: Question 20 2 pts Consider the following code: double lengthArr[50] = { 5.5, 6.4, 7.3, 8.1, 9.9, 11, 12.1 }; double* dptr = lengthArr; while ( *dptr ) cout << *dptr++ << endl; cout << *dptr << endl; What is the last value output by the last cout statement? Question 23 1 pts Which of the following ignores leading whitespace when reading into a variable, like val2? getchar(val2); get(val2); cin >> val2; getlinel cin, val2); cin.get(val2)

Answer:

A. Yes, it will run

B. X will not replace any value

Explanation:

A. Will it run?

First, the algorithm can be interpreted in python as follows:

#Set Minimum to 1

MINIMUM = 1

#For every element X in the list L

for X in L:

#If current element X is less than MINIMUM

    if X < MINIMUM:

#Set MINIMUM to X

         MINIMUM = X

#Print MINIMUM

print(MINIMUM)

The algorithm will run without error because it follows the right sequence and has no syntax error

B. Will X replace any value?

No, it won't

The smallest positive integer is 1.

So, setting the MINIMUM to 1 means that the value of X in the list will not replace the MINIMUM because the MINIMUM has already been set

Answer:

liquifid gas

Explanation:

when gas is introduced to a certain chemical it ends up slowly liquifying itself.

Thomas is checking an electrical wire in a washroom with a wet floor. Ground-fault circuit interrupters in the electrical wire will help prevent electrical shock.

The ground-fault circuit interrupter, or GFCI, is a quick-response circuit breaker that may cut off electricity in as little as 1/40 of a second in the event of a ground fault.

It compares the current flowing into and out of the machinery along the conductors of the circuit.

Therefore, electrical shock can be avoided with the aid of ground-fault circuit interrupters in the electrical line.

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The type of fire extinguisher that would be used on an electric motor that has overheated and caught fire is a CO² fire extinguisher.

CO² fire extinguishers should be used to put out electrical fires. They assist to smother the fire and prevent it from spreading by displacing the oxygen in the air while leaving no residue and so being safe to electrical equipment.

Whenever there is a case of fire from electricity, water is not used in such conditions, this is because water is a good conductor of electricity. If the water comes in contact with the electricity it can cause new problems.

Therefore, the type of fire extinguisher that would be used on an electric motor that has overheated and caught fire is a CO² fire extinguisher.

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Relationship between two variables.

The experimental research in psychology aims to analyze the relationships between the various variables. There are two variables such s independent and the dependent variable. The independent in the manipulated variable. Depended is measurable.

Thus the two variables are independent and dependent.

Thus the two variables can be recorded by the psychologist.

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Although most V welding machines are usually hardwired into a building’s electrical system, some electrical codes permit them to be plugged into special wall receptacles. This can provide more flexibility in the placement of the machine and make it easier to move around if necessary.

V welding machines are powerful tools used for welding metals together. They are typically designed to operate on a high voltage and amperage electrical system. In most cases, V welding machines are hardwired into a building's electrical system, which means they are permanently connected to the electrical supply.

However, some electrical codes permit V welding machines to be plugged into special wall receptacles. This can provide more flexibility in the placement of the machine and make it easier to move around if necessary. The receptacles used for V welding machines are designed to handle the high voltage and amperage requirements of the machine, and they are usually labeled to indicate that they are intended for this specific use.

Before plugging a V welding machine into a wall receptacle, it is important to check local electrical codes and ensure that the receptacle is properly rated to handle the voltage and amperage requirements of the welding machine. This will help to prevent electrical hazards and ensure that the machine operates safely and efficiently. Additionally, it is important to ensure that the machine is grounded to prevent electrical shock and damage to the equipment.

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Answer:

by hìuuf5ëcz

Explanation:

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The actual dimensions for the given nominal dimensions 1x2 stick of lumber, a 2x4 stick of lumber are;

Actual dimension of 1 x 2 stick of lumber = ³/₄'' × 3¹/₂''

Actual dimension of 2 x 4 stick of lumber = 1¹/₂'' × 3¹/₂''

The nominal dimension for a sheet of plywood is; 4' x 8'

Lumber sticks are sticks made from timber in forms used mainly in building construction as formwork support for the sheets of plywood used.

There could also be other uses of lumber sticks like making of some basic home furniture's but they are primarily used in building construction.

Now, Lumber sticks could come in different nominal dimensions such as;

Now, in the question, we are dealing with 1x2 stick of lumber and a 2x4 stick of lumber. From general cutting standards in most workshops, the actual sizes are respectively;

Actual size of 1 x 2 stick of lumber = ³/₄'' × 3¹/₂''

Actual size of 2 x 4 stick of lumber = 1¹/₂'' × 3¹/₂''

Now, for a sheet of plywood, the standard size of a sheet of plywood is 4' × 8'.

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Answer:

measures, dissolves, liquid, carbon dioxide, evaporates, water vapor, mold, decompose

A regulator is required on a nitrogen cylinder in order to reduce very high pressure within the gas cylinder to a safer pressure.

A regulator can be defined as a mechanical device that is designed and developed to ensure that a controlled amount of nitrogen gas is supplied from a gas cylinder.

This ultimately implies that, a regulator is required on a nitrogen cylinder in order to reduce very high pressure within the gas cylinder to a safer pressure.

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If a weight of 24,000 lb is supported on a rectangular baseplate that is 9-in wide and 2-ft long and the baseplate rests on a concrete slab, then the stress exerted by the baseplate on the concrete slab is approximately 515,200 lb/ft².

To determine the stress that the baseplate exerts on the concrete slab, we can use the formula for stress:

Stress (σ) = Force (F) / Area (A)

First, let's convert the weight of 24,000 lb to force in pounds by multiplying by the acceleration due to gravity (g) which is approximately 32.2 ft/s^2:

F = 24,000 lb * 32.2 ft/s² = 772,800 lb

Next, let's convert the width of the baseplate from inches to feet:

Width (w) = \(\frac{9}{12} = 0.75\) ft

The length of the baseplate is given as 2 ft.

Now, we can calculate the area of the rectangular baseplate:

Area (A) = Length (L) * Width (W) = 2 ft * 0.75 ft = 1.5 ft²

Finally, we can plug the values of force and area into the stress formula to calculate the stress exerted by the baseplate on the concrete slab:

Stress (σ) = Force (F) / Area (A) = \(\frac{772,800}{1.5} $\approx$ 515,200\) lb/ft²

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B

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Default argument is the correct option among the given alternatives. The functionality of an automatically assumed zero payment when the user doesn't enter the amount paid is an example of a default argument.

What is a default argument? A default argument is a value assigned to an argument in a function definition in Python. If the user doesn't provide a value for the argument in a function call, the default value is used. It's important to note that the default argument is the last argument in the parameter list. The following is the syntax: Syntax: def function name(parameter1, parameter2=default value):The default argument is assigned a value during the function definition process. When the function is called, the user may supply a different value for the argument. When the function is called without any arguments, the default value is used. This is the functionality that is seen in the given code, which is the example of a default argument. The write amount() function is defined with two arguments, name and amount, the latter of which is assigned a default value of 0. If the user does not supply a value for amount when calling write amount(), the default value of 0 is used. This is a typical use of default arguments in Python.

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Answer:

Explanation:

Answer: With crumple zones at the front and back of most cars, they absorb much of the energy (and force) in a crash by folding in on itself much like an accordion. ... As Newton's second law explains force = Mass x Acceleration this delay reduces the force that drivers and passengers feel in a crash.Sep 30, 2020

steam tables or thermodynamic software and verify the accuracy of the specific enthalpy and internal energy values for water vapor, as well as the properties of air, to ensure precise calculations.

In the given problem, two separate scenarios are described. Let's address each scenario individually.

Scenario 1: Water vapor cooling at constant volume

Starting with water vapor at 2.0 MPa and 300 °C, it is cooled at constant volume until the temperature drops to 150 °C. At the end of the process, we need to find the dryness fraction and the specific internal energy of the saturated liquid-vapor mixture.

To determine the dryness fraction, we need to calculate the quality (x) of the mixture, which represents the mass fraction of vapor present. The dryness fraction can be calculated using the equation:

x = (h - hf) / (hg - hf),

where h is the specific enthalpy of the mixture, hf is the specific enthalpy of the saturated liquid at the final temperature, and hg is the specific enthalpy of the saturated vapor at the final temperature.

The specific internal energy (u) of the saturated liquid-vapor mixture can be determined using the equation:

u = (x * u g) + ((1 - x) * u f),

where ug is the specific internal energy of the saturated vapor at the final temperature, and uf is the specific internal energy of the saturated liquid at the final temperature.

Scenario 2: Compressed air in a cylindrical tank

Given a compressed air pressure of 400 kPa, a tank diameter of 0.3 m, a height of 1.5 m, and the specific gas constant (R) for air as 0.287 kJ/kg·K, we need to find the mass and specific weight of the compressed air.

To determine the mass of the compressed air, we can use the ideal gas law:

PV = mRT,

where P is the pressure, V is the volume of the tank, m is the mass, R is the specific gas constant, and T is the temperature.

The specific weight (γ) can be calculated by dividing the weight (W) of the air by the volume (V) of the tank:

γ = W / V.

By substituting the known values into the equations and performing the necessary calculations, the mass and specific weight of the compressed air can be determined.

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Answer:

Explanation:

The image attached to the question is shown in the first diagram below.

From the diagram given ; we can deduce a free body diagram which will aid us in solving the question.

IF we take a look at the second diagram attached below ; we will have a clear understanding of what the free body diagram of the system looks like :

From the diagram; we can determine the length of BC by using pyhtagoras theorem;

SO;

\(L_{BC}^2 = L_{AB}^2 + L_{AC}^2\)

\(L_{BC}^2 = (3.5+2.5)^2+ 4^2\)

\(L_{BC}= \sqrt{(6)^2+ 4^2}\)

\(L_{BC}= \sqrt{36+ 16}\)

\(L_{BC}= \sqrt{52}\)

\(L_{BC}= 7.2111 \ m\)

The cross -sectional of the cable is calculated by the formula :

\(A = \dfrac{\pi}{4}d^2\)

where d = 4mm

\(A = \dfrac{\pi}{4}(4 \ mm * \dfrac{1 \ m}{1000 \ mm})^2\)

A = 1.26 × 10⁻⁵ m²

However, looking at the maximum deflection  in length \(\delta\) ; we can calculate for the force \(F_{BC\) by using the formula:

\(\delta = \dfrac{F_{BC}L_{BC}}{AE}\)

\(F_{BC} = \dfrac{ AE \ \delta}{L_{BC}}\)

where ;

E = modulus elasticity

\(L_{BC}\) = length of the cable

Replacing 1.26 × 10⁻⁵ m² for A; 200 × 10⁹ Pa for E ; 7.2111 m for \(L_{BC}\) and 0.006 m for \(\delta\) ; we have:

\(F_{BC} = \dfrac{1.26*10^{-5}*200*10^9*0.006}{7.2111}\)

\(F_{BC} = 2096.76 \ N \\ \\ F_{BC} = 2.09676 \ kN\)     ---- (1)

Similarly; we can determine the force \(F_{BC}\) using the allowable  maximum stress; we have the following relation,

\(\sigma = \dfrac{F_{BC}}{A}\)

\({F_{BC}}= {A}*\sigma\)

where;

\(\sigma =\) maximum allowable stress

Replacing 190 × 10⁶ Pa for \(\sigma\) ; we have :

\({F_{BC}}= 1.26*10^{-5} * 190*10^{6} \\ \\ {F_{BC}}=2394 \ N \\ \\ {F_{BC}}= 2.394 \ kN\)     ------ (2)

Comparing (1) and  (2)

The magnitude of the force \(F_{BC} = 2.09676 \ kN\) since the elongation of the cable should not exceed 6mm

Finally applying the moment equilibrium condition about point A

\(\sum M_A = 0\)

\(3.5 P - (6) ( \dfrac{4}{7.2111}F_{BC}) = 0\)

\(3.5 P - 3.328 F_{BC} = 0\)

\(3.5 P = 3.328 F_{BC}\)

\(3.5 P = 3.328 *2.09676 \ kN\)

\(P =\dfrac{ 3.328 *2.09676 \ kN}{3.5 }\)

P = 1.9937 kN

Hence; the maximum load P that can be applied is 1.9937 kN

Here is an example code segment in Python that uses the os module to list all the items (files and directories) in the current working directory and prints their names:

python

Copy code

import os

# Get the current working directory

cwd = os.getcwd()

# List all the items in the directory

items = os.listdir(cwd)

# Print the name of each item

for item in items:

   print(item)

This code first gets the current working directory using os.getcwd(). It then uses os.listdir() to obtain a list of all the items (both files and directories) in the directory and stores them in the items variable. Finally, it loops through each item in the items list and prints its name using print().

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The weight of a dry-rodded unit is typically 98.6 lb/ft3.

By dividing the volume of air to the total volume, the percentage of air voids in the soil is calculated. The percentage is used to express this. In a fully saturated state, the fraction of air gaps in the soil is zero. where Va = Air Volume.

To determine the typical dry-rodded unit weight:

To start, figure out how much the coarse aggregate weighs in each trial:

Trial 1 = 76.6 lb - 20.3 lb = 56.3 lb

Trial 2 = 75.1 lb - 20.3 lb = 54.8 lb

Trial 3 = 78.8 lb - 20.3 lb = 58.5 lb

Next, calculate the average weight of the coarse aggregate:

(56.3 lb + 54.8 lb + 58.5 lb) / 3 = 56.5 lb

Finally, calculate the average dry-rodded unit weight:

Unit weight = (56.5 lb) / (1/2 ft3) = 113 lb/ft3

Therefore, the average dry-rodded unit weight is 113 lb/ft3.

b. To calculate the percent voids between aggregate particles for each trial:

First, calculate the weight of the saturated surface-dry aggregate:

Wet weight = weight of bucket filled with saturated coarse aggregate - weight of empty bucket

Trial 1: 92.3 lb - 20.3 lb = 72 lb

Trial 2: 90.8 lb - 20.3 lb = 70.5 lb

Trial 3: 94.5 lb - 20.3 lb = 74.2 lb

Dry weight = wet weight / bulk dry specific gravity

Trial 1: 72 lb / 2.620 = 27.48 lb

Trial 2: 70.5 lb / 2.620 = 26.88 lb

Trial 3: 74.2 lb / 2.620 = 28.30 lb

Next, calculate the volume of the bucket filled with saturated surface-dry aggregate:

Volume = 1/2 ft3

Finally, calculate the percent voids between aggregate particles for each trial:

Percent voids = (1 - (Dry weight / (Unit weight x Volume))) x 100%

Trial 1: (1 - (27.48 lb / (113 lb/ft3 x 1/2 ft3))) x 100% = 60.8%

Trial 2: (1 - (26.88 lb / (113 lb/ft3 x 1/2 ft3))) x 100% = 62.3%

Trial 3: (1 - (28.30 lb / (113 lb/ft3 x 1/2 ft3))) x 100% = 58.5%

Therefore, the percent voids between aggregate particles for each trial are:

Trial 1: 60.8%

Trial 2: 62.3%

Trial 3: 58.5%

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Answer:

FOLLOWED BY...  2 6 5 3 5 8 9

UwU

The given fields E = E₀ cos(x) cos(tey) and H = (E₀/μ₀) sin(x) sin(tez) do not simultaneously satisfy Maxwell's equations.

To determine whether the given fields E = E₀ cos(x) cos(tey) and H = (E₀/μ0) sin(x) sin(tez) simultaneously satisfy Maxwell's equations.

we need to verify if they satisfy both the differential and integral forms of the equations.

Maxwell's equations in their differential form are:

∇ · E = ρ/ε₀ (Gauss's law for electric fields)Calculating the divergence of E, we have:

∇ · E = ∂/∂x(E₀ cos(x) cos(tey)) + ∂/∂y(E₀ cos(x) cos(tey)) + ∂/∂z(E₀ cos(x) cos(tey))

Differentiating each component with respect to the respective variable, we obtain:

∇ · E = -E₀ sin(x) cos(tey)

Since the right-hand side is not equal to ρ/ε₀, this equation is not satisfied.

∇ · H = 0 (Gauss's law for magnetic fields)

Calculating the divergence of H, we have:

∇ · H = ∂/∂x((E₀/μ₀) sin(x) sin(tez)) + ∂/∂y((E₀/μ₀) sin(x) sin(tez)) + ∂/∂z((E₀/μ₀) sin(x) sin(tez)).

Differentiating each component with respect to the respective variable, we obtain:

∇ · H = 0

Since the right-hand side is zero, this equation is satisfied.

∇ × E = -∂H/∂t (Faraday's law of electromagnetic induction)

Calculating the curl of E, we have:

∇ × E = ∂/∂y(E₀ cos(x) cos(tey)) - ∂/∂z(E₀ cos(x) cos(tey)) - ∂/∂t(E₀ cos(x) cos(tey))

Differentiating each component with respect to the respective variable, we obtain:

∇ × E = -E₀ sin(x) sin(tez) - 0 - 0

Simplifying this expression, we have:

∇ × E = -E₀ sin(x) sin(tez)

Now let's calculate the partial derivative of H with respect to time (-∂H/∂t):

-∂H/∂t = -(∂/∂t((E₀/μ₀) sin(x) sin(tez))) = -E₀/μ₀ cos(x) sin(tez)

The equation -∂H/∂t is not equal to ∇ × E, so this equation is not satisfied.

∇ × H = ∂E/∂t (Ampere's law with Maxwell's addition).

Calculating the curl of H, we have:

∇ × H = ∂//∂y((E₀/μ₀) sin(x) sin(tez)) - ∂/∂z((E₀/μ₀) sin(x) sin(tez)) + ∂/∂t((E₀/μ₀) sin(x) sin(tez))

Differentiating each component with respect to the respective variable, we obtain:

∇ × H = E₀/μ₀ cos(x) cos(tez) + 0 + 0

Simplifying this expression, we have:

∇ × H = E₀/μ₀ cos(x) cos(tez)

Now let's calculate the partial derivative of E with respect to time (∂E/∂t):

∂E/∂t = ∂/∂t(E₀ cos(x) cos(tey)) = -E₀ sin(x) sin(tey)

The equation ∇ × H is not equal to ∂E/∂t, so this equation is not satisfied.

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a)  The initial and final temprature are 99.61°C and T3 = 259.07°C

b)   The mass of liquid water when the piston first start moving is 0g

Using the data provided:

Initial Pressure = P1 = 125kPa

Mass of Saturated Vapor Liquid = m = 5kg

Initial Mass of Liquid water = mf = 2kg

Initial Mass of Vapor = mg = 3kg

The temperature for a mixture of liquid steam saturated with water according to the thermodynamic table is:

T₁ = 99.61°C

The specific volume is:

vf = 0.001043m³/kg

And the saturated volume is:

vg = 1.6941m³/kg

Therefore, the volume in state 1 will be equal to:

V1 = mfvf + mgvg

V1 = (2kg)(0.001043m³/kg) + (3kg)(1.6941m³/kg)

V1 = 5.084m³

In state 3 then the volume will be equal to:

V3 = 1.2V1

V3 = 1.2(5.084m³)

V3 = 6.1008m³

Then the specific volume will be equal to:

v3 = V₃/m

v3 = 6.1008m³/5kg

v3 = 1.2202m³/kg

For a pressure of 300 kPa and the previous specific volume found through the thermodynamic table, the value of the temperature is:

T3 = 259.07°C

Question b) When the piston first stats moving at P₂ = 300kPa and V₂ = V₁ = 5.084m³

v₂ =V₂/m

v₂ = 5.084m³/5kg

v2 = 1.0168m³/kg

While at 300 kPa the value of the vapor saturated vg = 0.88578m³/kg This implies that the condition is met:

v2 > vg

Therefore, no liquid is there in-cylinder when piston stats moving, mf = 0kg

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Answer:

The HTML ul tag is used for the unordered list. There can be 4 types of bulleted list: To represent different ordered lists, there are 4 types of attributes in <ul> tag. This is the default style. In this style, the list items are marked with bullets.

Answer:

Ordered

\({ \tt{ < ol > .... < / ol > }}\)

Unordered

\({ \tt{ < ul > .... < /ul > }}\)

Using the knowledge of computational language in C++ it is possible to write a code that user-input value is the number of nodes in the linked list

#include "MileageTrackerNode.h"

#include <string>

#include <iostream>

using namespace std;

int main(int argc, char *argv[]) {

   // References for MileageTrackerNode objects

   MileageTrackerNode *headNode;

   MileageTrackerNode *currNode;

   MileageTrackerNode *lastNode;

   double miles;

   string date;

   // Front of nodes list

   headNode = new MileageTrackerNode();

   lastNode = headNode;

   // Read in the number of nodes

   int no_nodes;

   cin >> no_nodes;

   // For the read in number of nodes, read in data and insert into the linked list

   MileageTrackerNode *tail = headNode;

   for (int i = 0; i < no_nodes; ++i) {

       double milesInit;

       cin >> milesInit;

       cin >> date;

       MileageTrackerNode *newNode = new MileageTrackerNode(milesInit, date, nullptr);

       tail->InsertAfter(newNode);

       tail = newNode;

   }

   // Call the PrintNodeData() method to print the entire linked list

   MileageTrackerNode *cur = headNode->GetNext();

   while (cur != nullptr) {

       cur->PrintNodeData();

       cur = cur->GetNext();

   }

   // MileageTrackerNode Destructor deletes all following nodes

   delete headNode;

}

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Ew Wakefield Hospital has only one portable X-ray machine. The emergency room staff claim to have the greatest need for the machine, but the surgeons in the operating room demand ready access to the machine. The conflict between these two groups is a result of scarcity.

Science and technology are the driving forces behind today's modern medicine, allowing us to identify and treat a range of medical problems. X-ray technology has had a significant impact on medicine, and it is commonly used to diagnose various diseases, making it an essential tool for hospitals.

Despite the advantages, the scarcity of portable X-ray machines creates difficulties for hospital employees, including a dispute between the emergency room and the operating room staff at Ew Wakefield Hospital. There is only one portable X-ray machine available at Ew Wakefield Hospital.

The conflict between the emergency room and the operating room staff is a result of scarcity. Both departments require ready access to the X-ray machine. Scarcity can generate rivalry, competition, and conflict when people and organizations compete for the same resource.

The staff's conflict is a direct result of the lack of accessibility to the X-ray machine. Thus, scarcity can be a significant factor contributing to interpersonal conflict.

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Answer:

Core analysis reports often show depths broken into increments of 1/2 feet because it provides a more detailed and accurate representation of the geologic layers present in the subsurface. By breaking the depth into smaller increments, geologists can more accurately depict the thickness and distribution of different geologic units and identify any changes or variations within those units. This can be especially important in cases where the geology is complex or there are small variations in the subsurface that could have significant impacts on the exploration or development of a resource.

In some cases, core analysis reports may show depths in whole feet rather than 1/2 feet. This is usually done when the geology is relatively simple and there are no significant variations within the geologic units being analyzed. In these cases, showing the depths in whole feet may be sufficient to accurately represent the geology and meet the needs of the project.

Ultimately, the decision to show depths in 1/2 feet or whole feet will depend on the specific needs of the project and the complexity of the geology being analyzed. Both approaches can be useful for different purposes and it is important to choose the one that is most appropriate for the task at hand.

a) The following options for structuring the contents of the invitations:- Unique key value- Time and date of the event- A message from Alice- The URL for the event- A unique QR code

b) The Process of Alice sending invitations to her friends:

Here is how Alice can send the invitations to her friends:

1. Alice can log in to PrivateOccasionZ.com.

2. Alice can access the section that allows her to generate invitations.

3. Alice can input the email addresses of her friends.

4. Alice can customize the invitations as required.

5. Alice can hit the send button to transmit the invitations.

6. Alice's friends will receive the invitations in their email inboxes.

7. Alice can also provide her friends with the unique URL or QR code if required.

c) The process of invitees gaining access to (coming into) the party: Here's the process of invitees gaining access to the party:

1. The invitee clicks on the URL sent to them by Alice or scans the QR code on their invitation.

2. This will take them to PrivateOccasionZ.com.

3. The website will require the invitee to input the unique key value from their invitation to gain access.

4. After inputting the correct unique key value, the invitee will gain access to the party.

5. PrivateOccasionZ.com will not be able to identify the invitee since they have not been asked to provide their name or other personal details.

d) Show that if an invitation is forwarded to someone else they would not be able to use it: If an invitation is forwarded to someone else, they will not be able to use it since the unique key value on the invitation would have been used by the original invitee. When the new recipient tries to access the party using the unique key value on the invitation, they will be denied access since the key value would have already been used.

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Answer:

A

Explanation:

Answer:

The following are the answer to this question:

Explanation:

In point a, Calculating the are of flow:

\(\bold{Area =B \times D_f}\)

         \(=6\times 5\\\\=30 \ ft^2\)

In point b, Calculating the wetter perimeter.

\(\bold{P_w =B+2\times D_f}\)

      \(= 6 +2\times (5)\\\\= 6 +10 \\\\=16 \ ft\)

In point c, Calculating the hydraulic radius:

\(\bold{R=\frac{A}{P_w}}\)

   \(=\frac{30}{16}\\\\= 1.875 \ ft\)

In point d, Calculating the value of Reynolds's number.

\(\bold{Re =\frac{4VR}{v}}\)

     \(=\frac{4V \times 1.875}{1 \times 10^{-5} \frac{ft^2}{s}}\\\\\)

     \(=750,000 V\)

Calculating the velocity:

\(V= \sqrt{\frac{8gRS}{f}}\)

   \(= \sqrt{\frac{8\times 32.2 \times 1.875 \times 0.02}{f}}\\\\=\frac{3.108}{\sqrt{f}}\\\\\)

\(\sqrt{f}=\frac{3.108}{V}\\\\\)

calculating the Cole-brook-White value:

\(\frac{1}{\sqrt{f}}= -2 \log (\frac{K}{12 R} +\frac{2.51}{R_e \sqrt{f}})\\\\ \frac{1}{\frac{3.108}{V}}= -2 \log (\frac{2 \times 10^{-2}}{12 \times 1.875} +\frac{2.51}{750,000V\sqrt{f}})\\\)

\(\frac{V}{3.108} =-2\log(8.88 \times 10^{-5} + \frac{3.346 \times 10^{-6}}{750,000(3.108)})\)

After calculating the value of V it will give:

\(V= 25.18 \ \frac{ft}{s^2}\\\)

In point a, Calculating the value of Froude:

\(F= \frac{V}{\sqrt{gD}}\)

\(= \frac{V}{\sqrt{g\frac{A}{\text{Width flow}}}}\\\)

\(= \frac{25.18}{\sqrt{32.2\frac{30}{6}}}\\\\= \frac{25.18}{\sqrt{32.2 \times 5}}\\\\= \frac{25.18}{\sqrt{161}}\\\\= \frac{25.18}{12.68}\\\\= 1.98\)

The flow is supercritical because the amount of Froude is greater than 1.  

Calculating the channel flow rate.

\(Q= AV\)

   \(=30x 25.18\\\\= 755.4 \ \frac{ft^3}{s}\\\)