Answers
2 times 4 is 8
8a
4 times 3 is 12
So 8a^12
B times ^4 it’s just B
4 times 4 is 16
So the answer is B
Hope this help *smiles*
Related Questions
if sinθ = A, find cos(π/2-θ)
(using trigonometric identities to fine the value)
Answers
Answer:
Cos(π/2 - θ) = A
Step-by-step explanation:
We know that:
Sin(θ) = A
And we want to find the value of Cos(π/2 - θ)
Here we can use the cosine relationship:
Cos(a - b) = Cos(a)*Cos(b) + Sin(A)*Sin(B)
Then:
Cos(π/2 - θ) = Cos(π/2)*Cos(θ ) + Sin(π/2)*Sin(θ)
We know that:
Cos(π/2) = 0
Sin(π/2) = 1
Then:
Cos(π/2 - θ) = Cos(π/2)*Cos(θ ) + Sin(π/2)*Sin(θ) = 0*Cos(θ ) + 1*Sin(θ)
= 1*Sin(θ) = A
Cos(π/2 - θ) = A
rewrite the fractions 3/4 and 7/10 as fractions with a least common denominator. a. 15/20 and 14/20b. 60/80 and 56/80c. 30/40 and 28/40d. 3/20 and 7/20
Answers
The rewritten fractions are 15/20 and 14/20. The correct answer is (a) 15/20 and 14/20.
To rewrite the fractions 3/4 and 7/10 with a least common denominator, follow these steps:
1. Find the least common multiple (LCM) of the denominators 4 and 10.
The LCM is the smallest number that both denominators can divide into.
In this case, the LCM is 20.
2. Rewrite each fraction with the new denominator (20) by multiplying the numerator and the denominator of each fraction by the necessary factor to reach the LCM.
For 3/4:
(3 * 5)/(4 * 5) = 15/20
For 7/10:
(7 * 2)/(10 * 2) = 14/20.
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Solve for a, b, and c
Answers
Answer:
a = 24(97√3 -168) ≈ 0.21428002b = 144(26 -15√3) ≈ 2.77025565c = 144(97 -56√3) ≈ 0.74228776Step-by-step explanation:
We can consider the horizontal line to be y=0, and define p, q, r to be the points on the top line left to right between c and 1 at the vertices of the 15° angles.
Then the y-value of r is 1 -tan(15°)². The y-value of q is the square of this, and the y-value of p is the cube (1 -tan(15°)²)³. That makes the value of c be ...
c = (1 -tan(15°)²)⁴
15° is half of 30°, so we can use the tangent half-angle identity to find its value:
tan(15°) = (1 -cos(30°))/sin(30°) = (1 -√3/2)/(1/2) = 2 -√3
This lets us find the exact value of c to be ...
c = (1 -(2 -√3)²)⁴ = (1 -(4 -4√3 +3))⁴ = (4√3 -6)⁴
= (4√3)⁴ -4·6·(4√3)³ +6·6²·(4√3)² -4·6³·(4√3) +6⁴
= 2304 -4608√3 +10368 -3456√3 +1296 = 13968 -8064√3
c = 144(97 -56√3)
__
The value of 'a' is ...
a = p·tan(15°) = (4√3 -6)³·(2 -√3) = (2 -√3)((4√3)³ -3·6·(4√3)² +3·6²(4√3) -6³)
= (2 -√3)(192√3 -864 +432√3 -216) = (2 -√3)(624√3 -1080)
= 1248√3 -2160 -1872 +1080√3 = 2328√3 -4032
a = 24(97√3 -168)
__
The value of b is ...
b = c/tan(15°) = (144)(97 -56√3)/(2 -√3) = (144)(2 +√3)(97 -56√3)/(4 -3)
= 144(194 -112√3 +97√3 -168)/1 = 144(26 -15√3)
b = 144(26 -15√3)
_____
Additional comment
The tangent of an angle in a right triangle is the ratio of the opposite to the adjacent side. For example, tan(15°) = c/b. Then the right-most short segment of the horizontal line is 1·tan(15°). The difference between the vertical at its right (1) and the vertical at its left (r) = tan(15°) times that segment length, or tan(15°)². Then r = 1-tan(15°)². Each vertical segment to the left of that is the previous vertical segment multiplied by this factor:
q = r²
p = r·q = r³
c = r·p = r⁴
__
The binomial expansions we used are ...
(a +b)⁴ = a⁴ +4a³b +6a²b² +4ab³ +b⁴
(a +b)³ = a³ +3a²b +3ab² +b³
Arithmetic question: You need to serve 58 people, 2 slices of pizza each. (Each pizza will be cut into 12 slices each.) (1) How many pieces of pizza do you need altogether? Identify the original improper fraction (or its reduced form) needed to solve this problem. Calculate the solution to give a mixed number answer? (2) How many pizzas do you need to order and how many extra slices will you have? Show any work needed to answer questions.
Answers
Answer:
5 order pizza
Step-by-step explanation:
12+12+12+12+12=60 I have 2 extra pizza
Find the value of a and YZ if Y is between X and Z. XY = 7a, YZ = 5a, XZ = 6a + 24 = YZ =
Answers
\(\\ \sf\longmapsto XY+YZ=XZ\)
\(\\ \sf\longmapsto 7a+5a=6a+24\)
\(\\ \sf\longmapsto 12a=6a+24\)
\(\\ \sf\longmapsto 12a-6a=24\)
\(\\ \sf\longmapsto 6a=24\)
\(\\ \sf\longmapsto a=\dfrac{24}{6}\)
\(\\ \sf\longmapsto a=5\)
YZ=5a=5(5)=25Value of a is 4 and value of YZ is 20 units
Step-by-step explanation:
Given:
Y is between point X and Z
Value of line XY = 7a
Value of line YZ = 5a
Value of line XZ = 6a + 24
Find:
Value of "a" and line YZ
Computation:
We know that
XY + YZ = XZ
So,
7a + 5a = 6a + 24
12a = 6a + 24
6a = 24
a = 4
Value of a = 4
So,
Value of line YZ = 5a
By putting value of a
Value of line YZ = 5(4)
Value of line YZ = 20 units
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What is 0.62x10 yo the power of 3
Answers
Answer:
62
Step-by-step explanation:
Answer:
238.328
Step-by-step explanation:
The product of 0.62 x 10 is 6.2. So, I did 6.2 to the power of 3, which is 238.328.
A horse owner needs to replace four sections of a coral for the horses. The first section
needs 26 yards of fencing, the second needs 10 3/5, the third, 10 1/5 yards, and the fourth,
8 3/10 yards. How many yards are needed to repair four sections of the fencing?
10
Answers
Answer:
55 1/10 yd
Step-by-step explanation:
26 + 10 + 3/5 + 10 + 1/5 + 8 + 3/10 =
= 54 + 4/5 + 3/10 =
= 54 + (8 + 3)/10 =
= 54 + 11/10 =
= 54 + 10/10 + 1/10 =
= 54 + 1 + 1/10 =
= 55 1/10
Answer:
55\(\frac{1}{10}\)
Step-by-step explanation:
Convert all the mixed numbers to fractions with a common denominator (10) then add them up:
26 + 53/5 + 51/5 + 83/10 =
26 + 106/10 + 102/10 + 83/10 =
26 + 291/10 =
26 + 29\(\frac{1}{10}\) = 55\(\frac{1}{10}\)
Let register x5 hold the hex number 01a74cd0hex and let x6 hold the hex number 00467b44 hex. If this information is enough, then answer the following three questions, else explain what extra information you may need to proceed.a) (1.5 pts) What are the contents of register x31 after the following instruction is executed? addi x31, x5, 32
b) (1.5pts) What would be the contents of register x28 after the following instruction is executed? add x28, x5, x6
c) (1.5 pts) What would be the contents of register x29 after the following instruction is executed? ld x29, 1056decimal (x30)
d) (1.5 pts) What would be the contents of register x29 after the following instruction is executed? sd x28, 16 decimal (x29)
Answers
a) The contents of register x31 after the following instruction is executed? addi x31, x5, 32 is 277968880 decimal.
b) The contents of register x28 after the following instruction is executed is 278427652 decimal.
c)The contents of register x29 after the following instruction is executed is 1056 decimal
d) The contents of register x29 after the following instruction is executed is 278427652 decimal
In computer architecture, registers are special storage locations within the CPU that hold data temporarily. These registers can hold values in binary, decimal, or hexadecimal formats. In this scenario, we have two registers x5 and x6, holding hexadecimal values. We will use these values to answer the given questions about register manipulation.
a) To determine the contents of register x31 after the instruction "addi x31, x5, 32", we need to add 32 to the value in x5 and store the result in x31. The value in x5 is 01a74cd0hex, which is equivalent to 277968848 in decimal. Adding 32 to this value, we get 277968880 decimal. Therefore, the contents of register x31 after the instruction is executed would be 277968880 decimal.
b) To determine the contents of register x28 after the instruction "add x28, x5, x6", we need to add the values in x5 and x6 and store the result in x28. The value in x5 is 01a74cd0hex, which is equivalent to 277968848 decimal. The value in x6 is 00467b44hex, which is equivalent to 458804 decimal. Adding these two values, we get 278427652 decimal. Therefore, the contents of register x28 after the instruction is executed would be 278427652 decimal.
c) To determine the contents of register x29 after the instruction "ld x29, 1056decimal (x30)", we need to load the value at memory location 1056decimal + the value in register x30 into register x29. The value in register x30 is not given in this scenario, so we cannot determine the contents of register x29.
d) To determine the contents of register x29 after the instruction "sd x28, 16 decimal (x29)", we need to store the value in register x28 at memory location 16 decimal + the value in register x29. The contents of register x28 is 278427652 decimal
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If Sultan Akbar goes to the Grand Bazaar With 8000 Rupees and 20% is spent on a carpet, how much has the carpet cost him?
Si el sultan Akbar va al Gran Bazar Con 8000 Rupias y se gasta el 20 % en una alfombra, cuanto le ha costado la alfombra?
Answers
Answer:
1600 Rupees
Step-by-step explanation:
20 divided by 100 times 8000 will give you 1600 so the carpet costed him 1600
Using the alternate form of the definition of the derivative, Compute f'(c) for f(x) = x+4/x, c=4
Answers
The value of the f(x) = (x + 4) / x at x = 4 is equal to - 1 / 4.
What is the value of the derivative of a function?
In this problem we have the following rational equation, which is equivalent to the following sum of functions:
f(x) = (x + 4) / x = 1 + 4 / x = g(x) + h(x)
Then, we must find both the derivatives of the functions g(x) and h(x) by using the definition of derivative:
g(x):
g'(x) = [1 - 1] / h
g'(x) = 0 / h
g'(x) = 0
h(x):
h'(x) = [4 / (x + h) - 4 / x] / h
h'(x) = [4 · x - 4 · (x + h)] / [h · (x + h) · x]
h'(x) = - 4 · h / [h · (x + h) · x]
h'(x) = - 4 /[(x + h) · x]
If h = 0, then:
h'(x) = - 4 / x²
Then, the first derivative of the function is f(x) = - 4 / x². Now we evaluate the function at x = 4:
f(4) = - 4 / 4²
f(4) = - 1 / 4
The value of the f(x) = (x + 4) / x at x = 4 is equal to - 1 / 4.
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A right rectangular prism has a volume of 6x^2 - 3x^2 - 45x. What are the expressions for the length, width, and height? And what is the least possible integer value of x for the rectangular solid to exist? Explain.
Answers
Step 1. The expression that we have for the volume of the rectangular prism is:
\(6x^3-3x^2-45x\)For part a, we need to find the expressions for the length, the width, and the height.
Step 2. The first step is to factorize the common factor which is 3x:
\(6x^3-3x^2-45x=3x(2x^2-x-15)\)Step 3. The expression for the volume now is:
\((3x)(2x^2-x-15)\)We can still factor the expression in the second parentheses so we will focus on that in this step.
• Factoring
\(2x^2-x-15\)We will factor it to have the general form:
\((x-x_1)(x-x_2)\)And to find x1 and x2, we use the quadratic formula:
\(\begin{gathered} For\text{ an expression} \\ ax^2+bx+c \\ We\text{ use the quadratic formula:} \\ x_{1,2}=\frac{-b\pm\sqrt{b^{^2}-4ac}}{2a} \end{gathered}\)In this case:
\(\begin{gathered} 2x^{2}-x-15 \\ \downarrow\downarrow \\ a=2 \\ b=-1 \\ c=-15 \end{gathered}\)Substituting these values into the quadratic formula:
\(\begin{gathered} x_{1,2}=\frac{-(-1)\pm\sqrt{(-1)^2-4(2)(-15)}}{2(2)} \\ Solving\text{ the operations:} \\ x_{1,2}=\frac{1\pm\sqrt{1+120}}{4} \\ x_{1,2}=\frac{1\pm\sqrt{121}}{4} \\ x_{1,2}=\frac{1\pm11}{4} \end{gathered}\)We find the two solutions using the + and the - sign:
\(\begin{gathered} x_1=\frac{1+11}{4}=\frac{12}{4}=3 \\ x_2=\frac{1-11}{4}=-\frac{10}{4}=-2.5 \end{gathered}\)Then, the factored expression is:
\(2x^2-x-15=(x-3)(x+2.5)\)Step 4. Remember that the expression after we factored the common term was:
\((3x)(2x^{2}-x-15)\)To this, we now substitute the factored form of the second expression:
\((3x)(x-3)(x+2.5)\)Step 5. Each pair of parentheses represents a dimension of the rectangular prism:
\(\begin{gathered} length:\text{ 3x} \\ width:\text{ x}-3 \\ height:\text{ x+2.5} \end{gathered}\)We have solved part a.
Step 6. In part b we need to find the least possible integer for the value of x.
This is simply that each expression for the length, width, and height that we found in step 5, must be greater than 0. That is because if one dimension is 0, there would be no volume.
\(\begin{gathered} 3x>0 \\ x-3>0 \\ x+2.5>0 \end{gathered}\)Solving each inequality:
\(\begin{gathered} x>0/3\rightarrow x>0 \\ x>3 \\ x>-2.5 \end{gathered}\)x has to be greater than 0, greater than -2.5 and greater than 3, therefore the least possible integer to that it meets all of the conditions is
x=4.
Answer:
Part a:
length: 3x
width: x-3
height: x+2.5
Part b:
x=4
If cot Theta = Two-thirds, what is the value of csc Theta? StartFraction StartRoot 13 EndRoot Over 3 EndFraction Three-halves StartFraction StartRoot 13 EndRoot Over 2 EndFraction Eleven-thirds
Answers
Answer:
csctheta= \(\frac{\sqrt{13} }{3}\)
Step-by-step explanation:
answer is provided on top
The value of the \(\rm cosec \theta = \frac{\sqrt{13} }{3}\). Cosec is found as the ratio of the hypotenuse and the perpendicular.
What is trigonometry?The field of mathematics is concerned with the relationships between triangles' sides and angles, as well as the related functions of any angle
The given data in the problem is;
\(\rm cot \theta = \frac{2}{3}\)
The \(cot \theta\) is found as;
\(\rm cot \theta = \frac{B}{P} \\\\ \rm cot \theta = \frac{2}{3} \\\\ B=2 \\\\ P=3 \\\\\)
From the phythogorous theorem;
\(\rm H=\sqrt{P^2+B^2} \\\\ \rm H=\sqrt{2^2+3^2} \\\\ H=\sqrt{13} \\\\\)
The value of the cosec is found as;
\(\rm cosec \theta = \frac{H}{P} \\\ \rm cosec \theta = \frac{\sqrt{13} }{3}\)
Hence the value of the \(\rm cosec \theta = \frac{\sqrt{13} }{3}\).
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Points A and B are on opposite sides of a lake. Another point, C. is 94.4 meters from Angle A. The measure of Angle A is 72° and the measure of Angle C is 30°. Find the distance between A and B.
Answers
To find the distance between points A and B, we can use trigonometry and the given information.
Let's label the distance between A and B as "d". We know that point C is 94.4 meters away from point A. From angle A, we have the measure of 72°, and from angle C, we have the measure of 30°.
Using trigonometry, we can use the tangent function to find the value of "d".
tan(72°) = d / 94.4
To solve for "d", we can rearrange the equation:
d = tan(72°) * 94.4
Using a calculator, we can evaluate the expression:
d ≈ 4.345 * 94.4
d ≈ 408.932
Therefore, the distance between points A and B is approximately 408.932 meters.
Find the value of the derivative (if it exists) at the indicated extremum. (If an answer does not exist, enter DNE.)
Answers
Answer:
The answer is "0".
Step-by-step explanation:
Please find the correct question in the attached file.
Given value:
\(\to f(x) =\frac{x^2}{x^2+5}\\\\\)
Formula:
\(\bold{\frac{d}{dx} \frac{u}{v} = \frac{ v \frac{du}{dx} - u \frac{dv}{dx}}{v^2}}\)
\(\to f'(x) =\frac{(x^2+5) 2x -2x^3 (2x)}{(x^2+5)^2}\\\\\to f'(0) =\frac{(0^2+5)2(0) -4(0)^4}{(0^2+5)^2}\\\\\to f'(0) =\frac{(0)(5) -2(0)}{(5)^2}\\\\\to f'(0) =\frac{0 - 0}{(5)^2}\\\\\to f'(0) =\frac{0}{25}\\\\\to f'(0) = 0\)
What is the median of 0.8, 1.0, 2.7, 2.8, 3.1, 13.3
Answers
Answer:
\(2.75\)
Step-by-step explanation:
Step 1: Determine the median
\(0.8, 1.0, 2.7, 2.8, 3.1, 13.3\)
The median of a set is the middle of the set. In this instance, we have 6 numbers so we don't have a number directly in the set representing the median. Instead, we need to find the average or middle between the 3rd and 4th number. So we take 2.7 and 2.8, add them together to get 5.5 and then we divide by 2 to get 2.75 which is our median.
Answer: \(2.75\)
Answer is 2.75
What is the value of x? Enter your answer in the box. X = cm 5 cm 48 cm 40 cm
Answers
The value of x in the similar triangle is 6 units.
How to find side of similar triangle?Two triangles are said to be similar if their corresponding angles are congruent and the corresponding sides are in proportion .
Therefore, let's use the similarity ratio to find the value of x in the similar triangle as follows:
Hence,
5 / 40 = x / 48
48 × 5 = 40x
240 = 40x
divide both sides by 40
x = 240 / 40
x = 6
Therefore,
x = 6
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A rental car company charges a fixed fee of $30 plus $0.05 per mile. The Boggs family paid $49.75 for their car rental. How many miles did they drive? Write an equation and solve.
Answers
Answer: 395
Step-by-step explanation:
Solve the triangle.
С
a
b
a =5, b=3, c=4
А
B
C
A-°
(Type your answer in degrees. Round to one decimal place as needed.)
Answers
Answer:
A = 90°
B = 37°
C = 53°
Step-by-step explanation:
Given three sides of a triangle, the Law of Cosines can be used to find the angles.
__
For angle A (the largest), we can use ...
a² = b² +c² -2bc·cos(A)
Solving for A, we get ...
A = arccos((b² +c² -a²)/(2bc)) = arccos((3² +4² -5²)/(2·3·4)) = arccos(0)
A = 90°
We can use a similar equation for angle B:
B = arccos((a² +c² -b²)/(2ac)) = arccos((25 +16 -9)/(2·5.4)) = arccos(4/5)
B ≈ 37°
The sum of angles is 180°, so ...
C = 180° -90° -37°
C = 53°
Carissa the chessplayer is a very, very slow walker. In fact, she walks at 100 meters per hour when walking uphill, 180 meters per hour when walking across flat ground, and 250 meters per hour when walking downhill. One day, Carissa walks across Boston from a café to a boba shop, and then takes the same route in reverse to return to the café. If there are equal parts of uphill, flat ground, and downhill, then what was Carissa's average speed during the entire round trip?
Answers
According to the statement, the Ship must move at an average pace of 150 meters per hour.
Is Downhill unfavorable?The variable under examination is lessened when the gradient is "downhill" (negative). When used as a gauge of how well things are doing, "downhill" denotes a downward trend. Yet, if this indicates trouble or some other unpleasant quality, the situation is improving.
The chess player Carissa walks very, very slowly. She actually moves at speeds of 100 meters per hr upward, 150 meters per hr on flat terrain, and 200 meters every hour on downhill terrain.
Here,
Carissa traverses Boston on foot from a coffeehouse to a boba store before returning over the same path.
Total distance walked = 2 [200 + 100 + 150] = 900 meter
Total time = 2 [1 + 1 + 1] = 6 hour
Average speed is calculated as distance divided by time (900 / 6 = 150 m/s),
As a result, the needed Carissa average speed is 150 meters per hr.
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Given P=0.15M +20. Is P a function of M? explain your choice using the definition of a function
Answers
Answer: Yes, this is a linear function between P and M.
Step-by-step explanation:
We can define a function as a relation between two or more variables, like y = f(x).
This function, maps the elements x (the input) into elements y (the output).
We have a rule for a function: Each input x can be mapped into only one output y.
In this case, we have:
P = 0.15*M + 20.
Let's prove that each value of M is related to only one value of P.
Suppose that, for a given M0, we have:
0.15*M0 + 20 = p1
and also for M0, we have:
0.15*M0 + 20 = p2
This means that p1 = p2, so we can not have different outputs for the same input.
This is a linear relation, so each value of M is related to only one value of P.
Then this is a function P(m) = 0.15*M + 20.
Jolene invests her savings in two bank accounts, one paying 3 percent and the other paying 9 percent simple
interest per year. She puts twice as much in the lower-yielding account because it is less risky. Her annual
interest is 3120 dollars. How much did she invest at each rate?
Amount invested at 3 percent interest is $____
Amount invested at 9 percent interest is $___
Answers
Let's denote the amount Jolene invested at 3 percent interest as 'x' dollars. Since she put twice as much in the lower-yielding account, the amount she invested at 9 percent interest would be '2x' dollars.
To calculate the interest earned from each account, we'll use the formula: Interest = Principal × Rate × Time.
For the 3 percent interest account:
Interest_3_percent = x × 0.03
For the 9 percent interest account:
Interest_9_percent = 2x × 0.09
We know that the total annual interest is $3120, so we can set up the equation:
Interest_3_percent + Interest_9_percent = 3120
Substituting the above equations, we have:
x × 0.03 + 2x × 0.09 = 3120
Simplifying the equation:
0.03x + 0.18x = 3120
0.21x = 3120
Dividing both sides of the equation by 0.21:
x = 3120 / 0.21
x = 14857.14
Therefore, Jolene invested approximately $14,857.14 at 3 percent interest and twice that amount, $29,714.29, at 9 percent interest.
Answer:
Step-by-step explanation:
X is the amount invested at 6%
Y is the amount invested at 9%
0.06X + 0.09Y = 4998
X = 2Y
0.06(2Y) + 0.09Y = 4998
.12Y + 0.09Y = 4998
0.21Y = 4998
21Y = 499800
Y = 499800/21 = 23800
So X = 2*23800 = 47600
$47,600 is invested at 6% and $23800 is invested at 9%
Find the equation of a line with a slope of 13/2
that passes through the point (−2, — 10).
Answers
Answer: \(y=\frac{13}{2} x+3\)
Step-by-step explanation:
Remember the point-slope equation which is \(y-y_{1} = m(x-x_{1} )\) where\((x_{1} , y_{1} )\) is your point and \(m\) is your slope.
Given that we substitute what you have:
\(y-(-10) =\frac{13}{2} (x - (-2))\)
Minus and minus give us positive:
\(y+10 =\frac{13}{2} (x +2)\)
Multiply slope into the parenthesis:
\(y+10= \frac{13}{2}x + \frac{13}{2}*2\\\)
Calculate it:
\(y+10= \frac{13}{2}x +13\)
Isolate the \(y\) by subtracting 10 from both sides:
\(y=\frac{13}{2} x + 13 -10\)
Your final equation is:
\(y=\frac{13}{2} x +3\)
Hope this makes sense!
And here's the graph to prove that the line actually goes through the point \((-2,-10)\):
At confidence, how large a sample should be taken to obtain a margin of error of for the estimation of a population proportion? assume that past data are not available for developing a planning value for. Round up to the next whole number.
Answers
At confidence, how large a sample should be taken to obtain a margin of error for the estimation of a population proportion? We now assume that past data are not available for developing a planning value for
Preliminary estimate for proportion (Not Known) is equal to 0.5
Margin of error = E = 0.03
Level of significance = 1-0.99 = 0.01
Z critical value is considered as (by using Z table) = 2.576
So, the sample size formula is taken as
n = [p(1 – p)]\(\left[Z/E]^{2}\)
=[0.5*(1-0.5)] [2.576/0.03]\(^{2}\)
=1,843.03
Hence, the sample size is approximately will be 1,844
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Given f(x) = x² - 5x - 6 and g(x) =
x² - 6x, what are the domain restrictions
for (-)(x)?
A) x # +6
B) x = 0
C) x = 0,6
D) x = -2,6
Answers
The domain restrictions for (f/g)(x) are (c) x = 0, 6
How to determine the domain restrictions for (f/g)(x)?From the question, we have the following parameters that can be used in our computation:
f(x) = x² - 5x - 6
g(x) = x² - 6x
The composite function (f/g)(x) is calculated as
(f/g)(x) = f(x)/g(x)
substitute the known values in the above equation, so, we have the following representation
(f/g)(x) = (x² - 5x - 6 )/(x² - 6x)
For the domain restriction, we have
x² - 6x = 0
When solved, we have
x = 6 or x = 0
Hence, the domain restrictions for (f/g)(x) are (c) x = 0, 6
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Question
Given f(x) = x² - 5x - 6 and g(x) = x² - 6x, what are the domain restrictions
for (f/g)(x)?
A) x = +6
B) x = 0
C) x = 0,6
D) x = -2,6
Logs5(3x-2) = 1 + Logs5 (x-4)
Answers
Answer:
57
Step-by-step explanation:
each of these bottles in a figure above contains different amounts of cola at different prices which bottle represents the cheapest price per ounce a $1.25 for 25oz, $1.50 for 25oz, $0.99 for 30oz, $1.20 for 30oz, $1.10 for 22oz
Answers
Answer
The cheapest bottle is $0.99 for 30 oz. bottle.
Explanation
The way to determine the cheapest bottle per ounce is to find the price per ounce for each of these bottles.
The different bottles and their price include
$1.25 for 25oz,
Price per ounce = (1.25/25) = $0.050 per ounce
$1.50 for 25oz,
Price per ounce = (1.50/25) = $0.060 per ounce
$0.99 for 30oz,
Price per ounce = (0.99/30) = $0.033 per ounce
$1.20 for 30oz,
Price per ounce = (1.20/30) = $0.040 per ounce
$1.10 for 22oz
Price per ounce = (1.10/22) = $0.050 per ounce
We can see that the cheapest option here is the $0.033 per ounce.
Hence, the cheapest bottle is $0.99 for 30 oz.
Hope this Helps!!!
12. You start the day left with 3 assignments due tomorrow. Your work load seems to double every period!
That means you would have how many assignments due tomorrow by 1st period? 4th period? 8th period?
Write an equation for this scenario & answer all questions.
Answers
The equation for the scenario of the work load doubling every period would be Assignments due = 3 x 2^(number of periods)
The assignments due would be:
1 st period - 6 assignments 4 th period - 48 assignments 8th period - 768 assignments How to find the assignments due ?Assignments start at 3 assignments and then double per period so the best equation is:
Assignments due = 3 x 2^(number of periods)
After 1 period:
Assignments due = 3 x 2^(number of periods)
= 3 x 2
= 6 assignments
After 4 periods:
= 4 x 2⁴
= 48 assignments
After 8 periods:
= 4 x 2 ⁸
= 768 assignments
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Type your response in the box.
Think about the impact on the consumer as you read these scenarios. Then answer the question that follows.
Scenario 1
Carlos is doing his weekly grocery shopping and needs to buy cereal. He turns his cart into the cereal aisle at the store. He sees many different cereals within his price range but notices that some are priced higher than others. He chooses a cereal he recognizes from a TV commercial, even though it’s slightly more expensive than he expected.
Scenario 2
Evelyn wants to purchase a plane ticket to visit her sister in London. She’s been checking prices frequently the past few days and notices that prices aren’t falling as she anticipated. She also notices that despite five airlines flying to London from the city she lives in, the prices of the tickets are all the same. She eventually decides not to go because the prices are too high for her budget.
What affected the purchasing decisions in these two scenarios?
Answers
The purchasing decisions in both scenarios were affected by the prices of the products/services being considered.
What is meant by budget?
In general, a budget is a financial plan or estimate that outlines the expected income and expenses over a specific period.
The purchasing decisions in both scenarios were affected by the prices of the products/services being considered.
In scenario 1, Carlos chose a more expensive cereal because he recognized it from a TV commercial, which may have influenced his perception of its quality or desirability.
In scenario 2, Evelyn decided not to purchase a plane ticket because the prices were too high for her budget, despite there being multiple airlines offering flights to London.
Therefore,The purchasing decisions in both scenarios were affected by the prices of the products/services being considered.
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Multiply 11.3 x 4.16
Answers
Answer:
47.008
Step-by-step explanation:
A rectangular prism has a length of 8in., a width of 4in., and a height of 2 1/4in. The prism is filled with cubes that have edge lengths of 1/4 in. How many cubes are needed to fill the rectangular prism?
Answers
We need 4608 cubes to fill the rectangular prism.
We have,
The rectangular prism has a volume of:
Volume = length x width x height
Volume = 8 in. x 4 in. x 2 1/4 in.
Volume = 72 in³
Each cube has a volume of:
Volume of cube = edge length³
Volume of cube = (1/4 in.)³
Volume of cube = 1/64 in³
To find the number of cubes needed to fill the rectangular prism, we can divide the volume of the prism by the volume of each cube:
Number of cubes = Volume of prism / Volume of a cube
Number of cubes = 72 in³ / (1/64 in³)
Number of cubes = 72 in³ x 64 / 1
Number of cubes = 4608 cubes
Therefore,
We need 4608 cubes to fill the rectangular prism.
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