Read the following scenarios and elaborate what is wrong with students's behaviour.
1.) Diana and Mike were going to be late to their next class.After rushing to put away a few materials, they left the rest of the materials on the table.
2.) Cindy broke a test tube.Carefully she picked up the pieces with one hand and placed them in her other hand.Then she dumped the glass pieces into the wastebasket.
3.) Mike and Colleen had a lot of chemicals left from their investigation.They dumped the chemical in the sink and left the water running in the sink as they left class.


ANYONE PLEASE HELP ME IN CHEMISTRY BECAUSE I HAVE TO PASS THIS TOMORROW AT 4TH PERIOD I HOPE Y'ALL CAN HELP ME:(​

Answer:

Na

Explanation:

Answer:

It is Rb!!

for plato users

Answer:

I have a picture from my excerpt that basically answers all of that!

Hope it helps!

Explanation:

The attachment

The alkali metals and alkaline earth metals has different physical and chemical properties due to difference in their valence electrons.

·Electronic      [Noble gas]ns1                                  [Noble gas]ns2

configuration

·Reactivity      Comparatively more reactive     Comparatively less

                                                                         reactive                        

·Hardness       Soft and can be cut by sharp     Comparatively harder

                      knife

·Valency         One valence electron               Two valence electron

·Ionic charge   +1                                              +2

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Explanation:

multiply 1.5m by 2m by 0.3m

Answer: 0.9m

The two conjugate acid-base pairs in the reaction \(HSO_4^-\)(aq) + \(OH^-\)(aq) ⇌ \(SO_4^{2-}\)(aq) + \(H_2O\)(l) are \(HSO_4^-\)/\(SO_4^{2-}\) and \(OH^-\)/\(H_2O\).

The given reaction is a proton transfer reaction, which involves the transfer of a proton (H+) from the \(HSO_4^-\) ion to the \(OH^-\) ion to form the \(SO_4^{2-}\) ion and water (\(H_2O\)).

The two conjugate acid-base pairs involved in this reaction are:

\(HSO_4^-\)/\(SO_4^{2-}\)  pair:

\(HSO_4^-\) is the acid and \(SO_4^{2-}\) is its conjugate base. When \(HSO_4^-\) loses a proton, it forms the conjugate base \(SO_4^{2-}\). Thus, \(HSO_4^-\) is acid and \(SO_4^{2-}\) is the base in this pair.

\(OH^-\)/\(H_2O\) pair:

\(H_2O\) is the acid and \(OH^-\) is its conjugate base. When \(H_2O\) donates a proton, it forms the conjugate base \(OH^-\). Thus, \(H_2O\) is the acid, and \(OH^-\)is the base in this pair.

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Answer: From top to bottom, 1 3 4 5 6

Explanation: The empirical formula is the most reduced whole number ratio of elements. N2O4 is the only compound that can be further reduced, making the empirical formula NO2, and thus is different from the molecular formula.

Answer:

Radiation

Conduction is the transfer of thermal energy through direct contact. Convection is the transfer of thermal energy through the movement of a liquid or gas. Radiation is the transfer of thermal energy through thermal emission.

The evolution of firearm and tool mark identification in forensic science has been shaped by various significant events. Here are five key milestones that have contributed to its development:

St. Valentine's Day Massacre (1929): The high-profile nature of this event, where seven gangsters were murdered, highlighted the need for improved forensic techniques. This led to the establishment of the first scientific crime laboratory in the United States by the Chicago Police Department, which included firearm examination as an important discipline. Landsdowne Committee (1960): The committee, led by Sir Ronald Fisher, conducted an investigation into the principles and reliability of firearm identification. Their report laid the foundation for statistical methods in firearms identification, emphasizing the importance of scientific rigor and standardization.

Introduction of the Comparison Microscope (1963): The comparison microscope revolutionized firearm examination by allowing side-by-side comparisons of bullet striations and tool marks. This breakthrough greatly enhanced the accuracy and efficiency of forensic analysis.The FBI's Firearms and Toolmarks Examiner Training Program (1978): The FBI established a comprehensive training program for firearms examiners, providing standardized protocols and promoting expertise in the field. This program played a vital role in enhancing the quality and consistency of firearm and tool mark identification across the United States.Introduction of Computerized Systems (1990s):

The integration of computerized systems allowed for digitization, storage, and retrieval of firearm and tool mark data. This advancement improved information management, facilitated comparison searches, and increased the speed and accuracy of identification processes.

These events represent significant milestones in the evolution of firearm and tool mark identification, leading to advancements in techniques, standardization, training, and technological integration, ultimately enhancing the reliability and efficiency of forensic science in this field.

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The barium chunk has a volume of 4.00 cm³ and a density of 3.62 g/cm³. Therefore, the mass of the barium sample is 14.48 g.

The mass of a substance per unit volume is what is meant by the term "density.". The equation for density is ρ = M/V, where ρ stands for density, M for mass, and V for volume.

A body's mass can be calculated from its volume or vice versa using density; the mass is equal to the volume multiplied by the density (M = ρV), and the volume is equal to the mass divided by the density

(V = M/ρ).

According to the question,

V = 4.00 cm³

ρ = 3.62 g/cm³

Therefore,

M = ρV = (4 × 3.62) = 14.48 g.

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Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 80 × 1.6

We have the final answer as

Hope this helps you

Answer:

59.46 g

Explanation:

To answer this question, the molecular weight of ammonium sulfate must be computed.  To accomplish this, the weights of the individual elements must be noted.
N=14.01\(\frac{g}{mol}\)

H=1.01\(\frac{g}{mol}\)

S=32.07\(\frac{g}{mol}\)

O=16.00\(\frac{g}{mol}\)

To compute the molecular weight:

\(2[14.01\frac{g}{mol}+4(1.01\frac{g}{mol})]+32.07\frac{g}{mol}+4(16.00\frac{g}{mol})=132.14\frac{g}{mol}\)

To calculate the mass:

\(0.45 mol(\frac{132.14g}{1mol})=59.463g\)

Answer:

a liquid which has passed through a filter.

Explanation:

Filtration is a physical separation process that separates solid matter and fluid from a mixture using a filter medium that has a complex structure through which only the fluid can pass

Answer:

D. hydrogen and oxygen

Explanation:

Both hydrogen and oxygen are neutral gases, so red litmus paper will stay red, and blue litmus paper will stay blue - there is no effect.

Hope this helps!

The energy of an incident photon that is just enough to excite a hydrogen atom from its ground state to its n = 150 excited state is approximately 13.6 eV.

The energy of an incident photon that is just enough to excite a hydrogen atom from its ground state to its nth energy level (n > 1) can be calculated using the formula:

\($E = -\frac{13.6 \text{ eV}}{n^2} + 13.6 \text{ eV}$\)

where E is the energy of the photon and n is the energy level of the excited state.

For n = 2 (i.e., first excited state), the energy of the photon required would be:

\($E = -\frac{13.6 \text{ eV}}{2^2} + 13.6 \text{ eV}$\)

= -3.4 eV + 13.6 eV

= 10.2 eV

For n = 150, the energy of the photon required would be:

\($E = -\frac{13.6 \text{ eV}}{150^2} + 13.6 \text{ eV}$\)

= -0.00006 eV + 13.6 eV

= 13.6 eV (approx.)

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Explanation:

I hope it helps

ya welcome

Answer:

Dimitri mendleev and Albert something. I forgot his last name. I think ghorso. Albert ghorso.

Answer:

The first person to go to the moon

Explanation:

Neil Armstrong was the first person !

heres more info on NASAs page!

https://www.nasa.gov/audience/forstudents/k-4/stories/first-person-on-moon.html

Toxicology is the branch which studies about toxic chemicals and their effects.

Toxicology is the branch in science in which the researches and study are done for finding the effect of the toxic  or poisonous elements on plants , animals , human and earth at large.

High levels of lead exposure is dangerous to humans as it can cause permanent disabilities , it is carcinogenic and hence can lead to death.

This is studied in toxicology.

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Answer:

12*2*6.022*10^23. Atoms of hydrogen.

Explanation:

First of all if u know that 1 molecule of calcium hydroxide contain 2 hydrogen atom and 1 mole of calcium hydroxide contain 6.022*10^23 molecules of calcium hydroxide.

Hence 1 mole of calcium hydroxide contain 2*6.022*10^23 atom of hydrogen.

So 12 mole of calcium hydroxide contain =12*2*6.022*10^23. Atoms of hydrogen.

Answer:

0

Explanation:

im pretty sure its 0 pls mark me as brainliest

The dot structure that can be shown to be incorrect is the dot structure that has been shown by option A

The Lewis structure is based on the concept that atoms tend to gain, lose, or share electrons in order to achieve a stable electron configuration similar to that of a noble gas. In the Lewis structure, the valence electrons of the atoms are represented as dots around the symbol of the atom.

We can see that in the dot structure that is in option A the both atoms are coming from the hydrogen atoms and shoud not be differently marked.

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Taking into account the definition of Avogadro's Number, 10.365 moles of H₂O are 6.243×10²⁴ molecules of H₂O.

Avogadro's Numberis called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance.

Its value is 6.023×10²³ particles per mole and it applies to any substance.

You can apply the following rule of three: if 6.023×10²³ molecules are contained in 1 mole of H₂O, then 6.243×10²⁴ molecules are contained in how many moles of H₂O?

amount of moles of H₂O= (6.243×10²⁴ molecules× 1 mole)÷ 6.023×10²³ molecules

amount of moles of H₂O= 10.365 moles

Finally, 10.365 moles of H₂O are 6.243×10²⁴ molecules of H₂O.

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Answer:

The third one

Explanation:

Nickel-62 has the highest binding energy per nucleon of any isotope for any element. Isotopes heavier than 62Ni cannot be formed by nuclear fusion without losing energy.

The volume sulfuric acid will be 89.3mL.

Volume will be determined by the molarity relation. The quantity of a substance in a specific volume of solution is known as its molarity (M). The number of moles of a component per liter of a solution would be known as molarity. The molar concentration of any solution would be another name for molarity.

The volume can be calculated by using molarity formula:

\(M_{1} V_{1} = M_{2} V_{2}\)

Given data:

\(M_{1}\) = 3.50 m

\(M_{2}\) =  1.25 m

\(V_{1}\)= 250.0 ml

Put the value of given data in above formula:

\(M_{1} V_{1} = M_{2} V_{2}\)

( 3.50 m) ( 250 mL) = ( 1.25 m) \(V_{2}\)

\(V_{2}\) = 89.3mL

Therefore, the volume sulfuric acid will be 89.3mL.

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The purpose of beta-oxidation in living organisms is the catabolism of fatty acids. The correct option is A.

The beta-oxidation of fatty acids refers to the process by which fatty acid molecules are broken down into acetyl-CoA molecules by the enzymes of beta-oxidation. The process begins at the beta carbon atom of the fatty acid, hence the name beta-oxidation.

The beta-oxidation of fatty acids occurs in the mitochondria and involves a series of four repetitive steps catalyzed by four separate enzymes.

Beta-oxidation involves even-number fatty acid molecules.

The product of beta-oxidation, acetyl-CoA can then be used by the citric acid cycle to produce reducing equivalents that enter the electron transport chain for the synthesis of ATP molecules.

Hence, the role of beta-oxidation in cells is to produce acetyl CoA for ATP synthesis.

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Answer:

15.5g

Explanation:

your welcome

Birch reduction of p-xylene likely produced only one organic compound, which is most likely 1,4-dimethylbenzene (also known as p-xylene).

An aromatic compound can be reduced via the Birch reduction, which commonly produces alkyl-substituted aromatic compounds. By reducing the p-xylene molecule in this instance, two methyl groups were added to the benzene ring, resulting in 1,4-dimethylbenzene.

The Birch reduction is a chemical process that uses sodium or lithium in liquid ammonia to decrease aromatic molecules. Alkyl groups are added to the aromatic ring as a result of the reaction, which lowers the electron density and lessens the aromatic nature of the molecule.

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