Answer:
2.a) 3 ( x - 1 ) = 5x - 6 (Because the sides of a square are always equal)
b) 3 ( x - 1 ) = 5x - 6
=> 3x - 3 = 5x - 6
=> 3x - 5x = -6 + 3 (Law of transposition)
=> -2x = -3
=> -x = -3/2
=> -x = -1.5
=> x = 1.5 (By cancelling out the negative sign from both the sides)
c) 3(x-1) = 3 (1.5 - 1)
=> 3 (0.5)
=> 3 * 0.5 = 1.5
Both the angles are 1.5 because they are equal
If my answer helped, please mark me as the brainliest!!
Thank You!
1. A circular town with a diameter of 50 miles has apopulation of 25,504. A square town with a length ofhas a population of 22,340. Determine which of thetwo towns has a greater population density.
ANSWER
The population density of the square town is greater than the population density of the circular town.
EXPLANATION
The population density is the quotient between the number of people (population) and the area of each town.
Therefore, we have to find the areas first.
The circular town has a diameter of 50 miles, so its radius is 25 miles. Its area is:
\(A_{\text{circular town}}=\pi\cdot r^2=\pi\cdot25^2\approx1963.5mi^2\)The area of the square town is:
\(A_{\text{square town}}=s^2=40^2=1600mi^2\)The population density (PD) of each town is:
\(PD_{\text{circular}}=\frac{25,504}{1963.5}\approx12.99\text{ people/ square mile}\)\(PD_{\text{square}}=\frac{22,340}{1600}\approx13.96\text{ people/square mile}\)The population density of the square town is greater than the population density of the circular town.
Solve the inequality.
Answer: x>-5
Step-by-step explanation:
For this problem there are 2 ways to solve for x.
Solution 1
6((x/2)+4)≥9 [distribute 6 to x/2 and 4]
3x+24≥9 [subtract 24 on both sides]
3x≥-15 [divide both sides by 3]
x≥-5
-----------------------------------------------------------------------------------
Solution 2
6((x/2)+4)≥9 [divide both sides by 6]
(x/2)+4≥1.5 [subtract 4 on both sides]
x/2≥-2.5 [multiply 2 on both sides]
x≥-5
Please help worth 10 points is this true that line n is perpendicular to line p? I think the answer is C, is this correct or not?
Answer: A
because slope are
Use synthetic division to find the quotient. If there is a remainder do not include it in your answer. Recall:dividend\div divisor=quotient (6x^3-10x^2-7x-15) \div(x+1) Be sure to type your answer in descending powers of x with now spaces between your terms. Use the "^" key (shift+6) to indicate a power/exponent.Answer:
We have the next the next division
\((6x^3-10x^2-7x-15)\div(x+1)\)And we need to use synthetic division to find the quotient.
1. we must write the problem in a division-like format.
- we need to take the constant term of the divisor with the opposite sign and write it to the left. Then, we must write the coefficients of the dividend to the right.
2. we must write down the first coefficient without changes:
3. we need to multiply the entry in the left part of the table by the last entry in the result row and add the obtained result to the next coefficient of the dividend, and write down the sum.
4. We must continue the same process
5. We must continue the same process
Now, We have completed the table and have obtained the following resulting coefficients: 6. -16, 9 and -24
To identify the quotient we need all coefficients we obtained except the last coefficients which represents the remainder.
So, the quotient would be
\(-6x^2-16x+9\)ANSWER:
-6x^2-16x+9
7. N.CN.7 Determine the zeroes for the equation below. Select all that apply.
x² - 6x +13=0
A. 1
B. 5
C. 13
D. -3 + 2i
E. 3+2i
F. 3+4i
G. 6 + 4i
H. 3-21
I .6-41
Answer:
D. -3 + 2i and E. 3+2i are the zeroes for the equation.
Step-by-step explanation:
Find the value of X.
Answer:
x = 36
Step-by-step explanation:
Given a tangent segment of length 24, and a secant segment from the same point with an external length of 12 and a total length of (12+x), you want to find the value of x.
RelationThe product of lengths from the common point to the two intersections with the circle are the same for both segments. In the case of the tangent, the two intersections with the circle are the same point, so the square of the length is used.
24² = 12(12 +x)
2·24 = 12 +x . . . . . . . divide by 12
36 = x . . . . . . . . . subtract 12
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What’s the length of kL?
Applying the intersecting secants theorem, the length of segment KL is approximately, 45.8.
What is the Intersecting Secants Theorem?According to the intersecting secants theorem, if two lines from a point outside a circle intersect the circle, then the product of the length of one line segment and its portion outside the circle is equal to the product of the length of the other line segment and its portion outside the circle.
Using the theorem, we have:
MN * MO = ML * MK
Substitute:
21 * 48 = 22 * KL
1,008 = 22KL
1,008/22 = KL
KL = 45.8 (nearest tenth)
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Which expression is equivalent to 7u+4u?
Answer:
11u
Step-by-step explanation:
Add 7u and 4u
Hope this helps! :)
Which statement is not true about the data shown
by the box-and-whisker plot below?
0 10 20 30 40 50 60 70 80 90 100
Select one:
a. The median of the upper half of the data is
70.
b. The range is 60.
C. Three fourths of the data is less than 58.
d. Half the data lies between 43 and 70.
e. None of the above
Answer:
A
Step-by-step explanation:
Because it's 50 writing it down n scratching it out u will find that 50 is your median not 70
Answer:
for me, the answer was "Three-fourths of the data is less than 58." or C.
Step-by-step explanation:
coz i had the same question and that was the answer for me, but not sure for others.
Help! Find the measure of the arc or angle indicated.
Answer:
m<QDC = 77
Step-by-step explanation:
First we need to generate an equation in order to find the value of x.
Thus:
m<QDC = ½(Arc QBC) => Inscribed Angles Theorem)
5x + 17 = ½(4x - 6 + 9x + 4)
5x + 17 = ½(13x - 2)
Multiply both sides by 2
2(5x + 17) = 13x - 2
10x + 34 = 13x - 2
Collect like terms
10x - 13x = -34 - 2
-3x = -36
Divide both sides by -3
-3x/-3 = -36/-3
x = 12
Find m<QDC:
m<QDC = 5x + 17
Plug in the value of x
m<QDC = 5(12) + 17 = 70 + 17
m<QDC = 77
Twelve percent of the population is left handed. Approximate the probability that there are at least 20 left-handers in a school of 200 students. State your assumptions.
Answer:
Step-by-step explanation:
We would assume a binomial distribution for the handedness of the population. Let x be a random variable representing the type of handedness in the population. The probability of success, p is that a randomly chosen person is left handed only. Then probability of failure is that a chosen person is not left handed only(right handed only or both).
p = 12/100 = 0.12
number of success, x = 20
n = 200
the probability that there are at least 20 left-handers is expressed as P(x ≥ 20)
From the binomial probability calculator,
P(x ≥ 20) = 0.84
Hello I need help with this , am studying but I just can’t get this
Given
Find
Length of AB
Explanation
\(\begin{gathered} \tan15\degree=\frac{AB}{BC} \\ \\ \tan15\degree=\frac{x}{6} \\ \\ x=6(\tan15\degree) \\ x=1.6077\approx1.61 \end{gathered}\)Final Answer
Therefore , the length of AB is 1.61 miles
What is true about the points on the graph of y=2x?
Answer:
Step-by-step explanation:
The number of points that satisfy y = 2^x is limited only by the origin and the last point on the graph. All other points between those two points will solve y = 2^x
The answer is the last one offered on the lower right.
A car travels along a straight road for 30 seconds starting at time t = 0. Its acceleration in ft/sec2 is given by the linear graph below for the time interval [0, 30]. At t = 0, the velocity of the car is 0 and its position is 10.
What is the velocity of the car when t = 6? Please show your work and include units in your answer.
The velocity experimented by the car is equal to - 1 feet per second.
What is the velocity of a car at a given time?
Herein we have the graph of the position of the car (y), in feet, versus time (t), in seconds. The graph shows a linear equation, that is, the position is described by a polynomial of the form:
y = m · t + b
Then, the functions for the velocity and acceleration are shown below:
Velocity
dy / dt = m
The slope represents the velocity of the car.
Acceleration
d²y / dt² = 0
Then, the velocity of the car is found by means of the secant line formula:
dy / dt = (0 ft - 10 ft) / (10 s - 0 s)
dy / dt = - 1 ft / s
The velocity of the car is - 1 feet per second.
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HELP ME SOLVE THUS PLEASE! 50 POINTS WILL BE REWARDED!!!!
Solve the equation for x.
2(x−1)/4=2(x+8)/13
Answer:
x=5
Step-by-step explanation:
2(x−1)/4=2(x+8)/13
Step 1: Cross-multiply:
2(x−1)*(13)=2(x+8)*(4)
26x−26=8x+64
Step 2: Subtract 8x from both sides.
26x−26−8x=8x+64−8x
18x−26=64
Step 3: Add 26 to both sides.
18x−26+26=64+26
18x=90
Step 4: Divide both sides by 18.
18x/18= 90/18
x=5
~Hope this helps~
\( \huge \boxed{\mathbb{QUESTION} \downarrow}\)
\( \tt\frac { 2 ( x - 1 ) } { 4 } = \frac { 2 ( x + 8 ) } { 13 } \\ \)
\( \large \boxed{\mathbb{ANSWER\: WITH\: EXPLANATION} \downarrow}\)
\( \tt\frac { 2 ( x - 1 ) } { 4 } = \frac { 2 ( x + 8 ) } { 13 } \\ \)
Cross multiply the equations on both sides.
\( \tt13\times 2\left(x-1\right)=4\times 2\left(x+8\right) \)
Multiply 13 and 2 to get 26.
\( \tt26\left(x-1\right)=4\times 2\left(x+8\right) \)
Use the distributive property to multiply 26 by x-1.
\( \tt26x-26=4\times 2\left(x+8\right) \)
Multiply 4 and 2 to get 8.
\( \tt \: 26x-26=8\left(x+8\right) \)
Use the distributive property to multiply 8 by x+8.
\( \tt \: 26x-26=8x+64 \)
Subtract 8x from both sides.
\( \tt \: 26x-26-8x=64 \)
Combine 26x and -8x to get 18x.
\( \tt \: 18x-26=64 \)
Add 26 to both sides.
\( \tt \: 18x=64+26 \)
Add 64 and 26 to get 90.
\( \tt \: 18x=90 \)
Divide both sides by 18.
\( \tt \: x=\frac{90}{18} \\ \)
Divide 90 by 18 to get 5.
\( \boxed{ \boxed{ \bf \: x=5 }}\)
Find the domain and real zeros of the given function
F(x)= 3x-5/x^2-x-12
Answer:
DOMAIN : x ∈ (-∞ , -3 )U (4 , ∞) or {x | x ∈ R where x ≠ -3 and 4}
REAL ZEROS : x = 5/3
Step-by-step explanation:
\(f(x) = \frac{3x -5}{x^{2} -x-12}\)
factorize the bottom part
\(x^{2} - x - 12\)
product = -12 , sum = -1 , factors = -4 and 3
\(x^{2} +3x-4x-12=0\)
x (x + 3) - 4(x + 3) = 0
(x - 4) ( x + 3) = 0
x - 4 = 0 and x + 3 = 0
x = 4 and x = -3
for the function f(x) the domain is all real numbers ( R ) except - 3 and 4
Domain = x ∈ (-∞ , -3 )U (4 , ∞)
TO FIND THE ZEROS LET f(x) be equal to zero
\(0 = \frac{3x - 5}{x^{2} - x - 12}\)
cross multiply
0 = 3x - 5
find x
3x = 5
\(x = \frac{5}{3}\)
An apple has 80 calories. This is 12 less than 1/4 the number of calories in a package of candy. How many calories are in the candy.
Pls helpp
Answer:
368 calories are in the candy.
Step-by-step explanation:
80 + 12 = 92.
92 x 4 = 368.
A fair die is rolled 12 times. Consider the following three possible outcomes:(i) 6 5 4 3 2 1 6 5 4 3 2(ii) 1 1 1 1 1 1 1 1 1 1 1(iii) 3 6 2 1 5 4 2 5 1 6 4 3Which of the following is true?A. The three outcomes are equally likely.B. It is absolutely impossible to get sequence (ii).C. (i) is more likely than (ii).D. (iii) is more likely than (i) or (ii).E. Both (C) and (D) are true.
Answer:
A. The three outcomes are equally likely
Step-by-step explanation:
Given
\((i)\ 6, 5, 4, 3, 2, 1, 6, 5, 4, 3, 2, 1\)
\((ii)\ 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1\)
\((iii)\ 3, 6, 2, 1, 5, 4, 2, 5, 1, 6, 4, 3\)
Required
Which of the options is true
The sample space of a fair die is:
\(S = \{1,2,3,4,5,6\}\)
And the probability of each (in a single roll) is:
\(P(x) = \frac{1}{6}\)
In 12 rolls, the probability would be:
\(P(x) = (\frac{1}{6})^{12}\)
What this means that the elements of the sample space have equal probability of showing up.
So, events (i), (ii) and (iii) are equally likely
Anthony surveys a group of students at his school about whether they play a
sport. This table shows the results broken down by gender.
Boys
Girls
Total
Play a sport
114
63
177
Do not play a
sport
61
67
128
Total
B. No, they are not independent, because P(girl) = 0.46 and
P(girl | plays a sport) = 0.36.
175
150
Are being a girl and playing a sport independent events? Why or why not?
D. No, they are not independent, because P(girl) = 0.46 and
P(girl | plays a sport) = 0.54.
325
A. Yes, they are independent, because P(girl)≈ 0.46 and P(girl | plays
a sport)≈ 0.36.
OC. Yes, they are independent, because P(girl) ≈ 0.46 and P(girl | plays
a sport) = 0.54.
The answer is D. No, they are not independent, because P(girl) = 0.46 and P(girl | plays a sport) = 0.54.
What is independent event ?
In probability theory, two events A and B are said to be independent if the occurrence of one event does not affect the probability of the occurrence of the other event. That is, the probability of A occurring does not change based on whether B occurs or not, and vice versa.
Mathematically, two events A and B are independent if and only if the probability of their joint occurrence is the product of their individual probabilities:
P(A and B) = P(A) x P(B)
If this equation holds true, then we can say that A and B are independent events. Otherwise, they are dependent events.
According to the question:
The answer is D. No, they are not independent, because P(girl) = 0.46 and P(girl | plays a sport) = 0.54.
Two events A and B are independent if the occurrence of one event does not affect the probability of the occurrence of the other event. In this case, we want to know if being a girl and playing a sport are independent events.
We are given that P(girl) = 0.46, which means that 46% of the students surveyed are girls. We are also given that P(girl | plays a sport) = 0.54, which means that 54% of the students who play a sport are girls.
If being a girl and playing a sport were independent events, then we would expect P(girl | plays a sport) to be equal to P(girl). However, we see that P(girl | plays a sport) = 0.54, which is different from P(girl) = 0.46.
This means that the probability of a student playing a sport is dependent on their gender. Therefore, being a girl and playing a sport are not independent events.
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What is the double of a hundred?
Answer:
200
Step-by-step explanation:
100 * 2 = 200
Answer:
200?
Step-by-step explanation:
Or is it something more complicated
Five cards are dealt from a standard deck. What is the probability that at least four of them are hearts?
Step-by-step explanation:
To calculate the probability of getting at least four hearts when dealing five cards from a standard deck, we can use the concept of combinations and probability.
There are a total of 52 cards in a standard deck, and 13 of them are hearts (assuming no jokers). So the probability of drawing a heart on the first card is 13/52, or 1/4.
Now, there are two possible scenarios that would result in at least four hearts:
Four hearts and one non-heart: This can happen in C(13,4) * C(39,1) ways, where C(n, k) is the number of combinations of n items taken k at a time. The first part C(13,4) represents choosing 4 hearts out of 13, and the second part C(39,1) represents choosing 1 non-heart out of the remaining 39 cards. The total number of ways to choose 5 cards from 52 is C(52,5).
Five hearts: This can happen in C(13,5) ways, where C(13,5) represents choosing all 5 hearts out of 13.
So, the total number of favorable outcomes is C(13,4) * C(39,1) + C(13,5), and the total number of possible outcomes is C(52,5). Therefore, the probability of getting at least four hearts is:
P(at least 4 hearts) = (C(13,4) * C(39,1) + C(13,5)) / C(52,5)
Plugging in the values and simplifying, we get:
P(at least 4 hearts) = (C(13,4) * C(39,1) + C(13,5)) / C(52,5)
= (715 * 39 + 1287) / 2,598,960
= 27,885 / 2,598,960
≈ 0.0107566
So, the probability of getting at least four hearts when dealing five cards from a standard deck is approximately 0.0107566 or about 1.08%.
Question 5 of 10
Factor the polynomial: x(3x + 5) - 4(3x + 5)
A. -4x(3x + 5)
B. (3x + 5)(x + 4)
C. 4x(3x + 5)
D. (3x + 5)(x-4)
HURRY PLEASE
\(\qquad\qquad\huge\underline{{\sf Answer}}♨\)
Let's solve ~
Take (3x + 5) common in there :
\(\qquad \tt \dashrightarrow \:x(3x + 5) - 4(3x + 5)\)
\(\qquad \tt \dashrightarrow (3x + 5) (x - 4)\)
So, choice D is correct
What is the value of x?
Enter your answer in the box. I need help ASAP/ Giving Branniest
x =
°
Answer:
x = 80
Step-by-step explanation:
The sum of the angles of a triangle is 180 degrees
70+30+x = 180
100+x = 180
Subtract 100 from each side
100+x-100 = 180-100
x = 80
What is the remainder in the synthetic division problem below?
4 6 - 1
A. 3
B. 7
C. 5
D. 9
Answer:
so,6-1 3+7x5 9
Multiple: 7 * 5 = 35
Divide: the result of step No. 1 / 9 = 35 / 9 = 3.88888889
Add: 3 + the result of step No. 2 = 3 + 3.88888889 = 6.88888889
What are the answers to these questions?
Step-by-step explanation:
the inside expression of an absolute value expression can be positive or negative, but the result is only the positive one.
therefore, for our example here the negative case would be
2.5x - 6.8 = -12.9
which gives us
2.5x = -6.1
x = -6.1/2.5 = -2.44
and the positive case would be
2.5x - 6.8 = 12.9
and that gives us
2.5x = 19.7
x = 19.7/2.5 = 7.88
The conversion rate for US Dollars to Costa Rican Colones is 1 USD = 518 Colones.
The conversion rate is also given for 1kg = 2.2025lbs
If bananas cost $0.69 per pound, how many colones are required to purchase 0.5kg?
The cost of 0.5 kg of bananas is 393.60 Colones as per the given conversion rates
Conversion rate of 1 USD to Costa Rican Colones = 518 Colones
The conversion rate of kg to pounds given in the question: 1 kg = 2.2025 lbs
Cost of one pound of bananas = $0.69
Bananas required to be purchased = 0.5kg
Converting 0.5kg bananas to pounds = 0.5*2.2025 = 1.10125 pounds
Cost of 1.10125 pound of bananas in dollars = 1.10125*0.69 = 0.7598
Cost of 1.1025 pounds of bananas in Colones = 0.7598*518 = 393.60 Colones
Hence, the cost is 393.60
Therefore, the cost of 0.5 kg bananas in Colones is 393.60 Colones
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Question 1 of 10
Simplify the following expression.
3x^4+2x³-5x² +4x²+6x-2x-3x^4 +7x^5-3x³
Combining like terms yields 7x⁵ - x³ - x² + 4x.
NP and QS are parallel lines.
N
Q
M
O
R
P
S
T
Which angles are supplementary angles?
The angles that are supplementary angles are: ∠SRT and ∠SRO
How to find the supplementary Angle?Angles that are defined as supplementary angles are simply those that will sum up to 180 degrees when we add them together. Thus, One of the angles is the supplement of the other.
Examples of angles supplementary angles formed when two parallel lines are said to be intersected by a transversal are:
Same-side interior angles
Same-side exterior angles
Linear pair angles formed on a straight line and are adjacent to each other.
From the attached image, we see that:
Angle SRT and angle SRO are angles that are adjacent to each other due to the fact that they share a common side named SR as well as a common vertex R. They are on the straight line OT.
Therefore, angle SRT and angle SRO are the two angles that are the supplementary angles since the lines NP and QS are parallel lines.
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Triangle TUV is dilated by a scale factor of 5 to form triangle T'U'V'. Side VT
measures 13. What is the measure of side V'T'?
Answer: 65
Step-by-step explanation: VT•5= v’T’
13•5= V’T’ 13•5=65
is the ordered pair a solution to the equation. y=-7; (-5,6)
Answer: No
To check if (-5,6) is a solution to the equation y=-7, we need to substitute -5 for x and 6 for y in the equation.
If the equation is true, then the ordered pair is a solution to the equation.
If we put (-5,6) into y=-7, we get 6=-7, which is not true.
So, (-5,6) is not a solution to the equation y=-7.