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A 14 V battery powers the headlights of a car. What is the resistance of the
headlights if they draw 3.0 A of current when turned on?

Answer:

I think the answer would be b, sorry if I'm wrong(EDIT: ITS ACTUALLY AAAAA)

The radioactive isotope Technium-99 decays most likely through alpha decay (99tc). An atomic nucleus emits an alpha particle during the radioactive decay process known as "alpha decay".

and then changes or "decays" into a separate atomic nucleus with a mass number that is decreased by four and an atomic number that is decreased by two. The nucleus of an atom of helium-4 is the same as an alpha particle. Radioisotopes are an element's radioactive isotopes. They are the atoms with unstable neutron-proton combinations or excess energy in their nuclei. During those processes, the radionuclide is said to experience radioactive decay, albeit the surplus energy may be put to use in any number of ways.

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Answer:serch it up i found it on the second website

Explanation:

The liquidus line separates the following combinations of phase fields: Liquid and Liquid + alpha. The correct option is b.

What is a phase field? A phase field is a technique for representing the microstructure of materials. It is used in materials science, mathematics, and computer science to simulate and study the behavior of materials in the solid and liquid phases. It is a multi-component field that contains information on the concentration of various components, their phase, and the local temperature, as well as other relevant variables.

The liquidus line is defined as the boundary between the liquid phase field and the field that includes both the liquid and the alpha phase. As a result, the liquidus line separates the following combinations of phase fields: Liquid and Liquid + alpha.

So, the correct option is b) Liquid and Liquid + alpha.

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Temperature factor plays the most important role in the decomposition reaction of magnesium oxide.

Those reactions which are exothermic in nature or release heat during the reaction are spontaneous reactions.

Given decomposition reaction of magnesium oxide is:

MgO(s) + 601.7 kJ → Mg(s) + ½ O₂(g)

From the above reaction, it is clear that during the decomposition of magnesium oxide heat is absorbed. So, for the feasible decomposition of compound accurate temperature is wanted.

Hence, correct option is temperature.

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Answer:

temperature

A.

Explanation:

edgen

The ΔU for candy is  35.68kJ/g.

The HHV of a biomass fuel is calculated using a bomb calorimeter, which measures the heat released during the combustion of a specific amount of biomass sample. Following each test, a small amount of sample fuel is ground and diluted so that it will fit inside a capsule and be used in a bomb.

Mass of Candy = 0.2g

Mass of water = 2000 g

specific heat of water = 4.184 5g⁻¹°c⁻¹

Initial temperature = 25.00°C

final  temperature = 25.47°C

Change in temperature = final- Initial

Change in  temperature = 25.47-25.00

ΔT = 0.47°C

specific heat of calorimeter = 700J/k

Thus, Heat produced by the combustion of candy is absorbed by water and calorimeter.

Hence,

ΔU = Heat absorbed by water +  Heat absorbed by calorimeter

ΔU = mass × specific heat × ΔT + specific heat × ΔT

ΔU = 2000 × 4.184 × 0.79 + 700 × 0.79

ΔU = 6.604 kJ + 0.532kJ

ΔU = 7.136kJ.

Thus, 0.2g of candy produced heat = 7.136kJ

1g of candy produced heat = 7.136/0.2 = 35.68kJ/g

Thus ΔU for candy =  35.68kJ/g.

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Induced dipole intermolecular force is mainly responsible for the boiling point difference between cyclohexane and decalin. Correct answer: letter D.

The difference in boiling point between cyclohexane and decalin is due to the fact that decalin has a longer chain of carbon atoms and therefore has a larger surface area. This larger surface area allows for more intermolecular forces to be formed, specifically induced dipole forces.

These dipole forces are created when the electrons of one molecule are attracted to the nucleus of another molecule, giving rise to a temporary dipole. This attraction between molecules is much stronger than the London dispersion forces that exist in cyclohexane, thus creating a higher boiling point in decalin.

Which intermolecular force do you think is primarily responsible for the difference in boiling point between cyclohexane and decalin?

A) Dipole-Dipole

B) Hydrogen bonding

C) Covalent

D) Induced Dipole

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Answer:

A

Explanation:

HCl and NaOH is a strong acid and strong base, respectively, and hence dissociates completely and reacts to form water:

\(\displaystyle \text{H}_\text{(aq)}^+ + \text{OH}_\text{(aq)}^- \longrightarrow \text{H$_2$O}_\text{($\ell$)}\)

We are given that 25.0 mL of 0.333 M NaOH was used to neutralize 15.0 mL of HCl.

Convert from moles of NaOH used to moles of HCl reacted:
\(\displaystyle \begin{aligned} 25.0\text{ mL} & \cdot \frac{0.333\text{ mol NaOH}}{1\text{ L}} \cdot \frac{1\text{ L}}{1000\text{ mL}} \cdot \frac{1\text{ mol OH}^-}{1\text{ mol NaOH}}\cdot \\ \\ & \cdot\frac{1\text{ mol H}^+}{1\text{ mol OH}^-} \cdot \frac{1\text{ mol HCl}}{1\text{ mol H}^+}\\ \\ & = 8.33\times 10^{-3}\text{ mol HCl}\end{aligned}\)

Therefore, the molarity of the original HCl solution is:
\(\displaystyle \begin{aligned} \ [\text{HCl}] & = \frac{\text{ mol HCl}}{\text{L soln.}} \\ \\ & =\frac{8.33\times 10^{-3}\text{ mol HCl}}{15.0\text{ mL}} \cdot \frac{1000\text{ mL}}{1\text{ L}} \\ \\ & = 0.555\text{ M}\end{aligned}\)

In conclusion, our answer is A.

25.898 g is the amount of magnesium nitride and magnesium oxide formed.

Step1 2Mg(s)+ O2(g)-----> 2 MgO(s)

3Mg(s)+N2(g)------> Mg3N2(s)

Mg3N2(s)+ 6 H2O(l)---> 3Mg(OH)2 + 2 NH3(g)

Step2 Moles of NH3 = (2.813/17)

Moles of Mg3N2= (1/2) Moles of NH3 = (2.813/2x17)= 2.813/34

Mass of Mg3N2 = (2.813/34) x100 =8.274g (Molar mass of Mg3N2=100)

Step3 Mass of Mg in Mg3N2 =(72/100) x8.274 =5.957g

Mass of Mg converted in MgO= 21.496-5.957=15.539

Moles of MgO= Moles of Mg = 15.539/24

Mass of MgO = 15.539x40/24 =25.898 g.

Magnesium is a cofactor for over 300 enzymatic systems that regulate various biochemical reactions in the body, including protein synthesis, muscle and nerve function, glycemic control, and blood pressure regulation [1-3].

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Answer:The empirical formula for this vitamin : C₃H₄O₃

Further explanation  

The empirical formula is the smallest comparison of atoms of compound =mole ratio of the components

The principle of determining empirical formula

Determine the mass ratio of the constituent elements of the compound.  

Determine the mole ratio by dividing the percentage by the atomic mass

Mass of C in CO₂ :(MW C = 12 g/mol, CO₂=44 g/mol)

Mass of H in H₂O :(MW H = 1 g/mol, H₂O = 18 g/mol)

Mass O = Mass sample - (mass C + mass H) :

mol ratio C : H : O =

Explanation:

Answer:

First Blank: 656.3 kJ

Second Blank: Endothermic

Explanation:

Edge 21'

Answer:

1.  656.3

2.  endothermic

Explanation:

Answer:

literss

Explanation:

on edge

The concentration of the dilute solution 1.76 M (option B).

The given information are :

Molarity of original solution of HCl is 6.00 M

Volume of original solution of HCl is 25.00 ml

Volume of the dilute solution is 85.00 ml

To determine the concentration of the dilute solution, we will use the dilution formula which is :

C₁V₁ = C₂V₂ where, C₁ = initial concentration of the solution ; V₁ = initial volume of the solution ;

C₂ = final concentration of the solution ; V₂ = final volume of the solution

Substituting the given values ,

6.00 M × 25.00 ml = C₂ × 85.00 ml

C₂ = (6.00 M × 25.00 ml) / 85.00 ml

C₂ = 1.76 M

Therefore, the concentration of the dilute solution is 1.76 M (option B).

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The amount of copper deposited is 0.1778 grams.

The electrolysis reaction for CuSO₄ solution

Copper deposits will occur at the cathode. According to Faraday's law the number of moles of an electron

ne = It ÷ 96,500

ne = (0.450 × 1,200) ÷ 96,500

ne = 540 ÷ 96,500

ne = 5.6 × 10⁻³ mol

The ratio of the coefficients of each element is equal to the ratio of the number of moles.

ne : n Cu = 2 : 1

n Cu = ne ÷ 2

n Cu = (5.6 × 10⁻³) ÷ 2

n Cu = 2.8 × 10⁻³ mol

Calculate the amount of copper

The molar mass for copper = 63.5

m = n × molar mass

m = 2.8 × 10⁻³ × 63.5

m = 0.1778 grams

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Answer:

180 g/mol.

Explanation:

What is given?

ΔT = [0 - (- 1.86 )] °C = 1.86 °C.

i = 1 (for a nonelectrolyte).

Kf = 1.86 °C/m.

Step-by-step solution:

To solve this problem, we have to use the boiling point elevation formula, which is the following:

Where ΔT is the change in boiling point, i is the Van't Hoff factor, m is the molality of solution, and Kf is the molal boiling point constant.

Let's calculate the molality with the given data:

1 m is the same that 1 mol/kg. As we have 1.00 g of water and 180.0 mg of the sugar, we can multiply 1 mol/kg by the mass of water. Remember that 1 kg equals 1000 g, so 1.00 g is the same that 0.001 kg:

Remember that the units of the molar mass is in g/mol, and 1 g equals 1000 mg, so 180.0 mg is the same that 0.18 g. If we divide 0.18 g by 0.001 mol, we will obtain the molar mass of the sugar, which would be:

The answer would be that the molar mass is 180 g/mol.

Explanation:

3 C

4 C because bonds of non-metal to non-metal N to O

5 I because metal ion loss valence electron Ca2+ non-metal gains valence electron F-

Answer:

Gas Pressure

Explanation:

Gas pressure is caused by the force exerted by gas molecules colliding with the surfaces of objects (Figure 5.2. 1). Although the force of each collision is very small, any surface of appreciable area experiences a large number of collisions in a short time, which can result in a high pressure.

Answer:

Collisions

Explanation:

It says that it was the answer.

Answer:

Helium (He)

Explanation:

An atom with two protons is always a helium atom. Hydrogen atom regards to atoms with 1 proton. If scientists count four protons in an atom, they know it's a beryllium atom. An atom with three protons is a lithium atom, an atom with five protons is a boron atom, an atom with six protons is a carbon atom, etc.

Answer: Calcium ion Ca² : 1 s² 2s² 2p ^6 (sorry I don't get 6 similar way as 2) 3s² 3p^6

Also 18 electrons, because Calcium donates two 4s electrons

Explanation:

At equivalence, the number of moles of methylamine and HCl are equal, and the pH of the solution is 4.76.

At equivalence, the number of moles of methylamine and HCl are equal, so we can use the equation:

n(CH3NH2) = n(HCl)

0.2108M * 110.0mL = 0.4152M * V

V = 52.4mL

Total volume of the solution: 110.0mL + 52.4mL = 162.4mL

We can use the Henderson-Hasselbalch equation to calculate the pH at equivalence:

pH = pKb + log([CH3NH2]/[HCl])

pH = 3.36 + log(0.2108M/(0.2108M + 0.4152M))

pH = 3.36 + log(0.2108M/(0.6259M))

pH = 3.36 + log(0.3389)

pH = 3.36 + (-0.4719)

pH = 4.76

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Answer:

C6H12O6 is the product.

Explanation:

As C6H12O6 is on the right side of the arrow, it indicates that C, H2, and O2 are all reacting with each other to produce (or form) C6H12O6. This means that C6H12O6 is the product in this specific reaction.

\(C_6H_{12}O_6\) is the product where 6 carbon, 12 hydrogens and 6 oxygen are there.

Elements are the simplest substances which cannot be broken down using chemical methods.

As \(C_6H_{12}O_6\) is on the right side of the arrow, it indicates that C, \(H_2\), and \(O_2\) are all reacting with each other to produce (or form) \(C_6H_{12}O_6\). This means that \(C_6H_{12}O_6\) is the product in this specific reaction:

\(C+H_2+O_2\) → \(C_6H_{12}O_2\)

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Elements with unpaired electrons are known as paramagnetic elements.  Paramagnetic elements, which have at least one unpaired electron in their outermost shell and can be easily influenced by an external magnetic field.

Paramagnetic elements are those which have at least one unpaired electron in their outermost shell. These unpaired electrons can be easily influenced by an external magnetic field and can become magnetized, thus exhibiting paramagnetism.

Hence, In summary, elements with unpaired electrons are referred to as paramagnetic elements, which have at least one unpaired electron in their outermost shell and can be easily influenced by an external magnetic field.

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The mass of hydrogen reacted with nitrogen to give ammonia is 0.1 grams.

Mass of any substance will be calculated by using the moles as:

n = W/M, where

W = required mass

M = molar mass

Given chemical reaction is:

3H₂ + N₂ → 2NH₃

Moles of 0.575 g of NH₃ will be calculated as:

n = 0.575g / 17.03g/mol = 0.033 moles

From the stoichiometry of the reaction, it is clear that:

2 moles of NH₃ = produced by 3 moles of H₂

0.033 moles of NH₃ = produced by 3/2×0.033=0.0495 moles of H₂

Now we calculate the mass of hydrogen from the given moles and molar mass as:
W = (0.0495mol)(2.0158g/mol) = 0.09 grams = 0.10 grams

Hence, option (a) is correct i.e. 0.1 grams.

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So,

First of all, there are too many types of intermolecular forces:

1. Dispersion forces: London dispersion force is a weak intermolecular force between two atoms or molecules in close proximity to each other. The force is a quantum force generated by electron repulsion between the electron clouds of two atoms or molecules as they approach each other. Every molecules have this kind of force.

2. Dipole: Dipole-dipole forces are attractive forces between the positive end of one polar molecule and the negative end of another polar molecule. They are much weaker than ionic or covalent bonds and have a significant effect only when the molecules involved are close together (touching or almost touching).

3. Hydrogen-bonding: Hydrogen bonding is a special type of dipole-dipole attraction between molecules, not a covalent bond to a hydrogen atom. It results from the attractive force between a hydrogen atom covalently bonded to a very electronegative atom such as a N, O, or F atom and another very electronegative atom.

Let's begin with hypobromous acid (HBrO).

HBrO is a compound that can form Hydrogen bonds since there's a hydrogen atom bonded to an Oxygen atom.

This compound also presents dispersion forces since atoms are close to each other.

And, there's also dipole-dipole forces because as you can see, there's a positive end (H+) and a negative end (BrO-).

Now, let's analyze SiH4:

SiH4 is composed of molecules, for which the only intermolecular forces are London dispersion forces.

There's no Hydrogen Bonding because Hydrogen can't bond to a very electronegative element such as O, N or F.

As you see, Si is not a very electronegative element.

And, there's not dipole-dipole forces because there's not a positive or a negative end. In this compound, H and Si share all their electrons but there's not any charges when they are close together.

Let's check now Oxygen difluoride (OF2):

As you can notice, London dispersion forces are present in all compounds, so, this is the first force identified.

Now, there's not Hydrogen, so, this molecule can't form Hydrogen-Bonds with itself.

If we look at the dipole-dipole forces, we can clearly notice that OF2 is a bent polar molecule. That means that it actually has this kind of force.

And, finally, carbon monoxide (CO):

Because CO is a polar molecule, it experiences dipole-dipole attractions.

We also know that there's London dispersion forces.

There's no Hydrogen Bonding in this molecule.

7 moles of oxygen are in the sample.

According to the chemical formula, each mole of nickel tetracarbonyl contains 4 moles of C atoms. Simply convert it into a fraction by putting the original solution in the denominator and the diluted solution in the numerator if you need to determine the concentration ratio between two solutions. The V/n ratio for each gas must be the same if the two gases are at the same temperature and pressure. The volume ratio of two gases at the same temperature and pressure is equal to their molar ratio. The mole ratio of C to O is 1 : 1

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