PLEASE HELP QUICK !!!

Which of the following is an irrational number? (v10)2 v8 0.63 v196

Answer:

Step-by-step explanation:

Let's solve for w.

s=a+lw

Step 1: Flip the equation.

lw+a=s

Step 2: Add -a to both sides.

lw+a+−a=s+−a

lw=−a+s

Step 3: Divide both sides by l

\(\frac{lw}{l} =\frac{-a+s}{l}\)

Using the relation between velocity, distance and time, it is found that she traveled 15 seconds at 10 m/s and 7 seconds at 50 m/s.

Velocity is distance divided by time, that is:

v = d/t.

For the first part, we have that she cycled a distance of d m in t seconds, at a velocity of 10 m/s, hence:

10 = d/t

d = 10t.

For the second part, we have that she cycled a distance of 500 - d meters, in 22 - t seconds, at a velocity of 50 m/s, hence:

50 = (500 - d)/(22 - t).

Since d = 10t, and applying cross multiplication:

500 - 10t = 50(22 - t)

500 - 10t = 1100 - 50t

40t = 600

t = 600/40

t = 15.

22 - t = 22 - 15 = 7, hence:

She traveled 15 seconds at 10 m/s and 7 seconds at 50 m/s.

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Answer:

C A person with an annual income of at least \$50{,}000$50,000dollar sign, 50, comma, 000 is more likely to be 454545 years old or above

A person in the 44 and under age group is more likely to have an annual income of at least $50,000​ is a correct statement.

We have given that,

A sociologist polled a random sample of people and asked them their age and annual income.

annual income is the amount of money you receive during the year into your bank account, before any deductions.

The two-way frequency table below shows the results.

Annual income vs. age group Less than $50,000 At least $50,000

Total Ages 44 and under 148 68 216 Ages 45 and above 38 94 132

Total 186 162 348

A person with an annual income of at least

\(=\$50000\\=$50,000dollar\)

Therefore statement b is true.

A person in the 44 and under age group is more likely to have an annual income of at least $50,000​.

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Answer:

72 child

369 adult

48 senior

Step-by-step explanation:

15 / (1/3)  is equal to  15 x 3/1  = 15 x 3 = 45

Answer:

solution given:

product of (4a-5b) and (3a+4b-2c) is:

the value of the product when A=2 b-3 and C= -2 :

(4a-5b)*(3a+4b-2c)

The simplified expression for this problem is given as follows:

(3²)^(1/3) = 3^(2/3) = \(\sqrt[3]{9}\)

The power of a power rule is used when a single base is elevated to multiple exponents.

Then the simplified expression is obtained keeping the base, while the exponents are multiplied.

The exponents for this problem are given as follows:

2 and 1/3.

Hence the product is of:

2 x 1/3 = 2/3.

Converting the fractional exponent to a rational expression, we have that:

3^(2/3) = \(\sqrt[3]{3^2} = \sqrt[3]{9}\)

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The median of the list is 3

We must arrange the numbers in this list from smallest to largest in order to determine the median:

-12, -3, 1, 1, 2, 4, 10, 16, 16, 19

The middle value of a dataset is represented by the median, a statistical measure. Half of the values in the dataset are greater than or equal to the median, and the other half are less than or equal to the median. This value is what divides the dataset into two halves.

A dataset's values must first be arranged in either ascending or descending order before the median can be determined. The median is simply the middle value when the dataset has an odd number of values. The median is the average of the two middle values when the dataset has an even number of values.

Think about the dataset 3, 5, 7, 9, and 11 as an example. This dataset's median value is 7, as

The median is the average of the two middle numbers in this list of ten numbers. The two middle numbers in this instance are 2 and 4. The median is thus:

median is equal to (3 / (2 + 4)

As a result, three is the list's median.

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a. Proportions in both the left-hand and right-hand tails tend to be relatively small.

The correct answer is: a. Proportions in both the left-hand and right-hand tails tend to be relatively small. This is because a normal distribution is symmetric and bell-shaped, with the majority of the data concentrated around the mean. As a result, the tails of the distribution have fewer data points and smaller proportions compared to the center. This is because a normal distribution is symmetric and bell-shaped, with the majority of the data concentrated around the mean.

So, a. Proportions in both the left-hand and right-hand tails tend to be relatively small.

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Answer:

47 inches and 66 inches

Step-by-step explanation:

took test

Answer:

A part of a line with a start point but no end point (it goes to infinity) Try moving points "A" and "B": line

Step-by-step explanation:

its just straight forward

Answer:

7.21 × 10⁻⁷

Step-by-step explanation:

(6.94 × 10⁻⁷) + (2.7 × 10⁻⁸) = 7.21 × 10⁻⁷

Answer: 883 Million is greater

Step-by-step explanation:

883M is extremely bigger than 334K.

It is over 2K times bigger

i hope this helps

Answer:

x= 5pie/6 +n*pie  nE Z

Step-by-step explanation:

The asymptote is vertical in this case and for that we need that the value of x stays the same for whichever value of y. and so on the graph the value of  x= 5pie/6 fits in what we need.

The congruent triangles in this problem are given as follows:

Triangles A and B.

Two figures are classified as congruent if their side lengths are the same.

If we rotate triangle B 180º over it's base, we have that it will have a similar format to triangle A, and also with the same side lengths.

Hence the congruent triangles in this problem are given as follows:

Triangles A and B.

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a) Mean: Approximately 590.17

b) Median: 585

c) Mode: 614

To find the mean, median, and mode of the given frequency distribution, we need to calculate the corresponding statistical measures using the provided values and frequencies.

a) Mean:

The mean is calculated by summing up the products of each value and its corresponding frequency, and then dividing by the total number of observations.

In this case, we have:

(614 × 13) + (535 × 8) + (610 × 9) + (585 × 12) + (584 × 5) + (601 × 7)

= 7,982 + 4,280 + 5,490 + 7,020 + 2,920 + 4,207

= 31,899

Now, we divide this sum by the total number of observations:

31,899 / (13 + 8 + 9 + 12 + 5 + 7)

= 31,899 / 54

≈ 590.17

Therefore, the mean of the frequency distribution is approximately 590.17.

b) Median:

The median is the middle value of a data set when it is ordered in ascending or descending order.

To find the median, we need to arrange the values in ascending order along with their corresponding frequencies:

535, 584, 585, 601, 610, 614

Now, we need to find the cumulative frequency.

Starting from the lowest value, we add up the frequencies until we reach or exceed half the total number of observations:

535 (8)

535 + 584 (8 + 5 = 13)

535 + 584 + 585 (13 + 12 = 25)

535 + 584 + 585 + 601 (25 + 7 = 32)

Since the cumulative frequency of 32 exceeds half the total number of observations (54/2 = 27), the median will lie in the group containing 585.

Therefore, the median of this frequency distribution is 585.

c) Mode:

The mode is the value(s) that appear(s) most frequently in a data set. In this case, the highest frequency is 13, which corresponds to the value 614.

Thus, the mode of this frequency distribution is 614.

To summarize:

a) Mean: Approximately 590.17

b) Median: 585

c) Mode: 614

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Answer:

D.

Step-by-step explanation:

Took the test

Answer:

i believe the answer is 40km.

Answer:

We are given that 1 cm on the map represents 5 km on earth's surface.

Then, if the cities are 8 cm apart on the map, they will be 8*5 = 40 km apart on Earth.

Step-by-step explanation:

R is right-total if and only if R−1 is left-total since there exists s ∈ S such that (s,t) ∈ R−1, since (s,t) ∈ R−1 if and only if (t,s) ∈ R and there exists t ∈ T such that (s,t) ∈ R, since (t,s) ∈ R if and only if (s,t) ∈ R−1 where R is a relation from S to T

Recall that a relation R from set S to set T is right-total if every element of S is related to some element of T, that is, for every s ∈ S, there exists t ∈ T such that (s,t) ∈ R.

On the other hand, a relation R from S to T is left-total if every element of T is related to some element of S, that is, for every t ∈ T, there exists s ∈ S such that (s,t) ∈ R.

First, suppose that R is right-total. Then, for any s ∈ S, there exists t ∈ T such that (s,t) ∈ R.

This means that for any t ∈ T, there exists s ∈ S such that (s,t) ∈ R−1, since (s,t) ∈ R−1 if and only if (t,s) ∈ R. Hence, R−1 is left-total.

Conversely, suppose that R−1 is left-total. Then, for any t ∈ T, there exists s ∈ S such that (s,t) ∈ R−1. This means that (t,s) ∈ R for some s ∈ S.

Hence, for any s ∈ S, there exists t ∈ T such that (s,t) ∈ R, since (t,s) ∈ R if and only if (s,t) ∈ R−1. Therefore, R is right-total.

In summary, we have shown that R is right-total if and only if R−1 is left-total.

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Answer:

39.98

Explanation:

39.98015​

0 < 5, so 2nd decimal stays at 8

Answer:39.98

Step-by-step explanation:

Hey! I’m not exactly sure what you’re asking, but if the question is how to write that number in only two decimal places, it would be 39.98. We would round it up or down in the hundredths place because that is the second decimal place. Since the number behind the 8 is 0, we can’t round up or down so we would just leave it how it is and cut off the rest.

Hope this helped! :D

Sorry it I didn’t answer what you were asking! You can comment and I will answer any further questions!

Answer:

the equation is in form

y=mx+b where

m=slope

and

b=y-int (the y value for the vertex)

first we look to see what the y value is for the point where x=0 and we can see that it is 5 so b=5

then we look at the slope, slope it the amont of units up then to the side are needed to reach the next point, in this case the line goes up 1 then to the right 1 so the slope is 1/1 (1) so the full equation is

y=x+5

Step-by-step explanation:

The integrations of ∫ sin (2x) dx is ∫sin(2x) dx = -(1/2)cos(2x) + C

The integration of sin(2x) with respect to x can be found using integration by substitution.

Let u = 2x, then du/dx = 2, and dx = du/2.

Substituting these values into the original equation, we get:

∫ sin(2x) dx = ∫ sin(u) (1/2) du

Now we can integrate sin(u) using the formula:

∫ sin(u) du = -cos(u) + C

where C is the constant of integration.

Substituting back in for u, we get:

∫ sin(2x) dx = (-1/2)cos(2x) + C

To find the integral of the given function, ∫sin(2x) dx, you can use the technique of substitution. Let u = 2x, then du/dx = 2, or du = 2 dx. Now, rewrite the integral:

∫sin(2x) dx = ∫sin(u) (1/2) du

Now integrate with respect to u:

(1/2) ∫sin(u) du = -(1/2)cos(u) + C

Now, substitute back the original variable x:

-(1/2)cos(2x) + C

So the final answer is:

∫sin(2x) dx = -(1/2)cos(2x) + C

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(a) The expression for Y(s) with non-zero initial conditions is given by:

Y(s) = 32/((s + 12)(s+32)) + y_0(s + 12)(s+32) Where, y_0 = y(t = 0)

(b) With zero initial conditions, the transfer function T(s) = Y(s)/U(s) is given by: T(s) = 32/((s + 12)(s+32))

(c) The impulse response of the system is given by the inverse Laplace transform of the transfer function: h(t) = 32(e^(-12t)-e^(-32t))

(d) The Routh table can be used to determine the BIBO stability of the system. If all of the entries in the Routh table are positive, then the system is BIBO stable. The impulse response of the system is related to its BIBO stability in that a BIBO stable system must have an impulse response that decays to zero as time increases. If the impulse response does not decay to zero, then the system is not BIBO stable.

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The probability that the red die shows a three and the blue die shows a number greater than three is 1/12

From the question, we have the following parameters that can be used in our computation:

Red die

Blue die

The sample space of a die is

{1, 2, 3, 4, 5, 6}

using the above as a guide, we have the following:

P(3) = 1/6

P(Greater than 3) = 1/2

So, we have

P = 1/2 * 1/6

Evaluate

P = 1/12

Hence, the probability of a three and and a number greater than three is 1/12

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1. Set up: To set up a void function, define it with the keyword "void" in the function signature, such as void functionName(). For a value-returning function, specify the return type in the function signature, such as dataType functionName().

2. Implementation and Documentation: In the implementation of the void function, write the necessary code to perform the desired actions. For a value-returning function, include a return statement to return the desired value. Properly document the function by providing a meaningful function name, describing the purpose of the function, and specifying any input parameters and the return value (if applicable).

1. Set up: To set up a void function, use the keyword "void" in the function signature. For example:

c++

void functionName()

This indicates that the function does not return a value. For a value-returning function, specify the return type in the function signature. For example:

c++

dataType functionName()

Replace dataType with the desired data type to be returned by the function.

2. Implementation and Documentation: In the implementation of a void function, write the necessary code to perform the desired actions. This can include any sequence of statements or function calls.

For a value-returning function, include a return statement to specify the value to be returned. For example:

c++

dataType functionName()

{

   // Code to perform calculations or operations

   return result; // Replace "result" with the actual value to be returned}

In both cases, it is crucial to provide proper documentation for the function. This includes choosing a meaningful name for the function, describing the purpose or functionality of the function, specifying any input parameters and their types, and indicating the return value (if applicable). This documentation helps other developers understand and use the function correctly.

By following these steps, you can effectively set up, implement, and document void and value-returning functions in your code.

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Answer:

hey do you want to do a zoom

Step-by-step explanation:

i am done with my basketball game

x= 3

awutydyt7asd67awt67

the answer of the question is $36

Answer:

£150

Step-by-step explanation:

£105 is the already reduced price. and it is reduced by 30%.

that means that price is 100-30 = 70% of the original price

so, how to get the 100% out of the 70% ?

well, in the same way we do it also in the other direction.

basically, figure out 1%, and then go for how many % we need.

so, we need to divide 105 by 70 (to get 1%) and then multiply the result by 100 (to get 100% out of the 1%).

price = 105/70 × 100 = 105 × 100 / 70 = 105 × 10 / 7 =

= 15 × 10 = £150