Answer:
C. Nonrenewable, renewable
Hope this helps!
The pressure at the top of Mount Everest is 0.31×105N/m2, and the temperature is −30∘C. The pressure at sea level is 1.0×105N/m2, and the temperature is 20∘C.
Determine how much more frequently you need to breathe on top of Mount Everest to inhale the same amount of oxygen as you do at sea level.
________ times more frequently.
It takes 2.7 times approximately to breath frequently on top of Mount Everest as you do at sea level.
What is Pressure ?Pressure is force per unit area. Pressure in fluid is the product of fluid density, acceleration due to gravity and the height. Pressure is measured in N/m²
Given that the pressure at the top of Mount Everest is 0.31×105N/m2, and the temperature is −30∘C.
From Ideal gas law, PV = nRT
Where
P = 31000 N/m²
T = - 30 + 273 = 243 K
n/V = ?
R = 8.314 1/K/Mol
n/V = P / RT
n/V = 31000 / (8.314 × 243)
n/V = 31000 / 2020.302
n/V = 15.34
When the pressure at sea level is 1.0×105N/m2, and the temperature is 20∘C, then
T = 20 + 273 = 293 K
n/V = 100000 / (8.314 × 293)
n/V = 100000 / 2436.002
n/V = 41.05
To determine how much more frequently you need to breathe on top of Mount Everest to inhale the same amount of oxygen as you do at sea level, you divide the two values. That is,
41.05 / 15.34 = 2.67
Therefore, it takes 2.7 times approximately to breath frequently on top of Mount Everest as you do at sea level.
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The food pyramid shows the proportions of foods that should be eaten for good health. The foods at the base of the pyramid should be eaten more, and those at the peak of the pyramid should be eaten less. Write down everything you eat in one day. Then compare the foods you ate to the foods shown in the pyramid. How was your diet different? How was it similar? Did you eat many foods not shown? Once you have completed your log and answered the questions, turn it in to your teacher here. To see how your assignment will be graded, Information is very organized with well‐constructed paragraphs and subheadings. Amount of Information (3) All topics are addressed and all questions answered with at least 2 sentences about each. Quality of Information (3) Information clearly relates to the main topic. It includes several supporting details and/or examples.
Comparing my diet to the food pyramid, I can see that my diet is similar in some ways and different in others.
How to explain the informationFor breakfast, I had a bowl of oatmeal with almonds, blueberries, and a drizzle of honey. For lunch, I had a turkey sandwich with lettuce, tomato, and avocado on whole wheat bread. I also had a side of carrot sticks and hummus. For dinner, I had grilled salmon with roasted sweet potatoes and broccoli. For snacks throughout the day, I had an apple, a handful of grapes, and a small serving of dark chocolate.
Comparing my diet to the food pyramid, I can see that my diet is similar in some ways and different in others. For example, my breakfast of oatmeal with blueberries is a good source of whole grains and fruits, which are both recommended in the food pyramid. Similarly, my lunch of turkey sandwich on whole wheat bread with vegetables provides a good balance of protein, whole grains, and vegetables. My snack of fruit, such as apples and grapes, is also recommended in the food pyramid as a healthy option for snacking.
However, there are also some differences in my diet compared to the food pyramid. For instance, my diet did not include any dairy products or legumes, which are both recommended in the food pyramid. Additionally, my dinner did not include any grains, which are also recommended in the food pyramid. Instead, I had sweet potatoes, which are a good source of complex carbohydrates.
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What is the magnetic force on a 240 mm length of wire stretched between two towers carrying a 150 A current given that the earth’s magnetic field is 5×10-5T and makes an angle of 60o with the wire?
We will have the following:
First, we recall that:
\(F=IBlsin(\theta)\)Now, from the information provided we will have that:
length = 0.24m
Current = 150A
Magnetic field = 5*10^-5T
Angle = 60°
So:
\(\begin{gathered} F=(150A)(5\ast10^{-5}T)(0.24m)sin(60)\Rightarrow F=1.558845727\ast10^{-3}N \\ \\ \Rightarrow F\approx1.56\ast10^{-3}N \end{gathered}\)So, the force is approximately 1.56*10^-3 N.
***Explanation***
We know that the magnetic force is given by the expression:
\(F=IBlsin(\theta)\)Here "I" is the current flowing, "B" is the magnetic field, "l" is the length of the wire in meters and theta is the angle of the magnetic field with respect to the wire.
When we replace the values we obtain the force of the magnetic field.
The Moon has a smaller mass than the Earth. If you were to travel to the moon your weight would....
A Increase
B Decrease
C Stay the Same
D Vary with day and night
Answer:The Moon has a smaller mass than the Earth. If you were to travel to the moon your weight would..
Explanation: It would decrease.
The Moon has a smaller mass than the Earth. If you were to travel to the moon your weight would decrease because the acceleration due by gravity on the moon is less than the acceleration due to gravity on the earth, therefore the correct answer is option C.
What is gravity?It can be defined as the force by which a body attracts another body towards its center as the result of the gravitational pull of one body and another.
In comparison to the Earth, the Moon is less massive. Your weight would drop if you traveled to the moon because the acceleration caused by gravity there is lower than that caused by gravity here on Earth.
As a result of the less gravity on the moon, the weight would decrease.
Thus, the correct answer is option C.
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A 70 kilogram hockey player skating east on an ice rink is hit by a 0.1 kilogram hockey puck moving toward the west. The puck exerts a 50 newton force toward the west on the player. Determine the magnitude of the force that the player exerts on the puck during this collision
Given:
70 Kilogram hockey
Hit by 0.1 kilogram
50 Newton
Description:
So in this case this bacially means that one object is experiencing a force then another object. So the answer to the question will be 50N.
Answer: 50N (3rd Law)
Hope this helps.
what do we call the games that involve different manipulation skills like throwing,tossing,rolling,catching,running,jumping,hopping and stretching what is the answer A.puzzle game B.simulation games C.target games D.role-playing games
Please help, it's a question on Elasticity!
A wire can support a load W without breaking. It is cut in to two equal parts. The maximum load that each part can support is
(1) W/4
(2)W/2
(3) W
(4) 2W
(5) 4W
A wire is capable of carrying a load W without snapping. It is divided in half, equally. Each component's maximum load capacity is W.
The maximum load supported by the cable is directly proportional to the breaking stress.
Since,
Breaking stress=F/A
where F is the force and A is the cross-sectional area
As we see that the breaking stress is independent of the length of the cable. So, if the cable is cut in two equal parts, the maximum load that can be supported by either part of the cable remains the same as before.
So, the answer would be W.
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g According to the Third Law, the action and reaction forces are exactly equal in magnitude and in opposite directions. So when a horse pulls a cart, the cart pulls the horse with the same force. Why then does the cart move
Answer:
One way to look at this is to consider the forces acting on any point in a string.
For a very small portion of string F = M a must still hold. As M approaches zero the small portion of string would have to approach infinite acceleration if the net force on that portion of string were not zero.
One generally considers the net force acting on the center of mass of an object not the individual forces acting on each infinitesimal mass composing
the object.
1. At what displacement the kinetic energy and potential energy of a particle executing SHM will be equal when the amplitude is 3cm?
The displacement at which the kinetic energy and potential energy of a particle executing SHM will be equal when the amplitude is 3cm is 1.5cm.
How does the amplitude of simple harmonic motion affect the ratio of kinetic to potential energy at a specific displacement?The amplitude of simple harmonic motion affects the ratio of kinetic to potential energy at a specific displacement in the following way: as the amplitude increases, the ratio of kinetic to potential energy decreases. This is because the amplitude represents the maximum displacement from the equilibrium position, and as the amplitude increases, the potential energy of the particle increases, while the kinetic energy remains constant. Therefore, at a specific displacement, a particle with a larger amplitude will have a greater proportion of its energy in the form of potential energy, while a particle with a smaller amplitude will have a greater proportion of its energy in the form of kinetic energy.
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When an object falls, its:
A. PE increases and KE decreases.
B. PE does not change.
C. PE and KE both increase.
D. PE decreases and kE increases
Answer:
Option D. is correct.
Explanation:
The object's mechanical energy refers to the sum of the potential and kinetic energies of the object. When an object falls, its potential energy (PE) decreases, and its kinetic energy (KE) increases. The increase in kinetic energy is exactly equal to the decrease in potential energy.
Option D. is correct.
2.
A ball player hits a home run, and the ball just clears the wall which is 22.0 m high.
The ball is hit at an angle of 37.0" with a velocity of 45.0 m/s. If the ball is hit from
a height of 0.750 m above the ground, (a) How long is the ball in the air until it
clears the wall while on its way down? (b) How far is the wall from home plate?
a.) the ball was going up at 0.95 seconds and coming down at 4.58 seconds
b.) the distance of the wall from the plate is 34 m
Given that a ball player hits a home run, and the ball just clears the wall which is 22.0 m high. The ball is hit at an angle of 37.0" with a velocity of 45.0 m/s.
Since the ball is hit at an angle of 37.0 degrees, We need to find the vertical and horizontal component of the velocity.
\(U_{y}\) = 45 Sin 37 = 27.08 m/s
\(U_{x}\) = 45 cos 37 = 35. 94 m/s
Let us first calculate the maximum height reached.
\(V^{2}\) = \(U_{y} ^{2}\) - 2gH
At maximum height, V = 0
0 = \(27.08^{2}\) - 2 x 9.8H
19.6H = 733.3
H = 733.33/19.6
H = 37.4 m
If the ball is hit from a height of 0.750 m above the ground,
(a) To calculate the time the ball stays in the air until it clears the wall while on its way down, we will use the formula below.
h = \(U_{y}\)t - 1/2g\(t^{2}\)
Substitute for all the parameters
22 - 0.75 = 27.08t - 0.5 x 9.8 x \(t^{2}\)
21.25 = 27.08t - 4.9\(t^{2}\)
4.9\(t^{2}\) - 27.08t + 21.25
We will use quadratic formula
a = 4.9
b = - 27.08
c = 21.25
t = \(\frac{-b+/- \sqrt{b^{2} - 4ac } }{2a}\)
t = \(\frac{27.08 +/- \sqrt{27.08^{2} - 4 * 4.9 * x^{2} 21.25 } }{2 * 4.9}\)
t = \(\frac{27.08 +/-\sqrt{733.3 - 416.5} }{9.8}\)
t = \(\frac{27.08 +/- 17.8}{9.8}\)
t = 44.88/9.8 or 9.28 / 9.8
t = 4.58 s or 0.95 s
This means that the ball was going up at 0.95 seconds and coming down at 4.58 seconds
(b) The distance of the wall from home plate will be the range which is
R = \(U_{x}\)t
R = 35.94 x 0.95
R = 34.143 m
Therefore, the distance of the wall from the plate is 34 m approximately
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Children and parents spend less time together in middle childhood than in the preschool years.
a. True
Ob. False
E
C
A
Apr 30
Children and parents spend less time together in middle childhood than in the preschool years. Yes this true. Hence option A is correct.
Children are people who are between the ages of birth and puberty, or between the early years of development and puberty. It may also be a reference to a human embryo. The term "child" as used in law often refers to a minor, also known as a person under the age of majority. In general, children are subject to fewer rights and obligations than adults. They are considered incapable of making important judgements.
In their own species, a parent is someone who cares for their children. In humans, a parent is a child's primary carer. A individual whose gamete produced a child—a male through the sperm and a female through the ovum—is said to be the biological parent. First-degree relatives and sharing 50% genetic material are the biological parents.
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What is the correct definition of a resistor?
A) the difference in electric charge between two points
B) a substance capable of transmitting and creating an electric charge
C) a component that resists the flow of electricity
D) a device that allows electrical energy to flow through a complete path
When we experience positive "g forces", it is as if we have become...
Answer:
heavier
Explanation:
A 12-kg sled is lying on a hill with an incline of 21 degrees.
If the sled it not moving what must the coefficient of
static friction be (at least)?
The coefficeint of static friction, given that the 12 Kg sled is lying on the hill with an incline of 21 degrees is 0.38
How do I determine the coefficient of static friction?We know that the coefficient of static friction is related to frictional force according to the following formula:
Frictional force (N) = coefficient of friction (μ) × normal reaction (N)
F = μN
μ = F / N
For inclined plane, we have:
F = mgSineθ
N = mgCosθ
Thus,
μ = mgSineθ / mgCosθ
Recall
Sineθ / Cosθ = Tanθ
μ = Tanθ
Where
m is the mass of objectg is the acceleration due to gravityNow, we shall determine the coefficient of static friction as follow:
Mass of sled(m) = 12 KgAngle of inclination (θ) = 21 degreesCoefficient of static friction (μ) =?μ = Tanθ
μ = Tan21
μ = 0.38
Thus, the coefficient of static friction is 0.38
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What does the term theory mean in science
Answer:
It is like a hypothesis. It is an idea of something.
Explanation:
A theory is a set of accepted beliefs or organized principles that explain and guide analysis and one of the ways that theory is defined is that it is different from practice, when certain principles are tested. ... This word is a noun and comes from the Greek theoria, which means "contemplation or speculation."
WILL BE BRAINLIEST
HELP!!!
Answer:
(8.0÷6.0)×10[(-2)-(-3)]
A state trooper is traveling down the interstate at 20 m/s. He sees a speeder traveling at 50 m/s approaching from behind. At the moment the speeder passes the trooper, the trooper hits the gas and gives chase at a constant acceleration of 2.5 m/s^2.
Required:
a. Assuming that the speeder continues at 60 m/s , how long will it take the trooper to catch up to the speeder?
b. How far down the highway will the trooper travel before catching up to the speeder?
Answer:
Explanation:
From the given information;
Let assume that the distance travelled by the speeder prior to the time the trooper catches with it to be = d
the time interval to be = t
Then, the speeder speed = distance/time
Making distance the subject; then:
distance (d) = speed × time
d = (50 m/s)t
d = 50 t --- (1)
Now, for the trooper; Using the equation of motion:
\(d = ut + \dfrac{1}{2}at^2\)
\(d = (20)t+\dfrac{1}{2}(2.5)t^2\)
d = 20t + 1.25t²
Replace the value of d in (1) to the above equation, we have:
50 t = 20 t + 1.25t²
50t - 20t = 1.25t²
30t = 1.25t²
30 = 1.25t
\(t = \dfrac{30}{1.25}\)
t = 24 seconds
From (1), the distance far down the highway the trooper will travel prior to the time it catches up with the speeder is:
= 50t
= 50(24)
= 1200 seconds
For which of the following types of electromagnetic radiation will diffraction most likely occur as the wave passes through a classroom doorway? A) X-rays, because of their high energy. B) Visible light, because that type of electromagnetic radiation is most abundant. C) Radio waves, because of their wavelength. D) Diffraction will occur equally for all electromagnetic waves.
Option C, Because of the wavelength of radio waves and other forms of electromagnetic radiation, diffraction is most likely to occur as the wave travels through a classroom doorway.
Diffraction is the bending of waves around barriers or through apertures that are equivalent to or smaller than the wavelength of the wave.
Because radio waves have longer wavelengths than visible light and X-rays, they are more likely to diffract while passing through a similar-sized aperture, such as a classroom doorway.
Because X-rays have considerably shorter wavelengths and visible light has wavelengths in between, diffraction is less likely to occur in this scenario for these forms of electromagnetic energy. As a result, option C is the right answer.
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PLEASE ANSWER ASAP BEFORE MY TEACHER AND MY MOM KILLES ME PLEASE ASAP
The first person with the right answer gets to be a brainlest
In the attachment there is a density column where there is colour
Question: tell me why is the red at the bottom of the density column if it is the least dense
Answer:
As you know, the denser objects have more weight per unit of volume, this will mean that the force that pulls down these objects is a bit larger.
This will mean that the denser objects will always go to the bottom.
This clearly implies that the red liquid, the one with one of the smaller densities, can not be at the bottom.
There are some cases where a liquid with a small density may become a lot denser as the temperature or pressure changes, and in a case like that, we could see the red liquid at the bottom, but for this case, there is no mention of changes in the temperature nor in the pressure, so this can be discarded.
The only thing that makes sense is that the red part at the bottom is the base of the tube, and has nothing to do with the red liquid.
Which kind of bond forms ions?
Answer:
Ionic bond
Explanation:
Hope it helps ya
A boat, whose speed in still water is 1.75 m/s, must aim upstream at an angle of 26.3° (with respect to a line perpendicular to the shore) in order to travel directly across the stream.
(a) Determine the speed of the current.
(b) Determine the resultant speed of the boat with respect to the shore.
(a) should be 0.7775 m/s
(b) should be 1.57 m/s (i’m looking for the explanation)
A boat must aim upstream at an angle of 26.3° (with respect to a line perpendicular to the coast) with respect to a line should be 1.57 m/s for a boat moving at 1.75 m/s in still water.
How come a line is perpendicular?Perpendicular lines are two different lines that cross at a right angle of 90 degrees. Here, AB and XY connect at a 90-degree angle, making AB perpendicular to XY. The two lines do not intersect and run parallel to one another. They can't possible be compared side by side.
What is a perpendicular's form?A form is considered perpendicular if at least two of its sides are 90 degrees from one another. Shapes with perpendicular sides include the following: Square. Rectangle.
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7. [Honors] A turn of radius 100 m is being designed for a speed of 25 m/s. At what angle should the turn be banked?
Answer:
The angle at which a turn should be banked depends on the speed of the vehicle, the radius of the turn, and the acceleration due to gravity. To calculate the angle, we can use the following formula:
tanθ = v^2 / (g * r)
where
θ is the angle at which the turn should be banked (in radians)
v is the speed of the vehicle (in m/s)
g is the acceleration due to gravity (approximately 9.81 m/s^2)
r is the radius of the turn (in meters)
Plugging in the values given in the problem, we get:
tanθ = (25 m/s)^2 / (9.81 m/s^2 * 100 m)
tanθ = 6.44
Taking the inverse tangent of both sides, we get:
θ = tan^-1(6.44)
θ ≈ 80.5 degrees
Therefore, the turn should be banked at an angle of approximately 80.5 degrees.
the student applies a net force of 4.5 N to the 1.5 kg textbook.
Calculate the magnitude of the textbook's acceleration.
Answer:
3 m/s²
Explanation:
acceleration = Force / mass; 4.5/1.5 = 3
When a student applies a net force of 4.5 Newtons to the 1.5-kilogram textbook, then the magnitude of the acceleration would be 3 meters/second².
What is acceleration?The rate of change of the velocity with respect to time is known as the acceleration of the object. Generally, the unit of acceleration is considered as meter/seconds².
As given in the problem, when a student applies a net force of 4.5 Newtons to the 1.5-kilogram textbook, then we have to find the magnitude of the acceleration,
the applied force on the textbook = 4.5 Newtons
the mass of the textbook is 1.5 kilograms
acceleration of the textbook = force / mass
=4.5 Newtons /1.5 kilograms
=3 meters/second²
Thus, the magnitude of the acceleration would be 3 meters/second².
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Fig above shows a wave traveling through a medium. Use the fig to answer the questions below.
A.)What is the amplitude of the wave ? Include correct units.
B.)Use the graph to determine the time of one wave. Use it to find the frequency.
C.)If the speed of the wave is 25 m/s, what is the wavelength of the wave ? Show data listing, equation , substitution leading to the answer for full credit.
(a) The amplitude of the wave is 0.2 m.
(b) The period of the wave is 4 s.
(c) The wavelength of the wave is 100 m.
What is the amplitude of the wave?(a) The amplitude of the wave is the maximum displacement of the wave.
amplitude of the wave = 0.2 m
(b) The period of the wave is the time taken for the wave to make one complete cycle.
period of the wave = 5.5 s - 1.5 s = 4 s
(c) The wavelength of the wave is calculated as follows;
λ = v / f
where;
v is the speed of the wavef is the frequency of the wavef = 1/t = 1 / 4s = 0.25 Hz
λ = ( 25 m/s ) / 0.25 Hz
λ = 100 m
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What is the minimum amount ( in kg) of liquid water at 26 degrees that would be required to completely melt 41 grams of ice? The specific heat capacity of liquid water is 4180 J/kg/°C and the specific heat of fusion of ice is 3.33×105 J/kg.
Approximately 0.123 kg of liquid water at 26 degrees Celsius would be needed to melt 41 grams of ice.
To calculate the minimum amount of liquid water required to melt 41 grams of ice at 0°C, we need to consider the energy required for the phase change from solid to liquid, which is known as the specific heat of fusion of ice.
The energy required to melt 1 kg of ice is 3.33×105 J/kg.
Therefore, the energy required to melt 41 grams of ice is (3.33×105 J/kg) × (41/1000) kg = 13653 J.
To calculate the amount of liquid water required, we use the specific heat capacity of water, which is 4180 J/kg/°C.
Assuming the initial temperature of water is 26°C, the amount of water needed can be calculated as (13653 J) ÷ (4180 J/kg/°C) ÷ (26°C) = 0.123 kg or approximately 123 ml of water.
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which has the greater acceleration: a car that increases its speed from 50 km/h to 60 km/h, or a bike that goes from 0 km/h to 10 km/h in the same time? Explain.
Answer:
They have the same acceleration.
Explanation:
50km/h to 60km/h = 10km/h
0km/h to 10 km/h = 10km/h
May I have Brainliest please? My next rank will be the highest one: A GENIUS! Please help me on this journey to become top of the ranks! I only need 15 more brainliest to become a genius! I would really appreciate it, and it would make my day! Thank you so much, and have a wonderful rest of your day!
Answer:
they have a same acceleration
Explanation:
50km/h to 60 km/h=10km/h
0km/h to 60 km/h=10km/h
How can you use the Pythagorean theorem to add two vectors that are not perpendicular?
The magnitude of the electric field due to a point charge object at a distance 4.0 m is 9 N/C. From the same
charged object the electric field of magnitude, 16 N/C will be at a distance of
The electric field of magnitude 16 N/C will be at a distance of 6.0 meters from the charged object.
The magnitude of the electric field due to a point charge object follows the inverse square law, which states that the magnitude of the electric field is inversely proportional to the square of the distance from the charged object. Mathematically, this is expressed as:
\(E = k*q/r^2\)
where E is the electric field, k is Coulomb's constant (\(k = 9 x 10^9 N*m^2/C^2\)), q is the charge of the object, and r is the distance from the object.
We can use this formula to find the distance at which the electric field has a magnitude of 16 N/C. Let's call this distance x:
16 = \(k*q/x^2\)
We can rearrange this equation to solve for x:
x = \(\sqrt(k*q/16)\)
To find q, we need another piece of information. We know that the electric field has a magnitude of 9 N/C at a distance of 4.0 m. Using the same formula as before, we can solve for q:
9 = \(k*q/4^2\)
q = \(9*4^2/k\)
Now we can substitute this value for q into the equation for x:
x =\(\sqrt(k*(9*4^2/k)/16)\)
x =\(\sqrt(9*4^2/16)\)
x = \(\sqrt(36)\)
x = 6.0 meters
Therefore, the electric field of magnitude 16 N/C will be at a distance of 6.0 meters from the charged object.
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How is the acceleration of a falling object calculated
Answer:
F=w=ma OR by using equations of motions vf=vi-at : a=vf-vi/t eq 1 s=vit+1/2at squre eq 2 2as=vf squre - vi squre eq 3
Explanation:
where m is the mass of falling body , f is the weight is the force acting down ward , vf is the final velocity, vi is the inetial velocity , t is the time and s is the distance covered by a body.