problem 24.52 what is the electric field strength at a point inside the insulation that is 1.0 mm from the axis of the wire?
Answers
The electric field strength (E) at a point inside the insulation that is 1.0 mm (0.001 m) from the axis of the wire can be calculated using the formula: \(E = (k * Q) / r^2\)
1. In the formula, E represents the electric field strength.
2. k is the electrostatic constant, which is approximately \(8.99*10^{9} N{m^{2}/{C^{2} }\).
3. Q is the charge on the wire.
4. r is the distance from the axis of the wire, which is 1.0 mm (0.001 m) in this case.
However, to provide a precise answer, we need to know the charge (Q) on the wire. Once we have this information, we can plug the values into the formula and calculate the electric field strength.
To find the electric field strength at a point inside the insulation that is 1.0 mm from the axis of the wire, we need to know the charge on the wire. Once we have this information, we can use the formula \(E = (k * Q) / r^2\)to calculate the electric field strength.
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Related Questions
A cyclist is riding his bike up a mountain trail. When he starts up the trail, he is going 8 m/s. As the trail gets steeper, he slows to 3 m/s in 1 minute. What is the cyclist’s acceleration? –0.08 m/s2 0.08 m/s2 –12 m/s2 12 m/s2
Answers
Answer:
-0.08m/s²
Explanation:
consider an experimental setup where charged particles (electrons or protons) are first accelerated by an electric field and then injected into a region of constant magnetic field with a field strength of 0.55 t.
What is the potential difference in volts required in the first part of the experiment to accelerate electrons to a speed of 6 1 × 107 m/s?
Answers
The potential difference in volts required in the first part of the experiment to accelerate electrons to a speed of 6.1 × 107 m/s is 73 kV.
What is potential difference?Potential difference is the amount of energy that is required to move a unit charge through an electric field from one point to another. The unit of potential difference is volts (V), and it is a scalar quantity. It is also known as voltage or electric potential difference.
The formula for calculating potential difference is as follows: Potential difference (V) = work done (J) / charge (C) or
V = W / Q,
where W is the work done and Q is the charge involved in the process
Work done is given as: W = F × d × cosθ
where, F is the force, d is the displacement, and θ is the angle between the force and the displacement.
Therefore, V = (F × d × cosθ) / Q
Field strength = 0.55 T
Charge on the electron, -e = 1.6 × 10¹⁹ C
Mass of the electron, me = 9.1 × 10⁻³¹ kg
Speed of the electron = 6.1 × 10⁷ m/s
The electric field (E) is given as: E = V / d
F = Q × E = -e × V/d = -1.6 × 10⁻¹⁹ × V / 0.5 = -3.2 x 10⁻¹⁹ × V N
θ = 0° (as the force and displacement are parallel)
W = F × d × cosθ = F × d = -3.2 × 10⁻¹⁹ × V × 0.5 = -1.6 × 10⁻¹⁹ × V J
Now, the kinetic energy (KE) of the electron is given as: KE = 1/2 mv²
Substituting the values, we get: KE = 1/2 mev² = 1/2 × 9.1 × 10⁻³¹ × (6.1 × 10⁷)² = 2.8 × 10⁻¹⁷ J
As the work done by the electric field is equal to the kinetic energy of the electron, we can equate the values:
1.6 × 10⁻¹⁹ × V = 2.8 × 10⁻¹⁷
Solving for V, we get: V = -2.8 × 10⁻¹⁷ / -1.6 × 10⁻¹⁹
V = 175 V
Therefore, the potential difference in volts required in the first part of the experiment to accelerate electrons to a speed of 6.1 × 10⁷ m/s is 175 V.
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5). A body of mass 75kg lying on a surface of
μ = 0.4 move in the direction of a horizontal force
of 300N applied to it.
a). Calculate the
i). friction force
ii). acceleration of the body
b). Explain the result in aii).
Answers
Explanation:
a) i) Calculation of the friction force:
The friction force can be determined using the equation:
friction force = coefficient of friction * normal force
The normal force is equal to the weight of the object, which can be calculated as:
normal force = mass * gravitational acceleration
where the gravitational acceleration is approximately 9.8 m/s².
normal force = 75 kg * 9.8 m/s² = 735 N
friction force = 0.4 * 735 N = 294 N
ii) Calculation of the acceleration of the body:
Now, we can calculate the acceleration using Newton's second law:
net force = mass * acceleration
Since the applied force and the friction force act in opposite directions, the net force can be calculated as:
net force = applied force - friction force
net force = 300 N - 294 N = 6 N
mass = 75 kg
6 N = 75 kg * acceleration
acceleration = 6 N / 75 kg = 0.08 m/s²
b) Explanation:
In part (a), we calculated the friction force to be 294 N and the acceleration of the body to be 0.08 m/s². The positive acceleration indicates that the body is moving in the direction of the applied force.
The friction force opposes the motion of the body and acts in the opposite direction to the applied force. In this case, the applied force of 300 N is greater than the friction force of 294 N. As a result, the net force acting on the body is 6 N in the direction of the applied force.
The small net force of 6 N, compared to the body's mass of 75 kg, results in a relatively low acceleration of 0.08 m/s². This indicates that the body will accelerate slowly in the direction of the applied force due to the presence of friction.
Overall, the friction force and the resulting acceleration of the body are determined by the coefficient of friction (μ) and the mass of the object. In this case, the body experiences a relatively high friction force, leading to a small acceleration.
Why don't we see objects in the universe colliding or moving towards each other due to gravitational force?
Answers
Answer:
the objects in the universe are evenly placed. This means that a celestial object's gravity may not be able to attract another object. Another reason may be that the stars in solar systems act as points of equilibrium for the planets in the system. Take for example the sun. It maintains the position of the planets in the system and likewise the earth maintains the position of the moon. You can picture it as evenly placed atoms in matter and the subsequent electrons held by the nucleus
Answer:
BECAUSE OF THE DISTANCEBETWEEN EACH OBJECT DECREASES THE CHANCE IN SEEING OBJECTS COLIDE. HOPE THIS HELPS ...
if heat rises why is it colder at higher altitudes
Answers
The statement "heat rises" is not accurate in explaining the temperature decrease with altitude.
The main reason why it is colder at higher altitudes is because of the decrease in air pressure with increasing altitude. As air rises in the atmosphere, the pressure decreases, and this decrease in pressure is accompanied by a decrease in temperature. It is known as adiabatic cooling.
When air molecules rise to higher altitudes, they expand due to the lower atmospheric pressure. As the air expands, it does work against the surrounding air molecules, leading to a decrease in its internal energy and, consequently, a drop in temperature. This adiabatic cooling causes the temperature to decrease with increasing altitude.
In summary, the decrease in temperature with higher altitudes is primarily due to adiabatic cooling resulting from the expansion of air as it rises and experiences lower atmospheric pressure.
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A 4. 90- kg steel ball is dropped from a height of 13. 0 min to a box of sand and sinks 0. 700 minto the sand before stopping
Answers
The steel ball has an initial potential energy of 638 J, and it loses 280 J of kinetic energy as it sinks 0.700 m into the sand.
We can use the principle of conservation of energy to solve this problem. Initially, the steel ball has potential energy due to its height above the box of sand, and no kinetic energy. At the moment the ball hits the sand, all of its potential energy is converted to kinetic energy. As the ball sinks into the sand, some of its kinetic energy is converted to work done on the sand by the ball, which slows it down until it comes to a stop. At this point, all of the ball's kinetic energy has been converted to heat and sound energy.
Using the formula for gravitational potential energy, we can calculate the initial potential energy of the ball:
PE = mgh
PE = (4.90 kg)(9.81 m/s^2)(13.0 m)
PE = 638 J
This initial potential energy is equal to the kinetic energy of the ball just before it hits the sand:
KE = 1/2 m\(v^2\)
where v is the speed of the ball just before it hits the sand. Since the ball is dropped from rest, its initial speed is zero, and we can simplify the equation to:
KE = 1/2 \(mv^2\) = 1/2 (4.90 kg) \(v^2\)
Setting PE equal to KE and solving for v, we get:
v = √(2PE/m) = √(2gh) = √(2(9.81 m/\(s^2\))(13.0 m)) = 10.1 m/s
The ball sinks 0.700 m into the sand before stopping, so the work done by the ball on the sand is:
W = Fs
where F is the force exerted by the ball on the sand, and s is the distance over which the force is applied. Assuming the force is constant over the distance the ball sinks into the sand, we can approximate the force as:
F = ma
where a is the acceleration of the ball while it is sinking into the sand. We can calculate the acceleration using the formula:
\(v^2 = u^2 + 2as\)
where u is the initial velocity of the ball (10.1 m/s), v is its final velocity (zero), and s is the distance it sinks into the sand (0.700 m). Solving for a, we get:
a = (\(v^2 - u^2\)) / 2s = (0 - (10.1 m/s\()^2\)) / (2(0.700 m)) = -81.5 m/\(s^2\)
The negative sign indicates that the acceleration is in the opposite direction to the velocity of the ball (i.e. upward).
Using F = ma and the value of a we just calculated, we can find the force exerted by the ball on the sand:
F = ma = (4.90 kg)(-81.5 m/\(s^2\)) = -400 N
The negative sign indicates that the force is directed upward, opposite to the direction of the ball's motion.
Finally, we can calculate the work done by the ball on the sand:
W = Fs = (-400 N)(0.700 m) = -280 J
The negative sign indicates that the work is done by the ball on the sand, and is equal in magnitude to the decrease in the ball's kinetic energy as it sinks into the sand.
Therefore, the steel ball has an initial potential energy of 638 J, and it loses 280 J of kinetic energy as it sinks 0.700 m into the sand.
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Cross-training employees is only necessary in the genetic science industry.
O True
O False
Answers
Answer: False
Explanation:
Answer:
False
Explanation:
A slate falls from the roof of a height-rise building. Find how far it falls
a. In the first second
b. In the first two seconds
c. During the third second
Answers
In the first second, a slate drops from the roof of a tall building.
Explain about the seconds?Second is the standard unit of time in the International System of Units (SI) (s or sec). In decimal form, one cycle of radiation, or 9,192,631,770 (9.192631770 x 109), is equal to one second. This radiation is produced as the cesium-133 atom moves between two levels.
The symbol for a second, or s, is used to denote SI time. It is described as the fixed numerical value of the cesium frequency, vCs, which is the unaltered ground-state hyperfine transition frequency of the cesium 133 atom. The unit Hz, which is equivalent to s-1, is used to express this frequency. The second is the unit of time measurement.
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an electron is in the ground state of an infinite well (a box) where its energy is 5.00 ev. in the next higher level, what would its energy be? (1 ev
Answers
An electron is in the ground state of an infinite well (a box) where its energy is 5.00 ev. In the next higher level, its energy would be 20.25 eV.
In an infinite well, the energy levels of an electron are quantized, meaning they can only exist at certain discrete energy levels. The ground state is the lowest energy level an electron can occupy in the well. In this scenario, the electron is in the ground state with an energy of 5.00 eV.
To find the energy of the next higher level, we need to use the formula for the energy levels of an infinite well:
\(E_n = (n^2 * h^2) / (8mL^2)\)
where \(E_n\) is the energy of the nth level, n is the quantum number (which starts at 1 for the ground state), h is Planck's constant, m is the mass of the electron, and L is the length of the well.
To find the energy of the next level, we can substitute n = 2 into the equation:
\(E_2 = (2^2 * h^2) / (8mL^2)\)
Simplifying this equation, we get:
\(E_2 = (4 * 6.626 \times 10^{-34} J s)^2 / (8 * 9.109 \times 10^{-31 } kg * (L in meters)^2)\)
Converting the answer to eV, we get:
\(E_2\) = 20.25 eV
Therefore, the energy of the next higher level in the infinite well is 20.25 eV, which is a difference of 15.25 eV from the ground state energy of 5.00 eV.
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Parallel light rays cross interfaces from air into two different media, 1 and 2, as shown in the figures below. In which of the media is the light traveling faster and why?
Answers
Light travels faster in medium 2 because it has a lower refractive index compared to medium 1.
Light travels at different speeds in different materials, which is determined by their refractive index.
The refractive index is a measure of how much a material can bend light.
When parallel light rays cross interfaces from air into two different media, the angle of refraction changes.
The speed of light in the media is inversely proportional to the refractive index.
Therefore, the medium with the lower refractive index will have a faster speed of light.
In the figures provided, medium 2 has a lower refractive index compared to medium 1.
Hence, light travels faster in medium 2 than in medium 1.
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Light travels faster in medium 2 because it has a lower refractive index compared to medium 1.
Light travels at different speeds in different materials, which is determined by their refractive index.
The refractive index is a measure of how much a material can bend light.
When parallel light rays cross interfaces from air into two different media, the angle of refraction changes.
The speed of light in the media is inversely proportional to the refractive index.
Therefore, the medium with the lower refractive index will have a faster speed of light.
In the figures provided, medium 2 has a lower refractive index compared to medium 1.
Hence, light travels faster in medium 2 than in medium 1.
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if a constant counter-clockwise moment of 500 nm causes a rigid body to rotate counter-clockwise by 90 degrees, how much work is done by the applied moment?
Answers
The work done by the applied moment is 412,500 J.
Work done by an applied moment, we can use the formula for work:
Work = Force x Distance
In this case, the force applied is the moment of 500 nm, and the distance over which the force is applied is the distance that the rigid body rotates. The distance that the rigid body rotates is 90 degrees, which is equal to the angle of rotation.
The force applied by the moment can be calculated using the following equation:
Force = Moment x Distance
here Moment is the moment of 500 nm, and Distance is the distance over which the moment is applied.
The distance that the rigid body rotates is equal to the angle of rotation, so we can substitute this value into the equation for force to get:
Force = Moment x Distance = 500 x 90 = 45,000 Nm
To find the work done by the applied moment, we can multiply the force by the distance over which the force is applied.
Work = Force x Distance = 45,000 Nm x 90 degrees = 412,500 J
Therefore, the work done by the applied moment is 412,500 J.
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______ is the ability to cause changes in matter.
Answers
Answer:
Explanation:
Energy is defined as the ability to cause changes in matter. The energy of moving matter is called kinetic energy.
Can someone write how to determine the viscosity of glycerin by falling ball ?
Answers
Answer:-
The terminal velocity of a steel ball 2 mm in diameter falling through glycerin is 44×10 - ²
cm/s (Given that specific gravity of steel = 8, specific gravity of steel =8, specific gravity of glycerin a 1.3, viscosity of glycerine 8.3 poise.) .
A marble is launched, using a ramp off the edge of a table from a height of 0.8 m. The horizontal displacement of the marble when it strikes the floor is 1.8 m.
What was the initial velocity of the marble when it left the edge of the table?
O 1.98 m/s
O 4.45 m/s
• 6.30 m/s
O 6.45 m/s
Answers
The initial velocity of the marble when it left the edge of the table is 6.45 m/s.
To solve this problem, we can use the kinematic equation:
d = vit + 1/2at^2
where:
- d is the horizontal displacement of the marble (1.8 m)
- vi is the initial velocity of the marble (what we want to find)
- a is the acceleration due to gravity (-9.8 m/s^2)
- t is the time it takes for the marble to hit the floor
We can find t using the height from which the marble was launched:
h = 1/2gt^2
0.8 = 1/2(-9.8)t^2
t = √(0.8/4.9) ≈ 0.4 s
Now we can use the first kinematic equation to find vi:
1.8 = vi(0.4) + 1/2(-9.8)(0.4)^2
1.8 = 0.4vi - 0.784
2.584 = 0.4vi
vi = 6.46 m/s
Therefore, the initial velocity of the marble when it left the edge of the table was approximately 6.46 m/s. The closest answer choice is O 6.45 m/s.
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What would happen to a plastic pop bottle full of air if it were taken 1000 m below the surface of the ocean? What would happen to it if it were taken 10 000 m into the atmosphere? Explain your answer.
Answers
Answer:
if it were submerged 1000 m in the ocean it would be crushed because of the differences of the air and water pressure.
If it were taken 10,000 m (higher than Mt Everest) it would explode due to the differences of external and internal air pressures.
An object is moving with a force 30N then hits a wall to a stop in 0.5s.
a. Calculate the impulse.
b. What is the change in momentum of the object?
Answers
The impulse and change in momentum of an object moving with a force 30N then hits a wall to a stop in 0.5s is 15Ns.
How to calculate impulse?Impulse is the integral of force over time. It is calculated by multiplying the force applied by the time as follows:
∆p = Force × time
According to this question, an object is moving with a force 30N and then hits a wall to a stop in 0.5s.
Impulse = 30N × 0.5s = 15Ns
Therefore, the impulse and change in momentum of an object moving with a force 30N then hits a wall to a stop in 0.5s is 15Ns.
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in an experiment, disk x is held at rest above disk y that rotates about its center with a constant angular velocity. a student slowly lowers disk x onto disk y until both disks come into contact and rotate with a common angular velocity. the student collects the necessary data to graph the angular velocity of disk y as a function of time, as shown in the graph. both disks are identical. how can the student use the graph to determine the magnitude of the angular impulse on disk y ? select two answers.
Answers
To determine the magnitude of the angular impulse, we have to calculate the area under the curve and the slope of graph.
How to determine the magnitude of the angular impulse on diskThe magnitude of the angular impulse on disk y can be determined from the graph by:
1. Calculating the area under the curve: The impulse is equal to the change in angular momentum, which can be calculated by finding the area under the curve of the graph. The integral of the graph with respect to time will give the change in angular momentum, which can be used to determine the magnitude of the angular impulse.
2. Finding the slope of the graph: The slope of the graph represents the rate of change of angular velocity, which is equal to the angular acceleration of the system. The angular impulse can be calculated by multiplying the angular acceleration by the time over which it acts. Therefore, the magnitude of the angular impulse can be determined by finding the slope of the graph and multiplying it by the time over which the impulse acts.
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d;GIGEQDFw'ugs;iE.DHJFDELFFTOftedteo
Answers
Answer:
d;GIGEQDFw'ugs;iE.DHJFDELFFTOftedteo
Explanation:
thanks for the points
stay safe and god bless
Bronco the skydiver, whose mass is 80 kg experiences 200 N of air resistance and gravity pulls on him with 800 N What is the acceleration of his fall?
Answers
Bronco the skydiver, whose mass is 80 kg experiences 200 N of air resistance and gravity pulls on him with 800 N. The acceleration of his fall 7.5 m/sec².
What is force?A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
To find the acceleration,
F = mg
F = 80.(10)
F = 800 N
air resistance = 200 N
Net force = F - air resistance
= 800 - 200
= 600 N
600 = mass . acceleration
600 = 80 . acceleration
acceleration = 7.5 m/sec²
Bronco the skydiver, whose mass is 80 kg experiences 200 N of air resistance and gravity pulls on him with 800 N. The acceleration of his fall 7.5 m/sec².
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difference between effort distance and load distance
Answers
Answer:
Lever systems are simple machines that change or increase the input force that we apply to the load. The lever provides us with some mechanical...
Answer:
● Effort arm or Effort distance (ED): The perpendicular distance from the fulcrum to the point of effort is called effort arm.
● Load arm or Load distance (LD): The perpendicular distance from the fulcrum to the point of load is called load arm.
b. Two vectors with dimensions A = 5i + 3j + k and B = 4i + j + 2k are used for the following calculation. Determine: i. ii. iv. The dot product A.B. [2 marks] [3 Marks] The angle between vectors A and B. The cross product A XB. [2 marks] The area of the parallelogram spanned by the vectors A and B. [3 Marks]
Answers
The dot product is 25, the angle is \(\theta = cos^{-1} \frac{25}{\sqrt{35} \times \sqrt{21}}\), the cross product is 1i + (-6)j + (-7)k, and the area of the parallelogram spanned by vectors A and B is \(\sqrt{86}\).
Given,
A = 5i + 3j + k
B = 4i + j + 2k
i. Dot Product (A · B):
The dot product of two vectors A and B is given by the sum of the products of their corresponding components.
\(A.B = (A_x \times B_x) + (A_y \times B_y) + (A_z \times B_z)\\A.B = (5 \times 4) + (3 \times 1) + (1 \times 2) \\= 20 + 3 + 2 \\= 25\)
ii. Angle between vectors A and B:
The angle between two vectors A and B can be calculated using the dot product and the magnitudes of the vectors.
\(cos\theta = (A.B) / (|A| \times |B|)\\\theta = \frac{1}{cos} ((A.B) / (|A| \times |B|))\\A = \sqrt{(5^2 + 3^2 + 1^2)} =\\ \sqrt{35}\\B = \sqrt{(4^2 + 1^2 + 2^2)} \\= \sqrt{21}cos\theta = \frac{(A.B) / (|A| \times |B|)\\\theta = \frac{1}{cos} \frac{25}{\sqrt{35} \times \sqrt{21}}}\)
iv. Cross Product (A × B):
The cross product of two vectors A and B is a vector that is perpendicular to both A and B and its magnitude is equal to the area of the parallelogram spanned by A and B.
\(A\times B = (A_y \timesB_z - A_z \timesB_y)i + (A_z \timesB_x - A_x \timesB_z)j + (A_x \times B_y - A_y \times B_x)k\\A\times B = ((3 \times 2) - (1 \times 1))i + ((1 \times 4) - (5 \times 2))j + ((5 \times 1) - (3 \times 4))k\\= 1i + (-6)j + (-7)k\)
Area of the parallelogram spanned by vectors A and B:
The magnitude of the cross product A × B gives us the area of the parallelogram spanned by A and B.
Area = |A × B|
Area of the parallelogram spanned by vectors A and B:
Area = |A × B| =
\(\sqrt{(1^2 + (-6)^2 + (-7)^2}\\\sqrt{1+36+49\\\\\sqrt{86}\)
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The string shown is replaced with a shorter string, but all other factors remain the same as before. Did the force change?
Answers
Changing the length of a string may alter the force in a physical system, like a pulley mechanism, if it impacts its tension and length.
How to explain the changeNonetheless, regarding a digital system such as a software application, replacing the string with another one that does not affect any crucial factors is improbable to cause an alteration in said force amount.
Determining whether changing a component of a method leads to any modifications in strength requires recognizing essential aspects influencing that force while keeping in mind how this modification might hinder these key elements.
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In order to increase the pain of a common emitter amplifier, we have to reduce the output impedance Select one: True false . Ves V. The NMOS transtor certainly operates in saturation region Select one True False
Answers
In order to increase the gain of a common emitter amplifier, we have to reduce the output impedance. This statement is false.
To increase the gain of a common emitter amplifier, it is more common to focus on increasing the input impedance and/or the transconductance of the transistor, rather than specifically reducing the output impedance.
The NMOS transistor certainly operates in the saturation region.
False. The operating region of an NMOS transistor depends on the voltages applied to its terminals. The NMOS transistor can operate in different regions, including the cutoff, triode, and saturation regions. The specific region of operation depends on the voltages applied to the gate, source, and drain terminals of the transistor.
It's important to note that the answers provided above are based on the given options, but the questions could be more accurately answered with additional context or clarification.
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Medium is water. The wavelength is 4.75 m and the frequency is 600 Hz. Calculate the speed of the wave.
Answers
Answer:
126.32m/s
Explanation:
The formula for calculating the speed of wave is expressed as:
Speed of wave = frequency/wavelength
Given
Wavelength = 4.75m
Frequency = 600Hz
Required
Speed of the wave
Substitute the given value into the formula
Speed = 600/4.75
Speed = 126.32m/s
Hence the speed of the wave is 126.32m/s
a question about the size of the universe
Answers
Answer: The Universe has no scale, no matter and no size it is an infinite void of never-ending wonder.
Explanation:
The mass of the train is 450000 kg.
Calculate the maximum possible speed of the train at the end of the first 4.0km of the
journey.
Answers
The maximum possible speed of the train at the end of the first 4.0 km of the journey is 0 m/s.
To calculate the maximum possible speed of the train at the end of the first 4.0 km of the journey, we can apply the principle of conservation of energy.
Assuming there are no external forces like friction or air resistance, the initial potential energy of the train will be converted into kinetic energy.
The potential energy (PE) of the train at the beginning of the journey can be calculated as PE = mgh, where m is the mass of the train, g is the acceleration due to gravity (approximately \(9.8 m/s^2\)), and h is the height difference (in this case, we assume it to be zero).
The kinetic energy (KE) of the train at the end of the 4.0 km journey can be calculated as \(KE = (1/2)mv^2\), where v is the velocity of the train.
Since the potential energy is converted into kinetic energy, we can equate the two expressions:
PE = KE
\(mgh = (1/2)mv^2\)
Simplifying and canceling out the mass:
\(gh = (1/2)v^2\)
Substituting the values, \(g = 9.8 m/s^2\)and h = 0, we get:
\((9.8 m/s^2)(0) = (1/2)v^2\)
Simplifying further:
\(0 = (1/2)v^2\)
This equation tells us that the maximum possible speed of the train at the end of the first 4.0 km of the journey is 0 m/s.
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A truck covered 2/7 of a journey at an average speed of 40
mph. Then, it covered the remaining 200 miles at another
average speed. If the average for the whole journey was 35
mph, what was the amount of time for the whole journey?
h
Answers
Answer:8h
Explanation:
Answer: 8 h
Explanation:
I got it right
what is the momentum of an object weighing 7.5 kg moving at 1.6 m/s?
Answers
Answer:
\(momentum = mass \times velocity \\ = 7.5 \times 1.6 \\ = 12 \: kg {ms}^{ - 1} \)
Mass is 7.5 kg
Velocity is 1.6 m/s
we know that,
momentum = mass × velocity
or; momentum =7. 5 kg × 1. 6 m/s
or; momentum = 12 kgms^1
Jim is meeting with his academic advisor. He is distracted by social media on his phone and not paying attention to the advisor. He figures he will change his major anyway, so the conversation seems pointless. Which style of listening is Jim displaying?
active
involved
passive
detached
Answers
Detached listening can hinder effective communication and understanding between individuals. It is important for Jim to be actively involved and attentive during his meeting with his academic advisor to ensure he receives the necessary guidance and support for his academic decisions.
Jim is displaying the style of listening known as "detached." This style of listening is characterized by a lack of attention, interest, or engagement in the conversation. Jim's distraction with social media on his phone shows that he is not actively participating or focusing on what his academic advisor is saying. Additionally, his belief that the conversation is pointless because he plans to change his major indicates a disinterest in the discussion and a lack of motivation to actively listen and engage with his advisor.
Detached listening can hinder effective communication and understanding between individuals. It is important for Jim to be actively involved and attentive during his meeting with his academic advisor to ensure he receives the necessary guidance and support for his academic decisions. By actively participating and listening, he can make more informed choices about his major and benefit from the advice and expertise of his advisor.
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Jim is displaying detached listening as he is being physically present in conversation with his academic advisor but his focus is elsewhere, particularly, his phone.
Explanation:The style of listening that Jim is displaying is detached. This is because he is not paying attention to his advisor and is instead distracted by his phone. Detached listening is when one is physically present in a conversation but not mentally or emotionally engaged. Examples include browsing on the phone or thinking about other things while someone is talking.
In contrast, active or involved listening would involve fully concentrating, understanding, responding, and then remembering what is being said. Considering that Jim is mainly focused on his phone, he is not displaying any signs of this type of engagement with his advisor, hence, detached is the appropriate choice to describe his listening style.
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Which type on manometer must take the atmospheric pressure into account to calculate the pressure exerted by a gas?
Answers
A closed end manometer is manometer must take the atmospheric pressure into account to calculate the pressure exerted by a gas.
in closed end manometer, the pressure of gas is measured by measuring the height 'h' and there is no use of atmospheric pressure here.
what is manometer?
A manometer could be a device that we utilize to measure the pressure of the pipelines (cab be of gas, water, fluid, etc.) Moreover, it is usually referred to as a U-shaped tube that's filled with a liquid. In this point, to examine what is it and how it works.
Types of manometer
U-Tube Manometer.
Enlarged-Leg Manometer.
Well-Type Manometer.
Inclined-Tube Manometer.
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