Pls help I am stuck and it is due soon number 6

Answer:

B. (-2,-1)

Step-by-step explanation:

A continuous function is one that do not discontinue, and a little change in its input has no effect on its result. This is one major difference between continuous and discontinuous functions. Both functions has major applications in calculus.

The turning point of a function can be obtained by determining where  it is increasing or decreasing.

In the given question, though there is no detailed information about the continuous function, but the probable turning point is (-2, -1).

Answer:

(–2, –1)

Step-by-step explanation:

Answer:

9

Step-by-step explanation:

It's really not that hard

For a student who participate in a wide variety of extra-curricular memorial high school, the probability of the union of being either a freshman or senior is equals to the 0.50.

We have students who attend memorial high school have a wide variety of extra-curricular activities.

Probability of student who likely to join the dance team = 38% = 0.38

Probability of student who likely to participate in the school play = 18% = 0.18

Probability of students who likely to join the yearbook club = 42% = 0.42

Probability of students who likely to join the marching band = 64% = 0.64

Also, students have equal probabilities of being freshmen, sophomores, juniors, or seniors.

So, the probability ( a student is senior )

= 1/4 = 0.25

The probability ( a student is freshman )

= 1/4 = 0.25

We have to determine the union of being either a freshman or senior. Now, the probability of the union of disjoint or independent events is the sum of their individual probabilities.

So, probability ( a student is freshman or senior) = P( freshman ∪ senior )

= P( freshman) + P( senior)

= 0.25 + 0.25 = 0.50

Hence, required probability is 0.50.

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Answer:

15 apples

Step-by-step explanation:

Add 10 and 5,

10 + 5 = 15

Answer:

x = -4

Step-by-step explanation:

The area of a triangle is half the product of its base and height.

\(\boxed{\begin{minipage}{5 cm}\underline{Area of a triangle}\\\\$A=\dfrac{1}{2}bh$\\\\where:\\ \phantom{ww}$\bullet$ $A$ is the area. \\ \phantom{ww}$\bullet$ $b$ is the base. \\ \phantom{ww}$\bullet$ $h$ is the height.\\\end{minipage}}\)

Given values:

Substitute the given values into the formula:

\(\implies 24=\dfrac{1}{2}(2-x)(4-x)\)

Multiply both sides of the equation by 2:

\(\implies 48=(2-x)(4-x)\)

Expand the parentheses:

\(\implies 48=8-2x-4x+x^2\)

\(\implies 48=8-6x+x^2\)

Subtract 48 from both sides;

\(\implies x^2-6x-40=0\)

Rewrite -6x as -10x + 4x:

\(\implies x^2-10x+4x-40=0\)

Factor the first two terms and the last two terms separately:

\(\implies x(x-10)+4(x-10)=0\)

Factor out the common term (x - 10):

\(\implies (x+4)(x-10)=0\)

Apply the zero-product property:

\((x+4)=0 \implies x=-4\)

\((x-10)=0 \implies x=10\)

If x ≥ 4 then the height of the triangle would be h ≤ 0.

If x = 10, the height of the triangle would be -6.

As length cannot be negative, the only value of x is x = -4.

The population at the start of the month is approximately 4815. The correct answer is 4815

Given, a farmer harvests 200 catfish per month. Also, Pn is the catfish population after n months and is given recursively by P0 = 5000 and Pn = 1.08Pn – 1 – 200.

The number of catfish in the pond at the end of the month, Pn, equals the population at the start of the month, plus the increase in population, minus the 200 harvested catfish.

Then, the population at the start of the month + increase in population – harvested catfish.

Pn= Population at the start of the month (Po) + Increase in population – harvested catfish= Po + 1.08Po – 1 – 200= 1.08Po – 201

We know that P0 = 5000P0= Population at the start of the month= 1.08Po – 201, so5000 = 1.08Po – 2015201+5000 = 1.08PoP0 = 5201/1.08P0 ≈ 4814.81

Therefore, the population at the start of the month is approximately 4815.

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Answer:

  C.  142°

Step-by-step explanation:

You want the angle between vectors u=3i+√3j and v=-2i-5j.

There are a number of ways the angle between the vectors can be found. For example, the dot-product relation can give you the cosine of the angle:

  u•v = |u|·|v|·cos(θ) . . . . . . where θ is the angle of interest

You can find the angles of the vectors individually, and subtract those:

  u = |u|∠α

  v = |v|∠β

  θ = α - β

When the vectors are expressed as complex numbers, the angle between them is the angle of their quotient:

  \(\dfrac{\vec{u}}{\vec{v}}=\dfrac{|\vec{u}|\angle\alpha}{|\vec{v}|\angle\beta}=\dfrac{|\vec{u}|}{|\vec{v}|}\angle(\alpha-\beta)=\dfrac{|\vec{u}|}{|\vec{v}|}\angle\theta\)

This method is used in the calculation shown in the first attachment. The angle between u and v is about 142°.

A graphing program can draw the vectors and measure the angle between them. This is shown in the second attachment.

__

Additional comment

The approach using the quotient of the vectors written as complex numbers is simply computed using a calculator with appropriate complex number functions. There doesn't seem to be any 3D equivalent.

The dot-product relation will work with 3D vectors as well as 2D vectors.

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Answer:

1,590.7 cm^3

Step-by-step explanation:

First, separate this shape into two smaller shapes you can easily find the volume of. In this example, you can separate this figure into a cone and a half-sphere.

Find the volume of the cone using the formula: V=πr^2(h/3). The radius is 7 because 14cm is the diameter, and 17cm is the height. When you solve, you get 872.32 for the volume of this cone.

Then, find the volume of the half-sphere. The volume of a sphere can be found with the formula: V=4/3πr^3. The radius is, again, 7. Now divide this value in half because you only want to find the volume of a half-sphere. You should get 718.38 cm.

Now add the two volumes together to get 1,590.7 cubed centimeters.

Step-by-step explanation:

volume of hemisphere

given

r=d/2=14/2=7cm

V=2/3πr^3

V=2/3×π×7^3

V=2/3×π×343cm^3

V=2/3×1077.56

V=718.37cm^3

volume of cone

given

r=7cm

h=17cm

V=πr^2×h/3

V=π×7^2×17cm/3

V=π×49cm^2×17cm/3

V=π×833cm^3/3

V=2616.94/3

V=872.31cm^3

Total volume=718.37cm^3+872.31cm^3

=1590.68cm^3

Answer:

7 1/4 pounds

\(4\frac{7}{8} + 2\frac{3}{8}\)

\(6\frac{7 + 3}{8}\)

= \(6\frac{10}{8}\)

convert the improper fraction to a mixed fraction

10/8 = 1 2/8 = 1 1/4

Add the 1 1/4 to 6 = 7 1/4

Step-by-step explanation:

Kelly buys 4 7/8 pounds of apples and 2 3/8 pounds of oranges. How many pounds of fruit does she buy altogether? Show Your work

The area of a shape is the amount of space on it:

The shaded area is 314 square centimeters

Start by calculating the area of sectors OFG and OAD using:

\(A = \frac{\theta}{360} * \pi r^2\)

So, we have:

\(OFG = \frac{40}{360} * \pi * 18^2\)

\(OFG = 36\pi\)

Also, we have:

\(OAD = \frac{40}{360} * \pi * 18^2\)

\(OAD = 36\pi\)

Next, calculate the area of the sectors BOE and COH

Note that the radius of these sectors is 6 cm.

So, we have:

\(COH =BOE = \frac{140}{360} * \pi * 6^2\)

\(COH = BOE = 14\pi\)

The shaded area is then calculated as:

\(Shaded = OFG + OAD + COH + BOE\)

This gives

\(Shaded =36\pi + 36\pi + 14\pi + 14\pi\)

\(Shaded =100\pi\)

The equation becomes

\(Shaded =100 * 3.14\)

\(Shaded = 314\)

Hence, the shaded area is 314 square centimeters

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The required percentage yield for the reaction when theoretical yield and actual yield are given is calculated to be 85.5 %.  

The maximum mass that can be generated when a particular reaction occurs is referred to as theoretical yield.

Theoretical yield is given as mt = 9.23 g

The actual amount of product recovered is given as ma = 7.89 g

We must comprehend that in order to calculate the reaction's percent yield, we must divide the total amount of product recovered by the utmost amount that can be recovered. If we multiply by 100%, we can represent this fraction as a percentage.

Percentage yield = ma/mt × 100 = 7.89/9.23 × 100 = 85.5 %

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Answer: ≈578 cm²

Step-by-step explanation:

\(V_{cyl}=1056\ cm^3\ \ \ \ H=21\ cm\\V_{cyl}=\pi R^2H\\1056=\pi *R^2*21\\1056=21\pi *R^2\\\)

Divide both parts of the equation by 21π:

16=R²

4²=R²

4=R

\(S{tot\ sur}=\pi R^2+2\pi RH\\S{tot\ sur}=\pi R*(R+2H)\\S{tot\ sur}=\pi *4*(4+2*21)\\S{tot\ sur}=4\pi *(4+42)\\S{tot\ sur}=4\pi *46\\S{tot\ sur}=184\pi \\S{tot\ sur}\approx578\ cm^2\)

Answer:

See below

Step-by-step explanation:

\(1\cdot24=2\cdot12=3\cdot8=4\cdot6=24\)

Answer:

1. 24

2. 12

3. 8

4. 6

Step-by-step explanation:

2 x 12 = 24, 3 x 8 = 24, 4 x 6 = 24

When you create the number line, put 0 in the middle. Basically you put all the numbers you got from least to greatest on the number.

Since -3/2 is less than 0, it will go to the left of 0.

Since 3/2 and 5/2 are greater than 0, it will go to the right of 0.

Remember to use sub points of 1.

Best of Luck!

Answer:

Step 1: Steps for construction

Take AB at 5.5 cm                                    

Step 2: construct as 45 degree  

Step 3: A draw angle ABY=45 degree    

Step 4: cut off from AY, a segment AD=5 cm

Step 5: With B as center and radius as 3.5cm draw an arc.

Step 6: With D as the center and mark radius as 5 cm and draw an arc cut the 1st arc at C

Step 7: join B to C and C to D

Result: Then ABCD is a required quadrilateral  

Hope this helps you hit the crown :D

tell me if correct ok?

9514 1404 393

Answer:

  see the attachment

Step-by-step explanation:

1. Lay out points A and B so they are 5.5 cm apart.

2. Set the compass to 5 cm and draw arcs that intersect above and below segment AB. Label the intersection points Y and Z.

3. Draw segment YZ as a perpendicular bisector of AB.

4. Label the intersection of YZ and AB point E.

5. Using E as the center and AE as the radius, draw an arc that intersects segment YZ at F.

6. Draw segment AD through F. D will lie on the circle of radius 5 cm centered at A. This segment makes 45° angle DAB.

7. Draw an arc of radius 4 cm centered at D through the vicinity of point C.

8. Draw an arc of radius 3.5 cm centered at B through the vicinity of C. The intersection point with the arc of step 7 is point C.

9. Draw quadrilateral ABCD meeting the given requirements.

_____

About the attachment

My geometry tool draws circles of a given radius more easily than arcs of a given radius, so you see circles where only arcs are needed.

Answer: 120d + 1500 = 110d + 2500

Solution: The first 1500 + 120d

The second 2500 + 110d

So. 120d + 1500 = 110d +2500

(a) p(2), that is, P(X = 2)The cdf is given by: F(x) = 0 x < 00.06 0 ≤ x < 10.16 1 ≤ x < 20.33 2 ≤ x < 30.69 3 ≤ x < 40.92 4 ≤ x < 50.99 5 ≤ x < 61 6 ≤ x

The probability mass function p(x) can be derived from the cdf by taking differences:

p(x) = F(x) − F(x-1)Thus the probability mass function p(x) is as follows: p(x) = 0.06  x = 10.1  x = 20.17 x = 30.36  x = 40.23 x = 50.07 x = 60.01 x = 6The probability P(X = 2) can be found as follows: P(X = 2) = p(2) = 0.17(b) P(X > 3)The probability can be found as follows: P(X > 3) = P(4 ≤ X) = 1 - P(X < 4) = 1 - F(3) = 1 - 0.33 = 0.67(c) P(2 ≤ X ≤ 5)The probability can be found as follows: P(2 ≤ X ≤ 5) = F(5) - F(1) = 0.99 - 0.1 = 0.89(d) P(2 < X < 5)

The probability can be found as follows: P(2 < X < 5) = F(4) - F(2) = 0.92 - 0.17 = 0.75.

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The coefficient of linear expansion of lead is given as 29 × 10^(-6) K^(-1). We need to find the change in temperature that would cause a 10-meter long lead bar to change in length by 3.0 mm.

The linear expansion of a material can be expressed using the formula:

ΔL = α * L0 * ΔT

Where ΔL is the change in length, α is the coefficient of linear expansion, L0 is the original length, and ΔT is the change in temperature.

We can rearrange the formula to solve for ΔT:

ΔT = ΔL / (α * L0)

Substituting the given values, we have:

ΔT = (3.0 mm) / (29 × 10^(-6) K^(-1) * 10 m)

Simplifying the expression, we find:

ΔT ≈ 1034.48 K

Therefore, a change in temperature of approximately 1034.48 K would cause a 10-meter long lead bar to change in length by 3.0 mm.

In summary, a change in temperature of approximately 1034.48 K would result in a 10-meter long lead bar changing in length by 3.0 mm.

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Answer:

your answer should be ty

Step-by-step explanation:

Answer:

perimeter of triangle IJH= 17.5

Step-by-step explanation:

line IJ is a midsegment, so you can divide the segments FH and GH by 2.

that means segment IH= 4.5 and segment GH=6. segment IJ is given as 7.

add 4.5 + 6 + 7, which equals 17.5

Answer:

One

Step-by-step explanation:

It is given that,

y = 3x-5 ....(1)

y = -x+4 .....(2)

We can solve the above equations using substitution method. Put the value of y from equation (1) to equation (2) such that,

\(3x-5 = -x+4\\\\3x+x = 5+4\\\\4x = 9\\\\x=\dfrac{9}{4}\)

Put the value of x in equation (1) we get :

\(y = 3x-5\\\\y = 3\times \dfrac{9}{4}-5\\\\y=\dfrac{7}{4}\)

It means that the value of x is \(\dfrac{9}{4}\) and the value of y is \(\dfrac{7}{4}\). Hence, the given equations has only one solution.

Answer:

1

Step-by-step explanation:

The function has a minimum of -4.35125

From the question, the equation of tis given as

f(x)=2x^2-9.1x+6

Rewrite the function as follows

f(x) = 2x² -9.1x + 6

Next, we differentiate the function

This is represented as

f'(x) = 2 * 2x - 1 * 9.1 + 0 * 6

Evaluate

f'(x) = 4x - 9.1

Set the differentiated function to 0

This is represented as

f'(x) = 0

So, we have

4x - 9.1 = 0

This gives

4x = 9.1

Divide by 4

x = 2.275

Substitute x = 2.275  in f(x) = 2x² -9.1x + 6

f(2.275) = 2(2.275)² - 9.1(2.275) + 6

Evaluate

f(2.275) = -4.35125

Hence, the minimum is -4.35125

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(I - A) has an inverse, which is the matrix (I + A + A^2 + ... + A^(K-1)). we get: (I - A)(I + A + A^2 + ... + A^(K-1)) = I + A^1 + A^2 + ... + A^(K-1) - (A^1 + A^2 + ... + A^(K-1) + A^K)

Given a square matrix a such that ak = 0 for some k. We need to prove that i - a is invertible and also find its inverse. Proof: We have a matrix a such that ak = 0 for some k. Since a is a square matrix, it follows that det(a) = 0.  Let us consider the determinant of the matrix (i - a). det (i - a) = | (i - a ) | = |i| |(i - a)-1| = | (i - a)-1|As i is the identity matrix, det(i) = 1. We have to prove that det (i - a) ≠ 0 so that (i - a) is invertible. Let us assume det (i - a) = 0. Since det (i - a) = | (i - a) |, we can say that |(i - a) | = 0. The determinant of a matrix is 0 when its rows or columns are linearly dependent. Since i - a is a square matrix, it follows that its rows or columns are linearly dependent. This implies that there exists a non-zero vector x such that (i - a) x = 0 Multiplying with a on both sides, we get x - ax = 0 => ax = x We can keep on multiplying x by a until we get a non-zero vector that satisfies ak = 0 which contradicts the given assumption. Hence, our assumption that det(i - a) = 0 is wrong. So, det(i - a) ≠ 0. Hence, (i - a) is invertible. So, (i - a)-1 exists. Now, we need to find the inverse of (i - a). Let (i - a)-1 = b. Then, (i - a) (i - a)-1 = i = (i - a) b= ib - ab= b - a b Multiplying the equation (i - a) b = i with (i - a) on both sides, we get(i - a)2 b = i - a => b = (i - a)-1 = i + a + a2 + ... + ak-1 This is the inverse of (i - a).Hence, (i - a) is invertible and its inverse is given by (i - a)-1 = i + a + a2 + ... + ak-1.

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Using Horner's algorithm, it is found that p(4) = 946.

Horner's algorithm is a method used to evaluate a polynomial at a given value of x. It simplifies the process of calculating the value of the polynomial by reducing the number of calculations needed. To use Horner's algorithm to find p(4), where p(z) = 3z^5 – 7z^4 – 5z^3+z^2- 8z +2, follow these steps:

p(4) = 3(4)^5 – 7(4)^4 – 5(4)^3+(4)^2- 8(4) +2
p(4) = 3(4)^5 – 7(4)^4 – 5(4)^3+(4)^2- 8(4) +2

p(4) = 3(1024) – 7(256)– 5(64) + 16 - 32 +2

p(z) = 3072– 1792 – 320 + 16 - 30

p(z) = 1280 – 320 - 14

p(z) = 960 - 14

p(z) = 946

Therefore, p(4) = 946.

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According to the given information, the value(s) of x for which\($f(G(x)) = g(f(x))$\) is x = 1 or x = -2/3.

The slope of a line is a measure of its steepness. Mathematically, the slope is calculated as "rise over run" (change in y divided by change in x).

\(To find the inverse of $G(x)$:Replace $G(x)$ with $y$: $y = x - x^2 + 1$Solve for $x$: $x^2 - x + (1 - y) = 0$Apply the quadratic formula: $x = \frac{1 \pm \sqrt{1 - 4(1)(1-y)}}{2} = \frac{1 \pm \sqrt{-3 + 4y}}{2}$The inverse of $G(x)$ is therefore: $G^{-1}(x) = \frac{1 \pm \sqrt{-3 + 4x}}{2}$To find the value of $x$ for which $f(G(x)) = g(f(x))$:Start with $f(G(x))$: $f(G(x)) = f(x^2 - x + 2)$\)

\(Replace $f(x)$ with $3 - 2x$: $f(G(x)) = 3 - 2(x^2 - x + 2) = -2x^2 + 2x - 3$Replace $G(x)$ with $y$: $y = x^2 - x + 2$Replace $g(y)$ with $y - x^2 + 1$: $g(y) = y - x^2 + 1$Set $f(G(x))$ equal to $g(f(x))$ and solve for $x$:$-2x^2 + 2x - 3 = (3 - 2x) - x^2 + 1$Simplify and solve for $x$: $x = 1$ or $x = -\frac{2}{3}$\)

Therefore, according to the given information, the value(s) of x for which \($f(G(x)) = g(f(x))$\)is x = 1 or x = -2/3.

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