Justification of Subaquatic soil if it is sediment or soil (on the point of view of a geologist)
Subaquatic soil can be classified as sediment or soil based on its geological properties and formation processes.
Sediment refers to any material that is transported and deposited by water, wind, ice, or gravity. Sediments can be composed of various materials, such as minerals, rocks, organic matter, and even human-made debris.
Sediments can accumulate in different environments, such as rivers, lakes, oceans, and deserts, and can be deposited in layers over time.
Subaquatic soil can be classified as sediment or soil based on its geological properties and formation processes. If it has primarily formed through sediment deposition, it is more appropriate to classify it as sediment.
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0.2g of sand in two-third in liter of ethanol . What is the concentration in g per dm cube
The mass concentration of sand in the ethanol solution is 0.299 g/dm³.
What is the concentration in grams per dm³?To find the concentration in grams per cubic decimeter (g/dm³), we first need to convert the volume from liters to cubic decimeters (dm³). Since 1 liter is equal to 1 cubic decimeter, we can directly convert the volume.
Given:
Mass of sand = 0.2 g
Volume of ethanol = two-thirds liter
Converting volume to dm³:
1 liter = 1 cubic decimeter
two-thirds liter = (2/3) cubic decimeter = 0.67 dm³ (rounded to two decimal places)
Now we can calculate the concentration in g/dm³ by dividing the mass of sand by the volume in dm³:
Concentration = Mass / Volume
Concentration = 0.2 g / 0.67 dm³
Concentration ≈ 0.299 g/dm³ (rounded to three decimal places)
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Vehicles that are propelled by a conventional gasoline engine in tandem with an
electric motor powered by batteries are called hybridelectric vehicles (HIVs).
A.True
B.False
If the reaction is begun with an initial PH3 concentration of 0.95 M, what will be the concentration of PH3 after 30.50 s
Answer:
\([PH_3]=0.30M\) but see detailed explanation, please.
Explanation:
Hello there!
In this case, unfortunately, we are not given the rate constant but we can set up a reaction according to the information available on the internet:
\(4PH_3\rightarrow P_4+6H_2\)
Whose rate constant is 0.0375/s. In such a way, it is possible infer that this is first-order reaction whose integrated rate law is:
\([PH_3]=[PH_3]_0exp(-kt)\)
Thus, given the initial concentration, rate constant and elapsed time, the final concentration of PH3 would be:
\([PH_3]=(0.95M)exp(-30.50s*0.0375/s)\\\\\)
\([PH_3]=0.30M\)
However, it is important to keep in mind this result may vary according to your actual question.
Regards!
which statement best describes an example of selective breeding?
Answer:
B people control how plants or animals reproduce to get desired traits
Explanation:
if you get it correct mark meh brainliest or however you say it so ppl know its correct
Hypothesis II: Write the equation with Iron (III) Chloride and balance it: Iron + Copper (II) chloride --> Iron (III) chloride + Copper
Answer:
Fe + CuCl2 = FeCl2 + Cu
Explanation:
This is already balanced.
6. How many moles are in 8.30 x 1023 molecules of CO₂?
a.
b.
C.
d.
1.37
2.8
55.5
100
how many moles of chloroethylene contain 5.47 x 10 26 molecules
Answer:
so each mole is 6.022 * 10^23
so subtract and we have 5.47 * 10^3
1000*5.47
5470/6.022
908.315 moles
908moles in sig figures
what type of energy is a furnace and using a telephone? pls help
Answer:
hope this helped
Explanation:
Radiant energy is created through electromagnetic waves and was discovered in 1885 by Sir William Crookes. Fields in which this terminology is most often used are telecommunications, heating, radiometry, lighting, and in terms of energy created from the sun.
Answer:
radiation energy is created through electromagneic waves and was discovered in 1885 by Sir William Crookes
Explanation:
Comparing Designs
Question 1
The students worked on their clay boats. The only building material allowed was the clay. Finally they teams had the first trial run and Boat 1 and Boat 2 were in hot competition. Boat 1 had a V-shaped hull while Boats 2 and 3 had wide, U-shaped hulls. Based on the results of the first trial run, what suggestion(s) would you give to Team 3?
Responses
A Make the sides lower and the base of the boat larger.Make the sides lower and the base of the boat larger.
B Rework the hull making sure there are no leaks.Rework the hull making sure there are no leaks.
C Try a V-shaped hull like Team 1.Try a V-shaped hull like Team 1.
D Cover the exterior with duct tape.Cover the exterior with duct tape.
Question 2
As we said, Boat 1 and Boat 2 were in hot competition. Boat 1 had a V- shaped hull with high sides to prevent water from entering the boat. Boat 2 had a U-shaped hull with a flat bottom and lower sides. If Boat 1 wants to beat Boat 2 in the second trial, how should the team modify the design?
Responses
A Line the inside of the boat with waterproof material.Line the inside of the boat with waterproof material.
B Make the sides higher to hold more cargo.Make the sides higher to hold more cargo.
C Leave the hull alone; be slow and careful when adding cargo.Leave the hull alone; be slow and careful when adding cargo.
D Lower the sides; make the base larger.
The research setup is a comparative analysis of several boats in an effort to understand their performance on the water and the differences between them because little would be learned from studying just one boat. Seven boats have been chosen for additional examination. They are all either "traditional" boats or boats that have been found in archaeology. Smaller open boats are the main focus.
The mass of an object per unit volume is what is meant by density. A brick, for instance, weighs more than a Styrofoam block of equal size (volume), indicating that the brick is denser than the Styrofoam. An object will float in a liquid if it has a lower density than the liquid. An object will sink in a liquid if it has a higher density than the liquid.
Instruct students to work in teams of two. First, they design their boats, keeping in mind that the boats must float while holding weight and that they have a limited amount of clay to use. Students can test their designs and make changes as often as they like. The goal is to create boats that can hold as much weight as possible while staying afloat.
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When the seed is fertilized, the sprout turns into an adult before a seedling?
Suppose a gas mixture used for anesthesia contains 4.60 mol oxygen (O₂) and 6.00 mol nitrous oxide (N₂O). The total pressure of the mixture is 2.00 atm. A mole fraction is defined as the moles of a specific component divided by the total number of moles present. What is the mole fraction of O₂ in this mixture?
Considering the definition of mole fraction, the mole fraction of O₂ in the mixture is 0.434.
Definition of mole fractionThe molar fraction is a way of measuring the concentration that expresses the proportion in which a substance is found with respect to the total moles of the solution.
In other words, the mole fraction expresses the concentration of solute in a solution as the ratio of moles of substance to total moles of solution:
\(mole fraction=\frac{moles of substance}{moles of solution}\)
Mole fraction of O₂ in this mixtureIn this case, you know a gas mixture used for anesthesia contains 4.60 mol oxygen (O₂) and 6.00 mol nitrous oxide (N₂O).
So, the total moles of the solution can be calculated as:
Total moles = moles of oxygen (O₂) + moles of nitrous oxide (N₂O)
Then:
Total moles= 4.60 moles + 6 moles
Total moles= 10.60 moles
Finally, the more fraction of O₂ can be calculated as follow:
\(Mole fraction of O_{2} =\frac{moles of O_{2}}{total moles}\)
\(Mole fraction of O_{2} =\frac{4.60 moles}{10.6o moles}\)
Solving:
Mole fraction O₂ = 0.434
Finally, the mole fraction of O₂ in the mixture is 0.434.
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The normal boiling point of a certain liquid X is 130.9 °C, but when 19.9 g of urea (NH2) CO are dissolved in 200. g of X, it is found that the solution boils at 134.1 °C instead. Use this information to calculate the molal boiling point elevation constant K, of X. Be sure your answer has the correct number of significant digits x 1 ℃.mol -kg
Answer:
K = 1.93 °C/m
Explanation:
This question can be solved by formula of elevation of boiling point.
Boiling T° of solution - Boiling T° of pure solvent = K . m . i
Our solute is urea.
Our solvent is X.
We convert mass of urea to moles: 19.9 g . 1 mol / 60.06g = 0.331 mol
We convert g of solute to kg = 200 g . 1 kg/ 1000g = 0.2kg
m = molality → moles of solute / kg of solvent
m = 0.331 mol / 0.2 kg = 1.66 m
As urea is an organic compound, no ions will be formed.
i = 1 (a non ionizing compound)
Let's replace data in formula:
134,1°C - 130.9°C = K . 1.66 m . 1
3.2 °C / 1.66 m = K
K = 1.93 °C/m
The blood pH is regulated by the following equations: CO2(g) + H2O(l) ↔ H2CO3(aq) ↔ H2CO3(aq) + H2O(l) ↔ HCO3- (aq) + H3O+(aq) [Equation A]
Using Le Chatelier’s principle, which direction will the reaction shifts if there is an increase in H3O+ when the blood becomes more acidic with increasing cellular metabolism.
How will the pH of the blood be affected if a person is hyperventilating?
An emergency medical team evaluates an Olympic athlete and determines that she has alkalosis (high blood pH). What does this mean in terms of the ratio of bicarbonate to carbonic acid? Which way would the reactions have to shift to lower her blood pH?
The blood pH would turn more alkaline
There is more bicarbonate ions in the blood
The equilibrium would have to shift to the left
How will the pH of the blood be affected if a person is hyperventilating?Hyperventilation is a condition in which a person breathes rapidly and deeply, leading to a decrease in the concentration of carbon dioxide (CO2) in the blood. This causes a shift in the balance of the carbonic acid-bicarbonate buffer system in the blood, which can affect the pH of the blood.
The carbonic acid-bicarbonate buffer system is an important mechanism that helps regulate the pH of the blood. It involves the equilibrium between carbonic acid (H2CO3) and bicarbonate ions (HCO3-) in the blood:
H2CO3 ⇌ H+ + HCO3-
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How much water has to be evaporated from 250 mL of 1 M Ca(OH)2 to make it 3 M?
Approximately 166.67 mL of water needs to be evaporated from 250 mL of 1 M Ca(OH)2 to make it 3 M.
To find the amount of water that needs to be evaporatedThe relationship between the initial and final concentrations and volumes must be taken into account.
Given: Initial concentration \((C^1) = 1 M Initial volume (V^1) = 250 mL\)
\((C^2) = 3 M final concentration\)
We can use the equation:
\(C^1 * V^1 = C^2 * V^2\)
Where:
\(V^2\)is the final volume of the solution
Rearranging the equation to solve for V2:
\(V^2 = (C^1 * V^1) / C^2\)
Substituting the given values:
\(V^2 = (1 M * 250 mL) / 3 M\)
\(V^2 = 250 mL / 3\)
\(V^2\) ≈ \(83.33 mL\)
To find the amount of water that needs to be evaporated, we subtract the final volume from the initial volume:
Amount of water to be evaporated = \(V^1 - V^2\)
Amount of water to be evaporated = 250 mL - 83.33 mL
Amount of water to be evaporated ≈ 166.67 mL
Therefore, approximately 166.67 mL of water needs to be evaporated from 250 mL of 1 M Ca(OH)2 to make it 3 M.
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A reaction is 50% complete in 30.0 min how long after its start will the reaction 75% complete if it is
a) first order?
b) zero order?
Answer:
Explanation:
a) For a first-order reaction, the rate of the reaction is proportional to the concentration of the reactant, i.e., rate = k[A]. The integrated rate law for a first-order reaction is given by:
ln([A]t/[A]0) = -kt
where [A]t is the concentration of the reactant at time t, [A]0 is the initial concentration, k is the rate constant, and t is time.
If a reaction is 50% complete in 30.0 min, it means that [A]t/[A]0 = 0.5. Substituting these values into the equation above, we can solve for the rate constant:
ln(0.5) = -k(30.0 min)
k = 0.0231 min^-1
Now, if the reaction is 75% complete, it means that [A]t/[A]0 = 0.25 (since 50% is half of the initial concentration and 75% is a quarter of the initial concentration). Substituting this value and the rate constant into the equation above, we can solve for the time t:
ln(0.25) = -0.0231 min^-1 * t
t = 61.3 min
Therefore, for a first-order reaction, the reaction will be 75% complete after 61.3 min.
b) For a zero-order reaction, the rate of the reaction is independent of the concentration of the reactant, i.e., rate = k. The integrated rate law for a zero-order reaction is given by:
[A]t = -kt + [A]0
where [A]t is the concentration of the reactant at time t, [A]0 is the initial concentration, k is the rate constant, and t is time.
If a reaction is 50% complete in 30.0 min, it means that [A]t = 0.5[A]0. Substituting these values into the equation above, we can solve for the rate constant:
0.5[A]0 = -k(30.0 min) + [A]0
k = 0.0167 M/min
Now, if the reaction is 75% complete, it means that [A]t = 0.25[A]0. Substituting this value and the rate constant into the equation above, we can solve for the time t:
0.25[A]0 = -0.0167 M/min * t + [A]0
t = 45.0 min
Therefore, for a zero-order reaction, the reaction will be 75% complete after 45.0 min.
chemist must prepare of hydrobromic acid solution with a pH of at . He will do this in three steps: Fill a volumetric flask about halfway with distilled water. Measure out a small volume of concentrated () stock hydrobromic acid solution and add it to the flask. Fill the flask to the mark with distilled water. Calculate the volume of concentrated hydrobromic acid that the chemist must measure out in the second step. Round your answer to significant digits.
Answer:
32 mL
Explanation:
A chemist must prepare 500.0mL of hydrobromic acid solution with a pH of 0.50 at 25°C. He will do this in three steps: Fill a 500.0mL volumetric flask about halfway with distilled water. Measure out a small volume of concentrated (5.0M) stock hydrobromic acid solution and add it to the flask. Fill the flask to the mark with distilled water. Calculate the volume of concentrated hydrobromic acid that the chemist must measure out in the second step. Round your answer to 2 significant digits.
Step 1: Calculate [H⁺] of the dilute solution
pH = -log [H⁺]
[H⁺] = antilog -pH = antilog -0.50 = 0.32 M
Step 2: Calculate [HBr] of the dilute solution
HBr is a strong acid that dissociates according to the following equation.
HBr ⇒ H⁺ + Br⁻
The molar ratio of HBr to H⁺ is 1:1. The concentration of HBr is 1/1 × 0.32 M = 0.32 M.
Step 3: Calculate the volume of the concentrated HBr solution
We will use the dilution rule.
C₁ × V₁ = C₂ × V₂
V₁ = C₂ × V₂ / C₁
V₁ = 0.32 M × 500.0 mL / 5.0 M
V₁ = 32 mL
Determine what happens in this reaction.S + Cl2 →SCl2
Sulfur act as a reducing agent and chlorine acts as an oxidizing agent.
Oxidation: The loss of electronsReduction: The gain of electronsOxidation number:The charge is based on the number of electrons assigned to an atom as compared to the neutral atom
Given reaction:-
\(S+Cl_2 \rightarrow SCl_2\)
The oxidation state of sulfur in the left side is 0, but in right side is +2. So, sulfur is oxidized. The oxidation number of Cl in the reactant side is 0 and n the product side is -1. So, Cl acts as oxidizing agent.
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read over the procedures of the lab you will be completing in class, and then identify the items that will be gaining and losing heat.
In most laboratory experiments, there are several items that may gain or lose heat during the experiment. These can include:
The reaction vessel: If the experiment involves a chemical reaction, the reaction vessel may gain or lose heat as the reaction proceeds. The vessel can be made of glass or metal and may be heated or cooled as needed.
Heating or cooling sources: The experiment may require heating or cooling sources such as Bunsen burners, hot plates, or refrigeration units. These sources will either gain or lose heat depending on the temperature of the surrounding environment.
Surrounding air or water: The surrounding air or water may also gain or lose heat as a result of the experiment. For example, if the reaction vessel is placed in a water bath to control the temperature, the water will gain or lose heat to maintain the desired temperature.
Overall, it is important to carefully consider the heat transfer mechanisms in a laboratory experiment to ensure accurate and reliable results. Proper monitoring and control of temperature can be critical to the success of an experiment.
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Determine whether the disruption of the bonds or attractions occurs during protein hydrolysis or protein denaturation.
Answer:
The disruption of the bonds or attractions occurs during protein hydrolysis which results in the loss for the primacy structure. The peptide bonds is the bond affected in this scenario.
The disruption of the bonds however only exist in the process of denaturation and this results in a change in the confirmation which could be secondary, tertiary, and quaternary structural related. And example of the bonds affected include salt bridges, disulfide bridges, hydrogen bonds etc.
The percent by mass of oxygen in H4P2O7
The percent by mass of oxygen in H₄P₂O₇ is 62.92%.
How to calculate percentage by mass?The percentage by mass of an element in a compound can be calculated by dividing the atomic mass of the element by the molar mass of the compound multiplied by 100 as follows:
% by mass = atomic mass of O/molar mass of H₄P₂O₇ × 100
The molar mass of H₄P₂O₇ can be calculated as follows:
1(4) + 31(2) + 16(7) = 178g/mol
Percent by mass of oxygen = (112g/mol ÷ 178g/mol) × 100
Percent by mass of oxygen = 62.92%
Therefore, 62.92% is the percent by mass of oxygen.
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How is the number of neutrons in the nucleus of an atom calculated?
a) Add the number of electrons and protons together.
b) Subtract the number of electrons from the number of protons.
c) Subtract the number of protons from the mass number.
d) Add the mass number to the number of electrons
Answer:
c
Explanation:
took this class last year
The Law of Conservation of Matter states that in a chemical reaction matter cannot be ___ or ____
Answer:
The law of conservation of matter states that in a chemical reaction matter cannot be created or destroyed
Explanation:
Calculate the [H+]
and pH of a 0.000295 M
butanoic acid solution. Keep in mind that the a
of butanoic acid is 1.52×10−5
[H⁺]=6.696 x 10⁻⁵
pH = 4.174
Further explanationGiven
The concentration of 0.000295 M (2.95 x 10⁻⁴ M) butanoic acid solution
Required
the [H+] and pH
Solution
Butanoic acid is the carboxylic acid group. Carboxylic acids are weak acids
For weak acid :
\(\tt [H^+]=\sqrt{Ka.M}\)
Input the value :
[H⁺]=√1.52 x 10⁻⁵ x 2.95 x 10⁻⁴
[H⁺]=6.696 x 10⁻⁵
pH = - log [H⁺]
pH = - log 6.696 x 10⁻⁵
pH = 5 - log 6.696
pH = 4.174
How many carbon atoms are in 6.5 moles of carbon?
3.91 ×10²⁴ carbon atoms are in 6.5 moles of carbon. The smallest unit of matter that may be divided without producing electrically charged particles is the atom.
What is atom?The smallest unit of matter that may be divided without producing electrically charged particles is the atom. It is also the smallest piece of substance with chemical element-like characteristics. As a result, the atom serves as the fundamental unit of chemistry. Space makes up the majority of an atom.
The rest is made up of a cloud of electrons that are negatively charged surrounding a nucleus that is positively charged made up of protons and neutrons. Compared to electrons, which are the smallest charged particles in nature, the nucleus is small and dense. Electric forces, which link radicals to the nucleus of atoms, cause them to be drawn to any positive charge.
number of atoms= 6.5 × 6.022×10²³
=3.91 ×10²⁴
Therefore, 3.91 ×10²⁴ carbon atoms are in 6.5 moles of carbon.
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What is the oxidation state of N in NaNOz?
The oxidation state of nitrogen (N) in NaNO3 is +5. option B
To determine the oxidation state of nitrogen (N) in sodium nitrate (NaNO3), we need to assign oxidation numbers to each element in the compound.
In NaNO3, we know that the sodium ion (Na+) has a +1 oxidation state because it is an alkali metal. Oxygen (O) typically has an oxidation state of -2 in compounds, and there are three oxygen atoms in NaNO3. Since the compound is neutral, the sum of the oxidation states must be zero.
Let's assume that the oxidation state of nitrogen is x. Therefore, we can set up the equation:
(+1) + x + (-2) * 3 = 0
Simplifying the equation:
+1 + x - 6 = 0
x - 5 = 0
x = +5
Therefore, the oxidation state of nitrogen (N) in NaNO3 is +5.
The oxidation state of an element indicates the number of electrons it has gained or lost in a compound. In this case, the nitrogen atom in NaNO3 has gained five electrons to achieve a stable oxidation state of +5.
It is important to note that oxidation states are formal charges and do not necessarily represent the actual distribution of electrons in a compound. They are assigned based on a set of rules and can be useful in understanding the reactivity and behavior of elements in chemical reactions.
Option B
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What is the approximate wavelength of radio waves
Answer:
CO32-:
✔ reactant
H2O:
✔ product
CO2:
✔ product
The 2 in front of H+:
✔ coefficient
Explanation:
A powder contains feso47h2o
The mass of FeSO4*7H2O in the sample is 1.21 grams.
Calculate moles of Fe2O3
moles of Fe2O3 = mass of Fe2O3 / Molar mass of Fe2O3
moles of Fe2O3 = 0.348 grams / 159.69 g/mole = 0.00218 moles
Calculate moles of Fe
4 Fe + 3O2 → 2Fe2O3
For 4 moles of Fe consumed there is 2 moles of Fe2O3 produced
This means it has a ratio 2:1
So 0.00218 moles of Fe2O3 produced , there is 2*0.00218 = 0.00436 moles of Fe consumed
Calculate moles of FeSO4*7H2O
Fe + H2SO4 + 7H2O → FeSO4*7H20 + H2
For 1 mole of Fe consumed there is 1 mole of FeSO4*7H2O produced
This means for 0.00436 moles there is 0.00436 moles of Fe2SO4*H2O produced
Calculate the mass of FeSO4*7H2O in the sample
mass of FeSO4*7H2O = 0.00436 moles * 278.01 g/mole = 1.212 g
The mass of FeSO4*7H2O in the sample is 1.21 grams.
Complete question: A powder contains FeSO4⋅7H2O (molar mass=278.01 g/mol), among other components. A 3.930 g sample of the powder was dissolved in HNO3 and heated to convert all iron to Fe3+. The addition of NH3 precipitated Fe2O3⋅xH2O, which was subsequently ignited to produce 0.348 g Fe2O3. What was the mass of FeSO4⋅7H2O in the 3.930 g sample?
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Select the statements that are TRUE about lambda max?
Note: You must select ALL the statements to earn credit. Partial answers will not receive partial credit.
A. Lambda max refers to the wavelength along the absorption spectrum where a substance has its strongest and highest absorption.
B. Lambda max refers to the wavelength along the absorption spectrum where a substance has its widest/broadest absorption.
C. Lambda max for different color dyes will be the same.
D. Lambda max refers to the absorbance value and is unitless.
E. Lambda max usually have a unit of nm or m.
A. Lambda max is the region of the absorption spectrum where a substance absorbs the most energy and strongly. E. The unit of lambda max is often nm or m.
What does choosing max accomplish?Because it will offer the lowest detection limits, the wavelength with the maximum molar absorptivity (max) is typically chosen for the study.
What factors affect Lambda Max?If you have read the remainder of this section, you are aware that the existence of specific chromophores (light-absorbing groups) within a molecule determines the wavelength of maximum absorption (lambda-max).
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What type of reactions are the following problems?
10) 12 Al + 1 S8→ 4 Al₂S3
a. Single replacement
b. double replacement.
c. Synthesis/combination
d. Decomposition
e. Combustion
Answer: a
Explanation: