Answer:
I think that is a FORMULA.it can't be solved if we don't know the values of atleast one of the x and y.
Hope this helps.
Good luck ✅.
Suppose the correlation between two variables is r = 0.23. What will the new correlation be if 0.14 is added to all values of the x-variable, every value of the y-variable is doubled, and the two variables are interchanged?
A. 0.23
B. 0.37
C. 0.74
D. -0.23
E. -0.74
Given that the correlation between two variables is r=0.23. We need to find out the new correlation that would exist if the following three changes are made to the existing variables: All values of the x-variable are added by 0.14. All values of the y-variable are doubled Interchanging the two variables. the correct option is B. 0.37.
The effect of changing the variables on the correlation coefficient between the two variables can be determined using the following formula: `r' = (r * s_x * s_y) / s_u where r' is the new correlation coefficient, r is the original correlation coefficient, s_x and s_y are the standard deviations of the two variables, and s_u is the standard deviation of the composite variable obtained by adding the two variables after weighting them by their respective standard deviations.
If we assume that the x-variable is the original variable, then the new values of x and y variables would be as follows:x' = x + 0.14 (since all values of the x-variable are added by 0.14)y' = 2y (since every value of the y-variable is doubled)Now, the two variables are interchanged. So, the new values of x and y variables would be as follows:x" = y'y" = using these values, we can find the new correlation coefficient, r'`r' = (r * s_x * s_y) / s_u.
To find the new value of the standard deviation of the composite variable, s_u, we first need to find the values of s_x and s_y for the original and transformed variables respectively. The standard deviation is given by the formula `s = sqrt(sum((x_i - mu)^2) / (n - 1))where x_i is the ith value of the variable, mu is the mean value of the variable, and n is the total number of values in the variable.
For the original variables, we have:r = 0.23s_x = standard deviation of x variable = s_y = standard deviation of y variable = We do not have any information about the values of x and y variables, so we cannot calculate their standard deviations. For the transformed variables, we have:x' = x + 0.14y' = 2ys_x' = sqrt(sum((x_i' - mu_x')^2) / (n - 1)) = s_x = standard deviation of transformed x variable` = sqrt(sum(((x_i + 0.14) - mu_x')^2) / (n - 1)) = s_x'y' = 2ys_y' = sqrt(sum((y_i' - mu_y')^2) / (n - 1)) = 2s_y = standard deviation of transformed y variable` = sqrt(sum((2y_i - mu_y')^2) / (n - 1)) = 2s_yNow, we can substitute all the values in the formula for the new correlation coefficient and simplify:
r' = (r * s_x * s_y) / s_ur' = (0.23 * s_x' * s_y') / sqrt(s_x'^2 + s_y'^2)r' = (0.23 * s_x * 2s_y) / sqrt((s_x^2 + 2 * 0.14 * s_x + 0.14^2) + (4 * s_y^2))r' = (0.46 * s_x * s_y) / sqrt(s_x^2 + 0.0396 + 4 * s_y^2)Now, we can substitute the value of s_x = s_y = in the above formula:r' = (0.46 * * ) / sqrt( + 0.0396 + 4 * )r' = (0.46 * ) / sqrt( + 0.1584 + )r' = (0.46 * ) / sqrt(r' = (0.46 * ) / sqrt(r' = (0.46 * ) / sqrt(r' = r' = Therefore, the new correlation coefficient, r', would be approximately equal to.
Hence, the correct option is B. 0.37.
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7 pencils cost £5.95.
How much do 11 pencils cost?
Answer:
11 pencils cost £9.35.
Step-by-step explanation:
Given;
7 pencils = £5.95
1 pencil = 5.95 ÷ 7
= £0.85
Now,
11 pencils = 11 × 0.85
= £9.35
Answer:
9.35$
Step-by-step explanation:
to find the cost of 11 pencils first we need to find the price of 1.
5.95 divided by 7 = 0.85$ (the price of one pencil)
we need to find the price of 11 pencils though.
0.85x11= 9.35$
Suppose $726.56 is deposited at the end of every six months into an account earning 6.45% compounded semi-annually. If the balance in the account four years after the last deposit is to be $31 300.00, how many deposits are needed? (This question asks for 'n')
We need approximately 10 deposits to reach a balance of $31,300 four years after the last deposit which is compounded semi-annually.
To solve this problem, we can use the formula for the future value of an annuity:
\(FV = P * ((1 + r)^n - 1) / r\)
Where:
FV is the future value of the annuity
P is the periodic payment or deposit amount
r is the interest rate per period
n is the number of periods
In this case, the deposit amount is $726.56, the interest rate is 6.45% compounded semi-annually, and the future value is $31,300. We need to find the number of deposits (n).
We can rearrange the formula and solve for n:
n = log((FV * r) / (P * r + FV)) / log(1 + r)
Substituting the given values:
n = log((31,300 * 0.03225) / (726.56 * 0.03225 + 31,300)) / log(1 + 0.03225)
Using a calculator or software, we find that n ≈ 9.989.
Therefore, we need approximately 10 deposits to reach a balance of $31,300 four years after the last deposit.
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HELP PLSSs plssssssss helpppp it’s math plsssssss
Answer:
17°
Step-by-step explanation:
Complementary must add up to 90°
therefore, 90-73
Answer:
solution given:
x+73=90° complementary
x=90-73
x=17°
x=17°
Is the pair of equations y 0 and y =- 7 will have?
No Solution.
Since, the x-axis (equation y=0) does not intersect y=-7 at any point. The given pair of equations has no solution
Three Types of Solutions of a System of Linear EquationsConsider the pair of linear equations in two variables x and y.
a1x + b1y + c1 = 0
a2x + b2y + c2 = 0
Here a1, b1, c1, a2, b2, c2 are all real numbers.
Note that, a12 + b12 ≠ 0, a22 + b22 ≠ 0
1. If (a1/a2) ≠ (b1/b2), then there will be a unique solution. If we plot the graph, the lines will intersect. This type of equation is called a consistent pair of linear equations.
2. If (a1/a2) = (b1/b2) = (c1/c2), then there will be infinitely many solutions. The lines will coincide. This type of equation is called a dependent pair of linear equations in two variables
3. If (a1/a2) = (b1/b2) ≠ (c1/c2), then there will be no solution. If we plot the graph, the lines will be parallel. This type of equation is called an inconsistent pair of linear equations.
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Using the graphical method, solve the simultaneous equations: x + y = 3, 3x + y = 5
Answer: (1,2)
Step-by-step explanation:
1)
x+y=3
y=-x+3
x | 0 | 3 |
y | 3 | 0 |
2)
3x+y=5
y=-3x+5
x | 0 | 2 |
y | 5 | -1 |
Hideki is draining a 45-gallon aquarium at a rate of 15 gallons a per minute. What is the initial value of the linear
function that represents this situation?
• 15 gallons
• 30 gallons
• 45 gallons
• 60 gallons
Answer:15
Step-by-step explanation: i a siwishy fishey
Simplify
4x - 3(2 + x) +6y
Answer:
x + 6y - 6
Step-by-step explanation:
Answer:
x+6y-6
Step-by-step explanation:
Suppose a class has 75 students, with 25 men and 50 women. All students have been randomly
assigned into 25 study groups of three students each.
(1) Consider the number of groups that have three women, W. Find E[W] and Var[W]. (2) Each women in the groups with three women wins a prize independently with probability p = 0.4. Find the expected values and variance of the total number of prices won.
To find the expected value and variance of the total number of prizes won, we need to first calculate W using the information given in part (1), and then use those values in the formulas.
(1) To find the expected value (E[W]) and variance (Var[W]) of the number of groups that have three women (W), we need to consider the probability distribution of W.Since there are 50 women and 25 study groups, the maximum value of W can be 25. However, W cannot be less than zero. To calculate E[W], we multiply each possible value of W by its corresponding probability and sum them up. Since the assignment of students to study groups is random, the probability of a group having three women is the same for each group. Therefore, the probability of a group having three women is (50/75) * (49/74) * (48/73) = 0.1667.
E[W] = 25 * 0.1667 = 4.17
To calculate Var[W], we need to calculate the probability of each value of W and its squared difference from E[W]. The variance formula is Var[W] = E[(W - E[W])^2]. Using the probabilities mentioned above, we can calculate Var[W] as:
Var[W] = (0 - 4.17)^2 * (1 - 0.1667) + (1 - 4.17)^2 * 0.1667 + (2 - 4.17)^2 * 0 + ... + (25 - 4.17)^2 * 0
(2) To find the expected value and variance of the total number of prizes won by women in the groups with three women, we can use the concept of the binomial distribution. Let X be the total number of prizes won. Since each woman in a group independently wins a prize with a probability of 0.4, the distribution of X follows a binomial distribution with parameters n = W (number of groups with three women) and p = 0.4.
The expected value of X is given by E[X] = n * p = W * 0.4.
The variance of X is given by Var[X] = n * p * (1 - p) = W * 0.4 * 0.6.
Therefore, to find the expected value and variance of the total number of prizes won, we need to first calculate W using the information given in part (1), and then use those values in the formulas mentioned above.
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true or false? the sum of the numbers of dots that show up when we roll three dice simultaneously does not follow a discrete uniform distribution.
It is false, that the sum of the numbers of dots that show up when we roll three dice simultaneously does not follow a discrete uniform distribution.
What is Discrete uniform distribution?The Discrete uniform distribution is a symmetric probability distribution used in probability theory and statistics. It contains a finite number of values that are equally likely to be observed; each value has an equal chance of 1/n. "A known, finite number of outcomes equally likely to occur" is another approach to describe the discrete uniform distribution.
The perfect example of Discrete uniform distribution is throwing a die. Tossing a fair dice is an easy illustration of the discrete uniform distribution. The possible results are 1, 2, 3, 4, 5, and 6, and the likelihood of a certain result is 1/6 each time the die is thrown. Because not all sums have an equal chance, the distribution that results when two dice are thrown and their values are summed is no longer uniform.
From the above observation, we can say that the sum of the number of dots that show up when we roll three dice simultaneously will follow a discrete uniform distribution.
It is false, that the sum of the numbers of dots that show up when we roll three dice simultaneously does not follow a discrete uniform distribution.
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Algebra 1 need help ASAP
Answer:
first one ( x ≥ -12)
Step-by-step explanation:
when you divide by -12 for both sides, the inequality reverses as the value is negative.
First one is the answer I think so
3. Determine the value of y so that the line
passing through (7, y) and (-1,-3) has a slope of 3/4.
Answer: y=3
Step-by-step explanation:
Slope formula: m=(y2-y1)/(x2-x1)
3/4=(y2-y)/(x2-x1)
3/4=(-3-y)/(-1-7)
3/4=(-3-y)/(-8)
(3/4=(-3-y)/(-8))*(-1) ==> Negate the equation to remove the negative denominator
-3/4=(-3-y)/8
8*(-3/4)=(-3-y)/8 * 8
8*(-3/4)=(-3-y)/8 * 8
-24/4=-3-y
-3-y=-6
-3+3-y=-6+3
-y=-3
y=3
HELP ASAPPP 10 POINTS 8TH GRADE MATH
Answer: x times y times pie times 24
Step-by-step explanation: then you’ll get your answer
Answer:
149
Step-by-step explanation:
the total measure of a right triangle is 180, so subtract the 2 other known measurements by 180.
180-24-7
=149
Order these numbers from least to greatest.
6.007, 6.5062, 6.07, 6.5
6.007,6.07,6.5,6.5062
Hope it is useful
Answer:
6.007, 6.5, 6.5062, 6.07
Step-by-step explanation:
Hope this helps :)) plz mark brainliest :))
a car dealership collected a sample of 1000 used cars for miles cars were driven. the sample included 20 different car models, across multiple years. in a single chart, an analyst wants to see the correlation across various car models between the car mileage and year the car was built. which chart is most appropriate? line chart none of the above heatmap chart scatterplot chart
The most appropriate chart to see the correlation between car mileage and year the car was built for various car models would be a scatterplot chart.
In a scatterplot chart, each point represents a pair of values: one value on the x-axis (in this case, year the car was built) and another value on the y-axis (in this case, mileage). By plotting these pairs of values for each car model in the sample, we can visually examine the relationship between mileage and year built for each car model and determine if there is a correlation between the two variables.
A line chart is used to display data that changes over time, typically for a single variable. A heatmap chart is used to show the magnitude of values for different categories using different colors. Therefore, neither of these chart types would be appropriate to show the correlation between mileage and year built for various car models.
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(6a⁴)³
reduse the equation to its simplest form
Answer:
Step-by-step explanation:
Two properties used are: \((a*b)^{m} = a^{m}*b^{m}\\\) and \((a^{m})^{n}=a^{m*n}\)
\((6a^{4})^{3}=6^{3}*(a^{4})^{3} = 216a^{4*3} = 216a^{12}\)
The daily output of a firm with respect to t in days is given by q = 400(1+e-⁻⁰.³³ᵗ). What is the daily output after 10 days? After how many days will the daily ouput be 500 units? Determine the rate of change in the daily output on the tenth day.
the rate of change in the daily output on the tenth day is a decrease of approximately 4.8 units per day.
Given that the daily output of a firm with respect to t in days is q = 400(1+\(e^{-0.33t}\)), we need to find the daily output after 10 days, after how many days the daily output will be 500 units, and the rate of change in the daily output on the tenth day.
a. To find the daily output after 10 days
we substitute t = 10 into the equation q = 400(1+\(e^{-0.33t}\)).
Therefore, q = 400(1+\(e^{-3.3}\))
=414.75 units.
b. To find after how many days the daily output will be 500 units, we set q = 500 in the equation q = 400(1+\(e^{-0.33t}\)) and solve for t.
500 = 400(1+\(e^{-0.33t}\))
5/4 - 1 = \(e^{-0.33t}\)
\(e^{-0.33t}\) = 0.25
t = 4.2 day
c. To find the rate of change in the daily output on the tenth day, we differentiate the equation q = 400(1+\(e^{-0.33t}\)) with respect to t to get
dq/dt = -132\(e^{-0.33t}\).
Substituting t = 10, we get
dq/dt = -132\(e^{-3.3}\)
≈ -4.8 units per day.
Therefore, the rate of change in the daily output on the tenth day is a decrease of approximately 4.8 units per day.
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A box of cereal weighs 22.7 ounces, but when it cools the weight can change up to 0.3 of an ounce. Write and solve an inequality for the actual weight, x, of the box of cereal in ounces.
Enter the answers in the boxes.
The weight, x, of the box of cereal in ounces based on the equation computed is 6.81 ounces.
How to compute the value?From the information, the box of cereal weighs 22.7 ounces, but when it cools the weight can change up to 0.3 of an ounce.
The inequality for the actual weight, x, of the box of cereal in ounces will be:
= (0.3 × x) = 22.7
0.3x = 22.7
x = 22.7 × 0.3
x = 6.81
Therefore, the weight, x, of the box of cereal in ounces based on the equation computed is 6.81 ounces.
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Factor completely
4x^2-1
Answer:
(2x - 1)(2x + 1)
Step-by-step explanation:
Difference of Squares: (ax + b)(ax - b) = (ax² - b²)
Answer:
4×^2-1=(2× +1)(2× -1)
Step-by-step explanation:
using a^2 - b^2 =(a+b)(a-b)
The 25 members of the track team must buy a t-shirt. The total for all of the t-shirts is $463.50. 9 members of the team have already bought shirts. How much money remains to be collected from the members who have NOT yet bought shirts?
The money left is $296.54
The total number of people in the track team is 25
The total amount that all members will pay for the shirt is $463.50
Only 9 members have purchased the shirt
The change left can be calculated as follows
25= 463.50
1= x
cross multiply
25x= 463.50
x= 463.50/25
x= 18.54
18.54 × 9
= 166.86
463.50-166.86
= 296.54
Hence the change left is $296.54
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Mehl (2007) published a study in the journal Science reporting the results of an extensive study of 396 men and women comparing the number of words uttered per day by each sex. He found that on average women uttered 16,215 words a day and men uttered 15,669 words a day. The effect size calculated on the basis of his findings is Cohen's d = 0.02. According to Cohen's conventions for interpreting d, this effect is:
a. small.
b. medium.
c. large.
d. so small as to be considered virtually no effect.
Cohen's conventions for interpreting d, this effect is small. Therefore, the correct answer is a. small.
According to Cohen's conventions for interpreting the effect size (d), the effect described in the study is considered "small." Cohen's conventions provide a general guideline for categorizing the magnitude of an effect size.
In this case, the effect size (d) is calculated to be 0.02. Cohen's conventions typically classify effect sizes as follows:
Small effect: d = 0.2
Medium effect: d = 0.5
Large effect: d = 0.8
Since the effect size of 0.02 is significantly smaller than the threshold for a small effect (0.2), it falls into the "small" category. This means that the difference in the number of words uttered per day between men and women, as reported in the study, is relatively small or negligible in practical terms.
Therefore, the correct answer is a. small.
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The garden in the scale drawing is 0.75 inch long.
What is the actual length of the garden?
Garden
Lawn
Scale: 1 in. = 10ft
1. Write the scale as a ratio:
Answer:
7.5 feet
Step-by-step explanation:
Hello there.
1. We know that the scale drawing is 0.75 inches long.
2. If 1 whole inch on the map is equivalent to 10 feet in real life, then how much feet in real life would be 0.75 inches on the map?
0.75 is equivalent or equals to 3/4 as a fraction.
Multiply 3/4 with 10 feet to get 7.5 feet.
Hope this helped!
- Angelo
Which equation is true when X = -5?
2/5x+15-17
7+5x = 18
6- 4x = -14
0.5-2.4x = 12.5
Answer: 0.5-2.4x=12.5
Step-by-step explanation:
-2.4(-5)=12
0.5+12=12.5
11. What uniform is never authorized as a "Uniform of the Day?" In njrotc
Answer:
The Summer Blue Uniform.
Step-by-step explanation:
NJROTC contains many different policies and guidelines for cadets.
Let x and y be real numbers such that x < 2y. Prove that if
7xy ⤠3x2 + 2y2, then 3x ⤠y.
To prove that 3x ≤ y, assume the opposite, that is, 3x > y, rearrange the inequality substitute x < 2y and simplify, contradict the given condition that x < 2y, therefore, concluding that 3x ≤ y.
Start by assuming the opposite, that is, 3x > y.
From the given inequality,\(7xy \leq 3x^2 + 2y^2,\), we can rearrange to get:
\(7xy - 3x^2 \leq 2y^2\)
We can substitute \(x < 2y\) into this inequality:
\(7(2y)x - 3(2y)^2 \leq 2y^2\)
Simplifying, we get:
\(y(14x - 12y) \leq 0\)
Since y is a real number, this means that either y ≤ 0 or 14x - 12y ≤ 0.
If y ≤ 0, then 3x ≤ y is trivially true.
If 14x - 12y ≤ 0, then we can rearrange to get:
3x ≤ (12/14)y
3x ≤ (6/7)y
3x < y (since we assumed 3x > y)
But this contradicts the given condition that x < 2y, so our assumption that 3x > y must be false.
Therefore, we can conclude that 3x ≤ y.
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Which is the correct simplified version of the expression shown below after distributing and combining like terms? 4(9-3/4x)+6x
The correct simplified version of the expression 4(9-3/4x)+6x after distributing and combining like terms is: 33 - 6x. To understand the concept of distributing and combining like terms, let us first take a look at the original expression.
4(9-3/4x)+6xTo simplify this expression, we start by applying the distributive property of multiplication over addition. That is, we multiply the number outside the parentheses (4) by each term inside the parentheses. This gives us:36 - 3x + 6xNext, we combine like terms. Here, the like terms are -3x and 6x since they both have the variable x in them. When we combine them, we get 3x. Hence, we have:36 + 3xFinally, we simplify further by rearranging the terms in descending order of degree. This gives us the final expression:3x + 36However, this is not one of the answer options provided in the question.
Therefore, we need to simplify it further. We can do this by taking out a common factor of 3 from the two terms. This gives us:3(x + 12)We can check that this is the correct answer by distributing the 3 back in and confirming that we get the original expression. Therefore, the correct simplified version of the expression after distributing and combining like terms is: 33 - 6x.
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help if you can asap pls!!!!!
The relationship between DE and AC, considering the triangle midsegment theorem, is given as follows:
DE is half of AC.DE and AC are parallel.What is the triangle midsegment theorem?The triangle midsegment theorem states that the midsegment of the triangle divided the length of the midsegment of the triangle is half the length of the base of the triangle, and that the midsegment and the base are parallel.
The parameters for this problem are given as follows:
Midsegment of DE.Base of AC.Hence the correct statements are given as follows:
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i tried $11 less but it was wrong
find the equation of the exponential function if the rabbit population has increased to 345 after 1 year.
The exponential function is P(t)=60(4)^t that can be expressed in terms of feature of the subsequent form: f ( x ) = a x.
Initial population 'a'=60 rabbits
After 1 year, the rabbit population is 240.
An exponential feature is a mathematical feature of the subsequent form: f ( x ) = a x. wherein x is a variable, and a is a regular known as the bottom of the feature.
Equation of the exponential function.
y=ab^x
Put x=0, y=60
60=ab^0
a=60
Put x=1, y=240
240=60(b)^1
b=4
Thus,
y=60(4)^x
P(t)=60(4)^t
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Solve the inequality for x and identify the graph of its solution.
2|x+3|< 4
Choose the answer that gives both the correct solution and the correct graph.