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The formal Positive sign convention for, work done by the system and heat transfer into the system. The Negative sign convention for heat transfer out of the system and work done to the system.

Thermodynamics is a special branch of chemistry that deals with concepts of heat, temperature and work and interconversion of heat into other forms of energy. Sign convention for heat : Heat transfer into the system is positive and heat transfer from the system is negative. In other words, all heat exchanges that increase the energy of a system are positive and all heat exchanges that decrease the energy of a system are negative. Sign rule for work :

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Complete question:

Following the formal sign convention, please match the heat and work interactions with their appropriate signs:Positive or Negative

1) work done by the system

2) heat transfer into the system

3) heat transfer out of the system

4) work done to the system

Answer:

M=0.816M

Explanation:

Hello,

In this case, we should consider the following reaction:

\(AgNO_3+KCl\rightarrow KNO_3+AgCl\)

Thus, by knowing the 1:1 molar ratio of silver nitrate and potassium chloride, we can easily compute the moles of silver nitrate precipitating the 1570 mg of potassium chloride considering its molar mass of 74.5513 g/mol:

\(n_{AgNO_3}=1570mgKCl*\frac{1gKCl}{1000mgKCl} *\frac{1molKCl}{74.5513gKCl}*\frac{1molAgNO_3}{1molKCl} \\\\n_{AgNO_3}=0.021molAgNO_3\)

Then, by using the volume of silver nitrate in liters (0.0258 L), we can directly compute the molarity:

\(M=\frac{0.021molAgNO_3}{0.0258L}\\ \\M=0.816M\)

Regards.

Answer: 9084355.951 L  if need in correct sig figs answer is

9.08 X 10^6 L

Explanation:

Ideal gas law  PV=nRT  = V=nrt/P

R= 62.44

n=0.511

T= 513

P= 555

V= 0.511 X 62.44 X 513 / 555

The heating curve of water is the temperature of a given volume of water changes as heat is added at a consistent pace, as shown by the water heating curve. The temperature of the water does not vary throughout a phase shift, creating a plateau on the graph.

A meniscus is a curvature that appears on the surface of a molecular substance (water, of course) when it comes into contact with another material. You may imagine that happening with water when it adheres to the interior of a glass.

Hence, The relationship between the supply temperature of the heating system and the outside air temperature is known as the heating curve. The CH boiler's ability to heat water to a specific temperature at a specific outside temperature is determined by the heating curve.

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Answer:

3 bags are required.

Explanation:

Find the number of mg needed for 150 pounds

150 pounds * 5 mg/pound = 750 mg

1 bag = 250 mg

x bags = 750 mg               Cross multiply

250 * x= 750                      Divide by 250

x = 750/250

x = 3

The balanced equation for the reaction between sulfur (S₈) and oxygen (O₂) to form sulfur trioxide (SO₃) is 2S₈ + 16O₂ → 16SO₃.

Balancing chemical equations involves the addition of stoichiometric coefficients to the reactants and products.

The balanced equation for the reaction between sulfur (S₈) and oxygen (O₂) to form sulfur trioxide (SO₃) is determined as;

2S₈ + 16O₂ → 16SO₃

From the reactants side we can see that sulfur is 16 and also 16 in the product side. The number of oxygen in the reactant side is 32 and also 32 in the product side.

Thus, the balanced equation for the reaction between sulfur (S₈) and oxygen (O₂) to form sulfur trioxide (SO₃) is 2S₈ + 16O₂ → 16SO₃.

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The total number of moles of electrons lost by Mg(s) when 2.0 moles of electrons are gained by Ni2+(ag) is also 2.0 moles of electrons.

This is because in a chemical equation, the number of moles of electrons gained by the reducing agent (in this case Ni2+) is equal to the number of moles of electrons lost by the oxidizing agent (in this case Mg(s)).

In this redox reaction, Mg is being oxidized because it loses electrons and Ni is being reduced because it gains electrons. The oxidation and reduction process are occurring simultaneously, so the number of electrons lost by Mg(s) is equal to the number of electrons gained by Ni2+(ag).

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The electrons that are gained by the \(Ni^{2+}\) ion is 2.0 moles of electrons.

We know that when there is a redox reaction, there would be the loss or gain of electrons in the process. The process is a simultaneous one so the electrons that are lost by one specie must as a matter of necessity be gained by another specie.

In this case, as we look at the reaction equation we can see that there are two electrons that have been lost by the magnesium atom and these two electrons would be gained by the Nickel II ion.

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The pOH of the 0.001 M NaOH solution is approximately 3.

To determine the pOH of a solution, we need to know the concentration of hydroxide ions (OH-) in the solution.

In the case of a 0.001 M NaOH solution, we can assume that all of the NaOH dissociates completely in water to form Na+ and OH- ions. Therefore, the concentration of hydroxide ions in the solution is also 0.001 M.

The pOH is calculated using the equation:

pOH = -log[OH-]

Substituting the concentration of hydroxide ions, we have:

pOH = -log(0.001)

Using a calculator, we can evaluate the logarithm:

pOH ≈ 3

Therefore, the pOH of the 0.001 M NaOH solution is approximately 3.

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The reason why red is the only color seen after white light passes thrrough the filter is:

B. The color filter absorbs all colors except red light.

As we know, light is a form of energy and a type of electromagnetic radiation. In the case of this experiments the light that is being used is the visible light that is only one part of the electromagnetic spectrum.

Visible light contains all colors, and they differ in wavelengh.

In this case, we are told that the only color of light that passes through the filter is red, and as we know the light that is going into the filter contains all colors (the complete visible spectrum). Therefore we know that the filter absorbs all colors exept for red light.

The mole ratio between sodium nitrate and sodium oxide is 2:1.

The mole ratio between two or more components of a reaction is the stoichiometric number of moles of each component.

The stoichiometric number of mole of a species of a chemical equation is the coefficient of the species when the equation is balanced.

A balanced equation is one in which the number of atoms of elements in the equation is conserved before and after the reaction.

Looking at the equation:

\(2NaNO_3 + PbO -- > Pb(NO_3)_2 + Na_2O\)

The number of atoms of each element before and after the reaction is the same.

The coefficient of sodium nitrate is 2.

The coefficient of sodium oxide is 1.

Thus, the mole ratio between sodium nitrate and sodium oxide is 2:1.

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Explanation:

Multiply the given moles times the molar mass of neon, 20.180 g/mol (periodic table).

Answer:

Multiply the supplied moles by 20.180 g/mol, the molar mass of neon (periodic table).

Explanation:

Answer: The chocolate has melted, which means it has turn from a solid to a liquid. A liquid has a definite volume but an indefinite shape. Therefore, the correct answer is B.

Priya brought a solid chocolate bar to school to eat as a snack in the afternoon. She left it in her pocket for a few hours. When she took out the chocolate bar to eat it, the bar was was no longer solid. The description that best describes the current state of the chocolate is "The chocolate is now made up of particles packed relatively close together, having an indefinite shape but a definite volume".

There are basically 3 states of matter - Solids, Liquids and gases.

Solid is having definite shape and definite volume, Liquid is having indefinite shape and definite volume and gas is having indefinite shape and indefinite volume.

Liquid and gas states are fluids that can flow easily and their particles are far away from each other.

Water is a liquid, Hydrogen and Oxygen are gases, Ice is a solid.

Given is that Priya left chocolate in her pocket for a few hours. When she took out the chocolate bar to eat it, the bar was was no longer solid.

Therefore, When she took out the chocolate bar to eat it, the bar was was no longer solid. The description that best describes the current state of the chocolate is "The chocolate is now made up of particles packed relatively close together, having an indefinite shape but a definite volume".

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Answer:

D

Explanation:

I hope this helps and have a great day

Answer:

b. 50ppm of Pb

c. 2x10⁻⁴M

j. no

Explanation:

The diluted sample has a concentration of 0.5 ppm of Pb. The sample was diluted from 1mL to 100mL. That means the dilution factor is:

100mL / 1mL = 100

That means, the sample was diluted 100 times from its original concentration.

As diluted sample has a concentration of 0.5ppm, the undiluted sample has a concentration of

0.5ppm×100 = 50ppm of Pb

1 ppm means 1x10⁻⁴ % by mass, 50 ppm are 50x10⁻⁴ % by mass

As molar mass of Pb is 207g/mol, molarity of 0.050g / L a(50 ppm) are:

0.050gₓ (1mol / 207g) / 1L = 2x10⁻⁴M

Based on EPA regulation, the maximum concentration of Lead in drinking water must be 0.015ppm. That means this water is not safe to drink

Answer:

A: 94

B: 36

C: Kr

Explanation:

Got them right & hope it helps :)

Answer:

A:  94

B:  36

C:  Kr

Explanation:

edg2020

From the solution that we have in the question;

The equilibrium constant, denoted as K, is a value that quantitatively represents the ratio of the concentrations of products to reactants at equilibrium in a chemical reaction.

It is a fundamental concept in chemical equilibrium.

The value of the equilibrium constant provides valuable information about the position of equilibrium and the relative concentrations of species involved in a chemical reaction.

Kc = [X] [Y]/[XY]

\(0.25 = (0.1 + x)^2/(0.5 - x)\)

\(0.25(0.5 - x) = (0.1 + x)^2\)

\(0.125 - 0.25x =0.01 + 0.2x + x^2\\ x^2 + 0.45x - 0.115 = 0\)

x = 0.18 M

The equilibrium amount of X and Y=  0.28 M and the equilibrium concentration of XY = 0.32 M

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Based on the answer to the question that we have;

The ratio of the product to reactant concentrations in a chemical reaction at equilibrium is represented quantitatively by the equilibrium constant, abbreviated as K.

It is a cornerstone of the theory of chemical equilibrium.

A chemical reaction's equilibrium position and the relative concentrations of the species involved can both be learned from the equilibrium constant's value.

Kc = [X][Y]/[XY]

\(0.25 = (0.1 + x)^2/(0.5 - x)\\0.25(0.5 - x) = (0.1 +x)^2\\0.125 - 0.25x = 0.01 +0.2x +x^2\\= 0.18 M\)

The equilibrium concentration of;

XY =0.5 - 0.18

=0.32 M

Then the equilibrium amount of

X and Y is

0.1 + 0.18= 0.28 M.

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Answer:

D

Explanation:

Photosphere is the layer where sunspots form.

Photosphere is the layer where sunspots form.

The Sun is made up of layers of material, like a baseball or rubber band ball. The photosphere is the lowest layer of the solar atmosphere. It is essentially the solar "surface" that we see when we look at the Sun in "white" (i.e. regular, or visible) light.

Like the Sun, our planet, Earth, is made up of layers, too. The thickest or most dense material on the Earth is in the very middle of our planet -- the core.

The thinnest is at the very top of our atmosphere - right next to outer space. The same is true of the Sun. But, the layers in the Sun and the Earth are much different.

Therefore, Photosphere is the layer where sunspots form.

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Taking into account the reaction stoichiometry, if 10.3 g of Ca(OH)₂ reacts, 5.01 grams of H₂O are formed.

The balanced reaction is:

2 H₃PO₄ + 3 Ca(OH)₂  → 6 H₂O + Ca₃(PO₄)₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

By reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The following rule of three can be applied: if by reaction stoichiometry 222 grams of Ca(OH)₂ form 108 grams of H₂O, 10.3 grams of Ca(OH)₂ form how much mass of H₂O?

mass of H₂O= (10.3 grams of Ca(OH)₂ ×108 grams of H₂O)÷ 222 grams of Ca(OH)₂

mass of H₂O= 5.01 grams

Finally, 5.01 grams of H₂O are formed.

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Answer:

see below

Explanation:

A. The given reaction releases energy, indicating that it is an exothermic reaction.

B. The △H value for the reaction can be written as △H = -571.7 kJ, with a negative sign indicating the energy is released.

C. The balanced equation for the reaction between hydrogen and oxygen to form water is:

2H2(g) + O2(g) → 2H2O(l)

D. To calculate the amount of energy released when 10.0g of hydrogen is reacted with an excess of oxygen, we need to first determine the amount of hydrogen involved in the reaction.

The molar mass of hydrogen is 1.008 g/mol, so 10.0 g of hydrogen is equivalent to 10.0 g / 1.008 g/mol = 9.92 mol of hydrogen.

From the balanced equation, we can see that 2 mol of hydrogen is required for every 1 mol of oxygen, so the amount of oxygen involved in the reaction is twice the amount of hydrogen.

Therefore, the amount of oxygen needed for 9.92 mol of hydrogen is 2 × 9.92 mol = 19.84 mol.

Assuming that there is an excess of oxygen, all of the hydrogen will react, so the limiting reactant is oxygen.

Using the △H value of -571.7 kJ, we can calculate the amount of energy released as follows:

-571.7 kJ / 2 mol H2 = -285.9 kJ/mol H2

So the energy released when 10.0 g of hydrogen reacts with an excess of oxygen is:

-285.9 kJ/mol H2 × 9.92 mol H2 = -2836.53 kJ

Therefore, the reaction releases 2836.53 kJ of energy when 10.0 g of hydrogen reacts with an excess of oxygen.

Answer:

2.81 g of H2O.

Explanation:

We'll begin by calculating mass of O2 that contains 1.25×10²³ molecules O2.

This can be obtained as follow:

From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.022×10²³ molecules. This implies that 1 mole of O2 also contains 6.022×10²³ molecules.

1 mole of O2 = 16x2 = 32 g.

Thus 6.022×10²³ molecules is present in 32 g of O2,

Therefore, 1.25×10²³ molecules will be present in =

(1.25×10²³ × 32) / 6.022×10²³ = 6.64 g of O2.

Therefore, 1.25×10²³ molecules present in 6.64 g of O2.

Next, the balanced equation for the reaction. This is given below:

CH4(g) + 2O2(g) —> CO2(g) + 2H2O(g)

Next, we shall determine the masses of CH4 and O2 that reacted and the mass of H2O produced from the balanced equation.

This can be obtained as follow:

Molar mass of CH4 = 12 + (4x1) = 16 g/mol.

Mass of CH4 from the balanced equation = 1 x 16 = 16 g

Molar mass of O2 = 16x2 = 32 g/mol.

Mass of O2 from the balanced equation = 2 x 32 = 64 g

Molar mass of H2O = (2x1) + 16 = 18 g/mol.

Mass of H2O from the balanced equation = 2 x 18 = 36 g

From the balanced equation above,

16 g of CH4 reacted with 64 g of O2 to produce 36 g if H2O.

Next, we shall determine the limiting reactant.

This can be obtained as follow:

From the balanced equation above,

16 g of CH4 reacted with 64 g of O2.

Therefore, 1.25 g of CH4 will react with = (1.25 x 64)/16 = 5 g of O2.

From the above calculations, we can see that only 5 g out of 6.64 g of O2 is needed to react completely with 1.25 g of CH4.

Therefore, CH4 is the limiting reactant.

Finally, we shall determine the mass of H2O produced from the reaction.

In this case, the limiting reactant will be used because it will give the maximum yield of H2O.

The limiting reactant is CH4 and the mass of H2O produced from the reaction can be obtained as follow:

From the balanced equation above,

16 g of CH4 reacted to produce produce 36 g if H2O.

Therefore, 1.25 g of CH4 will react to produce = (1.25 x 36)/16 = 2.81 g of H2O.

Therefore, 2.81 g of H2O were obtained from the reaction.

The mass in grams of H₂O which can be formed when 1.25g CH₄ are combined with 1.25×10²³ molecules O₂ is 2.8 grams.

Stoichiometry of any reaction tells about the amount of species present before and after the completion of the reaction.

Given chemical reaction is:

CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(g)

Moles of CH₄ will b calculate as:

n = W/M, where

W = given mass = 1.25g

M = molar mass = 16g/mol

n = 1.25/16 = 0.078 moles

Molecues of CH₄ in 0.078 moles = 0.078×6.022×10²³ = 0.46×10²³

Given molecules of O₂ = 1.25×10²³

Required molecules of CH₄ is less as compared to the molecules of O₂, so here CH₄ is the limiting reagent and formation of water is depends on it only.

From the stoichiometry of the reaction it is clear that:

1 mole of CH₄ = will produce 2 moles of H₂O

0.078 moles of CH₄ = will produce 2×0.078=0.156 moles of H₂O

Mass of H₂O will be calculated by using its moles as:

W = (0.156)(18) = 2.8g

Hence required mass of H₂O is 2.8g.

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Answer:

35.5 is the answer

Explanation:

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26.8L is the volume, in liters, of 1.20 mol of C\(_3\)H\(_8\) gas at STP. A measurement of three-dimensional space is volume.

A measurement of three-dimensional space is volume. It is frequently expressed quantitatively using SI-derived units, like the cubic metre or litre, or different imperial or US-standard units, including the gallon, quart and cubic inch. Volume and length (cubed) have a symbiotic relationship.

The volume of an envelope is typically thought of as its capacity, not as the amount of space it takes up. In other words, the volume is the quantity of fluid (liquid or gas) that the container may hold.

Volume = 1.20×22.4

              =26.8L

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Ammonia (\(NH_3\)) and ammonium chloride (\(NH_4Cl\)) mixture could be a useful buffer in a solution. Option C

A buffer is a solution that can resist changes in pH when small amounts of acid or base are added. It consists of a weak acid and its conjugate base or a weak base and its conjugate acid. The buffer system works by the principle of Le Chatelier's principle, where the equilibrium is shifted to counteract the changes caused by the addition of an acid or a base.

In option A, acetic acid (\(CH_3CO_2H\)) is a weak acid, but hydrochloric acid (HCl) is a strong acid. This combination does not form a buffer because HCl is completely dissociated in water and cannot provide a significant concentration of its conjugate base.

Option B consists of sodium hydroxide (NaOH), which is a strong base, and elemental sodium (Na), which is a metal. This combination does not form a buffer as there is no weak acid-base pair involved.

Option D contains acetic acid (\(CH_3CO_2H\)), a weak acid, and ammonia (\(NH_3\)), a weak base. Although they are weak acid and base, they do not form a buffer system together as they are both weak acids or bases and lack the required conjugate acid-base pair.

Option C, ammonia (\(NH_3\)), is a weak base, and ammonium chloride (\(NH_4Cl\)) is its conjugate acid. This combination can form a buffer system. When ammonia reacts with water, it forms ammonium ions (NH4+) and hydroxide ions (OH-).

The ammonium ions act as the weak acid, while the ammonia acts as the weak base. The addition of a small amount of acid will be counteracted by the ammonium ions, and the addition of a small amount of base will be counteracted by the ammonia, thus maintaining the pH of the solution relatively stable.

Therefore, option C, consisting of ammonia (\(NH_3\)) and ammonium chloride (\(NH_4Cl\)), is the suitable mixture that could be a useful buffer in a solution.

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In the given reaction, the limiting reactant is C₆H₆ (benzene).

To determine the limiting reactant as well as calculate the mass of HCl produced, compare the moles of each reactant.

The number of moles for each reactant:

Molar mass of Cl₂ = 35.5 g/mol + 35.5 g/mol = 71 g/mol

Moles of Cl₂ = mass of Cl₂ / molar mass of Cl₂

                     = 45 g / 71 g/mol

                     = 0.634 moles of Cl₂

Molar mass of C₆H₆ (benzene) = 12 g/mol + 6(1 g/mol) = 78 g/mol

Moles of C₆H₆ = mass of C₆H₆ / molar mass of C₆H₆

                        = 45 g / 78 g/mol = 0.577 moles of C₆H₆

Determine the stoichiometry between Cl₂ and HCl:

Cl₂ + C₆H₆ → C₆H₅Cl + HCl

Here, we can see that 1 mole of Cl₂ produces 1 mole of HCl.

Thus, the limiting reactant is C₆H₆ (benzene).

Calculate the mass of HCl produced:

Molar mass of HCl = 1 g/mol + 35.5 g/mol = 36.5 g/mol

Moles of HCl produced = moles of C₆H₆ = 0.577 moles

Mass of HCl produced = moles of HCl produced × molar mass of HCl

Mass of HCl produced = 0.577 moles × 36.5 g/mol

                                     ≈ 21.04 g

Therefore, approximately 21.04 grams of HCl will be produced.

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Answer:

pH of 7 is neutral

pH of 4 is weak acid

Explanation:

hope it helps you..

Answer:

Maybe (D)

......,.,......

The convergent plate boundary is the movement of the lithospheric plates. The North American plate boundary and the Aleutian trench is the site of convergent plate boundary. Thus, options B and D are correct.

A convergent plate boundary is the type of plate boundary and is marked by the region where the tectonic plates of the lithospheric region collide with each other due to the process of subduction.

The convergent plate boundary can be seen between ocean‐ocean, continent‐continent, and ocean‐continent. The convergent boundary is seen in the Aleutian trench and the North American Plate that is under the subduction process. On the other hand, the Mid-Atlantic Ridge and the Atlantic-Indian ridge has divergent or constructive plate boundary.

Therefore, options B and D. North American plate boundary and the Aleutian trench is the site of convergent plate boundary.

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According to the concept of molar concentration, molarity of the solution is 1.525 M.

Molar concentration is defined as a measure by which concentration of chemical substances present in a solution are determined. It is defined in particular reference to solute concentration in a solution . Most commonly used unit for molar concentration is moles/liter.

The molar concentration depends on change in volume of the solution which is mainly due to thermal expansion. Molar concentration is calculated by the formula, molar concentration=mass/ molar mass ×1/volume of solution in liters.

In terms of moles, it's formula is given as molar concentration= number of moles /volume of solution in liters.

In the given problem, by substituting values in mentioned formula related to moles we get,7.32/4.80=1.525 M.

Thus , the molarity of solution is 1.525 M.

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The number of moles of gas produced from the reaction of 2.00g of potassium with an excess amount of water is 0.025 moles.

The reaction of potassium with an excess amount of water is:

2K + 2H\(_2\)O \(\rightarrow\) 2KOH + H\(_2\)

To calculate the moles of hydrogen gas first we need to calculate moles of potassium in 2.00g

No. of moles = (mass) / (molecular mass)

The mass given is 2.00 g and the Molecular mass is 39.09 units

∴ No. of moles = (2) / (39.09) = 0.05

From the above reaction, we get that 2 moles of potassium give 1 mole of hydrogen gas. Thus, 0.05 moles of potassium gives 0.025 moles of hydrogen gas.

Therefore, the no. of moles of hydrogen gas produced is 0.025 moles.

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The products of the alpha decay of radium-226 and the beta decay of carbon-14 are radon-222 and nitrogen-14, respectively.

The alpha decay of radium-226 results in the emission of an alpha particle, which is a helium nucleus consisting of two protons and two neutrons.

Therefore, the product of the alpha decay of radium-226 is radon-222:

Ra-226 → Rn-222 + alpha particle

On the other hand, In the case of carbon-14, beta minus decay occurs, in which a neutron is converted into a proton, and an electron and an antineutrino are emitted.

So carbon-14 becomes nitrogen-14:

C-14 → N-14 + beta particle

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--The complete Question is, What is the product of the alpha decay of radium-226 and the beta decay of carbon-14?--