given options. Then it would be X-Ray. And finally Gamma since it has the shortest wavelength.

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The magnitude of the downward acceleration of the hollow cylinder is 6m/s^2.

Z = I α

T.R =1/2 M ( \(R^{2}\) + \((R/2)^{2}\) )α

T.R = 1/2M 5\(R^{2}\)/4 α

T = 5Ma/8

Mg - T = Ma

Mg -  5Ma/8 =  Ma

Mg= 5Ma/8 +  Ma = 13Ma / 8

acceleration = 8g/13 = 6 m/s^2

The rate at which an object's velocity with respect to time changes is called its acceleration. The direction of the net force imposed on an item determines its acceleration in relation to that force. According to Newton's Second Law, the magnitude of an object's acceleration is the result of two factors working together

The size of the net balance of all external forces acting on that item is directly proportional to the magnitude of this net resultant force; the magnitude of that object's mass, depending on the materials from which it is built, is inversely related to its mass.

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The acceleration of the plane is 8 m/s² while covering a distance of 1.20 km in 5 seconds.

To find the acceleration of the plane, we can use the following equation:

Acceleration (a) = (Final velocity (v) - Initial velocity (u)) / Time (t)

First, we need to convert the distance from kilometers to meters:

1.20 km = 1.20 × 10³ m

Given:

Initial velocity (u) = 2.00 × 10² m/s

Final velocity (v) = 2.40 × 10² m/s

Distance (s) = 1.20 × 10³ m

Using the formula for acceleration, we can rearrange it to solve for acceleration:

a = (v - u) / t

Since the airplane is flying level, we assume a constant velocity, so the time (t) can be calculated as:

t = s / v

Plugging in the values:

t = (1.20 × 10³ m) / (2.40 × 10² m/s) = 5 seconds

Now we can calculate the acceleration:

a = (2.40 × 10² m/s - 2.00 × 10² m/s) / 5 s = 8 m/s²

Therefore, the acceleration of the plane must be 8 m/s².

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If a cannonball takes 1.15 seconds to fall to the ground, and air resistance is negligible. Gravity does 127.24 Joules of work on the falling cannonball, and the average power exerted by gravity during the fall is 110.64 Watts.

The work done by gravity on the falling cannonball is calculated using the formula W = mgh, where W is the work done, m is the mass of the cannonball, g is the acceleration due to gravity, and h is the height from which the cannonball falls.

First, we need to find the height (h). Since air resistance is negligible, we can use the free-fall equation h = 0.5 * g * t², where t is the time it takes for the cannonball to fall. Given that t = 1.15 seconds and g = 9.81 m/s², we can calculate the height:
h = 0.5 * 9.81 * (1.15²) = 6.501075 m

Now we can find the work done by gravity:
W = mgh = 2.00 kg * 9.81 m/s² * 6.501075 m = 127.24 J (Joules)

During the fall, the average power exerted by gravity on the cannonball can be found using the formula P = W / t, where P is the power and t is the time taken:
P = 127.24 J / 1.15 s = 110.64 W (Watts)

In summary, gravity does 127.24 Joules of work on the falling cannonball, and the average power exerted by gravity during the fall is 110.64 Watts.

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The critical value is 7.82. Because the calculated chi-square value is greater than the critical value, the null hypothesis can be rejected.

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The depression was caused by a number of serious weaknesses in the economy. ... The lingering effects of World War I (1914-1918) caused economic problems in many countries, as Europe struggled to pay war debts and reparations. These problems contributed to the crisis that began the Great Depression. hope AND I HOPE it helps

Answer:

No

Explanation:

Electromagnetic radiation is used for communications and transmission of information. The waves that are used in this way are radio waves, microwaves, infrared radiation and light.

Answer:

stress tension tensile strength

Explanation:

The maximum stress which a material can withstand when it is pulled apart is its: stress tension tensile strength.

Answer:

Explanation:

Velocity = Displacement/Time

Given

Displacement = 880m

Time = 25s

Required

Average velocity

Substituting the given values into the formula

Velocity = 800/25

Average velocity = 32m/s

Answer:

The Answer Is -32 m/s

Explanation:

Displacement trianglex = -800m

time t = 25 s

Average velocity v = ?

You can use the equation v = trianglex/t to solve for average velocity v.

v = trianglex/t

= -800m/25s

= -32 m/s

The work done in pumping all the liquid out of the tank is 2500π lb-ft.

The potential energy of an object is given by the formula:

PE = mgh

Given:

Density of oil = 50 lb/ft^3

Diameter of the tank = 10 ft ( r = 5 ft)

To calculate the work done, we need to find the mass of the oil and the height it is lifted. Let's start by finding the mass:

Volume of oil in the tank:

The volume of a hemisphere = (2/3) * π * (r^3)

Volume = (2/3) * π * (5^3) = (2/3) * π * 125 = 250π/3 ft^3

Mass of the oil:

Mass = Volume * Density = (250π/3) * 50 lb

Now, we need to find the height of the tank. For a hemisphere, the height is equal to the radius (5 ft).

Finally, we can calculate the work done:

Work = PE = mgh = (250π/3) * 50 lb * 5 ft

Work = (250π/3) * 50 * 5 lb-ft

       = 2500π lb-ft

So, the work done in pumping all the liquid out of the tank is approximately 2500π lb-ft.

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Coulomb's experiment aimed to demonstrate the inverse-square law of electrostatic interaction, which it successfully achieved. He used a torsion balance to measure the forces of attraction and repulsion between charged objects.

In his experiments, Coulomb suspended two identical charged pith balls from the same point, each on separate thin strings, causing them to hang horizontally and in contact with each other. Another charged pith ball, also suspended on a thin string from the same point, could be brought close to the two hanging pith balls, resulting in their repulsion.

The experiments conducted by Coulomb confirmed that the electrostatic force of repulsion between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

This relationship can be mathematically expressed as:

\(\[ F = \frac{{kq_1q_2}}{{r^2}} \]\)

Here, F represents the electrostatic force of attraction or repulsion between the charges, q1 and q2 denote the magnitudes of the charges, r is the distance between the charges, and k is Coulomb's constant.

When considering two electrons separated by a distance r, the electrostatic force of repulsion between them can be calculated as:

\(\[ F_e = \frac{{kq_1q_2}}{{r^2}} \]\)

where q1 = q2 = -1.6x10^-19C, representing the charge of an electron.

Thus, the electrostatic force of repulsion between two electrons is:

\(\[ F_e = \frac{{kq_1q_2}}{{r^2}} = \frac{{9x10^9 \times 1.6x10^-19 \times 1.6x10^-19}}{{r^2}} = 2.3x10^-28/r^2 \]\)

On the other hand, when considering the gravitational force of attraction between two electrons, it can be expressed as:

\(\[ F_g = \frac{{Gm_1m_2}}{{r^2}} \]\)

where m1 = m2 =\(9.11x10^-31kg\) represents the mass of an electron, and G = \(6.67x10^-11N.m^2/kg^2\) is the gravitational constant.

Therefore, the gravitational force of attraction between two electrons is:

\(\[ F_g = \frac{{Gm_1m_2}}{{r^2}} = \frac{{6.67x10^-11 \times 9.11x10^-31 \times 9.11x10^-31}}{{r^2}} = 5.9x10^-72/r^2 \]\)

Consequently, the ratio of the electrostatic force of repulsion between two electrons to their gravitational force of attraction can be calculated as:

\(\[ \frac{{F_e}}{{F_g}} = \frac{{\frac{{2.3x10^-28}}{{r^2}}}}{{\frac{{5.9x10^-72}}{{r^2}}}} = 3.9x10^43 \]\)

This implies that the electrostatic force of repulsion between two electrons is approximately 10^43 times greater than their gravitational force of attraction. It is important to note that the gravitational force between the pith balls should not have been included in Coulomb's experiment since it is significantly weaker, by several orders of magnitude, compared to the electrostatic force between the charges on the balls.

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Answer:

The impulse transferred to the nail is 0.01 kg*m/s.

Explanation:

The impulse (J) transferred to the nail can be found using the following equation:

\( J = \Delta p = p_{f} - p_{i} \)

Where:                                                                

\(p_{f}\): is the final momentum

\(p_{i}\): is the initial momentum

The initial momentum is given by:

\( p_{i} = m_{1}v_{1_{i}} + m_{2}v_{2_{i}} \)

Where 1 is for the hammer and 2 is for the nail.

Since the hammer is moving down (in the negative direction):

\(v_{1_{i}} = -10 m/s \)

And because the nail is not moving:

\(v_{2_{i}}= 0\)                      

\( p_{i} = m_{1}v_{1_{i}} = 0.25 kg*(-10 m/s) = -2.5 kg*m/s \)

Now, the final momentum can be found taking into account that the hammer remains in contact with the nail during and after the blow:

\( p_{f} = m_{1}v_{1_{f}} + m_{2}v_{2_{f}} \)

Since the hammer and the nail are moving in the negative direction:

\(v_{1_{f}}\) = \(v_{2_{f}}\) = -9.7 m/s

\( p_{f} = -9.7 m/s(7 \cdot 10^{-3} kg + 0.25 kg) = -2.49 kg*m/s \)

Finally, the impulse is:

\( J = p_{f} - p_{i} = - 2.49 kg*m/s + 2.50 kg*m/s = 0.01 kg*m/s \)

Therefore, the impulse transferred to the nail is 0.01 kg*m/s.

I hope it helps you!