​Quadrilateral ABCD​ is inscribed in this circle.
What is the measure of angle C?
Enter your answer in the box.

The profit margin made by True Blue Vintage Toy Company is; 0.3 or 30%

A profit margin is defined as a profitability ratio that can tell you whether a company makes money. It highlights what portion of the company's sales have turned into profits or how many cents per dollar it generates per sale.

Now, the parameters given are;

Selling price = #40

Profit = $12

Thus;

Cost price = 40 - 12 = $28

Profit margin = (40 - 28)/40

= 0.3 or 30%

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Answer:

Volume of prism = 6.3 cm³

Step-by-step explanation:

Given:

Dimensions of parallels line = 2.3 and 1.2 cm

Height of prism = 1.8 cm

Width of prism = 2 cm

Find:

Volume of prism

Computation:

Volume of prism = Area of base x Width

Volume of prism = [(1/2)(sum of parallels line)(Height)]Width

Volume of prism = [(1/2)(2.3 + 1.2)(1.8)]2

Volume of prism = [(1/2)(3.5)(1.8)]2

Volume of prism = [(3.5)(1.8)]

Volume of prism = 6.3 cm³

The value of (f-g)(2) is 16, provided that Megan has made no mistakes in the calculation.

The problem asks us to compute the value of (f - g)(2) where f(x) = 3x^2 - 2x + 4 and g(x) = x^2 - 5x + 2.

The notation (f - g)(2) means that we need to subtract g(x) from f(x) and then evaluate the result at x = 2. We can do this as follows:

(f - g)(x) = f(x) - g(x) = (3x^2 - 2x + 4) - (x^2 - 5x + 2) = 2x^2 + 3x + 2

Substituting x = 2, we get:

(f - g)(2) = 2(2)^2 + 3(2) + 2 = 16

Therefore, the value of (f - g)(2) is 16.

It's worth noting that the problem statement mentions "what did she do wrong?" without providing any context or information about what Megan did or didn't do. So, it's not possible to identify any error in Megan's solution based on the given information. However, based on the correct computation above, we can be sure that (f - g)(2) is indeed equal to 16.

In other words, it can be described as,

The error in Megan's solution is not clear from the given statement. However, it seems that she may have made an error while computing (f-g)(2).

To compute (f-g)(2), we need to subtract g(2) from f(2) as follows:

f(2) = 3(2)^2 - 2(2) + 4 = 12

g(2) = (2)^2 - 5(2) + 2 = -4

Therefore, (f-g)(2) = f(2) - g(2) = 12 - (-4) = 16. is the final conclusion.

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The answer is A.To find the average value of a function f(x) on a closed interval [a,b], we use the formula:

1/(b-a) ∫[a,b] f(x) dx

In this case, we need to find the average value of the function f(x) = (x² + x) cos(5x) on the closed interval [2,6]. So, we plug in the values of a and b:

1/(6-2) ∫[2,6] (x² + x) cos(5x) dx

Simplifying this expression, we get:

1/4 ∫[2,6] (x² + x) cos(5x) dx

Now, we need to evaluate the integral. We can use integration by parts to do this:

u = (x² + x)   dv = cos(5x) dx
du/dx = 2x + 1   v = (1/5) sin(5x)

∫(x² + x) cos(5x) dx = (x² + x)(1/5) sin(5x) - ∫(2x + 1)(1/5) sin(5x) dx

= (x² + x)(1/5) sin(5x) - (2/25) cos(5x) - (1/25) x sin(5x) + C

Plugging in the limits of integration, we get:

1/4 [(6² + 6)(1/5) sin(30) - (2/25) cos(30) - (1/25) (6) sin(30) - (2² + 2)(1/5) sin(10) + (2/25) cos(10) + (1/25) (2) sin(10)]

Simplifying this expression, we get:

-7.392

So, the average value of f(x) on the closed interval [2,6] is -7.392. Therefore, the answer is A.

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ANSWER:

A polynomial is an algebraic expression of ordered addition, subtraction, and multiplication made up of variables, constants, and exponents.

Polynomials are made up of finite terms. Each term is an expression that contains one or more of the three elements they are made of variables, constants, or exponents.

In this case, for each term, the variable is x, the constant is 1, and the exponents are 5, 2, and 1, respectively.

This means that we have a sum of monomials, that is, that the expression is a polynomial.

a. The initial amount of money deposited into the account is $1575.

b. The annual interest rate being paid on the account is 4.5%.

c. The amount of money in the account after 15 years is approximately $2946.27.

d. It will take approximately 20 years for the account to reach a balance of at least $4000.

To answer these questions, let's analyze the given equation:

A(1) = 1575 * (1.045)^t

a. The initial amount of money deposited into the account is $1575. This is evident from the equation, where A(1) represents the amount of money after 1 year.

b. To determine the annual interest rate, we can compare the given equation with the general formula for compound interest:

A = P * (1 + r)^t

Comparing the two equations, we can see that the interest rate in the given equation is 4.5% (0.045) since (1 + r) is equal to 1.045.

c. To find the amount of money in the account after 15 years, we can substitute t = 15 into the equation and calculate the result:

A(15) = 1575 * (1.045)^15 ≈ $2946.27 (rounded to the nearest dollar)

Therefore, after 15 years, the amount of money in the account will be approximately $2946.

d. To find the number of years it will take for the account to have at least $4000, we need to solve the equation for t. Let's set up the equation and solve for t:

4000 = 1575 * (1.045)^t

To solve this equation, we can take the logarithm of both sides (with base 1.045):

log(4000) = log(1575 * (1.045)^t)

Using logarithm properties, we can simplify the equation:

log(4000) = log(1575) + log((1.045)^t)

log(4000) = log(1575) + t * log(1.045)

Now, we can isolate t by subtracting log(1575) from both sides and then dividing by log(1.045):

t = (log(4000) - log(1575)) / log(1.045)

Calculating this expression, we find:

t ≈ 19.56 (rounded to two decimal places)

Therefore, it will take approximately 20 years (rounded to the nearest whole year) for the account to have at least $4000.

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The amount of the sum Rs 1200 for one and a half year at 40 percent of interest compounded quarterly is Rs 1893.09.

The amount of the sum Rs 1200 for one and a half year at 40 percent of interest compounded quarterly can be calculated as follows:

Given, Principal = Rs 1200Time = 1.5 yearsInterest rate = 40% per annum, compounded quarterly

Let r be the quarterly rate of interest. Then we can convert the annual interest rate to quarterly interest rate using the following formula: \text{Annual interest rate} = (1 + \text{Quarterly rate})^4 - 1$$

Substituting the values, we get:0.40 = (1 + r)^4 - 1 Solving for r, we get:r = 0.095 or 9.5% per quarter

Now, we can use the formula for the amount of money after time t, compounded quarterly: $A = P \left( 1 + \frac{r}{4} \right)^{4t}

Substituting the values, we get:A = Rs 1200 x $\left(1 + \frac{0.095}{4} \right)^{4 \times 1.5}= Rs 1893.09

Therefore, the amount of the sum Rs 1200 for one and a half year at 40 percent of interest compounded quarterly is Rs 1893.09.

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Answer: 1436.8

Step-by-step explanation:

V= (4/3)*π*(7^3) = 1436.8

The question tells us to use 3 for pi.

And the radius is 7cm.

\(V = \frac{4}{3} *3*7^3\)

Answer:

I think it's c sorry if im wrong

Answer:

It is (D)

\(f(x) = \frac{ - 1}{2} x + 6\)

Step-by-step explanation:

I hope that is useful for you

Answer:

sec theta

Step-by-step explanation:

we have this as follows;

cos theta +cos theta tan^2 theta

= cos theta (1 + tan^2 theta)

Recall;

1 + tan^2 theta = sec^2 theta

= sec^2 theta * cos theta

Recall;

sec theta = 1/ cos theta

= 1/cos theta * cos theta * 1/cos theta

= 1/cos theta = sec theta

The equation of the line passing through (4, 7) and at a distance of 1 unit from the origin is y = (7/4)x.

To find the equation of a line passing through the point (4, 7) and at a distance of 1 unit from the origin, we can follow these steps:

Step 1: Determine the slope of the line.

Since the line passes through the origin (0, 0) and a point (4, 7), we can calculate the slope using the formula: slope = (y2 - y1) / (x2 - x1).

Let's substitute the coordinates:

slope = (7 - 0) / (4 - 0) = 7/4.

Step 2: Find the equation of the line.

We know that the line passes through the point (4, 7). Using the point-slope form of the equation, which is y - y1 = m(x - x1), where (x1, y1) is the point and m is the slope, we can substitute the values:

y - 7 = (7/4)(x - 4).

Step 3: Simplify the equation.

To simplify the equation, we can distribute the slope:

y - 7 = (7/4)x - 7.

Rearrange the equation to isolate y:

y = (7/4)x - 7 + 7.

Simplify further:

y = (7/4)x.

Therefore, the equation of the line passing through (4, 7) and at a distance of 1 unit from the origin is y = (7/4)x.

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the answer is 3x²

Step-by-step explanation:

we know that k = 3x

when we look at the actual equasion we can se that y = kx, meaning we have to multiply x by 3x which would give us 3x²

Answer:  the answer is 3x^2 three x to the power of 2

Answer:a

Step-by-step explanation:a cult

The process of adding the matrix is explained blow.

Matrices are powerful tools used to analyze data and solve complex equations.

A 3x3 matrix, or E₁₃, is a matrix composed of 3 rows and 3 columns. It can be used to perform various operations, including adding two rows together.

(a) To answer the first question, a 3x3 matrix E₁₃ can add row 3 to row 1 by performing a row operation. This involves taking the second row and adding it to the first, thus adding the values on each row together.

(b) To answer the second question, a 3x3 matrix E₁₃ can add row 1 to row 3 and at the same time add row 3 to row 1 by performing a row exchange operation. This results in a 3x3 matrix where each value in the first row is equal to the corresponding value in the third row.

(c) To answer the third question, a 3x3 matrix E₁₃ can add row 1 to row 3 and then add row 3 to row 1 by performing two separate row operation and then taking the third row and adding it to the first, thus adding the values of each row together again.

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Answer:

+sqrt(29)

Step-by-step explanation:

Note that the change in x (horizontal leg) is 8 - 6, or 2, and that the change in y (vertical leg) is |2 - 7|, or 5.  According to the Pythagorean Theorem, the length of the hypotenuse of the right triangle created here is:

distance = +sqrt(2^2 + 5^2), or +sqrt(29)

The central limit theorem tells us that the distribution of the sample mean will be approximately normal if the sample size is sufficiently large. This information can be used to calculate the standard error and construct confidence intervals.

The sampling distribution of the sample mean is approximately normally distributed.

This statement is true. When the sample size is large\((n ≥ 30),\) the sampling distribution of the sample mean is approximately normally distributed. The sample mean is the mean of the sample's measurements, while the sampling distribution of the sample mean is the distribution of all possible sample means with a particular sample size.The central limit theorem guarantees that the sampling distribution of the sample mean is approximately normal if the sample size is large enough. This is due to the fact that the distribution of the population is not necessary. This theorem allows us to use the normal distribution in inferential statistics, making it an important theorem in statistics. When the sample size is less than 30, it is appropriate to use the t-distribution instead of the normal distribution because the t-distribution takes into account the extra uncertainty generated by the smaller sample size.The sampling distribution is critical to statistical inference because it helps us estimate population parameters by making inferences based on sample statistics. For instance, suppose we want to know the mean salary of all the employees in a firm. We could take a random sample of employees and calculate their average salary.

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The 98% confidence interval for the population mean (μ) is approximately (2.711, 3.009).

1: Identify the given data

Sample size (n) = 150 students

Sample mean (x) = 2.86

Population standard deviation (σ) = 0.78

Confidence level = 98%

2: Find the critical z-value (z*) for a 98% confidence level

Using a z-table or calculator, you'll find that the critical z-value for a 98% confidence level is 2.33 (approximately).

3: Calculate the standard error (SE)

SE = σ / √n

SE = 0.78 / √150 ≈ 0.064

4: Calculate the margin of error (ME)

ME = z* × SE

ME = 2.33 × 0.064 ≈ 0.149

5: Construct the confidence interval

Lower limit = x - ME = 2.86 - 0.149 ≈ 2.711

Upper limit = x + ME = 2.86 + 0.149 ≈ 3.009

The 98% confidence interval is approximately (2.711, 3.009).

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Answer:

True

Step-by-step explanation:

Answer:

true

Step-by-step explanation:

just took the test

Answer:

1 neither

2 neither

3 neither

Step-by-step explanation:

p = number of pages written before today

p+16 = number of pages written currently

p+16 > 50

p+16-16 > 50-16

p > 38

Carl had written more than 38 pages, but less than 50 pages, before today.

For example, he could have written p = 40 pages

p+16 = 40+16 = 56 which fits the description of "more than 50".

Something like p = 30 doesn't work since

p+16 = 30+16 = 46 which comes up short.

The inequality that represents the situation is x + 16 > 50 and the solution is x > 34.

In mathematics, "inequality" refers to a relationship between two expressions or values that are not equal to each other.

Given, Carl wrote 16 pages today,

bringing hi total number of page written to more than 50.

Let x be the number of pages he wrote before today.

And we have the inequality,

x + 16 > 50

To solve the inequality, you may multiply or divide each side by the same positive number, add the same amount to each side, take the same amount away from each side, and more. You must flip the inequality sign if you multiply or divide either side by a negative number.

Subtract 16 on both sides.

x > 34

Therefore, he wrote more than 34 pages before today.

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Answer:

528,672

Step-by-step explanation:

A=P(1+r)^t

360,000(1+.03)^13 = 528,672.1368

Rounded: 528,672

Answer:

-2

Step-by-step explanation:

the equation of a function/line is y=mx+b where

b is the y intercept

m is the slope

The weight of the astronaut with gear on the moon is 80 pounds.

The pull of gravity is different on Earth than on the Moon as gravity depends on factors such as the mass of the celestial body, the radius of the celestial body, and the density of the celestial body.

The pull of gravity on Earth = 10 m/s²

Thus, Given:

Weight of object on Earth: 25 pounds

Weight is described as the product of mass and the acceleration due to gravity

Thus, 25 = 10 * mass

mass = 2.5 unit

Weight of the object on the Moon: 4 pounds

4 = 2.5 * acceleration due to gravity on the moon

Acceleration due to gravity on the moon = 1.6 m/s²

Weight of astronaut with gear on earth = 500 pounds

500 = mass * 10

mass = 50 units

Weight of astronaut with gear on earth = 50 * 1.6

= 80 pounds

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The probability that the sample mean will be within plus minus 2 of the population mean if the sample size is n = 100 between z-scores of 0 and 2.5 using a z-table.

The standard deviation of the sample distribution, commonly known as the standard error, can be computed using the formula given that the population mean is 100 and the standard deviation is 16:

Standard Error = Standard Deviation / sqrt(sample size)

Let's determine the likelihoods for sample sizes of n = 100 and n = 400:

For n = 100:

Standard Error = 16 / sqrt(100) = 16 / 10 = 1.6

We can determine the z-scores for the upper and lower boundaries to establish the likelihood that the sample mean will be within plus or minus 2 of the population mean:

Lower Bound z-score = (Sample Mean - Population Mean) / Standard Error

Lower Bound z-score = (100 - 100) / 1.6

Lower Bound z-score = 0

Upper Bound z-score = (Sample Mean - Population Mean) / Standard Error

Upper Bound z-score = (104 - 100) / 1.6

Upper Bound z-score = 4 / 1.6

Upper Bound z-score = 2.5

We can calculate the region under the normal distribution curve between z-scores of 0 and 2.5 using a z-table or statistical software. This shows the likelihood that the sample mean will be within +/- 2 standard deviations of the population mean.

For n = 400:

Standard Error = 16/√400

Standard Error = 16/20

Standard Error = 0.8

We determine the z-scores by following the same procedure as above:

Lower Bound z-score = (Sample Mean - Population Mean) / Standard Error

Lower Bound z-score = (100 - 100) / 0.8

Lower Bound z-score = 0

Upper Bound z-score = (Sample Mean - Population Mean) / Standard Error

Upper Bound z-score = (104 - 100) / 0.8

Upper Bound z-score = 4 / 0.8

Upper Bound z-score = 5

Once more, we may determine the region under the normal distribution curve between z-scores of 0 and 5 using a z-table or statistical software.

A larger sample size, like n = 400, has the benefit of a lower standard error. The sampling distribution of the sample mean will be more constrained and more closely resemble the population mean if the standard error is less.

As a result, there is a larger likelihood that the sample mean will be within +/- 2 of the population mean. In other words, the estimate of the population mean gets more accurate and dependable as the sample size grows.

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The amount of the carbon dioxide that is present after 11 years is 18,711 metric tons.

We know that the production of the carbon dioxide can be modelled as an exponential function and the  way that the amount of the carbon dioxide can be reducing is then shown by;

A(x) = Ae^rx

Where the rate of the emission is shown as r and the time taken is shown as x

A(x) = 87,280e^-0.14 * 11

A(x) = 18,711 metric tons

Thus the amount is cut down to 18,711 metric tons.

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Answer:

20 points

Step-by-step explanation:

We need to find how many points x a student needs to score on a test worth 50 points to get a test score of 40%.

Let x be the number of points.

ATQ,

\(\dfrac{x}{50}=\dfrac{40}{100}\\\\x=\dfrac{50\times 40}{100}\\\\x=20\)

Hence, a student needs 20 points to get a score of 40%.

The volume of the box with surface area 10 is given by the formula V = 2.5x^2 - 0.25x^4, where x is the length of a side of the square base.

To find a formula for the volume of the box with surface area A and square base with side x, we first need to find the height of the box. Since the box has a square base, the area of the base is x^2. The remaining surface area is the sum of the areas of the four sides, each of which is a rectangle with base x and height h. Therefore, the surface area A is given by:

A = x^2 + 4xh

Solving for h, we get:

h = (A - x^2) / 4x

The volume V of the box is given by:

V = x^2 * h

Substituting the expression for h, we get:

V = x^2 * (A - x^2) / 4x

Simplifying, we get:

V = (Ax^2 - x^4) / 4

The domain of V is all non-negative real numbers, since both x^2 and A are non-negative.

To graph V as a function of x, we can use a graphing calculator or plot points using a table of values. The graph will be a parabola opening downwards, with x-intercepts at 0 and sqrt(A) and a maximum at x = sqrt(A) / sqrt(2).

To find the maximum value of V, we can take the derivative of V with respect to x and set it equal to 0:

dV/dx = (2Ax - 4x^3) / 4

Setting this equal to 0 and solving for x, we get:

x = sqrt(A) / sqrt(2)

Plugging this value of x into the formula for V, we get:

V = A^1.5 / (4sqrt(2))

Therefore, the maximum value of V is A^1.5 / (4sqrt(2)).

To find the formula for the volume of a box having surface area 10, we simply replace A with 10 in the formula we derived earlier:

V = (10x^2 - x^4) / 4

Simplifying, we get:

V = 2.5x^2 - 0.25x^4

Therefore, the volume of the box with surface area 10 is given by the formula V = 2.5x^2 - 0.25x^4, where x is the length of a side of the square base. The domain of V is all non-negative real numbers.

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