Que ingrediente le falta completar y cuánto para preparar los alfajores?

The polar bear has a birth weight of 0.5 kilogram.

The linear equation is y = x + 0.4t

Given,

The weight gained by polar bear each week after it was born = 0.4 kg

The weight of polar bear after 3 weeks = 1.7 kilo grams

We have to write an linear equation to represent this ;

Here,

y be the weight of polar bear

x be the initial weight

t be the number of week.

So,

the equation be like;

y = x + 0.4t

Then,

1.7 = x + 0.4 x 3

x = 1.7 - 1.2 = 0.5

The polar bear has a birth weight of 0.5 kilogram.

The linear equation is y = x + 0.4t

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42.57 x 46630= 75769 =3794874 =37489438790=3474936

3(3x−5)

(3 times 3x)(3 times -5)

9x-15

Since you don't know what x is, you can't simplify it any more than this.

Hey there!

Use the Distributive Property to simplify the expression 3(3x - 5) :

9x - 15 ✅

- Distributive Property :

A(B - C) = AB - BC

- Given expression :

3(3x - 5)

>> Distribute the 3 to the 3x and to the 5 :

3(3x - 5)

= 3*3x - 3*5

Therefore, your answer is 9x - 15 .

Have a good day ;)

The candy distributor needs to use 30 kilograms of 10% fat-content chocolate and 70 kilograms of 50% fat-content chocolate to create 100 kilograms of a 14% fat-content chocolate.

To solve this problem, we can use the method of mixture problems, which involves setting up a system of equations. Let x be the number of kilograms of the 10% fat-content chocolate and y be the number of kilograms of the 50% fat-content chocolate.

We have two equations based on the fat content and the total weight of the mixture:

0.1x + 0.5y = 0.14(100) (equation for fat content)

x + y = 100 (equation for total weight)

We can solve this system of equations using substitution or elimination. Using substitution, we can solve for x in terms of y from the second equation and substitute it into the first equation:

x = 100 - y

0.1(100 - y) + 0.5y = 0.14(100)

10 - 0.1y + 0.5y = 14

0.4y = 4

y = 10

Then we can substitute y = 10 back into the equation for x and get:

x = 100 - y = 100 - 10 = 90

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The acceleration is 2 m/s²

The first step is to write out the parameters given in the question

Acceleration is the rate at which an object changes its velocity over time.

The formula to calculate the acceleration is v²= u² + 2as10²= 0² + 2(a)(25)100= 2a(25)100= 50a

Divide both sides by the coefficient of a which is 50

100/50 =  50a/50

a= 2

Hence the acceleration of the object is 2 m/s²

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Determine the y-intercept of the equation -x + 2y = 10

a. 1

b.-10

C. 5

d. 2

__________________________________________

y-intercept is (0, b)

y = mx +b

-x + 2y = 10

2y = x +10

y = 1/2 x + 5

______________

if x= 0

y= 1/2 *0 +5

y= 5

____________________

The y-intercept is (0, 5 )

The answer is c

Answer:

120

Step-by-step explanation:

5!, called 5 factorial is the product of all positive intergers from 5 down though 1. by definition, 0! is 0.

Factorials are basically the number times itself-1 the 2 the 3 until it times it by itself-(itself-1). n!=n*(n-1)*n(n-2).....*n-(n-1).

For example 2!=2*1=2 and 6!=6*5*4*3*2*1=720

keep in mind that I am not an expert so the blanks I filled in might be wrong and the explanation might have errors

5!, called "5 factorial," is the product of all positive integers from 5 down through 1. By definition, 0! is equal to 1.

Factorial is a mathematical operation denoted by an exclamation mark (!). It represents the product of all positive integers from a given number down to 1. In the case of 5!, it is calculated as 5 × 4 × 3 × 2 × 1, resulting in the value of 120.

The exclamation mark notation allows us to represent the factorial of a number concisely. For example, 5! represents the factorial of 5. It is important to note that 0! is defined to be equal to 1. This is a special case in factorial calculations. While it may seem counterintuitive, it is defined this way to maintain consistency and enable certain mathematical calculations and formulas.

Therefore, 5! is the product of all positive integers from 5 down through 1, equaling 120, and 0! is defined to be 1.

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Answer:

Step-by-step explanation:

Answer:

Rate of growth = 88

Initial value = 1600

Step-by-step explanation:

The given equation is an exponential function.

An exponential function is used to calculate the exponential growth or decay of a given set of data.  In an exponential function, the variable is the exponent.

\(\boxed{\begin{minipage}{9 cm}\underline{General form of an Exponential Function}\\\\$y=ab^x$\\\\where:\\\phantom{ww}$\bullet$ $a$ is the initial value ($y$-intercept). \\ \phantom{ww}$\bullet$ $b$ is the base (growth/decay factor) in decimal form.\\\end{minipage}}\)

Given equation:

\(y=1600(88)^x\)

The given equation is an exponential function where:

Therefore, the initial value of the equation is 1600.

As b > 1, the function represents exponential growth, and the growth factor is 88. This means that for each increase of one unit in the independent variable (x), the dependent variable (y) will be multiplied by 88.

The value of P(0) and P(6) of The Polynomial Function above are 2 and 253/2 respectively.

Polynomial function refers to the algebraic expression that consists of several terms.

Polynomial function can be of different degrees, like linear polynomial (degree 1), quadratic polynomial (degree 2), cubic polynomial (degree 3), and so on.

The given polynomial function is P(w) = 6w² - 20w + 2.

To find P(6), substitute w = 6 in P(w).

Therefore,P(6) = 6(6)² - 20(6) + 2P(6) = 6(36) - 120 + 2P(6) = 216 - 120 + 2P(6) = 96

Adding P(6) = 349 to this equation, we get:2P(6) = 349 - 96 = 253

Therefore, P(6) = 253/2

Now, to find P(0), substitute w = 0 in P(w).

Therefore, P(0) = 6(0)² - 20(0) + 2 = 2

Therefore, P(0) = 2

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Answer:

from what I remember ide say A

The anagrams that can be created from the word accommodate is N=4989600.

An anagram is a word or phrase made by rearranging the letters of another word or phrase, often using all of the original letters exactly once.

The original word or phrase is known as the anagram's subject. An anagram is any word or phrase that exactly duplicates the letters in a different order. An "anagrammatist" is someone who makes anagrams, and the purpose of a serious or expert anagrammatist is to make anagrams that reflect or remark on their subject.

Given word is

'accommodate'

Total number of letters= 11

Number of a = 2

c=2

m=2

0=2

The rest are one each.

Therefore, the number of possible arrangements can be written as;

N = 11!/(2!2!2!2!)

N = 39916800/8

N=4989600

Therefore, the anagrams that can be created from the word accommodate is N=4989600.

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Given logistic differential equation of population of meerkats, dP/dt = -0.002P^2 + 6P,Let us solve the differential prism equation for dP/dt to find the population of the meerkats when it is growing the fastest:At maximum, dP/dt = 0

Therefore, 0 = -0.002P^2 + 6PPutting 0 on one side,6P = 0.002P^2Divide both sides by P,6 = 0.002PTherefore, P = 3000 (population of meerkats when it is growing the fastest)Now, let us find the limit P(t) as t approaches infinity; that is, when the population stops growinglim P(t) = limit as t approaches infinity of the population P(t)Solving the logistic differential equation for P(t) by separation of variables,We get,∫(1/(K - P) dP) = ∫(-0.002 dt)Solving the integration,log(K - P) = -0.002t + C,where C is the constant of integration.At t = 0, P = P0

Then, C = log(K - P0)Therefore,log(K - P) = -0.002t + log(K - P0)log((K - P)/(K - P0)) = -0.002tTaking the antilog of both sides of the equation,(K - P)/(K - P0) = e^(-0.002t)Therefore, K - P = (K - P0) e^(-0.002t)Solving for P,We get,P = K - (K - P0) e^(-0.002t)As t approaches infinity, e^(-0.002t) approaches 0Hence, P approaches KTherefore, lim P(t) = K = 2000The value of the dt constant k for the logistic differential equation of the termite population dP/dt = KP - 0.0001P^2 with carrying capacity K = 2000 is given by dP/dt = KP - 0.0001P^2Given, K = 2000Also, dP/dt = KP - 0.0001P^2,So, dP/dt = K (1 - 0.0001(P/K)^2) = KP (1 - (P/20,000)^2)Therefore, the value of the constant k is 0.02 (option B).

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Answer:

5/9

Step-by-step explanation:

we add all of the values and divide by the total number in this case 9, all of them add to make 5 so we do 5÷9 to get 5/9

Let G be a cyclic group of order n and let a be an element in G. Since G is cyclic, there exists an element g in G such that every element in G can be written as some power of g. In other words, G = {g^0, g^1, g^2, ..., g^(n-1)}.

Now consider the order of the element a. Let k be the smallest positive integer such that a^k = e (the identity element). We know that such a k exists because a is finite and so its powers will eventually repeat.

Since G is cyclic, we can write a = g^m for some integer m. Then, by the properties of exponents, we have:

(a^n)^m = (g^mn)^n = g^(mnn) = g^(nmn) = (g^n)^m = e^m = e

Therefore, (a^n)^m = e. But since k is the smallest positive integer such that a^k = e, we must have k dividing mn. This implies that k divides n, since gcd(k,m)=1 (because otherwise k would not be the smallest possible value for which a^k=e). Hence, we have:

a^n = (a^k)^(n/k) = e^(n/k) = e

Therefore, for any element a in a cyclic group G of order n, we have aⁿ = e.

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Graphing the equation 3x - 2y = -6 over the range x = -10 to x = 10:

To graph the equation 3x - 2y = -6, we need to rearrange it in the form y = mx + b, where m is the slope and b is the y-intercept.

3x - 2y = -6

-2y = -3x - 6

Divide both sides by -2:

y = (3/2)x + 3

Now we have the equation in slope-intercept form.

To graph the equation, we can plot a few points and draw a line through them. Let's choose some x-values from the range -10 to 10 and find the corresponding y-values.

For x = -10:

y = (3/2)(-10) + 3

y = -15 + 3

y = -12

For x = 0:

y = (3/2)(0) + 3

y = 0 + 3

y = 3

For x = 10:

y = (3/2)(10) + 3

y = 15 + 3

y = 18

Plotting these points (-10, -12), (0, 3), and (10, 18) on the graph and drawing a line through them, we get the graph of the equation 3x - 2y = -6.

Using the graphical method to solve the pair of equations:

The given equations are:

10x = 5y

-3x + y = 1

To solve these equations graphically, we need to plot their graphs on the same coordinate plane and find the point where they intersect, which represents the solution.

Rearranging the second equation in slope-intercept form:

y = 3x + 1

Now we have the equations in the form y = mx + b.

Plotting the graphs of the equations 10x = 5y and y = 3x + 1, we can find the point of intersection, which represents the solution to the system of equations.

The point of intersection is the solution to the system of equations.

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No, a fraction is not a term. The distributive property can be applied to fractions because it is a general mathematical principle.

A fraction is not considered a term in the traditional sense. It is a mathematical expression that represents division. However, the distributive property can still be applied to fractions because the property itself is a fundamental rule of arithmetic that extends beyond specific types of expressions.

The distributive property states that for any real numbers a, b, and c:

a × (b + c) = (a × b) + (a × c).

When working with fractions, we can apply the distributive property as follows:

Let's consider the expression: a × (b/c).

We can rewrite this as: (a × b)/c.

Now, let's distribute the 'a' to 'b' and 'c':

(a × b)/c = (a/c) × b.

In this step, we applied the distributive property to the fraction (a/c) by treating it as a whole.

Although fractions represent division, we can still use the distributive property because it is a general mathematical principle that allows for manipulating expressions involving addition, subtraction, multiplication, and division.

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The value of IQR is 90 when box plot data where Q₁ = 200, Q₂ = 250, and Q₃ = 290.

Given that,

For box plot data where Q₁ = 200, Q₂ = 250, and Q₃ = 290

We have to find the data of IQR.

We know that,

IQR is define as the variation in the distribution of your data's middle quartile is measured by the interquartile range (IQR). It is the range that corresponds to your sample's middle 50%. Measure the variability where the majority of your numbers are by using the IQR.

IQR Formula is Q₃ - Q₁

So,

Q₃ = 290

Q₁ = 200

Then ,

IQR = Q₃ - Q₁

IQR = 290 - 200

IQR = 90

Therefore, The value of IQR is 90.

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Answer:

A=a+b

2h

Step-by-step explanation:

b). Ca^ 2+. is the correct option. Ammonium oxalate is added to a solution containing a mixture of ions, a white solid appears. Based on this result Ca^ 2+. is most likely to be present in the solution.

Ammonium oxalate is used as a reagent to identify calcium ions. Calcium ions, when mixed with ammonium oxalate, form a white precipitate.

Therefore, based on the white solid appearing, the ion that is most likely to be present in the solution is b.) Ca^ 2+.

What is ammonium oxalate? Ammonium oxalate is a white crystalline solid with the chemical formula C2H8N2O4, which is the ammonium salt of oxalic acid.

The salt is highly soluble in water and is used as a reducing agent, a mordant for dyes, and a reagent for the identification of calcium. It is a solid, white in color, and is readily soluble in water.

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Step-by-step explanation:

when 2 lines cross, the angles on one side of one of these lines are mirrored to the other side.

and crossing a second, parallel line creates exactly the same angles there too, because crossing the second line is like crossing the first line. otherwise the 2 lines are not parallel. the second line is just a shifted version of the first line (and vice versa). all the other attributes are the same.

and all angles around a single point on one side of a line are together 180°.

because of all that,

angle 2 = angle 3 = angle 6 = angle 7 = 76°

angle 1 = angle 4 = angle 5 = angle 8 = 180-76 = 104°

We will use Equation (5.9) of Fourier transform analysis to calculate the Fourier transforms of the given sequences: (a) (½)^(n-1)u[n-1] and (b) (½)^|n-1|. F(ω) = Σ (½)^(n-1)e^(-jωn) for n = 1 to ∞.  F(ω) = Σ (½)^(n-1)e^(-jωn) for n = -∞ to ∞

(a) To calculate the Fourier transform of (½)^(n-1)u[n-1], we substitute the given sequence into Equation (5.9). Considering the definition of the unit step function u[n-1] (which is 1 for n ≥ 1 and 0 for n < 1), we can rewrite the sequence as (½)^(n-1) for n ≥ 1 and 0 for n < 1. Thus, we obtain the Fourier transform as:

F(ω) = Σ (½)^(n-1)e^(-jωn)

Evaluating the summation, we get:

F(ω) = Σ (½)^(n-1)e^(-jωn) for n = 1 to ∞

(b) To calculate the Fourier transform of (½)^|n-1|, we again substitute the given sequence into Equation (5.9). The absolute value function |n-1| can be expressed as (n-1) for n ≥ 1 and -(n-1) for n < 1. Thus, we have the Fourier transform as:

F(ω) = Σ (½)^(n-1)e^(-jωn) for n = -∞ to ∞

In both cases, the specific values of the Fourier transforms depend on the range of n considered and the values of ω. Further evaluation of the summations and manipulation of the resulting expressions may be required to obtain the final forms of the Fourier transforms for these sequences.

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There are 380 ways to determine the first and second place in the race.

In a race, there are 20 runners. Trophies for the race are awarded to the runners finishing in first and second place. In how many ways can first and second place be determined?When the trophies for the race are awarded to the runners finishing in first and second place, then it means that there are only two trophies to be awarded. Now, the number of ways in which the two trophies can be awarded can be calculated by permutation, which is a way of counting the arrangements or selections of objects in which order is important.

To determine the number of ways first and second place can be determined in a race with 20 runners, we can use the concept of permutations.

The first-place finisher can be any one of the 20 runners. After the first-place finisher is determined, there are 19 remaining runners who can finish in second place. Therefore, the number of ways to determine the first and second place is given by:

Number of ways = 20 * 19 = 380

So, there are 380 ways to determine the first and second place in the race.

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9514 1404 393

Answer:

  x = 44.5

Step-by-step explanation:

The angles defined by x will be supplementary when the lines m and n are parallel.

  (x +4) +(3x -2) = 180

  4x +2 = 180

  4x = 178

  x = 44.5 . . . . will make m and n parallel

The perimeter of square ABCD is 28 units.

The perimeter of a square is the sum of all its sides. In this case, we need to find the perimeter of square ABCD.

The question provides two possible answers: 28 units and 37 units. However, we can only choose one correct answer. To determine the correct answer, let's think step by step.

A square has all four sides equal in length. Therefore, if we know the length of one side, we can find the perimeter.

If the perimeter of the square is 28 units, that would mean each side is 28/4 = 7 units long. However, if the perimeter is 37 units, that would mean each side is 37/4 = 9.25 units long.

Since a side length of 9.25 units is not a whole number, it is unlikely to be the correct answer. Hence, the perimeter of square ABCD is most likely 28 units.

In conclusion, the perimeter of square ABCD is 28 units.

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The answer is B. x = 12

First, you must set up the equation.

\(4x+11=6x-13\)

Then, you must subtract 6x on both sides.

\(-2x+11=-13\)

Next, subtract 11 on both sides.

\(-2x=-24\)

Finally, divide -2 on both sides.

\(x=12\)

Answer:

c

Step-by-step explanation:

C=2πr=2·π·2≈12.56637

Answer:

25.14

Step-by-step explanation:

formula is 2πr^2.

Answer:

Does the answer help you?

Answer:

If the area is 169 cm squared, and this is a square, the side length is the square root of 169 or 13 cm (centimeters).