List the following in order of increasing mass: an atomic nucleus, a cell, an electron, a DNA molecule.

The final answer, in joules, is -1835.120716 J.

Angles are measured in terms of radians. It is described as the angle occupied by a circle arc whose length is equal to the circle's radius. In other words, a circle with a radius of 1 unit subtends an arc with a length of 1 unit at an angle of 1 radian. Radians have no units because they are a dimensionless quantity.

Let's simplify and evaluate the given expression step by step:

First, let's calculate the terms inside the brackets:

(83)(2.1)²/4 = 185.3675 J

(100)(0)²/2 = 0 J

So, the first term in the expression becomes:

185.3675 J

Now, let's calculate the second term inside the brackets:

(83)(2.1)²/4 = 185.3675 J

(100)(2.1)²/2 = 2205 J

(0.14 rev/s * 2π rad/rev)² = 0.246784 J/(rad^2)

So, the second term in the expression becomes:

185.3675 J + 2205 J - 0.246784 J = 2390.120716 J

Now, we can calculate the final expression by plugging in the values and simplifying:

[(83)(2.1)²/4 +(100)(0)²/2] * (3 rad/sec)² - [(83)(2.1)²/4 +(100)(2.1)²/2 * (0.14 rev/s)² (2pi rad/rev)²]

= [185.3675 J + 0 J] * (3 rad/sec)² - [185.3675 J + 2205 J - 0.246784 J]

= 555 J - 2390.120716 J

= -1835.120716 J

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The pressure of the gas in the deodorant can when it is heated to 900 K is 9 atm.

Gay-Lussac's law states that the pressure exerted by a given quantity of gas varies directly with the absolute temperature of the gas.

It is expressed as;

P₁/T₁ = P₂/T₂

From the data:

We substitute our values into the expression above and solve for final pressure.

P₁/T₁ = P₂/T₂

P₁T₂ = P₂T₁

P₂ = P₁T₂  / T₁

P₂ = ( 3 atm × 900 K ) / 300 K

P₂ = 9.0 atm

Therefore, the final pressure is 9.0 atm.

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Answer:

The focal length of the mirror is 10.4 cm.

Explanation:

So substitute the values of object distance and image distance in the mirror equation,

1/f = 1/(-18cm) + 1/(-25.0cm)

1/f = -25cm/(-18cm x -25cm) - 18cm/(-18cm x 25cm)

1/f = ( -25cm - 18cm)/(18cm x 25cm)

1/f = -43.0/450.0

f = -10.4651 cm.

The focal length of the mirror is approximately -10.4 cm.

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Answer:

445 kPa

Explanation:

Use for conversion rates:

101.325 kPa = 760 mmHg = 14.7 psi

2637.5 mmHg × (101.325 kPa / 760 mmHg) = 351.6 kPa

13.6 psi × (101.325 kPa / 14.7 psi) = 93.7 kpa

The total pressure is:

351.6 kPa + 93.7 kPa = 445.3 kPa

Rounded to three significant figures, the pressure is 445 kPa.

Answer:

Irradiance (sunlight intensity or power), in Watts per square meter falling on a flat surface. ... Air Mass refers to “thickness” and clarity of the air through which the sunlight passes to reach the modules (sun angle affects this value). ... Cell temperature , which will differ from ambient air temperature

Answer:

- 670 kg.m/s

Explanation:

Newton's third law states that to every action, there is equal and opposite reaction force. Since the force will be same but different in direction and acted in the same time then the impulses ( force multiply by time) of the two car be same in magnitude but different in direction - 670 kg.m/s

Answer:

50 protons 50 electrons and 69 neutrons...

Explanation:

the number of protons is equal to number of electrons. then mass number is the sum of protons and neutrons in a nucleus so for we to get the number of neutrons we take the mass number subtract the protons number.

Answer:

The half-life is \( t_{1/2} = 1.005 h\)

Explanation:

Using the decay equation we have:

\(A=A_{0}e^{-\lambda t}\)

Where:

We know the activity decrease by a factor of two in a one hour period (t = 1 h), it means that \(A = \frac{A_{0}}{2}\)

\(\frac{A_{0}}{2}=A_{0}e^{-\lambda*1 h}\)

\(0.5=e^{-\lambda*1 h}\)

Taking the natural logarithm on each side we have:

\(ln(0.5)=-\lambda\)

\(\lambda=0.69 h^{-1}\)

Now, the relationship between the decay constant λ and the half-life t(1/2) is:

\(\lambda = \frac{ln(2)}{t_{1/2}}\)

\( t_{1/2} = \frac{ln(2)}{\lambda}\)

\( t_{1/2} = \frac{ln(2)}{0.69}\)

\( t_{1/2} = 1.005 h\)

I hope it helps you!

A net force can act in the same direction as that of the current velocity of the object, in which case it will not change the direction in which the object moves.

Answer: the force will increase 16 times

Explanation:

as the equation of the force is written, it's denominator is the distance squared

\(f = G\frac{m_{1}.{m_{2}}}{r^{2} }\)

so the distance is reduced by a factor of 4 ,the equation becomes\(f = G\frac{m_{1}.{m_{2}} }{{[r/4]}^{2} }\)

now as the distance r is divided by 4 the complete equation is multiplied by 16.

Answer:

(a)

67.1 s

(b) 2.5 m

(c) 2.5 m

Explanation:

initial speed, u = 0 m/s

final speed, v = 70 m/s

acceleration, a = 5 m/s2

distance, s = 1800 m

(a) Use third equation of motion

\(v^2= u^2 + 2 a s \\\\v^2 = 0 + 2 \times 5\times 1800\\\\v =134.2 m/s\)

Let the time is t.

Use first equation of motion

v = u + at

134.2 = 0 + 5 t

t = 67.1 s

(b) Use second equation of motion

\(s = u t +0.5 at^2\\\\s = 0 +0.5\times 5\times 1 \\\\s = 2.5 m\)

(c) Use second equation of motion

\(s = u t +0.5 at^2\\\\s = 0 +0.5\times 5\times 1 \\\\s = 2.5 m\)

How ??

Force:-

We know

According to newtons second law

\(\boxed{\sf Force=Mass\times Acceleration}\)

\(\\ \sf\longmapsto Force=kgm/s^2\)

We don't use it

\(\\ \sf\longmapsto Force=Newton(N)\)

Hence its a derived unit.

Pressure:-

\(\\ \sf\longmapsto Pressure=\dfrac{Force}{Area}\)

\(\\ \sf\longmapsto Pressure=\dfrac{N}{m^2}\)

\(\\ \sf\longmapsto Pressure=Pascal(Pa)\)

Hence its a derived unit

Answer:

23.9m

Explanation:

step one:

This problem is on energy.

we can proceed by using the expression for potential energy to solve for height h

we know that

PE=mgh

given that

mass m= 5kg

PE= 1176 joules

step two:

we can substitute our data and find h

1176= 5*9.81*h

1176=49.05h

step three:

divide both sides by 49.05 we have

1176/49.05=h

h=23.9 m

The height of the tree is 23.9m

We are asked to determine the linear speed given a radius and the number of revolutions per a given amount of time. To do that we will use the following formula:

Where:

We need to determine first the angular velocity. To do that we use the quotient between the number of revolutions and the time to do the revolutions. But first, we need to convert 1 revolution into radians. To do that we use the following formula:

Now, we determine the quotient:

Solving the operations:

Now, we need to convert the radius from inches into meters. To do that we will use the following conversion factor:

Multiplying by the conversion factor:

Now we substitute the values in the formula for the velocity:

Therefore, the linear speed is 9.78 m/s

Answer:

C number is write i think

Answer:

Explanation:

We shall represent each move of coach in vector form , considering unit vector i towards east and unit vector j towards north .

he drove 100 m North

First displacement D₁ = 100 j

200 m East to reach the 133

second displacement D₂ = 200 i

500 m North to reach Papa John's

third displacement

D₃ = 500 j

Total displacement ( resultant displacement )

= D₁ + D₂ + D₃

= 100 j + 200 i + 500 j

= 200 i + 600 j

magnitude of resultant displacement

= √ ( 200² + 600² )

= √ 40000 + 360000

= 632.45  m

Answer:

Area=1.5(1.5)=2.25m^2

Force of gravity=10N

\begin{gathered}\\ \sf\longmapsto Pressure=\dfrac{Force}{Area}\end{gathered}

⟼Pressure=

Area

Force

\begin{gathered}\\ \sf\longmapsto Pressure=\dfrac{10}{2.25}\end{gathered}

⟼Pressure=

2.25

10

\begin{gathered}\\ \sf\longmapsto Pressure=4.4Pa\end{gathered}

⟼Pressure=4.4Pa

Answer

I feel the answer is C because it could cause mental and physical trauma

Explanation:

It is not good to site a nuclear power plant in a densely populated areas as well as an area that has a high proximity to public infrastructure.

A nuclear plant is one of the proposed solution to the issue of power generation because of the capacity of the plants to generate electricity. Usually, a single nuclear plant could contribute to serve for many years using the same nuclear fuel.

Now, in the case whereby we want to site a new nuclear plant, we have to consider the population density of the area as well as the proximity of the plant to the regions whereby people live.

We know that it is not good to site a nuclear power plant in a densely populated areas as well as an area that has a high proximity to public infrastructure.

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We are given that a tree casts a shadow of 47.2 feet and we are asked to determine its height. We are also given that a yardstick cast a shadow of 3.5 feet. The yardstick and the tree form right triangles as shown in the next diagram:

Since both the tree and the yardstick have the same angle of incidence of light this means that both triangles are similar triangles, and therefore, we have the following relationship:

This is, the ratio between the opposite side and the adjacent sides of both triangles is the same. Now we solve for T by multiplying both sides by 47.2:

Solving the operations:

Therefore, the height of the tree is 40.46 feet.

For the second part we have:

If the tree falls then the length of 40.46 feet wouldn't be enough to hit the garage.

The Big Bang theory is the most widely accepted explanation for the origins of the universe, but it does not necessarily imply that the universe emerged from nothing.

It is possible that new discoveries or insights may shed light on this fundamental question in the future. The universe may have arisen from a pre-existing state or through some other natural process that we do not yet understand.

Instead, the theory describes how the universe underwent a rapid expansion from a very dense and hot state. The conditions and laws of physics that applied during the earliest moments of the universe may not necessarily be the same as those we observe today, and there are many unknowns and uncertainties in our understanding of these early stages.

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Answer: a . it decreases

Explanation:

The height of the motorcycle daredevil when it reaches the landing ramp is 4.93 m.

Since the ramp is a 33.0° ramp and the motorcycle daredevil jumps off with a speed of 20.3 m/s, the motorcycle dare devil has a horizontal component of speed u = 20.3cos33.0° m/s and a vertical component of speed v = 20.3sin33.0° m/s.

Now, since the other ramp is d = 28.0 m away, it takes the time it takes the motorcycle dare devil to reach it is t.

Considering motion in the horizontal direction, d = ut.

Thus, t = d/u

= 28.0 m/20.3cos33.0° m/s

= 28.0 m/(20.3 × 0.8387) m/s

= 28.0 m/17.025 m/s

= 1.645 s

Let h be the height of the motorcycle daredevil when it reaches the landing ramp in time, t.

Considering the vertical motion and using h = vt - 1/2gt² where v = vertical velocity of motorcycle daredevil = 20.3sin33.0°, t = time taken to reach landing ramp = 1.645 s and g = acceleration due to gravity = 9.8 m/s² (Note that there is a negative in front of g since it is directed downwards)

So, substituting the values of the variables into the equation, we have

h = vt - 1/2gt²

h = 20.3sin33.0° m/s × 1.645 s - 1/2 × 9.8 m/s² × (1.645 s)²  

h = 20.3 × 0.5446 m/s × 1.645 s - 1/2 × 9.8 m/s² × 2.706025 s²

h = 18.187 m - 1/2 × 26.519 m

h = 18.187 m - 13.26 m

h = 4.927

h ≅ 4.93 m

So, the height of the motorcycle daredevil when it reaches the landing ramp is 4.93 m.

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The kinetic energy of the flywheel after 1 minute of rotation, given that it has a mass of 50 and radius of 40 cm is 32.4 KJ (Option D)

We'll begin by obtaining the velocity of the flywheel. This is shown below:

v = at

v = 0.6 × 60

v = 36 m/s

Finally, we shall determine the kinetic energy of the flywheel. Details below:

KE = ½mv²

KE = ½ × 50 × 36²

KE = 25 × 1296

KE = 32400 J

Divide by 1000 to express in KJ

KE = 32400 / 1000

KE = 32.4 KJ

Thus, the kinetic energy is 32.4 KJ (Option D)

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Answer:

Refer to the step-by-step Explanation.

Step-by-step Explanation:

Simplify the equation with given substitutions,

Given Equation:

\(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2\)

Given Substitutions:

\(\omega=v/R\\\\ \omega_{_{0}}=v_{_{0}}/R\\\\\ I=(2/5)mR^2\)\(\hrulefill\)

Start by substituting in the appropriate values: \(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2 \\\\\\\\\Longrightarrow mgh+(1/2)mv^2+(1/2)\bold{[(2/5)mR^2]} \bold{[v/R]}^2=(1/2)mv_{_{0}}^2+(1/2)\bold{[(2/5)mR^2]}\bold{[v_{_{0}}/R]}^2\)

Adjusting the equation so it easier to work with.\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the left-hand side of the equation:

\(mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

Simplifying the third term.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2}\cdot \dfrac{2}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

\(\\ \boxed{\left\begin{array}{ccc}\text{\Underline{Power of a Fraction Rule:}}\\\\\Big(\dfrac{a}{b}\Big)^2=\dfrac{a^2}{b^2} \end{array}\right }\)

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2 \cdot\dfrac{v^2}{R^2} \Big]\)

"R²'s" cancel, we are left with:

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5}mv^2\)

We have like terms, combine them.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{7}{10} mv^2\)

Each term has an "m" in common, factor it out.

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)\)

Now we have the following equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the right-hand side of the equation:

\(\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac12\cdot\dfrac25\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\cdot\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15mv_{_{0}}^2\Big\\\\\\\\\)

\(\Longrightarrow \dfrac{7}{10}mv_{_{0}}^2\)

Now we have the equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

\(\hrulefill\)

Now solving the equation for the variable "v":

\(m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

Dividing each side by "m," this will cancel the "m" variable on each side.

\(\Longrightarrow gh+\dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2\)

Subtract the term "gh" from either side of the equation.

\(\Longrightarrow \dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2-gh\)

Multiply each side of the equation by "10/7."

\(\Longrightarrow v^2=\dfrac{10}{7}\cdot\dfrac{7}{10}v_{_{0}}^2-\dfrac{10}{7}gh\\\\\\\\\Longrightarrow v^2=v_{_{0}}^2-\dfrac{10}{7}gh\)

Now squaring both sides.

\(\Longrightarrow \boxed{\boxed{v=\sqrt{v_{_{0}}^2-\dfrac{10}{7}gh}}}\)

Thus, the simplified equation above matches the simplified equation that was given.  

Explanation:

it's true

Kiss me if I'm wrong. But dinosaurs still exist right?

Answer:

True

Definetely true

A white precipitate of calcium carbonate is created when carbon dioxide combines with calcium hydroxide solution.

Thus,  A calcium hydroxide solution is limewater. Limewater turns milky or hazy white when carbon dioxide is bubbled through it.

Therefore, you can infer that Co2 is created in the process when it becomes milky or murky white water.

A chemical reaction known as a gas evolution reaction creates a gas, such as oxygen or carbon dioxide. In the instances that follow, an acid and carbonate react to produce salt, carbon dioxide, and water, respectively. For instance, sodium nitrate, carbon dioxide, and water are produced when nitric acid interacts with sodium carbonate.

Thus, A white precipitate of calcium carbonate is created when carbon dioxide combines with calcium hydroxide solution.

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