someone please help

The probability that at least one bulb out of 12 will stop working during holiday season making all of lights go out on string is given by 0.2153.

Number of bulbs working throughout the holiday season = 12

Chance of each bulb working throughout the holiday season = 98%

Let A be the event that at least one bulb stops working during the holiday season, .

Making all of the lights go out, and let B be the event that all bulbs work throughout the holiday season.

Find P(A), the probability of event A.

Use the complement rule to find P(A),

P(A) = 1 - P(B)

To find P(B), we need to calculate the probability that each of the twelve bulbs works throughout the holiday season,

0.98¹² = 0.7847

So, the probability that all bulbs work throughout the holiday season is 0.7847.

This implies,

P(A) = 1 - P(B)

       = 1 - 0.7847

       = 0.2153

Therefore, probability that at least one bulb will stop working during  holiday season, making all of the lights go out on the string is 0.2153.

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Answer:

\(2.28*10^7\)

Step-by-step explanation:

\((2.4*10^3)(9.5*10^3)=(2.4*9.5)(10^3*10^3)=22.8*10^6=2.28*10^7\)

Answer:

228,000

Step-by-step explanation:

(2.4x10^3) x (9.5x10^3)

(2.4x100) x (9.5x100)

240x950

228,000

The perimeter of the rectangle is given by 4x+2.

The area of a rectangle is given by the formula A=l*w where l is the length and w is the width. In this case, the area is given by the equation x^2 + x - 6. To find the perimeter of the rectangle, we need to know the length and width. However, since the area is represented by an equation, we do not have a specific value for the length and width. The given equation x^2 + x - 6 is a quadratic equation which can be factorised as (x-2)(x+3). So, we can't find the length and width without the value of x. To find the perimeter of a rectangle we use the formula P=2(l+w). If we know the value of x, we can find the perimeter of rectangle. But, as we don't have the value of x, we can't find the perimeter of the rectangle

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Complete question:

Given a rectangle If its area is x² + x – 6, what is the perimeter of the rectangle .

Answer: The answer is B 7/4

Step-by-step explanation:

Answer: C

Step-by-step explanation: C

2 divided into 9 parts is 2/9.

Let's' explain this visually

Take this pizza, (image below)

Let's say we have two pizzas for 8 friends (including ourselves), so naturally, we'll cut the pizza's each into 9 slices, 1 for each, now everyone gets 1/9 of a pizza, but there are two pizzas, so if we add 1/9+1/9, we'll get two ninths.

Now 2/9=0.2 repeating!

This is how I got my answer sorry for the vague  explanation

Answer:

1) True

2) false

3) false

4) faIse

Did I give right answer or not please tell me ok

Answer:

\(\large\boxed{\tt x = 2}\)

Step-by-step explanation:

\(\textsf{We are asked to solve for x in the given equation.}\)

\(\textsf{We should know that x is cubed, meaning that it's multiplied by itself 3 times.}\)

\(\textsf{We should isolate x on the left side of the equation, then find x by cubic rooting}\)

\(\textsf{both sides of the equation.}\)

\(\large\underline{\textsf{How is this possible?}}\)

\(\textsf{To isolate variables, we use Properties of Equality to prove that expressions}\)

\(\textsf{are still equal once a constant has changed both sides of the equation. A Cubic}\)

\(\textsf{Root is exactly like a square root, but it's square rooting the term twice instead}\)

\(\textsf{of once.}\)

\(\large\underline{\textsf{For our problem;}}\)

\(\textsf{We should use the Subtraction Property of Equality to isolate x, then cubic root}\)

\(\textsf{both sides of the equation.}\)

\(\large\underline{\textsf{Solving;}}\)

\(\textsf{Subtract 1 from both sides of the equation keeping in mind the Subtraction}\)

\(\textsf{Property of Equality;}/tex]

\(\tt \not{1} - \not{1} - x^{3} = 9 - 1\)

\(\tt - x^{3} = 8\)

\(\textsf{Because x}^{3} \ \textsf{is negative, we should exponentiate both sides of the equation by}\)

\(\textsf{the reciprocal of 3, which is} \ \tt \frac{1}{3} .\)

\(\tt (- x^{3})^{\frac{1}{3}} = 8^{\frac{1}{3}}\)

\(\underline{\textsf{Evaluate;}}\)

\(\tt (- x^{3})^{\frac{1}{3}} \rightarrow -x^{3 \times \frac{1}{3} } \rightarrow \boxed{\tt -x}\)

\(\textsf{*Note;}\)

\(\boxed{\tt A^{\frac{1}{C}} = \sqrt[\tt C]{\tt A}}\)

\(\tt 8^{\frac{1}{3}} \rightarrow \sqrt[3]{8} \rightarrow 2^{1} \rightarrow \boxed{\tt 2}\)

\(\underline{\textsf{We should have;}}\)

\(\tt -x=2\)

\(\textsf{Use the Division Property of Equality to divide each side of the equation by -1;}\)

\(\large\boxed{\tt x = 2}\)

Given:

A tree is currently 10 feet tall and grows 2 feet per year.

To find:

The arithmetic sequence in explicit formula that can model this scenario.

Solution:

Current height of tree is 10 feet. So, initial value of the arithmetic sequence is a=10.

It grows 2 feet per year. So, common difference is d=2.

The explicit formula for an arithmetic sequence is

\(f(n)=a+(n-1)d\)

where, a is first term and d is common difference.

Put a=10 and d=2 in the above formula.

\(f(n)=10+(n-1)2\)

\(f(n)=10+2n-2\)

\(f(n)=8+2n\)

Therefore, the explicit formula for given scenario is \(f(n)=8+2n\).

(a) The first order lowpass filter isHc(s) = 10/(s+1)The analog bandpass filter has a cutoff frequency of ω1 = 50 rad/sec and ω2 = 100 rad/sec.

The transfer function of the analog filter is given byH(s) = s/(s^2 + 0.1506s + 1)Let s = jω and use the given frequencies, we getH(j50) = j50/(0.1506j50 + 1)

≈ j0.3257H(j100)

= j100/(0.1506j100 + 1)

≈ j0.6522The pole-zero diagram is shown below:b) The bilinear transformation used to convert the analog filter to a digital filter is given byThe bilinear transformation is a nonlinear transformation of s-plane to z-plane.

For Td = 2, we getz = (2+s)/(2-s)Let H(z) be the transfer function of the digital filter. Substituting z from above we getH(z) = H(s)|s=(2z-2)/(z+1)Substituting the transfer function of analog filter, we getH(z) = (1 - z^-1) / (1 + 0.1506z^-1 + 0.9900z^-2)The pole-zero diagram is shown below:c) The frequency response of the filter is given byH(ω) = |H(z)|z=ejωUsing the transfer function obtained in part (b), we getH(ω) = |(1 - e-jω) / (1 + 0.1506e-jω/2 + 0.9900e-jω)|The magnitude plot of the frequency response is shown below:

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Recall that a periodic function is a function that repeats itself at regular intervals, and the period is the distance between the repetitions.

Notice that the given graph repeats itself regularly, then it must be periodic.

From the given diagram we get that the period of the given graph is:

Answer: Option C.

Based on the provided scenario, the statement can be classified as: b. This is a nonsampling error that causes bias.

Nonsampling errors refer to errors that occur in data collection, processing, or analysis that are not related to the sampling method.

The scenario described, where individuals may not provide truthful answers due to fear of their responses being shared with law enforcement officials, introduces a bias in the collected data.

This bias occurs because the reported data does not accurately represent the true prevalence of illicit drug use in the population.

The fear of legal consequences leads to a systematic deviation from the true values, which is a form of bias.

Therefore, option b is the correct classification for this scenario.

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By using addition, it can be calculated that

Trina, Juan and their father can do one boat ride.

What is addition?

Suppose there are many numbers and we need to find the sum total of all those numbers, then the operation used in this case is called addition.

This is a word problem on addition

Cost of adult admission = $7

Cost of child admission = $5

Cost of boat ride for adult  = $3

Cost of boat ride for child = $2

Total expense for adult = $(7 + 3) =$10

Total expense for child = $(5 + 2) =$7

Trina and Juan and their father have $33 to spend at the water park

Trina and Juan qualify for a child's admission

Total expense for one boat ride = $(7 + 7 + 10) = $24

Total expense for two boat rides = $(24 + 24) = $48

But they have $33 to spend

So Trina, Juan and their father can do one boat ride.

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The probability of selecting the card with the number three at least once is 1/10.

Given that,

1 through 10 cards are contained in a box. Two cards are chosen at random and replaced

To find : The probability of selecting the card with the number three at least once?

Probability (3 at first)  * Probability (3 at second) + Probability (3 at first)  *Probability (others at second) + Probability (others at first) *Probability (3 at second) = 1/10 * 1/0 + 1/10 *9/10 + 9/10*1/10

= 19/100 = 0.19

Here there are 10 cards,

So, probability of picking three is 1/10 and probability of picking others is 9/10

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Answer: 1 solution I think

Step-by-step explanation:

The dividend in the formula P3 = Dx/(R - g) is for period e. three.

In the given formula P3 = Dx/(R - g), the dividend, Dx, refers to the cash flow or payment made during a specific period. The subscript "3" in P3 indicates the period of time for which the dividend is associated.

In the given formula, P3 = Dx/(R - g), the subscript 3 represents the period of time for which we are calculating the dividend.

The dividend, Dx, represents the cashflow or payment made during a specific period. In this case, the dividend is associated with period 3.

Therefore, the dividend in the formula corresponds to period e. three.

The dividend in the formula P3 = Dx/(R - g) is for period e. three

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The null hypothesis get rejected comparing the 95% confidence interval to the proportion of the given central valley residents and bay area residents .

As given in the question,

Total number of voters in California = 7525

x₁ = Number of voters of central valley residents approved California legislature

   = 68

n₁ = Total number of voters of central valley residents

   = 200

x₂ = Number of voters of bay area residents approved California legislature

   = 156

n₂= Total number of voters of bay area residents

   = 300

p₁ = proportion of voters of central valley

p₂= proportion of voters of bay area

p₁ = x₁/ n₁

   = 68/200

   = 0.34

p₂ = x₂/n₂

    = 156/300

    = 0.52

Standard error = √p₁(1 -p₁) / n₁ + p₂( 1- p₂)/n₂

                        = √0.34(1-0.34) / 200 + 0.52(1-0.52)/ 300

                        = √0.001122 + 0.000832

                        = 0.044

\(p_{w}\) = (68 + 156 )/ (200 + 300)

   = 0.448

\(q_{w} = 1- p_{w}\)

    = 1 - 0.448

    = 0.552

null hypothesis p₁ - p₂ = 0

z = ( 0.52 - 0.34 ) - 0/ √(0.448)(0.552)( 1/200 + 1/300)

  = 4

Tabular value for confidence interval 95% = 1.96

4 > 1.96

We reject the null hypothesis.

Therefore, the difference of proportion of central valley residents and the bay area residents rejection of null hypothesis as per given 95% confidence interval.

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The length of the garage in the drawing will be 2mm.

The mathematical expression combines numerical variables and operations denoted by addition, subtraction, multiplication, and division signs.

Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also denote the logical syntax's operation order and other properties.

Given that the scale he used was 1 millimetre: 7 meters. The actual length of the garage is 14 meters.

The length of the garage in the drawing will be calculated as,

7 meters = 1 mm

1 meter = 1 / 7 mm

14 meters = 14 / 7 mm

14 meters = 2 mm

Therefore, the length of the garage in the drawing will be 2mm.

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The solutions to the quadratic equation \(x^2 + 2x = 6\) are x = -1 + √(7) and x = -1 - √(7).

To solve the equation\(x^2 + 2x = 6\) using the quadratic formula, we need to rewrite the equation in the standard form\(ax^2 + bx + c = 0\). Comparing the given equation to the standard form, we have a = 1, b = 2, and c = -6.

The quadratic formula states that for an equation in the form\(ax^2 + bx + c = 0\), the solutions for x can be found using the formula:

Plugging in the values for a, b, and c from the given equation, we get:

\(x= \frac{-2 + \sqrt{((2)^2 - 4(1)(-6) ))} }{2(1)}\)

Simplifying further:

\(x= \frac{-2+\sqrt{(4 + 24)}} {2}\)

Now, we can simplify the square root of 28:

\(x = \frac{-2+\sqrt{7} }{2}\)

Next, we can simplify the expression:

x = -1 ± √(7).

Therefore, the solutions to the quadratic equation \(x^2 + 2x = 6\) are x = -1 + √(7) and x = -1 - √(7).

These are the exact solutions to the equation. If you need numerical approximations, you can substitute the value of √(7) as approximately 2.64575, and you'll get x ≈ -1 + 2.64575 ≈ 1.64575 and x ≈ -1 - 2.64575 ≈ -3.64575.

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In the given Markov chain, State 1 is absorbing, State 4 is periodic, State 1 is recurrent, and States 3, 4, and 5 are recurrent.

A Markov chain is a stochastic model that represents a sequence of states where the probability of transitioning from one state to another depends only on the current state. Let's analyze the given Markov chain to determine the properties of each state.

State 1: This state has a probability of 1 in the first row, indicating that it is an absorbing state. An absorbing state is one from which there is no possibility of leaving once it is reached. Therefore, statement a) is correct, and State 1 is absorbing.

State 2: There are no transitions from State 2 to any other state, which means it is an absorbing state as well. However, since it is not explicitly mentioned in the question, we cannot determine its status based on the given information.

State 3: This state has non-zero probabilities to transition to other states, indicating that it is not absorbing. Furthermore, it has a loop back to itself with a probability of 1/6, making it recurrent. Hence, statements c) and e) are incorrect, while statement f) is correct. State 3 is recurrent.

State 4: State 4 has a transition probability of 1/3 to State 3, which means there is a possibility of leaving this state. However, there are no outgoing transitions from State 4, making it an absorbing state. Moreover, since there is a loop back to itself with a probability of 2/3, it is also recurrent. Therefore, statement b) is correct, and State 4 is periodic and recurrent.

State 5: Similar to State 4, State 5 has a transition probability of 2/3 to State 3 and no outgoing transitions. Hence, State 5 is also an absorbing and recurrent state. Consequently, statement e) is correct.

To summarize, State 1 is absorbing and recurrent, State 4 is periodic and recurrent, and States 3 and 5 are recurrent.

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Answer:

\( a_{100} = 387 \)

Step-by-step explanation:

I think the first term is -9.

Then each term is 4 more than the previous term.

The constant difference is 4. d = 4.

\( a_n = a_{n - 1} + 4 \)

\( a_1 = -9 \)

For n ≥ 2,

\( a_n = -9 + (n - 1)d \)

\( a_{100} = -9 + (100 - 1)(4) \)

\( a_{100} = 387 \)

The Genotype frequency is the percentage of the total number of individuals represented by a genotype.

The student population will most likely not match the US population figures. The data for the US population comes from a much larger sample and better represents the rates expected for a large heterogeneous population.

Since your class data represents a much smaller sample size, the allele frequencies will most likely be different. The frequency of the AA genotype is determined by the square of the frequency of the A allele.

The frequency of genotype Aa is obtained by multiplying the frequency of A times the frequency of A twice. The frequency of aa is the square of a. Try replacing p and q with other values, just making sure p and q are still 1.

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Answer:

6

Step-by-step explanation:

Step 1:

10 = 3x - 8      Equation

Step 2:

18 = 3x      Add 8 on both sides

Step 3:

18 ÷ 3     Divide

Answer:

x = 6

Hope This Helps :)

The statements that only apply to C3, C4, and CAM photosynthesis are:

1. C3, C4, and CAM plants all have cells that have chloroplasts which attach CO2 directly to ribulose bisphosphate to produce sugars.

2. CAM plants have one set of cells that harvests CO2 and passes the carbon to another set of cells that builds sugars.

3. Stomata open at night to allow gas exchange and sugars are produced during the day.

The statement that applies to all three types of photosynthesis is: Light energy, CO2, and H20 are needed to make sugars.

C4 and CAM plants have adaptations that prevent the Calvin cycle from shutting down in periods of dryness. These adaptations include C4 plants using a carbon concentrating mechanism that separates the fixation of CO2 from the Calvin cycle and CAM plants using a process called crassulacean acid metabolism (CAM), where CO2 is taken up at night and stored as an acid until the following morning when it is converted into sugars in the Calvin cycle.

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The scalar projection of the vector (4,6) onto (-2,-8) is 1.5. The vector projection of (4,6) onto (-2,-8) is (-3,-12).

To find the scalar projection, we use the formula: scalar projection = |A| * cos(θ), where A is the vector being projected and θ is the angle between A and the projection vector. In this case, |A| = √(4^2 + 6^2) = √(16 + 36) = √52 = 2√13. The angle between the vectors can be found using the dot product: A · B = |A| * |B| * cos(θ). The dot product of (4,6) and (-2,-8) is -20. Thus, cos(θ) = -20 / (2√13 * √(-2^2 + (-8)^2)) = -20 / (2√13 * √68) = -5 / (2√13). Therefore, the scalar projection is 2√13 * (-5 / (2√13)) = -5.

The vector projection can be found using the formula: vector projection = scalar projection * unit vector of the projection vector. The unit vector of (-2,-8) is (-2,-8) / √((-2)^2 + (-8)^2) = (-2,-8) / √(4 + 64) = (-2,-8) / √68 = (-1/√17, -4/√17). Thus, the vector projection is (-5) * (-1/√17, -4/√17) = (5/√17, 20/√17) = (5√17/17, 20√17/17).

For the vector (-1,4,8) projected onto (4,3,1), the scalar projection is 3. The vector projection is (12/26, 9/26, 3/26).

The scalar projection is found using the formula: scalar projection = |A| * cos(θ), where A is the vector being projected and θ is the angle between A and the projection vector. In this case, |A| = √((-1)^2 + 4^2 + 8^2) = √(1 + 16 + 64) = √81 = 9. The dot product of (-1,4,8) and (4,3,1) is 1. Thus, cos(θ) = 1 / (9 * √(4^2 + 3^2 + 1^2)) = 1 / (9 * √(16 + 9 + 1)) = 1 / (9 * √26). Therefore, the scalar projection is 9 * (1 / (9 * √26)) = 1 / √26 = 1/√26 * √26/√26 = √26/26 = 1/√26 = √26/26 ≈ 0.196.

The vector projection can be found using the formula: vector projection = scalar projection * unit vector of the projection vector. The unit vector of (4,3,1) is (4,3,1) / √(4^2 + 3^2 + 1^2) = (4,3,1) / √(16 + 9 + 1) = (4,3,1)

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Hey there! :)

Answer:

f(n) = n²

Step-by-step explanation:

Let n be the term number of this pattern and f(n) the number of shapes: Examine the pattern shown:

When n = 1, f(n) = 1.

When n = 2, f(n) = 4.

When n = 3, f(n) = 9.

The pattern of this sequence is:

f(n) = n².

This means that the # of shapes shown is the square of the term number.

Answer:

z= 4-x-y

z= -1+4x-y

z= 2-x

Step-by-step explanation:

z = 2-x

y = -1-z +4x

substitute

x -1 -2+x +4x + 2 -x = 4

-1 + 5x = 4

5x = 5

x = 1

z = 1

1+y+1 = 4

y = 2

Answer:

c=ab/2y

Step-by-step explanation:

y=ab/2c

to get rid of the denominator we divide by 2c.

(y=ab/2c)2c

2cy=ab

now we need to get rid of the 2y from the c to isolate it. in order to do this, we must divide by 2y.

Doing this we get c=ab/2y

9514 1404 393

Answer:

  c = (ab)/(2y)

Step-by-step explanation:

The given equation can be multiplied by c/y to solve for c.

  \(y=\dfrac{ab}{2c}\\\\y\cdot\dfrac{c}{y}=\dfrac{ab}{2c}\cdot\dfrac{c}{y}\\\\\boxed{c=\dfrac{ab}{2y}}\)

_____

Comment on the form of the answer

When the answer is written in plain text, the fraction bar no longer serves as a grouping symbol. Hence, parentheses are needed around the denominator:

  c = ab/(2y)

Answer:

D $3.24

Step-by-step explanation:

13.5 times 24 is 324 cents, and 324 cents is equal to $3.24

Answer:

see explanation

Step-by-step explanation:

The perimeter is the sum of the sides of the figures

(1)

The figure has 5 congruent sides , then perimeter P

P = 5 (\(\frac{2}{5}\) x + 1) ← multiply each term in the parenthesis by 5

  = 2x + 5

(2)

There are 4 congruent sides of (\(\frac{5}{2}\) x - y) and 8 of y , then

P = 4(\(\frac{5}{2}\) x - y) + 8y ← distribute parenthesis by 4

  = 10x - 4y + 8y ← collect like terms

  = 10x + 4y

(3)

P = 2(\(\frac{2a-b}{2}\) ) + 2(\(\frac{3b}{2}\) ) + 2a ← distribute parenthesis

  = 2a - b + 3b + 2a ← collect like terms

  = 4a + 2b