Answer:
x = - 3 ± 2\(\sqrt{3}\)
Step-by-step explanation:
Given
2x² + 12x = 6 ( divide through by 2 )
x² + 6x = 3
To complete the square
add ( half the coefficient of the x- term )² to both sides
x² + 2(3)x + 9 = 3 + 9
(x + 3)² = 12 ( take the square root of both sides )
x + 3 = ± \(\sqrt{12}\) = ± 2\(\sqrt{3}\) ( subtract 3 from both sides )
x = - 3 ± 2\(\sqrt{3}\) ← exact solutions
Find the outer perimeter of this figure. Round your answer to the nearest hundredth. Use 3.14 to approximate pi.
Therefore, The outer perimeter of the figure is approximately 50.27 units when rounded to the nearest hundredth, using 3.14 as an approximation for pi.
The figure's outer perimeter is the sum of the lengths of all its sides. To find the perimeter, we need to measure each side and add them together. Since we don't have exact measurements, we can use the given information and approximation of pi to estimate the lengths. Once we've estimated the lengths, we can add them up to get the perimeter. Finally, we can round the answer to the nearest hundredth.
To find the outer perimeter of the figure, we need to estimate the lengths of its sides and add them together. The figure is composed of a semicircle, a rectangle, and a quarter circle. We can use the formula for the circumference of a circle to find the lengths of the circular portions and add them to the length and width of the rectangle to get the total perimeter. Using 3.14 as an approximation for pi, we get a perimeter of approximately 50.27 units. Rounded to the nearest hundredth, the outer perimeter of the figure is 50.27 units.
Therefore, The outer perimeter of the figure is approximately 50.27 units when rounded to the nearest hundredth, using 3.14 as an approximation for pi.
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whats the equivalent expression 2r-5+6r
2r-5+6r
Add like terms:
(2r + 6r) - 5
8r - 5
You have a standard number cube. What is the probability of rolling a number less than 3, and then rolling a prime number? A. 1/3 B. 1/2 C. 1/36 D. 1/6
Hey Mate !
Your Answer is given in the snip below !!
Please do mark me as brainliest !!!
(ANSWER= (D) \(\frac{1}{6}\) )
Explanation
Answer:
You have a standard number cube.
What is the probability of rolling a number less than 3, and then rolling a prime number?
D. 1/6
Evan has $560 to spend at a bicycle store for some new gear and biking outfits. Assume all prices listed include tax.
He buys a new bicycle for $236.27.
He buys 3 bicycle reflectors for $14.61 each and a pair of bike gloves for $15.56.
He plans to spend some or all of the money he has left to buy new biking outfits for $57.65 each.
What is the greatest number of outfits Evan can buy with the money that's left over?
PLEASE HELP ME!!! I REALLY NEED THIS
the surface area of a triangular prism is 78 square inches. what is the surface area of a similar prism that is 3 times as large?
The surface area of the new prism is 702 square inches.
Given that,
The area of triangular prism = 78 square inches
Use the fact that the surface area of a similar prism is proportional to the square of the scale factor.
Since,
The new prism is 3 times larger than the original, the scale factor is 3.
Therefore,
The surface area of the new prism will be 3 = 9 times larger than the original prism.
To find the surface area of the new prism, we can multiply the surface area of the original prism by 9,
78 in x 9 = 702 in²
Thus,
Surface area of new prism = 702 in².
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This table shows the three different ways that toy animals are packaged at a factory
Answer:
I dont have the table I need it to answers
Someone help! Please
Answer:
Sorry I don't now I'm just grade 6
Can someone please help me with this
Answer:
circumference of circular track =2πR
R = 50/2 = 25m
circumference = 2 × 22/7 × (25) = 157.14 ≈ 157m
No. of rounds made = 10
total distance covered = 157 × 10 = 1570m
Option 3) 1570 is correct
Please only answer : The horizontal scale should be X-scale and The vertical scale should be Y-scale
Regarding the scales to plot the points on the table, we have that:
The horizontal goes from X-min = -7 to X-max = 6.The horizontal scale should be X-scale = 1.The vertical goes from Y-min = -1500 to Y-max = 1200.The vertical scale should be Y-scale = 200.What are the ideal scales for the graphs?To find the ideal scales, we have to verify which are the extrema values of each variable, that is, the minimum and maximum value of each x and y.
From the table, the minimum and maximum values of X are given as follows:
X-min = -7.X-max = 6.This is a small range of values, hence the horizontal scale should be of 1.
From the same table, second column, the minimum and maximum values of Y are given as follows:
Y-min: -1500.Y-max: 1200.This is a large range of values, hence an ideal vertical scale is of 200, as then the number of traces would be almost the same as the number of traces of x.
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i need this asap for a test plsssss help. Which statement is true about acute triangles?
A.
a triangle that has one obtuse angle
B.
a triangle that has three acute angles
C.
a triangle with no sides that are the same length
D.
a triangle with three sides that are the same length
Answer:
B
Step by step solution:
A is an obtuse triangle
B is an acute triangle
C is a scalene triangle
D is an equilateral triangle.
2. One candle, in the shape of a right circular cylinder, has a
height of 7.5 inches and a radius of 2 inches. What is the
volume of the candle? Show your work and round your
answer to the nearest cubic inch.
Use 3.14 for pi
The volume of the candle is approximately 94 cubic inches.
What is circular cylinder?
A circular cylinder is a three-dimensional solid object made up of two parallel and congruent circular bases and a curving surface connecting the bases.
The volume of a right circular cylinder is given by the formula:
V = πr²h
Where
V is the volumer is the radiush is the heightSubstituting the given values into the formula, we get:
V = 3.14 x 2² x 7.5
V = 3.14 x 4 x 7.5
V = 94.2
Rounding to the nearest cubic inch, we get:
V ≈ 94 cubic inches
Therefore, the volume of the candle is approximately 94 cubic inches.
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What is the end behavior of f(x)?
f(x)=-3072+2432x+128x^4-576x^3+256x^2-8x^5
1. as x→−∞,y→∞ and as x→∞,y→−∞
2. as x→−∞,y→∞ and as x→∞,y→∞
3. as x→−∞,y→−∞ and as x→∞,y→∞
4. as x→−∞,y→−∞ and as x→∞,y→−∞
14-65=-25+x what the value of x
Answer: x = -26
Step-by-Step Explanation:
14-65 = -25+x
-51 = -25+x
-26 = x
The graphs below have the same shape. What is the equation of the red graph?
G(x) = ?
F(x) = 3 - x^4
G(x) =____
Answer:
A
Step-by-step explanation:
because if x=0
y=4
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The function represented by the red graph is -
g(x) = 4 - x⁴
What is translation of graph?
A translation is a movement of the graph either horizontally (parallel to the
x - axis) or vertically (parallel to the y -axis).
Given is the graph of the function -
f(x) = 3 - x⁴
In order to shift the graph upwards by one unit upwards, we will make a new function g(x) such that -
g(x) = f(x) + 1
Therefore -
g(x) = 3 - x⁴ + 1
g(x) = 4 - x⁴
Therefore, the function represented by the red graph is -
g(x) = 4 - x⁴
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2. Samantha's mom has a koi fish pond at the corner of her backyard. Samantha wanted to install a brick walkwa on two sides of the pond. Below is a picture of the pond." Assuming that the walkway has the same width, x, along its two sides, and assuming the entire walkway will use exactly 6 ft. of brick, answer the following questions. Brick C. Use any method to figure out how much the width, x, of the walkway will be. Make sure you show your work.
Answer:
3 feets
Step-by-step explanation:
Given that :
Entire walkway uses 6 feets of brick
Width of walkway = x
Width of walkway is the same along both sides ;
SINCE, the number of sides of the walkway = 2 and each side is the same
Hence,
x + x = 6 feets
2x = 6 feets
x = 6 feets / 2
x = 3 feets
Omar rides the train and ferry to visit his uncle the train ticket cost $42. The train ticket cost 7 times as much as the ferry tickets. How much does the ferry tickets cost
Answer:
6
Step-by-step explanation:
I don’t know if this is correct !!!!!!! Please answer correctly !!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!
Answer:
It is correct
Which of the following are among common transformations of variables to accommodate non-linear relationships in a linear regression model?
-The natural log-transformation.
-For a given predictor X, we can create an additional predictor 2X2 to accommodate a quadratic relationship between X and Y.
-For a given predictor X, we can create an additional predictor 3X3 to accommodate a cubic relationship between X and Y.
The natural log-transformation is among the common transformations of variables to accommodate non-linear relationships in a linear regression model.
There are several transformations of variables to accommodate non-linear relationships in a linear regression model. Three of the common ones are: The natural log-transformation.For a given predictor X, we can create an additional predictor X² to accommodate a quadratic relationship between X and Y.For a given predictor X, we can create an additional predictor X³ to accommodate a cubic relationship between X and Y.Therefore, the natural log-transformation is among the common transformations of variables to accommodate non-linear relationships in a linear regression model. The natural log transformation is the one that's most frequently employed. It changes the distribution of a variable to make it more normal and decrease the impact of outliers. It is common for continuous predictors with right-skewed or exponential distributions, such as income, expenditures, or time. This transformation is most frequently used to help correct non-normal distributions and to correct heterogeneity of variance.
So, the natural log-transformation is among the common transformations of variables to accommodate non-linear relationships in a linear regression model.
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The two legs of a right triangle measure 7 inches and 5 inches. Find the measure of the acute angle that is included between the longer leg and the hypotenuse. WILL GIVE BRAINIEST TO FIRST RIGHT ANSWER
Answer:
44.4 degrees
Step-by-step explanation:
Given the following
Hypotenuse = 7
Longer leg = 5 (adjacent])
Let the acute angle angle between both sides be x
According to SOH CAH TOA
Cos theta = adj/hyp
Cos x = 5/7
x= arccos (5/7)
x = arccos (0.7143)
x = 44.4degrees
Hence he measure of the acute angle that is included between the longer leg and the hypotenuse is 44.4 degrees
Given the following list of times for independent tasks, schedule these on two machines.
What is the best time for both machines to finish their tasking? List of times: (18, 8, 12, 6, 16) Show your work.
a) 32
B) 30
C) 34
D) 35
To schedule the tasks on two machines in a way that minimizes the time for both machines to finish their tasks, we can use the "Longest Processing Time" algorithm.
1. Sort the list of times in descending order: (18, 16, 12, 8, 6).
2. Assign the tasks one by one to the machine with the currently shorter total processing time.
Machine 1: (18) -> Total time: 18
Machine 2: (16) -> Total time: 16
Machine 1: (12) -> Total time: 30
Machine 2: (8) -> Total time: 24
Machine 1: (6) -> Total time: 36
3. The best time for both machines to finish their tasks is the maximum of the two total times: 36.
the correct answer is:
D) 35 (Incorrect)
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Which graph represents the equation -5x+4y>-1?
======================================================
Explanation:
The inequality sign has an "or equal to", which means the boundary line will be solid. We can rule out choices B and C because they have dashed boundary lines.
A solid boundary line means that points on the boundary are part of the solution set.
Now let's see what happens when we plug in a point like (x,y) = (4,0). This will tell us how to shade the blue region.
\(-5x + 4y \ge -1 \\\\-5(4) + 4(0) \ge -1 \\\\-20 \ge -1 \\\\\)
This is false because -20 is not larger than -1. It's the other way around.
This tells us the point (4,0) is not in the blue shaded region, and it's not on the boundary line either. We can rule out choice A because of this.
The only thing left is choice D, which is the final answer. I recommend plugging a point from this region into the inequality to confirm we have a true statement.
I forgot how to do this. I will give brainliest!
Answer:
A = 2, B = 3 and C = 4
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Given
2x + 3y = 2 ( subtract 2x from both sides )
3y = - 2x + 2 ( divide all terms by 3 )
y = - \(\frac{2}{3}\) x + \(\frac{2}{3}\) ← in slope- intercept form
with slope m = - \(\frac{2}{3}\)
Parallel lines have equal slopes, thus
y = - \(\frac{2}{3}\) x + c ← is the partial equation
To find c substitute (2, 0) into the partial equation
0 = - \(\frac{4}{3}\) + c ⇒ c = \(\frac{4}{3}\)
y = - \(\frac{2}{3}\) x + \(\frac{4}{3}\) ← in slope- intercept form
Multiply through by 3
3y = - 2x + 4 ( add 2x to both sides )
2x + 3y = 4 ← in standard form
with A = 2, B = 3 and C = 4
Given an unlimited supply of coins of denominations X1, X2, ..., xn, we wish to make change for a value v; that is, we wish to find a set of coins whose total value is v. This might not be possible: for instance, if the denominations are 5 and 10 then we can make change for 15 but not for 12. Give an O(nv) dynamic-programming algorithm to find if it is possible to make change for v using coins of denominations X1, ..., Xn?
The O(nv) dynamic programming algorithm determines if it is possible to make change for value v using coin denominations X1, X2, ..., Xn by iteratively updating a boolean array.
To determine if it is possible to make change for a value v using coins of denominations X1, X2, ..., Xn, we can utilize dynamic programming. Here's an O(nv) algorithm:
Create a boolean array dp of size (v + 1), initialized with False values.
Set dp[0] to True, as it is always possible to make change for a value of 0.
Iterate through each coin denomination Xi from 1 to n:
For each coin, iterate through the range from Xi to v:
If dp[j - Xi] is True, set dp[j] to True. This means that we can make change for value j using coins up to denomination Xi.
Finally, return the value of dp[v]. If dp[v] is True, it is possible to make change for value v; otherwise, it is not.
The dynamic programming algorithm builds on the idea that if we can make change for a certain value j - Xi, then we can also make change for value j by adding a coin of denomination Xi. By updating the dp array iteratively, we keep track of the possible values that can be reached using the available coin denominations.
The algorithm has a time complexity of O(nv) since we iterate through n denominations for each value from 1 to v, performing constant time operations in each iteration.
This dynamic programming approach efficiently determines if it is possible to make change for a given value using the provided coin denominations.
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Which choice is equivalent to the expression below
5x sqrt2 - 3 sqrt2 + x sqrt2
Answer:
answer is D I think
Step-by-step explanation:
.............
one of the beauties of mathematics is that it is able to provide help in all sorts of different situations and to all sorts of people. you have land that you would like to use to create two distinct fenced-in areas in the shape given below. you have 410 meters of fencing materials to use. what values of x and y would result in the maximum area that you can enclose?
The perimeter be 410 then the maximum area be \($A=\left(\frac{410-3 x}{2}\right) * x$$\).
What is meant by perimeter?A perimeter is a closed path that encloses, surrounds, or delimits a one-dimensional length, a two-dimensional shape, or both. The circumference of a circle or an ellipse is its perimeter. There are numerous practical uses for calculating the perimeter.
Let the perimeter be p = 410
The perimeter of the fence is:
p = 2(x + y + 5 + y) + x
p = 2x + 2y + 10 + 2y + x
Collect like terms
p = 2x + x + 2y + 2y + 10
p = 3x + 4y + 10
Where, p = 410, then
3x + 4y + 10 = 410
\($$\begin{aligned}& 4 y=410-10-3 x \\& 4 y=400-3 x\end{aligned}$$\)
simplifying the equation, we get
\($y=\frac{400-3 x}{4}$$\)
The area (A) of the fence is:
\($$\begin{aligned}& A=(y+y+5) * x \\& A=(2 y+5) * x\end{aligned}$$\)
Substitute: \($y=\frac{400-3 x}{4}$\)
\($$\begin{aligned}& A=\left(2 * \frac{400-3 x}{4}+5\right) * x \\& A=\left(\frac{400-3 x}{2}+5\right) * x\end{aligned}$$\)
simplifying the equation, we get
\($A=\left(\frac{400-3 x+10}{2}\right) * x$$\)
\($A=\left(\frac{410-3 x}{2}\right) * x$$\)
\($A=\frac{410 x-3 x^2}{2}$$\)
A = 205x - 1.5 x²
Differentiate both sides, we get
A' = 205-3 x
simplifying the equation, we get
205 - 3x = 0
3x = 205
Therefore, the maximum area be \($A=\left(\frac{410-3 x}{2}\right) * x$$\).
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A tree 6m high casts a shadow 4m long. What angle do the sun's rays make with the ground?
Answer:
tan x° = 56.31°
Step-by-step explanation:
6/4= 1.5
hence x° = 56.31
how u work it
and answer
Answer:
B
Step-by-step explanation:
So if B is the midpoint of AC, AB must be 1/2 of AC.
If D is the midpoint of AB, it must be 1/2 of 1/2 of AC, which is 1/4 of AC.
So AC= 4 DB
From a group of 9 people, you randomly select 4 of them. What is the probability that they are the 4 oldest people in the group
The probability that they are the 4 oldest people in the group = 4/9
What is probability?The area of mathematics known as probability deals with numerical descriptions of how likely it is for an event to happen or for a claim to be true. A number between 0 and 1 is the probability of an event, where, broadly speaking, 0 denotes the event's impossibility and 1 denotes its certainty.
According to the given information:the group of people = 9
you randomly select 4 of them
the probability that they are the 4 oldest people in the group?
According to the formula :
Probability = expected number of outcome/Total number of outcome
If there are group of 9 people, then the total outcome of events will be 9.
If we are to select 4 oldest people from the group, then the expected outcome is 4.
So,
The probability that they are the 4 oldest people in the group = 4/9
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Each side of a square kitchen tile is 5 inches long. What is the tile's perimeter?
Solution:
Given:
\(side,s=5\text{ }in\)Since it is a square tile, the perimeter is the perimeter of a square.
Hence, the perimeter of a square is;
\(\begin{gathered} P=4s \\ P=4\times5 \\ P=20\text{ inches} \end{gathered}\)Therefore, the tile's perimeter is 20 inches.
A)There are twice as many students in the math club as in the telescope club. Suppose there are $x$ students in the telescope club and $y$ students who are members of both clubs. Find an expression for the total number of students who are in the math club or the telescope club (or both). Give your answer in simplest form.
b)There are twice as many students in the math club as in the telescope club. Suppose there are students in the telescope club and students who are members of both clubs. Find an expression for the total number of students who are in the math club or the telescope club but not both. Give your answer in simplest form.
The number of students in the telescope club by $x$ and the number of students in the math club by $y$.
$y=2x$Now, suppose there are $z$ students who are members of both clubs. Then the total number of students who are in the math club or the telescope club (or both) is given by:$x + y - z$ Substituting $y=2x$ in the above expression, we get:$x + 2x - z=3x - z$ Hence, the expression for the total number of students who are in the math club or the telescope club (or both) is $3x - z$.b)The number of students who are in the math club but not in the telescope club is given by:$y-z$ And the number of students who are in the telescope club but not in the math club is given by:$x-z$ Adding these two expressions, we get the total number of students who are in the math club or the telescope club but not both:$ y-z+x-z $.
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