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The frequency at which the capacitive reactance is 375 ω and the Capacitance of 3.25 μF is 131 s⁻¹.

Capacitance is the ability or capacity of the substance to collect and store electrical energy and the unit of capacitance is Farad (F). Capacitive reactance is the term that measures the opposition to current flow in the AC circuits and the unit of capacitive reactance is the ohm(Ω).

From the given,

The capacitive reactance (Xc) = 375ω

capacitance (C) = 3.25μF

capacitive reactance Xc = 1/(2π×f×C)

Frequency (f) = 1/(2π×Xc×C)

                     = 1/(2×3.14×375×3.25×10⁻⁶)

                     = 131 s⁻¹.

Thus, the frequency of the capacitive reactance is 131 s⁻¹.

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To change a large amount of force with a small force, you will have to apply the force over a longer period of time. So, option (a) is correct.

In physics, the term "impulse" is used to characterize or measure the impact of force operating gradually to alter an object's motion. It is often stated in Newton-seconds or kilograms per second and is denoted by the symbol J.

Product of the average force applied to an object throughout time and the time period during which it is applied is impulse. The change in momentum is the same as impulse.

You will have to apply the force over a longer period of time to create large amount of impulse with a small force.

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The mass rate of change of the space probe is approximately 28.49 kg/s .

To solve this problem, we can use the generalized form of Newton's Second Law, which states that the force acting on an object is equal to its mass times its acceleration:

F = ma

In this case, the force acting on the space probe is the thrust force generated by the rocket motor, which is equal to the rate of change of momentum of the ejected fuel:

F = (Δ m /Δt) * v

where;

Since the space probe is landing on the planet, the net force acting on it should be equal to the force of gravity pulling it down minus the upward thrust force generated by the rocket motor. So we can write:

F_net = m * g - (Δ m /Δt) * v

Plugging in the values and solving for delta m / delta t, we get:

2.00 m/s² = (175,000 kg * 8.25 m/s²) - (Δ m / Δt) * 35,000 m/s

Δ m / Δt = (175,000 kg * 8.25 m/s² - 2.00 m/s² * 35,000 m/s) / 35,000 m/s

Δm / Δt ≈ 28.49 kg/s

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Answer:

1500000 Pa

Explanation:

The formula for pressure is force per unit area.

P=F/A where  F is force and A is area

Given that ;

F= mass * acceleration due to gravity

F= 60 * 9.81 = 588.6 = 589 N

A= area = 4cm² = 0.0004 m²

P= F/A = 589 / 0.0004

P= 1471500

P=1500000 Pa

Answer:

La energía potencial elástica es la energía asociada con los materiales elásticos. Por ejemplo, un resorte al ser comprimido o elongado almacena energía potencial elástica y, al ser soltado, puede realizar trabajo sobre un objeto.

Para mantener el resorte comprimido o alargado una cierta longitud x, a partir de su largo natural, es necesario que, en este caso, la mano aplique una fuerza F_{M} sobre el resorte; esta fuerza es directamente proporcional a x.

Explanation:

ón conocida como ley de Hooke.

Para encontrar una expresión que describa la energía potencial asociada con la fuerza del resorte, se determina el trabajo que se requiere para comprimir el resorte desde su posición de equilibrio hasta cierta posición final arbitraria x. Debido a que la fuerza varía desde O hasta kx, se utiliza la fuerza promedio \frac{(F_{0}+F_{X})}{2}.

 \[ \bar{F}=\frac{0+K X}{2}=\frac{1}{2}kx \]

fuerza-sobre-un-resorte

Fuerza sobre un resorte. La fuerza para estirar un resorte aumenta linealmente con su elongación .

El trabajo realizado por la fuerza aplicada será: W=\bar{Fx}=\frac{1}{2}kx^{2}

El trabajo realizado se almacena en el resorte comprimido en forma de energía potencial elástica como:

 \[ \boxed{ Ep_{elas}=\frac{1}{2}kx^{2}} \]

Una vez que se ha comprimido o estirado el resorte respecto a su posición de equilibrio, la energía potencial elástica se puede considerar como la energía almacenada en el resorte deformado. Esta energía siempre es positiva en un objeto deformado al depender de x^{2}.

Por ejemplo, en la figura se observa que un resorte realiza trabajo sobre un bloque. El resorte que se encuentra sin deformar (a) cuando es empujado por un bloque de masa m, se comprime una distancia x (b). Cuando el bloque se suelta (c), partiendo del reposo, la energía potencial plástica almacenada en el sistema se transforma en energía cinética del bloque.

energia-potencial

Answer:

Therefore, the 10 kg mass should be placed at x = 5.7 m along the x-axis to achieve a center of mass located at y = 4.5 m.

Explanation:

To find the position along the x-axis where a 10 kg mass should be placed such that the center of mass is located at y = 4.5, we can use the formula for the center of mass:

x_cm = (m1 * x1 + m2 * x2) / (m1 + m2)

Here, m1 and x1 represent the mass and position of the 8 kg mass, respectively. m2 is the mass of the 10 kg mass, and we need to find x2, its position.

Given:

m1 = 8 kg

x1 = 3 m

x_cm = unknown (to be found)

m2 = 10 kg

y_cm = 4.5 m

Since the center of mass is at y = 4.5, we only need to consider the y-coordinate when calculating the center of mass position along the x-axis.

To solve for x2, we can rearrange the formula as follows:

x2 = (x_cm * (m1 + m2) - m1 * x1) / m2

Substituting the given values:

x2 = (x_cm * (8 kg + 10 kg) - 8 kg * 3 m) / 10 kg

Simplifying:

x2 = (x_cm * 18 kg - 24 kg*m) / 10 kg

Now, we can set the y-coordinate of the center of mass equal to 4.5 m and solve for x_cm:

4.5 m = (8 kg * 3 m + 10 kg * x2) / (8 kg + 10 kg)

Simplifying:

4.5 m = (24 kg + 10 kg * x2) / 18 kg

Multiplying both sides by 18 kg:

81 kg*m = 24 kg + 10 kg * x2

Subtracting 24 kg from both sides:

10 kg * x2 = 81 kg*m - 24 kg

Dividing both sides by 10 kg:

x2 = (81 kg*m - 24 kg) / 10 kg

Simplifying:

x2 = 8.1 m - 2.4 m

x2 = 5.7 m

(brainlest?) ples:(

Answer:

the 10 kg mass should be placed at x = -2.4 m to achieve a center of mass at y = 4.5 m.

Explanation:

To find the position along the x-axis where the 10 kg mass should be placed so that the center of mass is located at y = 4.5, we can use the principle of the center of mass.

The center of mass of a system is given by the equation:

x_cm = (m1x1 + m2x2) / (m1 + m2),

where x_cm is the x-coordinate of the center of mass, m1 and m2 are the masses, and x1 and x2 are the positions along the x-axis.

Given:

m1 = 8 kg,

x1 = 3 m,

m2 = 10 kg,

y_cm = 4.5 m.

To solve for x2, we need to find the x-coordinate of the center of mass (x_cm) by using the y-coordinate:

y_cm = (m1y1 + m2y2) / (m1 + m2),

where y1 and y2 are the positions along the y-axis.

Rearranging the equation and substituting the given values:

4.5 = (83 + 10y2) / (8 + 10).

Simplifying the equation:

4.5 = (24 + 10*y2) / 18.

Multiplying both sides by 18:

81 = 24 + 10*y2.

Rearranging the equation:

10*y2 = 81 - 24,

10*y2 = 57.

Dividing both sides by 10:

y2 = 5.7.

Therefore, the y-coordinate of the 10 kg mass should be 5.7 m.

To find the x-coordinate of the 10 kg mass, we can use the equation for the center of mass:

x_cm = (m1x1 + m2x2) / (m1 + m2).

Substituting the given values:

x_cm = (83 + 10x2) / (8 + 10).

Since the center of mass is at x_cm = 0 (the origin), we can solve for x2:

0 = (83 + 10x2) / (8 + 10).

Rearranging the equation:

83 + 10x2 = 0.

24 + 10*x2 = 0.

10*x2 = -24.

Dividing both sides by 10:

x2 = -2.4.

The advantage that the runner nearest the gun in the 100-meter dash might have is known as  the "reaction time advantage."

A reaction time advantage is known to allow runners in a race  to be agile and efficient when it comes to responding to stimuli in situations like driving, playing sports, or even having a conversation.

It is believed that the runner closest to the gun has a shorter distance for the sound wave to travel which might result in a slightly quicker reaction time in comparison to the other runners.

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The magnitude of the initial acceleration of the object is 4.2 m/s².

The tension in the string once the object starts moving is 13.65 N.

The magnitude of the initial acceleration of the object is calculated by applying Newton's second law of motion as follows;

F(net) = ma

m₂g - μm₁g cosθ = a(m₁ + m₂)

where;

(4.75 x 9.8) - (0.535 x 3.25 x 9.8 x cos40) = a(3.25 + 4.75)

33.5 = 8a

a = 33.5/8

a = 4.2 m/s²

The tension in the string once the object starts moving is calculated as;

T = m₁a

T = 3.25 x 4.2

T = 13.65 N

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A parallel circuit is an electrical circuit with more than one current path and all circuit components are connected between the same two sets of electrically common points. The current supplied by the source in a parallel circuit is equal to the sum of all branch currents in the circuit.

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The statement that is an example of diffraction is Sound bending around a corner. Option D

Diffraction refers to the bending or spreading of waves as they encounter an obstacle or pass through a narrow opening. Sound waves, being a type of wave, can undergo diffraction when they encounter an obstacle or a narrow opening.

In the case of sound waves bending around a corner, the waves encounter an obstacle (the corner) and are forced to bend around it, resulting in a diffraction pattern.

Hence, Option a refers to refraction, where light changes direction as it passes through a medium with a different refractive index (e.g., entering a prism). Option b refers to attenuation, where sound waves decrease in amplitude (i.e., become muffled) as they pass through an obstacle such as a wall. Option c refers to reflection, where light waves bounce off a surface such as a mirror.

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The average force is equal to the area under the curve of force versus time divided by the time of contact between the hammer and the nail.

The equation can be used to determine the average force the nail applies to the hammer.

\(F = \frac{mv}{t}\), where m is the hammer's mass, v is its speed, and t is the time at which it made impact with the nail. The average force in this situation is given by:

\(F = \frac{(2.5 kg)(6 m/s - 2.0 m/s)}{(0.002 s)}\\ F= 4500 N.\)

To solve this problem using force vs. time, you would need to plot a graph of force versus time, with the time of contact between the hammer and the nail representing the x-axis and the force exerted on the hammer by the nail representing the y-axis. The force exerted on the hammer increases from 0 to 4500 N as the hammer moves from rest to its maximum velocity. The average force is equal to the area under the curve of force versus time divided by the time of contact between the hammer and the nail.

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Answer:

The rate of acceleration slow

Explanation:

Force (N) = mass (kg) × acceleration (m/s²) , because acceleration multiply by mass it a inverse relationship

Answer:

I think 32

Explanation:

Answer:

The velocity is \(v = 4.76 \ m/s\)

Explanation:

From the question we are told that

   The first distance is   \(d_1 = 4.0 \ km = 4000 \ m\)

   The  first speed  is  \(v_1 = 5.0 \ m/s\)

    The  second distance is  \(d_2 = 1.0 \ km = 1000 \ m\)

    The  second speed  is  \(v_2 = 4.0 \ m/s\)

Generally the time taken for first distance is  

      \(t_1 = \frac{d_1 }{v_1 }\)

        \(t_1 = \frac{4000}{5}\)

       \(t_1 = 800 \ s\)

The time taken for second  distance is

           \(t_1 = \frac{d_2 }{v_2 }\)

        \(t_1 = \frac{1000}{4}\)

       \(t_1 = 250 \ s\)

The total time is mathematically represented as

     \(t = t_1 + t_2\)

=>   \(t = 800 + 250\)

=>    \(t = 1050 \ s\)

Generally the constant velocity that would let her finish at the same time is mathematically represented as

      \(v = \frac{d_1 + d_2}{t }\)

=>    \(v = \frac{4000 + 1000}{1050 }\)

=>    \(v = 4.76 \ m/s\)

The constant speed that will let her finish in the same time as in the first race is 4.76 m/s

Time 1 = distance / speed

Time 1 = 4000 / 5

Time 1 = 800 s

Time 2 = distance / speed

Time 2 = 1000 / 4

Time 2 = 250 s

Constant speed = Total distance / total time

Constant speed = 5000 / 1050

Constant speed = 4.76 m/s

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Answer:

94.248 g/sec

Explanation:

For solving the total current of the blood passing first we have to solve the cross sectional area which is given below:

\(A_1 = \pi R^2\\\\A_1 = \pi (1)^2\\\\A_1 = 3.1416 cm^2\)

And, the velocity of blood pumping is 30 cm^2

Now apply the following formula to solve the total current

\(Q = \rho A_1V_1\\\\Q = (1)(3.1416)(30)\\\\\)

Q =  94.248 g/sec

Basically we applied the above formula So, that the total current could come

Answer:

I think it is A.

Explanation:

Word has a meaning similar to obesity?

Fatness

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The state of being fat

A condition characterized by abnormal or excessive fat accumulation.

Treatable by a medical professional

Does diagnosis require lab test or imaging?

Doesn't require lab test or imaging

Time taken for recovery

Can last several years or be lifelong

Condition Highlight

Family history may increase likelihood for some types

Answer:

360 N

Explanation:

m = 30kg    u = 2 m/s     a = -2m/s/s

Since the object has an initial velocity of 2 m/s and acceleration of -2 m/s/s

the object will come to rest in 1 second but the force applied in that one second can be calculated by:

F = ma

F = 30 * -2

F = -60 N (the negative sign tells us that the force is acting downwards)

Now, calculating the force applied on the box due to gravity

letting g = -10m/s/s

F = ma

F = 30 * -10

F = -300 N (the negative sign tells us that the force is acting downwards)

Now, calculating the total downward force:

-300 + (-60) = -360 N

Hence, a downward force of 360 N is being applied on the box and since the box did not disconnect from the rope, the rope applied the same amount of force in the opposite direction

Therefore tension on the force = 360 N

Answer:

Tension

Explanation:

Differentiation

Derivative Rule [Basic Power Rule]:

\(\displaystyle\begin{aligned}f(x) & = cx^n \\f'(x) & = c \cdot nx^{n - 1} \\\end{aligned}\)

Derivative Rule [Chain Rule]:
\(\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)\)

Let's define what the problem gives us:

We know from our trigonometric derivatives that the derivative of \(\displaystyle \sin x\) is equal to \(\displaystyle \cos x\). However, since we have some arbitrary constant \(\displaystyle a\) multiplying \(\displaystyle x\) inside our \(\displaystyle \sin x\) function, we will have to apply the derivative rule of Chain Rule:

\(\displaystyle\begin{aligned}y & = \sin ax \\y' & = \boxed{ \cos (ax) (ax)' } \\\end{aligned}\)

To further simply the derivative, we now apply the derivative rule of Basic Power Rule and simplify:

\(\displaystyle\begin{aligned}y & = \sin ax \\y' & = \cos (ax) (ax)' \\& = (ax)' \cos ax \\& = 1 \cdot ax^{1-1} \cos ax \\& = ax^0 \cos ax \\& = \boxed{ a \cos ax } \\\end{aligned}\)

∴ the derivative of the function \(\displaystyle y = \sin ax\) is equal to \(\displaystyle \boxed{ y' = a \cos ax }\).

___

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Topic: Calculus

Unit: Differentiation

25.487 km did the scramjet travel during its 11 second test.

Given that the scramjet travels at a speed seven times that of sound, speed v is equal to 7 x 331 m/s or 2317 m/s.

(A) We require the scramjet's travel time over a distance of

       d = 5000 km (5x10^6 m).

Using the formula

time taken = distance traveled/speed,

we can calculate the following:

(5x10^6)/2317 sec

= (5x10^6)/(23175x60) minute

= 5000000/139020 minutes

= 35.97 seconds

As 1 second equals 1/60 of a minute, Therefore, the travel time on Scramjet from San Francisco to New York will be 35.97 minutes.

(B) The distance covered by the Scramjet in 11 seconds must now be determined. as a result,

using speed, distance, and time relation.

Distance = Speed x Time

               = 7  x 331  x 11

                =  25487 m

Since 1 metre equals 1/1000 of a kilometer, 25487 m of 25.487 km

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Answer:

Below

Explanation:

First, we need to find the time of flight of this projectile :

     \(t=\sqrt{\frac{2dy}{g} }\)

     \(t =\sqrt{\frac{2(0.99)}{9.81}\)

     \(t =\sqrt{\frac{1.98}{9.81}\)

     \(t =\sqrt{0.20183486238}\)

     \(t = 0.448489506\) \(seconds\)

Now we can use this formula to find the initial horizontal velocity :

     \(Dhorizontal = Vhorizontal (time)\)

     \(0.34 m = Vx(0.448489506) \\0.76m/s^2 = Vx\)

Therefore the initial velocity of the baseball was 0.76 m/s^2 [Forward]

Hope this helps! Best of luck <3

Answer:

[See Below]

Explanation:

✦ Formula = \(Mass / 1000\)

  ✧ \(4800 / 1000 = 4.8\)

So \(4800\) grams is equal to \(4.8\) kilograms.

~Hope this helps Mate. If you need anything feel free to message me.

I believe that Gigafood is the future of food. It is a healthy, convenient, and sustainable way to get all the nutrients our bodies need. I am excited to see how Gigafood can change the way people eat.

Name: Gigafood

Company: Gigafood, Inc.

Components:

Gigafood is a complete and balanced meal that provides all the essential nutrients the body needs.

Macronutrients: Carbohydrates are the body's main source of energy. Fats provide essential fatty acids and help the body absorb vitamins. Protein is necessary for building and repairing tissues.

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Antioxidants: Berries and nuts are rich in antioxidants, which help protect the body against damage from free radicals.

Slogan: Gigafood: The only food you'll ever need.

Disclaimer: Gigafood is a healthy and nutritious food, but it is not a cure for any disease. It is important to eat a balanced diet and get regular exercise.

Health benefits:

Diseases or conditions that Gigafood can help with:

Gigafood is a convenient and delicious way to get all the nutrients your body needs.

Gigafood is a healthy and sustainable choice for the environment.

Gigafood is a great way to save time and money on food.

The advertisement should be visually appealing and easily noticeable. It should use bright colors and simple graphics to capture attention. The advertisement should also include the Gigafood logo and slogan.

I believe that Gigafood is the future of food. It is a healthy, convenient, and sustainable way to get all the nutrients our bodies need. I am excited to see how Gigafood can change the way people eat.

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Answer:

Joules is considered as the SI unit because it measures the capacity to do work or generate heat

Answer:

when an electric current of one ampere passes through a resistance of one ohm for one second. It is named after the English physicist James Prescott Joule

Explanation:

Hope this helps <3

~lil pickle

ANSWER:

Sound waves are faster in water

STEP-BY-STEP EXPLANATION:

Sound travels differently in water than it does in air.

Sound waves travel faster in denser substances because neighboring particles will more easily collide with each other.

Water is denser than air, which means that sound waves travel much faster in water than in air.

Although they travel faster in water, we must keep in mind that the human ear evolved to hear sounds in the air and is not as useful when submerged in water.

Answer:

Hello There!!

Explanation:

The answer is=> It is a common component of antacids.

hope this helps,have a great day!!

~Pinky~

Answer:

chloride, ion, -1, this is an anion

Answer:

i Believe the correct answer is "An open circuit being changed into a closed circuit"

Explanation:

Answer:

A CT scan involces multiple X-Ray images

Explanation:

A patient receives more radiation from a CT scan than from having an X-ray image made because a CT scan involves multiple X-ray images. Thus, option A is correct.

A computed tomography scan is a type of medical imaging procedure used to produce in-depth pictures of the body's inside. The individuals who perform CT scans are known as radiologists or radiography technologists.

Identify conditions affecting the muscles and bones, such as bone cancers and fractures. Identify a tumor, an infection, or a blood clot's precise site. Surgical, biopsied, and radiation therapy guidelines Find and keep an eye on problems and illnesses like cancer, heart disease, lung nodules, and liver masses.

A patient receives more radiation from a CT scan than from having an X-ray image made because a CT scan involves multiple X-ray images. Thus, option A is correct.

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Your question is incomplete, most probably the full question is this:

Why does a patient receive more radiation from a CT scan than from having an X-ray image made?

A. A CT scan involves multiple X-ray images.

B. Higher-frequency rays are used in a CT scan.

C. Fewer X-rays are reflected in a CT scan.

D. X-rays are more powerful in a CT scan.