Linear functions model situations that are continually increasing or continually decreasing. Quadratic functions model situations that increase and then decrease, or vice versa.

Polynomial functions can model situations that change directions multiple times. What is a situation in which a polynomial model might make sense, and why?

Answer:

A= (2xy^2)^3. (-1/2x^2yz) (gạch chéo là phần)

B=(-4x3y2z)(  x2y3)3xy

Step-by-step explanation:

ok :)

It will take the two ships at ports M and N 162miles apart 2.33 hours to meet.

a rate is a ratio that compares two different quantities which have different units. For example, if we say John types 50 words in a minute, then his rate of typing is 50 words per minute. The word "per" gives a clue that we are dealing with a rate.

let the distance both ships meet be x and he time taken to get to x by first ship be t.

second ship: time taken to get to (160 - x) is (t - 0.75) 45 minutes is same as 0.75 hour

so speed of first sheep

45 = x/t

x = 45t--------------1

speed of second ship

36 = 162-x / t - 0.75

cross multiply

36(t - 0.75) = 162 -x

x = 160 - 36(t - 0.75) -------------------2

equate equation 1 and 2

45t = 162 - 36(t - 0.75)

multiply out

45t = 162 -36t + 27

45t+36t = 162+27

81t = 189

t = 189/81

t = 2.33 hours

In conclusion the time taken for both ships to meet is 2.33 hours

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Answer:

I can do 102 problems in 9.01 hours.

Step-by-step explanation:

9.01 hours = 9.01 * 60 = 540.6 minutes

540.6 / 5.3 = 102

Answer:

D circumference: diameter

Step-by-step explanation:

The circumference is expressed by dπ while the diameter is "d." Since dπ/d is π, the ratio is π, meaning that D is the answer

A.  The payback period is 7.2 years. The net present value of the proposed investment is 3720.55.

B. No, the project does not meet the company's cash payback criteria.

C.  Yes, the project does meet the net present value criteria for acceptance.

A. The truck costs $55,440 and generates annual cost savings of $7,700. So the payback period is the cost of the truck divided the expected amount the truck will generate.

                $55,440 / $7,700 = 7.2 years

To solve for the net present value, we say

Net Present Value = ∑ [(Cash inflow in period t) / (1 + \(r^{t}\)] - Initial Investment.

NPV = (($7,700 / (1 + 0.08)¹) = 7 129.63

+ ($7,700 / (1 + 0.08)²) = 6601.51

+ .($7,700 / (1 + 0.08)³ = 6112.51

+ ($7,700 / (1 + 0.08)⁴) = 5659.73

+ ($7,700 / (1 + 0.08)⁵) = 5240.49

+ ($7,700 / (1 + 0.08)⁶) = 4 852.31

+ ($7,700 / (1 + 0.08)⁷) = 4492.88

+($7,700 / (1 + 0.08)⁸)  = 4160.07

+ ($27,600 / (1 + 0.08)⁸)) = 14911.42

- $55,440

We add all these values together and subtract by  $55,440

7 129.63 + 6601.51 + 6112.51 + 5659.73 + 5240.49 +4 852.31 + 4492.88 + 4160.07 + 14911.42 - $55,440

59160.55 - 55,440

NPV = 3720.55

B. The cash payback period of the project is 7.2 years. The company's cash payback criteria state that a project should not be accepted unless it has a payback period that is less than 50% of the asset's estimated useful life, which would be 4 years which is 50% of 8 years. Since 7.2 years is greater than 4 years, the project does not meet the company's cash payback criteria.

C. The positive NPV of $3,720.55 shows that embarking on the prooject will be valuable to the company. This means the project meets the NPV criteria for acceptance.

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Explanation:

Let's say there are 1000 students. The students must take math, science or they can take both simultaneously.

Now onto the sentence that says "Suppose a high school student who is enrolled in a math class is selected at random"

This means we only focus on the 650 math students and ignore the 1000-650 = 350 students who aren't in math.

Of those 650 math students, 130 are also in science (since 130 are in both classes).

The probability we're after is therefore 130/650 = 0.20

The probability that the student is also enrolled in a science class is 0.20

It is a branch of mathematics that deals with the occurrence of a random event.

Given that A recent survey found that 65% of high school students were currently enrolled in a math class,

Let us consider the number of students are 1000

65% of 1000 is 650

43% were currently enrolled in a science class

43% of 1000 is 430 science students

13% were enrolled in both a math and a science class.

43% of 1000 is 130students who are in both.

We have to find probability of Suppose a high school student who is enrolled in a math class is selected at random"

The probability is  130/650 = 0.20

Hence, the probability that the student is also enrolled in a science class is 0.20

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Answer:

D. Corrine is not correct because Hannah also wins if 6 is on the first cube and 1 is on the second, if 5 is on the first cube and 2 is on the second, and if 4 is on the first cube and 3 is on the second.

Step-by-step explanation:

To get a sum of 7 by rolling two cubes, we need to get one of the combinations from the list below:

1 on the first cube, 6 on the second cube

or

6 on the first cube, 1 on the second cube

2 on the first cube, 5 on the second cube

or

5 on the first cube, 2 on the second cube

3 on the first cube, 4 on the second cube

or

4 on the first cube, 3 on the second cube

Therefore, the correct answer option is D. Corrine is not correct because Hannah also wins if 6 is on the first cube and 1 is on the second, if 5 is on the first cube and 2 is on the second, and if 4 is on the first cube and 3 is on the second.

Answer:

D

Step-by-step explanation:

Corrine is not correct because Hannah also wins if 6 is on the first cube and 1 is on the second, if 5 is on the first cube and 2 is on the second, and if 4 is on the first cube and 3 is on the second.

Answer:

the probability of no defects in 10 feet of steel = 0.1353

Step-by-step explanation:

GIven that:

A roll of steel is manufactured on a processing line. The anticipated number of defects in a 10-foot segment of this roll is two.

Let consider β to be the average value for defecting

So;

β = 2

Assuming Y to be the random variable which signifies the anticipated number of defects in a 10-foot segment of this roll.

Thus, y follows a poisson distribution as number of defect is infinite with the average value of β = 2

i.e

\(Y \sim P( \beta = 2)\)

the probability mass function can be represented as follows:

\(\mathtt{P(y) = \dfrac{e^{- \beta} \ \beta^ \ y}{y!}}\)

where;

y =  0,1,2,3 ...

Hence,  the probability of no defects in 10 feet of steel

y = 0

\(\mathtt{P(y =0) = \dfrac{e^{- 2} \ 2^ \ 0}{0!}}\)

\(\mathtt{P(y =0) = \dfrac{0.1353 \times 1}{1}}\)

P(y =0) = 0.1353

Answer:

13 dollars

Step-by-step explanation:

5dollars + 8dollars =

13dollars

The required solution of the feasible region the rate of clothes is 13 $.

Arithmetic is the branch of mathematics that deals with the study of numbers using various operations on them. Basic operations of math are addition, subtraction, multiplication and division. These operations are denoted by the given symbols.

Given:

The given statement is

Michael is getting some clothes for himself and his brothers there’s a sale offering shirts for five dollars each and pants for eight dollars.

According to given question we have

Michael buy shirts for five dollars each and pants for eight dollars.

1 shirts = 5 $

1 pants  =  8 $

So total rate of clothes

= 5 $ + 8 $

=13 $

Therefore, the required solution of the feasible region the rate of clothes is 13 $.

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let's firstly convert the mixed fractions to improper fractions and then proceed.

\(\stackrel{mixed}{4\frac{2}{3}}\implies \cfrac{4\cdot 3+2}{3}\implies \stackrel{improper}{\cfrac{14}{3}}~\hfill \stackrel{mixed}{1\frac{1}{4}}\implies \cfrac{1\cdot 4+1}{4}\implies \stackrel{improper}{\cfrac{5}{4}} \\\\[-0.35em] ~\dotfill\)

\(\begin{array}{ccll} batches&cups\\ \cline{1-2} 1&\frac{14}{3}\\[1em] \frac{5}{4}&x \end{array}\implies \cfrac{1}{~~ \frac{5}{4}~~}=\cfrac{~~ \frac{14}{3}~~}{x}\implies \cfrac{\frac{1}{1}}{~~ \frac{5}{4}~~}=\cfrac{~~ \frac{14}{3}~~}{\frac{x}{1}}\implies \cfrac{1}{1}\cdot \cfrac{4}{5}=\cfrac{14}{3}\cdot \cfrac{1}{x} \\\\\\ \cfrac{4}{5}=\cfrac{14}{3x}\implies 12x=70\implies x=\cfrac{70}{12}\implies x=\cfrac{35}{6}\implies x=5\frac{5}{6}\)

The ratio of the number of baskets scored by team A to the number of baskets by team B is 2: 5. Then the correct option is B.

In a basketball game, team B scored 5 baskets for every 2 that team A scored.

The utilization of two or more additional numbers that compares is known as the ratio.

Assume that Team A scored two baskets while Team B netted five.

The problem statement states that for every two baskets Team A scored, Team B scored five. This may be expressed as the ratio shown below:

Ratio = 2x : 5x

Ratio = 2: 5

Thus, the correct option is B.

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Answer:

$13.70

Step-by-step explanation:

y=2.80x+2.50

=2.8*4+2.5

=13.7

Answer: $13.70

Step-by-step explanation: The first thing you would do is mulitply 2.80 time four. Then you would add 2.50 to the product to get 13.7.

Answer:

my name is jajahiaj,vsjava

Answer:

Answer in explanation.

Step-by-step explanation:

An equation to represent Juan's total savings y, in dollars, after x Fridays will be;

⇒ y = 12x

What is an expression?

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

Given that;

Juan wants to buy a video game for $63.

And, He saves $12 every Friday.

Now,

Let total dollars after x Friday = y

And, He saves $12 every Friday.

So, We can formulate;

⇒ Total money (y) = 12x

⇒ y = 12x

Thus, An equation to represent Juan's total savings y, in dollars, after x Fridays will be;

⇒ y = 12x

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The mean number of workers with a college degree is 40.8, and the standard deviation is 5.37.

The probability that the number of workers with a college degree is at least 35 is 0.976, or 97.6%.

Given Sample size (n) is 120 workers

Proportion of workers who are college graduates (p): 34% or 0.34

a) Mean and Standard Deviation:

The mean (μ) of a binomial distribution is given by μ = np, and the standard deviation (σ) is given by σ =√np(1 - p).

Substituting the values:

μ = 120 ×0.34 = 40.8

σ = √120 × 0.34 × (1 - 0.34)) = 5.37

To find the probability that the number of workers with a college degree is at least 35

we need to calculate the cumulative probability of the binomial distribution from 35 to the maximum possible value, which is 120 in this case.

Using a binomial probability calculator or a statistical software, we can find this probability.

Assuming a binomial distribution with parameters n = 120 and p = 0.34, the probability can be calculated as follows:

P(X ≥ 35) = 1 - P(X < 35)

The probability that the number of workers with a college degree is at least 35 is 0.976, or 97.6%.

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Answer:

she needs to buy 4 boxes since she can't buy a part of a box. assuming total boxes means completely filled boxes, then she fills 3

Step-by-step explanation:

Answer:

Divide the distance by the time.

Step-by-step explanation:

if i traveled 150 miles in 3 hours, my averadge would be 50 miles per hour

Answer:

x = 90

Step-by-step explanation:

The given diagram shows a circle with intersecting chords, KM and JL.

To find the value of x, we can use the Angles of Intersecting Chords Theorem.

According to the Angles of Intersecting Chords Theorem, if two chords intersect within a circle, the angle formed at the intersection point is equal to half the sum of the measures of the arcs intercepted by the angle and its corresponding vertical angle.

Let the point of intersection of chords KM and JL be point P.

As the chords are straight lines, angle x° forms a linear pair with angle JPM.

Note: We cannot use the Angles of Intersecting Chords Theorem to find the value of x directly, since we have not been given the measures of the arcs KJ and ML. Therefore, we need to use the theorem to find m∠JPM first.

From inspection of the given diagram:

Using the Angles of Intersecting Chords Theorem, we can calculate the measure of angle JPM (shown in orange on the attached diagram):

\(\begin{aligned}m \angle JPM &=\dfrac{1}{2}\left(m\overset\frown{JM}+m\overset\frown{LK}\right)\\\\&=\dfrac{1}{2}\left(30^{\circ}+(2x-30)^{\circ}\right)\\\\&=\dfrac{1}{2}\left(30^{\circ}+2x^{\circ}-30^{\circ}\right)\\\\&=\dfrac{1}{2}\left(2x^{\circ}\right)\\\\&=x^{\circ}\end{aligned}\)

As angle JPM forms a linear pair with angle x°, the sum of the two angles equals 180°:

\(\begin{aligned}m \angle JPM+x^{\circ}&=180^{\circ}\\\\x^{\circ}+x^{\circ}&=180^{\circ}\\\\2x^{\circ}&=180^{\circ}\\\\\dfrac{2x^{\circ}}{2}&=\dfrac{180^{\circ}}{2}\\\\x^{\circ}&=90^{\circ}\\\\x&=90\end{aligned}\)

Therefore, the value of x is 90, which means that the two chords intersect at right angles.

The value of the angle x is 108 degrees

To determine the value, we need to note that the sum of the angles on a straight line is 180 degrees.

Also, parallel lines are lines that do not meet or intersect each other on any side of a plane

From the information given, we have that;

x + 72 = 180

now, collect the like terms in the equation, we have;

x = 180 - 72

subtract the values

x  = 108 degrees

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Answer:

The population of deer at any given time = 200(e^0.03t)  ÷ (1.5 + (e^0.03t))

Step-by-step explanation:

This is an example of logistic equation on population growth

carrying capacity, k = 200

Rate, r = 3% = 0.03

Initial Population, P1 =  80

P(t) =?

P(t) = (P1 (k)(e^rt)) ÷ (k- P1 + P1(e^rt))

P(t) = (80 (200)(e^0.03t)) ÷ (200 - 80 + 80(e^0.03t))

     = (16000(e^0.03t))  ÷ (120 + 80(e^0.03t))

      = 200(e^0.03t)  ÷ (1.5 + (e^0.03t))

Answer:

200 children.

180 adults.

Step-by-step explanation:

let x=Children and y=Adults

create 2 equations.

x+y = 380

2.50x+5.80y = 1544

solve for x in the first equation and plug into the second equation.

x = 380-y

2.50(380-y) +5.80y = 1544

distribute and simplify.

950 + 3.3y = 1544

simplify

3.3y = 594

y = 180

plug y back into first equation and you get that there were 200 children.

Answer:

\(\huge\boxed{y=-x-1}\)

Step-by-step explanation:

The slope-intercept form of an equation of a line:

\(y=mx+b\)

\(m\) - slope

\(b\) - y-intercept

The point-slope form of an equation of a line:

\(y-y_1=m(x-x_1)\)

\((x_1;\ y_1)\) - point on a line

========================================

We have

\(m=-1;\ (-4;\ 3)\to x_1=-4;\ y_1=3\)

substitute

\(y-3=-1(x-(-4))\\\\y-3=-(x+4)\\\\y-3=-x-4\qquad|\text{add 3 to both sides}\\\\y-3+3=-x-4+3\\\\y=-x-1\)

Answer:

Step-by-step explanation:

Exchange rates are the rates at which one currency can be exchanged for another currency. They represent the value of one currency relative to another currency.

Answer: I think it’s 68.2

Answer:

68.2 for sure

Step-by-step explanation:

Answer: 26

Step-by-step explanation: 8+4(6−3)+6=26

Answer:

y2-y1/x2-x1= 36-8/8-4 and that gives you 31

Step-by-step explanation:

this is your slope formula y2-y1/x2-x1

YOU MUST PLUG IN YOUR X & Y VALUES

Answer:

9w

Step-by-step explanation:

First: combine like terms

3 - 5w + 12 + 2w - 3

(-5w) + 2w = (-3w)

Second: subtract 3 from 12 (12 - 3)

3 - 3w + 12 - 3

Third: subtract 3w from 3 (3 - 3w)

3 - 3w + 9

Forth: add 9 to w (w + 9)

w + 9

Answer:

9w

The simplified form of the given expression, 6 × 10⁻³ / 8 × 10⁻⁶, is 3/4  × 10³

From the question, we are to simplify the given expression

The given expression is

6 × 10⁻³ / 8 × 10⁻⁶

Simplifying the expression

6 × 10⁻³ / 8 × 10⁻⁶

This can be written as

6/8 × 10⁻³/10⁻⁶

Reduce the fraction

3/4  × 10⁻³/10⁻⁶

Apply the division law of indices

3/4  × 10⁻³ ⁻ ⁽⁻⁶⁾

3/4  × 10⁻³ ⁺ ⁶

3/4  × 10³

Hence, the value is 3/4  × 10³

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