Please help me, I will give brainliest if possible!
Pythagoras
1. if the radius of the smaller circle is 3, find its area
2. Find the area of the yellow ring
3. Find the area of the white ring

The next three terms of the sequence are 111, 131, and 151.

(i) To find the next three terms of the sequence 2, 8, 16, 26, 38, ..., we can use the difference method:

First difference: 6, 8, 10, 12, ...

Second difference: 2, 2, 2, ...

Since the second difference is constant, we know that the sequence is quadratic. We can find the quadratic formula by using the first three terms of the sequence:

a + b + c = 2

4a + 2b + c = 8

16a + 4b + c = 16

Solving these equations gives us a = 1, b = 1, and c = 0. Therefore, the quadratic formula for the sequence is:

f(n) = n^2 + n

Using this formula, we can find the next three terms:

f(6) = 6^2 + 6 = 42

f(7) = 7^2 + 7 = 56

f(8) = 8^2 + 8 = 72

So the next three terms of the sequence are 42, 56, and 72.

(ii) To find the next three terms of the sequence 11, 7, 3, -1, -5, ..., we can use the difference method:

First difference: -4, -4, -4, ...

Second difference: 0, 0, 0, ...

Since the second difference is zero, we know that the sequence is linear. We can find the linear formula by using the first two terms of the sequence:

a + b = 11

a + 2b = 7

Solving these equations gives us a = -9 and b = 20. Therefore, the linear formula for the sequence is:

f(n) = -9 + 20n

Using this formula, we can find the next three terms:

f(6) = -9 + 20(6) = 111

f(7) = -9 + 20(7) = 131

f(8) = -9 + 20(8) = 151

So the next three terms of the sequence are 111, 131, and 151.

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The probability that a randomly selected student scores more than 82% on the physics test, we can use the standard normal distribution and the given mean and standard deviation.

The z-score formula is given by z = (x - μ) / σ, where z represents the z-score, x is the observed value, μ is the mean, and σ is the standard deviation. In this case, the observed value is 82%, the mean is 75%, and the standard deviation is 6.5%. Plugging these values into the formula, we calculate the z-score as z = (0.82 - 0.75) / 0.065 = 1.0769.

Next, we need to find the area to the left of the z-score in the standard normal distribution table or using a calculator. The area to the left of 1.0769 corresponds to the probability of scoring less than 82%. Let's assume this area is P(z < 1.0769).

The probability of scoring more than 82%, we subtract P(z < 1.0769) from 1: P(z > 1.0769) = 1 - P(z < 1.0769).

Using a standard normal table or a calculator, we can find P(z < 1.0769) to determine the probability.

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The prime factorization of the number 21 is:

21 = 3*7

We want to write the prime factorization of 21.

To do so, we just need to divide the number by prime numbers.

The first prime number we can try is 2, if we divide by 2 we get:

21/2 = 10.5

This is not an integer, so 2 is not a factor.

The next one is 3:

21/3 = 7

Now we can rewrite:

21 = 3*7

Where 3 and 7 are prime numbers, so that is the prime factorization.

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Answer:

It's 13

Step-by-step explanation:

You can use the Pythagorean theorem:

(-3)² + 2² = ?²

9 + 4 = ?²

13 = ?²

? = √13

Answer:

Distance =

\( \sqrt{ {( - 3 - 0)}^{2} + {(2 - 0)}^{2} } \)

\( \sqrt{9 + 4} \)

\(13\)

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Answer:

Step-by-step explanation:

a. Associative property

b. Identity property

c. Commutative property

d. Properties of Zero

e. Properties of Zero

f. Associative property

The samples of size n = 2 that can be drawn from this population is 28

From the question, we have the following parameters that can be used in our computation:

Population, N = 8

Sample, n = 2

The samples of size n = 2 that can be drawn from this population is calculated as

Sample = N!/(n! * (N - n)!)

substitute the known values in the above equation, so, we have the following representation

Sample = 8!/(2! * 6!)

Evaluate

Sample = 28

Hence, the number of samples is 28

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Complete question

A finite population consists of 8 elements.

10,10,10,10,10,12,18,40

How many samples of size n = 2 can be drawn this population?

The probability is 0.9772. The average age of professors at a certain university is normally distributed with an average of 45.0 years and a standard deviation of 6.0 years.

If 16 professors are chosen at random for a committee, find the probability that the average age of those professors is greater than 42.0 years. We are required to find the probability that the average age of the 16 professors is greater than 42 years. Let us consider the mean of sample means as mu_x = 45 years. The standard error of the mean can be calculated as;  standard error = standard deviation/sqrt(n)`where n = sample size.

Standard error = 6.0/sqrt(16) = 1.5. Therefore, z-score is calculated as; z-score = (sample mean - population mean)/standard error = (42-45)/1.5 = -2. Now, the probability of Z being less than -2 can be found from the z-table as P(Z < -2) = 0.0228. So, the probability that the average age of those professors is greater than 42 years is 1- P(Z < -2) = 1- 0.0228 = 0.9772.

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Answer: 7 and 8

Step-by-step explanation:

The probability of observing 182 or fewer women in the sample under H0, which is the same as P(X ≤ 182) ≈ 0.000000007. This is called the p-value.

We can use the binomial distribution to model this situation. Let X be the number of women in the sample of 404 people. Then X follows a binomial distribution with parameters n = 404 and p = 0.5, since the population is half women.

If the people were randomly chosen, then we can calculate the probability of observing 182 or fewer women in the sample as follows:

P(X ≤ 182) = Σ P(X = k) for k = 0, 1, ..., 182

Using a binomial probability table or calculator, we can find that:

P(X ≤ 182) ≈ 0.000000007

This means, that if the people were randomly chosen, the probability of observing 182 women or fewer in the sample is very small (less than 0.000001%).

Therefore, if we observe a sample with 182 women or fewer, we may suspect that the people were not randomly chosen and instead be biased against women.

To make this conclusion more rigorous, we can use statistical hypothesis testing. Let H0 be the null hypothesis that the people were randomly chosen and H1 be the alternative hypothesis that the people were biased against women.

We want to test if the observed sample with 182 women or fewer provides enough evidence to reject H0 in favor of H1.

We can use the significance level α to control the probability of making a Type I error, which is rejecting H0 when it is actually true. A common choice for α is 0.05.

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The necessary journal entries for Sew What are as follows: April 1: Record the sale of 100 bolts of upholstery fabric to Design Center on account, Record the cost of goods sold for the fabric sold to Design Center. April 15: Record the return of 3 defective bolts of fabric by Design Center, Reverse the cost of goods sold for the returned fabric. April 30: Adjust the estimated return expense based on the normal return rate.

1. On April 1, Sew What will make the following journal entry:

Accounts Receivable (Design Center) $4,000

Sales Revenue $4,000

This entry records the sale of 100 bolts of fabric to Design Center on account.

2. On April 1, Sew What will also record the cost of goods sold with the following entry:

Cost of Goods Sold $2,000

Inventory $2,000

This entry reflects the cost of the fabric sold to Design Center.

3. On April 15, Sew What will record the return of 3 defective bolts of fabric by Design Center with the following entry:

Accounts Receivable (Design Center) $600

Sales Returns and Allowances $600

This entry recognizes the return and reduces the accounts receivable from Design Center.

4. Also on April 15, Sew What will reverse the cost of goods sold for the returned fabric:

Inventory $300

Cost of Goods Sold $300

This entry removes the cost of the returned fabric from the cost of goods sold.

5. On April 30, Sew What will adjust the estimated return expense based on the normal return rate. Let's assume the normal return rate is 10% of sales ($400):

Estimated Return Expense $40

Estimated Liability for Product Returns $40

This entry reflects the estimated return expense and establishes a liability for potential future returns based on past experience.

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Answer:

The correct answer is:

b. 6

Step-by-step explanation:

We are given the graph of an exponential function.

We have to find the average rate of change for this exponential function from x = 2 to x = 4.

First of all, let us plot the point on the graph on the points x = 2 and x = 4.

Please refer to the attached diagram.

We can easily find that the value of y at x = 2 is 4.

the value of y at x = 4 is 16.

\(\therefore\) the coordinates are (2, 4) and (4, 16).

Let the points be A(2, 4) and B(4, 16)

Now, let us find the average rate of change for exponential function i.e. change in value of y divided by change in value of x from x = 2 to x = 4:

Formula:

\(\text{Average rate of change = } \dfrac{\text{Change in y coordinate}}{\text{Change in x coordinate}}\)

\(\Rightarrow \dfrac{16-4}{4-2}\\\Rightarrow \dfrac{12}{2}\\\Rightarrow 6\)

So, correct answer is option b. 6

In reliability engineering, systems can be represented in terms of components that need to function or fail for the system to function or fail.

The notation koon:G represents the number of components that need to function for the system to function, while koon:F represents the number of components that need to fail to cause system failure. The goal is to determine the value of x in different scenarios to understand the system's behavior.

(a) To find the number x such that a 2004:G structure corresponds to a xoo4:F structure, we need to consider that the total number of components is n = 4. In a 2004:G structure, all four components need to function for the system to function. Therefore, we have koon:G = 4. In an xoo4:F structure, all components except x need to fail for the system to fail. In this case, we have koon:F = n - x = 4 - x.

Equating the two expressions, we get 4 - x = 4, which implies x = 0. Therefore, a 2004:G structure corresponds to a 0400:F structure.

(b) To determine the number x such that a koon:G structure corresponds to a xoon:F structure, we have k components that need to function for the system to function. Therefore, koon:G = k. In an xoon:F structure, x components need to fail for the system to fail.

Hence, we have koon:F = x. Equating the two expressions, we get k = x. Therefore, a koon:G structure corresponds to a koon:F structure, where the number of components needed to function for the system to function is the same as the number of components needed to fail for the system to fail.

By understanding these representations, we can analyze system reliability and determine the criticality of individual components within a larger system. This information is valuable in designing robust and resilient systems, as well as identifying potential points of failure and implementing appropriate redundancy or mitigation strategies.

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Answer:

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Step-by-step explanation:

Answer:

∠ NST = 59°

Step-by-step explanation:

∠ NST and ∠ LSN form a right angle , that is

∠ NST + ∠ LSN = 90

3x - 1 + 2x - 9 = 90

5x - 10 = 90 ( add 10 to both sides )

5x = 100 ( divide both sides by 5 )

x = 20

Then

∠ NST = 3x - 1 = 3(20) - 1 = 60 - 1 = 59°

Answer:

Hey! read this and use the link twice for it to work! :) good luck :D

i posted an answer on https-:-/-/-docterrickrollmath-.-com

Step-by-step explanation:

just remove the -'s

Answer:

True

Explanation:

Niko and Carlos are studying parallelograms and trapezoids. They agree that a parallelogram is a quadrilateral with two pairs of parallel sides. ... A trapezoid has one pair of parallel sides and a parallelogram has two pairs of parallel sides. So a parallelogram is also a trapezoid.

Answer:

Trapezoids have only one pair of parallel sides; parallelograms have two pairs of parallel sides. so no

Step-by-step explanation:

The required fill-in-the-blank below as:

1.) RS ⊥ ST, RS ⊥ SQ, ∠STR ≅ ∠SQR | Given

2.) RS≅RS | Reflexive Property

3.) △RST ≅ △RSQ | AAS Triangle Congruence Property

Two triangles are said to be congruent if their corresponding sides and angles are equal.

The given in question as:

RS ⊥ ST

RS ⊥ SQ

∠STR = ∠SQR

To prove:

△RST ≅ △RSQ

1.) RS ⊥ ST, RS ⊥ SQ, ∠STR ≅ ∠SQR | Given

2.) RS≅RS | Reflexive Property

According to AAS, two triangles are congruent if the two sides and the included angle of one triangle are equal to the corresponding sides and the included angle of the other triangle.

3.) △RST ≅ △RSQ | AAS Triangle Congruence Property

Hence, △RST ≅ △RSQ

Thus, the required fill-in-the-blank above is in the solution.

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Answer:

4 red marbles and 6 blue marbles

Step-by-step explanation:

Multiply any numbers to 2 and 3 and you get another ratio.

To solve the given equation (x³ + 3x³y⁴) dx + exy³ dy = 0, we can separate the variables and integrate.

Let's rearrange the equation to isolate the variables:

(x³ + 3x³y⁴) dx = -exy³ dy

Now, we can divide both sides by (x³ + 3x³y⁴) and multiply by dx:

dx/dy = -(exy³) / (x³ + 3x³y⁴)

Next, we can separate the variables:

(x³ + 3x³y⁴) / x³ dx = -1 / (ey³) dy

Simplifying the left side:

1 + 3y⁴ dx = -1 / (ey³) dy

Now, we can integrate both sides:

∫(1 + 3y⁴) dx = -∫(1 / (ey³)) dy

Integrating the left side with respect to x:

x + y⁴ + C₁ = -∫(1 / (ey³)) dy

For the integral on the right side, we can use the substitution u = ey³, du = 3y²e⁻³ dy:

x + y⁴ + C₁ = -∫(1 / u) du

x + y⁴ + C₁ = -ln|u| + C₂

Simplifying further:

x + y⁴ + C₁ = -ln|ey³| + C₂

x + y⁴ + C₁ = -3y³ + C₂

Combining the constants:

x + y⁴ = -3y³ + C

Therefore, the general solution to the given equation is x + y⁴ = -3y³ + C, where C is an arbitrary constant.

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Answer:

Step-by-step explanation:

They give you the equation, you must substitute the x values into the equation to find the y values.

Example on top equation:

y=-5x so the y values would be

y=-5(-1)=5

y=-5(0)=0

y=-5(1)=-5

y=-5(2)=-10

Roger has enough stainless steel pipe to replace the chimney liner, with a slight surplus remaining.

To determine if Roger has enough stainless steel pipe for the chimney liner, we need to convert the given measurements to a consistent unit of measurement. Since the length of the liner required is given in feet, we need to convert the 400 inches of stainless steel pipe to feet.

There are 12 inches in a foot, so 400 inches is equal to 400/12 = 33.33 feet (approximately).

Comparing this converted length of the stainless steel pipe (33.33 feet) with the length of the liner required (33 feet), we can see that Roger does indeed have enough pipe. In fact, he has slightly more than required.

Since the length of the liner required is 33 feet and Roger has 33.33 feet of stainless steel pipe available, there is a surplus of approximately 0.33 feet (about 4 inches) of pipe. This additional length is more than enough to cover any potential measurement errors or adjustments needed during the installation process.

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a) To maximize its net savings, the company should use the new machine for 7 years.  b) The net savings during the first year of use of the machine are $405 (rounded off to the nearest dollar).  c) The net savings over the period determined in part a are $1,833.33 (rounded off to the nearest cent).

Step-by-step explanation: a) To determine for how many years should the company use the new machine to maximize its net savings, we need to find the value of x that maximizes the difference between the savings and the costs.To do this, we need to first calculate the net savings, N(x), which is given by:S'(x) - C'(x) = 175 - x² - (x² + 11x) = -2x² - 11x + 175To find the maximum value of N(x), we need to find the critical values, which are the values of x that make N'(x) = 0:N'(x) = -4x - 11 = 0 ⇒ x = -11/4The critical value x = -11/4 is not a valid solution because x represents the number of years of operation of the machine, which cannot be negative. (i.e., not use it at all).However, this answer does not make sense because the company would not introduce a new machine that it does not intend to use. Therefore, we need to examine the concavity of N(x) to see if there is a local maximum in the feasible interval.

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-> The domain is the input values

      [] What "goes into" the function

      [] The x-coordinate values

-> The range is the output values

      [] What "comes out" of the function

      [] The y-coordinate values

-> They both are values from / with regards to a function.

There are 36 '5' letter words that can be formed from the letters of "formulated" with 2 vowels, 3 consonants, and a vowel at the end.

The word "formulated" has 4 vowels and 6 consonants. If each 5 letter word must contain 2 vowels and end with a vowel, there are two options for the last letter, "e" or "a". To form a 5 letter word with 2 vowels and 3 consonants, we need to choose 2 vowels from the 4 vowels in "formulated" and 3 consonants from the 6 consonants in "formulated". The order of the chosen letters does not matter, as we will arrange them later. Thus, we can use the combination formula to find the number of ways to choose the vowels and consonants: C(4, 2) * C(6, 3) = 6 * 20 = 120. Finally, we need to arrange these 5 letters in a specific order: consonant-consonant-vowel-consonant-vowel. There are 3 choices for the first consonant, 2 choices for the second consonant (since it cannot be the same as the first), 2 choices for the vowel (either "e" or "a"), 3 choices for the third consonant (since it cannot be the same as the first or second), and 1 choice for the final vowel. Thus, the total number of 5 letter words that can be formed from the letters of "formulated" with 2 vowels, 3 consonants, and a vowel at the end is 3 * 2 * 2 * 3 * 1 = 36.

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Answer:

$11.25

Step-by-step explanation:

You give the farmer $60.00 and you subtract $48.75 = $11.25

Therefore the farmer gave you $1.00 more.

Sand is leaving at the rate of 3528 cm³/s when Sand collects in a conical pile with a radius that is always three times.

Given that,

Sand collects in a conical pile with a radius that is always three times its height as it falls from an overhead container. When the pile is 14 cm high, assume that the height of the pile is growing at a rate of 2 cm/s.

We have to find how quickly is the sand currently leaving the bin. Let V and h represent the cone's volume and height, respectively. Create an equation that connects V and h but leaves out the cone's radius.

We know that,

From given  r = 3 × h

Get an equation for the cone's volume in terms of height first.

v = 1/3 × π × r² × h

v = 1/3 × π × (3 × h)² × h

v = 1/3 × π × 9 × h³

Take derivative of both sides

d/dt { v = 3 × π × h }

dv/dt = 9 × pi × h² × dh/dt

In your problem,

dh/dt =2cm/sd

h = 14 cm

Plug in and solve for dh/dt

dv/dt = 9× π × 196 m² × 2

dv/dt = 3528 π cm³/s

Therefore, Sand is leaving at the rate of 3528 cm³/s when Sand collects in a conical pile with a radius that is always three times.

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The wholesale price of a flower arrangement was $60 and the flowers were marked up 30% then, it's retail price b is $78 and a= $18.00

Markup is the amount that will be increased in the original price of the considered thing.

Markdown is the amount that will be decreased from the original price of the considered thing. Think of "up" and "down" as increasing and decreasing prices respectively.

WE have been given that 100 percent is a 60 dollars wholesale price, 30 percent markup is a, and retail price is b.

The Wholesale price of a flower arrangement = $60

And Flowers were marked 30% above the wholesale price.

Then,

Retail price = wholesale price + 30% of wholesale price

= 60 + 30% x 60

= 60 + 18

= 78

Hence, a= $18.00

Therefore, The wholesale price of a flower arrangement was $60 and the flowers were marked up 30% then, it's retail price b is $78 and a= $18.00

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