Question 20: The synchronous reactance of a cylindrical rotor synchronous motor is \( 0.8 \) p.u. (per unit \( = \) p.u.) and is kept at this value, at voltage from an ideal source, without being adju

Answer: the gravitational attraction on the Moon is much less than it is here on Earth, and a person weighs less on the Moon.

Explanation:

Answer:

499.73 m

Explanation:

We'll begin by calculating the change in the temperature. This can be obtained as follow:

Initial temperature (T₁) = 25 °C

Final temperature (T₂) = –20° C

Change in temperature (ΔT) =?

ΔT = T₂ – T₁

ΔT = –20 – 25

ΔT = –45 °C

Finally, we shall determine the length on a cold day at –20° C. This can be obtained as follow:

Length at 25°C (L₁) = 500 m

Coefficient of linear expansion (α) = 12×10¯⁶ /°C

Change in temperature (ΔT) = –45 °C

Length at –20 °C (L₂) =?

α = L₂ – L₁ / L₁ΔT

12×10¯⁶ = L₂ – 500 / (500 × –45)

12×10¯⁶ = L₂ – 500 / –22500

Cross multiply

L₂ – 500 = 12×10¯⁶ × –22500

L₂ – 500 = –0.27

Collect like terms

L₂ = –0.27 + 500

L₂ = 499.73 m

Therefore, the length on a cold day at –20° C is 499.73 m.

Answer:

Gravitational potential energy is the maximum at point C and lowest at point A

Explanation:

The image for the question is provide in the attached file

The energy of pendulum is governed by mechanical energy. Mechanical energy is the sum of potential energy and kinetic energy

Potential energy increases with increasing height. Thus, when the pendulum bob is at maximum height, then its potential energy is also the highest.

Thus, At point C, the gravitational potential energy is the highest

At point A, the  gravitational potential energy  is substantial but lower than that of gravitational potential energy at point C

AT point A, gravitational energy is the lowest

Answer:

Explanation:

lThe mass of an object given only it's force and acceleration can be found by using the formula

\(m = \frac{f}{a} \\ \)

f is the force

a is the acceleration

From the question

f = 195 N

a = 2.1 m/s

We have

\(m = \frac{195}{2.1 } = 92.857142... \\ \)

We have the final answer as

Hope this helps you

Answer:

moon planet star galaxy universe

a) The planar density expression for FCC (100) is 4/a^2.

    The planar density expression for FCC (111) is 2 / [(sqrt(3) / 2) * a^2].

b)  The planar density for the FCC (100) plane is 24.63 atoms/nm^2.

    The planar density for the FCC (111) plane is  12.32  atoms/nm^2.

a) To derive the planar density expression for the FCC (100) and (111) directions in terms of the atomic radius R, we need to consider the arrangement of atoms in these planes.

FCC (100) Plane:

In the FCC crystal structure, there are 4 atoms per unit cell. The (100) plane cuts through the middle of the unit cell, passing through the centers of the atoms at the corners. Since the atoms at the corners are shared with adjacent unit cells, we only count a fraction of these atoms.

For the (100) plane, we have 2 atoms in the plane, located at the corners of the square, and 1/2 atom at each of the 4 face centers. Thus, the total number of atoms in the plane is 2 + (1/2) * 4 = 4 atoms.

The area of the (100) plane is determined by the square formed by the lattice vectors a and a, which gives an area of a^2.

The planar density (PD) is defined as the number of atoms per unit area, so we divide the total number of atoms (4) by the area (a^2):

PD(100) = 4/a^2

FCC (111) Plane:

In the FCC crystal structure, there are 4 atoms per unit cell. The (111) plane passes through the centers of the atoms at the corners and the center of the face. Similarly to the (100) plane, we need to account for the fraction of shared atoms.

For the (111) plane, we have 1 atom in the plane, located at the corner of the equilateral triangle, and 1/3 atom at each of the 3 face centers. Thus, the total number of atoms in the plane is 1 + (1/3) * 3 = 2 atoms.

The area of the (111) plane is determined by the equilateral triangle formed by the lattice vectors a, a, and a, which gives an area of (sqrt(3) / 2) * a^2.

The planar density (PD) is defined as the number of atoms per unit area, so we divide the total number of atoms (2) by the area ((sqrt(3) / 2) * a^2):

PD(111) = 2 / [(sqrt(3) / 2) * a^2]

b) Now, let's compute the planar density values for the FCC (100) and (111) planes using the atomic radius R = 0.143 nm for Aluminum.

For FCC (100) plane:

PD(100) = 4 / a^2

For Aluminum, the lattice constant a is related to the atomic radius R by the formula:

a = 4R / sqrt(2)

Substituting the given value of R = 0.143 nm:

a = 4 * 0.143 nm / sqrt(2) ≈ 0.404 nm

Therefore, the planar density for the FCC (100) plane is:

PD(100) = 4 / (0.404 nm)^2 ≈ 24.63 atoms/nm^2

For FCC (111) plane:

PD(111) = 2 / [(sqrt(3) / 2) * a^2]

Using the calculated value of a = 0.404 nm:

PD(111) = 2 / [(sqrt(3) / 2) * (0.404 nm)^2] ≈ 12.32 atoms/nm^2

Therefore, the planar density for the FCC (111) plane is approximately 12.32 atoms/nm^2

Thus,

a) The planar density expression for FCC (100) is 4/a^2.

    The planar density expression for FCC (111) is 2 / [(sqrt(3) / 2) * a^2].

b)  The planar density for the FCC (100) plane is 24.63 atoms/nm^2.

    The planar density for the FCC (111) plane is  12.32  atoms/nm^2.

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Stars form from molecular clouds through a process known as stellar formation.

These clouds, characterized by low temperatures and high densities, provide the ideal conditions for atoms to combine and form molecules. With a mass range spanning from a few solar masses to millions of solar masses, molecular clouds serve as the birthplaces of new stars. The Pleiades cluster serves as a notable example of stars that have recently formed within such a stellar nursery.

The formation of stars from molecular clouds involves several key steps. Firstly, gravitational forces acting on regions of higher density within the cloud cause them to collapse under their own gravity. As the cloud collapses, it begins to fragment into smaller, denser clumps called protostellar cores. These cores continue to collapse, and their central regions become increasingly dense and hot. At this stage, they are known as protostars.

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my brain.

Explanation:

...................

Answer:The Nokia XR20. ... HMD Global said the Nokia XR20 is the most durable phone it's created to date. The XR20 sports a tough 6.67-inch Gorilla Glass Victus display from American tech firm Corning and can resist damage from scratches and drops from about 6 feet, the company says.Jul 26, 2021

Explanation:

When a magnetic field is present, the quantity of flux that passes through a surface can be calculated by multiplying the normal component of the magnetic field by the surface area. (ϕ=3.43×10−3 Wb).

We are given:

Diameter of the coil,d=7.9cm

Magnetic Field, B=2.2T

Initial angle between magnetic field and the normal, θi=0∘

Initial angle between magnetic field and the normal,θf=180∘

Cross section Area of the coil,

A=π×d2/4 =π×(7.9×10−2)2/4 =1.56×10−3 m2

Magnitude of change in magnetic flux through the loop

ϕ =B×A×cosθi −B×A×cosθf

ϕ =2.2x1.56×10−3×(cos0∘ −cos180∘)

ϕ=3.43×10−3 Wb

To get the average induced emf over a period of time t, we apply Faraday's law of induction: emf=Nt. Given that N=200 and t=15.0ms are known, we must ascertain the flux change in order to find the emf. Solution: We can see that =(BAcos)=AB(cos) because the magnetic field intensity and loop area are both constants.

Based on the discrepancy between the provided voltage and the current loss due to resistance, the back emf is determined. Based on the provided data, one of the power formulas is used to determine the power from each device.

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Answer:

v_kyle = 0.5 m/s

v_jennies = 0.333 m/s

Kyle's Rabbit was the fastest

Explanation:

For the velocity of Kyle's Rabbit:

d = distance covered = 40 m

t = time taken = (1 min)(60s/1 min) + 20 s = 80 s

\(v_{kyle} = \frac{d}{t} = \frac{40\ m}{80\ s}\)

v_kyle = 0.5 m/s

For the velocity of Jennies Rabbit:

d = distance covered = 30 m

t = time taken = (1 min)(60s/1 min) + 30 s = 90 s

\(v_{jennies} = \frac{d}{t} = \frac{30\ m}{90\ s}\)

v_jennies = 0.333 m/s

It is clear from the results that:

Kyle's Rabbit was the fastest

Answer:

temperature of about  2.72548 ± 0.00057 K.

Explanation:

The cosmic background radiation is an electromagnetic radiation that remains from an early stage of the universe during the big bang. It was accidentally discovered in 1965 by two American radio astronomers Arno Penzias and Robert Wilson. The radiation was given off before the formation of stars and planets, when the universe was young, denser, hotter, and filled with a uniform glow from a white-hot fog of hydrogen plasma, which cooled down as the universe expanded. From calculations, it was deduced that the radiation had a temperature of 2.72548±0.00057 K, which is close to the temperature of the universe during its formation.

The direction of this current's magnetic force on an electron that is moving perpendicular to the page and outward from it on the left side of the wire is downward.

What is Magnetic force?

The force exerted by a magnetic field on a moving charged particle is known as a magnetic force. It is described by the formula F = q(v x B), where F is the magnetic force, q is the particle's charge, v is the particle's velocity, and B is the magnetic field.

The right-hand rule states that when a wire-carrying current is held in the right hand with the thumb pointing in the direction of the current, the fingers will curl in the direction of the magnetic field lines created by the current.

The magnetic field lines will create clockwise circles around the wire because, in this instance, the current flows from the top of the page downward.

Now imagine an electron on the left side of the wire traveling perpendicular to the page. The electron will experience a magnetic force since it travels in a direction perpendicular to both the magnetic field and the current.

We can use the left-hand rule for a negative charge to determine the direction of this force. If the left hand is held with the fingers pointing toward the magnetic field and the thumb pointing toward the electron's velocity, the palm will face the order of the force on the electron.

The thumb points to the left because the electron leaves to the left. The fingers curl because the magnetic field lines go clockwise around the wire. Therefore, the magnetic force acting on the electron is directed downward because the palm is facing downward.

Therefore, the magnetic pull exerted by this current on an electron traveling outward and perpendicular to the page on the wire's left side is directed downward.

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The Sun's apparent yearly path across planet Earth's sky against the background stars wouldn't be described as the celestial equator.

A solar system can be defined as a collection of the outer and inner planetary (astronomical) bodies alongside the Moon that are in orbit around the Sun, in slightly elliptical orbits.  

Basically, there are nine (9) planets in the solar system and these include;

Based on astronomical records and information, we can infer and logically deduce that the Sun's apparent yearly path across planet Earth's sky against the background stars wouldn't be described as the celestial equator.

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Answer:

:)

Explanation:

i need 5 points i really do :)

Answer:

a) 2.5s

b)24.2m/s

Explanation:

a) s = ut +1/2gt^2

Where u=0

Make t the subject and solve

b) v^2=u^2+2gs

Where u =0

Make v the subject and solve

To calculate the recombination frequency, we need to determine the number of recombinant progeny (ab/ab) divided by the total number of progeny. Therefore, the recombination frequency in this case is 100%.

Given:

Number of progeny with ab/ab genotype = 72 + 68 + 17 + 21 = 178

Total number of progeny = 72 + 68 + 17 + 21 = 178

Recombination frequency = (Number of recombinant progeny / Total number of progeny) × 100%

Recombination frequency = (178 / 178) × 100%

Recombination frequency = 100%

Therefore, the recombination frequency in this case is 100%.

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A cosmic day is equivalent to approximately 13.8 billion Earth years.

To calculate how many Earth years a cosmic day is equivalent to, we need to determine the length of a cosmic year in Earth years and then divide it by 365 to find the duration of a cosmic day.

Given that the age of the universe is estimated to be 13.8 billion normal years, and only one cosmic year has passed in that time, we can conclude that a cosmic year is equal to 13.8 billion normal years.

To convert this into Earth years, we multiply the length of a cosmic year by 365, since there are 365 days in a normal year.

13.8 billion normal years * 365 = 5.04 trillion Earth years.

Now, to find the duration of a cosmic day, we divide the length of a cosmic year in Earth years by 365 (the number of cosmic days in a cosmic year).

5.04 trillion Earth years / 365 = 13.8 billion Earth years.

Therefore, a cosmic day is equivalent to approximately 13.8 billion Earth years.

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Answer:

The force due to friction is generally independent of the contact area between the two surfaces. This means that even if you have two heavy objects of the same mass, where one is half as long and twice as high as the other one, they still experience the same frictional force when you drag them over the ground.

Plz mark 5 star, thanks, and brainliest

Answer:

Initial y-component of speed

Vy = 28 * sin 30 = 14 m/sec vertically

1/2 m Vy^2 = 2 m g h    conservation of energy of y-component

h = Vy^2 / (2 * g) = 14^2 / (2 * 9.8) = 10 m

Earth takes 365.25days or one year time to complete one revolution around the sun.

what is a revolution:

The movement of the earth around the sun is called revolution. A revolution or orbit is the time for the earth to make one complete revolution around the sun. Time for one revolution=365.25 days/one year. the speed of earth's revolution is 68000 miles per hour.

Importance of Revolution:

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Answer:

to see how much you are getting of something

Explanation:

Answer:

I would use it to track everything nutrition wise.

Explanation:

I would use it to track everything nutrition wise. Meaning that if I do anything that is in the process of eating or consuming food, I would log it down. A good example of what goes in a dietary log would be how much you ate, the amount of calories you ate, and occasionally the amount of serving you ate based off the recommended serving size. It should be important to keep a fitness log if you are interested in keeping a diet diary; to  further track calories!

Hope this helps <3

To calculate the power required to do 6 kJ of work in three minutes, we need to use the formula P = W/t, where P is the power in watts, W is the work done in joules, and t is the time taken in seconds.

First, we need to convert the time from minutes to seconds. Since one minute equals 60 seconds, three minutes would be 3 x 60 = 180 seconds. Next, we can substitute the values into the formula: P = 6,000 / 180 = 33.33 watts. Therefore, the power required to do 6 kJ of work in three minutes is 33.33 watts. It's important to note that power is a measure of how quickly work is done. In this case, the power required to do 6 kJ of work in three minutes is relatively low, which suggests that the work is being done at a slower rate. In contrast, if a higher power output was required to do the same amount of work, it would indicate that the work was being done more quickly. Understanding power requirements is important in a wide range of fields, including engineering, physics, and energy production.

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angle to the shore should a person navigate a boat, which is maintaining a constant speed of 16 km/h, in order to reach a point directly opposite is 75.5 degrees.

Since the stream is flowing parallel alongside the shore, it takes the vector form of  v {stream} = [0,4]

the boat velocity is perpendicular to the stream, it's takes the vector form of  v{boat} = [-16,0]

The resultant velocity of the boat is the sum of the velocity of the boat and stream, thus it takes the form

v{total} =  [-16,0] +  [0,4]

           = [ -16,4]

the cosine of angle to the shore,

                  cos {theta} = v{total} . v {stream} / ||v{total} || x ||v {stream}||

                                     =  [ -16,4] . [0,4] / (16x4)

                                     = 16/64

                                     = 0.25

                       angle = 75.7 degrees.

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Because of Kinetic Theory Postulate, the gas molecule's collision will affect.

Gases can be compressed because most of the volume of gas is an empty space according to Kinetic Molecular theory. If we compress a gas without changing its temperature, the average K.E of the gas particles remains the same. There is no change in the speed of the gas molecules with which the particles move in a container, but the container is smaller. So particles travel from one side of the container to the other in a very small period of time. So it means that they strike the walls mostly. Any increase in the frequency of collisions with the walls must increase the pressure of the gas. from Boyle's law, the pressure of gas becomes more significant as the volume of the gas becomes smaller have opposite relation.

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The angular velocity of the ISS is 0.012 rad/s. the height above the Earth's surface at which the ISS orbits is 408 km. the tangential speed of the ISS is 7 km/s.

a) Calculate the angular velocity of the ISS.

The angular velocity of the ISS can be calculated using the following formula:

ω = v / r

where:

ω is the angular velocity in radians per second

v is the tangential velocity in meters per second

r is the radius of the orbit in meters

The tangential velocity of the ISS is the speed at which it travels along the circumference of its orbit. The radius of the ISS's orbit is the distance from the center of the Earth to the ISS.

In this case, the tangential velocity of the ISS is 7.66 kilometers per second. The radius of the ISS's orbit is 6371 kilometers. Therefore, the angular velocity of the ISS is:

ω = 7.66 km/s / 6371 km = 0.012 rad/s

b) Calculate the height above the Earth’s surface at which the ISS orbits.

The height above the Earth's surface at which the ISS orbits can be calculated using the following formula:

h = r * (1 - (1 - e^2)^(1/2))

where:

h is the height above the Earth's surface in meters

r is the radius of the Earth in meters

e is the eccentricity of the orbit

The eccentricity of the ISS's orbit is 0.016. Therefore, the height above the Earth's surface at which the ISS orbits is:

h = 6371 km * (1 - (1 - 0.016^2)^(1/2)) = 408 km

c) Calculate the tangential (linear) speed the ISS must travel to maintain this orbit.

The tangential speed of the ISS can be calculated using the following formula:

v = ω * r

where:

v is the tangential speed in meters per second

ω is the angular velocity in radians per second

r is the radius of the orbit in meters

The angular velocity of the ISS is 0.012 rad/s. The radius of the ISS's orbit is 6371 kilometers. Therefore, the tangential speed of the ISS is:

v = 0.012 rad/s * 6371 km = 7.66 km/s

rounded to the nearest whole number: 7 km/s

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the radius of the sphere is 6.125 cm.

Given,

The least count (vernier constant) of a slide caliper = 0.01 cm

Main scale reading = 12.2 cm

Vernier coincidence = 5 cm

Formula to find the radius of the sphere

Radius of the sphere = (main scale reading + vernier coincidence × least count of vernier scale) ÷ 2

So,Radius of the sphere = (12.2 cm + 5 cm × 0.01 cm) ÷ 2

= (12.2 cm + 0.05 cm) ÷ 2

= 6.125 cm

Hence, the radius of the sphere is 6.125 cm.

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