someone please help me out ill mark you as brainlest

The 5 moles of water is equal to 90.075 grams of water and 220 J of energy is equal to 52.636 calories.

To change moles of water to grams, it is required to find the molar mass of the substance. The molar mass of water (H2O) is equal to 18.015 grams/mol.

To change 5 moles of water to grams, by using the following calculation:

5 moles × 18.015 grams/mol = 90.075 grams of water

Thus, 5 moles of water is equal to 90.075 grams of water.

To change joules to calories,  by using the conversion factor:

1 cal = 4.184 J.

To change 220 J of energy to calories, by using the following calculation:

220 J ×  (1 cal / 4.184 J) = 52.636 cal

Thus, 220 J of energy is equal to 52.636 calories.

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Answer:

hello

Explanation

sup

The molar mass in grams of "one mole" of each substance is:

Fe: 55.845 g/mol

\(Cl_2\): 70.906 g/mol

\(FeCl_3\): 162.204 g/mol

To calculate the molar mass in grams of "one mole" of each substance, we need to determine the atomic masses of the elements involved in the equation.

The atomic mass of iron (Fe) is 55.845 g/mol.

For chlorine (\(Cl_2\)), we need to consider that the molar mass of \(Cl_2\) is twice the atomic mass of chlorine because the formula shows that two chlorine atoms combine to form one molecule of \(Cl_2\). The atomic mass of chlorine is 35.453 g/mol, so the molar mass of \(Cl_2\) is 2 * 35.453 g/mol = 70.906 g/mol.

The formula for iron(III) chloride (\(FeCl_3\)) indicates that one mole of \(FeCl_3\)contains one mole of iron and three moles of chlorine. Therefore, we can calculate the molar mass of \(FeCl_3\)by summing the atomic masses of iron and chlorine:

Molar mass of \(FeCl_3\)= (1 * atomic mass of Fe) + (3 * atomic mass of Cl)

Substituting the values, we have:

Molar mass of \(FeCl_3\) = (1 * 55.845 g/mol) + (3 * 35.453 g/mol)

= 55.845 g/mol + 106.359 g/mol

= 162.204 g/mol

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Sickle cell anemia is a genetic blood disorder that affects shape and function of red blood cells.

Sickle cell anemia is a genetic blood disorder that affects the shape and function of red blood cells. Hemostasis refers to process of maintaining balance between clotting and bleeding and sickle cell anemia can disrupt this balance in several ways.

One of the main effects of sickle cell anemia on hemostasis is that it can cause Vaso-occlusion, which is blockage of small blood vessels by sickle cells. This can cause tissue damage, inflammation and pain, which in turn can trigger an overactive clotting response.

Sickle cell anemia is caused by mutations in HBB gene, which provides instructions for making protein called hemoglobin.

Sickle cell anemia is most commonly found in people of African descent, although it can also occur in people of Hispanic, Middle Eastern, and Mediterranean ancestry.

Diagnosis of sickle cell anemia involves blood test to look for the presence of sickle hemoglobin.

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Answer: Chemical change

Explanation: Chemical change because when you add baking soda, a chemical reaction is happening. I hope this helps :)

Answer:

A lot

Explanation:

BillBill's recipe for onion soup calls for 4.0 lb of thinly sliced onions . if an onion has an average mass of 115 g , how many onions does Bill need ?

The final volume of the ladybug's prison is approximately 0.4 liters.

To determine the final volume of the ladybug's prison, we can use Boyle's Law, which states that the pressure and volume of a gas are inversely proportional at constant temperature. The equation for Boyle's Law is:

P1 * V1 = P2 * V2

Where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume, respectively.

In this scenario, the initial volume (V1) is given as 0.5 L, and the initial pressure (P1) is 1 atm. The final pressure (P2) is 1.25 atm. We need to find the final volume (V2).

Plugging the given values into the equation, we have:

1 atm * 0.5 L = 1.25 atm * V2

Simplifying the equation, we find:

0.5 L = 1.25 atm * V2

Dividing both sides of the equation by 1.25 atm, we get:

0.5 L / 1.25 atm = V2

V2 ≈ 0.4 L

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4.933 mL of sulfuric acid needs to be added to have an acetanilide concentration of 1.5 M for the given molarity .

The molarity of a solution is defined as the total number of moles of solute present per litre. It is also referred to as "molar concentration" and is spelled "molar." It is denoted by the symbol "M," and its unit of measurement is mol/L. A solution is said to have one molarity if one mole of solute dissolves in one litre of solution. The molarity of a solution is determined by its volume but not by the volume of the solvent. Unlike mass, the molarity of a given solution relies on the physical properties of the system, such as pressure and temperature, because the volume of the solution changes as the physical conditions of the system change.

Use formula M₁ × V₁ = M₂ × V₂

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The mass of Aluminum Sulfate is 5.373 grams if you have \(2.837*10^{26\) atoms of Sulfur .

The molecular formula of Aluminum Sulfate is \(Al_2(SO_4)_3.\) In one molecule of aluminum sulfate, there are 3 sulfur atoms. To calculate the mass of aluminum sulfate, follow the steps below:

Step 1: Calculate the molar mass of aluminum sulfate using the periodic table.Al = 27.0 g/molS = 32.1 g/molO = 16.0 g/mol

(2 × Al) + (3 × S) + (12 × O) = molar mass of \(Al_2(SO_4)_3.\) = 342.2 g/mol

Step 2: Find the number of moles of sulfur in the given number of atoms of sulfur.2\(2.837*10^{26\) atoms of sulfur × 1 mol S/\(6.022 * 10^{23\)atoms S = 0.0470 mol S

Step 3: Use the molar ratio of sulfur to aluminum sulfate to calculate the number of moles of aluminum sulfate.1 mol \(Al_2(SO_4)_3.\) / 3 mol S = 0.333 mol\(Al_2(SO_4)_3.\) per mol S0.0470 mol S × 0.333 mol \(Al_2(SO_4)_3.\)/mol S = 0.0157 mol \(Al_2(SO_4)_3.\)

Step 4: Calculate the mass of aluminum sulfate.0.0157 mol \(Al_2(SO_4)_3.\) × 342.2 g/mol\(Al_2(SO_4)_3.\)= 5.373 g\(Al_2(SO_4)_3.\)

Therefore, the mass of Aluminum Sulfate is 5.373 grams if you have \(2.837*10^{26\) atoms of Sulfur.

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The state of matter that tends to have unique factors to consider when discussing solubility compared to the other two states (solid and gas) is the liquid state.

Solubility refers to the ability of a substance (solute) to dissolve in a particular solvent to form a homogeneous mixture (solution). Various factors can affect the solubility of a substance, including temperature, pressure, and the nature of the solute and solvent.

In the case of liquids, the unique factor to consider when discussing solubility is often temperature. The solubility of many solid solutes in liquids generally increases with increasing temperature. This is because higher temperatures provide more energy to break the intermolecular forces between solute particles, allowing them to disperse more evenly throughout the solvent.

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Potassium citrate (also known as tripotassium citrate) is a potassium salt of citric acid with the molecular formula K3C6H5O7.

Answer:

"\(N^+(g) \rightarrow N^{2+}(g) + e^-\)" is the appropriate answer.

Explanation:

Thus the above is the correct answer.

Helium gains no stability by adding one H because it is already stable due to a complete valance shell or orbit.

To attain stability an atom will gain, lose, or share electrons to complete the outermost shell means the last shell. Helium atom has two electrons in the first orbit which completes the doublet rule so it is stable we know that noble gases are stable elements and we know that helium is also a member of a noble family. Nuclides are the most stable because it contains even numbers of both protons and neutrons which make them less radioactive. Nuclear stability is greater in nuclides that comprise even numbers of protons and neutrons or both.

So we can conclude that the helium atom does not need hydrogen to get stability.

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Explanation:

Bohr built on Nicholson's idea by adopting the requirement that the angular momentum can have only certain discrete values related to Planck's constant. However Bohr's atom has many orbits for the electrons.

The amount of heat energy produced when 1 g of hydrogen and 2 g of nitrogen are reacted, is -6.61 KJ

First, we shall obtain the limiting reactant. Details below:

3H₂ + N₂ -> 2NH₃

From the balanced equation above,

28 g of N₂ reacted with 6 g of H₂

Therefore,

2 g of N₂ will react with = (2 × 6) / 28 = 0.43 g of H₂

We can see that only 0.43 g of H₂ is needed in the reaction.

Thus, the limiting reactant is N₂

Finally, we the amount of heat energy produced. Details below:

3H₂ + N₂ -> 2NH₃ ΔH = -92.6 KJ

From the balanced equation above,

When 28 grams of N₂ reacted, -92.6 KJ of heat energy were produced.

Therefore,

When 2 grams of N₂ will react to produce = (2 × -92.6) / 28 = -6.61 KJ

Thus the heat energy produced from the reaction is -6.61 KJ

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Answer:

A)

Explanation:

It estimates the probability of extinction.

Answer:

Any molecule which has a hydrogen atom attached directly to an oxygen or a nitrogen is capable of hydrogen bonding. Hydrogen bonds also occur when hydrogen is bonded to fluorine, but the HF group does not appear in other molecules.

So, the HF no. c) is a right answer.

Answer:

Explanation:

Here are the labels for each situation:

1.Usually conducts electricity & heat well - Metal (1)

2.At room temperature these are gases or liquids - Nonmetal (2)

3.Will lose valance electrons to form compounds - Metal (1)

4.Can be used as semiconductors - Metalloid (3)

5.Will gain valance electrons to form compounds - Nonmetal (2)

Answer:

its sodium hydroxide

Explanation:

Answer: The answer is incus

Answer:

group 1 elements(hydrogen,sodium,etc)

Explanation:

bexause if noticed all the element in the same group have the same eletron in thr outer most shell for example the group 1 elements are said to have 1 outermost elect ron which make them react so the same

Mercury(II) oxide, a red solid, decomposes when heated to produce mercury and oxygen gas. Mercury(II) oxide is a red solid. When it is heated, it decomposes into mercury metal and oxygen gas. A reaction is also considered to be a decomposition reaction even when one or more of the products are still compounds.

The energy of interaction for the linear arrangement of ions shown in the diagram below is 4.44 * 10⁻⁵⁸ J.

The total energy of interaction is the sum of the interaction energies for the individual pairs of ions.

The energy of interaction of the individual pairs is given below as follows:

V = 2.31 * 10⁻¹⁹ * Q₁ * Q₂ / r

where;

Q₁ = 1.602 * 10⁻¹⁹ coulombs.

Q₂ = 1.602 * 10⁻¹⁹ coulombs

r is the distance in nm

The total energy of interaction of the charges shown in the given arrangement will be 3V.

V = 2.31 * 10⁻¹⁹ * 1.602 * 10⁻¹⁹ * 1.602 * 10⁻¹⁹ / 0.4

V = 1.48 * 10⁻⁵⁸ J

3V = 4.44 * 10⁻⁵⁸ J

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Answer:

It released hydroxide ions (OH ¯).

Explanation:

A PH of 8.3 indicates that the solution has become a basic solution.

Now, for us to have a basic solution from the addition of an alka-seltzer to Koolaid, it means the Alka-seltzer released plenty of hydroxide ons (OH¯) to the solution.

Answer:

2c2gh2+5cg2o4+2h2lo

Explanation:

To graph the function g(x) = f(-x), you can start with the graph of f(x) and then reflect it about the y-axis.

To find the graph of the function g(x) = f(-x), we can start with the graph of the function f(x) and then reflect it about the y-axis.

If the graph of f(x) is symmetric with respect to the y-axis, meaning it is unchanged when reflected, then g(x) = f(-x) will have the same graph as f(x).

However, if the graph of f(x) is not symmetric with respect to the y-axis, then g(x) = f(-x) will be a reflection of f(x) about the y-axis.

In either case, the resulting graph of g(x) = f(-x) will be symmetric with respect to the y-axis.

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Answer:

I think its J

Explanation:

sorry if im wrong

Answer:

How do amoeba respire.

Define Diffusion.

The percent yield of the reaction when 3.85g of Ammonia reacts with 5.78g of O2 to give out 0.750L of nitrogen is 27.43%

It is given that the mass of Ammonia is 3.85g and the mass of Oxygen is 5.78g. The yield of Nitrogen is 0.750L. To find the percent yield, we need to know the number of moles of ammonia and Oxygen.

No of moles of Oxygen =  5.78/31.99

No moles of Oxygen= 0.181 mol of O2.

No. of moles of Ammonia = 3.85/17.03

                                             = 0.226 mol of NH₃

It can be seen that 0.226 mol of NH₃ reacts with 3/4th of 0.226 mol of O₂ which is 0.1695 mol of O₂.

But the given moles of O₂ are more than that of the required value. Therefore, NH₃ is the limiting reactant and O₂ is the excess.

Therefore,

0.226 mol of NH3 x 2 mol of N₂/ 4 mol of NH3

= 0.113 mol of N₂

Experimentally it would be calculated as

n = PV/RT

n =  (1 x 0.750)/(0.0821x295)

n = 0.031 mol of N₂

Percent yield = Experimental yield/theoretical yield x 100

Percent yield= (0.031/0.113)x100

Percent yield= 27.43%

Therefore, the percent yield of N₂ is 27.43%

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Explanation:

The trick here is to realize the every sample of sodium bromide, regardless of its mass, will contain

22.34

%

sodium by mass.

This is true because sodium and bromide always combine in definite proportions, i.e. stable ratios by mass, to form sodium bromide.

Now, a

22.34

%

percent concentration by mass means that every

100 g

of sodium bromide will contain

22.34 g

of sodium and

100 g

−

22.34 g

=

77.66 g Br

Therefore, you can say that the mass ratio that exists between sodium and bromine in any sample of sodium bromide will be

22.34 g Na

77.66 g Br

=

22.34

77.66

You can thus use this definite proportion to say that a

5.69 g

sample of sodium bromide will contain

5.69

g NaBr

⋅

22.34 g Na

100

g NaBr

=

1.271 g Na

=

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

∣

∣

a

a

1.27 g Na

a

a

∣

∣

−−−−−−−−−−−−−

The answer is rounded to three sig figs.

You can use the known definite proportion to find the mass of bromide present in the sample

1.271

g NaBr

⋅

77.66 g Br

22.34

g NaBr

=

4.42 g Br

This checks out because

mass of NaBr sample



5.69 g

−

mass of Na



1.27 g

=

mass of Br



4.42 g

The answers to your questions are ;

a) The mass percentage of Na in the sample will be higher in the sample

b) The mass percentage of Na in the sample will be be lower in the sample

Given that:

Mass percentage of sodium contained in sodium Bromide = 22.34%

a) Determine if the mass percentage of Na will be higher or lower when sodium Bromide is contaminated with sodium chloride  

mass percentage of Na in sodium bromide

= ( mass of Na / mass of NaBr )*100

The mass of sodium in NaBr and NaCl is the same while the mass of Br is not same ( greater than ) as the mass of Cl.  hence when NaBr is contaminated with NaCl the total mass of  in percentage NaBr will decrease. and This decrease in mass of NaBr will lead to a decrease/lower mass percentage of Na in the sample

b) When NaBr is contaminated with NaI

The mass of Na is the same in NaBr and NaI while the mass of I is not the same ( greater than ) as the mass of Br, therefore the total mass will increase and the increase in the Total mass in percentage will lead to an increase/higher value of Na in the given sample.

hence the mass percentage of Na will decrease when NaBr is contaminated with NaCl while the mass percentage of Na will increase when NaBr is contaminated with NaI

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