Simplify:
3x(2y+5)-2y(3x-5)-5(3x+2).

The final result contains how many terms?

Answer:

1. ?

2. d

3. g

4. f

5. k

6. ?

7. j

8. l

9. h

10. b

11. ?

12.?

Answer:

F

Step-by-step explanation:

The shape ABCD is reflected over the given line. If you were to fold the shape over to overlap the new figure FGHI, point A would correspond with point F

Answer:  F.

Step-by-step explanation:

because that's the answer.

Test of significance is  the observed effect due to chance. Option (c) is correct .

What is a significance test?

What makes significance significant?

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Answer:

640

Step-by-step explanation:

PRT

___ principal=3200, Rate=4, Time=5=

100 3200x4x5

_________=640.

100

Answer:

(0,3)

Step-by-step explanation:

The y-intercept has an x-value of 0. Hence, the y-intercept is (0,y).

Substituting (0,y) into the equation:

4(0) + 9y = 27

9y = 27

y = 3

Hence,

(0,3) is the y-intercept.

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The quadratic equation 2a^2 = -6 + 8a has two solutions: a = 3 and a = 1.

To solve the quadratic equation 2a^2 = -6 + 8a, we need to rearrange it into standard quadratic form, which is ax^2 + bx + c = 0, where a, b, and c are coefficients.

Step 1: Move all the terms to one side of the equation to set it equal to zero:

2a^2 - 8a + 6 = 0

Step 2: The equation is now in standard quadratic form, so we can apply the quadratic formula to find the solutions for 'a':

a = (-b ± √(b^2 - 4ac))/(2a)

Comparing with our equation, we have:

a = (-(-8) ± √((-8)^2 - 4(2)(6)))/(2(2))

Simplifying further:

a = (8 ± √(64 - 48))/(4)

a = (8 ± √16)/(4)

a = (8 ± 4)/(4)

Now, we can calculate the two possible solutions:

a1 = (8 + 4)/(4) = 12/4 = 3

a2 = (8 - 4)/(4) = 4/4 = 1

Therefore, the quadratic equation 2a^2 = -6 + 8a has two solutions: a = 3 and a = 1.

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The root cause of the problem Michael is facing is that the sales volume of What's Happening? is steadily declining, which is reflected in the downward trend in the sales data.

This decline in sales volume is making it difficult for the newspaper to sell advertising space and maintain shelf space at supermarkets, and is leading to reduced revenue. Michael's use of a computerized system to collect sales data and make sales forecasts is not addressing this root cause.

The appropriate solution to the problem is for Michael to conduct a thorough analysis of the market and customer needs to identify why the sales volume is declining.

He could consider conducting surveys, focus groups, or other market research methods to gain insight into the needs and preferences of his target audience.

He could also explore new ways to reach his target audience and promote the newspaper, such as using social media or partnering with local businesses. Additionally, he may need to re-evaluate the content and format of the newspaper to make it more appealing to readers.

Once the problem is solved, Michael could use a variety of forecasting approaches to make sales forecasts. For example, he could use time-series analysis to forecast sales based on historical sales data and trends, or he could use regression analysis to identify the factors that influence sales and use them to make sales forecasts.

He could also use qualitative forecasting methods, such as expert opinion or market surveys, to supplement quantitative forecasting methods.

Ultimately, the choice of forecasting approach will depend on the availability of data and the specific needs of the business. Michael should evaluate the accuracy and reliability of each method before deciding which one to use.

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If I started a job on 08/21/2019 and graduated on 05/20/2022 , I have been working here for 1003 days while I was a student.

The correct answer is B. 1003 days.

To find the number of days you have been working at the job as a student, you need to subtract the start date from the end date.

First, convert the dates to a standard format:

Start date: 08/21/2019 = 2019-08-21

End date: 05/20/2022 = 2022-05-20

Next, subtract the start date from the end date:

2022-05-20 - 2019-08-21 = 2 years, 8 months, 29 days

Convert the years and months to days:

2 years = 730 days

8 months = 243 days

29 days = 29 days

Add the days together:

730 + 243 + 29 = 1002 days

Finally, add one day to account for the fact that the end date is included in the calculation:

1002 + 1 = 1003 days

Therefore, you have been working at the job as a student for 1003 days.

Answer: B. 1003

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Number of observations would be necessary to determine the true cycle time with a 95% confidence level and an accuracy are 16.

Sample timings as observed are 3.5, 3.1, 4.0, 3.5, and 3.9.

Sample-time average (X) = (3.5+3.1+4+3.5+3.9)/5

The average sample time (X) is 3.6.

Observed time (T) Mean (X) (X - T) (X - T)^2

3.5 3.6 0.1 0.01

3.1 3.6 0.5 0.25

4.0 3.6 -0.4 0.16

3.5 3.6 0.1 0.01

3.9 3.6 -0.3 0.09

Allow Standard deviation to be S.

2 in (X-T) - 1 n

\(S=\sqrt{\frac{0.52}{4}}\)

S = 0.3605

Considering that (h) = 0.05,

Given that 95% of the time,

Z value at 95% confidence interval = 1.96

Let N be the number of observations.

2 N= Z.S hX

\(N=(\frac{1.96X0.3605}{0.05X3.6})\)

N = 15.4

N = 16 (rounded off to next whole number) (rounded off to next whole number)

Consequently, 16 observations are required.

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Answer:

Step-by-step explanation:

Number of observations would be necessary to determine the true cycle time with a 95% confidence level and an accuracy of 16.

Sample-time average (X) = (3.5+3.1+4+3.5+3.9)/5

The average sample time (X) is 3.6. Observed time (T) Mean (X) (XT) (X-T)^2

3.5 3.6 0.1 0.01

3.1 3.6 0.5 0.25

4.0 3.6 -0.4 0.16

3.5 3.6 0.1 0.01

3.9 3.6-0.3 0.09

Allow Standard deviation to be S.

2 in (X-T) - 1n

S=√0.52/4

S=0.3605

Considering that (h) = 0.05,

Given that 95% of the time,

Z value at 95% confidence interval = 1.96 Let N be the number of observations.

2 N=Z.S hx

N=(1.96X0.3605)÷(0.05×3.6)

N = 15.4

N = 16 (rounded off to next whole number) (rounded off to next whole number) Consequently, 16 observations are required.

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The pitch of the roof is 0.3.

Pitch:

The pitch can be expressed numerically as a fraction. The pitch fraction represents a certain amount of vertical rise over the entire span.

Here it is given that the rise in the roof is 3.6m and a rum of 12m,

We have to find the pitch of the roof.

As is already given in the statement that the slope of a roof is called its pitch.

By this we get the slope:

Slope = 3.6/12

= 3/10

= 0.3

Therefore we get the pitch of the roof at 0.3.

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We need a minimum sample size of 336 to estimate the population proportion of U.S. adults who eat fast food four to six times per week with a 90% confidence level.

A) When there is no preliminary estimate available, we can use the worst-case scenario, which is p = 0.5 (since this gives the maximum possible variability). The margin of error is given as 3% or 0.03. The formula to calculate the minimum sample size needed is:

n = [Z² x p x (1 - p)] / E²

where Z is the z-value for the desired confidence level, p is the population proportion, and E is the margin of error.

At 90% confidence, the z-value is 1.645. Plugging in the values, we get:

n = [(1.645)² x 0.5 x (1 - 0.5)] / (0.03)²

n ≈ 1217.75

We need a minimum sample size of 1218 to estimate the population proportion of U.S. adults who eat fast food four to six times per week with a 90% confidence level and an accuracy of 3%.

B) If a proper study found that 11% of U.S. adults eat fast food four to six times per week, we can use this as a preliminary estimate and calculate the minimum sample size needed with the formula:

n = [Z² x p x (1 - p)] / E²

where p is the preliminary estimate of the population proportion (0.11), and the other variables are the same as before.

At 90% confidence, the z-value is 1.645. Plugging in the values, we get:

n = [(1.645)² x 0.11 x (1 - 0.11)] / (0.03)²

n ≈ 335.77

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\(24^{1/3}=\sqrt[3]{24}=\sqrt[3]{8 \cdot 3}=\sqrt[3]{8}\sqrt[3]{3}=\boxed{2\sqrt[3]{3}}\)

The table of values that represents exponential decay is (c)

From the question, we have the following parameters that can be used in our computation:

The table of values

An exponential function is represented as

y = abˣ

Where

Rate = b

When the rate is less than 1, then the table represents a decay

i.e when y reduces as x increases

The table that has the above features is the table (c)

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2x + y ≤ 7 is the solution

The difference quotient of f(x) is \(\frac{-\frac{1}{h}+ 5}{5x+ h -12}\) .

According to the given question.

We have a function

f(x) = -1/(5x -12)

As we know that, the difference quotient is a measure of the average rate of change of the function over and interval.

The difference quotient formula of the function y = f(x) is

[f(x + h) - f(x)]/h

Where,

f(x + h) is obtained by replacing x by x + h in f(x)

f(x) is a actual function.

Therefore, the difference quotient formual for the given function f(x)

= [f(x + h) - f(x)]/h

= \(\frac{\frac{-1}{5(x+h)-12} -\frac{-1}{5x-12} }{h}\)

= \(\frac{\frac{-1}{5x + 5h -12}+\frac{1}{5x-12} }{h}\)

= \(\frac{\frac{-1+5h}{5x + 5h-12} }{h}\)

= \(\frac{-1+5h}{(5x +h-12)(h)}\)

= \(\frac{-1+5h}{5xh + h^{2} -12h}\)

= \(\frac{h(-\frac{1}{h}+5) }{h(5x+h-12)}\)

= \(\frac{-\frac{1}{h}+ 5}{5x+ h -12}\)

Hence, the difference quotient of f(x) is \(\frac{-\frac{1}{h}+ 5}{5x+ h -12}\) .

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Answer: 6

Step-by-step explanation:

just plug two into the equation

Answer:45

Step-by-step explanation:

Jamie pay if her dog weighs 45 pounds

f(x) = 25$  , X ≤ 15

         35$ , 15 < x ≤ 40

        50$ , 50 + 1.5(x - 40)

A relation between two sets is a group of ordered pairs that each contain one item from both sets. If the ordered pair (x,y) is present in the relation and object x is a member of the first set and object y is a member of the second set, then the objects are said to be connected.

An expression, rule, or law in mathematics that specifies the relationship between an independent variable and a dependent variable (the dependent variable). In mathematics and the sciences, functions are fundamental for constructing physical relationships.

if at 25$ the dog is 15 pound or less.

25$  , X ≤ 15

if at 35$ the dog is over 15 and no more than 40 pounds.

35$ , 15 < x ≤ 40

the dog is over 40 pounds, the charge is $50 plus 1.5 times the number of pounds over 40 that the dog is.

50$ , 50 + 1.5(x - 40)

The accurate value cant be calculated.

So ,

f(x) = 25$  , X ≤ 15

         35$ , 15 < x ≤ 40

        50$ , 50 + 1.5(x - 40)

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Answer:

false its 2 hours a 55 minutes I think hope this helps :)

Step-by-step explanation:

Answer:

noooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooo

Step-by-step explanation:

Answer:

9(x+y)

(3x + 3y) 3

With the possibility of repeating letters and digits, the total number of license plates that can be generated in this format is 8,000,000.

In a state where license plates consist of three letters followed by three digits, with the exclusion of three specific letters and three specific digits, there are a total of 20 letters and 7 digits available for use.

The number of possibilities for each position on the license plate can be calculated by multiplying the number of options for each position. For the letters, since three letters are chosen from a set of 20 (excluding the three specified letters), with repetition allowed, the number of possibilities is 20^3 = 8,000. Similarly, for the digits, since three digits are chosen from a set of 7 (excluding the three specified digits), with repetition allowed, the number of possibilities is 7^3 = 343. To find the total number of license plates, we multiply these two results together: 8,000 * 343 = 2,744,000. Therefore, there are a total of 2,744,000 possible license plates.

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Let S = N, and let R be the relation of divisibility, l.To prove that the relation of divisibility is a partial order, we need to show that it satisfies the three conditions of a partial order: reflexivity, antisymmetry, and transitivity.

Reflexivity: For any natural number n, n is divisible by itself (n l n), so the relation is reflexive.

Antisymmetry: Suppose m l n and n l m for natural numbers m and n. Then we have m = kn and n = lm for some natural number k and l. It follows that m = klm and n = kln. Since k, l, and m are all natural numbers, we have klm l kln, which implies that lm l ln. But since m and n are positive integers, we must have m = n. Therefore, the relation is antisymmetric.

Transitivity: Suppose m l n and n l p for natural numbers m, n, and p. Then we have n = km and p = ln for some natural number k. It follows that p = lkm, which implies that m l p. Therefore, the relation is transitive.

Since the relation of divisibility satisfies all three conditions of a partial order, it is a partial order.

b. Let T be any set. Let S = 2^T, the power set of T. Let R be the relation of subset, ⊆.

To prove that the relation of subset is a partial order, we need to show that it satisfies the three conditions of a partial order: reflexivity, antisymmetry, and transitivity.

Reflexivity: For any set A, A is a subset of itself (A ⊆ A), so the relation is reflexive.

Antisymmetry: Suppose A ⊆ B and B ⊆ A for sets A and B. Then we have x ∈ A implies x ∈ B and x ∈ B implies x ∈ A, which implies that A = B. Therefore, the relation is antisymmetric.

Transitivity: Suppose A ⊆ B and B ⊆ C for sets A, B, and C. Then we have x ∈ A implies x ∈ B and x ∈ B implies x ∈ C, which implies that x ∈ A implies x ∈ C. Therefore, A ⊆ C, and the relation is transitive.

Since the relation of subset satisfies all three conditions of a partial order, it is a partial order.

c. Let A be any alphabet, a set totally ordered by some relation <. Let S be the set of finite words whose letters are drawn from A. Let R be the dictionary order on S, defined as follows. Let i be the smallest integer where the ith letter of the two words differ. The word whose ith letter is smaller in < (or that doesn't have an ith letter) is smaller in R.

To prove that the dictionary order is a partial order, we need to show that it satisfies the three conditions of a partial order: reflexivity, antisymmetry, and transitivity.

Reflexivity: For any word w in S, w is equal to itself, and so it is equal to w in the dictionary order. Therefore, the relation is reflexive.

Antisymmetry: Suppose wRv and vRw for words w and v. Then there must exist some i where the ith letter of the two words differ. Let x be the ith letter of w and let y be the ith letter of v. Since A is totally ordered by <, we must have either x < y or y < x. Without loss of generality, assume that x < y. Then w < v in the dictionary order, which contradicts vRw. Therefore,

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Answer:

d = 3 and d = 3/4

Step-by-step explanation:

This is a quadratic eqution.  Let's use the quadratic formula to solve it.

If ax^2 + bx + c = 0, then:

      -b ± √(b^2 - 4ac)

x = ---------------------------

                 2a

With a = 4, b = -15 and d = 9, we have:

      -(-15) ± √(225 - 4(4)(9) )        15 ±√81         15 ±9

d = ------------------------------------ = -------------- = -------------- = 24/8 and 6/8

                      2(4)                              8                   8

Simplifying these results, we get d = 3 and d = 3/4

Al needs to order 500 widgets to restock his widget store  after the sale of 473 widgets

What do lots of 100 mean?

The lots of 100 means that the minimum that can be ordered from the supplier is 100 widgets at a time, which means that to restock 473 widgets, the company needs to order 5 lots of 100 lots, which implies that the company must order for 500 widgets to replace 473 widgets sold

400 widgets, which means 4 lots cannot be ordered because the number is less than the quantity sold which requires replenishment

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Answer:Step-by-step explanation:

c。4.3

ddddddddddddddddddddddddddddddd

Ivy likes to buy trail mix in bulk at her local grocery store. If she paid $5.16 for 1.2 pounds of trail mix, the price per pound would be $4.3.

The unitary method is a method for solving a problem by the first value of a single unit and then finding the value by multiplying the single value.

If she paid $5.16 for 1.2 pounds of trail mix

Cost 1.2 pounds of trail mix = $5.16

Cost per pound of trail mix = $5.16/1.2

                                              = $4.3

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The solution of the quadratic equation using the quadratic formula is

x = 4 + 2√6 or  4 - 2√6

The quadratic formula is a formula used to solve quadratic equations, which are equations of the form ax² + bx + c = 0 where a, b, and c are constants. The quadratic formula is:

x = (-b±√(b²-4ac))/(2a)

Given: x² - 8x - 84 = 0

Here, a = 1, b = -8 and c = -84

x = (-b±√(b²-4ac))/(2a)

x = [-(-8)±√((-8)²-[4×1×(-8)])]/(2a)

x = [8±√(96)]/2

x = (8± 4√6)/2

x = 4 ± 2√6

x = 4 + 2√6 or  4 - 2√6

Thus, the solution is x = 4 + 2√6 or  4 - 2√6

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The probability that a woman was wearing a belt given that she was also carrying a purse is 0.333 or 33.3%.

To find the probability that a woman was wearing a belt given that she was also carrying a purse, we need to use conditional probability.

We know that out of the 30 women observed, 18 were carrying purses and 6 were both carrying purses and wearing belts.

This means that the number of women carrying purses who were also wearing belts is 6.
Therefore, the probability that a woman was wearing a belt given that she was also carrying a purse is:
P(wearing a belt | carrying a purse) = number of women wearing a belt and carrying a purse / number of women carrying a purse
P(wearing a belt | carrying a purse) = 6 / 18
P(wearing a belt | carrying a purse) = 0.333
Given the information provided, we can determine the probability of a woman wearing a belt, given that she is also carrying a purse.

First, we need to find the number of women carrying a purse and wearing a belt, which is 6. There are 18 women carrying purses in total.
So, to find the probability, we will use the formula:
P(Belt | Purse) = (Number of women wearing belts and carrying purses) / (Number of women carrying purses)
P(Belt | Purse) = 6 / 18
P(Belt | Purse) = 1/3 or approximately 0.33
Therefore, the probability that a woman was wearing a belt, given that she was also carrying a purse, is 1/3 or approximately 0.33.

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The smallest such whole number is 11 which is, Which is divided by 3, the remainder is 2, f it, divided by 4, the remainder is 3

Let the number be x

Here we have to find the whole number which is Divided by 3,4 the remainder is 2,3 respectively,

x+(3–2)= x +1 is multiple of 3

Div by 4 remainder is

3x+(4–3) = x+1 is multiple of 4

So LCM of 3,4 is 3×4 = 12

Hence,x=12 –1 =11

The smallest such whole number is 11 which is divided by 3, the remainder is 2, if it divided by 4, the remainder is 3.

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Answer:

Step-by-step explanation:

Total zigzag = 5 + 5 = 10

5 zigzag made of velvet

Probability of zigzag made of velvet = 5/10 = 1/2

I guess this is the answer. 1/2

Answer:

5/17

Step-by-step explanation:

number of zigzag AND velvet (5) over the total number of bow ties (17)

a) The value of z corresponding to an area of 0.1210 can be found using statistical tables or a statistical calculator.

b) Similarly, the value of z corresponding to an area of 0.9898 can be obtained using statistical tables or a statistical calculator.

c) To find the value of z at the 45th percentile, we can use the standard normal distribution table or a statistical calculator.

a) To find the value of z corresponding to an area of 0.1210, you can use a standard normal distribution table or a statistical calculator. By looking up the area of 0.1210 in the table, you can determine the corresponding z-value. For example, if you find that the z-value for an area of 0.1210 is -1.15, then -1.15 is the value of z corresponding to the given area.

b) Similarly, to find the value of z corresponding to an area of 0.9898, you can refer to a standard normal distribution table or use a statistical calculator. Find the z-value that corresponds to the area of 0.9898. For instance, if the z-value for an area of 0.9898 is 2.32, then 2.32 is the value of z corresponding to the given area.

c) To find the value of z at the 45th percentile, you can use a standard normal distribution table or a statistical calculator. The 45th percentile corresponds to an area of 0.4500. By finding the z-value for an area of 0.4500, you can determine the value of z at the 45th percentile. For example, if the z-value for an area of 0.4500 is 0.125, then 0.125 is the value of z at the 45th percentile.

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