Select all ions that are produced when KCl is dissolved in water

Cl+

K-

Cl-

K+

Answer: The molarity of solution is 3.37 M

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

\(Molarity=\frac{n\times 1000}{V_s}\)

where,

n = moles of solute = 0.614  

\(V_s\) = volume of solution in ml = 182 ml

Now put all the given values in the formula of molarity, we get

\(Molarity=\frac{0.614\times 1000}{182}=3.37M\)

Therefore, the molarity of solution is 3.37 M

1,640.  The number is rounded up because the digit in the tenths place is 8, which is greater than or equal to 5.

Rounding off is a mathematical process of replacing a number with an approximate value that has a shorter, simpler, or more explicit representation. It is often done to reduce the number of significant figures in a calculation or to make calculations easier. Rounding off is used in many everyday situations, such as calculating a restaurant bill or estimating the amount of paint needed to paint a room. It is also used in more complex calculations, such as in scientific and engineering calculations.

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Answer:

53.29%oxygen

Explanation:

math and stuff

Answer:

low precision, high accuracy

Explanation:

not all the arrows are hitting the bullseye (low precision) but they are getting very close the the bullseye (high accuracy)

The archer's results can be described as low precision and high accuracy. Therefore, option (B) is correct.

Target archery is a form of archery, in which archers shoot at stationary circular targets at specific distances.

Standard targets are marked with 10 concentric rings that have score values from 1 through 10 except in outdoor Imperial rounds under AGB rules have score values 1, 3, 5, 7 and 9. There is an inner 10 ring called the X ring.

Archers shoot up to 90 metres. Although the standard competition distances are 70 metres and 50 metres. They are usually consisting of 10 scoring zones and gold, red, blue, black and white coloured rings.

Modern archery is used at the Olympic Games, Paralympic Games, and, for competitions, at the World Games and major international events.

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The products of the acid-base reaction between chloric acid \((HClO_{3})\), and lithium hydroxide \((LiOH)\), are water \((H_{2}O)\) and lithium chlorate \((LiClO_{3} )\)

An acid-base reaction is a chemical reaction that occurs between an acid and a base producing salt and water. It is a double-replacement reaction where ions exchange their positions.

The general equation of an acid-base reaction is as follows.

Acid + Base → Salt + Water

The H(+) cation of the acid combines with the OH(-) anion of the base to form water. The compound formed by the cation of the base and the anion of the acid is called a salt.

For the reaction between chloric acid \((HClO_{3})\), and lithium hydroxide \((LiOH)\), the H(+) cation of the acid \((HClO_{3})\) combines with the OH(-) anion of the base \((LiOH)\) to form water. The compound formed by the cation of the base \((LiOH)\) and the anion of the acid \((HClO_{3})\) is lithium chlorate.

\(H^{+}+ ClO_{3}^{-} +Li^{+} +OH^{-} = LiClO_{3} + H_{2}O\)

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Answer:

The electronic configuration of ions formed are:

Li+ (2) => 1s2

Cl- (18) => 1s2 2s2 2p6 3s2 3p6

Explanation:

Lithium metal, Li will lose 1 electron to lithium ion Li+. Chlorine atom, Cl will receive the 1 electron to form the chloride ion Cl- as shown by the following equation below:

Li —> Li+ + e

Cl+ e —> Cl-

Combine both equation

Li + Cl + e —> Li+ + Cl- + e

Cancel out 'e'

Li + Cl —> Li+ Cl-

Thus, we can write the electronic configuration for the reaction as follow:

Before reaction:

Li (3) => 1s2 2s1

Cl (17) => 1s2 2s2 2p6 3s2 3p5

After reaction

Li+ (2) => 1s2

Cl- (18) => 1s2 2s2 2p6 3s2 3p6

Therefore, the electronic configuration of the ions formed are:

Li+ (2) => 1s2

Cl- (18) => 1s2 2s2 2p6 3s2 3p6

Answer:

Explanation:

C

Answer:

The pattern of change in the electron configuration increases from left to right across the period.

Explanation:

In the periodic table, elements having the same number of electrons in the outermost shell of their atoms are placed over one another in vertical columns. Each of the vertical columns is known as a group or family. while each of the resulting horizontal rows is known as a period or row.

There are 18 vertical columns and seven periods in the periodic table. Each period begins with an atom having a valence electron and ends with an atom having a complete outer shell structure of an inert gas.

The fourth period of the periodic table (d-block) consists of the transition elements.

The electron distribution into the energy levels of sublevels of atoms  can be shown in any of the tree important electronic configuration.

Electronic configuration shows the sequence of filling electrons into the orbitals of the sublevels as guided by some principles.

The maximum number of electrons in the orbitals of sublevels are two for s-sublevel(one orbital) ; six for p-sublevel( three orbital); ten for d-sublevel ( five orbitals) and fourteen for f-sublevel( seven orbitals). This indicates that the maximum number of electrons in an orbital is two

In the Periodic table ,The sublevels with lower energies are filled  up before those with higher energies. One important thing about this principle is that the sublevels do not fill up in numerical order. The pattern of filling is as follows:

1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f etc.

Answer:

In the electron configuration of potassium, I observe that after the 3p orbital is filled, the next electron enters the 4s orbital instead of the 3d orbital because 3d is at a higher energy than 4s. This pattern shows that orbitals fill up according to the Aufbau principle. As I move on right, the number of electrons increases by one for each element until vanadium is reached. The electron configuration of chromium shows all Half-filled orbitals in the 4s and 3d energy levels. Again, as I move right, an exception occurs at copper. Copper’s electron configuration shows completely filled 4s and 3d orbitals. This is an exception to the Aufbau principle to attain more stable electron configurations, whenever possible. Half-filled electron configurations are more stable than other configurations and completely filled electron configurations are the most stable.

Answer:

The atomic number or proton number (symbol Z) of a chemical element is the number of protons found in the nucleus of every atom of that element. The atomic number uniquely identifies a chemical element. ... The sum of the atomic number Z and the number of neutrons N gives the mass number A of an atom.

Answer:

Atoms of each element contain a characteristic number of protons. In fact, the number of protons determines what atom we are looking at (e.g., all atoms with six protons are carbon atoms); the number of protons in an atom is called the atomic number.

Explanation:

Its Hunting
A wolf is taught to hunt

In the presence of water, ionic and hydrogen bonds can be disrupted.

Water is a polar molecule, meaning it has a partial positive charge on one end and a partial negative charge on the other end.

This polarity allows water to interact with other polar molecules, including ionic compounds and molecules containing hydrogen bonds.

Ionic compounds are held together by strong electrostatic forces between positively and negatively charged ions.

In the presence of water, the partial charges on the water molecule can attract and surround the ions, weakening the electrostatic forces and causing the ionic compound to dissociate into its component ions.This is why ionic compounds dissolve readily in water.

Hydrogen bonds are a type of intermolecular force that forms between a hydrogen atom bonded to an electronegative atom and another electronegative atom in a different molecule.

Water molecules can form hydrogen bonds with other polar molecules, and in the presence of water, these hydrogen bonds can be disrupted as water molecules compete for hydrogen bonding partners. This can affect the solubility and reactivity of molecules containing hydrogen bonds.

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The amount, in grams, of radon that will be collected in the office sample of air, would be 148.8 grams.

The air sample contains 3.20 x 10⁻⁴ mg of radon per mL of gas. A total air volume of 4.65 x 10⁴ L passed through the office. The amount of radon in the air that passed through the office can be estimated as follow:

Amount of radon per mL of gas = 3.20 x 10⁻⁴ mg

Total volume of air in sample = 4.65 x 10⁴ L

The total air volume needs to be converted to mL:

4.65 x 10⁴ L x 1000 = 4.65 x \(10^7\) mL

1 mL = 3.20 x 10⁻⁴ mg

4.65 x \(10^7\) mL = 4.65 x \(10^7\) x 3.20 x 10⁻⁴

                       = 14.88 x \(10^4\) mg

In other words, the total amount of radon gas in the sample of air is 14.88 x \(10^4\) mg.

1 g = 0.001 mg

14.88 x \(10^4\) mg = 14.88 x \(10^4\)/1000

                        = 148.8 grams

In summary, the total amount of radon gas that will be collected in the office sample would be 148.8 grams.

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Answer:

Iron slowly reacts with oxygen and forms rust. In this case, the reactants are iron and oxygen. The product is rust, or iron oxide. The chemical equation looks like this:

Explanation:

iron + oxygen → iron oxide

Answer:

Iron slowly reacts with oxygen and forms rust. In this case, the reactants are iron and oxygen. The product is rust, or iron oxide. The chemical equation looks like this:

iron + oxygen → iron oxide

Explanation:

This was the answer straight from Plato. I hope that this helped you, please mark me the brainiest, like and rate my answer if it did! :)

The free energy change, ΔG, is approximately -0.0198 kJ/mol to one decimal place.

To calculate the free energy change, ΔG, we can use the equation:

ΔG = -RT ln(K)

where ΔG is the change in Gibbs free energy, R is the gas constant (8.314 J/mol·K), T is the temperature in Kelvin, and K is the equilibrium constant.

In this case, we are given the partial pressures of CH3OH, P(CH3OH) = 110.0 mmHg and P(CH3OH) = 14.00 mmHg, respectively.

First, we need to calculate the equilibrium constant, K, using the ratio of the partial pressures:

K = P(CH3OH) / P(CH3OH)

K = (110.0 mmHg) / (14.00 mmHg)

K ≈ 7.857

Next, we need to convert the pressure from mmHg to atm because the gas constant R is expressed in J/mol·K, which is based on the unit of atm:

1 atm = 760 mmHg

So, P(CH3OH) = 110.0 mmHg = 110.0 mmHg / 760 mmHg/atm ≈ 0.145 atm

P(CH3OH) = 14.00 mmHg = 14.00 mmHg / 760 mmHg/atm ≈ 0.0184 atm

Now we have the equilibrium constant, K, and the pressures in atm. We can proceed to calculate the free energy change, ΔG:

ΔG = -RT ln(K)

Let's assume the temperature, T, is given as 298 K:

ΔG = -(8.314 J/mol·K) * (298 K) * ln(7.857)

ΔG ≈ -19.78 J/mol

To convert the free energy change from joules to kilojoules, we divide by 1000:

ΔG ≈ -0.0198 kJ/mol

It's important to note that the free energy change depends on the temperature and the equilibrium constant of the reaction. If the temperature or the equilibrium constant changes, the calculated value of ΔG will also change.

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Answer:

no ,its not necessary tht two objects have same volume have the same mass because the density of the material they are made up of can be different. mass and volume areindependent, two objects with thesame volume can have differentmasses. Therefore, the objects can have different densities.

Answer:

B holding together molecules in a material

Explanation:

Intermolecular forces are primarily responsible for holding together molecules in a material due to the fact that they are interactive forces between molecules

The volume of the substance with mass of 54mg and density of 1.2g/mL will be 0.045 mL.

How much "stuff" is contained in a specific quantity of space is determined by its density. For instance, a block of the harder, lighter element gold (Au) will be denser than a block of the heavier element lead (Pb) (Au). Styrofoam blocks are less dense than bricks.

Mass per unit volume serves as its definition.

We know that, Density = mass of substance / volume of substance

Given,

mass = 54 mg = 0.054 g

Density = 1.2g/mL

D = m/ v

1.2 = 0.054 / v

1.2 × v = 0.054

v = 0.054 / 1.2

v = 0.045 mL

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The molarity of a solution prepared by diluting 40.0 ml of 0.0706 m ammonium sulfate to 500.00 ml is

Molarity of solution = M₁

Molarity of Ammonium sulfate (M₂) = 0.0706 m

Volume of Solution (V₁) = 40.0 ml

Volume of ammonium sulfate (V₂) = 500.00 ml

According to Dilution formula - M₁V₁=M₂V₂

M₁ = M₂V₂/V₁

M₁ = 0.0706 m × 500 × 10⁻³ L/ 40× 10⁻³ L

M₁ = 0.8825 m

Molarity is defined as number of moles of solute in 1 litre of solution. It is used to measure concentration of a solution. It is also called amount concentration, molar concentration or substance concentration.

Concentration of solution can also be measured using molality, normality etc.

Units: Moles/ litre

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The heat evolved or absorbed in an open system, where reactants and products are constantly in contact with their environment and there is constant pressure, is equivalent to the change in enthalpy.

Under conditions of constant pressure, the change in enthalpy of the reacting species equals the amount of heat evolved or absorbed in a chemical reaction. This is referred to as the reaction's enthalpy change (H). A thermodynamic property called enthalpy (H) denotes a system's overall heat capacity. The difference between the enthalpy of the products and the reactants determines the change in enthalpy of a reaction. The heat evolved or absorbed in an open system, where reactants and products are constantly in contact with the environment and there is constant pressure, is equivalent to the change in enthalpy (H), because the heat is being exchanged with the environment. The name of this law is Hess's Law.

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The correct increasing order of solubility for the given gases is: NH₃ < N₂ < CO₂

A chemical's solubility is the maximum amount of that substance that will dissolve in a specific amount of solvent at a specific temperature. Solubility has several practical applications, including water filtering, beverage manufacturing, and vitamin storage.

The ability of a medicine to dissolve is essential to its effectiveness. A drug substance could be absorbed without it, which results in limited bioavailability. Drugs with poor solubility can potentially cause problems with metabolism or permeability, interaction with other medications, or the requirement for prolonged drug release.

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Answer:

50%, pups haven't solidfur

2. DOMINANT FF IS NOT POSSIBLE

False, frogs cannot see in all directions.

The sample of water containing 0.004 ml of oxygen in 2000 ml of water is equivalent to 2× 10⁻⁴ volume percentage of the solution.

Volume percentage of an aqueous solution is the ratio of the  volume of the dissolved substance to the total volume of the solution. Volume percentage is thus, used to express the concentration of the solution in terms of its volume.

The other terms used to express the concentration of a solution are molarity, normality, mass percentage, ppm etc.

Given the total  volume of the water sample = 2000 ml

volume of oxygen dissolved in water = 0.004 ml

volume percentage = volume of oxygen / total volume ×100

                                 = 0.004 /2000 ×100 = 2× 10⁻⁴

Therefore, 2000 ml water sample containing 0.004 ml of sample is equivalent to 2× 10⁻⁴ volume percentage.

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The separation of hemoglobin A (HbA) and hemoglobin S (HbS) in part b of today's experiment is based on their differences in charge, size, and affinity for an ion exchange resin.

The ion exchange resin used in the experiment is negatively charged and attracts positively charged molecules. HbA and HbS both have positive charges, but their surface charges are slightly different due to differences in their amino acid sequences. HbA has a net negative charge, whereas HbS has a net positive charge.

When a mixture of HbA and HbS is passed through the column containing the ion exchange resin, HbA, with its net negative charge, binds less strongly to the resin and is eluted first. HbS, with its net positive charge, binds more strongly to the resin and is eluted later.

The size of the molecules can also play a role in the separation, with smaller molecules having a faster elution time than larger molecules. However, in this case, the charge differences are the main factor contributing to the separation.

Overall, the separation of HbA and HbS in part b of the experiment is based on their differences in charge, which allows for selective binding to an ion exchange resin, leading to their separation.

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Answer:

\(\boxed {\boxed {\sf 4 \ g/cm^3}}\)

Explanation:

We are asked to find the density of a brick. Density is a substance's mass per unit volume. The formula for calculating density is as follows.

\(\rho= \frac{m}{v}\)

The mass of the brick is 100 grams and the volume is 25 cubic centimeters.

Substitute the values into the formula.

\(\rho= \frac{ 100 \ g}{25 \ cm^3}\)

Divide.

\(\rho=4 \ g/cm^3\)

The density of the brick is 4 grams per cubic centimeter.

Answer:

Hmm 65

Explanation: