Ordering number from least to greatest. HELP

As is clear from the map's greatest contour value of 6485 feet, poorman Hill's peak elevation is 6485 feet. This contour value corresponds to Poorman Hill.

The angle formed by the line of sight and the horizon is known as elevation. The angle created, if the line of sight is above the horizon, is the elevation angle.

Wonderland Lake has an estimated elevation of 5500 feet since it is located close to a ridge where some of the peaks have contour values as high as 6600 feet and the lake is on a lower contour that is close to that height. As is clear from the map's greatest contour value of 6485 feet, poorman Hill's peak elevation is 6485 feet. This contour value corresponds to Poorman Hill.

Poorman Hill has an elevation of around 6485 feet, according to the map, although Boulder Creek, which is located to the south of Poorman Hill, has an elevation of less than 6000 feet. As a result, poorman Hill is higher in elevation than the boulder Creek bank.

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Answer:

see explanation

Step-by-step explanation:

Under a rotation about the origin of 180°

a point (x, y ) → (- x, - y ) , then

A (- 5, - 8 ) → A' (5, 8 )

B (2, - 3 ) → B' (- 2, 3 )

C (- 2, 9 ) → C' (2, - 9 )

If a t-distribution with 20 degrees of freedom is used to test a hypothesis with a Type I error value of 5%, then the critical t-value corresponding to the given significance level is 1.725.

The critical t-value is the value beyond which we reject the null hypothesis in a t-test. The value is determined by the significance level (Type I error) and the degrees of freedom.

In this case, with a significance level of 5% and 20 degrees of freedom, the critical t-value is 1.735. This means that if the calculated t-value for a sample falls beyond 1.735, we reject the null hypothesis at the 5% level of significance.

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The values of constants are b = -6 and c = 8

The values of x are log base 4 of 3 or log base 4 of 5

Given equation,

(4^x-1) ²- 6(4^x-1) + 8 = 0

Let this equation be f(x) i.e., f(x) = (4^x-1) ²- 6(4^x-1) + 8 (equation 1)

In question it's mentioned that y = 4^x-1

Now substitute this 'y' value in equation 1. We get,

f(y) = y ²- 6y + 8 (Here, f(x) changed to f(y) because the equation now is in terms of y)

It's in form of y² + by + c = 0 where b = -6 and c = 8

Factorizing f(y),

y ²- 6y + 8 = 0

y ²- 4y -2y + 8 = 0 (Since, -6 = -4 -2)

y(y - 4) -2(y - 4) = 0

(y - 2)(y - 4) = 0

So, y = 2 or 4

i.e., 4^x-1 = 2 or 4

if 4^x-1 = 2 then

4^x-1 = 2

4^x = 3

x = log base 4 of 3

else (i.e., 4^x-1 = 4)

4^x-1 = 4

4^x = 5

x = log base 4 of 5

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Answer:-2 -4 for point b

Step-by-step explanation:

The average score of all students, calculated by taking a weighted average based on the number of students in each group, is 38. The overall performance is slightly below the group averages.

The average score of students in the first, second, and third groups are 39, 32, and 43, respectively. There are 24 students in the first group, 26 students in the second group, and 27 students in the third group.

To find the average score of all students, we need to take a weighted average of the scores in each group, with the number of students in each group as the weights.

Here's how to do it: First, we calculate the total number of students:24 + 26 + 27 = 77. Then, we calculate the total score across all students: 39*24 + 32*26 + 43*27 = 936 + 832 + 1161 = 2929

Finally, we divide the total score by the total number of students to get the average score:2929/77 = 38. The average score of all students is 38.

This means that the overall performance of all the students is slightly below the average of the scores in each group.

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A characteristic of a real number line is an order relation that is transitive. Therefore, this is a false statement, "Not a characteristic of a real number line.

"In mathematical terms, a real number line is defined as a geometric line on which each point corresponds to a unique real number and conversely, each real number is represented by a unique point. In other words, we can map each real number to a point on the number line and vice versa.Each point on a real number line is called a real number and a real number can be represented as an ordered pair of numbers (x,y).In the same way, the real number line has certain characteristics which are:Transitivity of Order Relation.Completeness.Archimedean Property.Origin Symmetry.The characteristic which is not a characteristic of a real number line is "Not transitive."

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The statement that is not a characteristic of a real number line is "It can only be used to represent whole numbers."A real number line is a line that is used to represent real numbers.

It is one of the most important mathematical concepts, as it is used in various fields of mathematics and science. It is a straight line that goes in both directions, has a zero at the middle point, and is infinitely long. Real numbers are represented on the number line with dots and are usually written with their decimal or fraction forms.A real number line has several characteristics, which include the following:

It is infinitely long, which means that it has no end. It extends indefinitely in both directions.

The midpoint of the number line is zero, which is neither positive nor negative. It is a neutral value.It is a one-dimensional line that has no thickness or width.Each point on the line represents a unique real number.A real number line can be used to represent both positive and negative numbers as well as zero.Any point on the number line can be used to divide it into two halves. This is known as the division property.Each real number on the line is associated with a unique coordinate value known as the ordered pair (x, y).It can be used to represent rational and irrational numbers as well as whole numbers. Therefore, the statement that is not a characteristic of a real number line is "It can only be used to represent whole numbers."

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Answer:

\(\text{Perimeter}=8x^2+14x-5\)

Step-by-step explanation:

\(\text{Perimeter}=(7x-4)+(3x^2+7x-1)+(5x^2)\\\text{Perimeter}=7x-4+3x^2+7x-1+5x^2\\\text{Perimeter}=5x^2+3x^2+7x+7x-4-1\\\text{Perimeter}=8x^2+14x-5\)

Antawan's solution is the absolute value of Maggie's solution is the solution related to Antawan's and Maggie's solution.

Given

Antawan determines the distance between two points as 9.

Maggie finds the difference between two numbers ₋ 7 ₋ 2 = ₋9

Hence we notice that Antawan's solution is the absolute value to the Maggie's solution.

The non-negative value of x, regardless of its sign, is the absolute value (or modulus) | x | of a real number x. For instance, 5 has an absolute value of 5 and so does 5, which likewise has an absolute value of 5. One way to conceptualize a number's absolute value is as its separation from zero on the real number line.

hence option 2 is right.

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Answer:

\( x = \dfrac{-1 \pm \sqrt{11}}{2} \)

Step-by-step explanation:

(2x - 3)² - 14 = 2x(x - 7)

4x² - 12x + 9 - 14 = 2x² - 14x

2x² + 2x - 5 = 0

\( x = \dfrac{-2 \pm \sqrt{2^2 - 4(2)(-5)}}{2(2)} \)

\( x = \dfrac{-2 \pm \sqrt{4 + 40}}{4} \)

\( x = \dfrac{-2 \pm 2\sqrt{11}}{4} \)

\( x = \dfrac{-1 \pm \sqrt{11}}{2} \)

Considering concepts of divisibility, the amount of numbers in the set that are divisible by 2 but not by 10 is:

(C) 19.

The data-set has (55 - 10) + 1 = 46 numbers, hence 23 are divisible by 2. 20, 30, 40 and 50 are also divisible by 10, that is, 4 numbers have to be removed, hence the amount is:

23 - 4 = 19.

Which means that option C is correct.

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The following is an assembly program that calculates the value of the given polynomial, assuming signed integers x and y are stored in register r2 and r3, respectively.

\(```.LIST.ALIGN 4    .GLOBAL _start_start:    PUSH {R4, R5, LR}\)
   \(MOV R4, R2        // R4 < - x    MOV R5, #2        // R5 < - 2\)\(MUL R4, R4, R4    // R4 < - x^2    MUL R4, R4, R5    // R4 < - 2x^2    MOV R5, #3        // R5 < - 3\)
  \(ADD R4, R4, R5, LSL #16    // R4 < - 2x^2 + 3x^2    MOV R5, #5        // R5 < - 5    MUL R5, R5, R2    // R5 < - 5x\)
  \(SUB R4, R4, R5, LSL #16    // R4 < - 2x^2 + 3x^2 - 5x    MOV R5, #11       // R5 < - 11    SUB R4, R4, R5, LSL #16    // R4 < - 2x^2 + 3x^2 - 5x - 11\)
  \(MOV R3, R4        // R3 < - y    POP {R4, R5, PC}.END```\)

Explanation: The polynomial is given as

\(`y = 2x^4 + 3x^2 - 5x - 11`.\)

To calculate this polynomial in assembly language, we need to perform the following steps:

Load the value of `x` into a register. We assume that `x` is stored in register `r2`.

Calculate \(`2x^2`\) and add \(`3x^2`\) to it. We first square the value of `x` by multiplying it with itself and then multiply it with `2`. We then add \(`3x^2`\) to this result. We store this result in register `r4`.

Calculate `5x` and subtract it from the result of step 2. We first multiply the value of `x` with `5` and then subtract it from the result of step 2. We store this result in register `r4`.

Subtract `11` from the result of step 3. We subtract `11` from the result of step 3 and store this result in register `r4`.

Load the value of `y` into a register. We assume that `y` is stored in register `r3`.

Return from the subroutine. We pop the registers from the stack and return from the subroutine.

The assembly program that is used to calculate the value of a given polynomial assuming signed integers x and y are stored in registers r2 and r3, respectively. The polynomial given is\(y = 2x4 + 3x² - 5x - 11\). In this assembly program, we load the value of x into a register, calculate 2x^2, add 3x^2 to it, subtract 5x from the result, and subtract 11 from the final result. The value of y is then stored in a register, and we return from the subroutine.

This assembly program is designed for 32-bit ARM architecture, and it can be run on any ARM processor. The program is written in ARM assembly language, which is a low-level programming language used to write programs that run on ARM processors. It is a complex language that requires a deep understanding of the processor architecture and instruction set.

In conclusion, the assembly program presented here can be used to calculate the value of a given polynomial using signed integers x and y stored in registers r2 and r3, respectively. This program can be adapted to calculate other polynomials or perform other arithmetic operations on ARM processors. It is a powerful tool for low-level programming and optimization, but it requires a significant amount of expertise to write and debug.

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The mean is lower than the mode which is lower than the median.

A skewed curve is a type of statistical distribution in which the data is unevenly distributed. It is often referred to as an asymmetric distribution, meaning that the two halves of the curve look different. Skewed curves can be either positively or negatively skewed, depending on which direction the data points are shifted. Positively skewed curves tend to have a long tail to the right, while negatively skewed curves have a long tail to the left. This type of distribution is commonly seen in real-world data, such as income or wealth distributions.

A negatively skewed curve is characterized by a tail on the negative side of the graph. This means that the data points have a higher probability of being lower than the mean. As such, the mean is lower than the mode, which is lower than the median. The mean is the arithmetic average of all of the data points, the mode is the most frequent value, and the median is the midpoint of the data points.

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The given statement "An algorithm is a calculation that determines how long it will take to solve a problem." is False.

An algorithm is not just a calculation that determines how long it will take to solve a problem. An algorithm is a step-by-step set of instructions or a process used to solve a problem or perform a specific task. It is a systematic approach that allows a computer or human to break down a problem into smaller, manageable parts and reach a solution effectively.

Algorithms are the foundation of computer programming and can be applied in various fields such as mathematics, data processing, and problem-solving. They can be simple, like finding the largest number in a list, or complex, like solving a Rubik's Cube.

Efficiency is a key factor in evaluating algorithms. The time and resources required for an algorithm to solve a problem can vary greatly depending on the method used. However, the primary purpose of an algorithm is to provide a clear and concise procedure to reach a solution, rather than just estimating the time needed to solve a problem.

In summary, an algorithm is a well-defined process designed to perform a specific task or solve a problem, rather than just calculating the time required to do so. Its effectiveness depends on its efficiency, accuracy, and the simplicity of the steps involved.

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Answer:

3/2

Step-by-step explanation:

Given: X ~ Exp(1/3) Mean and standard deviation:

The mean of an exponential distribution is equal to the reciprocal of the rate parameter, which in this case is 1/3. So, the mean (μ) is given by:

μ = 1 / (1/3) = 3

The standard deviation (σ) of an exponential distribution is also equal to the reciprocal of the rate parameter. Therefore, the standard deviation is also 1/3.

Mean (μ) = 3

Standard deviation (σ) = 1/3

P(x > 1):

To find P(x > 1), we need to calculate the cumulative distribution function (CDF) of the exponential distribution and subtract it from 1.

The CDF of an exponential distribution is given by:

F(x) = 1 - exp(-λx)

Since the rate parameter (λ) is 1/3 in this case, the CDF becomes:

F(x) = 1 - exp(-(1/3)x)

Therefore, to find P(x > 1), we evaluate the CDF at x = 1 and subtract it from 1:

P(x > 1) = 1 - F(1)

P(x > 1) = 1 - (1 - exp(-(1/3)(1)))

P(x > 1) = exp(-(1/3))

So, P(x > 1) is approximately 0.7165.

Minimum value for the upper quartile:

The upper quartile is the 75th percentile of the distribution. To find the minimum value for the upper quartile, we can use the quantile function of the exponential distribution.

The quantile function for an exponential distribution is given by:

Q(p) = -ln(1 - p) / λ

Since the rate parameter (λ) is 1/3 in this case, the quantile function becomes:

Q(p) = -ln(1 - p) / (1/3)

To find the minimum value for the upper quartile, we set p = 0.75 (75th percentile) and solve for Q(p):

Q(0.75) = -ln(1 - 0.75) / (1/3)

Q(0.75) = -ln(0.25) / (1/3)

Calculating this expression, the minimum value for the upper quartile is approximately 2.7726.

P(x = 1/3):

Since the exponential distribution is a continuous distribution, the probability of getting an exact value (such as x = 1/3) is zero. Therefore, P(x = 1/3) is equal to zero.

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The monthly budget for rent is $1,627.33 ≤ m ≤ $2,441.00

An equation is an expression that shows the relationship between two or more numbers and variables.

Let m represent the monthly rent of the shop.

The average yearly revenue is $195,280. Hence:

Monthly revenue = $195,280 / 12 = $16273.33

If the monthly budget for rent is 10%, hence:

m = 10% of $16273.33 = 0.1 * $16273.33 = $1627.33

If the monthly budget for rent is 15%, hence:

m = 15% of $16273.33 = 0.15 * $16273.33 = $2441.00

$1,627.33 ≤ m ≤ $2,441.00

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Answer:

C, B, A

Step-by-step explanation:

Who ever is reading this:

I love u.

U matter.

The world needs u

hang in there ik it may be bad but u deserve the world <3

ur beautiful no matter ur shape, size, color, gender.. anything

don't give up bby i need u to live.

i wish i could take everyones problems so yall wouldn't have to have em but i cant so just know ily and if anyone needs to talk u can talk to me

Pls pass this on. Everyone deserves to know this. ♥️♥️

just copy and paste its not hard pls this could save someones life

Answer:

The answer is C.) y = 2x + 5

Answer:

The factor pairs are: 1,16   2*8  and 4*4

Step-by-step explanation:

Factor pairs are the pairs of numbers that multiply to 16

1*16 = 16

2*8=16

4*4 = 16

The factor pairs are: 1,16   2*8  and 4*4

The type of transformation and scale factor as required are;

16) Rotation

17) Reflection

18) Dilation

19) n = 5

20)P = r = 4

There are different types of transformation as follows;

1) Translation: This type of translation is defined as moving the object in space by keeping its size, shape or orientation constant. In a translation, each point of the shape must be moved in the same direction and for the same distance

2) Dilation: This type of translation expands or contracts the object by keeping its orientation or shape the same. This is also known as resizing.

3) Rotation: This type of transformation has an object about a fixed point without changing its size or shape.

4) Reflection: This type of translation is called reflection because it flips the object across a line by keeping its shape or size constant.

16) This transformation is rotation based on the definitions above.

17) This type of transformation is a reflection as it is like the image was flipped across a line more like a mirror image.

18) This called dilation as the scale factor was adjusted to produce the new image.

19) Scale Factor = 6/3 = 2

Thus;

n = 10/2 = 5

20) Scale factor = 12/9 = 4/3

Thus;

P = r = 3 * 4/3

= 4

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The length of the minor arc of a circle with a given radius and central angle is approximately 12.7368 units.

What is the central angle?

A central angle is an angle with endpoints located on a circle's circumference and a vertex located at the circle's center. A central angle in a circle determines an arc.

The length of a minor arc of a circle with a given radius and central angle can be calculated using the formula:

length of arc = (central angle / 360 degrees) * 2 * π * radius

where π is the constant pi (approximately 3.14159), and the central angle is measured in degrees.

Substituting the given values, we get:

length of arc = (25 / 360) * 2 * π * 9.6

Simplifying, we get:

length of arc = (5 / 72) * π * 9.6

length of arc = 1.3258 * 9.6

length of arc ≈ 12.7368

Therefore, the length of the minor arc is approximately 12.7368 units.

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The probability that the committee will find no students with phones in the class is approximately 0.000250047.

To find the probability that the committee will find no students with phones in the class, we need to calculate the probability of none of the students being caught with a phone.

Given that 10% of the students have been caught with phones, we can assume that the probability of a student being caught with a phone is 0.10, and the probability of a student not being caught with a phone is 1 - 0.10 = 0.90.

Since we want to find the probability that no students are caught with phones, we need to calculate the probability of each student not being caught and multiply them together.

The probability that the committee will find no students with phones can be calculated as follows:

P(no students with phones) = (0.90)^54

Using this formula, we raise the probability of not being caught (0.90) to the power of the total number of students in the class (54).

P(no students with phones) = 0.90^54 ≈ 0.000250047

Therefore, the probability that the committee will find no students with phones in the class is approximately 0.000250047.

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The binomial distribution is applicable when only two outcomes are possible. The probability that the newspaper staff receives quotes from exactly 3 athletes is 0.1238.

A common discrete distribution is used in statistics, as opposed to a continuous distribution is called a Binomial distribution. It is given by the formula,

\(P(x) = ^nC_x p^xq^{(n-x)}\)

Where,

x is the number of successes needed,

n is the number of trials or sample size,

p is the probability of a single success, and

q is the probability of a single failure.

Given that 18 of the senior DLT members are athletes, therefore, the probability of a DLT member being an athlete is,

\(P = \dfrac{18}{30} = \dfrac{6}{10} = 0.6\)

Also, 12 of the senior DLT members are non-athletes, therefore, therefore, the probability of a DLT member being a non-athlete is,

\(q = \dfrac{12}{30} = \dfrac{4}{10} = 0.4\)

Now, using the binomial distribution the probability that the newspaper staff receives quotes from exactly 3 athletes can be written as,

\(P(x) = ^nC_x p^xq^{(n-x)}\\\\P(x=3) = ^8C_3\cdot (0.6)^3\cdot (0.4)^{(8-3)}\\\\P(x=3) = ^8C_3\cdot (0.6)^3\cdot (0.4)^{(5)}\\\\P(x=3) = 0.1238\)

Hence, the probability that the newspaper staff receives quotes from exactly 3 athletes is 0.1238.

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Answer:

$3863.17

Step-by-step explanation:

This is simple adding and subtracting.

3000.00

   345.97

   567.20

+ 150.00

4063.17

  -200.00

 $3863.17

An equation for the line in slope-intercept form is, \(y = \frac{5}{4}x + 8\).

What is slope intercept form of the line?

Using a straight line's slope and the location of its y-axis intersection, the slope intercept equation can be used to determine the general equation of the line. Y = mx + b is the equation in slope intercept form.

From the given graph of line we have to find the equation of line in slope - intercept form.

From graph we can see that the line passes through the points (0, 8) and (8, 18).

From this two points first to find the slope of the line.

\(m = \frac{y_2-y_1}{x_2-x_1} = \frac{18-8}{8-0} = \frac{10}{8} = \frac{5}{4}\)

Now, consider the slope point form of the line,

\(y-y_1=m(x-x_1)\)

Plug, \((x_1, y_1) = (0, 8), m = \frac{5}{4}\)  in the above equation.

⇒

\(y-8=\frac{5}{4}(x-0)\\ y-8=\frac{5}{4}x\\ y=\frac{5}{4}x+8\)

Hence, the equation of line in slope intercept form is, \(y = \frac{5}{4}x + 8\).

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Graph:

Answer: $14.25

Step-by-step explanation:

Plug in 20 for x.

(0.05)(20) + 13.25 = 14.25

Answer:  $14.25

Step-by-step explanation:

just input 20 miles into the equation and solve for the rental cost

c(x) = 0.05x + 13.25  

c(20) = 0.05(20) + 13.25

c(20)=  1 + 13.25

c(20) = 14.25

Answer:

First you simplify by first taking 4 multiply the parentheses: 4 x 3X - 4 x 2 = 12X - 8 =

Then you have to do the same thing at the right side, try figure it out. When u get the answer simplify it by taking. The x to left side and the ordinary numbers to right side(not always). As said try figure it out urself if u need help i got u