show that lim x-0 sinx/x=1 using limx-0 cosx-1/x=0

a) The proportion of the students scored at least 26 points on this test is 0.02275.

b) The 71 percentile of the distribution of test scores is 24.073

A low standard deviation suggests that values are often close to the mean of the collection, whereas a large standard deviation suggests that values are dispersed over a wider range.

Standard deviation, often known as SD, is most frequently represented in mathematical texts and equations by the lower case Greek letter (sigma), for the population standard deviation, or the Latin letter s, for the sample standard deviation.

Let the scores be X and X is normally distributed with a mean of 22 and standard deviation of 2.

μ=22

σ=2

X≈N(22,2)

a) P(X≥26)=P(((X-μ)/σ)≥(26-μ)/σ)

=1-P(Z≥2)

=1-P(Z<2)

=1-0.97725

=0.02275

b) Let a is the 71th percentile of X,

P(X≤a)=0.71

P((X-μ)/σ)≤(a-μ)/σ)=0.71

P(Z≤z)=0.71

From the standard normal table by calculating with z value, we get

a=24.073

Therefore,

a) The proportion of the students scored at least 26 points on this test is 0.02275.

b) The 71 percentile of the distribution of test scores is 24.073.

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Answer:

55 degrees

Step-by-step explanation:

well, x is on the same line as 125, and a line is always a straight 180 degrees, so you subtract 180-125=55, and angle x and angle y are corrisponding angles, so y also equals 55 degrees.

hope that helps!

Answer:

The area is 1,725 ft²

Refer to attachment for your answer

Answer:

The correct answer would be 2.00%

Answer:

11.75 please give brainliest

Step-by-step explanation:

Since it is given that  ∠1 and ∠2 are supplementary angles, the value of x=26.

Given that ∠1 ​ and ∠2 are supplementary.

∠1=124°

∠2=(2x+4)°

We know that the sum of supplementary angles is 180°.

For, example if ∠A, ∠B ,∠C and ∠D are four angles of a quadrilateral, and ∠A and ∠D are supplementary. Then,

∠A + ∠D= 180°

Therefore,

             ∠1 + ∠2 = 180°

Substituting the values given, we have:

                 124° + (2x + 4)° = 180°

Simplifying, we have:

                      2x + 128° = 180°

2x = 180° - 128°

2x = 52°

x = 52°/2

x = 26

Hence, the value of x is 26. Therefore, the correct answer is option B.

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To carpet the rectangular floor, it will cost $1,137.6. The result if obtained by multiplying the area of the carpet by the cost per square yard.

To calculate the cost of a product, multiply the product price for one item by the quantity.

We have a rectangular floor with a dimension of 27 feet by 24 feet. The carpet cost is $15.8 per square yard. Find the total cost to carpet it!

Let's change the unit of length.

The area of the carpet is

A = 9 yard × 8 yard

A = 72 square yard

The total cost is

C = A × price/square yard

C = 72 × $15.8

C = $1,137.6

Hence, the total cost to carpet the floor is $1,137.6.

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The expected winnings on a $5 bet are -0.1157 dollars. This means that on average, you will lose about 11.57 cents for each $5 bet you make.

Therefore, the game is not a good bet, as you are expected to lose money in the long run.

What is the probability distribution?

A probability distribution is a mathematical function that describes the probability of different possible values of a variable.

The probability of winning on a $5 bet on a specific number in chuck-a-luck is determined by the number of ways that the number can appear on the three dice and the total number of possible outcomes.

If the number appears on exactly one die, there are 3 ways that this can happen out of a total of 6^3 = 216 possible outcomes, giving a probability of 3/216 or 1/72.

If the number appears on exactly two dice, there are 3 ways to choose the two dice on which it appears, and 3 ways to choose the third die, giving a total of 33 = 9 ways out of 216 possible outcomes, giving a probability of 9/216 or 1/24.

If the number appears on all three dice, there is only 1 way this can happen out of 216 possible outcomes, giving a probability of 1/216.

If it appears on none of the dice, there are (543) ways this can happen, giving a probability of (54*3)/216 = 20/216.

We can use this information to construct the probability distribution for chuck-a-luck:

x P(x)

-5 (losing the bet) 20/216

5 (winning the bet for one appearance) 1/72

10 (winning the bet for two appearances) 1/24

15 (winning the bet for three appearances) 1/216

To find the expected winnings on a $5 bet, we can multiply the value of each outcome by its corresponding probability, and sum the results:

E(X) = (-5)(20/216) + (5)(1/72) + (10)(1/24) + (15)(1/216)

E(X) = -5/43.2 + 5/72 + 5/12 + 15/216

E(X) = -0.1157

Hence, the expected winnings on a $5 bet are -0.1157 dollars. This means that on average, you will lose about 11.57 cents for each $5 bet you make.

Therefore, the game is not a good bet, as you are expected to lose money in the long run.

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The type of loan that Brady most likely getting  is option (a) conventional loan

Conventional loans are typically not guaranteed or insured by the government and often require a higher down payment compared to government-backed loans such as FHA or VA loans. The down payment requirement of $5,250, which is 3.5% of the purchase price, is lower than the typical down payment requirement for a conventional loan, which is usually around 5% to 20% of the purchase price.

ARM (Adjustable Rate Mortgage) loans have interest rates that can change over time, which can make them riskier for borrowers. FHA (Federal Housing Administration) loans are government-backed loans that typically require a lower down payment than conventional loans, but they also require mortgage insurance premiums.

VA (Veterans Affairs) loans are available only to veterans and offer favorable terms such as no down payment requirement, but not everyone is eligible for them. Fixed-rate loans have a fixed interest rate for the life of the loan, but the down payment amount does not indicate the loan type.

Therefore, the correct option is (a) Conventional loan

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Answer:

x=-1

Step-by-step explanation:

7x-5=2x

-7x -7x

-5=-5x

-5/-5=-5x/-5

-1=x

hopefully this helps :)

==============================================

Work Shown:

T = tens digit

U = units digit (aka ones digit)

A number like 27 is really 20+7 = 2*10 + 7*1 = 10*2 + 1*7. We have 2 in the tens digit and 7 in the units digit. So 27 can be written in the form 10T + U where T = 2 and U = 7. Reversing the digits gives 72, so T = 7 and U = 2 now. Clearly the difference between the digits 7 and 2 is not 1, so 27 or 72 is not the answer (as it's just an example).

-----------------------

Let T be larger than U. This doesn't work if T = U.

Because T is larger, saying "The difference between the digits is 1" means T - U = 1. We can isolate T to get T = U+1. We'll use this later.

-----------------------

If T > U, then the original number 10T+U reverses to the new number 10U+T and it becomes smaller. We are told that it becomes 5/6 of what it used to be.

So,

new number = (5/6)*(old number)

10U + T = (5/6)(10T + U)

6(10U + T) = 5(10T + U)

60U + 6T = 50T + 5U

60U + 6(U+1) = 50(U+1) + 5U ... plug in T = U+1

60U + 6U + 6 = 50U + 50 + 5U

66U + 6 = 55U + 50

66U - 55U = 50-6

11U = 44

U = 44/11

U = 4 is the units digit of the original number

T = U+1

T = 4+1

T = 5 is the tens digit of the original number

The original number is therefore 10T + U = 10*5+4 = 54.

We see the difference in their digits is T-U = 5-4 = 1

The reverse of 54 is 45. The number 45 is 5/6 of 54

45 = (5/6)*54

Answer:

\(\frac{9}{4} - \frac{5}{10} = 1\frac{3}{4}\)

Step-by-step explanation:

Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD. This is basically multiplying each fraction by 1.

LCD(9/4, 5/10) = 20

\((\frac{9}{4} * \frac{5}{5} ) - (\frac{5}{10} * \frac{2}{2} ) = ?\)

Complete the multiplication and the equation becomes

\(\frac{45}{20} - \frac{10}{20}\)

The two fractions now have like denominators so you can subtract the numerators.

Then:

\(\frac{45 - 10}{20} = \frac{35}{20}\)

This fraction can be reduced by dividing both the numerator and denominator by the Greatest Common Factor of 35 and 20 using

GCF(35,20) = 5

\(\frac{35 / 5 }{20 / 5} = \frac{7}{4}\)

The fraction

\(\frac{7}{4}\)

is the same as

7 ÷ 4

Therefore:

\(\frac{9}{4} - \frac{5}{10} = 1\frac{3}{4}\)

Apply the fractions formula for subtraction, to

\(\frac{9}{4} - \frac{5}{10}\)

and solve

\(\frac{(9 * 10)- (5* 4) }{4 * 10}\)

\(= \frac{90-20}{40}\)

\(= \frac{70}{40}\)

Reduce by dividing both the numerator and denominator by the Greatest Common Factor GCF(70,40) = 10

\(\frac{70/ 10 }{40 / 10} = \frac{7}{4}\)

Convert to a mixed number using

long division for 7 ÷ 4 = 1R3, so

\(\frac{7}{4} = 1\frac{3}{4}\)

Therefore:

\(\frac{9}{4} - \frac{5}{10} = 1\frac{3}{4}\)

(A) Usain Bolt's average speed in meters per second was approximately 10.36 m/s.

(B) Usain Bolt's average speed in miles per hour was approximately 23.35 mph.

(A) Average speed = Distance / Time

Average speed = 200 meters / 19.30 seconds

Average speed = 10.36 meters per second

Therefore, Usain Bolt's average speed in meters per second was approximately 10.36 m/s.

(B) 1 mile = 2580 feet

Converting the distance from meters to miles:

Distance in miles = Distance in meters / (1 meter / 3.28 feet) / (1 mile / 5280 feet)

Distance in miles = 200 meters / 3.28 / 5280 miles

Time in hours = Time in seconds / (60 seconds / 1 minute) / (60 minutes / 1 hour)

Time in hours = 19.30 seconds / 60 / 60 hours

Average speed = Distance in miles / Time in hours

Average speed = (200 meters / 3.28 / 5280 miles) / (19.30 seconds / 60 / 60 hours)

Average speed = 23.35 miles per hour

Therefore, Usain Bolt's average speed in miles per hour was approximately 23.35 mph.

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Answer:

\(\dfrac{1}{729}\)

Step-by-step explanation:

\(\left(\dfrac{}{}(-3)^2\dfrac{}{}\right)^{-3}\)

First, we should evaluate inside the large parentheses:

\((-3)^2 = (-3)\cdot (-3) = 9\)

We know that a number to a positive exponent is equal to the base number multiplied by itself as many times as the exponent. For example,

\(4^3 = 4 \, \cdot\, 4\, \cdot \,4\)

       ↑1 ↑2 ↑3 times because the exponent is 3

Next, we can put the value 9 into where \((-3)^2\) was originally:

\((9)^{-3}\)

We know that a number to a negative power is equal to 1 divided by that number to the absolute value of that negative power. For example,

\(3^{-2} = \dfrac{1}{3^2} = \dfrac{1}{3\cdot 3} = \dfrac{1}{9}\)

Finally, we can apply this principle to the \(9^{-3}\):

\(9^{-3} = \dfrac{1}{9^3} = \boxed{\dfrac{1}{729}}\)

The two numbers are 7/6 and 5 when the sum of two numbers is 3 more than four times the first number.

Let's call the two numbers x and y, where x is the first number and y is the second number.

The problem gives us two equations that relate the two numbers:

\(x + y = 3 + 4x\\y - x = 2y - 10\)

We can substitute the expression for y from equation 1 into equation 2:

\(y - x = 2(3 + 4x) - 10\)

Expanding the right side and simplifying, we get:

\(y - x = 6 + 8x - 10\\y - x = 8x - 4\)

Adding x to both sides:

\(y = 9x - 4\)

Substituting this expression for y into equation 1:

\(x + (9x - 4) = 3 + 4x\)

Expanding and simplifying the right side:

\(10x - 4 = 3 + 4x\)

Subtracting 4x from both sides:

\(6x - 4 = 3\)

Adding 4 to both sides:

\(6x = 7\)

Dividing both sides by 6:

\(x = 7/6\)

Substituting this value of x back into the expression for y:

\(y = 9x - 4 = 9 * (7/6) - 4 = 63/6 - 4 = 9 - 4 = 5\)

So the two numbers are 7/6 and 5.

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One point that would lie on the second line is (0,-4). Another  possible point on the 2nd line is (0, 12).

To find the equation of the first line, we can use the slope-intercept form:

y = mx + b

where m is the slope and b is the y-intercept. The slope of the line passing through (-3,8) and (1,9) can be found using the formula:

m = (y2 - y1) / (x2 - x1)

m = (9 - 8) / (1 - (-3))

m = 1/4

Using one of the points and the slope, we can find the y-intercept:

8 = (1/4)(-3) + b

b = 9

So the equation of the first line is:

y = (1/4)x + 9

To find the equation of the second line, we need to use the fact that it is perpendicular to the first line. The slopes of perpendicular lines are negative reciprocals, so the slope of the second line is:

m2 = -1/m1 = -1/(1/4) = -4

Using the point-slope form, we can write the equation of the second line:

y - 4 = -4(x + 2)

y - 4 = -4x - 8

y = -4x - 4

To find a point that lies on this line, we can plug in a value for x and solve for y. For example, if we let x = 0, then:

y = -4(0) - 4

y = -4

So the point (0,-4) lies on the second line.

Therefore, another point that would lie on the second line is (0,-4).

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Answer:

900

Step-by-step explanation:

Step-by-step explanation:

11x-4<15

11x<15+4

11x<19

x<1

Answer:

the anwser is 95 dollars I know because i did this

Answer:

You need to use the angles as a waypoint such as the one opposite b is equal to b then you need to use the angles on a straight line

Step-by-step explanation:

Answer:

∠A= 111.75°

Step-by-step explanation:

Please see the attached picture.

∠B +∠C= 180° (adj ∠s on a str. line)

(x +35)° +∠C= 180°

∠C= 180° -(x +35)°

∠C= 145° -x°

∠A= ∠C (corr. ∠s)

∠A= 145° -x°

Given that ∠A is (3x +12)°, equate this expression to the expression we found.

145° -x°= 3x° +12°

3x° +x°= 145° -12°

4x°= 133°

x°= 133° ÷4 (÷4 on both sides)

x°= 33.25°

Substitute the value of x back into the expression for ∠A:

∴∠A= 3(33.25°) +12°

∠A= 111.75°

Answer:

Step-by-step explanation:

The value of b according to the binomial expansion expressed in the form, (ax + b)⁴ is; b = 15.

The binomial expansion given is;

625x4 – 7,500x3 + 33,750x2 – 67,500x + 50,625.

While expressing the binomial expansion in the form; (ax + b)⁴;

The value of b can be evaluated as follows;

In essence, the quartic root of 50625 is the value of b as follows;

\(b = \sqrt[4]{50625} \)

b = 15. OR. b = -15

However, more convincingly, the value of b is; Choice D: 15

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The maximum profit is 6 and it is obtained when we mix 0.6 kg of type A, 0 kg of type B, and 0.4 kg of type C.

The optimal mix for the maximum profit can be found as follows:

The company mixes three types of toffees, A, B, and C. Let the weights of type A, B, and C be a, b, and c kg, respectively. Let us assume that we are making 1kg of toffee pack. Therefore, the weight of type C should be 1 - (a + b) kg. Also, the mixture must contain at least 300 gms of type A i.e a >= 0.3 kg

Also, the weight of the first two types (A and B) must be at least equal to the weight of type C, i.e a + b >= c. This condition can also be written as a + b - c >= 0

Let us now calculate the total cost of making 1kg of toffee pack.

Cost = 20a + 10b + 5c

If the pack is sold at Rs. 17, then the profit per 1kg of toffee pack is by

Profit = Selling Price - Cost = 17 - (20a + 10b + 5c)

Now we have the following linear programming problem:

Maximize P = 17 - (20a + 10b + 5c)

Subject to constraints: a + b + c = 1 (since we are making 1kg of toffee pack)

a >= 0.3a + b - c >= 0a, b, c >= 0

We can use the simplex method to solve this linear programming problem. However, to save time, we can solve it graphically. The feasible region is as follows:

We can see that the corner points of the feasible region are: (0.3, 0, 0.7), (0.6, 0, 0.4), (0, 0.5, 0.5), and (0, 1, 0).

Let us calculate the profit at each of these corner points. For example, at the point (0.3, 0, 0.7), we have a = 0.3, b = 0, and c = 0.7. Therefore, the profit is

P = 17 - (20(0.3) + 10(0) + 5(0.7)) = 3.5

Similarly, we can calculate the profit at the other corner points as well. The corner point (0.3, 0, 0.7) gives a profit of 3.5

Corner point (0.6, 0, 0.4) result in a profit of 6

Corner point (0, 0.5, 0.5) results in a profit of 5

Corner point (0, 1, 0) gives a profit of 3

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Answer:

165cm

Step-by-step explanation:

An ordered pair is a solution of an equation in two variables if replacing the variables by the coordinates of the ordered pair results in a true statement.

In mathematics, an equation in two variables represents a relationship between two quantities. An ordered pair consists of two values, typically denoted as (x, y), that represent the coordinates of a point in a two-dimensional plane.

When these values are substituted into the equation, if the equation holds true, then the ordered pair is considered a solution or a solution set to the equation. This means that the relationship described by the equation is satisfied by the values of the ordered pair. In other words, the equation is true when evaluated with the values of the ordered pair.

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The y-coordinate for the solution to the system of equations is -3.

What is a system of equations?

A finite set of equations for which common solutions are sought is referred to in mathematics as a set of simultaneous equations, often known as a system of equations. The intersection of two lines represents the system of equations' solution.

Given system of equations are,

6x + 11y = -3

4x + y = 17

To solve these equations, we must first remove x or y terms.

To do this we must make the removing term's coefficients the same.

In this case, let's remove y.

We are multiplying the second equation by 11. Then,

6x + 11y = -3

44x + 11y = 187

Now we will subtract the second equation from the first.

- 38x  = -190

x = 5

Now to find y, substitute x in any one of the equations.

6 * 5 + 11y = -3

11y = -33

y = -3

Hence the y-coordinate for the solution to the system of equations is -3.

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Let's label the regions in the Venn diagram as follows:

F: students who do only field events

T: students who do only track events

S: students who do only swimming events

FT: students who do both field and track events

ST: students who do both swimming and track events

FST: students who do all three events

From the information given in the problem, we can fill in some of the values in the Venn diagram:

F + FT + 15 = 33 (33 students do field events, and 15 do field events only)

T + FT + 14 = 40 (40 students do track events, and 14 do both field and track events)

S + ST + 10 = 23 (23 students do swimming, and 10 do both swimming and track events)

F + T + S + 2FT + ST + FST = 68 (there are 68 students in total)

We can simplify these equations to:

F + FT = 18

T + FT = 26

S + ST = 13

F + T + S + 2FT + ST + FST = 68

To solve for the remaining unknowns, we need to use some algebra. We can start by solving for FT:

F + FT = 18

T + FT = 26

Adding the two equations, we get:

F + T + 2FT = 44

Rearranging, we get:

FT = (44 - F - T) / 2

Now we can substitute this expression for FT into the equation for the total number of students:

F + T + S + 2FT + ST + FST = 68

F + T + S + 2((44 - F - T) / 2) + ST + FST = 68

F + T + S + 44 - F - T + ST + FST = 68

Simplifying, we get:

S + ST + FST = 26

Now we have two equations involving S, ST, and FST:

S + ST = 13

S + ST + FST = 26

We can solve for S and ST by subtracting the first equation from the second:

S + ST + FST = 26

(S + ST) + FST = 26

Substituting S + ST = 13:

13 + FST = 26

FST = 13

So there are 13 students who do all three events. Now we can use the equation S + ST = 13 to solve for S:

S + ST = 13

ST = 10 (given in the problem)

S = 13 - 10 = 3

So there are 3 students who do swimming only. Similarly, we can use the equation T + FT = 26 to solve for T:

T + FT = 26

FT = (44 - F - T) / 2

Substituting F + FT = 18:

T + (18 - F) / 2 = 26

Multiplying both sides by 2:

2T + 18 - F = 52

Via Gelato total revenue for the month of June as the the details of expenses is equal to $7870.

As given in the question,

Total revenue is:

= (6200 × 13) - 72,540

=$ 8060

Details of all expenses are as follow:

Expense on raw material:

= (6200 × 4.75) -30,330

= -$880

Wages :

= (6200 ×1. 50) + 5,700 - 14,560

= $440

Utilities:

= (6200 × 0.30) +1730 - 3,800

= -$210

Rent:

= (2700-2700)

= 0

Insurance :

= (1450-1450)

= 0

Miscellaneous :

= (6200 × 0.45) + 660 -2,990

= $460

Total expense

=-$190

Net operating income :

=$ [8060-190]

=$7870

Therefore, Via Gelato's  total revenue of the June month is equal to $7870.

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