select all the compounds from the following list that would give rise to two signals in the 1h nmr spectrum with an integration ratio of 2:3.

Answer:

Milk would be a homogeneous substance

Answer:

Milk is a heterogeneous mixture

Explanation:

Heterogeneous mixture which can be defined as a complex chemical substance in which fat is emulsified as globules, major milk protein (casein), and some mineral matters in the colloidal state and lactose together with some minerals and soluble whey proteins in the form of true solution.

Answer:

A salt is a neutral ionic compound. Let's see how a neutralization reaction produces both water and a salt, using as an example the reaction between solutions of hydrochloric acid and sodium hydroxide. The overall equation for this reaction is: NaOH + HCI → H2O and NaCl.

Explanation:

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\(\\ \orange{MaggieEve}\)

Answer:

c. baking soda

Explanation:

C. Antarctica and Greenland

No. According to solubility rule, we cannot use the Fe(NO3)3 rather than AgNO3 via analysis of precipitate of AgCl because no precipitate of cl- ion formed in Fe(NO3)3 .

A solubility chart having solubility rules is defined as a chart describing for different combinations of cations and anions whether the ionic compounds formed dissolve in or precipitate from a solution. This chart shows the solubility of various common ionic compounds in water, at a pressure of 1 atm. and under room temperature.

The following reactions are involved to determine Cl- concentration,

Case 1:  Fe(NO3)3 (aq.) + Cl-(aq.)   ----> FeCl3(aq.) + NO3-(aq.).

In this reaction involving aqueous solution of Fe(NO3)3 no precipitate of Cl- ion compound is formed .so this we can not use Fe(NO3)3 to determine %Cl- ion in solution.

Case 2 :

AgNO3(aq.) + Cl- (aq.)  ---> AgCl(precipitate) + NO3-.

This reaction involving aqueous solution of AgNO3 can be use to determine %Cl- ion concentration in solution via analysis of precipitate of AgCl .

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The boiling point of water generally increases as the amount of impurities (which a solute like KCl technically can be thought of) dissolved increases. This relation can be quantified using the equation,

\(\Delta T_b = i \times K_b \times m\)

where \(\Delta{T}_{b}\) is the change in the water's boiling point (normally taken to be 100 °C), \(i\) is the Van 't Hoff factor (the number of particles a single formula unit of the solute dissociates into in water), \(K_b\) is the boiling point elevation constant, and \(m\) is the molality (moles of solute/kilogram(s) of solvent) of the solution.

We are forming a solution by dissolving KCl in water. KCl is an electrolyte that, in water, will dissociate into K⁺ and Cl⁻ ions. So, for every formula unit, KCl, we obtain two particles. Thus, the Van 't Hoff factor, or \(i\), will be 2.

The molality of the solution can be calculated by dividing the number of moles of KCl by the mass of water in kilograms. Since we have 1.00 kg of water, we would be dividing 0.75 mol KCl by 1, giving us a molality (m) of 0.75 m.

We aren't provided the boiling point elevation constant for water. Several authoritative sources give the value 0.512 °C/m, so we will adopt that as our \(K_b\).

Note: m = mol/kg as used in this problem.

Plugging everything in,

\(\Delta T_b = i \times K_b \times m \\\Delta T_b = 2 \times 0.512 \text{ } \frac{^oC}{mol/kg} \times 0.75 \text{ } \frac{mol}{kg} \\\Delta T_b = 0.768 \text{ } \mathrm{ ^oC}\)

As you can see, our change in boiling point is positive (the boiling point is elevated), and it is also quite modest. Taking 100 °C to be the boiling point of pure water, the boiling point of our solution would be 100 ⁰C + 0.768 ⁰C, or 100.768 ⁰C.

If we are considering significant figures, then we must give our answer to two significant figures (since 0.75 has two sig figs). We can regard the boiling point of water (100 ⁰C) as a defined value. Since our final answer is a sum, the boiling point of our solution to two significant figures would be 100.77 ⁰C.

Given:

We know,

The molality of the solution will be:

= \(\frac{Mole}{Mass}\)

= \(\frac{0.75}{1}\)

= \(0.75 \ m\)

Now,

→ \(T_{solution}-T_{water} = Kb\times m\times i\)

By putting the values, we get

                              \(= 0.51\times 0.75\times 2\)

                              \(= 0.765\)

hence,

Solution's boiling point will be:

→ \(T_{solution} = 100+0.765\)

                \(= 100.765^{\circ} C\)

Thus the above approach is right.

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Answer: They are versatile and perform a variety of tasks.

Explanation:

The conversions that could be performed with these two conversion factors alone, Density—> molar mass or/formula mass—> is volume ---> moles; option D

Conversion factors are expressions or values which are used to convert from one unit or value to another.

The conversion factor given is:

Density—> molar mass or/formula mass—>

volume = density/mass

moles = mass/molar mass

Volume to moles = density/mass -->  mass/ molar mass

Volume to moles = density ---> molar mass or formula mass

The conversion of volume to moles will therefore require density and molar mass or formula.

In conclusion, conversion factors are used to convert from one unit  value to another.

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Answer:

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7 moles of Cr

Given that there is 1 mole of he compound Cr7(PO4)3, the 1 mole of the compound is composed of 12moles of oxygen, 3 moles of phosphorous and 7 moles of chromium.

Hence we can conclude that there will be 7 moles of Cr in 1 mole of Cr7(PO4)3

The new volume assuming that the pressure and temperature remain constant is 0.46 L and the correct option is option 1.

The Ideal gas law is the equation of state of a hypothetical ideal gas. It is a good approximation to the behaviour of many gases under many conditions, although it has several limitations. The ideal gas equation can be written as-

                        PV = nRT

where,

P = Pressure

V = Volume

T = Temperature

n = number of moles

Given,

Initial volume = 1.5 L

Initial moles = 7.5 moles.

Moles remaining = 2.3 moles

\(\frac{n_{1} }{V_{1} } = \frac{n_{2} }{V_{2} }\)

\(\frac{7.5}{1.5 } = \frac{2.3}{V_{2} } }\)

V₂ = 0.46 L

Thus, the ideal selection is option 1.

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In terms of yield, the repeated extraction technique is more efficient.

The residue left over after extraction contains the same amount of material as the extract itself. If you extract again, both the concentration in the extract and the residue will be decreased.

Therefore, with several extractions, there will be less material left in the residue, meaning the extraction will be more thorough.

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Answer:

lhigygygigy

Explanation:

hyfgutfytifytftyfjgfhjfv

The volume of 12 gas forms when 21 L Cl2 react at STP is 21 L.

To determine the volume of 12 gas (I assume you mean I2 gas) formed when 21 L of Cl2 reacts at STP (standard temperature and pressure), we need to use the ideal gas law equation.

The ideal gas law equation is given by:

PV = nRT

Where:

P = pressure

V = volume

n = number of moles

R = ideal gas constant

T = temperature

At STP, the pressure is 1 atm, and the temperature is 273.15 K.

From the balanced equation, we can see that the molar ratio between Cl2 and I2 is 1:1. So, if 21 L of Cl2 reacts, it will produce an equal volume of I2 gas.

Given that the volume of Cl2 is 21 L, we can assume the volume of I2 gas formed will also be 21 L.

Therefore, the volume of I2 gas formed is 21 L.

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Answer:

BUDDY YO

Explanation:

The best description of the relationship between population size, carrying capacity, and limiting factors is: "The size of a population usually stays near its carrying capacity due to limiting factors."

Carrying capacity refers to the maximum number of individuals that a particular environment can sustainably support. It represents the limit to which a population can grow given the available resources, such as food, water, and habitat. Limiting factors, on the other hand, are the factors that restrict population growth by reducing birth rates, increasing death rates, or limiting access to resources.As a population approaches its carrying capacity, limiting factors come into play and regulate the population size. These limiting factors can include competition for resources, predation, disease, availability of suitable habitat, and other environmental factors. They act as checks on population growth, preventing it from exceeding the carrying capacity of the ecosystem.

Therefore, the size of a population usually stays near its carrying capacity because the limiting factors ensure that the population does not exceed the available resources and ecological limits of the environment. If the population surpasses the carrying capacity, the limiting factors will intensify, causing a decline in resources and an increase in mortality rates, which ultimately brings the population back towards the carrying capacity.It's important to note that the relationship between population size, carrying capacity, and limiting factors is dynamic and can vary depending on various ecological and environmental factors.

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We can see here that the catalytic cycle for the hydrogenation of alkenes using Wilkinson's catalyst involves several steps.

Here's an overview of the catalytic cycle, including the necessary details:

i. Chemical structure of the catalyst:

Wilkinson's catalyst, also known as chloridotris(triphenylphosphine)rhodium(I), has the following chemical structure: [RhCl(PPh3)3]

ii. Molecular geometry of the catalyst:

The Wilkinson's catalyst has a trigonal bipyramidal geometry around the rhodium center. The three triphenylphosphine (PPh3) ligands occupy equatorial positions, while the chloride (Cl) ligand occupies an axial position.

iii. Type of reactions involved:

The catalytic cycle involves several reactions, including:

iv. Starting material, reagent, and solvent:

The starting material is an alkene, and the reagent is Wilkinson's catalyst ([RhCl(PPh3)3]). The reaction is typically carried out in a suitable solvent, such as dichloromethane (CH2Cl2) or tetrahydrofuran (THF).

v. Major and minor end-products:

The major end-product of the hydrogenation reaction is the fully saturated alkane, resulting from the addition of hydrogen across the double bond. The minor end-product may include cis- or trans-configured alkanes if the original alkene substrate possesses geometric isomers.

vi. Intermediates:

The intermediates in the catalytic cycle include:

These intermediates play a crucial role in facilitating the hydrogenation reaction and enabling the catalytic cycle to proceed.

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Taking into account the definition of pH and pOH, the [H⁺] is 3.16×10⁻⁵ M and the solution will be acid.

First of all, pH is a measure of acidity or alkalinity that indicates the amount of hydrogen ions present in a solution or substance.

The pH is defined as the negative base 10 logarithm of the activity of hydrogen ions, that is, the concentration of hydrogen ions or H₃O⁺:

pH= - log [H⁺]= - log [H₃O⁺]

Similarly, pOH is a measure of hydroxyl ions in a solution and is expressed as the logarithm of the concentration of OH⁻ ions, with the sign changed:

pOH= - log [OH⁻]

The following relationship can be established between pH and pOH:

pH + pOH= 14

In this case, being pOH= 9.50, pH is calculated as:

pH + 9.40= 14

pH= 14 - 9.50

pH= 4.50

Replacing in the definition of pH the concentration of H⁺ ions is obtained:

- log [H⁺]= 4.50

Solving :

[H⁺]= 10⁻⁴ ⁵

[H⁺]= 3.16×10⁻⁵ M

The numerical scale that measures the pH of the substances includes the numbers from 0 to 14, being acidic solutions with a pH lower than 7, and basic those with a pH greater than 7. The pH = 7 indicates the neutrality of the solution.

In this case, the pH has a value of 4.50. So, the solution is acidic.

In summary, the [H⁺] is 3.16×10⁻⁵ M and the solution will be acid.  

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Heat is added to ice at 0 °C. Explain why the temperature of the ice does not change. What does change?When heat is added to ice at 0°C, the temperature of the ice does not change. This happens because all the heat energy is used up in overcoming the intermolecular forces of attraction (hydrogen bonds) that exist between the water molecules in ice.

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i)  Absolute dating method is used to measure absolute age of a rock using  radioactive decay of isotope.

ii) The working of this Absolute dating was discussed below:

By monitoring the radioactive decay of isotopes or the effects of radiation on the crystal structure of minerals, absolute dating techniques estimate the amount of time since rocks first formed. To help establish the age of rocks, paleomagnetism measures the ancient orientation of the Earth's magnetic field.

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Complete question:

To determining the absolute age of a rock, scientists measure the radioactive decay of isotope

i) What is name of this method?

ii) How this method works?

Answer: D

Explanation:

I took the test

Answer:

\([base]=0.28M\)

Explanation:

Hello,

In this case, by using the Henderson-Hasselbach equation one can compute the concentration of acetate, which acts as the base, as shown below:

\(pH=pKa+log(\frac{[base]}{[acid]} )\\\\\frac{[base]}{[acid]}=10^{pH-pKa}\\\\\frac{[base]}{[acid]}=10^{4.9-4.76}\\\\\frac{[base]}{[acid]}=1.38\\\\\)

\([base]=1.38[acid]=1.38*0.20M=0.28M\)

Regards.

The first step to solve this question is to balance the given equation. To do it, make sure that the amount of every element is equal in both, reactants and products.

Now, use the stoichiometric ratio between the coefficients of potassium oxide and potassium nitride:

The answer is 4.66moles of magnessium nitride.

After the reaction is complete, no nitrogen and no hydrogen molecules remain, and 8.00 x 1014 molecules of NH3 are produced.

In the equation, nitrogen and hydrogen react at a high temperature, in the presence of a catalyst, to produce ammonia, according to the balanced chemical equation:N2(g)+3H2(g)⟶2NH3(g)The coefficients of each molecule suggest that one molecule of nitrogen reacts with three molecules of hydrogen to create two molecules of ammonia.

So, to determine how many molecules of ammonia are produced when four nitrogen and nine hydrogen molecules are present, we must first determine which of the two reactants is the limiting reactant.

To find the limiting reactant, the number of moles of each reactant present in the equation must be determined.

Calculations:
Nitrogen (N2) molecules = 4Hence, the number of moles of N2 = 4/6.02 x 1023 mol-1 = 6.64 x 10-24 mol
Hydrogen (H2) molecules = 9Hence, the number of moles of H2 = 9/6.02 x 1023 mol-1 = 1.50 x 10-23 mol

Now we have to calculate the number of moles of NH3 produced when the number of moles of nitrogen and hydrogen are known, i.e., mole ratio of N2 and H2 is 1:3.

The mole ratio of N2 to NH3 is 1:2; thus, for every 1 mole of N2 consumed, 2 moles of NH3 are produced.
The mole ratio of H2 to NH3 is 3:2; thus, for every 3 moles of H2 consumed, 2 moles of NH3 are produced.
From these mole ratios, it can be observed that the limiting reactant is nitrogen.

Calculation for NH3 production:
Nitrogen (N2) moles = 6.64 x 10-24 moles
The mole ratio of N2 to NH3 is 1:2; therefore, moles of NH3 produced is 2 × 6.64 × 10−24 = 1.33 × 10−23 moles.

Now, to determine how many molecules of NH3 are produced, we need to convert moles to molecules.
1 mole = 6.02 x 1023 molecules
Thus, 1.33 x 10-23 moles of NH3 = 8.00 x 1014 molecules of NH3 produced.

To find the amount of each reactant remaining after the reaction is complete, we must first determine how many moles of nitrogen are consumed, then how many moles of hydrogen are consumed, and then subtract these from the initial number of moles of each reactant.

The moles of nitrogen consumed = 4 moles × 1 mole/1 mole N2 × 2 mole NH3/1 mole N2 = 8 moles NH3
The moles of hydrogen consumed = 9 moles × 2 mole NH3/3 mole H2 × 2 mole NH3/1 mole N2 = 4 moles NH3
Thus, the moles of nitrogen remaining = 6.64 × 10−24 mol – 8 × 2/3 × 6.02 × 10^23 mol-1 = 5.06 × 10−24 mol
The moles of hydrogen remaining = 1.50 × 10−23 mol – 4 × 2/3 × 6.02 × 10^23 mol-1 = 8.77 × 10−24 mol

Finally, the number of molecules of each reactant remaining can be calculated as follows:
Number of N2 molecules remaining = 5.06 × 10−24 mol × 6.02 × 10^23 molecules/mol = 3.05 × 10−1 molecules ≈ 0 molecules
Number of H2 molecules remaining = 8.77 × 10−24 mol × 6.02 × 10^23 molecules/mol = 5.28 × 10−1 molecules ≈ 0 molecules.

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The chemical formula has been defined as the representation of the chemical symbols along with the coefficient and proportions. The chemical formula of the unknown compound X is Al₂O₃.

The chemical formula has been the representation of the relative numbers of the elemental atoms involved in the chemical substance that makes the molecule and the compound. The chemical formula of the unknown substance can be calculated from the number of moles.

The moles of the atom or the element represent the proportions of the atom involved in the various elements in the substance. The chemical formula is represented by letters, coefficients, subscripts, superscripts, parentheses, signs, etc.

Given,

Moles of compound X = 1 mol

Moles of Al element = 2 mol

Moles of O element = 3 mol

So the chemical formula of the unknown compound X will be Al₂O₃ as there are two moles of aluminum and three moles of oxygen in the compound.

Therefore, Al₂O₃ is the chemical formula of the unknown compound X.

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The grams solutes ini 835 mL of 0.390 M KBr is 38.75 g.

The grams can be calculated as follows:

The first you should calculate the molar

Times the molar of KBr by its valume to get moles

n = Molar x volume

n = 0.390 M x 0.835L

n = 0.32565 moles

thus, you should calculate molar mass so you can calculate the gram

Mass of potasium = 39.10 g/mol

Mass of Bromine = 79.904 g/mol

mass molar = 39.1 g/mol+79.9 g/mol = 119 g/mol

The next step is calculate the gram by time the moles to  its mass molar

gram = n x mass molar

gram = 0.32565 moles x 119 g/mol= 38.75 g.

so, The grams solutes ini 835 mL of 0.390 M KBr is 38.75 g.

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The mass of the asteroid is C. 1.2 x \(10^{12}\) Kg

To find the mass of the other asteroid, we can rearrange the equation for the gravitational force between two objects:

F = (G * m1 * m2) / \(r^{2}\)

where F is the force of gravity, G is the gravitational constant, m1 and m2 are the masses of the two asteroids, and r is the distance between them.

Given that the distance between the asteroids is 75000 m, the force of gravity between them is 1.14 N, and one asteroid has a mass of 8 x \(10^{7}\) kg, we can substitute these values into the equation and solve for the mass of the other asteroid (m2):

1.14 N = (6.67430 × \(10^{-11}\) N \(m^{2}\)/\(Kg^{2}\) * 8 x \(10^{7}\) kg * \(m2\)) / \((75000 m)^{2}\)

Simplifying and solving the equation, we find that the mass of the other asteroid (m2) is approximately 1.2 x \(10^{12}\) kg. Therefore, Option C is correct.

The question was incomplete. find the full content below:

Two asteroids are 75000 m apart one has a mass of 8 x \(10^{7}\) kg if the force of gravity between them is 1.14 what is the mass of the asteroid

A. 3.4 x \(10^{11}\) kg

B. 8.3 x \(10^{12}\) kg

C. 1.2 x \(10^{12}\) kg

D. 1.2 x \(10^{10}\) kg

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The molar mass in grams of "one mole" of each substance is:

Fe: 55.845 g/mol

\(Cl_2\): 70.906 g/mol

\(FeCl_3\): 162.204 g/mol

To calculate the molar mass in grams of "one mole" of each substance, we need to determine the atomic masses of the elements involved in the equation.

The atomic mass of iron (Fe) is 55.845 g/mol.

For chlorine (\(Cl_2\)), we need to consider that the molar mass of \(Cl_2\) is twice the atomic mass of chlorine because the formula shows that two chlorine atoms combine to form one molecule of \(Cl_2\). The atomic mass of chlorine is 35.453 g/mol, so the molar mass of \(Cl_2\) is 2 * 35.453 g/mol = 70.906 g/mol.

The formula for iron(III) chloride (\(FeCl_3\)) indicates that one mole of \(FeCl_3\)contains one mole of iron and three moles of chlorine. Therefore, we can calculate the molar mass of \(FeCl_3\)by summing the atomic masses of iron and chlorine:

Molar mass of \(FeCl_3\)= (1 * atomic mass of Fe) + (3 * atomic mass of Cl)

Substituting the values, we have:

Molar mass of \(FeCl_3\) = (1 * 55.845 g/mol) + (3 * 35.453 g/mol)

= 55.845 g/mol + 106.359 g/mol

= 162.204 g/mol

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