Solve the following if x = 2;
5x – 2x =

The surface area of the composite solid is approximately 127.65 square yards

From the question, we are to calculate the surface area of the composite solid

From the diagram, we have two cones. A big cone and a small cone

Thus,

Surface area of the composite solid = Curved surface area of big cone + Curved surface area of small cone

Curved surface area of big cone = πr(√(h² + r²))

Curved surface area of big cone = π(3)(√(8² + 3²))

Curved surface area of big cone = 3π(√(64 + 9))

Curved surface area of big cone = 3π√(73)

Curved surface area of small cone = πr(√(h² + r²))

Curved surface area of small cone = π(3)(√(4² + 3²))

Curved surface area of small cone = 3π(√(16 + 9))

Curved surface area of small cone = 3π√(25)

Curved surface area of small cone = 3π  × 5

Curved surface area of small cone = 15π

Thus,

Surface area of the composite solid = 3π√(73) + 15π

Surface area of the composite solid = 80.5253 + 47.1239

Surface area of the composite solid = 127.6492

Surface area of the composite solid ≈ 127.65 square yards

Hence,

The surface area is 127.65 square yards

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Answer:

y=-2   x=7

Step-by-step explanation:

Differentiating each function, we have for all x, unless otherwise indicated,

\(h(x) = 2^x - 1 \implies h'(x) = \ln(2) \, 2^x > 0\)

\(g(x) = -4 (2^x) \implies g'(x) = -4 \ln(2) \, 2^x < 0\)

\(f(x) = -3x+7 \implies f'(x) = -3 < 0\)

\(j(x) = x^2 + 8x + 1 \implies j'(x) = 2x + 8 > 0 \text{ only when } x > -4\)

and only h(x) has a strictly positive derivative. (A)

A vertical asymptote exists of the form x = k where y→∞ or y→ -∞.

A slant asymptote exists of the form y = mx + b where m ≠ 0.

Vertical lines go up and down and are in the form of x = a, where a stands for the common x-coordinate of all locations, whereas horizontal lines go left to right and take the shape of y = b, where b stands for the y-intercept.

A vertical line that directs the function's graph but is not actually a part of it is called a vertical asymptote. Because it appears at an x-value outside of the function's domain, the graph can never cross it. There may be multiple vertical asymptotes for a given function. All common factors are cancelled in the denominator, D(x).

A horizontal asymptote exists of the form y = k where x→∞ or x→ -∞ if the value of the one/both of the limits lim ₓ→∞ f(x) and lim ₓ→ -∞ f(x).

A vertical asymptote exists of the form x = k where y→∞ or y→ -∞.

A slant asymptote exists of the form y = mx + b where m ≠ 0.

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Answer:

Did you just start today? It looks like you're new here. I'm also new here.

Step-by-step explanation:

I don't really know what to do either.

From what I've done so far, I don't understand it.

Sorry.

Answer:

The answer is B: 21

Answer:

$24

Step-by-step explanation:

brainliest plzzz

Answer:

Chris has 30$

Maria has 42$

Step-by-step explanation:

This is a very simple question, let me show you how it is done

First of all, if Maria has 12 more dollars than Chris, therefore we have to find out how much Chris has first. In total, they have 72 and Maria has 12 dollars more than Chris so one way to solve this problem is to subtract 12 leaving us with 60, then we can divide it by 2 leaving us with 30, hence 30$ is the amount of money Chris has. But we're not done yet because we still have to find out how much Maria has, and in order to do that we simply have to add 12 to 30 and this leaves us with 42, Thus Maria has 42$ and Chris has 30$

Hope this Helps!

Answer:

n=2

Step-by-step explanation:

Below is the answer

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Answer:

56fifjjfiggitrireieisixii3eiirr

Answer:

Length = 33 cm

width = 11 cm

Step-by-step explanation:

a = 3w           ⇒ eq. 1

88 = 2(a+w)   ⇒ eq. 2

a = length

w = width

then:

replacing the value of the eq. 1 on the eq. 2

88 = 2(3w + w)

88/2 = 4w

44 = 4w

w = 44/4

w = 11 cm

from the eq. 1

a = 3w

a = 3*11

a = 33cm

Check:

perimeter = 88 = 2(a+w)

88 = 2(33+11)

88 = 2*44

Similarity and Difference between Data Mining and Machine Learning

Data mining and machine learning are both disciplines within the field of data science that aim to extract insights and patterns from data. While they share some similarities, they also have distinct characteristics. Let's explore their similarities and differences:

Similarities:

Data-driven Approach: Both data mining and machine learning rely on the analysis of data to generate useful information and make predictions or decisions.

Utilization of Algorithms: Both disciplines employ algorithms to process and analyze data. These algorithms can be statistical, mathematical, or computational in nature.

Pattern Discovery: Both data mining and machine learning seek to discover patterns and relationships in data. They aim to uncover hidden insights or knowledge that can be useful for decision-making.

Differences:

Focus and Purpose: Data mining primarily focuses on exploring large datasets to discover patterns and relationships. It aims to identify useful information that was previously unknown or hidden. On the other hand, machine learning focuses on creating models that can automatically learn from data and make predictions or decisions without being explicitly programmed.

Techniques and Methods: Data mining employs a wide range of techniques, including statistical analysis, clustering, association rule mining, and anomaly detection. Machine learning, on the other hand, focuses on developing algorithms that can learn patterns and relationships from data and make predictions or decisions based on that learning.

Task Orientation: Data mining is often used for exploratory purposes, where the goal is to gain insights and knowledge from data. Machine learning, on the other hand, is typically used for predictive or prescriptive tasks, where the goal is to build models that can make accurate predictions or optimal decisions.

Similarity and Difference between Machine Learning and Statistics

Machine learning and statistics are two closely related fields that deal with data analysis and modeling. They share some similarities but also have distinct approaches and goals. Let's discuss their similarities and differences:

Similarities:

Data Analysis: Both machine learning and statistics involve analyzing data to extract insights, identify patterns, and make predictions or decisions.

Utilization of Mathematical Techniques: Both fields utilize mathematical techniques and models to analyze data. These techniques can include probability theory, regression analysis, hypothesis testing, and more.

Inference: Both machine learning and statistics aim to make inferences from data. They seek to draw conclusions or make predictions based on observed data.

Differences:

Focus and Goal: Machine learning focuses on developing algorithms and models that can automatically learn patterns from data and make predictions or decisions. Its primary goal is to optimize performance and accuracy in predictive tasks. Statistics, on the other hand, is concerned with understanding and modeling the underlying statistical properties of data. It aims to make inferences about populations based on sample data and quantify uncertainties.

Data Assumptions: Machine learning typically assumes that the data is generated from an underlying distribution, but it may not explicitly model the distribution. Statistics, on the other hand, often makes assumptions about the distribution of data and employs statistical tests and models that are based on these assumptions.

Interpretability vs. Prediction: Statistics often focuses on interpreting the relationships between variables and understanding the significance of these relationships. It aims to provide explanations and insights into the data. In contrast, machine learning is more focused on predictive accuracy and optimization, often sacrificing interpretability for improved performance.

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Answer:

15-6+10= 19

Step-by-step explanation:

Answer:

19° F

Step-by-step explanation:

This is the answer because:

1) If the temperature fell by 6° F, you would do 15° F -  6° F which equals 9° F

2) And then it rose by 10° F, you would basically add 9° F with 10° F which equals 19° F

3) Finally, the equation is (15° F -  6° F ) + 10° F which equals to 19° F

Hope this helps!

To determine the probability that the power supply will be inadequate on any given day, we need to find the probability that the daily consumption of electric power exceeds 12 million kilowatt-hours. We have a gamma distribution with α = 3 and β = 2.

Step 1: Identify the parameters of the gamma distribution.
α = 3 (shape parameter)
β = 2 (scale parameter)

Step 2: Set up the problem.
We want to find the probability P(X > 12), where X is the random variable representing daily power consumption in millions of kilowatt-hours.

Step 3: Calculate the cumulative distribution function (CDF) for the given parameters at X = 12.
We can use a gamma CDF calculator or software to find the CDF. For example, using the R programming language, you can use the "pgamma" function:

pgamma(12, shape = 3, scale = 2)

Step 4: Calculate the probability of power supply being inadequate.
Since we want the probability of X > 12, we can subtract the CDF from 1 to obtain the probability:

P(X > 12) = 1 - CDF(12)

After calculating the CDF with the given parameters, you'll obtain the probability that the power supply will be inadequate on any given day.

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(a) The statement is "For functions f, if f"(x) < 0 on the interval (a, b), then f'(x) > 0 on the interval (a, b)." : some

(b) The statement is "For functions f, if f(x) is a polynomial, then it is differentiable for all x." : all

(c)The statement is "For functions f, the tangent line to f(x) at x = a will intersect the graph of f(x) at exactly one point." : no

(a) The statement is "For functions f, if f"(x) < 0 on the interval (a, b), then f'(x) > 0 on the interval (a, b)."

Answer: Some.

The statement is not true for all functions. Here are two specific examples:

Example where the statement is true: Let f(x) = -x^2. The second derivative is f"(x) = -2. On the interval (-∞, ∞), f"(x) < 0, which satisfies the "if" part of the statement. However, the first derivative is f'(x) = -2x, which is negative for x > 0 and positive for x < 0, contradicting the "then" part of the statement.

Example where the statement is false: Let f(x) = x^3. The second derivative is f"(x) = 6x. On the interval (-∞, ∞), f"(x) < 0 is never satisfied. Therefore, we don't have any interval where the "if" part of the statement is true, making the "then" part irrelevant.

(b) The statement is "For functions f, if f(x) is a polynomial, then it is differentiable for all x."

Answer: All.

The statement is true for all polynomials. A polynomial function is differentiable for all x because it is formed by a finite number of terms involving powers of x, constant coefficients, and addition or multiplication operations. The derivative of a polynomial can be obtained using the power rule, which is applicable to all terms of the polynomial. Therefore, the statement holds true for all polynomial functions.

(c) The statement is "For functions f, the tangent line to f(x) at x = a will intersect the graph of f(x) at exactly one point."

Answer: No.

The statement is not true for all functions. Here are two specific examples:

Example where the statement is true: Let f(x) = x^2. The tangent line to f(x) at x = 0 is the line y = 0. It intersects the graph of f(x) at exactly one point (0, 0).

Example where the statement is false: Let f(x) = |x|. The tangent line to f(x) at x = 0 is the line y = 0. However, the graph of f(x) does not intersect the tangent line at exactly one point. The graph of f(x) has a "V" shape at x = 0 and intersects the tangent line at infinitely many points.

In conclusion:

(a) The statement is "For functions f, if f"(x) < 0 on the interval (a, b), then f'(x) > 0 on the interval (a, b)." : some

(b) The statement is "For functions f, if f(x) is a polynomial, then it is differentiable for all x." : all

(c)The statement is "For functions f, the tangent line to f(x) at x = a will intersect the graph of f(x) at exactly one point." : no

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With the same point estimate, Matthew's estimate will have a smaller margin of error due to the larger sample size and wider confidence interval.

The margin of error is influenced by the sample size and the chosen confidence level. Generally, a larger sample size leads to a smaller margin of error, and a higher confidence level leads to a larger margin of error.

Matthew's sample size is four times larger than Katrina's sample size (400 vs. 100). Assuming they obtained the same point estimate, Matthew's estimate will have a smaller margin of error compared to Katrina's estimate. This is because a larger sample size allows for more precise estimation and reduces the variability in the estimate.

Additionally, Katrina constructed a 95% confidence interval, while Matthew constructed a 99% confidence interval. A higher confidence level requires a wider interval to capture the true population parameter with a higher degree of certainty. Therefore, Matthew's estimate will have a smaller margin of error compared to Katrina's estimate.

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Answer:

$74.55

Step-by-step explanation:

420 divided by 20 =21

21 times 3.55= 74.55

Hope this helps!

Answer:

x = 12√2

y = 12√2

Step-by-step explanation:

By applying cosine rule in the given triangle,

cos(45)° = \(\frac{\text{Adjacent side}}{\text{Hypotenuse}}\)

\(\frac{1}{\sqrt{2}}=\frac{y}{24}\)

y = \(\frac{24}{\sqrt{2}}\)

y = \(12\sqrt{2}\)

By applying sine rule in the given triangle,

sin(45°) = \(\frac{\text{Opposite side}}{\text{Hypotenuse}}\)

\(\frac{1}{\sqrt{2}}=\frac{x}{24}\)

x = \(\frac{24}{\sqrt{2}}\)

x = \(12\sqrt{2}\)

Answer:

1.06m

0.2 × 5.3 = 1.06

Answer:Find the vol of the sphere:

radius of the sphere = 3 in

V = %284%2F3%29%2Api%2A3%5E3

V = 97.858

:

Find the vol between the sphere and cube:

216 - 97.858 = 118.142 cu/in

Step-by-step explanation:

Answer:

tooth A

Step-by-step explanation:

0.23 = 0.230

0.230 > 0.195

Answer:

a

Step-by-step explanation:

The ordered pairs for the system of equations f(x) = x^2 -2x + 3 and f(x) = -2x + 12 are (3, 6) and (-3, 18)

A quadratic equation is an algebraic equation of the second degree in x. The quadratic equation in its standard form is ax2 + bx + c = 0, where a and b are the coefficients, x is the variable, and c is the constant term. The first condition for an equation to be a quadratic equation is the coefficient of x2 is a non-zero term(a ≠ 0)

f(x) = x^2 -2x +3 and f(x) = -2x + 12

which means

x^2 -2x +3  = -2x + 12

x^2 -2x +3  + 2x - 12 = 0

x^2 -9 = 0

by factorizing we have

(x-3)(x+3) = 0

x = 3 or -3

when x = 3

f(x) = -2x + 12

f(3) = -2(3) + 12 which is 6

when x = -3

f(-3) = -2(-3) + 12 which is 18

ordered pairs are (3, 6) and (-3, 18)

In conclusion, (3, 6) and (-3, 18) are the ordered pairs

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Answer:

42.31 → 42.49

Step-by-step explanation:

range of h rounded to 47.2:   47.15 → 47.24

range of k rounded to 4.8:  4.75 → 4.84

lower bound of h - k:  47.15 - 4.84 = 42.31

upper bound of h - k:  47.24 - 4.75 = 42.49

42.31 → 42.49

47.2 - 4.8 = 42.4

lower and upper range of h - k can also be expressed as:

42.4 ± 0.09

Answer:

The height of the tree is approximately 21.4 feet

Step-by-step explanation:

We list out the question parameters first as follows;

The distance from the base of the tree where the angle of elevation is measured, d = 10 feet

The angle of elevation to the top of the tree from 10 feet from the base, θ = 65°

Let 'h' represent the height of the tree, then we have;

The line formed by the angle 65° angle, the height of the tree, 'h', and the distance 'd', form a right triangle with 'h' being the opposite leg to the given reference angle, 65°, and 'd' being the adjacent leg

By trigonometric ratio, we have;

\(tan(\theta) = \dfrac{Opposite \ leg \ length}{Adjacent\ leg \ length} = \dfrac{h}{d}\)

∴ h = d × tan(θ)

Plugging in the given values, we get;

h = 10 feet × tan(65°) = 21 feet \(5\frac{11}{32}\) inches

∴  By rounding to the nearest tenth of a foot, the height of the tree, h ≈ 21.4 feet.

Answer:

  (a)  169.1 m

Step-by-step explanation:

The diagram shows you the distance (x) will be shorter than 170 m, but almost that length. The only reasonable answer choice is ...

  169.1 m

__

The relevant trig relation is ...

  Cos = Adjacent/Hypotenuse

The leg of the right triangle adjacent to the marked angle is x, and the hypotenuse is 170 m. Putting these values into the equation, you have ...

  cos(6°) = x/(170 m)

  x = (170 m)cos(6°) ≈ (170 m)(0.994522) ≈ 169.069 m

The horizontal distance covered is about 169.1 meters.

_____

Additional comment

Expressed as a percentage, the slope of this hill is tan(6°) ≈ 10.5%. It would be considered to be a pretty steep hill for driving.

Answer:

-6

Step-by-step explanation:

-2x - 3 = 9

     + 3     +3

-2x = 12

/ -2     / -2

x = -6

The volume of the cone is 4840 cubic ft if the diameter of the base is 34 feet and the height is 16 feet.

It is defined as a three-dimensional shape in which the base is a circular shape and the diameter of the circle decreases as we move from the circular base to the vertex.

V = πr²h/3

Volume can be defined as a three-dimensional space enclosed by an object or thing.

It is given that:

A pile of tailings from a gold dredge is in the shape of a cone.

The diameter of the base is 34 feet and the height is 16 feet.

As we know,

The volume of the cone is given by:

V = πr²h/3

r = 34/2 = 17 ft

h = 16 feet

Plug the above values in the formula:

v = 1/3 × (3.14 × 17 × 17 × 16 )

V = 1541.33(3.14) cubic feet

V = 4839.78 ≈ 4840 cubic ft

Thus, the volume of the cone is 4840 cubic ft if the diameter of the base is 34 feet and the height is 16 feet

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The first one is r=5

The second one is m=175

Answer:

1. r=5  2.m=175

HOPE THIS HELPS :)

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

7r+10=45

Step 2: Subtract 10 from both sides.

7r+10−10=45−10

7r=35

Step 3: Divide both sides by 7.

7r /7 = 35 /7

r=5

Step 1: Simplify both sides of the equation.

m /5 −9=26

1 /5 m+−9=26

1 /5 m−9=26

Step 2: Add 9 to both sides.

1 /5 m−9+9=26+9

1 /5 m=35

Step 3: Multiply both sides by 5.

5*( 1 /5 m)=(5)*(35)

m=175

Answer:

b

Step-by-step explanation:

b

Answer:

27 are blue  C.

Step-by-step explanation: