Ralph went on a shopping trip. He bought a pair of shoes and a sweater. Ralph spent 12​% more on the sweater than on the shoes. The cost of the sweater is​ ____% of the cost of the shoes.

According to the solving the lenght of line segment is TU = 12.

An  portion of a line with two endpoints is referred to as a line segment. A line segment, unlike a line, has a definite length.

Because T is on the line segment SU. so, addition of ST and TU must be equal to SU

SU = ST + TU..........(1)

SU = 3x -7

TU = x -1

ST = x + 7

Substituting these values into equation (1)

3x-7 = x +7 + x -1

3x -7 = 2x + 6

x = 13

For the numerical length of TU

TU = x - 1

TU = 13 - 1

TU = 12

The numerical value of tu is 12

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The equation of the tangent line to the curve y^2(6−x)=x^3 at the point (2, 2) is y = x.

To find the equation of the tangent line to the curve y^2(6−x)=x^3 using implicit differentiation at the point (2, 2), we'll differentiate both sides of the equation with respect to x.

Starting with the given equation: y^2(6−x) = x^3

Differentiating both sides with respect to x: d/dx [y^2(6−x)] = d/dx [x^3]

Using the product rule for differentiation on the left side and the power rule on the right side, we have:

2y * d/dx [y] * (6−x) + y^2 * (-1) * d/dx [x] = 3x^2

Simplifying:

2y * dy/dx * (6−x) - y^2 * dx/dx = 3x^2

Since we're interested in finding the slope (dy/dx) at the point (2, 2), we can substitute x = 2 and y = 2 into the equation:

2 * 2 * dy/dx * (6−2) - 2^2 * 1 = 3 * 2^2

4 * dy/dx * 4 - 4 = 12

16 * dy/dx - 4 = 12

16 * dy/dx = 12 + 4

16 * dy/dx = 16

dy/dx = 16/16

dy/dx = 1

Therefore, at the point (2, 2), the slope (dy/dx) of the curve y^2(6−x)=x^3 is 1. To find the equation of the tangent line, we have the slope (m = 1) and a point on the line (2, 2). Using the point-slope form, we can write the equation: y - y1 = m(x - x1)

where (x1, y1) is the point on the line. Substituting the values, we get:

y - 2 = 1(x - 2)

y - 2 = x - 2

y = x

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This is because as the sample size increases, the confidence interval becomes more precise and thus narrower.

When the level of confidence and sample standard deviation remains the same, a confidence interval for a population mean based on a sample of n = 100 will be narrower than a confidence interval for a population mean based on a sample of n = 50. This is because larger sample sizes typically result in more precise estimates of the population mean, leading to a smaller margin of error and therefore a narrower confidence interval.
This is because as the sample size increases, the confidence interval becomes more precise and thus narrower.

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Answer:

102

Step-by-step explanation:

Given f(x) =18x+12

F(5)=18(5)+12

=90+12

=102

The square mil area for a 2 inch wide by 1/4 inch thick copper busbar is 500 square mils.

To find the square mil area for a 2 inch wide by 1/4 inch thick copper busbar, we need to multiply the width and thickness of the busbar in mils.

1 inch = 1000 mils

So, the width of the busbar in mils = 2 inches x 1000 mils/inch = 2000 mils

And, the thickness of the busbar in mils = 1/4 inch x 1000 mils/inch = 250 mils

Therefore, the square mil area of the copper busbar = width x thickness = 2000 mils x 250 mils = 500,000 square mils.

Hence, the square mil area for a 2 inch wide by 1/4 inch thick copper busbar is 500,000 square mils.

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Answer:

3900 $

Step-by-step explanation:

(32×18)+(18×8)+(47×26)+(63×23)+(52×9)

Answer:

2688 cm³

Step-by-step explanation:

2058×704/539 = 2688 cm³

Answer:

x = 5 /2 , y = 9 / 8

Step-by-step explanation:

x = 4y - 2 ....... (i)

x + 4y =7 ....... (ii)

Substituting eqn  (i) into eqn (ii);

(4y - 2 ) + 4y = 7

4y - 2 + 4y = 7

8y = 7 + 2 = 9

y = 9 / 8

substitute y = 9 / 8 in eqn (i)

x = 4 (9 / 8) - 2

x = 9 / 2   -   2

x = (9 - 4 ) / 2

x = 5 / 2

Answer:

\( \displaystyle 8\)

Step-by-step explanation:

we would like to compute the following limit

\( \displaystyle \lim_{x \to 16} \left( \frac{x - 16}{ \sqrt{x} - 4} \right) \)

if we substitute 16 directly we'd end up

\( \displaystyle = \frac{16 - 16}{ \sqrt{16} - 4} \)

\( \displaystyle = \frac{0}{ 0} \)

which isn't a good answer now notice that we have a square root on the denominator so we can rationalise the denominator to do so multiply the expression by √x+4/√x+4 which yields:

\( \displaystyle \lim_{x \to 16} \left( \frac{x - 16}{ \sqrt{x} - 4} \times \frac{ \sqrt{x} + 4 }{ \sqrt{x} + 4 } \right) \)

simplify which yields:

\( \displaystyle \lim_{x \to 16} \left( \frac{(x - 16)( \sqrt{x} + 4)}{ x - 16} \right) \)

we can reduce fraction so that yields:

\( \displaystyle \lim_{x \to 16} \left( \frac{ \cancel{(x - 16)}( \sqrt{x} + 4)}{ \cancel{x - 16} } \right) \)

\( \displaystyle \lim _{x \to 16} \left( \sqrt{x } + 4\right) \)

now it's safe enough to substitute 16 thus

substitute:

\( \displaystyle = \sqrt{16} + 4\)

simplify square root:

\( \displaystyle = 4 + 4\)

simplify addition:

\( \displaystyle = 8\)

hence,

\( \displaystyle \lim_{x \to 16} \left( \frac{x - 16}{ \sqrt{x} - 4} \right) = 8\)

Answer:

A) y = 1/3x + 10/3

Step-by-step explanation:

Answer:

w^2+15w+54

Step-by-step explanation:

(w+9)(w+6)

w^2+9w+6w+54

w^2+15w+54

Answer:

w^2 + 15w + 54

Step-by-step explanation:

Answer:

18π

Step-by-step explanation:

Answer: I think that the answer is all of the above.

I am not 100% sure if that is completely correct so just pick some answers and see if they are correct.

Step-by-step explanation:

Answer:

176mm

Step-by-step explanation:

Given

Diameter of the pencil = 7mm

First, we need to find the length of one roll of paper

Circumference of one roll = πd

Circumference of one roll = 22/7  *7

Circumference of one roll = 22mm

Since a student winds a strip of paper eight times around a cylindrical pencil, then the length of the paper = 8 * 22  = 176mm

Answer:

14.14

Step-by-step explanation:

Recall :

The sides of a square are always equal ;

Since all sides are equal, the the diagonal of the square will be :

XZ² = XY² + WX²

XZ² = 20² + 20²

XZ² = 400 + 400

XZ² = 800

XZ = √800

XZ = 28.28

WY = XZ

WV = 1/2 WY

WV = 1/2 * 28.28

WV = 14.14

The output of this code will be a signal that starts at zero and gradually increases to three. After five seconds, the signal starts decreasing to zero, with an exponential decay rate. The output plot will look like a ramp that rises linearly and falls exponentially after five seconds.

The term "son of a mention" is not familiar in mathematics. The correct term might be "son of a gun" or "son of a function."A differential equation used to model your specific engineering course is called an engineering differential equation. Such equations are used to predict, control, and monitor various physical processes, ranging from the dynamics of mechanical systems to the motion of fluids and gases, and electrical and electronic circuits. It's essential to know the form of the differential equations, the initial and boundary conditions, and the physical meaning of the parameters to use them effectively in modeling physical systems.

The following MATLAB code represents a simple for loop with a nested if-else statement and a plotting command. The code generates a signal with two segments: a rising ramp from zero to three and a falling ramp from three to zero. The signal has a total duration of 10 seconds, a sampling interval of 0.05 seconds, and a plotting delay of 0.002 seconds.

01 t=0 02 while t<10 03

if

(t<5) 04 y=3*(1-exp(-t)); 05 else if

(t>=5) 06 y=3*exp(-t+5); 07 ends 08 end 09

t = t + 0.05 10 pauses (0.002)

The output of this code will be a signal that starts at zero and gradually increases to three. After five seconds, the signal starts decreasing to zero, with an exponential decay rate. The output plot will look like a ramp that rises linearly and falls exponentially after five seconds.

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Answer:

ella uso 1202403.6 chispas de chocolate para cada charola de panques

oh algo asi no se jajjaja

Answer:

$109.875

Step-by-step explanation:

Assuming "a pair" means 4 tires the math would be as follows:

146.50 for 4 tyres.

146.5/4 = cost of one tyre.

1 tyre: $36.625

Multiply by 3 for price of three tires:

36.625 x 3 = $109.875

Answer:180

Step-by-step explanation:

This statement is True. The statement is known as the 68-95-99.7 rule, which applies to a normal distribution. According to this rule, approximately 99.7 percent of the sample means will fall within plus or minus two standard deviations of the process mean if the process is under control. This rule is derived from the properties of a normal distribution and provides a guideline for assessing the variability of a process.

In statistical terms, if a process is under control and follows a normal distribution, about 68 percent of the sample means will fall within one standard deviation of the process mean, around 95 percent will fall within two standard deviations, and roughly 99.7 percent will fall within three standard deviations. This rule assumes that the process is stable and does not have any significant shifts or outliers.

The 99.7 percent figure is derived from the empirical rule, which is based on the characteristics of a normal distribution. It is widely used in statistical process control and quality management to assess the performance and variability of a process. By monitoring the sample means and their deviation from the process mean, practitioners can identify if the process is in control or if there are any significant variations that need to be addressed.

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The difference quotient of f(x) is \(\frac{-\frac{1}{h}+ 5}{5x+ h -12}\) .

According to the given question.

We have a function

f(x) = -1/(5x -12)

As we know that, the difference quotient is a measure of the average rate of change of the function over and interval.

The difference quotient formula of the function y = f(x) is

[f(x + h) - f(x)]/h

Where,

f(x + h) is obtained by replacing x by x + h in f(x)

f(x) is a actual function.

Therefore, the difference quotient formual for the given function f(x)

= [f(x + h) - f(x)]/h

= \(\frac{\frac{-1}{5(x+h)-12} -\frac{-1}{5x-12} }{h}\)

= \(\frac{\frac{-1}{5x + 5h -12}+\frac{1}{5x-12} }{h}\)

= \(\frac{\frac{-1+5h}{5x + 5h-12} }{h}\)

= \(\frac{-1+5h}{(5x +h-12)(h)}\)

= \(\frac{-1+5h}{5xh + h^{2} -12h}\)

= \(\frac{h(-\frac{1}{h}+5) }{h(5x+h-12)}\)

= \(\frac{-\frac{1}{h}+ 5}{5x+ h -12}\)

Hence, the difference quotient of f(x) is \(\frac{-\frac{1}{h}+ 5}{5x+ h -12}\) .

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Answer:

\(\huge\boxed{\sf Right.}\)

Step-by-step explanation:

\((-a+b)^2\)

Let's apply the formula (x+y)² = x² + 2xy + y²

Here, x = -a and y = b

So,

= (-a)² + 2(-a)(b) + (b)²

= a² - 2ab + b²

Hence, it has been proved that (-a + b)² = a² - 2ab + b².

\(\rule[225]{225}{2}\)

Hope this helped!

Answer:

46.67

Step-by-step explanation:

Answer:

Iam 5 yea4s old did you no that

Step-by-step explanation:

Answer: y-4=1.2(x-5)

Step-by-step explanation:

Step-by-step explanation:

Let's use "x" to represent the number of chocolate cakes sold and "y" to represent the number of vanilla cakes sold.

From the problem statement, we know that the bakery sold a total of 50 cakes, so we can set up an equation:

x + y = 50

We also know that the total sales were $200. If the chocolate cakes sold for $5 each and the vanilla cakes sold for $3 each, we can set up another equation for the total sales:

5x + 3y = 200

We can use the first equation to solve for one of the variables in terms of the other. For example, we can solve for y in terms of x:

y = 50 - x

Substituting this expression for y into the second equation, we get:

5x + 3(50 - x) = 200

Simplifying this equation, we get:

2x + 150 = 200

2x = 50

x = 25

So the bakery sold 25 chocolate cakes. To find the number of vanilla cakes sold, we can substitute x = 25 into the equation y = 50 - x:

y = 50 - 25

y = 25

So the bakery also sold 25 vanilla cakes.

Therefore, the bakery sold 25 chocolate cakes and 25 vanilla cakes.

Answer:

m=-4k + 3f -7

Step-by-step explanation:

-5m = 20k - 15f + 35

Divide both sides by -5

\(\dfrac{-5m}{-5}= \dfrac{20k-15f+35}{-5}\\\\m= \dfrac{20k}{-5}- \dfrac{15f}{-5}+ \dfrac{35}{-5}\\\\m=-4k+3f-7\)

Hello!

Let's identify the parts of all the algebraic expressions below.

Please remember that

#1:

4x+7y+8

Variables: x, y

Coefficients: 4, 7

Constant: 8

Number of Terms: 3

\(\rule{300}{1}\)

#2:

Variables: a, b, c

Coefficients: 9, 3

Constants: No constants here!

Number of terms: 3

\(\rule{300}{1}\)

#3:

Variables: d, x

Coefficients: 3, 1

Constant: 10

Number of terms: 3

_________________________________________

#4:

variables: x, y

coefficients: 2, 6

constant: 2

number of terms: 3

______________________________________

#5:

variables: b, c, d

coefficients: 8, -7, 11

constants: -5

number of terms: 4

________________________

#6:

variables: s, t

coefficients: 18, 2

constant: -8

number of terms: 3

Hope everything is clear.

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:-)

Answer:

i) 0 is the additive identity of rational number