Predict the major organic product of the following reaction.

Answer:

Explanation:

Lattice energy is a way to measure the bond strength in ionic compounds. Ionic compounds tend to have high melting and boiling points. Ionic compounds tend to be hard. Ionic compounds have a range of solubilities.

Answer:

1 mole of water weighs 18g. 10/18 moles = 10/18 * 6 * 10^23 number of molecules = 3.33 * 10^23 molecules of water. Each molecule of water has 3 atoms, so the total number of atoms in 10g of water is 3*3.33*10^23 = 10^24.

Explanation:

Answer:

the eye socket

Explanation:

the area around the eye is called the eye socket or the eye orbit.

The mass of ammonia that can be produced from the reaction of 74.2 g of N₂ and 14.0 moles of H₂ is 90.1 g.

The mole ratio of the reaction for the production of ammonia is obtained from the balanced equation of the reaction as follows:

Equation of the reaction: N₂ (g) + 3 H₂ (g) → 2 NH₃ (g)

The mole ratio of the reactants nitrogen and hydrogen is 1 : 3

Moles of nitrogen in 74.2 g of nitrogen = 74.2/28

Moles of nitrogen in 74.2 g of nitrogen = 2.65 moles

Moles of hydrogen present = 14.0 moles

The limiting reactant is nitrogen

Mole ratio of nitrogen to ammonia is 1 : 2

Mass of ammonia produced = 2.65 * 2 * 17 g

Mass of ammonia produced =  90.1 g

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Cloning is used for to create duplicate of other cell or organism. Because there are legal and ethical restrictions regarding human cloning. So, option D is correct.

The process in which replication occurs to produce another cell, tissue or organism is called as cloning. It increase the disease resistance and yield.

Banana cloning allows them to be a crop provides high yields, with or without pollination and seed formation. But before domestication, most banana varieties produces large number of seeds in the middle of the fruit.

Scientists clone banana plants it gives genetic modification for the lack of traditional breeding opportunities. It is an effective way to develop bananas yield.

Hence, option D is correct.

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Answer:

sigma bond

represents two electrons

Explanation:

The bond between hydrogen and oxygen is sigma bond because the bond between hydrogen and oxygen is covalent means sharing of electron takes place between two atoms and we know that sigma bond is also occurs in a covalent bond in which overlapping of atomic orbitals or hybrid orbitals along the bond axis occurs. Both also represent two electrons because both atoms share one electron each so we can say that the two atoms represents two electrons.

The resulting mixture will have a sugar concentration of 22.22% when 5g of sugar is added to a 45g of serving which is 10% sugar.

This is calculated by adding the grams of sugar (5g) to the existing grams of sugar (4.5g) and dividing by the total grams of cereal (45g). The resulting percentage is then multiplied by 100 to express it as a percentage.

5+4.5=9.5

9.5/45×100=21.11

To put this into perspective, the original 10% sugar concentration translates to 4.5g of sugar in the 45g serving, and the addition of the 5g of sugar brings the total to 9.5g of sugar.

When divided by the total of 45g of cereal, this yields a concentration of 21.11%, which is then multiplied by 100 to give the final percentage of 22.22%.

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the given statement was false cause when the gas law constant R = 0. 0821 was used the temperature should be in K and the volume should be in liters.

define gas law constant ?

In chemistry and physics, "R" is the symbol for the gas constant, molar gas constant, ideal gas constant, or universal gas constant. In numerous equations, it is a proportionality factor that connects energy and temperature scales.

Chemistry's Gas Constant

The gas constant is also known as the ideal gas constant and the universal gas constant in chemistry.

The Boltzmann constant has a molar equivalent.

The gas constant has a SI value of 8.31446261815324 JK1mol1. The number is usually rounded to 8.314.

the given statement was false cause when the gas law constant R = 0. 0821 was used the temperature should be in K and the volume should be in liters.

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British thermal units (Btu) are a unit used to measure the amount of heat in fuels or other energy sources.

The amount of heat needed to raise a pound of liquid water's temperature by one degree Fahrenheit at the point where water has its highest density (approximately 39 degrees Fahrenheit).

Temperature is a physical parameter that, with the aid of a certain scale, indicates the kinetic energy and amount of energy transfer from an object or an entity to its environment (surrounding). Different temperature sensors, such as thermocouples, thermistors, and digital temperature sensors, can be used to control or maintain the temperature.

A unit of measurement that shows the amount of energy or heat required to raise the temperature associated with an object's hotness.

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The total number of molecules that are present in 4.6×\(10^{3}\) mg of NaCl is 0.47×\(10^{23}\)

Atomic masses:

Na=23  , Cl=35.5

The molar mass of NaCl=58.5

1gm of NaCl contains=1/58.5 moles of NaCl

And,

      1gm of NaCl contains=1/58.5×6.022×\(10^{23}\) molecules of NaCl

4.6x\(10^{3}\) mg =(4.6x\(10^{3}\)x\(10^{-3}\) gm) of NaCl contains= \(\frac{1}{58.5}\) ×6.022×\(10^{23}\)×4.6

                                                                              =0.017×27.70×\(10^{23}\)

                                                                              =0.47×\(10^{23}\)

Therefore the total number of molecules present in 4.6×\(10^{3}\) mg NaCl is 0.47×\(10^{23}\)

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Answer:

Why does D-block start on the fourth row of the periodic table?

Explanation:

The require more energy to reach 3d than 4s, and they fill up 4p before 4d, and so forth. ... The energy is lower for 6s than 4f, and 4f and 5f are lower in energy than the final D level.

Answer:

2,7

Explanation:

Two in the first shell and 7 in the outer and last shell.

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The combustion reaction must involve oxygen as one of the reactant. The grams of water produced by the combustion of 32.0g of CH₄ is 72 g.

The combustion can be defined as a chemical process or reaction between the hydrocarbon and oxygen. When they react together, heat and light energy is released. The burning of wood is an example.

Here the reaction is:

CH₄ +2O₂ → 2H₂O +CO₂

Combustion of one mole of CH₄ gives 2 moles of water (36 g).

Then combustion of 32 g of CH₄ gives:

36 g H₂O/16 g CH₄ × 32 g CH₄ = 72 g water

Thus the grams of water produced is 72 g.

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Answer:

A 4 half-life

B. 0.05 mg

Explanation:

A. Determination of the number of half-lives after 2.8×10⁹ years.

From the question given above,

7×10⁸ years = 1 half life

Therefore

2.8×10⁹ years = 2.8×10⁹ years × 1 half life / 7×10⁸ years

2.8×10⁹ years = 4 half life

Thus, the sample went through 4 half-lives at the end of 2.8×10⁹ years.

B. Determination of the amount of the sample remaining after 2.8×10⁹ years.

Original amount (N₀) = 0.74 mg

half life (t½) = 7×10⁸ years

Time (t) = 2.8×10⁹ years

Amount remaining (N) =?

Next, we shall determine the rate of disintegration. This can be obtained as follow:

half life (t½) = 7×10⁸ years

Decay constant (K) =?

K = 0.693 / t½

K = 0.693 / 7×10⁸

K = 9.9×10¯¹⁰ /year

Finally, we shall determine the amount remaining as follow:

Original amount (N₀) = 0.74 mg

Time (t) = 2.8×10⁹ years

Decay constant (K) = 9.9×10¯¹⁰ /year

Amount remaining (N) =?

Log (N₀/N) = kt / 2.303

Log (0.74/N) = 9.9×10¯¹⁰×2.8×10⁹ /2.303

Log (0.74/N) = 2.772 / 2.303

Log (0.74/N) = 1.2036

Take the antilog of 1.2036

0.74/N = antilog (1.2036)

0.74 / N = 15.98

Cross multiply

0.74 = N × 15.98

Divide both side by 15.98

N = 0.74 / 15.98

N = 0.05 mg

Thus, 0.05 mg of the sample will remain after 2.8×10⁹ years

The amount of uranium sample remained after 4 cycles in \(\rm 2.8\;\times\;10^9\) years has been 0.04625 mg.

The half-life can be described as the time required by the element to reduce to its half concentration from the initial concentration.

A. The number of half-life cycles can be calculated as:

\(\rm 7.0\;\times\;10^8\) = 1 cycle

\(\rm 2.8\;\times\;10^9\) = \(\rm \dfrac{1}{\rm 7.0\;\times\;10^8}\;\times\;2.8\;\times\;10^9\)

= 4 cycles.

The number of half-life cycles after \(\rm 2.8\;\times\;10^9\) years are 4 cycles.

B. The amount of sample remained can be calculated as:

Sample remained = Initial sample \(\rm \times\;\dfrac{1}{2}^\frac{time}{Half-life}\)

Sample remained = 0.74 mg \(\rm \times\;\dfrac{1}{2}^\frac{2.8\;\times\;10^9}{7.0\;\times\;10^8}\)

Smaple remianed = 0.74 \(\rm \times\;\dfrac{1}{2}^4\)

Sample remained = 0.74 \(\times\) 0.0625 mg

Sample remained = 0.04625 mg.

The amount of uranium sample remained after 4 cycles in \(\rm 2.8\;\times\;10^9\) years has been 0.04625 mg.

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hello

the answer to the question is C) tetrahedral

Answer: B

Explanation: The atomic number is based only on the number of protons in the nucleus of an atom. Since this is a count of whole numbers, it cannot be a decimal. It's either element 110 or 111, not 110.5.

Answer:

B

A

C

A

C

These should be the answers for your test. If you have any questions, please DM me

In the chemical reaction AgNO3 + NaI → AgI + NaNO3, the products are AgI and NaNO3.

This is a double displacement reaction where the two reactants switch their ions to form two new compounds. AgNO3 is silver nitrate and NaI is sodium iodide. When they are mixed, the silver ion (Ag+) from AgNO3 combines with the iodide ion (I-) from NaI to form silver iodide (AgI).

At the same time, the nitrate ion (NO3-) from AgNO3 combines with the sodium ion (Na+) from NaI to form sodium nitrate (NaNO3). AgI is a yellow solid that is sparingly soluble in water, while NaNO3 is a white solid that is highly soluble in water.

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D- A molecule

Explanation:

(Apex)

Answer:

non-polar covalent bond

The covalent bonds form silicon dibromide, or \(Si_2Br_6\). Instead of being an ionic compound, it is a covalent one.

The sharing of electrons between the silicon (Si) and bromine (Br) atoms in \(Si_2Br_6\) provides the basis for their bonding. Covalent bonds are formed when atoms share electrons to form a stable electron configuration. In this example a total of twelve electrons are shared between each of the silicon atoms and six of the bromine atoms. By filling their valence electron shells, this electron sharing enables silicon and bromine to have more stable structures.

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Answer:

Iodine

Explanation:

Iodine is in group 17 on the periodic table (first picture attached). The second picture shows you in the top left-hand corner of Iodine's little square, there is the number 53. This is the atomic number, it is also the number of protons and electrons in an element.

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Option a, which involves a positive charge on carbon, has the potential to make a greater contribution to the overall hybrid structure than option c, which features positive charges on sulfur.

a. The structure with the positive charge on carbon: This option indicates that there is a positive charge on a carbon atom. Carbon is less electronegative than sulfur, meaning it has a lower affinity for electrons. As a result, a positive charge on carbon is more favorable and stable compared to a positive charge on sulfur. Carbon can accommodate the positive charge by sharing its electrons with adjacent atoms, forming stable carbon cations.

b. All contribute equally: This statement suggests that all the resonance structures provided contribute equally to the hybrid. However, in reality, resonance structures can have different contributions based on factors such as the location and stability of charges. So, this answer is not accurate.

c. The structure with the positive charge on sulfur: This structure indicates that there is a positive charge on a sulfur atom. In organic chemistry, a positive charge on sulfur is less stable than a positive charge on carbon. Sulfur, is more electronegative than carbon. It has a higher affinity for electrons and prefers to maintain a full octet rather than carrying a positive charge. Positive charges on sulfur are less stable and tend to be more reactive and less common in organic compounds.

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Answer:

0.342 mol

Explanation:

Molar mass of  

NaCl = 58.4 g/mol

Number of moles in  

20.0 g NaCl

is

20.0

g

58.4

g

/mol

=

0.342 mol

1st one

2_2_2

2nd one

3_1_1_3

i looked it up

The pressure in the left intrapleural cavity changes when the valve was opened as : It went from negative number to zero and the pressure in intrapleural cavity equalized with the atmospheric pressure.

The pressure inside the pleural cavity is called as intrapleural pressure. It is characterized as negative pressure when the pressure inside the pleural cavity is typically only a little bit lower than the ambient pressure.

The external intercostal muscles and diaphragm contract during inspiration, expanding the thoracic cavity. As a result, the intrapleural pressure decreases, increasing the transpulmonary pressure and expanding the lungs.

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Answer:

- Anode: Co3+ | Co2+

- Cathode: Ni | Ni2+

Explanation:

The anode is where oxidation reaction occurs, and the cathode is where reduction reaction occurs.

From the table of reduction potencials, we find that:

- Co reaction:

- Ni reaction:

Now, to find out which one is the anode and which one is the cathode, it is necessary to compare the reduction potencials.

The reaction of Ni have negative potentials, so Ni will be the anode and Co will be the cathode.

Hi! In an organic redox reaction, you can indeed identify the reduced and oxidized organic molecules by monitoring the charges between the reactants and products. In a redox reaction, there is a transfer of electrons between molecules, leading to a change in their oxidation states. To understand this better, let's break down the two processes involved in a redox reaction: reduction and oxidation.

Reduction corresponds to a gain of electrons by a molecule, causing a decrease in its oxidation state. This means that the reduced molecule becomes more negatively charged or less positively charged. In organic reactions, reduction often involves the addition of hydrogen atoms or the removal of oxygen atoms.
On the other hand, oxidation corresponds to a loss of electrons by a molecule, resulting in an increase in its oxidation state. This causes the oxidized molecule to become more positively charged or less negatively charged. In organic reactions, oxidation typically involves the removal of hydrogen atoms or the addition of oxygen atoms.
To recognize the reduced and oxidized organic molecules in a redox reaction, follow these steps:
1. Determine the oxidation state of each atom in the reactants and products.
2. Identify any changes in the oxidation state between the reactants and products.
3. The molecule with a decreased oxidation state has undergone reduction (gained electrons).
4. The molecule with an increased oxidation state has undergone oxidation (lost electrons).
By tracking these changes in oxidation states and charges, you can easily recognize the reduced and oxidized organic molecules in a redox reaction.

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