Please help me with this asiment please I’ll do anything!!!!

Answer:

x= -10

if u need explanation pls let me know

Answer:

$12.50

Step-by-step explanation:

100%-20% -> $10

80% -> $10

100% -> \(\frac{100}{80}\) × $10 = $12.50

Answer:

The original price was $12

We can Long Division method to solve quotients step by step

What is long division method and its steps ?

When splitting huge numbers, the task is divided into several sequential parts using the long division approach. The dividend is divided by the divisor, just as in conventional division problems, and the result is known as the quotient; occasionally, it also produces a remainder.

We need to comprehend a few stages in order to divide. A vinculum or right parenthesis separates the dividend from the quotient, while a vertical bar separates the divisor from the dividend. Let's now go through the long division stages listed below to comprehend the procedure.

1. Take the dividend's first digit starting from the left . Verify if this digit exceeds or is equal to the divisor.

2. Next, divide it by the divisor, and write the result as the quotient on top.

3. Subtract the outcome from the digit, and then put the difference below.

Step 4: Decrease the dividend's subsequent digit (if present).

Step 5: Carry out Step 4 again.

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Answer:

0.7, 70/100 or 7/10

Step-by-step explanation:

70 squares are shaded.

So 70/100 of all squares are shaded

Answer:

look at the picture .......................

Answer:

37.68m^3

2143.57 m^3

Step-by-step explanation:

Volume of a cone 1/3(nr^2h)

n = 3.14

(1/3) x (3^2) x 4 x 3.14 = 37.68

Volume of a sphere = 4/3 x pi x r^3

4/3 x 8^3 x 3.14 =

Answer:  The graph is shown below. It is nonlinear

==========================================================

Explanation:

I used GeoGebra to make the graph. Desmos is another option I recommend.

The equation we graph is y = (1/2)^x since we're splitting the paper in half each time. This is an exponential decay function. Note how the curve slopes downhill when moving to the right.

It appears the curve touches or crosses the x axis; which is misleading. Instead, the curve is getting closer and closer to this horizontal asymptote. It will never reach the x axis. Think of it like an electric fence.

As the graph indicates, we don't have a straight line. Therefore, the function isn't linear. It's a nonlinear curve.

True. If a matrix has at least one row that is all zeroes, it means that the corresponding equation in the system of linear equations will be of the form 0x = 0, which is always true for any value of x.

Therefore, this equation will not impose any restrictions on the values of the variables, and hence, there will be at least one free variable.

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Answer:

GIF can support small animations

The inequalities equation which will shade all the points except target point are, y >= 2, y >= -3.5x + 4.5 and y <= 1.25x - 1.5.

The line passing through P(-1,2) and P(-4,2) has a slope of 0 and a y-intercept of 2, so its equation is y = 2. The line passing through P(-1,2) and P(-2,0.5) has a slope of -3.5 and a y-intercept of 4.5, so its equation is y = -3.5x + 4.5. The line passing through P(-2,0.5) and P(-4,2) has a slope of 1.25 and a y-intercept of -1.5, so its equation is y = 1.25x - 1.5.

Now we can create a system of inequalities that will shade all of the points except for T(-2,2). We can do this by making sure that the inequality for each line is greater than or equal to the target point on one side of the line, and less than or equal to the target point on the other side of the line.

For the line y = 2, we can write the inequality y >= 2 on the side of the line that contains the target point T(-2,2). For the line y = -3.5x + 4.5, we can write the inequality y >= -3.5x + 4.5 on the side of the line that contains the point T(-2,2). For the line y = 1.25x - 1.5, we can write the inequality y <= 1.25x - 1.5 on the side of the line that contains the point T(-2,2).

Putting all of these inequalities together, we get:

y >= 2 (for the line passing through P(-1,2) and P(-4,2))

y >= -3.5x + 4.5 (for the line passing through P(-1,2) and P(-2,0.5))

y <= 1.25x - 1.5 (for the line passing through P(-2,0.5) and P(-4,2))

These inequalities should shade all of the points except for the target point T(-2,2), and they should do so with the fewest number of inequalities possible.

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--The complete question is, With the fewest inequalities, shade all the points but leave the targets exposed. Write the inequality equations to do this.

Points are P(-1,2), P(-4,2) and P(-2, 0.5)

T(-2,2)
Graph is show in the image.--

Answer:5

Step-by-step explanation:

Answer:

B. n ≥ 12

Step-by-step explanation:

As you can see, the number is represented by n. So when n is no less than 12, it means that n is greater than 12 but can also be equal to it.

Therefore, the answer is n ≥ 12

Answer:

AAA

Step-by-step explanation:

(i) P(X < 1/2) is approximately 0.5333.

(ii) Var(X) is approximately 0.7075.

What is a density function?

A density function, also known as a probability density function (PDF), is a function that describes the probability distribution of a continuous random variable. It provides information about the relative likelihood of different values occurring within a given range.

To find the constants a and b, we can use the fact that the density function must integrate to 1 over its support. In this case, the support is the interval (0, 1). We can set up the integral and solve for the values of a and b.

∫[0,1] f(x) dx = 1

∫[0,1] (ax + b\(x^{2}\)) dx = 1

Integrating term by term:

(a/2)\(x^{2}\) + (b/3)\(x^{3}\) | [0,1] = 1

[(a/2)\((1)^2\) + (b/3)\((1)^3\)] - [(a/2)\((0)^2\) + (b/3)\((0)^3\)] = 1

(a/2) + (b/3) = 1

Now, we can use the given information that E(X) = 0.6 to find another equation involving a and b.

E(X) = ∫[0,1] x * f(x) dx

∫[0,1] x(ax + b\(x^{2}\)) dx

(a/3)\(x^3\) + (b/4)\(x^4\) | [0,1] = 0.6

[(a/3)\((1)^3\) + (b/4)\((1)^4\)] - [(a/3)\((0)^3\) + (b/4)\((0)^4\)] = 0.6

(a/3) + (b/4) = 0.6

Now we have a system of equations:

(a/2) + (b/3) = 1 ---(1)

(a/3) + (b/4) = 0.6 ---(2)

We can solve this system of equations to find the values of a and b.

Multiplying equation (1) by 3 and equation (2) by 2, we get:

(3a/2) + (2b/3) = 3

(2a/3) + (2b/2) = 1.2

Simplifying the equations:

3a + (4b/3) = 3

2a + (3b/2) = 1.2

Now we can multiply the second equation by 2 and subtract it from the first equation to eliminate a:

3a + (4b/3) - (4a + 3b) = 3 - 2(1.2)

3a + (4b/3) - 4a - 3b = 3 - 2.4

-a - (5b/3) = 0.6

Multiplying through by -1:

a + (5b/3) = -0.6

Now we can solve this equation simultaneously with equation (1) to find a and b:

a + (5b/3) = -0.6 ---(3)

(a/2) + (b/3) = 1 ---(1)

Multiplying equation (1) by 3 and equation (3) by 2, we get:

(3a/2) + b = 3

2a + (10b/3) = -1.2

Simplifying the equations:

3a + 2b = 6

6a + 10b = -3.6

Multiplying the first equation by 3 and subtracting it from the second equation to eliminate a:

6a + 10b - 9a - 6b = -3.6 - 18

-3a + 4b = -21.6

Now we have two equations:

-3a + 4b = -21.6 ---(4)

3a + 5b = 1.8 ---(5)

We can eliminate a by adding equations (4) and (5):

(-3a + 4b) + (3a + 5b) = -21.6 + 1.8

9b = -19.8

b = -19.8 / 9

b = -2.2

Substituting the value of b into equation (4):

-3a + 4(-2.2) = -21.6

-3a - 8.8 = -21.6

-3a = -21.6 + 8.8

-3a = -12.8

a = -12.8 / -3

a = 4.27 (rounded to two decimal places)

Therefore, the constants a and b are approximately a = 4.27 and b = -2.2.

(i) To find P(X < 1/2), we need to integrate the density function from 0 to 1/2:

P(X < 1/2) = ∫[0,1/2] f(x) dx

P(X < 1/2) = ∫[0,1/2] (4.27x - 2.2\(x^{2}\)) dx

Integrating term by term:

(4.27/2)\(x^2\) - (2.2/3)\(x^3\) | [0,1/2]

[(4.27/2)(1/2)² - (2.2/3)(1/2)³] - [(4.27/2)(0)² - (2.2/3)(0)³]

[4.27/8 - 2.2/24] - [0]

P(X < 1/2) = 0.5333 - 0 = 0.5333 (rounded to four decimal places)

Therefore, P(X < 1/2) is approximately 0.5333.

(ii) To find Var(X), we can use the formula:

Var(X) = E(X²) - [E(X)]²

We already know E(X) = 0.6. Now let's calculate E(X²):

E(X²) = ∫[0,1] x² * f(x) dx

E(X^2) = ∫[0,1] x² * (4.27x - 2.2x²) dx

E(X^2) = ∫[0,1] (4.27x³ - 2.2x⁴) dx

Integrating term by term:

(4.27/4)x⁴ - (2.2/5)x⁵ | [0,1]

[(4.27/4)(1)⁴ - (2.2/5)(1)⁵] - [(4.27/4)(0)⁴ - (2.2/5)(0)⁵]

[4.27/4 - 2.2/5] - [0]

E(X²) = 1.0675 - 0 = 1.0675 (rounded to four decimal places)

Now we can calculate Var(X):

Var(X) = E(X^2) - [E(X)]²

Var(X) = E(X^2) - [E(X)]²

Var(X) = 1.0675 - (0.6)²

Var(X) = 1.0675 - 0.36

Var(X) = 0.7075

Therefore, Var(X) is approximately 0.7075.

Therefore:

(i) P(X < 1/2) is approximately 0.5333.

(ii) Var(X) is approximately 0.7075.

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Gender and ethnicity are categorical variables and therefore, the standard deviation cannot be calculated for variables.

The standard deviation is a measure of the spread or dispersion of the data around the mean. In other words, it tells us how far each data point in a set is from the average of the set.

When we analyze data, it's important to understand how much variation there is in the data, and the standard deviation is one way to do this.

When it comes to the three dependent variables in the data set (gender, age, and ethnicity), it is important to understand that the standard deviation is only calculated for numerical data.

However, age is a numerical variable, and the standard deviation can be calculated for it.

To find the standard deviation of the ages, we need to first find the mean of the ages and then subtract each age value from the mean and square the result.

Next, we add up all the squared deviations and divide by the number of ages minus one. Finally, we take the square root of the result, and that gives us the standard deviation of the ages in the data set.

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Answer:

I think it's C and E am not sure

Answer:

3 4/5

Step-by-step explanation:

If Natalie runs 5 miles each week and she already ran 1 1/5 then she will need to run 3 4/5.

5 - 1 1/5 = 3 4/5

Answer:

-5/3

Step-by-step explanation:

The value exceeds $1 million for the first time on the 21st square of the checkerboard.

The value of each square follows a doubling pattern:

$1, $2, $4, $8, $16, and so on.

We can express this pattern as \(2^{(n-1)}\), where n represents the square number.

We need to find the value of n for which \(2^{(n-1)}\) exceeds $1 million:

\(2^{(n-1)} > 1,000,000\)

Taking the logarithm base 2 of both sides, we get:

\((n-1) > log_2(1,000,000)\)

Using a calculator, we can determine the logarithm:

\(log_2(1,000,000) = 19.93\)

Now, solving for n:

n-1 > 19.93

n > 20.93

Since n represents the square number, it must be a whole number. Therefore, we need to round up to the nearest whole number, giving us:

n = 21

Therefore, the value exceeds $1 million for the first time on the 21st square of the checkerboard.

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The complete question is as follows:

A father put a dollar on the first square of an 8x8 checkerboard. On the second square, the father doubled $2, on the third $4, on the fourth $8, and so on. At what square would the value be more than $1 million for the first time?

The volume of the cone is V = 193.8 inches³

Given data ,

Let the volume of the cone be represented as V

Now , the height of cone h = 5.9 inches

And , diameter of cone = 11.2 inches

So , radius of cone r = 5.6 inches

where , Volume of Cone = ( 1/3 ) πr²h

V = ( 1/3 ) ( 3.14 ) ( 5.6 )² ( 5.9 )

V = 193.8 inches³

Hence , the volume is V = 193.8 inches³

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Answer:

Step-by-step explanation:

are there values for f or b or q? What are we trying to solve?

Answer:

4(6+7)

Explanation:

24+28

(4×6)+(4×7)

4(6+7)

The correct answer is C. We need to multiply the top equation by \(2\) in order to solve this system using the elimination method.

To solve the system of equations using the elimination method, we need to manipulate one or both equations by multiplying them by a constant so that the coefficients of either \(x \ or\ y\) in one equation will cancel out when added to the corresponding term in the other equation.

In this case, to eliminate the y terms, we can multiply the top equation by the coefficient of y in the bottom equation, which is \(3\).

By multiplying the top equation by \(3\), we get:

\(\[3(2x + y) = 3(11)\]\[6x + 3y = 33\]\)

Now, the new system of equations is:

\(\[6x + 3y = 33\]\[5x + 3y = 29\]\)

We can now subtract the second equation from the first equation to eliminate the y term:

\(\[(6x + 3y) - (5x + 3y) = 33 - 29\]\[x = 4\]\)

Therefore, the correct answer is C. We need to multiply the top equation by \(2\) in order to solve this system using the elimination method.

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The p-value can be calculated to test the null hypothesis that the average running time of HP laptops is 120 minutes against the alternative hypothesis that it is not equal to 120 minutes.

The p-value for testing the hypothesis that the average time for the HP laptops is not equal to 120 minutes can be calculated using a t-test. Given a sample mean of 122 minutes, a sample size of 60, a null hypothesis mean of 120 minutes, and a standard deviation of 25 minutes, we can calculate the t-value and find the corresponding p-value.

To calculate the t-value, we use the formula: t = (sample mean - null hypothesis mean) / (sample standard deviation / sqrt(sample size))

Plugging in the values, we get: t = (122 - 120) / (25 / sqrt(60))

Calculating the t-value, we find t ≈ 0.894

To find the p-value associated with this t-value, we can refer to a t-distribution table or use statistical software. The p-value represents the probability of observing a t-value as extreme as the one obtained, assuming the null hypothesis is true.

Since the p-value (0.757) is greater than the commonly used significance level of 0.05, we fail to reject the null hypothesis. This suggests that there is not enough evidence to conclude that the average running time of HP laptops is significantly different from 120 minutes.

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Answer:

In a dilation, the figure changes size but not shape.

Step-by-step explanation:

Helping in the name of Jesus.

Thus, the ordered triple (s, m, l) that represents the costs of the three boxes is (1.50, 2.00, 2.75).

The cost for three packages of moving boxes is modeled by the system of equations below.

Let s represents the cost of each small box, m represents the cost of each medium box, and l represents the cost of each large box, the ordered triple (s, m, l) that represents the costs of the three boxes is (1.50, 2.00, 2.75).

Explanation: The cost for each package of small box is 's' dollars,

therefore, the cost for three packages of small boxes is 3s dollars.

The cost for each package of medium box is 'm' dollars, therefore, the cost for three packages of medium boxes is 3m dollars.

The cost for each package of large box is 'l' dollars, therefore, the cost for three packages of large boxes is 3l dollars.

The total cost of three packages of moving boxes is given as $10.25.

Thus, the equation can be written as follows:\(3s + 3m + 3l = $10.25, or3(s + m + l) = $10.25\), or \(s + m + l = $3.42.\)

The ordered triple (s, m, l) that represents the costs of the three boxes can be determined by solving the given system of equations as follows:1.50s + 2.00m + 2.75l = $3.42

Divide the above equation by 0.25, to get:6s + 8m + 11l = $13.68.......(i)2.00s + 2.50m + 3.50l = $10.25

Multiply the above equation by 3, to get:6s + 7.5m + 10.5l = $30.75.......(ii)Solve equations (i) and (ii) by using the elimination method: 6s + 8m + 11l = $13.68.......(i)6s + 7.5m + 10.5l = $30.75.......(ii)- 6s - 7.5m - 10.5l = - $30.75

Add both the equations to eliminate \('s':0.5m + 0.5l = $17.07 - $13.68m + l = $0.78\)......(iii)Substitute the value of l in equation (iii) into equation (i) to solve for 'm':\(6s + 8m + 11($0.78) = $13.686s + 8m = $4.12m = $2.00.\)

Substitute the value of m and l in equation (iii) into equation (i) to solve for \('s':1.50s + 2.00($2.00) + 2.75($0.78) = $3.42s = $1.50.\)

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Answer:

a = 7.5

Step-by-step explanation:

7*3(2a-1) over 7 = 6.7

(2a-1) = 42/3

2a-1=14

2a=13

a=7.5

I hope this helps you out!

Answer:

put 6 over 1 then look for the LCM of 7 and 1 the LCM is 7 then ask yourself how times does seven go into 7 one time right so multiply 1 by 3(2a - 1) then ask yourself how many times does 1 go into 7 it goes 7 times right multiply 7 by 6 so your equation is like this 3(2a - 1) = 42 open the bracket so it will be 6a - 3 = 42 collect the like terms so 3a = 42+3, 3a =45 , divide both sides by 3 so x =15

The value of x is 22.

Given is a parallelogram ABCD, in which angle B and C are 4x+12 and 3x+14, we are asked to find the value of x,

We can make use of the fact that a parallelogram's adjacent angle sum equals 180 degrees.

According to the given information, the adjacent angles B and C are 4x + 12 and 3x + 14, respectively.

The equation:

(4x + 12) + (3x + 14) = 180

Combine like terms:

7x + 26 = 180

Subtract 26 from both sides:

7x = 154

Divide both sides by 7:

x = 22

Therefore, the value of x is 22.

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Answer:

Where are the expressions?

Answer:

48+12=60

60÷2=30

your answer is 30+30