Plz help me in this math​

Step-by-step explanation:

The probability of not snowing is 1-4/11=7/11

The sum of integers from 33 to 47 is 600.

So, the sum of integers:

Simply perform addition as follows:

Therefore, the sum of integers from 33 to 47 is 600.

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Answer:

No solution is the correct answer for this inequality.

Step-by-step explanation:

equation 1 equal to  y > \(\frac{3x}{2}\) -1

equation 2 equals to y < \(\frac{3x}{2}\) -1

and can be written as

\(\[\frac{3}{2}x - 1 < \frac{3}{2}x - 1\]\)

which clearly shows there is no solution

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The distance = speed * time

The time is 13 seconds

The speed is 7 m/second

So we can find the distance

D is the distance

S is the speed

t is the time

S = 7 m/s

t = 13 s

You could run 91 m

Answer:

BCD

Step-by-step explanation:

Is that hegarty maths? Just curious. Anyway acute means a angle below 90

Answer:

∠C

Step-by-step explanation:

Angle A is incorrect because it is 90° and acute angles are LESS than 90°.

Angle B is incorrect because it is more than 90° which makes it obtuse.

Angle D is incorrect because it is more than 90° which makes it obtuse.

Angle C is correct because it is less than 90°.

Answer:190

Step-by-step explanation:

We can write the scale factor for the table as {K} = y/x.

Given is to determine the scale for the given table.

Therefore, we can write the scale factor for the table as {K} = y/x.

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Answer:

\(2(20) \times 3(60) \\ 40 \times 180 = 7200\)

The area of a square inscribed in a circle is 25, then the area of the circle is 25π/2 or approximately 39.27 square units.

To solve this problem, we can use the relationship between the area of a square inscribed in a circle and the area of the circle itself.

When a square is inscribed in a circle, the diagonal of the square is equal to the diameter of the circle. Let's assume that the side length of the square is 's' and the radius of the circle is 'r'.

We are given that the area of the square is 25, so we can find the side length of the square:

Area of square = \(s^2 = 25\)

Taking the square root of both sides, we get:

s = √25 = 5

Since the diagonal of the square is equal to the diameter of the circle, we can find the diameter of the circle:

Diagonal = Diameter = s√2 = 5√2

The radius of the circle is half the diameter, so:

Radius = 5√2 / 2 = (5√2)/2

Now, we can calculate the area of the circle using the formula:

Area of circle = \(\pi r^2\)

Substituting the value of the radius, we get:

Area of circle = π((5√2)/\(2)^2\) = π(25/2) = 25π/2

Therefore, the area of the circle is 25π/2 or approximately 39.27 square units.

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"s" can be concluded from the premises

To use the rules of inference to show that "s" is a conclusion, we can use modus ponens,

This is a rule that allows us to infer a conclusion from a premise and its conditional statement.

Thus, "s" can be concluded from the premises "p → q", "q → r", "(q → r) → s", and "p".

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The center of the hanger represents an equal sign, since both sides of the hanger are equal.

Given different coloured triangles and shapes, we can assign a variable to each of them.

Let one green triangle be equal to \(a\).

Let one blue square be equal to \(b\)

Let one red circle be equal to \(c\).

Let one yellow pentagon be equal to \(d\).

On the left side of the hanger/equation, there are 3 green triangles. This means that one of our terms in our equation will be \(3a\).

Under the triangles on the left side is 1 blue square. This means that the next term could be \(1b\), or just \(b\).

Next is 2 red circles ⇒ \(2c\)

And finally are 3 yellow pentagons ⇒ \(3d\)

To sum up the left side as an expression, we can write all the terms we have just written as a sum:

\(3a+b+2c+3d\)

Now, after doing the same procedure for the right side of the hanger, we get:

\(2a+3b+c+2d\)

For now, we only have two expressions representing the two sides of the hanger:

Left: \(3a+b+2c+3d\)

Right: \(2a+3b+c+2d\)

To turn these into an equation, we must have an equal sign.

Remember that both sides of the hanger are equal. Knowing this, we can state the following:

Left side = Right side

\(3a+b+2c+3d = 2a+3b+c+2d\)

\(3a+b+2c+3d = 2a+3b+c+2d\)

Answer:

interquartile range = 6

Step-by-step explanation:

the interquartile range is the difference between the upper quartile Q₃ and the lower quartile Q₁

Q₃ is the value at the right side of the box, that is 86

Q₁ is the value at the left side of the box, that is 80

interquartile range = Q₃ - Q₁ = 86 - 80 = 6

Answer:

what is the expressio

Step-by-step explanation:

Answer:

36^6 or 2176782336

Step-by-step explanation: if you multiply 10^2 would equal because you would multiply 10 by 10 and 4^3 would equal 64 because you would have to multiply four 3 times (4 x 4 x 4) and you subtract 100 and 64 (100 - 64) and you get 36 BUT, the question says "Give your answer as APO 6, so you put your answer as 36^6 or 2,176,782,336

After expansion we get (-4x-2) , (4x+2), ( -10x+6), (-15x+9)

The way of multiplication by removing parathesis is called expansion. we use expansion rules for rearrangement of algebraic phrase and solving algebraic equation.

The next step of expansion is the addition or subtraction of like term.

The problems given in the question asked to expand. we expanded it multiplying by the factor and removing parenthesis, -2(2x+1)

-4x-2

(2x+1)+(2x+1)

4x+2

-2(5x)-2(-3)

-10x+6

-15x+9

hence, the algebraic terms are expanded step by step.

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Step-by-step explanation:

use length x width x height

Answer:The volume of a rectangular pyramid is 120 cubic centimeters. The base is 12 centimeters long and 5 centimeters wide. What is its height?

A.2

Step-by-step explanation: so rember try your best

a.) The value of pulses exported by US in billion would be=30 billion.

b.) The ratio of wheat export of UK to maize export of IND would be= 6:5

For question a.)

To calculate the pulses, the following steps should be taken as follows:

From the bar chart, the value of pulses in billions = 30 billions.

For question b.)

The ratio of wheat export at UK and maize export at IND would be calculated as follows:

The quantity of wheat export at UK = 24

The quantity of maize export at IND = 20

Therefore, the ratio of wheat to maize = 24:20= 6:5

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The function that best models this scenario is C of x equals 3.75 times x if x is less than 5 and 3.25x plus 5 if x is greater than 6.

Let the number of hours be illustrated as x. In this situation, local city park rents kayaks for $3.75 per hour. This will be:

= 3.75 × x

= 3.75x

Also, customer rents for four or more hours, the cost is only $3.25 per hour, plus a $5 processing fee. This will be illustrated as:

= 5 + (3.25 × x)

= 5 + 3.25x

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Answer:

4322 ft^2

Step-by-step explanation:

First, we need a formula. The formula is (50*110) - (3.14*18^2) - (4*40). The answer is 4322 ft^2 (This is the rounded answer)

9514 1404 393

Answer:

  $1814.38

Step-by-step explanation:

The future value will be ...

  A = P(1 +r/n)^(nt)

where P is the principal invested at annual rate r compounded n times per year for t years.

  6000 = P(1 +0.08/12)^(12·15) = P(1.00666667)^180 = 3.3069215P

  P = 6000/3.3069215 = 1814.38

You need to deposit $1814.38 in the account.

Answer:

Step-by-step explanation:

5

Answer:

Step-by-step explanation:

$100x0.5x1=$5

Answer:

\(13k - 5\)

Step-by-step explanation:

\(5(2k + 2) + 3(k - 5) = 10k + 10 + 3k - 15 \\ = 13k - 5\)

Therefore the result of adding the system of equations  2x + y = 4  ,

6=3x-y is 5x =10

Equations are statements in mathematics containing the equals (=) sign flanked on either side by two algebraic expressions. The relationship between the expressions printed on the left and right sides is shown to be equal in this way. In all mathematical equations, LHS = RHS  is used. You can solve equations to find the value of an unknown variable that stands in for an unknown quantity. If a sentence lacks a "equal to" sign, it is not considered an equation. It will be considered to be a phrase.

Here,

Given:

we have to solve the system of equations given. .Each equation is added together to remove the variable Y.

2x + y = 4  

+

3x - y = 6

________

=> 5x =10

Therefore the result of adding the system of equations  2x + y = 4  ,

6=3x-y is 5x =10

The value of x :

x =10 / 5 = 2

⇒ x=2

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Answer:

247 students

Step-by-step explanation:

37/75 = .49333...

so you multiply the 500 by .49333... and get

246.666

round up and get 247

Answer:

(1) The point estimate for the population mean is 4.925.

(2) Therefore, a 95% confidence interval for the population mean pH of rainwater is [4.715, 5.135] .

(3) Therefore, a 99% confidence interval for the population mean pH of rainwater is [4.629, 5.221] .

(4) As the level of confidence increases, the width of the interval increases.

Step-by-step explanation:

We are given that the following data represent the pH of rain for a random sample of 12 rain dates.

X = 5.20, 5.02, 4.87, 5.72, 4.57, 4.76, 4.99, 4.74, 4.56, 4.80, 5.19, 4.68.

(1) The point estimate for the population mean is given by;

Point estimate, \(\bar X\) = \(\frac{\sum X}{n}\)

                            = \(\frac{5.20+5.02+ 4.87+5.72+ 4.57+ 4.76+4.99+ 4.74+ 4.56+ 4.80+5.19+ 4.68}{12}\)

                            = \(\frac{59.1}{12}\)  = 4.925

(2) Let \(\mu\) = mean pH of rainwater

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                             P.Q.  =  \(\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }\)  ~  \(t_n_-_1\)

where, \(\bar X\) = sample mean = 4.925

             s = sample standard deviation = 0.33

            n = sample of rain dates = 12

            \(\mu\) = population mean pH of rainwater

Here for constructing a 95% confidence interval we have used a One-sample t-test statistics as we don't know about population standard deviation.

So, 95% confidence interval for the population mean, \(\mu\) is ;

P(-2.201 < \(t_1_1\) < 2.201) = 0.95  {As the critical value of t at 11 degrees of

                                               freedom are -2.201 & 2.201 with P = 2.5%}  

P(-2.201 < \(\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }\) < 2.201) = 0.95  

P( \(-2.201 \times {\frac{s}{\sqrt{n} } }\) < \({\bar X-\mu}\) < \(2.201 \times {\frac{s}{\sqrt{n} } }\) ) = 0.95

P( \(\bar X-2.201 \times {\frac{s}{\sqrt{n} } }\) < \(\mu\) < \(\bar X+2.201 \times {\frac{s}{\sqrt{n} } }\) ) = 0.95

95% confidence interval for \(\mu\) = [ \(\bar X-2.201 \times {\frac{s}{\sqrt{n} } }\) , \(\bar X+2.201 \times {\frac{s}{\sqrt{n} } }\) ]

                                      = [ \(4.925-2.201 \times {\frac{0.33}{\sqrt{12} } }\) , \(4.925+2.201 \times {\frac{0.33}{\sqrt{12} } }\) ]  

                                     = [4.715, 5.135]

Therefore, a 95% confidence interval for the population mean pH of rainwater is [4.715, 5.135] .

The interpretation of the above confidence interval is that we are 95% confident that the population mean pH of rainwater is between 4.715 & 5.135.

(3) Now, 99% confidence interval for the population mean, \(\mu\) is ;

P(-3.106 < \(t_1_1\) < 3.106) = 0.99  {As the critical value of t at 11 degrees of

                                               freedom are -3.106 & 3.106 with P = 0.5%}  

P(-3.106 < \(\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }\) < 3.106) = 0.99

P( \(-3.106 \times {\frac{s}{\sqrt{n} } }\) < \({\bar X-\mu}\) < \(3.106 \times {\frac{s}{\sqrt{n} } }\) ) = 0.99

P( \(\bar X-3.106 \times {\frac{s}{\sqrt{n} } }\) < \(\mu\) < \(\bar X+3.106 \times {\frac{s}{\sqrt{n} } }\) ) = 0.99

99% confidence interval for \(\mu\) = [ \(\bar X-3.106 \times {\frac{s}{\sqrt{n} } }\) , \(\bar X+3.106 \times {\frac{s}{\sqrt{n} } }\) ]

                                     = [ \(4.925-3.106 \times {\frac{0.33}{\sqrt{12} } }\) , \(4.925+3.106 \times {\frac{0.33}{\sqrt{12} } }\) ]  

                                     = [4.629, 5.221]

Therefore, a 99% confidence interval for the population mean pH of rainwater is [4.629, 5.221] .

The interpretation of the above confidence interval is that we are 99% confident that the population mean pH of rainwater is between 4.629 & 5.221.

(4) As the level of confidence increases, the width of the interval increases as we can see above that the 99% confidence interval is wider as compared to the 95% confidence interval.

Answer:

  B.  False

Step-by-step explanation:

You want to compare the lateral surface areas of a cone and cylinder, where the slant height of the cone is twice the height of the cylinder. Your proposition is that the cone's lateral area is half that of the cylinder.

Effectively, the lateral area of a cone is the area of a triangle whose base is the circumference of the cone, and whose height is the cone's slant height. The formula for the lateral area of a cone of radius r and slant-height s is ...

  A = πrs

For the given dimensions (s=2h), the lateral area is ...

  A = πr(2h) = 2πrh

The lateral area of a cylinder is the area of a rectangle whose base is the circumference of the cylinder, and whose height is the cylinder's height. The formula for the lateral area of a cylinder of radius r and height h is ...

  A = 2πrh

The lateral areas of the given figures are both 2πrh, so one is not half the other.

The proposition is False.