postulate a reason why so many aliphatic amino acids are essential

Answer:

C. identification. PCR testing can aid in the identification of fly species in a forensic investigation.

Explanation:

PCR testing can aid in the identification of fly species in a forensic investigation. PCR (Polymerase Chain Reaction) is a laboratory technique that allows the amplification of a small amount of DNA to detectable levels.

In forensic entomology, PCR can be used to identify the species of flies that are found at a crime scene. This is important because different species of flies have different developmental rates and life cycles. By identifying the species of fly present at a crime scene, forensic investigators can estimate the time of death more accurately.

PCR can be used to identify the fly species by analyzing the DNA present in the fly samples. The DNA is extracted from the samples and then amplified using PCR. The amplified DNA can then be sequenced to identify the fly species.

Therefore, the answer to the question is C. identification. PCR testing can aid in the identification of fly species in a forensic investigation.

Answer:

don't be sad you have a nice peach

babe you got that wap

don't be sad go get a tattoo

Answer:

Netflix and chill | do you need d!c rn ? | spoil her

Explanation:

Answer:

a. H3PO4 + 3KOH => K3PO4 + 3H2O

b. 1.67 moles

c. KOH is the limiting agent

Explanation:

H3PO4 + 3KOH => K3PO4 + 3H2O

a = 3, b = 1, c = 1, d = 3

1 mole of H3PO4 will react with 3 moles of KOH

=> 2 moles of H3PO4 will react with 6 moles of KOH

since there are only 5 moles of KOH available, KOH is the limiting agent

Since there are only 5 moles of KOH available, the amount of H3PO4 needed is (5 x 1)/3 = 5/3 = 1.67 moles

1 mole of H3PO4 will produce 1 mole of K3PO4 => 1.67 moles of H3PO4 will produce 1.67 moles of K3PO4

Hope this helps

Answer:

4510 J

Explanation:

To calculate the energy of the water, you need to use the following equation:

Q = mcΔT

In this equation,

-----> Q = energy/heat (J)

-----> m = mass (g)

-----> c = specific heat capacity (J/g°C)

-----> ΔT = change in temperature (°C)

First, you need to determine the mass of the water. To do this, you need to multiply the given volume by the density of water (1.00 g/mL).

 100.0 mL H₂O          1.00 g
------------------------  x  ------------  =  100.0 g H₂O
                                    1 mL

Now, you can plug the given values into the equation and solve for "Q" (Q = \(q_H_2_O\)). The final answer should have 3 significant figures to match the given values with the lowest number of sig figs.

Q = ? J                           c = 4.18 J/g°C

m = 100.0 g                  ΔT = 32.0 °C - 21.2 °C = 10.8 °C

Q = mcΔT

Q = (100.0 g)(4.18 J/g°C)(10.8 °C)

Q = 4510 J

4510Answer:

Explanation:

Answer:You have it right the answer is c!

Explanation:

Answer:

c ........................!

Answer:

sog-20g=30g

Explanation:

Answer:

Each experimentation document should have these sections; introduction, problem, hypothesis, experimentation design, results, and conclusion. Write in first person active or 3rd person passive. Always document using past tense.

The Hazardous Material class that includes compressed gases, dissolved gases, and gases liquefied by compression or refrigeration is Class 2: Gases. This class is further divided into three divisions:

1. Division 2.1 - Flammable Gases: These are gases that can burn in the presence of an ignition source. Examples include propane, butane, and hydrogen.
2. Division 2.2 - Non-Flammable, Non-Toxic Gases: These are gases that do not burn and are not toxic, but may still pose risks due to their physical properties, such as high pressure or low temperature. Examples include nitrogen, helium, and carbon dioxide.
3. Division 2.3 - Toxic Gases: These are gases that are harmful or even fatal when inhaled. Examples include chlorine, ammonia, and phosgene.

The proper handling, storage, and transportation of these gases are essential to minimize the risks associated with their hazardous properties. Regulations and guidelines are in place to ensure the safety of those working with and around these materials.

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The value of K_eq for this reaction is approximately 1.805 × 10^-5.

To find the value of the equilibrium constant (K_eq) for the given reaction, we can use the equilibrium concentrations of the species involved. The equilibrium constant expression for the reaction is:

K_eq = [CH3COO-][H3O+] / [CH3COOH]

Given the following concentrations at equilibrium:

[CH3COOH] = 2.0 × 10^-1 M

[CH3COO-] = 1.9 × 10^-3 M

[H3O+] = 1.9 × 10^-3 M

Substituting these values into the equilibrium constant expression, we get:

K_eq = (1.9 × 10^-3)(1.9 × 10^-3) / (2.0 × 10^-1)

K_eq = 3.61 × 10^-6 / 2.0 × 10^-1

K_eq = 3.61 × 10^-6 × 5.0 × 10^0

K_eq = 1.805 × 10^-5

Therefore, the value of K_eq for this reaction is approximately 1.805 × 10^-5.

None of the provided answer choices match this value exactly.

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Answer:

The answer is the 2nd one down: The green house affect

Answer:

C1H201 or COH2

Explanation:

The molecular formula of the compound can be determined by finding the number of atoms of each element in a molecule and combining them to form the molecular formula.From the percent composition, we can find the number of moles of each element in 100 g of the compound.

40 g of Carbon, which is equal to 40/12 = 3.33 moles of Carbon

6.7 g of Hydrogen, which is equal to 6.7/1 = 6.7 moles of Hydrogen

53.3 g of Oxygen, which is equal to 53.3/16 = 3.33 moles of Oxygen

The molar mass of the compound is 90 amu, so there are 90 g/mol of the compound.The molecular formula can be determined by dividing the number of moles of each element by the smallest number of moles of the elements, then rounding to the nearest whole number.

Carbon: 3.33 moles / 3.33 moles = 1

Hydrogen: 6.7 moles / 3.33 moles = 2

Oxygen: 3.33 moles / 3.33 moles = 1

Therefore, the molecular formula for the compound is C1H2O1 or COH2.

Hope this helps! Correct me if I’m wrong.

Explanation:

We know that,

1 mile = 1609.34 m

We need to find how many meters are present in the 12.45 miles. To find it use unitary method as follows :

12.45 mile = 1609.34 × 12.45

12.45 mile=20036.283 meters

or

\(12.45\ mile=2.0036\times 10^4\ m\)

Hence, this is the required solution.

Answer:

1. curious

2. curious

3. creative

4. Ethical

Explanation:

I am not sure but I hope they are correct! :)

Answer:

Curious.)
Andrew asks questions about how the volcanoes in Hawaii were formed.

Skeptical.)
Robyn sees a magazine for kids at the grocery store with an article about a new fossil discovery. So, she searches scientific journals that support the content of the article.

Creative.)

Maggie uses her knowledge of physics to create a simple machine for a science fair project.

Ethical.)

Shaun is testing a new medication on animal subjects. He is sure to follow all guidelines for appropriate care and testing.




Explanation:

Have a great rest of your day
#TheWizzer

Answer:

The nonpolar covalent compounds are:

H2O (polar covalent)

NCl3 (polar covalent)

AuCl3 (ionic)

ClO2 (polar covalent)

SF4 (polar covalent)

SO3 (nonpolar covalent)

Answer: 0.027 moles

Explanation:

Answer:

File down there

Explanation:

Answer:

A. 3.5ml

Explanation:

lowest point of liquid or meniscus

Answer:

A chain of volcanic

Explanation:

Answer:

A

Explanation:

The standard enthalpy of formation (ΔH°f) for LiCl(s) is +412.35 kJ/mol.

The standard enthalpy of formation (ΔH°f) for LiCl(s) can be calculated using the Born-Haber cycle, which relates the enthalpy change for the formation of an ionic compound to various other energy changes involved. The steps involved in the Born-Haber cycle for LiCl(s) are:

1. Sublimation of Li(s): Li(s) → Li(g) ΔH° = +155.2 kJ/mol

2. Ionization of Li(g): Li(g) → Li+(g) + e- ΔH° = +520 kJ/mol

3. Dissociation of Cl₂(g): Cl₂(g) → 2Cl(g) ΔH° = +242.7 kJ/mol

4. Electron affinity of Cl(g): Cl(g) + e- → Cl-(g) ΔH° = -349 kJ/mol

5. Formation of LiCl(s): Li+(g) + Cl-(g) → LiCl(s) ΔH° = -828 kJ/mol

The value of ΔH°f for LiCl(s) can be calculated by summing the enthalpy changes for these steps, which gives:

ΔH°f(LiCl) = Σ(nΔH°f(products)) - Σ(nΔH°f(reactants))

            = ΔH°f(LiCl(s)) - [ΔH°(sublimation of Li) + ΔH°(ionization of Li) + 1/2ΔH°(dissociation of Cl₂) + ΔH°(electron affinity of Cl) + ΔH°(lattice energy of LiCl)]

            = ΔH°f(LiCl(s)) - [155.2 + 520 + 1/2(242.7) + (-349) + 828] kJ/mol

            = ΔH°f(LiCl(s)) - 415.65 kJ/mol

Solving for ΔH°f(LiCl(s)), we get:

ΔH°f(LiCl(s)) = 415.65 kJ/mol - (-828 kJ/mol) = +412.35 kJ/mol

As a result, the standard enthalpy of formation (H°f) for LiCl(s) is +412.35 kJ/mol.

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Answer: Nonpolar Covalent Bond

Explanation: A Nonpolar Covalent Bond is created when atoms share their electrons equally. This usually occurs when two atoms have similar or the same electron affinity. The closer the values of their electron affinity, the stronger the attraction. This occurs in gas molecules; also known as diatomic elements.

The Answer is LEAD ......................

Answer:

See explanation

Explanation:

A simple test that will distinguish flour from sugar is to dissolve the unknown substance in water.

Sugar dissolves in water due to the presence of polar groups in the chemical structure of sugar that are capable of interaction with water.

Flour does not dissolve in water. It rather becomes suspended in water when agitated and settles at the bottom of the container when the suspension is left to stand.

Answer:

i think it is true

Explanation:

The volume of water added to dissolve potassium hydrogen phthalate (KHP) does not matter because the mass of KHP used is known and it will dissolve completely in any volume of water.

In volumetric analysis, the primary objective is to find the exact concentration of an analyte in a given solution. Analyte refers to the substance whose concentration is to be determined.In order to measure the analyte concentration, the known volume of the titrant of known concentration is added to the analyte until the endpoint is reached.Endpoint refers to the point in a titration where the reaction between the analyte and titrant is complete. The endpoint can be detected by observing a physical change in the system.In the case of KHP, it dissolves completely in any volume of water.

Therefore, the mass of KHP used can be accurately measured and dissolved in any volume of water. As a result, the volume of water added to dissolve the KHP does not affect the accuracy of the experiment.In summary, the volume of water added to dissolve KHP does not matter because the mass of KHP used is known and it will dissolve completely in any volume of water.

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Answer:

Drilling for oil

Explanation:

That is the only one that directly impacts the earth. Hope this helps you!

Answer:

Drilling for oil.

Combustion of Hydrocarbons

Using methane to separate hydrogen gas

Explanation:

The volume, in liters, is occupied by  \(1.5 x 10²³\) atoms of argon gas at STP (Standard Temperature and Pressure) occupying a volume of 22.4 liters.



1. To determine the volume occupied by the atoms of argon gas, we can use Avogadro's law, which states that equal volumes of gases at the same temperature and pressure contain an equal number of molecules or atoms.
2. According to Avogadro's law, at STP, 1 mole of any gas occupies a volume of 22.4 liters.
3. 1 mole of any substance contains \(1.5 x 10²³\) particles (Avogadro's number).
4. In this case, we have \(1.5 x 10²³\) atoms of argon gas.
5. By dividing the number of atoms by Avogadro's number, we can determine the number of moles of argon gas: \(1.5 x 10²³ atoms / 6.022 x 10²³ atoms/mole = 0.249 moles\).
6. Finally, we can multiply the number of moles by the volume occupied by 1 mole of gas at STP: 0.249 moles x 22.4 liters/mole = 5.576 liters (rounded to 3 significant figures).

In conclusion, \(1.5 x 10²³\) atoms of argon gas at STP occupy a volume of approximately 5.576 liters.

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It is a base because in solution it produces two hydroxide anions.

The Arrhenius theory, proposed in 1887 by the Swedish scientist Svante Arrhenius, states that acids dissociate in water to produce electrically charged atoms or molecules known as ions, one of which is a hydrogen ion (H+), and that bases ionize in water to produce hydroxide ions (OH). Acid, according to the Arrhenius theory, is a substance that releases H+ ions when dissolved in aqueous solution. The concentration of H+ ions in the solution rises. The base is a substance that, when dissolved in aqueous solution, ionizes the OH- ion.

Here,

The same logic holds true for the reaction of sulfuric acid and barium hydroxide. This reaction involves an Arrhenius acid, which generates two hydrogen cations in solution, and an Arrhenius base, which generates two hydroxide anions in solution.

It is a base as it generates two hydroxide anions in solution.

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(1) decreasing the temperature- True, (2)decreasing the pressure (by changing the volume)-False, (3) increasing the volume-True, (4) removing CH2Cl2-False, (5) removing CCl4-False

According to Le Chatelier's principle, if a system at equilibrium is subjected to a change, the system will adjust to reestablish the equilibrium. The production of CH2Cl2 (g) is favored by decreasing the temperature and increasing the volume, and is disfavored by decreasing the volume, removing CH2Cl2, and removing CCl4.
1. True - Decreasing the temperature will shift the equilibrium towards the side with higher enthalpy, which in this case is the production of CH2Cl2 (g).
2. False - Decreasing the pressure (by changing the volume) will cause the system to shift towards the side with a higher number of moles, which in this case is the reactant side. Therefore, it will not favor the production of CH2Cl2 (g).
3. True - Increasing the volume will decrease the pressure and cause the system to shift towards the side with a higher number of moles, which in this case is the production of CH2Cl2 (g).
4. False - Removing CH2Cl2 will cause the system to adjust by producing more CH2Cl2 to reestablish the equilibrium, so it will not favor the production of CH2Cl2 (g).
5. False - Removing CCl4 will cause the system to adjust by producing more CCl4 to reestablish the equilibrium, so it will not favor the production of CH2Cl2 (g).
In summary, the production of CH2Cl2 (g) is favored by decreasing the temperature and increasing the volume, while it is disfavored by decreasing the volume, removing CH2Cl2, and removing CCl4.

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In 0.75 moles of caffeine, there are a total of 6 carbon atoms, 7.5 hydrogen atoms, 3 nitrogen atoms, and 1.5 oxygen atoms.

To determine the total number of atoms in 0.75 moles of caffeine, we need to consider the molecular formula of caffeine, which is C8H10N4O2. The molecular formula provides the ratios of each element present in the compound. By multiplying the number of atoms in each element by the corresponding coefficient in the molecular formula, we can calculate the total number of atoms. In this case, there are 8 carbon (C) atoms, 10 hydrogen (H) atoms, 4 nitrogen (N) atoms, and 2 oxygen (O) atoms in each molecule of caffeine. Multiplying these values by 0.75 moles will give us the total number of atoms in 0.75 moles of caffeine.

The molecular formula of caffeine, C8H10N4O2, provides the number of atoms for each element present in one molecule of caffeine. In this case, there are 8 carbon (C) atoms, 10 hydrogen (H) atoms, 4 nitrogen (N) atoms, and 2 oxygen (O) atoms.

To calculate the total number of atoms in 0.75 moles of caffeine, we need to multiply the number of atoms for each element by the coefficient in the molecular formula, and then multiply that by the number of moles (0.75 moles).

For carbon (C): 8 atoms x 0.75 moles = 6 atoms (since there are 8 carbon atoms in one molecule of caffeine).

For hydrogen (H): 10 atoms x 0.75 moles = 7.5 atoms (since there are 10 hydrogen atoms in one molecule of caffeine).

For nitrogen (N): 4 atoms x 0.75 moles = 3 atoms (since there are 4 nitrogen atoms in one molecule of caffeine).

For oxygen (O): 2 atoms x 0.75 moles = 1.5 atoms (since there are 2 oxygen atoms in one molecule of caffeine).

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The energy, in kj, is transferred between the system and surroundings when 250. 0 g of potassium fluoride is dissolved into water, the molecular mass of kf is 58. 10 g/mol is 745 kJ per second  thermodynamics

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