Order the following sets of data in decreasing order of Mutual Information. Question 2 Suppose that X is a random variable whose entropy H(X) is 8 bits. Suppose that Y=F(X) is a deterministic function that takes on a different value for each value of X. H(Y∣X) is the conditional entropy of X given Y H(X∣Y)=0 bit H(Y∣X)=1 bit H(Y)=8 bits

Answer:

for the 81st term of this arithmetic sequence is going to be -508

Step-by-step explanation:

From the first three term(a1, a2, a3) we can see the common difference is going to be -6, and we know the first term of the arithmetic sequence is -28,

and the general expression of a arithmetic sequence is going to be an=a1+d(n-1)

in this case is going to be an=-6n-22, replacing 81 we got a a81 is going to be -508

Answer:

1/n³

Explanation:

I can't explain it, this is the way the exponents work.. so bear with it lol

The auditing software can identify 63.7% of misreporting issues in accounting ledgers. The probability that no misreported transactions are found is 1 - 63.7% = 36.3%. The probability that at least half of the transactions are misreported is 1 - P(X  25) = 1 - P(X  24) P(X  24) = _(i=0)24 (50C_i) (0.363)i (1 - 0.363)(50 - i)  0.0001. The expected monetary gain is approximately -$49.8.

Given that an auditing software can identify 63.7% of misreporting issues in accounting ledgers. Let X be the number of accounting misreporting transactions identified by the software among 50 randomly selected transactions for the last 3 months.Probability that no misreported transactions are found:X follows a binomial distribution with n = 50 and p = 1 - 63.7% = 36.3%.P(X = 0) = (1 - p)^n = (1 - 0.637)^50 ≈ 0.0002Probability that less than 10 misreported transactions are found:

P(X < 10) = P(X ≤ 9)P(X ≤ 9)

= P(X = 0) + P(X = 1) + P(X = 2) + ... + P(X = 9)P(X ≤ 9)

= ∑_(i=0)^9 (50C_i ) (0.363)^i (1 - 0.363)^(50 - i) ≈ 0.99

Probability that at least half of the transactions are misreported:

P(X ≥ 25)P(X ≥ 25)

= P(X > 24)P(X > 24)

= 1 - P(X ≤ 24)P(X ≤ 24)

= ∑_(i=0)^24 (50C_i ) (0.363)^i (1 - 0.363)^(50 - i) ≈ 0.0001

Expected monetary gain:Let Y be the amount of money that the firm gets to earn or pay. The probability distribution of Y can be shown below:Outcomes: $200, -$50, -$100

Probabilities: P(X = 0), P(0 < X < 10), P(X ≥ 25)P(X = 0)

= 0.0002P(0 < X < 10)

= 0.99 - 0.0002 = 0.9898P(X ≥ 25)

= 0.0001E(Y)

= ($200 x P(X = 0)) + (-$50 x P(0 < X < 10)) + (-$100 x P(X ≥ 25))E(Y)

= ($200 x 0.0002) + (-$50 x 0.9898) + (-$100 x 0.0001)≈ -$49.8

Therefore, the expected monetary gain is approximately -$49.8.

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Answer:

IT IS B BECAUSE IT IS FACING TO THE RIGHT SIDE

Step-by-step explanation:

A. angle KLJ

B. angle MLK

D. angle EFH

All three angles mentioned have a tiny square marker to visually show the reader that the angle is a right angle, aka 90 degree angle. We can say that the segments forming the angle are perpendicular segments.

For angle GFE, it is smaller than angle EFH because point G is between or inside the angle EFH. So there is no way that angle GFE is a right angle.

Answer: Tissue

Step-by-step explanation:

They work together and there are in similar group.

From the graph we see that x takes the values in blue, those values are:

• x > 4,

• x < -4.

Now, the function absolute value |x| is equal, by definition, to:

• x if x > 0,

• -x if x < 0.

Using the absolute value, we represent the values of the graph with the following inequality:

Answer

Answer:

c

Step-by-step explanation:

The scenario described expressed as an inequality could be written thus :

The problem could be written thus :

The inequality expression :

Divide both sides by 63 to isolate m

This means that, David will need to save $63 for 5 months in other to be able to afford his birthday cost.

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Answer:

 120

Step-by-step explanation:

i did it

The input value that corresponding number to an output of 2 is -2

The graph that completes the question is added as an attachment

The input is represented by x and the output is y

From the attached graph;

The value of x is -2, when the value of y is 2

Hence, the input value that corresponding number to an output of 2 is -2

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a. The median number of calls = 55

b. The first and third quartiles, Q1 = 48 and Q3 = 66

c. The first decile and the ninth decile, D1 = 45 and D9 = 71.

d. The 33rd percentile = 52.5

To answer the questions, let's first organize the data in ascending order:

38 40 41 45 48 48 50 50 51 51 52 52 53 54 55 55 55 56 56 57 59 59 59 62 62 62 63 64 65 66 66 67 67 69 69 71 77 78 79 79

(a) The median is the middle value of a dataset when arranged in ascending order.

Since we have 40 observations, the median is the value at the 20th position.

In this case, the median is the 55th visit.

(b) The quartiles divide the data into four equal parts.

To find the first quartile (Q1), we need to locate the position of the 25th percentile, which is 40 * (25/100) = 10.

The first quartile is the value at the 10th position, which is 48.

To find the third quartile (Q3), we need to locate the position of the 75th percentile, which is 40 * (75/100) = 30.

The third quartile is the value at the 30th position, which is 66.

Therefore, Q1 = 48 and Q3 = 66.

(c) The deciles divide the data into ten equal parts.

To find the first decile (D1), we need to locate the position of the 10th percentile, which is 40 * (10/100) = 4.

The first decile is the value at the 4th position, which is 45.

To find the ninth decile (D9), we need to locate the position of the 90th percentile, which is 40 * (90/100) = 36.

The ninth decile is the value at the 36th position, which is 71.

Therefore, D1 = 45 and D9 = 71.

(d) To find the 33rd percentile, we need to locate the position of the 33rd percentile, which is 40 * (33/100) = 13.2 (rounded to 13). The 33rd percentile is the value at the 13th position.

Since the value at the 13th position is between 52 and 53, we can calculate the percentile using interpolation:

Lower value: 52

Upper value: 53

Position: 13

Percentage: (13 - 12) / (13 - 12 + 1) = 1 / 2 = 0.5

33rd percentile = Lower value + (Percentage * (Upper value - Lower value))

                = 52 + (0.5 * (53 - 52))

                = 52.5

Therefore, the 33rd percentile is 52.5.

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Answer:

w = -19

Step-by-step explanation:

10 + w = -9

-10         -10

w = -9 - 10

w = -19

The survival time of a 60kg deer without food at -20 degrees Celsius depends on various factors, including its age, sex, and physical condition. However, assuming the deer is healthy and has 5kg of fat, it could potentially survive for around 30 to 50 days without food.

The exact survival time can vary depending on several factors, such as the deer's level of physical activity, environmental conditions, and how much energy it is expending to stay warm in the cold temperature. Additionally, if the deer is able to find sources of water, this can also increase its chances of survival.

It's important to note that this is just an estimate and that the actual survival time may vary. If the deer is injured or sick, its chances of survival may be reduced, and it may not be able to survive as long without food.

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Complete Question

How many days could a 60kg deer survive without food at -20 degrees Celsius if it has 5kg of fat?

The coordinates of one endpoint, n of a line sigment, mn and mid point k are equal to the (10,3).

A midpoint of a segment is defined as a point on that line segment that divides the segment into two congruent segments. The midpoint is the point on the segment halfway between two endpoints. For considering a sigment with end points (x₁,y₁ ) and (x₂,y₂) then mid point coordinates, (x,y)

= ((x₁ +x₂)/2, (y₁+y₂)/2)

We have a segment mn with end point, m= ( 2,-7) and it's mid point, k, coordinates (6,-2). We have to determine the coordinates of end point n. let (p,q) be coordinates of end point n. Using the Mid-point formula, (6,-2) = ( (2 + x)/2 , (-7 + y)/2 )

=> 6 = (2 + p)/2 and - 2 = ( -7 + q)/2

=> 12 = 2 + p and -4 = -7 + q

=> p = 10 and q = 3

So, required corrdinates are (10,3) .

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Answer:

9

Step-by-step explanation:

4x-7 + 3x = 5x -1

7x - 7 = 5x +1

2x = 8

x = 4

VW = 4x - 7

      = 4(4) - 7

      = 16-7

      = 9

Answer:5$

Step-by-step explanation:

To find P(Y ≤ X + 1), we need to set up a double integral with the correct limits. First, let's sketch out the region using the support from part a.

From part a, we know that the region is defined by the inequalities 0 ≤ X ≤ 1 and 0 ≤ Y ≤ X. This forms a triangular region in the XY-plane.

To set up the double integral, we integrate over this region. The limits for the outer integral will be from 0 to 1, which corresponds to the limits of X.

For the inner integral, the limits will be from 0 to X + 1, since we want to find P(Y ≤ X + 1). This corresponds to the limits of Y.

Therefore, the double integral that needs to be solved is ∫∫R f(x, y) dy dx, with the limits of integration as follows:

Outer integral limits: 0 to 1 (X)
Inner integral limits: 0 to X + 1 (Y)

In conclusion, to find P(Y ≤ X + 1), you need to set up the double integral ∫∫R f(x, y) dy dx, with the limits as mentioned above.

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Using Mathematica, we can find the roots of the function y = x^3 Exp[-x] Sin[2x] by substituting x = 3t and evaluating the expression for t in the range [0,1]. The roots correspond to the values of t where the function crosses the x-axis.

To find the roots of the given function, we substitute x = 3t into the expression y = x^3 Exp[-x] Sin[2x]. This gives us y = (3t)^3 Exp[-3t] Sin[2(3t)]. Simplifying further, we have y = 27t^3 Exp[-3t] Sin[6t].

Using Mathematica, we can evaluate this expression for t values ranging from 0 to 1. The roots of the function correspond to the values of t where y equals zero, indicating that the function crosses the x-axis. By plotting the function or using numerical methods such as FindRoot or NSolve in Mathematica, we can determine the values of t where y = 0, thus finding the roots of the function.

In summary, by substituting x = 3t and evaluating the expression y = x^3 Exp[-x] Sin[2x] for t in the range [0,1] using Mathematica, we can find the roots of the function, which represent the values of t where the function crosses the x-axis.

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To estimate the project's beta, we need to make assumptions and use available data. Given the information provided for a publicly traded firm in the same line of business, including the debt outstanding, number of shares, stock price per share, book value of equity per share, and the beta of equity, we can calculate an estimate of the project's beta.

The beta measures the systematic risk of an investment relative to the overall market. To estimate the project's beta, we can use the leveraged beta approach. Since the project will be financed with equity, we assume that the project's beta will be equal to the equity beta of the publicly-traded firm in the same line of business. Therefore, the estimated beta of the project would be 1.19, based on the given information.

It is important to note that this estimation relies on the assumption that the project's risk profile and systematic risk are similar to that of the publicly-traded firm used as a reference. Additionally, this approach assumes that the project is solely financed with equity and does not take into account any potential debt financing or other factors that may affect the project's beta.

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The correct option is:(–[infinity], 2) ∪ (2, [infinity])The function `g(x) = (x² + 3x)/(x² + x – 6)`, for x < 3, and the function `g(x) = log2(x + 5)`, for x ≥ 3.

We can see that the function is piecewise.Therefore, to find the domain of a piecewise function, we must determine the domain of each piece and then join the two domains to find the domain of the entire piecewise function. 1. For the first part of the piecewise function, g(x) = (x² + 3x)/(x² + x – 6) is undefined for x = -2 and x = 3. So, the domain of the first piece is (–[infinity], -2) ∪ (-2, 3) ∪ (3, [infinity]).2.

For the second part of the piecewise function, g(x) = log2(x + 5) is defined for all x ≥ -5. Therefore, the domain of the second piece is [-5, [infinity]).Since we are looking for the domain of the entire piecewise function, we need to find the intersection of the domain of each piece: (–[infinity], -2) ∪ (-2, 3) ∪ (3, [infinity]) ∩ [-5, [infinity]) = (–[infinity], -2) ∪ (-2, 3) ∪ (3, [infinity]).The domain of the entire piecewise function is (–[infinity], -2) ∪ (-2, 3) ∪ (3, [infinity]), which can be expressed as (–[infinity], 2) ∪ (2, [infinity]).Hence, the option `(–[infinity], 2) ∪ (2, [infinity])` describes the domain of the given piecewise function.

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Answer:

Step-by-step explanation:

\(\displaystyle\ \Large \boldsymbol{} \frac{5(\frac{1}{5}+(-4) )}{2\cdot(-4) \cdot (0-0,8)^2} =\frac{^1 \ 5^{ }\!\!\!\!\diagup\cdot \frac{1}{5\!\!\!\!\diagup}-20 }{-8 \cdot 0,64 } = \\\\\\ \frac{-20+1}{-5,12} =\frac{-19}{-5,12} \cdot \frac{25}{25} =\frac{475}{128} =\boxed{\pmb{3\frac{91}{128} }}\)

Answer:

0.84 kg

Step-by-step explanation:

Given that :

Weight per liter = 1.12kg per liter

That is 1 Litre weighs 1.12 kilogram

The weight of saline solution of 0.75 Litre will be :

1 Litre = 1.12 kg

0.75 Litre = x

Cross multiply :

1 * x = 1.12 * 0.75

x = 0.84 kg

Hence, 0.75 Litre weighs 0.84 kg

Answer:

A

Step-by-step explanation:

Its a positive slope and you go up 2 and to the right 5

The radius of the sector, considering the angle measure and the area of the circle, is given as follows:

3 meters.

The area of a circle of radius r is given by the multiplication of π and the radius squared, as follows:

A = πr²

The radius of a circle represents the distance between the center of the circle and a point on the circumference of the circle, while the diameter of the circle is the distance between two points on the circumference of the circle, on a segment that passes through the center. Hence, the diameter’s length is twice the radius length.

The entire circle has an angle measure of 360º, hence for an angle measure of 45º, the equation is given as follows:

A = 0.125πr²

(as 45/360 = 0.125).

The area is of 4 m², hence the radius is obtained as follows:

4 = 0.125πr²

r = sqrt(4/(0.125π))

r = 3 meters.

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Answer:

A

Step-by-step explanation:

Bulldogs PitBulls Dogs the answer is A