please help me i’m debating with two answers but i’m not sure. also please explain thanks

A pencil consists of a cylindrical body (10 cm long, radius 0.3 cm) with a cone-shaped eraser (1 cm slant height) and a hemisphere-shaped eraser.

A pencil consists of three main parts: a cylindrical body, a cone-shaped eraser, and a hemisphere-shaped eraser. Let's break down the dimensions of each part:

Cylindrical Body:

Length: 10 cm

Radius: 0.3 cm

Cone-shaped Eraser:

Slant height: 1 cm (assumed height of the cone)

Hemisphere-shaped Eraser:

Since the dimensions of the hemisphere-shaped eraser are not specified in detail, we'll assume a few things:

Let's assume that the hemisphere is attached to the cone in such a way that the flat surface of the hemisphere is aligned with the circular base of the cone.

We'll assume that the radius of the hemisphere is the same as the radius of the cylindrical body, which is 0.3 cm.

Please note that the actual dimensions of a pencil can vary, and these assumptions are made for the purpose of explanation.

It's worth mentioning that the cylindrical body of the pencil is the main part used for writing, while the cone-shaped and hemisphere-shaped erasers are located at the opposite end of the pencil, typically used for erasing mistakes.

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Answer:

The segment that connects the midpoints of the legs of a trapezoid is called the median of the trapezoid.

Step-by-step explanation:

One radian is equal to approximately 57.2958 degrees. Radians and degrees are two units of measurement for angles.

Radians are based on the radius of a circle, while degrees are based on dividing a circle into 360 equal parts. One radian is defined as the angle formed at the center of a circle when the arc on the circumference is equal in length to the radius of the circle. This angle is equal to approximately 57.2958 degrees. One radian is equal to approximately 57.2958 degrees. Radians and degrees are two units of measurement for angles. To convert from radians to degrees, you can multiply the angle in radians by approximately 57.2958. Conversely, to convert from degrees to radians, you can multiply the angle in degrees by approximately 0.0174533.

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Answer:

The Answer should be 6%

Step-by-step explanation:

Given,

MP =1500 and Discount =10%

So, SP = 1500 × 90% =1350

We know, profit = \(\frac{sp-cp}{cp}\) × 100%

               =>20 =\(\frac{1350-cp}{cp}\) × 100

               =>CP = 1125

Now, if profit =12%

then, SP' = 1260 ;(using previous equation for profit and CP=1125)

So, SP' = MP × (100 -Discount )

∴ Discount = 16% ;(SP' = 1260 and MP = 1500)

So, Discount should be increased = 16% - 10% = 6%

Pls mark this as the brainliest

Answer:

C. 17 yards

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Equality Properties

Trigonometry

Step-by-step explanation:

Step 1: Identify Variables

Leg a = 15

Leg b = 8

Hypotenuse c = c

Step 2: Solve for c

To draw the graph of the function f(x) = 2 - x^2 using a graphing calculator, follow these steps: Turn on your graphing calculator and enter the function f(x) = 2 - x^2 into the calculator's equation editor.

Set the viewing window of the calculator to a suitable range, such as -5 ≤ x ≤ 5 and -5 ≤ y ≤ 5, to capture the shape of the graph. Press the "Graph" button to plot the graph of f(x). The graph of f(x) = 2 - x^2 should appear on the screen as a downward-opening parabola centered at the point (0, 2). You can use the arrow keys on the calculator to move around and explore different parts of the graph.

The graph of f(x) = 2 - x^2 will show a symmetric curve that opens downwards. The highest point on the graph will be at (0, 2), and the curve will extend infinitely in both the positive and negative x-directions.

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Answer:

6

Step-by-step explanation:

delta math

The required measure of the other leg will be 6 cm in the given right triangle.

Pythagoras's theorem states that in a right-angled triangle, the square of one side is equal to the sum of the squares of the other two sides.

We have been given that one of the legs of a right triangle measures 8 cm and its hypotenuse measures 10 cm.

Let the measure of the other leg would be x cm.

According to Pythagoras's theorem,

⇒ c² = a² + b²  ....(i)

As per the given question, we have

c = 10cm, a = 8 cm and b = x

Substitute the values in the above formula, and solve for x

⇒ 10² = 8² + x²

⇒ 100 = 64 + x²

⇒  x² = 100 - 64

⇒  x² = 36

⇒  x² = 6²

⇒  x = 6

Therefore, the required measure of the other leg will be 6 cm in the given right triangle.

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Answer:

9:21

Step-by-step explanation:

Answer:

9:12

Step-by-step explanation:

There are 9 purple flowers, 7 pink flowers, and 5 white flowers.

If you want the ratio of purple to the total, all you have to do is add the pink and white flowers together.

So the answer would be...

9:12

The work done by f in moving a particle once counterclockwise around the given curve is -15π.

The problem requires us to calculate the work done by the vector field f along a closed curve C, which is a circle centered at (5,5) with a radius of 5. To do this, we can use the line integral of f along C, which is given by:

∫C f · dr = ∫C (f(x,y) · T) ds

where T is the unit tangent vector to C and ds is the arc length element along C.

To parameterize the curve C, we can use the parametric equations:

x = 5 + 5cos(t)

y = 5 + 5sin(t)

with 0 ≤ t ≤ 2π. Then, the unit tangent vector T is given by:

T = (-sin(t), cos(t))

and the arc length element ds is given by:

ds = √(x'(t)² + y'(t)²) dt = 5 dt

Using these expressions, we can compute the line integral as:

∫C f · dr = ∫C [(x-3y)i + (3x-y)j] · (-sin(t)i + cos(t)j) 5 dt

After some algebraic manipulation, we obtain:

∫C f · dr = -15π

Therefore, the total work done by f in moving the particle once around the given curve counterclockwise is -15π.

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The work done by f in moving a particle once counterclockwise around the given curve is zero.

To find the work done by a vector field f in moving a particle along a curve C, we use the line integral formula. The line integral of a vector field f along a curve C is given by the formula ∫C f · dr, where dr is the differential of the position vector r(t) of the curve C. In this case, the vector field is f = (x - 3y)i + (3x - y)j and the curve is the circle (x - 5)² + (y - 5)² = 25 centered at (5,5) with radius 5. To evaluate the line integral, we need to parameterize the curve. Since the curve is a circle, we can use the parametrization r(t) = 5cos(t)i + 5sin(t)j, where t ranges from 0 to 2π. Then, dr = -5sin(t)dt i + 5cos(t)dt j.

Evaluating the line integral, we get ∫C f · dr = ∫0^2π f(r(t)) · dr/dt dt = ∫0^2π (-15sin²(t) + 15cos²(t))dt = 0. Therefore, the work done by f in moving a particle once counterclockwise around the given curve is zero.

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Answer:

f(x) = 7/6

Step-by-step explanation:

First off, hello! This is my explanation to the provided answer,

You can use the slope formula, (or simply graph the points), y2 - y2 / x2 - x1.

This would give you: 1 - 8 / -2 - 4, meaning that you would get the answer: 7/6 as the slope.

Hope this helps, if you have any more questions please ask.

Answer:

x=3

Step-by-step explanation:

The equation is written in the form ax2+bx+c. As you can see, a=1, b=-6 and c=2. The axis of symmetry is worked out by x=−b2a.

−(−6)2(1) = 62=3

Substituted this value of x back into the equation to find the y coordinate.

y=(3)2−6(3)+2

y=9−18+2

y=−7q

So the vertex of the line is at (3,-7)

Answer:

m=33.7g

Step-by-step explanation:

See attachment

The minimum value of the objective function subject to the given constraints is 48 and it occurs at (6,0).

The given problem is:

min 8x₁ + 6x₂ subject to4x₁ + 2x₂ ≥ 20−6x₁ + 4x₂ ≤ 12x₁ + x₂ ≥ 6x₁ + x₂ ≥ 0

The feasible region is as follows:

Firstly, plot the following lines:4x₁ + 2x₂ = 20-6x₁ + 4x₂ = 12x₁ + x₂ = 6x₁ + x₂ = 0On plotting, the following graph is obtained:

Now, let's check each option one by one:

a. 4x₁ + 2x₂ ≥ 20

The feasible region is the region above the line 4x₁ + 2x₂ = 20.

b. −6x₁ + 4x₂ ≤ 12

The feasible region is the region below the line −6x₁ + 4x₂ = 12.c. x₁ + x₂ ≥ 6

The feasible region is the region above the line x₁ + x₂ = 6.d. x₁ + x₂ ≥ 0

The feasible region is the region above the x-axis.

Now, check the point of intersection of the lines.

They are:(10,0),(2,4),(6,0)The point (2,4) is not in the feasible region as it lies outside it.

Therefore, we reject this point.

The other two points, (10,0) and (6,0) are in the feasible region.

Now, check the values of the objective function at these two points.

Objective function value at (10,0): 80

Objective function value at (6,0): 48

Therefore, the minimum value of the objective function subject to the given constraints is 48 and it occurs at (6,0).

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In a group G of order 3n, where n is a positive integer not divisible by 3, if x and y are elements of order 3, it can be proven that y is conjugate to either x or x⁻¹. This result highlights the relationship between elements of order 3 in such groups.

To prove that y is conjugate to either x or x⁻¹, we need to consider the properties of groups of order 3n and elements of order 3.

First, since the order of G is 3n, by Lagrange's theorem, the order of any element in G must divide the order of the group. Therefore, the orders of x and y must be divisors of 3.

Since x has an order of 3, it means that x generates a cyclic subgroup of order 3. Similarly, y also has an order of 3 and generates another cyclic subgroup of order 3 in G.

Now, if x and y are elements of the same cyclic subgroup, then they are conjugate to each other. This is because within a cyclic subgroup, every element is conjugate to any other element. Therefore, if x and y are in the same cyclic subgroup, y is conjugate to x.

On the other hand, if x and y are in different cyclic subgroups, we can consider the cosets formed by these subgroups. Since the order of G is 3n and each subgroup has an order of 3, there are exactly n cosets. This means that each element in one subgroup is conjugate to exactly one element in the other subgroup. Therefore, if x and y are in different cyclic subgroups, y is conjugate to x⁻¹.

Hence, we have shown that in a group G of order 3n, if x and y are elements of order 3, y is conjugate to either x or x⁻¹.

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We can order them in increasing x-coordinate as:

(0, 0), (0.585, 6.415), and (5.748, 1.252)

To find the critical points of the predator/prey model, we need to find the values of x and y that make both x' and y' equal to zero.

From the given equations, we have:

x' = 7x - x² - xy = 0

y' = -5y + xy = 0

Factoring x out of the first equation, we get:

So, either x = 0 or 7 - x - y = 0.

If x = 0, then the second equation simplifies to y' = -5y = 0, which has a critical point at y = 0.

If 7 - x - y = 0, then we can solve for y to get:

y = 7 - x

y' = -5y + xy = -5(7 - x) + x(7 - x) = 0

Simplifying, we get:

6x² - 49x + 35 = 0

x = (49 ± sqrt(49² - 4(6)(35))) / (2(6)) ≈ 0.585 or x ≈ 5.748

Substituting these values into y = 7 - x, we get:

y ≈ 6.415 or y ≈ 1.252

(0, 0), (0.585, 6.415), and (5.748, 1.252)

We can order them in increasing x-coordinate as:

(0, 0), (0.585, 6.415), and (5.748, 1.252)

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Answer:

1/2 + 3/4 + 5/8

4/8 + 6/8 + 5/8 = 15/8 or 1 7/8 cups

Step-by-step explanation:

probably right dunno

This is one batch right? if so shud be right

When swerving, there are a number of factors that come into play, including traction, lean, load triangle, and being upright. Swerving in a straight line can be relatively easy, as the rider only needs to make minor adjustments to maintain balance.

When comparing swerving in a straight line to swerving in a curve, the key differences involve traction and maintaining an appropriate lean angle.
Swerving in a curve requires more traction than swerving in a straight line. Traction is essential for maintaining control of your vehicle, especially when navigating curves. As you swerve in a curve, your tires need to have a good grip on the road surface to prevent skidding or losing control.
Additionally, managing lean angles is more critical when swerving in a curve. To maintain balance and control, you must avoid leaning too much, as it can cause the vehicle to tip over or slide out. In a curve, the lean angle needs to be adjusted appropriately to match the curve's radius, while also considering your speed and road conditions.
In summary, swerving in a curve requires more traction and careful management of lean angles compared to swerving in a straight line. The load triangle and keeping the vehicle upright are important, but they are not the primary factors that make swerving in a curve more challenging than swerving in a straight line.

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To construct a stem and leaf plot, you first need to separate each data point into a stem and a leaf. The stem represents the leading digit(s) of the data point, while the leaf represents the trailing digit(s).

Once you have organized the data in this way, you can create the plot. The stems are listed vertically, and the leaves are placed horizontally next to their corresponding stems. Make sure to arrange the leaves in ascending order.

Regarding how the stem and leaf plot suggests the sample mean and median will compare, we can look at the distribution of the data. If the leaves are evenly distributed across the stems, it suggests a symmetrical distribution. In this case, the sample mean and median will be similar.

However, if the leaves are concentrated in certain stems, it suggests an asymmetrical distribution. In this scenario, the sample mean and median may differ. The median tends to be less affected by extreme values, while the mean can be influenced by outliers.

Therefore, by examining the stem and leaf plot, you can get a sense of whether the sample mean and median will be similar or different based on the distribution of the data.

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The probability of event A and event B is 6.

Given that, P(A)=6, P(B)=20 and P(A∩B)=6.

P(A/B) Formula is given as, P(A/B) = P(A∩B) / P(B), where, P(A) is probability of event A happening, P(B) is the probability of event B.

P(A/B) = P(A∩B) / P(B) = 6/20 = 3/10

We know that, P(A and B)=P(A/B)×P(B)

= 3/10 × 20

= 3×2

= 6

Therefore, the probability of event A and event B is 6.

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Answer:

967.6

Step-by-step explanation:

967.6

967.12 in

Step-by-step explanation:

the formula for the area (surface area) of a cylinder is: A=2πrh+2πr2

to solve we need to determine the values

R= radius = half the diameter = 14/2 =7

D= diameter =14inches

H= height= 15 inches

plug in

A=2πrh+2πr2 = A=2π(\(\frac{d}{2}\))h+2π(\(\frac{d}{2}\))^2

= 2\(\pi\)(\(\frac{14}{2}\))(15) + 2\(\pi\)(\(\frac{14}{2}\))^2

= 2\(\pi\)(7)(15) + 2\(\pi\)(7)^2

=\(\pi\)((2x7x15)+(2x7^2))

=\(\pi\)(210+98)

=\(308\pi\)

=967.12 in

Answer: 5/3

Step-by-step explanation:

The scale factor is the same as the ratio of the length of a side of the image to the length of the corresponding side in the preimage.

We know that N'Q'=10 and NQ=6, so the scale factor is 10/6 = 5/3.

Answer:

the answer is 8 hope it helped <3

Step-by-step explanation:

Answer: 8,

I apologize if I'm wrong. Good luck!

Step-by-step explanation:

First, you need to do parenthesis, 1-0.80=0.2

Then, you do exponents, 0.2^2=0.04

Last, you do 200x0.04=8

The mean-square end-to-end distance for the fractal line is ⟨R2⟩ = b².L^(1-D).

The mean-square end-to-end distance for the fractal line is as follows.⟨R2⟩ = ⟨(R(u)- R(v))^2⟩ for u = 0 and v = L where L is the length of the line.⟨R2⟩ = b²/L^2.D.L = b².L^(1-D).

Thus, the mean-square end-to-end distance for the fractal line is ⟨R2⟩ = b².L^(1-D).

The radius of gyration Rg is defined as follows.

Rg² = (1/N)∑_(i=1)^N▒〖(R(i)-R(mean))〗²where N is the number of monomers in the fractal line and R(i) is the position vector of the ith monomer.

R(mean) is the mean position vector of all monomers.

Since the fractal dimension is D, the number of monomers varies with the length of the line as follows.N ~ L^(D).

Therefore, the radius of gyration for the fractal line is Rg² = (1/L^D)∫_0^L▒〖(b/v^(1-D))^2 v dv〗 = b²/L^2.D(1-D). Thus, Rg² = b².L^(2-D).

The ratio R²/Rg² is given by R²/Rg² = L^(D-2).

When D = 1, R²/Rg² = 1/L. When D = 1.7, R²/Rg² = 1/L^0.7. When D = 2, R²/Rg² = 1/L.

This provides information on mean-square end-to-end distance and radius of gyration for fractal line with a given fractal dimension.

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Answer:(2x+3)(2x+3)

Step-by-step explanation:

Question will be like this Factorize the following polynomial.

4x\({2}\) +12x +9

4x\(2\) +6x+6x+9

⇒2x(2x+3)+3(2x+3)

⇒(2x+3)(2x+3)

Answer:

1- -5, 7

2- 5,12

3- -5,0

4- 5,-7

Step-by-step explanation:

Answer:

its C

Step-by-step explanation:

-30,6

:)

Answer:

bro just look on a caculater

Step-by-step explanation:

1087658.22

With the usage of isometric dot paper, we can sketch as per the attached image.

A three-dimensional solid object called a prism has two identical ends. It consists of equal cross-sections, flat faces, and identical bases. Without bases, the prism's faces are parallelograms or rectangles.

The triangular prism has 5 faces and 6 vertices.

Now given the prism is 2 units high, with bases that are right triangles with legs 3 units and 4 units long.

The steps will be as follows,

⇒ Let's make the corner of the solid. Draw 2 units down, 4 units to the right, and 5 units to the left. And draw the triangle.

⇒For the vertical edges, draw segments 2 units down from each vertex. For the hidden edge, join the corresponding vertices using a dashed line.

And that's how we can sketch prism on isometric dot paper.

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Answer: Jas is 9, and Sandeep is 11.

Step-by-step explanation: 9 + 11 = 20

Answer:

x = 0.793701

Step-by-step explanation:

take the cube root : x = (1/2)(1/3)