SOMEONE PLEASE HELP!
5.) Write both an explicit equation and a recursive equation for the sequence 4, 2, 1,05,0.25...

Explicit equation:


Recursive equation:


HURRY PLEASE!!!​

Step-by-step explanation:

\(Domain:\ x>0\ \wedge\ y>0\)

\(\dfrac{2\sqrt{x}-3\sqrt{y}}{\sqrt{x}+\sqrt{y}}\qquad|\text{use}\ (a+b)(a-b)=a^2-b^2\\\\=\dfrac{2\sqrt{x}-3\sqrt{y}}{\sqrt{x}+\sqrt{y}}\cdot\dfrac{\sqrt{x}-\sqrt{y}}{\sqrt{x}-\sqrt{y}}=\dfrac{(2\sqrt{x}-3\sqrt{y})(\sqrt{x}-\sqrt{y})}{(\sqrt{x}+\sqrt{y})(\sqrt{x}-\sqrt{y})}\\\\\text{use FOIL}\ (a+b)(c+d)=ac+ad+bc+bd\\\\=\dfrac{(2\sqrt{x})(\sqrt{x})+(2\sqrt{x})(-\sqrt{y})+(-3\sqrt{y})(\sqrt{x})+(-3\sqrt{y})(-\sqrt{y})}{(\sqrt{x})^2-(\sqrt{y})^2}\)

\(\text{use}\ (\sqrt{a})^2=a\ \text{and}\ (\sqrt{a})(\sqrt{a})=a\ \text{for}\ a\geq0\\\text{and}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\ \text{for}\ a\geq0\ \wedge\ b\geq0\\\\=\dfrac{2x-2\sqrt{xy}-3\sqrt{xy}+3y}{x-y}\qquad|\text{combine like terms}\\\\=\dfrac{2x+3y-5\sqrt{xy}}{x-y}\)

The prime factorization of the number 21 is:

21 = 3*7

We want to write the prime factorization of 21.

To do so, we just need to divide the number by prime numbers.

The first prime number we can try is 2, if we divide by 2 we get:

21/2 = 10.5

This is not an integer, so 2 is not a factor.

The next one is 3:

21/3 = 7

Now we can rewrite:

21 = 3*7

Where 3 and 7 are prime numbers, so that is the prime factorization.

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In order to calculate the standard error of the sample mean, you'll need to use the following formula:

Standard Error (SE) = Standard Deviation (SD) / √(Sample Size)

In this case, you have the following information:
- The average refund in the 2011 tax year, according to the IRS, was $3,109 (this is not directly needed for the calculation).
- The standard deviation for these refunds is $874.
- The random sample size is 50 tax returns.

Now, plug these values into the formula:

SE = 874 / √(50)

SE ≈ 874 / 7.071

SE ≈ 123.64

The standard error of the sample mean for a random sample of 50 tax returns is approximately $123.64.

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Answer:

5 eggs

Step-by-step explanation:

Part A) To find what percent of the paint is red, you divide the part (5) by the whole (15 + 5 = 20)

Answer: 5/20 = 25%

Part B) To simplify the 15:5 ratio of yellow paint to red paint, you determine what number both 5 and 15 is divisible by. Both 5 and 15 are divisible by 5.

15/5 = 3 and 5/5 = 1   Therefore, the simplified ratio is 3/1 or 3:1 (read as 3 to 1)

Answer:

Parallel mean the same slope so it is - 2

Y-3=-2(x+3)

Y-3=-2x-6

Y=-2x+3

Answer:

24 minutes

Step-by-step explanation:

Fred can mow a lawn in 60 minutes.

Fred's Rate  \(=\frac{1}{60}\)

Rocky can mow the same lawn in 40 minutes.

Rocky's rate \(=\frac{1}{40}\)

Let the time it will take both of them = x minutes

Therefore:

\(\frac{1}{60}+\frac{1}{40}=\frac{1}{x}\\$Multiply all through by 1200$\\1200\times \frac{1}{60}+1200\times\frac{1}{40}=1200\times\frac{1}{x}\\20+30=\frac{1200}{x}\\50=\frac{1200}{x}\\$Cross multiply\\50x=1200\\Divide both sides by 50\\x=24\\\)

It would take the two of them 24 minutes to mow the lawn.

Answer:

probably not helpful but a lil guide; first you need to solve for slope. (y2-y1/x2-x1) this will be m. next solve for y, to do this put on of your x values (2 or 6) using y=mx+b. to get b, place x=0.

The value of the given expression is 16000, which can be written in scientific notation as 1.6 * \(10^4\). Therefore, a = 1.6 and k = 4.

Given expression is 4.0 *\(10^3\) 4 * \(10^2\). The product of these two expressions can be found as follows:

4.0 *\(10^3\) * 4 *\(10^2\) = (4 * 4) * (\(10^3\) * \(10^2\)) = 16 *\(10^5\)

To write this value in scientific notation, we need to make the coefficient (the number in front of the power of 10) a number between 1 and 10.

Since 16 is greater than 10, we need to divide it by 10 and multiply the exponent by 10. This gives us:

1.6 * \(10^6\)

Since we want to express the value in terms of a * \(10^k\), we can divide 1.6 by 10 and multiply the exponent by 10 to get:

1.6 * \(10^6\) = (1.6 / 10) * \(10^7\)

Therefore, a = 1.6 and k = 7. To check if this is correct, we can convert the value back to decimal notation:

1.6 * \(10^7\) = 16,000,000

This is the same as the product of the original expressions, which was 16,000. Therefore, the values of a and k when the value of the given expression is written in scientific notation are a = 1.6 and k = 4.

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To find the possible values of k, we need to calculate the determinant of matrix D and set it equal to 1024.

Given matrix D:

D = | k 0 0 |

| 3 k² k³ |

| 0 kª k³ kº |

| k k k |

| 0 0 0 |

| k¹⁰ |

The determinant of D can be calculated by expanding along the first row or the first column. Let's expand along the first row:

det(D) = k(det | k³ k k |

| 0 k³ kº |

| 0 0 k¹⁰ |)

- 0(det | 3 k² k³ |

| 0 kª k³ |

| k k k |)

+ 0(det | 3 k² k³ |

| k k k |

| k k k |)

Simplifying further, we have:

det(D) = k(det | k³ k k |

| 0 k³ kº |

| 0 0 k¹⁰ |)

Now, we can calculate the determinant of the 3x3 submatrix:

det | k³ k k |

| 0 k³ kº |

| 0 0 k¹⁰ |

This determinant can be found by expanding along the first row or the first column. Expanding along the first row gives us:

det = k(k³(kº) - 0(k)) - 0(0(k¹⁰)) = k⁴kº = k⁴+kº

Now, we can set det(D) equal to 1024 and solve for k:

k⁴+kº = 1024

Since we are looking for all possible values of k, we need to solve this equation for k. However, solving this equation may require numerical methods or approximations, as it is a quartic equation.

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Answer:

\(48a^{2}\)

Step-by-step explanation:

First, multiply the numbers

-8a ( -6)a

48aa

Next, We can combine the exponents

\(48a^{2}\)

That is all you need to do. : - )

The image of dilating the points by a scale factor 3.5 with centre of enlargement (4, -6) is (-7, 14), (0, 14), (-7,7) and (0, 7)

The coordinates are given as:

(2,-2) (4,-2) (2,-4) (4,-4)

The scale factor is given as:

k = 3.5

The center of enlargement is given as:

(a,b) = (4, -6)

The image of dilation is calculated using:

\((x,y) \to (k(x -a), k(y -b))\)

So, we have:

A = (3.5(2 -4), 3.5(-2 +6))

A = (-7, 14)

B = (3.5(4 -4), 3.5(-2 +6))

B = (0, 14)

C = (3.5(2 -4), 3.5(-4 +6))

C = (-7,7)

D = (3.5(4 -4), 3.5(-4 +6))

D = (0, 7)

Hence, the image of dilating the points is (-7, 14), (0, 14), (-7,7) and (0, 7)

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The answer is: A) The data support the researchers' belief that night owls have better dream recall than early birds. B) we can be 92% confident that the true difference in mean number of dreams recalled per week between night owls and early birds is between 1.87 and 2.63.

A) These are the alternative and null hypotheses:

H0: μE = μN (the mean number of dreams recalled each week is the same for early birds and night owls) (the mean number of dreams recalled per week is the same for early birds and night owls)

Ha: μE < μN (the mean number of dreams recalled each week is smaller for early birds than for night owls) (the mean number of dreams recalled per week is lower for early birds than for night owls)

Using the following formula, we can run a two-sample t-test with unequal variances:

t = [(sN2 / nN) + (sE2 / nE)] / sqrt[(xN - xE)]

where nN and nE are the sample sizes for night owls and early birds, respectively, and xN and sN and xE and sE are the sample means and standard deviations for night owls and early birds, respectively.

When we enter the values, we obtain:

t = (9.55 - 7.26) / sqrt[(5.88^2 / 100) + (6.94^2 / 100)] = 5.01

The data are consistent with the researchers' hypothesis that night owls are more capable of remembering their dreams than early birds.

B) We can use the following formula to determine the confidence interval:

CI is equal to (xN - xE) t/2 * sqrt[(sN / nN) + (sE / nE)].

where t/2 is the t-value for the required level of confidence and degrees of freedom, and xN, xE, sN, sE, nN, and nE are the same as previously (198 in this case).

With a t-value of 1.75 and a 92% confidence level (from a t-distribution with 198 degrees of freedom), we get:

CI is equal to (9.55 - 7.26) 1.75 * sqrt[(5.88 - + 6.94 / 100)] = (1.87, 2.63) (1.87, 2.63)

The genuine difference between night owls and early birds in terms of the average number of dreams recalled per week is therefore between 1.87 and 2.63, with a 92% confidence interval.

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Answer:

- 36\(w^{8}\) - 36\(w^{6}\) - 36\(w^{5}\)

Step-by-step explanation:

Using the rule of exponents

\(a^{m}\) × \(a^{n}\) = \(a^{(m+n)}\) , then

4\(w^{5}\) (- 9w³ - 9w - 9) ← distribute parenthesis by 4\(w^{5}\)

= - 36\(w^{(5+3)}\) - 36\(w^{(5+1)}\) - 36\(w^{5}\)

= - 36\(w^{8}\) - 36\(w^{6}\) - 36\(w^{5}\)

Answer:

\( = > 4 {w}^{5} ( - 9 {w}^{3} - 9w - 9) \\ \: \: \: \: = > - 36w {}^{5 + 3} - 36 {}^{5 + 1} - 36 {}^{5} \\ = > - 36 w{}^{8} - {36w}^{6} - 36w {}^{5} \)

The investigator is using stratified random sampling.

Stratified random sampling is a probability sampling technique in which the population is divided into sub-populations (called strata) according to one or more common characteristics. A random sample is then taken from each stratum, and the samples from all strata are combined to form the overall sample.

Formula:

Let S = Total population size

Let N = Sample size

Let N1, N2, N3, ..., Nn = Sample sizes from each stratum

Then, N1 + N2 + N3 + ... + Nn = N

Calculation:

In this case, the investigator is dividing the schools in the state into groups based on school district. Therefore, the total population size (S) is the total number of high schools in the state. The sample size (N) is the total number of high schools and students included in the survey. The sample sizes from each stratum (N1, N2, N3, ..., Nn) are the number of high schools and students randomly selected from each school district.

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The answers that  best explains how we check to make sure that this condition is met is: c. Make sure there is similar spread around the sample mean of y.

The equal spread condition states that the residuals (differences between the actual and predicted values of y) should have roughly equal variance at each value of x.

To check if this condition is met, we examine the residual plot, which is a scatterplot of the residuals versus the independent variable x. If the spread of residuals around the mean is roughly equal for all x, then the equal spread condition is satisfied.

Therefore the correct option is C.

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The z-values for the given situations are approximate:

a. The area to the left of z is 0.1827. z = -0.90

b. The area between −z and z is 0.9830. z = 2.17

c. The area between −z and z is 0.2148. z = 0.85

d. The area to the left of z is 0.9997. z = 3.49

e. The area to the right of z is 0.6847. z= -0.48

a. For an area of 0.1827 to the left of z, the corresponding z-value can be found using a standard normal distribution table or a statistical calculator. The z-value is approximately -0.90.

b. To find the z-value for an area between -z and z equal to 0.9830, we need to find the value that corresponds to (1 - 0.9830)/2 = 0.0085 in the upper tail of the standard normal distribution. Using the table or calculator, the z-value is approximately 2.17.

c. Similarly, for an area between -z and z equal to 0.2148, we find the value that corresponds to (1 - 0.2148)/2 = 0.3926 in the upper tail. The z-value is approximately 0.85.

d. For an area of 0.9997 to the left of z, we find the value that corresponds to 0.9997 in the upper tail. The z-value is approximately 3.49.

e. To find the z-value for an area to the right of z equal to 0.6847, we find the value that corresponds to 1 - 0.6847 = 0.3153 in the upper tail. The z-value is approximately -0.48.

In summary, the z-values for the given situations are approximate:

a. -0.90

b. 2.17

c. 0.85

d. 3.49

e. -0.48

These values can be used to determine the corresponding percentiles or probabilities for the standard normal distribution. The values are typically found using standard normal distribution tables or statistical calculators that provide the cumulative probability distribution function (CDF) for the standard normal distribution.

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Answer:

x = 14.25

Step-by-step explanation:

7(x-9)=3(x-2)

Follow the distributive property

7x - 63 = 3x - 6

Add 63 to both sides

7x = 3x + 57

Subtract 3x from both sides

4x = 57

Divide both sides by 4

x = 14.25

Answer:

the answer is 14.25 or 14 1/4

Step-by-step explanation:

The probability that a randomly selected score will be between 77 and 83 is 0.2841

The probability that a randomly selected score will be between 77 and 83 can be found using the Z-score formula and the standard normal distribution table.

First, we need to calculate the Z-scores for both 77 and 83 using the formula:

Z = (X - μ)/σ

Where X is the score, μ is the mean, and σ is the standard deviation.

For 77:

Z = (77 - 77.4)/7.8 = -0.05

For 83:

Z = (83 - 77.4)/7.8 = 0.72

Now, we can use the standard normal distribution table to find the probability for each Z-score. The table gives us the area to the left of the Z-score on the standard normal distribution curve.

For Z = -0.05, the probability is 0.4801.

For Z = 0.72, the probability is 0.7642.

To find the probability that a randomly selected score will be between 77 and 83, we need to subtract the smaller probability from the larger probability:

0.7642 - 0.4801 = 0.2841

Therefore, the probability that a randomly selected score will be between 77 and 83 is 0.2841.

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The score she needs on the next test for her average to be 84% = 92

In this question, Jordan has an average of 82% on her first four tests.

We need to find the score she needs on the next test for her average to be 84%

We know that, average score = sum of scores / number of tests

Jordan has an average of 82% on her first four tests.

Using the formula of the average,

82 = sum of score / 4

sum of scores = 328

Let 'm' be  the score she needs on the next test for her average to be 84%

Using the formula of the average,

84 = (328 + m) / 5

420 = 328 + m

m = 92

Therefore, the score she needs on the next test for her average to be 84% = 92

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A lifeline in a sequence diagram is a line that is used to represent an active object, such as a class, interface, or object, and is typically identified by a solid line.

A lifeline in a sequence diagram is a graphical element used to depict the active objects in an interaction or sequence diagram. The lifeline is typically represented as a solid line running from the top of the diagram to the bottom, which represents the object's lifetime. The lifeline is used to show the messages that are sent and received between objects, as well as the sequence in which they occur. Additionally, the lifeline is often used to represent any changes of state in the objects, such as method calls, data values, and more. By depicting the lifelines of the active objects in a sequence diagram, it is possible to gain a better understanding of the interactions between the objects, and how they are related.

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Answer:

I tried to answer this and, I'm sorry but I couldn't even figure it out

Dr black is standing 13 feet from a streetlamp. The lamp is making his shadow 9 feet long. He estimates that the angle of elevation from the tip of his shadow to the top of the streetlamp is 50° to the nearest foot the streetlamp is about  26 feet tall.

I hope this helps!

Answer:

x = 16

I hope this helps!

Answer:

x=16

Step-by-step explanation:

The angles of the inside of a triangle always add up to 180

2*16= 32

3*16=48

16+84=100

32+48+100=180

Answer:

14

Step-by-step explanation:

70/5 = 14

Answer: l tried may bad some one can do this one

Step-by-step explanation:

Answer:

y^3

Step-by-step explanation:

x^3 y^3     and    y^4  

y^3 * x^3     and y^3  * y

H(t) represents the reaction's temperature t hours after it starts. Midline, amplitude, and period are 5h, 70°, and 40° respectively.

Knuckles or crenulations along the midline can be found directly behind the hump. The lone blowhole is situated far forward on the head, considerably to the left of the midline. Midline research gives you the chance to assess how the program is doing and determine how you may change course and do better. It is an opportunity to examine the program's design and the logic that went into it while it is still in use. In the sagittal plane, the body's midline follows the centre of the body. In other words, the body is divided into left and right halves by the midline, which extends from the top of the head to the bottom of the feet.

The period of the function is y=H(t)= 5h Include units in your answer. The midline of the function is y=H(t)= 70degC Include units in your answer. The amplitude of the function is y=H(t)= 40degC Include units in your answer.

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The function f(x) = √(x - 1) is continuous on the interval [1, ∞).

To determine the interval where the function f(x) = √(x - 1) is continuous, we need to consider the domain of the function.

In this case, the function is defined for x ≥ 1 since the square root of a negative number is undefined. Therefore, the domain of f(x) is the interval [1, ∞).

Since the domain includes all its limit points, the function f(x) is continuous on the interval [1, ∞).

Thus, the correct answer is [1, ∞).

In interval notation, we use the square bracket [ ] to indicate that the endpoints are included, and the round bracket ( ) to indicate that the endpoints are not included.

Therefore, the function f(x) = √(x - 1) is continuous on the interval [1, ∞).

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