Please help. I want to know if im doing this right or not. ​

Based on the supply graph and demand graph shown above, the price at the point of equilibrium is $ 30.

Demand refers to quantity of a commodity that the consumers are willing to, able to purchase at a given price during a given period of time. Supply refers to quantity of a commodity that the producers are willing to, able to offer for sale at a given price during a given period of time.

Demand curve slopes downward due to inverse relationship between price and quantity demanded whereas supply curve slopes upward due to direct relationship between quantity supplied and price. When both demand and supply curve intersect with each other balance is achieved. Intersection point between demand and supply curve is known as equilibrium.

At this point when prices are equal is known as equilibrium price and when quantiy demanded or supplied are equal it is known as equilibrium quantity. When we combine the given graph. Equilibrium is achieved at a point when price is equal to $ 30 and quantity is equal to 20 units.

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Answer:

The answer is "Initial value".

Step-by-step explanation:

The initial function value was its feature desired output unless the input signal is 0. It's an input valuing name, as well as the name for just a function's performance values set. In all input forces are defined as their function domain as well as the range of its program is called the output collection.

Answer:

initial value

Step-by-step explanation:

Answer:

a

Step-by-step explanation:

it the only one with an area of 17 square inches

Answer: Polygon A is 17 Square units

Answer:

\(\displaystyle \large{y\prime = 2t \sin (2t) + 2t^2 \cos (2t)}\)

Step-by-step explanation:

We are given a function:

\(\displaystyle \large{y = t^2 \sin (2t)}\)

To differentiate a function, we are going to use the product rules since there are two functions which are t^2 and sin(2t) multiplying together.

From the product rules, \(\displaystyle \large{y = f(x)g(x) \to y\prime = f\prime (x) g(x)+f(x) g\prime (x)}\)

Therefore, \(\displaystyle \large{y = t^2 \sin (2t) \to y\prime = (t^2)\prime \sin (2t) + t^2 (\sin (2t))\prime}\)

Before we start differentiating, I’d like you to look at [sin(2t)]’. A function like this, you cannot just directly derive and answer. You need to use chain rules.

We know that, \(\displaystyle \large{y = \sin (x) \to y\prime = \cos (x)}\) but what if the “x” is another function? Like sin(3x), sin(x^2) as examples. The insides are another function, can be expressed as fog(x) or gof(x) is composite function.

Basically, chain rule is a rule or formula for composite function and it’s the most common and useful as well as being always used in differentiation.

Chain Rules

\(\displaystyle \large{\frac{dy}{dx} = \frac{dy}{du} \frac{du}{dx}}\)

where u is another function in a bracket. From the formula above, it can be also written as:

\(\displaystyle \large{[f(g(x))]\prime = f(g(x))\prime \cdot g(x)\prime\)

To simply say, you differentiate the whole function first then multiply with the chain or inner derived function.

So from the function, we obtain:

\(\displaystyle \large{y\prime = 2t \sin (2t) + t^2 \cos (2t) \cdot (2t)\prime}\\ \displaystyle \large{y\prime = 2t \sin (2t) + t^2 \cos (2t) \cdot 2}\\ \displaystyle \large{y\prime = 2t \sin (2t) + 2t^2 \cos (2t)}\)

The factored form would be:

\(\displaystyle \large{y\prime = 2t ( \sin (2t) + t \cos (2t))}\)

From above, for polynomial function, to differentiate, you can do by using the power rules.

Power Rules

\(\displaystyle \large{y = ax^n \to y\prime = nax^{n-1}}\)

The axis of symmetry is at x = 1, the domain is (-∞, +∞), the y-intercept c is at 7 and x intercept is not applying .

A parabolic function is one that satisfies the formula f(x) = ax2 + bx + c and, when represented graphically in two dimensions, has the shape of a parabola. Any quadratic equation with just a second degree in x is the equation for a parabolic function.

The following characteristics define a basic parabola:

Thus, from the given graph the value are obtained as:

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The placement results provided, the student should start with Math 100.

The placement results indicate that the student has placements for Math 111, Math 100, and Math 102+. Math 111 typically corresponds to a higher-level course than Math 100, and Math 102+ implies a placement beyond Math 102.

To progress towards Math 103E, it is essential to follow the recommended course sequence. Usually, Math courses are designed to build upon previously learned concepts and skills. Starting with Math 100 would provide the foundational knowledge necessary to succeed in subsequent courses.

Therefore, the student should first start with Math 100, and upon successful completion, they can proceed to Math 103E. It is important for the student to consult with their academic advisor or the mathematics department at their institution for specific course placement and sequencing information to ensure they are following the appropriate path.

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Answer:

Depends on how many spoonfuls they use per sundae. If they use one spoonful they made 32 sundaes, if they use 2 spoonfuls they made 16 sundaes.

The value of x that makes the line containing (1,2) and (5,3) perpendicular to the line containing (x,4) and (3,0) is x = 2.

To determine the value of x such that the line containing (1,2) and (5,3) is perpendicular to the line containing (x,4) and (3,0), we need to find the slope of both lines and apply the concept of perpendicular lines.

The slope of a line can be found using the formula:

slope = (change in y) / (change in x)

For the line containing (1,2) and (5,3), the slope is:

slope1 = (3 - 2) / (5 - 1) = 1 / 4

To find the slope of the line containing (x,4) and (3,0), we use the same formula:

slope2 = (0 - 4) / (3 - x) = -4 / (3 - x)

Perpendicular lines have slopes that are negative reciprocals of each other. In other words, if the slope of one line is m, then the slope of a line perpendicular to it is -1/m.

So, we can set up the equation:

-1 / (1/4) = -4 / (3 - x)

Simplifying this equation:

-4 = -4 / (3 - x)

To remove the fraction, we can multiply both sides by (3 - x):

-4(3 - x) = -4

Expanding and simplifying:

-12 + 4x = -4

Adding 12 to both sides:

4x = 8

Dividing both sides by 4:

x = 2

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The equation of the perpendicular line is y = -1/3x

From the question, we have the following parameters that can be used in our computation:

y = 3x + 2

The equation of a line can be represented as

y = mx + c

Where

Slope = m

By comparing the equations, we have the following

m = 3

This means that the slope is 2

The slopes of perpendicular lines are opposite reciprocals

This means that the slope of the other line is -1/3

The equation of the line is then calculated as

y = mx

Where

m = -1/3

So, we have

y = -1/3x

Hence, the line has an equation of y = -1/3x

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Answer:

x = 12

Step-by-step explanation:

Answer:

Slope: 1

y-intercept: 8

Step-by-step explanation:

x, y

-8,0

0,8

Answer:3/7

Step-by-step explanation:There are total 7 days in a week. 3 days were dry so the fraction is 3/7 . The dry days over the total days of the week

Answer: 6/(6+2x) ; (-infinity, -3) U (-3, infinity)

Step-by-step explanation:

(a) This can be read as f(x) composed of g(x). Plug in the expression given for g(x) for every x value in f(x):

(6/x)/(6/x+2)

I gave the terms in the denominator the same denominator to combine the bottom two terms into one term. 6/x + 2 is equal to 6/x + 2x/x -->

(6 +2x)/x

Do the classic keep, change, flip. \(\frac{6}{x} * \frac{x}{6+2x}\)

This simplifies to: \(\frac{6}{6+2x}\)

(b) Domain is all real numbers except for what makes the denominator equal to 0.     6 + 2x = 0 when x = -3. Therefore it is all real numbers except -3.

Answer:

4.28%

Step-by-step explanation:

We Know

Last year you earned $72,400

This year you earned $75,500

What was the rate of change in your earnings since last year?

We Take

(75,500 ÷ 72,400) x 100 ≈ 104.28%

Then We Take

104.28 - 100 = 4.28%

So, the earning increased by about 4.28%.

The average price of the textbook over all seasons is $77.9625 (without the dollar sign).

What is Average?

When you add two or more numbers and divide the result by the number of numbers you added together, you get an average.

To compute the average price of the textbook over all seasons, we need to calculate the weighted average of the prices during each season, where the weights are the proportions of sales in each season.

Let P1, P2, and P3 be the average prices of the textbook during the "end of term," "start of term," and "other" periods, respectively. Let w1, w2, and w3 be the corresponding proportions of sales in each period, as given in the table. Then the weighted average price is:

Average price = w1P1 + w2P2 + w3*P3

Substituting the values from the table, we get:

Average price = 0.3076.75 + 0.4582.52 + 0.25*71.21

= 23.025 + 37.134 + 17.8025

= 77.9625

Therefore, the average price of the textbook over all seasons is $77.9625 (without the dollar sign).

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(a) The mean of the relevant distribution is 2.4 defective pistons.

(b) The standard deviation of the distribution is 1.539.

The mean of the relevant distribution is the expected number of defective pistons that we would expect to get from a sample of 80 pistons produced by this machine. The mean is calculated by multiplying the probability of a defective piston (3%) with the number of pistons in the sample (80). In this case, the mean is 2.4 defective pistons. The standard deviation of the distribution quantifies the uncertainty of our estimate. It is calculated by taking the square root of the variance, which is the expected value of the squared differences between the number of defective pistons in the sample and the mean. In this case, the standard deviation is 1.539. This means that, in theory, we would expect 68% of the samples to contain between 0.861 and 4.139 defective pistons.

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Answer:

9

Step-by-step explanation:

18/ 2= 9

ANSWER

B) 195

EXPLANATION

The related series of a sequence is the terms of the sequence separated by a + sign, so it becomes a sum:

the function in the terms of π and r will be f(r) = (1 - π)r².

The area is the entire amount of space occupied by a flat (2-D) surface or an object's form. On a sheet of paper, draw a square using a pencil. It has two dimensions. The area of a form on paper is the area that it occupies.

Given, A circle is inscribed in a square. the radius of the circle is r.

Since the circle is inscribed in a square,

Thus, the Side of the square = 2*r

So, the Area of the circle = π r²

And the Area of the square = r*r

The Area of the square = r²

Since,

Area of Shaded region  =  The Area of the square -  the Area of the circle

Area of shaded region = r² - πr²

Area of shaded region = (1 - π)r²

Therefore, the function in the terms of π and r will be f(r) = (1 - π)r².

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The line slants downward from left to right, indicating that as x increases, y decreases.

The given linear equation is -x = 2y + 1. To represent this equation graphically, we need to rearrange it into the slope-intercept form, which is y = mx + b, where m represents the slope and b represents the y-intercept.Rearranging the given equation, we get:2y = -x - 1

Dividing both sides by 2:y = (-1/2)x - 1/2

The slope of the line is -1/2, which means that for every unit increase in x, y decreases by 1/2 unit. The y-intercept is -1/2, indicating that the line intersects the y-axis at (0, -1/2).

Based on this information, the best graph that represents the linear equation y = (-1/2)x - 1/2 is a straight line with a negative slope of -1/2, starting at the point (0, -1/2) and extending infinitely in both directions.

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A function that has a greater maximum include the following: A. Function 1 has a larger maximum at (4, 1).

In order to determine the maximum value of function 2, we would have to take the first derivative with respect to x and then, substitute this x-value into the original function while equating it to zero (0), and then evaluate as follows;

f(x) = −x² + 2x - 15

f(x) = −2x + 2

0 = −2x + 2

2x = 2

x = 2/2

x = 1

For the maximum value of function 2, we have:

f(1) = −(1)² + 2(1) - 15

f(1) = -14

For the maximum value of function 1, we can logically deduce that it is equal to 1 based on the graph in image attached above.

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The sets are solved and the compliment of set A = set B

Given data ,

A: Rolling a number greater than 4.

B: The complement of event A (i.e., not rolling a number greater than 4).

Given that we are rolling a single six-sided die, we have the following possible outcomes: {1, 2, 3, 4, 5, 6}.

Event A consists of the outcomes {5, 6} because those are the numbers greater than 4.

The complement of event A, event B, consists of the outcomes {1, 2, 3, 4} because those are the numbers not greater than 4.

Hence , set A = {5, 6} and set B = {1, 2, 3, 4}

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ANSWER

The height of the house is 55.5 feet

EXPLANATION

Since this forms a right triangle, we can use the tangent of the elevation angle to the top of the house to find its height - because we know the lenght of the adjacent side and we want to know the lenght of the opposite side:

Answer:5

Step-by-step explanation:

Answer: b = 11.62

Step-by-step explanation:

We can use this formula to solve for b:

\(b^{2} =\) \(\sqrt{c^{2}-a^{2} }\)

\(b^{2} =\) \(\sqrt{12^{2}-3^2 }\)

\(b^2= \sqrt{144-9}\)

= 11.61895004

We can round that to 11.62.

Hope this helped!

The box in the middle of the plot spans from the first quartile (Q1) to the third quartile (Q3), with a line inside representing the median.

A whisker plot, also known as a box and whisker plot, is a graphical representation of a set of numerical data through their quartiles. The plot consists of a box with whiskers extending from the top and bottom, showing the spread and distribution of the data. The five-number summary, which includes the minimum value, first quartile (Q1), median, third quartile (Q3), and maximum value, is used to create the whisker plot.

Here,

To create a box and whisker plot, we need to find the five-number summary of the data set, which includes:

Minimum value: the smallest value in the data set.

First quartile (Q1): the median of the lower half of the data set.

Median: the middle value in the data set.

Third quartile (Q3): the median of the upper half of the data set.

Maximum value: the largest value in the data set.

First, we need to put the data in order:

10, 12, 14, 15, 16, 18, 22, 24, 25, 28

The minimum value is 10 and the maximum value is 28.

The median is the middle value, which is 18.

To find the first quartile, we need to find the median of the lower half of the data set, which is:

10, 12, 14, 15, 16

The median of this lower half is 14.

To find the third quartile, we need to find the median of the upper half of the data set, which is:

22, 24, 25, 28

The median of this upper half is 24.

So, the five-number summary for this data set is:

Minimum value = 10

First quartile (Q1) = 14

Median = 18

Third quartile (Q3) = 24

Maximum value = 28

Now we can use this information to create the box and whisker plot:

      |          |      

 ----+----+----+----+----

    10   14   18   24   28

The box in the middle of the plot spans from the first quartile (Q1) to the third quartile (Q3), with a line inside representing the median. The whiskers extend from the box to the minimum and maximum values in the data set.

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Explanation:

This problem is a simple percent chage problem. The absoluge change in price was $12−$8=$4. Relative to the original price, it was 412, which is 0.3333 or 33.33%.