Please answer urgent!

Answer: D.) 14

Step-by-step explanation:

First, you first calculate the square root of 64 , this gives you 8

Next, you calculate the square root of 36, which gives you 6

Then, since you are asked to add the two, you add 8 + 6 since this is the simplified version of the original equation.

8 + 6 = 14

Therefore, your answer is D.) 14

to get the equation of any straight line, we simply need two points off of it, let's use those two in the picture below.

\((\stackrel{x_1}{-16}~,~\stackrel{y_1}{-69})\qquad (\stackrel{x_2}{8}~,~\stackrel{y_2}{-33}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{-33}-\stackrel{y1}{(-69)}}}{\underset{\textit{\large run}} {\underset{x_2}{8}-\underset{x_1}{(-16)}}} \implies \cfrac{-33 +69}{8 +16} \implies \cfrac{ 36 }{ 24 } \implies \cfrac{ 3 }{ 2 }\)

\(\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-69)}=\stackrel{m}{ \cfrac{ 3 }{ 2 }}(x-\stackrel{x_1}{(-16)}) \\\\\\ y +69 = \cfrac{ 3 }{ 2 } ( x +16)\implies y+69=\cfrac{ 3 }{ 2 }x+24\implies {\Large \begin{array}{llll} y=\cfrac{ 3 }{ 2 }x-45 \end{array}}\)

Answer:

56

Step-by-step explanation:

Answer:

450

Step-by-step explanation:

A=hb/2

b = 20

h=45

Answer: True

Step-by-step explanation: because bias can lead to personal errors

Answer:

\(ax^{2} +bx+c^{2}=0\)

Step-by-step explanation:

A quadratic equation is a equation that takes the form: \(ax^{2} +bx+c^{2} = 0\)

   Ex. Using our definition of quadratic equations, \(ax^{2} +bx+c^{2}=0\),

          We can set a = 2, b = 1, c = 6:

               \(2x^{2} +x+6^{2}=0\)

               \(2x^{2} +x+36=0\)

          Which can then be solved (if you are trying to solve it) as:

               \((2x+9)(x-8)=0\)

                \(x=\frac{9}{2}, 8\)

Answer:

A. 176

Step-by-step explanation:

44 x 4

44           4 x 4= 16 4 x 4=16 plus 1 from he first 16. 176.

x 4

------

17 6

The next three terms of the sequence.

(a) The sequence alternates between a run of "1"s and a run of "0"s.

Specifically, the nth term is 1 if the number of "1"s in the first n-1 terms is

odd, and 0 if the number of "1"s in the first n-1 terms is even.

(b) The nth term is\(\lfloor (n+1)/2\rfloor\) if n is odd, and n/2 if n is even.

(c) The nth term is\(2^{(n-1)/2}\) times the parity (i.e., 0 or 1) of n.

(d) The nth term is \(3\cdot 2^{n-1}\).

(e) The nth term is 15-7(n-1).

(f) The nth term is the sum of the first n positive integers minus 3, i.e.,

\(1+2+3+\cdots+n-3.\)

To determine the next three terms of each sequence, we simply apply the rule or formula given above. For example, for sequence (a), the next three terms are 0, 1, 1, since the next term is 0 (since there are an even number of 1's so far), followed by two 1's (since there are now an odd number of 1's).

For sequence (b), the next three terms are 9, 10, 10, since the next term is 9 (since the next term in the pattern is odd), followed by two 10's (since the next two terms in the pattern are even). And so on for the other sequences.

(a) The sequence alternates between a run of "1"s and a run of "0"s.

Specifically, the nth term is 1 if the number of "1"s in the first n-1 terms is

odd, and 0 if the number of "1"s in the first n-1 terms is even.

(b) The nth term is\(\lfloor (n+1)/2\rfloor\) if n is odd, and n/2 if n is even.

(c) The nth term is\(2^{(n-1)/2}\) times the parity (i.e., 0 or 1) of n.

(d) The nth term is \(3\cdot 2^{n-1}\).

(e) The nth term is 15-7(n-1).

(f) The nth term is the sum of the first n positive integers minus 3, i.e.,

\(1+2+3+\cdots+n-3.\)

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The greatest possible value of k such that n is divisible by 5k is 39.

Any number that cannot be divided by two is considered an odd number. For instance, 25 is strange because it cannot be split by 2. A integer is considered to be divisible by two if its last digit is any of the following: 0, 2, 4, 6, or 8.

To find the greatest possible value of k such that n is divisible by 5k, we need to determine the highest power of 5 that divides n.

The product of the odd numbers from 99 to 199, inclusive, can be expressed as:

n = 99 * 101 * 103 * ... * 197 * 199

To find the power of 5 that divides n, we need to determine the number of factors of 5 in the product.

A factor of 5 is introduced for every multiple of 5 in the product. We need to count the multiples of 5 in the range from 99 to 199.

The largest multiple of 5 in that range is 195, which is 39 * 5.

Therefore, there are 39 multiples of 5 in the product.

To find the highest power of 5 that divides n, we divide 39 by k and find the largest possible integer value for k.

The largest possible value of k is the largest factor of 39.

The factors of 39 are 1, 3, 13, and 39.

Since we are looking for the greatest possible value of k, the answer is 39.

Therefore, the greatest possible value of k such that n is divisible by 5k is 39.

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Answer:

25.38 pounds for three roll

Step-by-step explanation:

Find and then compare the unit prices:

9.21 pounds per roll

25.38 pounds for three rolls =>  8.46 pounds per roll

42.85 pounds for five rolls  =>  8.57 pounds per roll

Conclusion:  25.38 pounds for three rolls corresponds to the lowest (cheapest) unit price and is thus the best buy.

ΔXYZ will also be an equilateral triangle.

What is equilateral triangle?

An equilateral triangle in geometry is a triangle with equal-length sides on all three sides. In the well-known Euclidean space, an equilateral triangle also is equiangular, meaning that each of its three internal angles is 60 degrees and congruent with the others. It's also referred to it as a regular triangle because it is a regular polygon.

As X,Y,Z are the midpoints of sides of equilateral triangle so when we will join the X,Y,Z we will find that distances XY=YZ=XZ are three are equal because this is proved by similarity of triangles which in itself is a detailed and vast topic

Hence XYZ will also be an equilateral triangle

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Answer:

524

Step-by-step explanation:

First find the number we want to find

532 - 308 = 224

Set blank -300 equal to the number

blank - 300 = 224

Add 300 to each side

blank -300+300 = 224+300

blank = 524

Answer:

a. 35 people participated in the walk.

b. About 16 people traveled more than 14 kilometers.

Step-by-step explanation:

(Warning: This may be wrong)

(a) The community will use approximately 1.21449 billion units of electricity 5 years from now.

(b) It will take approximately 35 years for the consumption to double.

(a) To calculate the electricity consumption of the community 5 years from now, we need to apply the annual growth rate of 2% to the current consumption of 1.1 billion units.

The formula to calculate the future value with a constant growth rate is:

Future Value = Present Value * (1 + Growth Rate/100)^Number of Years

Let's calculate the future value:

Future Value = 1.1 billion * (1 + 2/100)⁵

Future Value = 1.1 billion * (1.02)⁵

Future Value ≈ 1.1 billion * 1.10408

Future Value ≈ 1.21449 billion

Therefore, the community will use approximately 1.21449 billion units of electricity 5 years from now.

(b) To find the number of years it will take for the consumption to double, we need to determine the time it takes for the initial consumption to increase by 100% or multiply by 2.

Let's set up the equation:

Future Value = Present Value * (1 + Growth Rate/100)^Number of Years

2 * Present Value = Present Value * (1 + 2/100)^Number of Years

Dividing both sides by Present Value:

2 = (1 + 2/100)^Number of Years

Taking the natural logarithm of both sides:

ln(2) = Number of Years * ln(1 + 2/100)

Number of Years = ln(2) / ln(1 + 2/100)

Using a calculator, we can determine the approximate value of Number of Years:

Number of Years ≈ 34.66

Therefore, it will take approximately 34.66 years for the consumption to double. Rounded to the nearest year, it will take about 35 years.

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Answer:

VW = 8

Step-by-step explanation:

Because this trapezoids are similar

PS : TW = PQ : TU = QR : UV = RS : VW

We can take for example this equation

QR : UV = RS : VW

6 : 4 = 12 : VW

6*VW = 4*12

VW = 4*12/6 = 8

Answer:  x = 8

Step-by-step explanation:

From all the other dimensions given, you can see that the small trapezoid's sides are each 2/3 of the large trapezoid.

6= 2/3(9) . 4= 2/3(6) .12= 2/3(18) .  so take 2/3(12) = 8

The answer would be B. -1 + (-9) = -10

Answer:

Step-by-step explanation:

yyes

To determine how far apart stress scores are within one of your groups in the study, you should look at the standard deviation. Optin C

The standard deviation measures the dispersion or spread of data points around the mean. A higher standard deviation indicates that the scores within the group are more spread out or farther apart, while a lower standard deviation suggests that the scores are closer together.

The mean (a) represents the average score of the group and does not provide information about the dispersion of the scores. The median (b) represents the middle value in the group and also does not directly measure the spread of scores. The substantial difference score (d) is not a commonly used statistical term and may not be relevant in this context.

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The area of the shaded region cannot be determined without additional information about the dimensions of the square.

To determine the area of the shaded region, we need additional information about the dimensions of the square. The length of AD alone is not sufficient to calculate the area.

We need either the length of one side of the square or the radius of the outer circle. With the length of one side of the square, we can calculate the area by squaring the side length. If we have the radius of the outer circle, we can calculate the area by subtracting the area of the square from the area of the circle.

However, without this information, we cannot accurately determine the area of the shaded region.

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Answer:

Step-by-step explanation:

Properties of an Isosceles Triangle

(Most of this can be found in Chapter 1 of B&B.)

Definition: A triangle is isosceles if two if its sides are equal.

We want to prove the following properties of isosceles triangles.

Theorem: Let ABC be an isosceles triangle with AB = AC.  Let M denote the midpoint of BC (i.e., M is the point on BC for which MB = MC).  Then

a)      Triangle ABM is congruent to triangle ACM.

b)      Angle ABC = Angle ACB (base angles are equal)

c)      Angle AMB = Angle AMC = right angle.

d)      Angle BAM = angle CAM

Corollary: Consequently, from these facts and the definitions:

Ray AM is the angle bisector of angle BAC.

Line AM is the altitude of triangle ABC through A.

Line AM is the perpendicular bisector of B

Segment AM is the median of triangle ABC through A.

Proof #1 of Theorem (after B&B)

Let the angle bisector of BAC intersect segment BC at point D.  

Since ray AD is the angle bisector, angle BAD = angle CAD.  

The segment AD = AD = itself.

Also, AB = AC since the triangle is isosceles.

Thus, triangle BAD is congruent to CAD by SAS (side-angle-side).

This means that triangle BAD = triangle CAD, and corresponding sides and angles are equal, namely:

DB = DC,

angle ABD = angle ACD,

angle ADB = angle ADC.

(Proof of a).  Since DB = DC, this means D = M by definition of the midpoint.  Thus triangle ABM = triangle ACM.

(Proof of b) Since angle ABD = angle ABC (same angle) and also angle ACD = angle ACB, this implies angle ABC = angle ACB.

(Proof of c) From congruence of triangles, angle AMB = angle AMC.  But by addition of angles, angle AMB + angle AMC = straight angle = 180 degrees.  Thus 2 angle AMB = straight angle and angle AMB = right angle.

(Proof of d) Since D = M, the congruence angle BAM = angle CAM follows from the definition of D.  (These are also corresponding angles in congruent triangles ABM and ACM.)

QED*

*Note:  There is one point of this proof that needs a more careful “protractor axiom”.  When we constructed the angle bisector of BAC, we assumed that this ray intersects segment BC.  This can’t be quite deduced from the B&B form of the axioms.  One of the axioms needs a little strengthening.

The other statements are immediate consequence of these relations and the definitions of angle bisector, altitude, perpendicular bisector, and median.  (Look them up!)

Definition:  We will call the special line AM the line of symmetry of the isosceles triangle.  Thus we can construct AM as the line through A and the midpoint, or the angle bisector, or altitude or perpendicular bisector of BC. Shortly we will give a general definition of line of symmetry that applies to many kinds of figure.

Proof #2 (This is a slick use of SAS, not presented Monday.  We may discuss in class Wednesday.)

The hypothesis of the theorem is that AB = AC.  Also, AC = AB (!) and angle BAC = angle CAB (same angle).  Thus triangle BAC is congruent to triangle BAC by SAS.

The corresponding angles and sides are equal, so the base angle ABC = angle ACB.

Let M be the midpoint of BC.  By definition of midpoint, MB = MC. Also the equality of base angles gives angle ABM = angle ABC = angle ACB = angle ACM.  Since we already are given BA = CA, this means that triangle ABM = triangle ACM by SAS.

From these congruent triangles then we conclude as before:

Angle BAM = angle CAM (so ray AM is the bisector of angle BAC)

Angle AMB = angle AMC = right angle (so line MA is the perpendicular bisector of  BC and also the altitude of ABC through A)

QED

Faulty Proof #3.  Can you find the hole in this proof?)

In triangle ABC, AB = AC.  Let M be the midpoint and MA be the perpendicular bisector of BC.

Then angle BMA = angle CMA = right angle, since MA is perpendicular bisector.  

MB = MC by definition of midpoint. (M is midpoint since MA is perpendicular bisector.)

AM = AM (self).

So triangle AMB = triangle AMC by SAS.

Then the other equal angles ABC = ACB and angle BAM = angle CAM follow from corresponding parts of congruent triangles.  And the rest is as before.

QED??

Yes, This statement is valid.

A triangle is a three sided polygon, which has three vertices and three angles which has the sum 180 degrees.

Given that;

The two sides of a triangle are congruent.

Then, In ΔABC;

⇒ AB ≅ BC

So, ΔABC is isosceles.

Now,

Since, The two sides of a triangle are congruent.

We know that;

In a triangle if two sides are equal then it is an Isosceles triangle.

So, The given statement '' ΔABC is isosceles'' is valid.

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The relation r is reflexive and symmetric, but not transitive. In order to determine if the relation r is reflexive, symmetric, and transitive, we need to check certain conditions.

Reflexive: For every element, a in the set A, (a, a) is in the relation r. In this case, we have (a, a), (b,b), and (c,c) in the relation r, so r is reflexive.

Symmetric: If (a,b) is in the relation r, then (b, a) must also be in the relation r. In this case, we have (a,b), (a,c), (b,b), (c,b), and (b,c) in the relation r, so (b, a), (c, a), (b,b), (b,c), and (c,b) must also be in the relation r. Therefore, r is symmetric.

Transitive: If (a,b) and (b,c) are in the relation r, then (a,c) must also be in the relation r. In this case, we have (a,b), (a,c), (b,b), (c,b), and (b,c) in the relation r. However, (a,c) is not in the relation r since there is no (a,x) and (x,c) such that (a,x) and (x,c) are both in the relation r. Therefore, r is not transitive.

In summary, the relation r is reflexive and symmetric, but not transitive.

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The z score of a dog of this breed weighs 52 pounds is 0.571. The weight of the dog if z is -0.35 is 45.55 kg. The weight of the dog if z is 0.35 is 50.45 kg.

A z score refers to a numerical measurement that defines a value's relationship to the mean of a group of values. Z-score is measured in terms of standard deviations from the mean. If a Z-score is 0, it indicates that the data point's score is identical to the mean score.

The z score is given by:

z = (x - µ)/σ

where x is the raw score, µ is the mean, and σ is the standard deviation.

In the given case,

x = 52 pounds

µ = 48 pounds

σ = 7 pounds

Hence,

z = (52 - 48)/7 = 0.571

If z = -0.35

Then

-0.35 = (x - 48)/7

x - 48 = -2.45

x = 45.55 kg

Hence, the weight of the dog if z is -0.35 is 45.55 kg.

If z = 0.35

Then

0.35 = (x - 48)/7

x - 48 = 2.45

x = 50.45 kg

Hence, the weight of the dog if z is 0.35 is 50.45 kg.

Note: The question is incomplete. The complete question probably is: The weights of a certain dog breed are approximately normally distributed with a mean of 48 pounds, and a standard deviation of 7 pounds. A dog of this breed weighs 52 pounds. What is the dog's z-score? Round your answer to the nearest hundredth as needed. A dog has a z-score of -0.35. What is the dog's weight? Round your answer to the nearest tenth as needed. pounds A dog has a z-score of 0.35. What is the dog's weight? Round your answer to the nearest tenth as needed. pounds

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The area of the computer monitor display is approximately 0.103 square meters, with three significant figures.

The area of the monitor display in square meters is found by converting the measurements from inches to meters and then calculate the area.

The conversion factor from inches to meters is 0.0254 meters per inch.

Width in meters = 14.60 inches * 0.0254 meters/inch

Height in meters = 10.95 inches * 0.0254 meters/inch

Area = Width in meters * Height in meters

We calculate the area:

Width in meters = 14.60 inches * 0.0254 meters/inch = 0.37084 meters

Height in meters = 10.95 inches * 0.0254 meters/inch = 0.27813 meters

Area = 0.37084 meters * 0.27813 meters = 0.1030881672 square meters

Now, we determine the number of significant figures.

The measurements provided have four significant figures (14.60 and 10.95). However, in the final answer, we should retain the least number of significant figures from the original measurements, which is three (10.95). Therefore, the answer should have three significant figures.

Thus, the area of the monitor display in square meters is approximately 0.103 square meters, with three significant figures.

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the critical value zα/2 that corresponds to an 80% confidence level is approximately 1.2816.

To find the critical value zα/2 that corresponds to an 80% confidence level, we need to determine the value of α/2.

A confidence level of 80% implies that the remaining area under the standard normal distribution curve is (1 - 0.80) = 0.20.

Since the standard normal distribution is symmetric, we divide this remaining area equally between the two tails, resulting in

α/2 = 0.10.

To find the corresponding critical value, we look up the z-score that corresponds to an area of 0.10 in the standard normal distribution table (also known as the z-table) or use a statistical calculator.

The critical value zα/2 for α/2 = 0.10 is approximately 1.2816.

Therefore, the critical value zα/2 that corresponds to an 80% confidence level is approximately 1.2816.

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The expected value of the continuous random variable V is 5. The expected value of V is 5, indicating that, on average, we expect the value of V to be around 5.

To calculate the expected value of a continuous random variable V with a given probability density function (PDF), we integrate the product of V and the PDF over its entire range.

The PDF of V is defined as:

f(v) = 6/24 = 0.25 for 3 ≤ v ≤ 7, and 0 otherwise.

The expected value of V, denoted as E(V), can be calculated as:

E(V) = ∫v * f(v) dv

To find the expected value, we integrate v * f(v) over the range where the PDF is non-zero, which is 3 to 7.

E(V) = ∫v * (0.25) dv, with the limits of integration from 3 to 7.

E(V) = (0.25) * ∫v dv, with the limits of integration from 3 to 7.

E(V) = (0.25) * [(v^2) / 2] evaluated from 3 to 7.

E(V) = (0.25) * [(7^2 / 2) - (3^2 / 2)].

E(V) = (0.25) * [(49 / 2) - (9 / 2)].

E(V) = (0.25) * (40 / 2).

E(V) = (0.25) * 20.

E(V) = 5.

Therefore, the expected value of the continuous random variable V is 5.

The expected value represents the average value or mean of the random variable V. It is the weighted average of all possible values of V, with each value weighted by its corresponding probability. In this case, the expected value of V is 5, indicating that, on average, we expect the value of V to be around 5.

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The cost equation is used to estimate total costs associated with a given level of activity or output, where f is the fixed cost and v is the variable cost per unit of activity. The variable cost component (vx) changes in proportion to the level of activity or output (x), whereas the fixed cost component (f) remains constant regardless of the level of activity.

In the cost equation tc = f + vx, x is best described as the level of activity or the quantity of the input variable. The cost equation is a mathematical representation of the relationship between the total cost of production and the level of activity or the quantity of the input variable. The variable x represents the number of units produced or the amount of resources used in the production process, which can be measured in terms of labor hours, machine hours, or any other relevant unit of measure. The variable v represents the variable cost per unit of activity, and f represents the fixed cost of production.

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