Someone please help me with this problem, I have tried multiple times but still couldn't get the correct answer. :(

Step-by-step explanation:

Given that

To find

So, according to the question

we have,

For finding the y coordinate, we have find f(8) from equation,

So now put 8 from x, or in other word x = 8,

So, we will get

f(x) =  -5x²-8x+6

f(8) =  -5(8)²-8(8)+6

       = -5× 64- 8×8 +6

       = -320 -64 +6

       = -384 + 6

       = 378

Answer:

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The price elasticity of demand is the change in quantity demanded relative to the change in price.

Let:

\(P \to Price\\Q \to Quantity\)

(a) The total revenue

From the first graph (see attachment), we have:

\((P_1,Q_1) = (50,90)\)

\((P_2,Q_2) = (75,81)\)

\((P_3,Q_3) = (100,72)\)

\((P_4,Q_4) = (125,63)\)

\((P_5,Q_5) = (150,54)\)

\((P_6,Q_6) = (175,45)\)

\((P_7,Q_7) = (200,36)\)

The total revenue (T) is calculated using:

\(T = P \times Q\)

So, we have:

\(T_1 = 50 \times 90 = 4500\)

\(T_2 = 75 \times 81 = 6075\)

\(T_3 = 100 \times 72 = 7200\)

\(T_4 = 125 \times 63 = 7875\)

\(T_5 = 150 \times 54 = 8100\)

\(T_6 = 175 \times 45 = 7875\)

\(T_7 = 200 \times 36 = 7200\)

The second figure in the attached image represents the revenue graph

(b) Price elasticity of demand

Between points A and B, we have:

\((P_1,Q_1) = (50,90)\)

\((P_2,Q_2) = (25,99)\)

The price elasticity of demand is:

\(E_d = \frac{(Q_2 - Q_1)/(Q_1 + Q_2)/2}{(P_2 - P_1)/(P_1 + P_2)/2}\)

So, we have:

\(E_d = \frac{(Q_2 - Q_1)/(Q_1 + Q_2)}{(P_2 - P_1)/(P_1 + P_2)}\)

\(E_d = \frac{(99 - 90)/(90 + 99)}{(25 - 50)/(50 + 25)}\)

\(E_d = \frac{9/189}{-25/75}\)

\(E_d = -0.143\)

The price elasticity of demand between points A and B is 0.143, and the demand must be inelastic because an increase in price of the bike leads to a decrease in the total revenue

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Answer:

1.029 is greater than 1.0275

Step-by-step explanation:

Answer:

1.029

Step-by-step explanation:

What is greater 1.0275 or 1.029

.027 < .029

So, 1.029 is greater.

Answer: The total distance covered by the car is 331 9/16 km.

Step-by-step explanation:

We know that, speed= distance/time taken

Therefore, distance = speed x time taken

= 132 5/8 x 2 1/2

= 5/2 x 1061/8

= 5305/16

= 331 9/16 km

Therefore, total distance is 331 9/16 km.

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Answer:

B) \( 10\pi \: cm\)

Step-by-step explanation:

Option B is the correct answer

\(A= \pi r^2 \)

\(25\pi= \pi r^2 \)

\(25= r^2 \)

\(\sqrt{25} = r \)

\(5\: cm= r \)

\(C = 2\pi r \)

\(C = 2\pi \times 5\)

\(C = 10\pi \: cm\)

The final answer for the surface area of the prism is 32 m^2 + 16h m^2.

To find the surface area of the prism, we need to calculate the area of each face and sum them up.

The prism has two identical square faces and four rectangular faces. The square face has a side length of 4 m. The area of one square face is given by:

Area of square face = side length^2 = 4^2 = 16 m^2

Since there are two square faces, the total area of the square faces is:

Total area of square faces = \(2 * 16 = 32 m^2\)

The rectangular faces have a length equal to the side length of the square face (4 m) and a width equal to the height of the prism. Let's assume the height of the prism is h. The area of one rectangular face is given by:

Area of rectangular face = length * width = \(4 * h = 4h m^2\)

Since there are four rectangular faces, the total area of the rectangular faces is:

Total area of rectangular faces = \(4 * 4h = 16h m^2\)

Therefore, the surface area of the prism is the sum of the areas of the square and rectangular faces:

Surface area of prism = Total area of square faces + Total area of rectangular faces

                          = \(32 m^2 + 16h m^2\)

                          = \(32 m^2 + 16h m^2\)

The answer for the surface area of the prism is 32 m^2 + 16h m^2.

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Step-by-step explanation:

A Scatter Analysis is used when you need to compare two data sets against each other to see if there is a relationship. Scatter plots are a way of visualizing the relationship; by plotting the data points you get a scattering of points on a graph.

Answer:

Step-by-step explanation:

r² means the length of the radius is multiplied by itself.

It is also a clue that area is expressed in square units.

(a) U is a subspace of L(V, W) (b) F is a linear map, and U is the null space of F. (c) The dimension of U is n - 1

The dimension of U is n - 1

(a) To demonstrate that U is a subspace of L(V, W), we must demonstrate that it meets the three subspace properties:

If T1 and T2 are in U, then T1 + T2 is in U as well, since if T1(v) = 0 and T2(v) = 0, then (T1 + T2)(v) = T1(v) + T2(v) = 0 + 0 = 0.

If T is in U and c is a scalar, then cT is in U, since if T(v) = 0, then (cT)(v) = c * T(v) = c * 0 = 0.

Containing the zero vector: Because 0(v) = 0, the zero transformation in L(V, W), indicated by 0, is in U.

As a result, U is a subspace of L. (V, W).

(b) To demonstrate that F is a linear map, we must demonstrate that it meets the following two properties:

Addition linearity: F(T1 + T2) = (T1 + T2)(v) = T1(v) + T2(v) = F(T1) + F(T2) (T2).

Homogeneity is defined as F(cT) = (cT)(v) = c * T(v) = c * F. (T).

As a result, F is a linear map. To demonstrate that U is the null space of F, we must first demonstrate that U is the set of all T in L(V, W) such that F(T) = 0. In other words, T(v) = 0.

(c) A basis for U can be used to calculate the dimension of U. Because U is a subspace of L(V, W), we may construct a basis for U by limiting a basis for L(V, W) to U. A basis for L(V, W) can be produced by designating as T1, T2,..., Tn the set of all transformations that send the standard basis vectors of V to the standard basis vectors of W. These transformations' constraints to U are T1, T2,..., Tn such that T1(v) = T2(v) =... = Tn(v) = 0. Because v = 0, T1, T2,..., Tn constitute a linearly independent set. As a result, dim(U) = n - 1.

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ANSWER

m = 90

EXPLANATION

To find m first we have to multiply both sides by m:

Then multiply both sides by 27:

And finally divide both sides by 18:

In spherical coordinates, the region R is the set

\(R = \left\{ (\rho, \theta, \varphi) \, : \, 0 \le \rho \le 3, \, 0 \le \theta \le 2\pi, \, \dfrac\pi6 \le \varphi \le \pi\right\}\)

Then the volume of R is

\(\displaystyle \iiint_R dV = \int_0^3 \int_0^{2\pi} \int_{\frac\pi6}^\pi \rho^2 \sin(\varphi) \, d\varphi \, d\theta \, d\rho\)

The integrand is free of \(\theta\), so we can immediately compute that integral and pull out a factor of 2π :

\(\displaystyle \iiint_R dV = 2\pi \int_0^3 \int_{\frac\pi6}^\pi \rho^2 \sin(\varphi) \, d\varphi \, d\rho\)

and the remaining double can be factorized as

\(\displaystyle \iiint_R dV = 2\pi \left(\int_0^3 \rho^2 \, d\rho\right) \left(\int_{\frac\pi6}^\pi \sin(\varphi) \, d\varphi\right)\)

The single integrals are trivial:

\(\displaystyle \int_0^3 \rho^2 \, d\rho = \frac13 (3^3 - 0^3) = 3^2 = 9\)

\(\displaystyle \int_{\frac\pi6}^\pi \sin(\varphi) \, d\varphi = -\cos(\pi) - \left(-\cos\left(\frac\pi6\right)\right) = 1 + \frac{\sqrt3}2\)

So, the volume of R is

\(\displaystyle \iiint_R dV = 2\pi \cdot 9 \cdot \left(1 + \frac{\sqrt3}2\right) = \boxed{9(2+\sqrt3)\pi}\)

The simplification of the expression ab³/a⁴b  +  (c²)³ is determined as b²/a³  +  c⁶.

The given expression is simplified as follows;

The given expression is written as;

ab³/a⁴b  +  (c²)³

To simplify the expression given above, we will divide the fraction with the common factor as follows;

From the numerator; ab³, we will factor out "ab"

From denominator; a⁴b, we will factor out "ab"

The resulting expression becomes;

ab³/a⁴b  +  (c²)³

= b²/a³  +  c⁶

Note: for the power of c, we simplify by multiplying 2 and 3 = 6

Thus, the simplification of the expression ab³/a⁴b  +  (c²)³ is determined as b²/a³  +  c⁶.

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Answer:

1. 2400+250v=t

2. 11

3. at the least 15

Step-by-step explanation:

1. 250 is dependent variable

2. 5,150-2400=2750

2750/250=11

3.2400+250x=6000

6000-2400=3600

250x=360

3600/250

x=14.4

you need to sell at least 15

i think it would be 202.3

Answer:

Step-byHow do I calculate the mean?

The mean can be calculated only for numeric variables, no matter if they are discrete or continuous. It's obtained by simply dividing the sum of all values in a data set by the number of value

-step explanation:

46+57+66+63+49+52+61+68= 462/8 the total number of observation

the answer 57

Answer:

Step-by-step explanation:

First, you could factor 2 out of the whole thing.  The result would be 2(x^2-4x-45). Now we find the factors of 45 which are 1, 45, 5, 9, 15, 3. We have to find the pair that adds up to 4, and multiply to get 45. After some guess and check, we can find that 5 and 9 are those numbers. Now we have to get the right signs. Since the result is a negative number for -8k, and -90, the number that is a negative must be less than the other negative. -9<-5, so the answer would be 2(x-9)(x+5)

Answer:

true

Step-by-step explanation:

Answer:

3. 2,071,740

Step-by-step explanation:

To find the product of 34.529 and 0.67, the 7 in the number "0.67" is used in multiplying the whole of "34.529" to get the first set of digit below = 241703.

(Note. When multiplying this way, decimal points are ignored. The decimal point is included at the end of the calculation)

Next is to use the number 6 to multiply 34.529, all through. Which will give us the number that should be in the empty box.

Multiplying 34.529 by 6, we would have: 207,174. 0 would be added after it to make it 2,071,740. This is done in order for the last digit of of the number to call under 6 that we used in multiplying.

241703 is then added to 2,071,740 = 2,313,443

34.529 has 3 decimal places to the right, 0.67 has 2 decimal places to the right, therefore, we would count 5 decimal places to our left and put our decimal point in the figure "2,313,443" = 23.13443

Answer:

B is the correct answer

Answer:  Portfolio 1:

Tech Company Stock: $2,800 * 2.95% = $82.60

Government Bond: $3,200 * 4.56% = $145.92

Total return for Portfolio 1 = $82.60 + $145.92 = $228.52

Portfolio 2:

Junk Bond: $950 * (-3.75%) = -$35.63

Common Stock: $1,500 * 7.18% = $107.70

Total return for Portfolio 2 = -$35.63 + $107.70 = $72.07

From the calculations, we can see that Portfolio 1 earns $228.52 in returns, while Portfolio 2 earns $72.07. Therefore, Portfolio 1 earns $228.52 - $72.07 = $156.45 more than Portfolio 2.

Step-by-step explanation:

Answer:

35x-35y

Step by step explanation: I

0.5(20x-50y+36)-0.25(100x+40y-12)

10x-25y+18+25x-10y+3 -------- after we distribute 0.5&-0.25

10x+25x-25y-10y+18+3. ---------we collect the like terms to add them or substract

35x-35y+21 -----------------------------simplified form

Answer:

35x-35y

Step-by-step explanation:

simply simplify both sides then subtract

A. The distributions of the periods is that using the five number summary is that

B. The box and whisker plot of the periods is attached

From the question, we have the following parameters that can be used in our computation:

7th Period

66, 72, 77, 78, 78, 80, 82, 84, 84, 87, 88, 88, 89, 89, 90 92, 92, 93, 94, 94 96, 96

3rd Period

52, 60, 62, 64, 64, 65, 68, 71, 72, 74, 75, 76, 78, 79, 83, 84, 85, 88, 89, 93, 94, 97

The distributions of the periods will be compared using the five-number summaries

Using a graphing tool, the five-number summaries are:

7th Period

3rd Period

The box and whisker plot of the periods is added as an attachment

From the box and whisker plot attached, we can see the five-number summaries of the periods

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240° is the coterminal angle of 23×π÷3.

First, we can simplify 23 times π over 3 by noticing that 2π is equivalent to 6 pi over 3, so we can add 2π to 23 times pi over 3 until we get an angle between 0 and 2π (or 0 and 360 degrees).

23 times π over 3 is equivalent to an angle of 360 degrees times (23 times π over 3)/(2π), which simplifies to 360 degrees times 23/2, or 4140 degrees.

To find a coterminal angle between 0 and 360 degrees, we can subtract 360 degrees until we get an angle in that range.

4140 - 360(11) = 240

Therefore, a coterminal angle of 23 times pi over 3 between 0 and 360 degrees is 240 degrees.

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\(w^2 - 6w + 4\) is a polynomial that represents how much more profit is earned by selling w apple trees than w pear trees.

The profit earned by selling w pear trees is 2w + 10

To find the difference in profit, we need to subtract the profit earned by selling w pear trees from the profit earned by selling w apple trees:

\((w^2 - 4w + 14) - (2w + 10)\)

Simplifying the expression:

\(w^2 - 6w + 4\)

Therefore, the polynomial that represents how much more profit is earned by selling w apple trees than w pear trees is \(w^2 - 6w + 4\).

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Answer:  6 * 24 = 144 ways.

Step-by-step explanation:

Solution:

Given word => DANGER.

The condition is that vowels can't occupy odd places so, we will let them occupy even places.

A total number of arrangements will be = 6 * 24 = 144 ways.

Answer: 6x24 = 144 ways.

Answer:

The 99% confidence interval is (-20.774, 2.774)

Step-by-step explanation:

The 60 seconds and 120 seconds breaking strength measures are;

60 seconds:  43, 52, 52, 58, 49, 52, 41, 52, 56, 51

120 seconds: 59, 55, 59, 66, 62, 55, 57, 66, 66, 51

The Mean and standard deviation for the data are obtained as follows;

The mean strength for the 60 seconds treatment samples, μX = 50.6 N

The standard deviation for the 60 seconds treatment samples, sX = 5.211099 N

The number of threads in the sample, n₁ = 10

The mean strength for the 60 seconds treatment samples, μY = 59.6 N

The standard deviation for the 60 seconds treatment samples, sY = 5.295701 N

The number of threads in the sample, n₂ = 10

The 99% confidence interval for the difference in mean, is given as follows;

\(\left (\mu X- \mu Y \right )\pm t_{\left(\dfrac{\alpha}{2}, df \right) } \cdot \sqrt{\dfrac{sX^{2}}{n_{1}}+\dfrac{sY^{2}}{n_{2}}}\)

The degrees of freedom, df = n₁ + n₂ - 2 = 20 - 2 = 18

(1 - α)·100 = 99%

α = 1 - 99/100 = 0.01

α/2 = 0.01/2 = 0.005

The critical-t at 0.005 significant level and df = 18 is 2.878

The confidence interval is therefore;

\(C.I. = \left (50.6- 59.6 \right )\pm 2.878 \right) } \times \sqrt{\dfrac{5.211099^{2}}{10}+\dfrac{5.295701^{2}}{10}}\)

C.I. = -9 ± 11.774425

∴ By rounding to three decimal places, the 99% confidence interval is (-20.774, 2.774).

Answer:

Therefore, the constant of proportionality for the given proportional relationship is 5.

Step-by-step explanation:

To determine the constant of proportionality in the given proportional relationship, we can use the formula:

Constant of Proportionality = Tickets / Games

Let's plug in the values from the table:

For the first set of values (4 games and 20 tickets):

Constant of Proportionality = 20 / 4 = 5

For the second set of values (7 games and 35 tickets):

Constant of Proportionality = 35 / 7 = 5

For the third set of values (10 games and 50 tickets):

Constant of Proportionality = 50 / 10 = 5

In all three cases, the constant of proportionality is equal to 5.

Therefore, the constant of proportionality for the given proportional relationship is 5.

Choose the equation that represents a line that passes through points (-6, 4) and (2, 0).

O x + 2y = 2

O 2x - y = -16

O x + 2y = -8

2x + y = 4

step 1

Find the slope

m=(0-4)/(2+6)

m=-4/8

m=-1/2

step 2

Find the equation of teh line in slope intercept form

y=mx+b

we have

m=-1/2

point (2,0)

substitute

0=-(1/2)(2)+b

0=-1+b

b=1

so

y=-(1/2)x+1

step 3

Convert to standard notation

Ax+By=C

Multiply by 2 both sides

2y=-x+2

The mass of the individual can be up to 87.27 kg for the hot-weather training strategy to be appropriate.

Given that the training strategy is appropriate for a BSA less than 2.0, we need to find the maximum mass (M) for the individual with a height (H) of 165 cm. The equation for BSA is:

BSA = √(H x M) / 3600

We can rearrange the equation to solve for M:

M = (BSA^2 x 3600) / H

Since we want the maximum mass for a BSA less than 2.0, we can use BSA = 2.0 as the upper limit:

M = (2.0^2 x 3600) / 165

M = (4 x 3600) / 165

M = 87.27 kg

The above question is in response to the full question as seen in the image;

A sports medicine specialist determines that a hot-weather training strategy is appropriate for a 165 cm tall individual whose BSA is less

than 2.0. To the nearest hundredth, what can the mass of the individual be for the training strategy to be appropriate?

The equation for BSA is BSA = √(H x M)/3600

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Option 1 is not true

Option 2 is true

Option 3 is true

Option 4 is false (a coefficient would just be the variable and only the variable.)

Option 5 is true

Option 6 is false.

Hope this helps and have a nice day.

-R3TR0 Z3R0

Answer:

The answer is B!!

Step-by-step explanation:

I hope I helped! Pls give me brainliest if I did