please help me :((((

Answer:

1) 2   2) 8   3) 2   4) 8   5) 3   6) 9   7) 6   8) 3

Step-by-step explanation:

examples

2⁴ⁿ⁺¹: n=1     2⁹ = 512

7⁴ⁿ⁺⁷: n=1     7¹¹ = 1977326743

Work Shown:

\(\frac{1+\sqrt{-32}}{4}\\\\\frac{1+\sqrt{-1*16*2}}{4}\\\\\frac{1+\sqrt{-1}*\sqrt{16}*\sqrt{2}}{4}\\\\\frac{1+i*4*\sqrt{2}}{4}\\\\\frac{1+4i*\sqrt{2}}{4}\\\\\frac{1}{4}+\frac{4i*\sqrt{2}}{4}\\\\\boldsymbol{\frac{1}{4}+i\sqrt{2}}\\\\\)

This matches with choice C. The imaginary 'i' term is not under the square root.

Answer:

\( \frac{x + 19}{ - 2} = 5 \\ x + 19 = 5 \times ( - 2) \\ x + 19 = - 10 \\ x = - 19 - 10 \\ \boxed{x = - 29 }\)

If p > 5 is prime and p is divided by 10, then the remainders are 1, 3, 7, or 9

The given information, we know that p is a prime number greater than 5, and that p is divided by 10. This means that p must end in either 0 or 5. since those are the only digits that allow for a number to be divisible by 10.

However, we also know that p is prime, which means it cannot be divisible by any number other than 1 and itself. This rules out the possibility of p ending in 0. since any number ending in 0 is divisible by 10 (and therefore not prime).

Therefore, p must end in 5. This means that p can be written in the form:

p = 10n + 5

where n is some integer. Now, let's consider what happens when we divide p by 10:

p/10 = (10n + 5)/10 = n + 0.5

Since p/10 is not an integer (it has a decimal component of 0.5), we know that p cannot be evenly divided by 10. Therefore, when p is divided by 10, there must be a remainder.

To determine what possible remainders there could be, we can look at the possible values for the last digit of p. Since p ends in 5, the last digit can only be 1, 3, 7, or 9 (since these are the only digits that, when multiplied by 5 and added to 10n, result in a number ending in 5).

Therefore, if p > 5 is prime and p is divided by 10, the remainder must be either 1, 3, 7, or 9.

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The expression to differentiate is f(x) = 3x(4x+3)³. Differentiate the expression using the power rule and the chain rule.

Then, show your answer.Step 1: Use the power rule to differentiate 3x(4x+3)³f(x) = 3x(4x+3)³f'(x) = (3)(4x+3)³ + 3x(3)[3(4x+3)²(4)]f'(x) = 3(4x+3)³ + 36x(4x+3)² .

Simplify the expressionf'(x) = 3(4x+3)²(16x + 3): The value of f'(x) = 3(4x+3)²(16x + 3).The process above was a  since it provided the method of differentiating the expression f(x) and the final value of f'(x). It was  as requested in the question.

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Answer:

12(a) 4(x+19)=752 (b) 169

Step-by-step explanation:

12(a) 4(x+19)=752

   (b) 4(x+19)=752

        4x+76=752

               4x=676

                 x=169

a. The equation representing the situation is 4(x+19)=752

b. The price of one ticket is $169

It is important to note that algebraic expressions are defined as expressions consisting of terms, coefficients, constants, factors and variables

They are also made up of mathematical operations are;

From the information given, we have that;

Let x be the price ticket

This is then represented as;

4(x+19)=752

expand

4x + 76 = 752

collect the like terms

4x = 676

Divide by the coefficient

x = $169

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This question is incomplete, the complete question is;

PROBLEM SOLVING WITH PERCENTS: You are planning a wedding reception for 75 guests that will take place in exactly 10 months. There are two different sites that you are contemplating using, with the stipulations on payments as described below. Determine the TOTAL cost of renting each location.

Rental of space = $68 per guest; Down payment = 25% of total cost; Payment due one month before the reception includes a 7.4% interest payment on the balance.

Answer:  Total Cost of Renting = $5312.29

Step-by-step explanation:

Given that;

Rental space = $68 per guest, down payment = 25%,  7.4% interest payment on the balance.

Total Cost of Renting = Down Payment + Remaining payment

Total Cost of Renting = $68 × Guests × 25% + ($68 × Guest - Down payment) ×  (1 + Interest *9/12)

Total Cost of Renting = $68 × 75 × 25% + ($68 × 75 - Down payment) × (1 + 7.40% × 9/12)

Total Cost of Renting = $1275 + ($5100 - 1273) × (1.0555)

Total Cost of Renting = $1275 + 4037.29

Total Cost of Renting = $5312.29

Based on the information provided the coordinates would be

To know her sequence, let's apply the rule given"Add 1, then multiply by 3"

2 + 1 = 3 x 3 = 9

3+1 = 4 x 3 =12

4 +1 = 5 x 3 =14

5 + 1 = 6x3 = 18

Let's apply the rule given "Add 2, then multiply by 2"

2+ 2 = 4x2= 8

3+2= 5x2= 10

3+3= 6x 2= 12

4+3=7x 12 = 14

Based on this, the coordinates are (2,2), (9,8), (12,10), (14,12), (18,14).

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Answer:

You are missing some of the equation my dude

Step-by-step explanation:

The statement ' if this model suffers from heteroskedasticity, then the usual OLS t statistics no longer have a t distribution and the f statistics no longer have an f distribution' is true because a model suffering from heteroskedasticity will not be accurate.

If a model suffers from heteroskedasticity, which is the condition where the variance of the errors is not constant across observations, then the usual OLS t statistics and F statistics no longer have t or F distributions, respectively. In other words, the standard errors of the coefficients and the overall fit of the model cannot be accurately estimated using the usual assumptions of OLS regression.

Specifically, when heteroskedasticity exists, the OLS estimator remains unbiased, consistent, and asymptotically normal, but its estimated standard errors are biased and inconsistent, leading to invalid inference. This means that t-tests for individual coefficients and F-tests for overall model significance based on these standard errors may be unreliable.

Instead, alternative methods such as robust standard errors or weighted least squares should be used to correct for heteroskedasticity.

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Statement 1 : True .

Statement 2 : False .

Statement 3 : True

Here,

Elasticity is the responsiveness of quantity demanded or quantity supplied to a change in the price. There are five categories of elasticities:

1. Perfectly elastic: Quantity changes even without a change in price. Curve is a horizontal line.

2. Elastic: Change in price is smaller than a change in quantity. Curve has a smoother slope.

3. Unit elastic: Change in price causes a proportionate change in quantity. Curve is a rectangular hyperbola.

4. Inelastic: Change in price causes a smaller change in quantity. Curve is a steep slope.

5. Perfectly inelastic: Change in price causes no change in quantity. Curve is a vertical line.

Relationship between curves:

a. Curve MM is more elastic between points A and C than curve NN is between points A and D: TRUE

b. Between points A and B, curve LL is unit elastic: FALSE

c. Between points A and D, curve NN is inelastic: TRUE

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Complete question:

Using the graph, complete the table that follows by indicating whether each statement is true or false. (Hint: You can display the coordinates by clicking on the points.)

a. Curve MM is more elastic between points A and C than curve NN is between points A and D.

b. Between points A and B, curve LL is unit elastic.

c. Between points A and D, curve NN is inelastic.

Answer: \(\dfrac{1}{3}\)

Step-by-step explanation:

Given: Jim and Renee will play one game of Rock, Paper, Scissors. In this game, each will select and show a hand sign for one of the three items.

Rock beats Scissors, Scissors beat Paper, and Paper beats Rock.

We assume that both Jim and Renee have an equal chance of choosing any one of the hand signs.

Since, there are 3 possibilities, either Jim win or Renee or its a tie.

So, the probability that Jim will win: \(\dfrac{\text{Outcomes for Jim to win}}{\text{Total outcomes}}\)

\(=\dfrac{1}{3}\)

Hence, the required probability is \(\dfrac{1}{3}\) .

Answer:

B

Step-by-step explanation:

Answer:

x^2-2x-9

Step-by-step explanation:

Answer: 5 more students need to sign up.

The point (- 1, 2) lies on the new graph.

A transformation that occurs when a figure is moved from one location to another location without changing its size or shape is called translation.

Given that;

The graph of f(x) = |x| has been translated left 2 units and up 1 unit.

Now, The function is,

⇒ f (x) = |x|

After translated 2 unit left we get;

⇒ f (x) = |x + 2|

And, After translated 1 unit down we get;

⇒ f (x) = |x + 2| + 1

Now, We can check all the given points as;

For point (- 1, 2);

Put x = -1 , f (x) = 2;

⇒ f (x) = |x + 2| + 1

⇒ 2 = |- 1 + 2| + 1

⇒ 2 = 1 + 1

⇒ 2 = 2

Thus, The point (- 1, 2) lies on the new graph.

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The probability of selecting a random sample of 100 marbles that has a mean diameter greater than 0.851 cm is approximately 15.87%.

To find the probability of selecting a sample of 100 marbles with a mean diameter greater than 0.851 cm, first, we'll compute the standard error (SE) of the sample mean:

In this case,
Mean diameter (μ) = 0.850 cm
Standard deviation (σ) = 0.010 cm
Sample size (n) = 100 marbles
Target mean diameter (x) = 0.851 cm

SE = σ / √n = 0.010 cm / √100 = 0.001 cm

Next, we'll calculate the z-score:

z = (x - μ) / SE = (0.851 - 0.850) / 0.001 = 1

Now, we need to find the probability (P) that corresponds to this z-score. You can use a z-table, a calculator, or statistical software to find the probability. In this case, P(Z > 1) ≈ 0.1587.

So, selecting a random sample of 100 marbles having a mean diameter greater than 0.851 cm has a probability of approximately 15.87%.

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The total change in the consumed quantity of x₁ as per given price and income  is equal to 213.

x₁ = (21/7)P₁

x₂ = (51/7)P₂

P₁ = 10

P₂ = 5

P₁' = 81

To calculate the total change in the quantity consumed of x₁ when the price of P₁ changes from P₁ to P₁',

The difference between the quantities consumed at the original price and the new price.

Let's calculate the quantity consumed at the original price,

x₁ orig

= (21/7)P₁

= (21/7) × 10

= 30

x₂ orig

= (51/7)P₂

= (51/7) × 5

= 36.4286 (approximated to 4 decimal places)

Now, let's calculate the quantity consumed at the new price,

x₁ new

= (21/7)P1'

= (21/7) × 81

= 243

x₂ new

= (51/7)P2

= (51/7) × 5

= 36.4286

The total change in the quantity consumed of x₁ can be calculated as the difference between the new quantity and the original quantity,

Change in x₁

= x₁ new - x₁ original

= 243 - 30

= 213

Therefore, the total change in the quantity consumed of x₁ is 213.

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The above question is incomplete, the complete question is:

The optimal amount of x1, x2, P1, P2 and income are given by the following:

x1= 21/ 7p1 x2= 51 / 7p2

The original prices are: P1=10 P2=5 The original income is: I =4189 The new price of P1 is the following: P1'=81 Assume that the price of x1 has changed from P1 to P1'. What is the total change in the quantity consumed of x1?

Please answer step by step

Answer:

Angles A and C are alternate exterior angles.

Answers:

====================================

Explanation:

For n ≥ 459, Algorithm A is better than Algorithm B when B uses n√n operations.

To determine the value of n₀ for which Algorithm A is better than Algorithm B when B uses n√n operations, we need to find the point at which the number of operations for Algorithm A is less than the number of operations for Algorithm B.

Algorithm A: 10n log n operations

Algorithm B: n√n operations

Let's set up the inequality and solve for n₀:

10n log n < n√n

Dividing both sides by n gives:

10 log n < √n

Squaring both sides to eliminate the square root gives:

100 (log n)² < n

To solve this inequality, we can use trial and error or graph the functions to find the intersection point. After calculating, we find that n₀ is approximately 459. Therefore, For n ≥ 459, Algorithm A is better than Algorithm B when B uses n√n operations.

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R-1.3: For \($n \geq 14$\), Algorithm A is better than Algorithm B when B uses \($n^2$\) operations.

R-1.4: Algorithm A is always better than Algorithm B when B uses \($n\sqrt{n}$\) operations.

R-1.3:

Algorithm A: \($10n \log n$\) operations

Algorithm B: \($n^2$\) operations

We want to determine the value of \($n_0$\) such that Algorithm A is better than Algorithm B for \($n \geq n_0$\).

We need to compare the growth rates:

\($10n \log n < n^2$\)

\($10 \log n < n$\)

\($\log n < \frac{n}{10}$\)

To solve this inequality, we can plot the graphs of \($y = \log n$\) and \($y = \frac{n}{10}$\) and find the point of intersection.

By observing the graphs, we can see that the two functions intersect at \($n \approx 14$\). Therefore, for \($n \geq 14$\), Algorithm A is better than Algorithm B.

R-1.4:

Algorithm A: \($10n \log n$\) operations

Algorithm B: \($n\sqrt{n}$\) operations

We want to determine the value of \($n_0$\) such that Algorithm A is better than Algorithm B for \($n \geq n_0$\).

We need to compare the growth rates:

\($10n \log n < n\sqrt{n}$\)

\($10 \log n < \sqrt{n}$\)

\($(10 \log n)^2 < n$\)

\($100 \log^2 n < n$\)

To solve this inequality, we can use numerical methods or make an approximation. By observing the inequality, we can see that the left-hand side \($(100 \log^2 n)$\) grows much slower than the right-hand side \($(n)$\) for large values of \($n$\).

Therefore, we can approximate that:

\($100 \log^2 n < n$\)

For large values of \($n$\), the left-hand side is negligible compared to the right-hand side. Hence, for \($n \geq 1$\), Algorithm A is better than Algorithm B when B uses \($n\sqrt{n}$\) operations.

So, for R-1.4, the value of \($n_0$\) is 1, meaning Algorithm A is always better than Algorithm B when B uses \($n\sqrt{n}$\) operations.

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Answer:

Identify the output values. If each input value leads to only one output value, classify the relationship as a function. If any input value leads to two or more outputs, do not classify the relationship as a function.

Step-by-step explanation:

The probability of the sets are solved and

a) n(P U Q) = 85%

b) n(P ∩ Q) = 20%

c) n(only P) = 35%

d) n(only Q) = 30%

Given data ,

P and are the subsets of universal set U

And , n (p) = 55% n (Q) = 50% and n(PUO)complement = 15%

Now , we'll use the formula for the union and intersection of sets:

n(P U Q) = n(P) + n(Q) - n(P ∩ Q)

n(P ∩ Q) = n(P) + n(Q) - n(P U Q)

n(only P) = n(P) - n(P ∩ Q)

n(only Q) = n(Q) - n(P ∩ Q)

We're given that:

n(P) = 55%

n(Q) = 50%

n(P U Q)' = 15%

To find n(P U Q), we'll use the complement rule:

n(P U Q) = 100% - n(P U Q)'

n(P U Q) = 100% - 15%

n(P U Q) = 85%

Now we can substitute the values into the formulas above:

(i)

n(P U Q) = n(P) + n(Q) - n(P ∩ Q)

n(P ∩ Q) = n(P) + n(Q) - n(P U Q)

n(P ∩ Q) = 55% + 50% - 85%

n(P ∩ Q) = 20%

(ii)

n(P ∩ Q) = 20%

(iii) n(only P) = n(P) - n(P ∩ Q)

n(only P) = 55% - 20%

n(only P) = 35%

(iv)

n(only Q) = n(Q) - n(P ∩ Q)

n(only Q) = 50% - 20%

n(only Q) = 30%

Hence , the probability is solved

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Using trigonometric identity, cos(A-B) is:

\(cos (A-B) = \frac{2\sqrt{8}\ + \sqrt{5}}{9}\)

Trigonometry deals with the relationship between the ratios of the sides of a right-angled triangle with its angles.

If sin A = 1/3 and A terminates in Quadrant 1. All trigonometric functions in Quadrant 1  are positive

sin A = 1/3 (sine = opposite/hypotenuse)

adjacent = √(3² - 1²)

               = √8 units

cosine = adjacent/hypotenuse. Thus,

\(cos A = \frac{\sqrt{8} }{3}\)

If cos B = 2/3 and B terminates in Quadrant 4.

opposite = √(3² - 2²)

                = √5

In  Quadrant 4, sine is negative. Thus:

\(sin B = \frac{\sqrt{5} }{3}\)

We have:

cos(A-B) = cosA CosB + sinA sinB

\(cos (A-B) = \frac{\sqrt{8} }{3} * \frac{2}{3} + \left \frac{1}{3} * \frac{\sqrt{5} }{3}\)

\(cos (A-B) = \frac{2\sqrt{8} }{9} + \left\frac{\sqrt{5} }{9}\)

\(cos (A-B) = \frac{2\sqrt{8}\ + \sqrt{5}}{9}\)

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Answer:

Have a Nice Best Day : )

the answer isn't a whole number it is a fraction and the fraction is 1/64 your welcome

The probability of obtaining a sample mean between 4.1 and 4.11 in a random sample of size 511 is 0.

To calculate the probability that a random sample of size 511, selected with replacement, will yield a sample mean between 4.1 and 4.11 in a discrete uniform population with x = 2.4, we can use the properties of the sample mean and the given population.

In a discrete uniform population, all values are equally likely. Since the mean of the population is x = 2.4, it implies that each value in the population is 2.4.

The sample mean is calculated by summing all selected values and dividing by the sample size. In this case, the sample size is 511.

To find the probability, we need to calculate the cumulative distribution function (CDF) for the sample mean falling between 4.1 and 4.11.

Let's denote X as the value of each individual in the population. Since X is uniformly distributed, P(X = 2.4) = 1.

The sample mean, denoted as M, is given by M = (X1 + X2 + ... + X511) / 511.

To find the probability P(4.1 < M < 4.11), we need to calculate P(M < 4.11) - P(M < 4.1).

P(M < 4.11) = P((X1 + X2 + ... + X511) / 511 < 4.11)
           = P(X1 + X2 + ... + X511 < 4.11 * 511)

Similarly,
P(M < 4.1) = P(X1 + X2 + ... + X511 < 4.1 * 511)

Since each value of X is 2.4, we can rewrite the probabilities as:

P(M < 4.11) = P((2.4 + 2.4 + ... + 2.4) < 4.11 * 511)
           = P(2.4 * 511 < 4.11 * 511)

Similarly,
P(M < 4.1) = P(2.4 * 511 < 4.1 * 511)

Now, we can calculate the probabilities:

P(M < 4.11) = P(1224.4 < 2099.71) = 1 (since 1224.4 < 2099.71)
P(M < 4.1) = P(1224.4 < 2104.1) = 1 (since 1224.4 < 2104.1)

Finally, we can calculate the probability of the sample mean falling between 4.1 and 4.11:

P(4.1 < M < 4.11) = P(M < 4.11) - P(M < 4.1)
                 = 1 - 1
                 = 0

Therefore, the probability that a random sample of size 511, selected with replacement, will yield a sample mean between 4.1 and 4.11 in the given discrete uniform population is 0.

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Given:

The value of x = 2.

Solution:

F ( x ) = 2x⁴ - x³ + 5x - 9

=> 2 ( 2 )⁴ - ( 2 )³ + 5 × 2 - 9

=> 2 × 16 - 8 + 10 - 9

=> 32 - 8 + 10 - 9

=> 24 + 1

=> 25

A. 25

The given expression has to be expanded and evaluated. The given expression is FA1 for\(L1 FA1 a a 1+ FA2 for L2 FA2 3 a CO b b b b b a a 2 a 4 OS + b.\)

\(FA3 for L1 + L2\):

It is given that FA1 for \(L1 = a + b, FA1 a a 1 = 2a\), FA2 for\(L2 = 3a + 4b, FA2 3 a CO b b b b b a a 2 a 4 OS = 3a + 5b\). Substituting the given values in the expression, we have:

\(FA3 for L1 + L2 = (FA1 for L1) (FA1 a a 1) + (FA2 for L2) (FA2 3 a CO b b b b b a a 2 a 4 OS) + b\)
\(FA3 for L1 + L2 = (a + b) (2a) + (3a + 4b) (3a + 5b) + b\)
\(FA3 for L1 + L2 = 2a2 + 3a2 + 15ab + 12b2 + 2ab + b\)
\(FA3 for L1 + L2 = 5a2 + 17ab + 12b2 + b\)
\(FA3 for L1 + L2 is 5a2 + 17ab + 12b2 + b.\)
FA1 for L1:

It is given that FA1 for\(L1 = a + b.\)

FA1 for L1 is a + b.

Answer:

FA3 for L1 + L2 is 5a² + 17ab + 12b² + b and FA1 for L1 is a + b.

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Answer:

126 units!

Step-by-step explanation:

I hope this helped!! c:

Answer:

The answer is

Step-by-step explanation:

To find the GCF of

\( {2}^{4} \times {3}^{2} \: \: \: \: and \: \: {2}^{5} \times {3}^{6} \)

Find the prime numbers with the lowest exponents and multiply them

From the question the prime numbers with the lowest exponents are

2⁴ and 3²

So the GCF in the question is

2⁴ × 3²

Hope this helps you